Applying ADMD method of an industrial building: - Floor area 150m² per floor and total 20 storeys including G/F lobby and entrance There are 6 cargo lifts and one fireman lift One basement carpark 50m² and one covered G/F loading and unloading bay 100m² Assume the ADMD for industrial building is 0.23 kVA/m² and no central air conditioning ; car park is 0.01 kVA/m²; car park with ventilation is 0.02 kVA/m²; public service is 40 kVA per lift a) evaluate the rating of main switch (4 marks) b) which grade and which class of REW shall be employed for this building
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For an industrial building with a total of 20 storeys, including a basement carpark, loading bay, and multiple lifts, the rating of the main switch and the grade and class of the Residual Current Circuit Breaker with Overcurrent Protection (REW) need to be determined.
The main switch rating can be calculated based on the total connected load of the building, taking into account the floor areas and ADMD values. The grade and class of the REW should be selected based on the specific requirements and safety considerations of the building.
a) To evaluate the rating of the main switch, we need to calculate the total connected load of the building. The connected load is determined by multiplying the floor area of each floor by the corresponding ADMD value. In this case, the floor area is 150m² per floor, and the ADMD for an industrial building is given as 0.23 kVA/m².
Total connected load = (Floor area per floor) * (ADMD)
= 150m² * 0.23 kVA/m²
= 34.5 kVA
Based on the total connected load of 34.5 kVA, the main switch rating should be equal to or higher than this value to accommodate the electrical demand of the building.
b) The selection of the grade and class of the REW depends on the specific requirements and safety considerations of the building. Different grades and classes offer varying levels of protection against electrical faults and provide different levels of sensitivity to detect current imbalances.
To determine the appropriate grade and class, factors such as the type of electrical equipment used, the level of electrical insulation, and the potential risks associated with electrical faults should be considered. It is important to consult relevant electrical codes and regulations to ensure compliance and safety in the building's electrical system. The specific grade and class of the REW for this building should be determined by considering the building's electrical design, usage, and safety requirements.
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Related Questions
How long has Artificial Intelligence (AI) existed?
Answers
Answer:
In the 1940s and 50s, a handful of scientists from a variety of fields (mathematics, psychology, engineering, economics and political science) began to discuss the possibility of creating an artificial brain. The field of artificial intelligence research was founded as an academic discipline in 1956
Explanation:
The beginnings of modern AI can be traced to classical philosophers' attempts to describe human thinking as a symbolic system. But the field of AI wasn't formally founded until 1956, at a conference at Dartmouth College, in Hanover, New Hampshire, where the term "artificial intelligence" was coined.
A bead of mass 100g lying in a rough honzontal straight groove Coefficient of friction 3/4 and equation r(t) = (1+t) i+2t)j (distances measured in metres) is slowly drawn along the groove from the point r(0) to the point r(3) by a force which act parallel to 3i+j - find the magnitude of the force and the work done.
Answers
u stewpid vhild u sholuld study more a scool than relay on thiss app so stewpid ur parents Disapointed at u
For the following code, what is returned? public String testQueue() throws Empty CollectionException {
String s; Queue queue = new Array Queue(); queue.add("a"); queue.add("b"); S = queue.remove(); S = queue.remove(); queue.add("c"); queue.add("d"); s = queue.remove(); return s; }
a. "b" b. Nothing, the code won't compile. c. Nothing, an exception is thrown. d. "d" e. "c"
f. "a"
Answers
For the stated code, the following is returned "c". The correct answer is E.
Explanation:
The code creates a new Queue and adds the elements "a" and "b" to it. Then, it removes the first two elements, which are "a" and "b", leaving the Queue empty. After that, it adds the elements "c" and "d" to the Queue. Finally, it removes the first element, which is "c", and returns it. Therefore, the correct answer is e. "c".
The code snippet creates a queue, adds two elements ("a" and "b"), removes them, adds two more ("c" and "d"), and finally removes the first element, "c". The code performs a FIFO (first-in-first-out) operation, meaning the first element added to the queue will be the first one removed.
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For the stated code, the following is returned "c". The correct answer is E.
