Are alloy and gemstone are same type of solution?

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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Based on their valencies, the subscripts of the ionic compounds formed will be:

A. An alkali metal and a halogen.

An alkali metal and a halogen both have valencies of one.

Therefore the subscripts would be 1.

B. An alkali metal and a non-metal from group 16.

An alkali metal has a valency of 1 and a group 16 non-metal has a valency of 2.

By exchange of valencies, the subscript would be 2 and 1.

C. An alkaline earth metal and a halogen.

An alkaline earth metal has a valency of 2 and a halogen has a valency of 1.

By exchange of valencies, the subscripts would be 1 and 2.

D. An alkaline earth metal and a non-metal from group 16.

An alkaline earth metal has a valency of 2 and a non-metal from group 16 has a valency of 2.

By exchange of valencies, the subscripts would be 2 and 2.

Therefore, the subscripts of the ionic compounds formed will be:

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Answer:

\(m=406.26g\)

Explanation:

Hello,

In this case, since the density is defined as the degree of compactness of a substance and it mathematically defined as the ratio of the mass and volume:

\(\rho = \frac{m}{V}\)

By knowing that its density is 1.11 g/mL, the mass in 366 mL is:

\(m=\rho V=366mL*1.11\frac{g}{mL}\\ \\m=406.26g\)

Regards.

Answer:

stuff

Explanation:

it is kewl and it does stuff

Answer:

A covalent bond is a chemical bond that involves the sharing of electron pairs between atoms. These electron pairs are known as shared pairs or bonding pairs, and the stable balance of attractive and repulsive forces between atoms, when they share electrons, is known as covalent bonding. 

Answer:

A covalent bond is the “interatomic linkage that results from the sharing of an electron pair between two atoms.”

Explanation:

Hope this helps have a nice day

A chemist determines that a substance is composed of 30.4% nitrogen by mass and 69.6% oxygen by mass. The molar mass of the compound is 230.5 g/mol, the molecular formula is NO₂.

We must compute the empirical formula in order to ascertain the compound's chemical composition.

If we have 100 grams of the compound.

This suggests we have:

30.4 g of nitrogen

69.6 g of oxygen

Now, we have to convert the mass of each element to moles.

The molar mass of nitrogen (N) = 14.01 g/mol

the molar mass of oxygen (O)  =  16.00 g/mol.

Number of moles of nitrogen (N):

2.17 mol

Number of moles of oxygen (O):

4.35 mol

The simplest whole-number ratio between the moles of nitrogen and oxygen must now be determined. To calculate the ratio, we divide both numbers by the smaller value.

Moles N / moles O = 2.17 mol / 2.17 mol = 1.00

Moles O / moles O = 4.35 mol / 2.17 mol = 2.00

The ratio is approximately N₁O₂.

We divide the subscripts by their greatest common divisor to obtain the simplest ratio, since we are looking for the empirical formula. The empirical formula is NO₂ since the greatest common divisor in this situation is 1.

The molecular formula of the compound is NO₂.

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Answer: Atoms with a lower atomic mass have a greater density than the atom with the higher atomic weight because the atoms are tightly packed together. The volume of a material can change with temperature and pressure. This can also modify the density of the material.

Explanation: HOPE IT HELPS YOU . PLEASE GIVE BRAINLIEST . THANKS .

The sentence that suggests that the container is an open system is option C: "The container contains 8 grams of liquid water and no ice."

In an open system, matter can freely enter or leave the system. In this case, if the container contains only liquid water and no ice, it indicates that some of the ice has melted and the resulting liquid water has escaped from the container. This suggests that matter (in the form of liquid water) has left the system, indicating an open system.

Option A suggests that the container contains 12 grams of liquid water and no ice, which implies that all of the ice has melted and the liquid water remains inside the container. This does not necessarily indicate an open system as the liquid water could still be contained within a closed system.

Option B suggests that the container contains 12 grams of ice and no liquid water, indicating that none of the ice has melted. This does not provide information about the system being open or closed.

Option D suggests that the container contains 8 grams of ice and 4 grams of liquid water, indicating that some of the ice has melted but the liquid water remains inside the container. This does not necessarily indicate an open system as the liquid water could still be contained within a closed system.