The code creates a new Queue and adds the elements "a" and "b" to it. Then, it removes the first two elements, which are "a" and "b", leaving the Queue empty. After that, it adds the elements "c" and "d" to the Queue. Finally, it removes the first element, which is "c", and returns it. Therefore, the correct answer is e. "c".
The code snippet creates a queue, adds two elements ("a" and "b"), removes them, adds two more ("c" and "d"), and finally removes the first element, "c". The code performs a FIFO (first-in-first-out) operation, meaning the first element added to the queue will be the first one removed.
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Design a double angle section for the lower chord of the roof truss depicted below. Allow for a double row of bolt holes in the larger leg. The smaller leg of the double angle used for the lower chord does not have bolts. Finally, assume no fewer than 3 bolts per line in the direction of the load. Use ASD.
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which headphones should i get? which ones do u think looks good and which do u think has high quality? OFF TOPIC
Answers
CE-3610
Design Basic
1. The building is to be designed according to the provisions for structural requirement for LRFD
for steel as set forth in ASCE 7/IBC.
2. Material Specifications:
2.1 Light weight Concrete floor over deck
2.2 ASTM A992 (Gr.50) for all W shape Beams, Girders and Columns
2.3 Braces HSS (ASTM A500) or W shapes (ASTM A992, Gr.50)
3. Dead Loads:
3.1 Roof:
3.1.1 Roofing Materials (Water Proofing etc.) = 4 psf
3.1.2 18" Gage deck= 3 psf
3.1.3 Light weight concrete 5 in thick
3.1.4 Framing & Fire proofing= 8 psf
3.1.5 Suspended ceiling= 4 psf
3.1.6 Mechanical & Electrical= 4 psf
3.1.7 Solar panels & assembly= 9 psf
3.2 Floor:
3.2.1 Tile including assembly= 9.5 psf
3.2.2 18" Gage deck
3.2.3 Light weight concrete 6 1/4 "= 3 psf
3.2.4 Framing & Fire proofing = 15 psf
3.1.5 Suspended ceiling= 5 psf
3.1.6 Mechanical & Electrical= 5 psf
3.3 Wall:
3.3.1 Parapets on roof (outer boundary only) = 25 psf (3.5 ft high)
3.3.2 Glazed walls (outer boundary only) = 18 psf (ground to roof level)
Floors require 2 hour fire rating.
Live Load considers partition loads as appropriate.
4. The deflection requirements are as follows:
4.1 L/360 due to live load deflection in all interior Beams and Girders
4.2 L/180 due to total load for all spandrel Beams and Girders
5. For Seismic design, the values of spectral response acceleration parameters for the given location should be found using the USGS website
Answers
The primary objective of this project is to design a building in accordance with the structural requirements for LRFD for steel as defined in ASCE 7/IBC. The building's materials are defined in the following terms:
Light-weight concrete flooring over deck with a thickness of 5 inches.
ASTM A992 (Gr.50) for all W shape Beams, Girders, and Columns.
HSS Braces (ASTM A500) or W shapes (ASTM A992, Gr.50).
Dead Loads: The building's dead load will be made up of a variety of elements, including:
Roof: Roofing Materials (Water Proofing, etc.) = 4 psf.
18" Gage deck = 3 psf.
Light-weight concrete 5 in thick.
Framing & Fire proofing = 8 psf.
Suspended ceiling = 4 psf.
Mechanical & Electrical = 4 psf.
Solar panels & assembly = 9 psf.
Floor: Tile including assembly = 9.5 psf.
18" Gage deck.
Light-weight concrete 6 1/4 "= 3 psf.
Framing & Fire proofing = 15 psf.
Suspended ceiling = 5 psf.
Mechanical & Electrical = 5 psf.
Wall: Parapets on roof (outer boundary only) = 25 psf (3.5 ft high).
Glazed walls (outer boundary only) = 18 psf (ground to roof level).
The live load of partitions is taken into consideration as appropriate. Flooring requires a two-hour fire rating. The following deflection requirements are in effect:
L/360 due to live load deflection in all interior Beams and Girders.
L/180 due to total load for all spandrel Beams and Girders.
the building's seismic design should consider the values of spectral response acceleration parameters for the given location, which can be found using the USGS website.
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Calculate the pressure of dry O2 if the total pressure of O2 generated over water is measured to be 698 Torr and the temperature is 30.1 oC. P(H2O) = 19.8 torr.
If the volume of the O2 sample in the question above was 56.3 ml, what volume would the dry O2 occupy at 755 torr (assume the temp was unchanged).
Answers
Answer:
\(V_2=46mL\)
Explanation:
From the question we are told that:
Pressure over Water \(P=698 Torr\)
Temperature \(T= 30.1 \textdegree C\)
Pressure of Water \(P(H2O) = 19.8 torr.\)
Volume of O2 \(O_2=56.3\)
Pressure of Dry O2 \(P_(0)=755torr\)
Generally the equation for Total Pressure is mathematically given by
\(P_t = P_O + P_H\)
Therefore
\(P_O=P_t-P_H\)
\(P_O=638-19.8\)
\(P_O=618.2torr\)
Generally the equation for Ideal gas is mathematically given by
\(P_1*V_1 = P_2*V_2\)
\(V_2=\frac{P_1*V_1}{P_2}\)
Therefore
\(V_2=\frac{ 618.2*56.3}{755}\)
\(V_2=46mL\)
Hence,The volume would the dry O2 occupy at 755 torr
\(V_2=46mL\)
application's of kirchoff's law
Answers
assuming complementary inputs are available, the minimum number of transistors needed to realize a two input xor gate is:
Answers
Assuming complementary inputs are available, the minimum number of transistors needed to realize a two input xor gate is 4.
If two inputs work well together in the production process, they are said to be complements. Since the inputs are used in fixed proportions, if the price of one input lowers, more of it will be sought after, increasing the demand for the other input.
In this study, a model of anticompetitive exclusive contracts with complimentary inputs is built. A downstream company converts a variety of complementary inputs into finished goods. When complementary input providers hold a dominant position in a specific input market, upstream competition price within that market benefits both the downstream firm and the complementary inputs providers by driving up complementary input prices.
Thus, even when entry that is socially optimal is permitted, the downstream firm is unable to generate higher profits. Therefore, even in the absence of scale economies, downstream competition, and relationship-specific investment, the inefficient incumbent provider can prevent socially efficient entrance by employing exclusive contracts.
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PLEASE HELP give an example of how scientists, technologists, engineers, and mathematicians may work together when inventing or innovating a new product. Include the role of each profession.
Answers
An example of them working together would be something like building a robot. Technologists would work on this project bc they would code the robot. Engineers would work on this bc they would design the interior. A mathematician would work in this bc a mathematician would calculate the angels of when a robot picks something up or when it turns. A scientist would work on this bc the scientist know about physics. You need physics so u know how much force to apply, how much energy to use, how much mass u need, and how much charge u need.
Explanation:
In a high-quality coaxial cable, the power drops by a factor of 10 approximately every 5 km. If the original signal power is 0.25 W (=2.5 x 10-1), how far will a signal be transmitted before the power is attenuated to 25 μW? As part of your answer, include a Table showing the signal power vs. distance in 5 km intervals. If optical fibre is used instead of the coaxial cable, briefly explain how you would expect the above calculated distance value to change. You are not required to include another Table.
Answers
Answer:
20 km for 40 dB loss80 km for 40 dB loss, or 10 dB loss for 20 kmExplanation:
Here's your table of (distance, power level):
(0 km, 250 mW), (5 km, 25 mW), (10 km, 2.5 mW),
(15 km, 250 μW), (20 km, 25 μW)
The signal can be transmitted 20 km before being attenuated to 25 μW.