Option E suggests that the container contains 8 grams of liquid water and 4 grams of water vapor. This indicates a phase change from liquid to vapor, but it does not provide information about whether the system is open or closed.

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Answer:

1-C,2-C ,3- P ,4-C ,5- P ,6-P ,7- C ,8-C ,9- P,10- C,11- P,12- C,13-C, 14- P,15- C

Explanation:

Answer:

The answer is "Option b"

Explanation:

In this question first we calculates the moles in F-, HF, and in HCL, which can be defined as follows:

Formula:

\(\ Number \ of \ moles\ = \ Molarity \times \ Volume \ in \ litter\)

\(\ moles \ in\ F- = 0.100 \ M \times 0.0250 L\\\\\)

                     \(=\ 0.0025 \ moles\)

\(\ moles \ in \ HF \ = 0.126M \times 0.0250 L\)

                       \(= 0.00315 \ moles\)

\(\ moles \ in \ HCl = 0.0100M \times 0.00500 L\)

                       \(= 0.00005 \ moles\)

\(\ Reaction: \\\\F - + H+ \rightarrow HF\)

\(\Rightarrow \ moles \ in \ F- = 0.0025 \\\\\Rightarrow \ moles \ in \ H+ = 0.00005 \\\\ \Rightarrow \ moles \ in \ HF = 0.00315\\\\ \ total \ moles = 0.00250 -0.0000500 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.00315 + 0.00005\\\\\ total \ moles =0.00245 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.00245\)

\(\ total \ volume \ in \ the \ solution = \ V = \ 0.0300 L\\\\ after \ addition \ of \ HCl \ the \ concentration \ of \ F- \ = 0.00245\ moles \div V\)

                                                                                \(=\frac{ 0.00245 \ moles }{0.0300L}\\\\= \frac{245 \times 10^4}{300 \times 10^5} \\\\= \frac{245}{3000} \\\\ = 0.0817 M\)

The Fischer projection given here is for L-enantiomer and ketopentose. Option B is correct, as there is a ketone group present in the carbohydrate monomer. Carbohydrate can have an aldehyde or ketone as a functional group.

Carbohydrate monomer is a single unit that can either have an aldehyde functional group called aldose or a ketone functional group called ketose. Here in the given diagram, the monomer has a ketone group (C=O) and has five carbons, so it is considered a keto pentose. Carbohydrates are classified into L and D forms based on their OH group, and this L and D form differs from the "l" and "d" form (classified on the direction of movement around the plane polarized light).

Hence, this given diagram is L-enantiomer and keto pentose, which is option B.

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The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1, depending on which rate was used to calculate it.

The rate of the reaction is given by the equation:

Rate = -k[A]

where k is the rate constant and [A] is the concentration of the reactant.

Rate at t=140 s:

Rate = (8.00×10−2 M - 0 M) / (140 s - 0 s)

= 5.71×10−4 M/s

Rate at t=400 s:

Rate = (4.00×10−2 M - 0 M) / (400 s - 0 s)

= 1.00×10−4 M/s

Since this is a zero-order reaction, the rate of the reaction is constant, and we can use either rate to calculate the rate constant:

k = Rate / [A]

Using the rate at t=140 s:

k = 5.71×10−4 M/s / 8.00×10−2 M = 7.14×10−3 s−1

Using the rate at t=400 s:

k = 1.00×10−4 M/s / 4.00×10−2 M

= 2.50×10−3 s−1

The rate constant for the reaction is either 7.14×10−3 s−1 or 2.50×10−3 s−1.

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Answer:

A the heat started a chemical reactions

The heat started a chemical reaction between the iron and sulfur, making the compound iron sulfide. So, the correct option is (A).

A chemical reaction is defined as the process that leads to a chemical change from one set of chemical substances to another.

In this process, a substance or substance undergoes a chemical change to produce a new substance or substances, with whole new properties, in a process known as chemical reactions. The nature and identity of the products is completely different from that of the reactants.

For the information above, the chemical reaction caused by the heat, the iron and the suphur mixed with each other are heated on a burner forming a yellow color, which turns into iron sulphide, a black colored compound having totally different properties.