__
Reportedly, the loss in fiber optic cable is about 0.5 dB/km. This compares to 10 dB/5 km = 2 dB/km for the coaxial cable. Loss in dB/km is a factor of 4 less for fiber optic cable, so the distance for the same loss would be multiplied by 4.
write a verilog description of the following combinational circuit using concurrent statements. Each gate has a 5-ns delay, excluding the inverter, which has a 2-ns delay. (consider the below circuit is a full module)
Answers
Answer: Hello your question is incomplete attached below is the complete question
answer:
attached below
Explanation:
In this Verilog description we will refer to figure attached below
we will make some representation which are :
Represent outputs of the input AND gates = P
Represent outputs of the input NOR gates = Q
Inverter = R
attached below is the Verilog description
IV. An annealed copper strip 9 inches wide and 2.2 inches thick, is rolled to its maximum possible draft in one pass. The following properties of annealed copper are given: strength coefficient is 90,000 psi; true strain at the onset of non-uniform deformation is 0.45; and, engineering strain at yield is 0.11. The coefficient of friction between strip and roll is 0.2. The roll radius is 14inches and the rolls rotate at 150 rpm. Calculate the roll-strip contact length. Calculate the absolute value of thetrue strain that the strip undergoes in this operation. Determine the average true stress of the strip in theroll gap. Calculate the roll force. Calculate the horsepower required.
Answers
Answer:
13.9357 horse power
Explanation:
Annealed copper
Given :
Width, b = 9 inches
Thickness, \($h_0=2.2$\) inches
K= 90,000 Psi
μ = 0.2, R = 14 inches, N = 150 rpm
For the maximum possible draft in one pass,
\($\Delta h = H_0-h_f=\mu^2R$\)
\($=0.2^2 \times 14 = 0.56$\) inches
\($h_f = 2.2 - 0.56$\)
= 1.64 inches
Roll strip contact length (L) = \($\sqrt{R(h_0-h_f)}$\)
\($=\sqrt{14 \times 0.56}$\)
= 2.8 inches
Absolute value of true strain, \($\epsilon_T$\)
\($\epsilon_T=\ln \left(\frac{2.2}{1.64}\right) = 0.2937$\)
Average true stress, \($\overline{\gamma}=\frac{K\sum_f}{1+n}= 31305.56$\) Psi
Roll force, \($L \times b \times \overline{\gamma} = 2.8 \times 9 \times 31305.56$\)
= 788,900 lb
For SI units,
Power = \($\frac{2 \pi FLN}{60}$\)
\($=\frac{2 \pi 788900\times 2.8\times 150}{60\times 44.25\times 12}$\)
= 10399.81168 W
Horse power = 13.9357
are trains cool because if they are then my dad didn't beat me
Answers
Answer:
I think trains are pretty awesome. There's a train in japan that levitates slightly and runs on magnetism. Pretty amazing. It's super fast too
For laminar flow of air over a flat plate that has a uniform surface temperature, the curve that most closely describes the variation of the local heat transfer coefficient with position along the plate is
Answers
This question is incomplete, the missing diagram is uploaded along this answer below;
Answer:
from the diagram, the curve that most closely describes the variation of the local heat transfer coefficient with position along the plate is Option D
Explanation:
Given the data in the question;
We write the expression for the local Nusselt number for Laminar flow over the flat plate;
Nu = \(C\)\((Re_x)^{0.5\) \((Pr)^{1/3\)
Nu = \(C(\frac{Vx}{v})^{0.5}\) \((Pr)^{1/3\)
\(\frac{h_xx}{k}\) = \(C(\frac{V}{v})^{0.5}\) \((Pr)^{1/3\) \((x)^{0.5\)
\(h_x\) = \(\frac{1}{x^{1/2}}\)
Next we write down the expression for the local heat flux from the plate with uniform surface temperature;
q = \(h_xA(\) T\(_s\) - T∞ )
q ∝ \(h_x\)
∴
q ∝ \(\frac{1}{x^{1/2}}\)
The local heat flux decreases with the position as it is inversely proportional to the square root of the position from the leading edge and it will not be zero at the end of the plate.
Therefore, from the diagram, the curve that most closely describes the variation of the local heat transfer coefficient with position along the plate is Option D
1. A bar is 500 mm long and is stretched to 505 mm with a force of 50 kN. The bar is 10 mm diameter. Calculate the stress and strain. The material has remained within the elastic limit. Determine the modulus of elasticity.
Answers
Answer:
The modulus of elasticity is 63760 MPa.
in a p -n junction, the n-doping nd is doubled. how do the following change if everything else remains unchanged? indicate only increase or decrease. (a) junction capacitance (b) built-in potential (c) breakdown voltage (d) ohmic losses
Answers
In a p-n junction, option c is accurate because the is double. the values below change if everything else stays the same and they only indicate a rise or fall in breakdown voltage.
Breakdown voltage It is the voltage at which current in a forward biased PN junction begins to flow or increases. When reverse voltage is present, junctions break down and reverse current increases quickly. The depletion layer's width narrows. The depletion layer becomes wider. A diode's breakdown voltage specifies the highest reverse voltage that can be used without exponentially increasing the leakage current in the diode. A diode won't necessarily be destroyed if its breakdown voltage is exceeded, but it will be if its current capacity is. To create an ionization path through the dielectric, the open gap voltage must increase before current can flow.
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A passive instrument performs which of the following tasks?
sends transmissions to Earth
records echo results from signals
accepts transmissions from Earth
collects radiation reflected from Earth
Answers
Answer:
D. Collects radiation reflected from Earth.
Explanation:
a rough rule for leather belt is that effective tension in it, shall not exceed 15 n/mm of width for a belt of 10 mm thickness. this rule is applied to determine width of belt required to transmit 37 kw, under the following conditions: angle of lap = 165º; coefficient of friction=0.3; velocity of belt = 1500 m/min; density of leather = 950 kg/m find the width of belt required. assuming limiting friction between belt and pulley rim, find the stress in the belt
Answers
The stress in the belt is calculated as follows: Stress in belt = 212.12 N / (14.14 mm x 10 mm) = 1.50 N/mm2.
How should a leather belt be sized?Just "add 2" to your off-the-rack trouser size will yield the belt size. For instance, a 38-belt size will be a good bet if you wear 36" waist trousers. Most people will discover that this straightforward method works best when pants are worn at the customary height—near the natural waistline.
Power = (Tension in belt) x (Belt speed)
Tension in belt = (Power x 1000) / (Belt speed x Angle of lap x Coefficient of friction)
Substituting the given values, we get:
Tension in belt = (37,000 x 1000) / (1500 x 165 x 0.3) = 212.12 NEffective tension in belt = 15 N/mm x Belt width
Belt width = Effective tension in belt / 15 N/mmBelt width = 212.12 N / 15 N/mm = 14.14 mm
Stress in belt = Tension in belt / (Belt width x Belt thickness)
Substituting the given values, we get:
Stress in belt = \(212.12 N / (14.14 mm x 10 mm) = 1.50 N/mm^2\)
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Engineering Physics
The x and y component of a vector is 3 and 5, respectively. What is the angle between the vector and positive x-axis?
Answers
Answer:
The angle between the vector and positive x-axis is approximately 59.036º.
Explanation:
By Linear Algebra and to be precise, by definition of Dot Product we can determine the angle between two vector from following expression:
\(\theta = \cos^{-1}\frac{\vec u \,\bullet \,\vec v}{\|\vec u\|\cdot \|\vec v\|}\) (1)
Where:
\(\vec u\), \(\vec v\) - Vectors, no unit.
\(\|\vec u\|\), \(\|\vec v\|\) - Norms of vectors, no unit.
\(\theta\) - Angle, measured in sexagesimal degrees.
Please notice that norms are calculated by Pythagorean Theorem. If we know that \(\vec u = (3,5)\) and \(\vec v = (1, 0)\), then the angle between the vector and positive x-axis is:
\(\|\vec u\| = \sqrt{3^{2}+5^{2}}\)
\(\|\vec u\| = \sqrt{34}\)
\(\|\vec v\| = 1\)
\(\theta = \cos^{-1}\frac{(3)\cdot (1)+(5)\cdot (0)}{\sqrt{34}\cdot 1 }\)
\(\theta = \cos^{-1}\frac{3}{\sqrt{34}}\)
\(\theta \approx 59.036^{\circ}\)
The angle between the vector and positive x-axis is approximately 59.036º.
A pizza shop makes serves both vegan pizza and meat pizza. Customers place N orders at the shop. Their order number is printed" on their bill. The shop displays K out of N orders (both vegan and meat) on their display screen at any given time. The pizza shop is very famous and they receive many orders. To avoid confusion, vegan pizza orders are represented by positive numbers and meat pizza orders are represented by negative numbers on the screen. The orders are served in the order in which they are displayed on the screen. Each time an order is ready, its number is removed from the display screen and a new order is added to the display at the end of the list. A couple has arrived with their child Billy. Billy is a very naughty child. To keep him occupied, his parents tell him to make a list of the first meat pizza that appear in each set of K orders displayed on the shop's display screen. Write an algorithm to help Billy make a list of the first meat based pizza order numbers displayed on the screen each time an order is
Answers
The algorithm helps Billy make a list of the first meat-based pizza order numbers displayed on the screen each time an order is written below.
What is an algorithm?A process for solving a problem or completing a computation is referred to as an algorithm.
The store's display screen is always displaying Kout of Borders (meat and vegan). The pizza shop is well-known and frequently receives orders.
Program Details
Make a class for a bank account with two attributes:
Owner and Balance,
and two methods:
Deposit and Withdraw.
Note: Withdrawals may not exceed the available balance.
Therefore, the algorithm is written above.
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stationary work zones have ___________ unlike mobile work zones.
Answers
In contrast to mobile work zones, stationary work zones have clearly defined boundaries.
What exactly is a "stationary work zone"?According to the 2009 edition of the Manual on Uniform Traffic Control Devices (MUTCD), a short-term stationary work zone is "daytime work that occupies a location for more than one hour within a single daylight period."
The following are typical daytime work shift-length tasks:
paving the road, fixing broken underground water lines, fixing storm water catch basins, trimming trees along the road, and parking work vehicles for a long time on the side of the road. The minimum traffic control planning and devices that are required to safely direct motorists, bicyclists, and pedestrians around workers and work vehicles during daylight hours will be discussed in this bulletin. Night operations necessitate additional equipment and planning, which is not the subject of this bulletin.
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Positive engagement or movable pole shoe type starters are normally found on older vehicles built by _____. A)GM B)Ford C)Chrysler D)Toyota.
Answers
Ford requested inclusion so that the firm wouldn't suffer, but the Treasury Department lent money and purchased GM and Chrysler stock instead.
Companies that relied on credit suffered greatly during the 2008 financial crisis, commonly known as the "credit crisis," and as a result, the automotive industry experienced a crisis from 2008 to 2010. Prior to the crisis, the automotive industry had been suffering from the rise in car fuel prices and the energy crisis, which had deterred consumers from purchasing fuel-hungry vehicles. Although the 2008 financial crisis had an impact on the European and Asian automobile industries, it had the greatest impact on the American industry because it was the source of the financial catastrophe. Therefore, the "Big Three" automakers—GM, Chrysler, and Ford—asked Congress for a financial bailout and issued a bankruptcy warning for GM and Chrysler.
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Electronic returnless fuel systems use the question 3 options: a) throttle bodymounted regulator. b) mechanical bypass regulator. c) in-line fuel supply pump. d) pressure vent valve in tank.
Answers
Electronic returnless fuel systems use an in-line fuel supply pump.
What is the role of electronic Returnless fuel systems?Electronic returnless EFI systems is known to bean “On Demand” returnless EFI systems due to the fact that it make use of fuel tank pressure sensor to examine fuel pressure.
Therefore, one can say that an Electronic returnless fuel systems use an in-line fuel supply pump.
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What does a restriction in the fuel return line cause?
Answers
Answer:
Carburetor flooding, engine stalling, and hard starting
Explanation:
If the fuel return hose becomes blocked or kinked it may cause the carburetor to flood from excessive fuel or pressure buildup.
A particular Table in a relational database contains 100,000 Data Records/rows, each of which Data Record/row requires 200 bytes. A select statement returns all Data Records/rows in the Table that satisfy an equality search on an attribute. Estimate the time in milliseconds to complete the query when each of the following Indexes on that attribute is used.
A. No Index (Heap File of Data Records)
B. A Static Hash Index (with no overflow buckets/Pages). Assume the cost of applying the hash function is H, negligible.
Answers
The correct question is;
A particular table in a relational database contains 100,000 rows, each of which requires
200 bytes of memory. Estimate the time in milliseconds to to insert a new row into the
table when each of the following indices on the related attribute is used. Assume a page
size of 4K bytes and a page access time of 20 ms.
a. No index (heap file)
b. A clustered, non-integrated B+ tree index, with no node splitting
required. Assume that each index entry occupies 100 bytes. Assume that the
index is 75% occupied and the actual data pages are 100% occupied. Assume
that all matching entries are in a single page.
Answer:
A) 20 ms
B) 120 ms
Explanation:
A) Append (at the end of file). Just one IO, i.e., 20 ms
B) Now, when we assume that each entry in the index occupies 100 bytes, then an index page can thus hold 40 entries. Due to the fact that the data file occupies 5000 pages, the leaf level of the tree must contain at least 5000/40 pages which is 125 pages.
So, the number of levels in the tree (assuming page 75% occupancy in the
index) is (log_30 (125)) + 1 = 3. Now, if we assume that the index is clustered and not integrated with the data file and all matching entries are in a single
page, then 4 I/O operations and 80ms are required to retrieve all matching
records. Two additional I/O operations are required to update the leaf page
of the index and the data page. Hence, the time to do the insertion is
120ms.
Counter argument for why engineers dont make a positive change in the world.
Answers
Answer:
They don't make a positive change in the world because they have made mistakes that aren't able to be made fixed and there are a lot of engineers who haven't study enough and know the important basis of coming to engineer.
9. Programs A and B are analyzed and found to have worst-case running time no greater than 150 N log, N and N?, respectively. Answer the following questions, if possible a. Which program has the better guarantee on the running time, for large values of N (N>10,000)? b. Which program has the better guarantee on the running time, for small values of N (N<100)? c. Which program will run faster on average for N=1,000? d. Is it possible that program B will run faster than program A on all possible inputs.
Answers
a) Program B has the better guarantee on the running time, for large values of N (N>10,000).
b) Program A has the better guarantee on the running time, for small values of N (N<100)
.c) Which program will run faster on average for N=1,000 cannot be determined from the given information.
d) It is possible that program B will run faster than program A on all possible inputs.Explanation:
a) For large values of N (N>10,000), Program B has a worst-case running time of N log N which is better than the running time of program A which is 150N log N. Hence, program B has the better guarantee on the running time.
b) For small values of N (N<100), Program A has a worst-case running time of 150N log N which is better than the running time of program B which is N. Hence, program A has the better guarantee on the running time.
c) The average running time of the programs for N=1000 cannot be determined from the given information.
d) It is possible that program B will run faster than program A on all possible inputs. It depends on the input, so it is not possible to make a general statement regarding which program is faster on all possible inputs.
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design a filter that has infinite dc gain, a gain of one from 1hz to 100 hz and filters (1st order) any signals above 100 hz. a) sketch the bode plot b) sketch the s-plane c) write the transfer function of the filter d) write the differential equation e) write out the unforced transient response f) write out the frequency response
Answers
To design a filter with infinite DC gain and a gain of one from 1Hz to 100Hz, while filtering any signals above 100Hz (1st order), we can use a high-pass filter with a cutoff frequency of 100Hz.
a) The Bode plot of this filter would show a flat line at infinity for frequencies less than 1Hz, a slope of 20dB/decade from 1Hz to 100Hz, and a sharp drop of 20dB/decade for frequencies above 100Hz.
b) The s-plane would show a single pole at -100rad/s.
c) The transfer function of this filter can be written as: H(s) = (s+100)/s
d) The differential equation for this filter can be written as: \(y''(t) + 100y'(t) + y(t) = 100x'(t) + x(t)\)
e) The unforced transient response for this filter can be written as: y(t) = \([c1e^(-50t)cos(99.5t) + c2e^(-50t)sin(99.5t)]\)
f) The frequency response for this filter is given by: H(jw) = (jw + 100) / jw.
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Assume a regulator has a percent load regulation of 0.5%. What is the output voltage at full-load if the unloaded output is 12.0 V
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Answer:
11.94 V
Explanation:
Generally the regulated voltage drops as load increases. When the voltage has dropped by 0.5%, it will be 60 mV less than the nominal value:
12.0 V - 0.06 V = 11.94 V . . . . full load voltage