Thus, the heat started a chemical reaction between the iron and sulfur, making the compound iron sulfide. So, the correct option is (A).

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Answer:

663 g

Explanation:

Step 1: Write the balanced equation

2 LiOH + CO₂ ⇒ H₂O + Li₂CO₃

Step 2: Calculate the moles corresponding to 825 L of CO₂

At standard pressure and temperature, 1 mole of CO₂ has a volume of 22.4 L.

825 L × 1 mol/22.4 L = 36.8 mol

Step 3: Calculate the moles of H₂O formed from 36.8 moles of CO₂

The molar ratio of CO₂ to H₂O is 1:1. The moles of H₂O formed are 1/1 × 36.8 mol = 36.8 mol.

Step 4: Calculate the mass corresponding to 36.8 moles of H₂O

The molar mass of H₂O is 18.02 g/mol.

36.8 mol × 18.02 g/mol = 663 g

Answer:

False.

Explanation:

If the answer to this question was true, then that would mean that the more the solute is broken down, the less it'll dissolve... and everyone know that this doesn't make sense. I hope I explained this is an easy manner so you could understand! Good luck! :)

The more solute is broken down in solution the more conductive the solutions is and the statement is False.

Conductivity depends upon solvation of ions present in solution. Greater the solvation of ions, lesser is the conductivity.

Solvation is the process in which molecules of a solvent attract the particles of a solute.

The main forces in solvation are ion-dipole and hydrogen bonding attractions.

The more concentrated a solution is, the greater the conductivity measured (if the solute is a conductor in solution). This is because the higher the concentration of the solute, the more ions will be available to carry electric charge.

Therefore, the more solute is broken down in solution the more conductive the solutions is and the statement is False.

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Answer:

A pure substance is a form of matter that has a constant composition and properties that are constant throughout the sample. Mixtures are physical combinations of two or more elements and/or compounds.

We obtain the nutritional calories as 2967 cal/g.

Now we know that heat is evolved when we combust a compound or a substance inside the bomb calorimeter. Given that we have the following information about the system;

Temperature rise = 2.42 ∘C

Heat capacity =  30.70 kJ⋅K−1

The we have the energy as obtained from;

H = 30.70 kJ⋅K−1 * 2.42 ∘C = 74.29 kJ or 17.8 * 10^3 cal

Now we are required in this question as we have it to obtain the heat capacity per gram as; 17.8 * 10^3 cal/6g = 2967 cal/g

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Answer:

Step 1: Find the molarity

We have 22 moles of HNO3 in 5000L Water. Hence, 22 mol/ 5000L = 0.0044 M

Step 2: Dissociation of H+ ions

Since HNO3 is a strong acid, it completely dissociates. hence, we have 0.0044 M of H+ ions from 0.0044M solution

Step 3: pH

pH = -log[H+] = -log[0.0044] = 2.36.

(I don't think its right, but maybe)

Explanation: お役に立てば幸いです+

The outermost of the six sun layers with the letters A, B, C, D, E, and F, layer F in the cross-sectional figure symbolises the corona.

The Sun's atmosphere's outermost region is called the corona. The brilliant brightness of the Sun's surface often obscures the corona. Without employing specialised equipment, it is challenging to see. A total solar eclipse, however, makes the corona visible.

The term "corona" refers to the topmost region of the Sun's atmosphere. It rises hundreds of kilometres above the Sun's surface and gradually changes into the solar wind, which travels across our solar system.

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the capillary action, the tops of plants are supported by little tubes. In a tube with a diameter of 0.005 mm and a height of 70.8 m, a water solution will rise due to the capillary effect.

Given,

tube diameter ,D= 0.005 mm

contact angle, Ф=20°

density of water ,ρ=998.21 kg/m³

the surface tension of water at 20° C,σ\(_{s}\)=0.073 N/m

radius of capillary tube ,R=D/2

R=0.005/2

 = 0.0025 mm

R=2×10⁻⁶ m

capillary raise is given by

h=(2σ\(_{s}\)/PgR)cosФ

 =(2(0.073 N/m)/(998.21 kg/m³)(9.81m/s²)(2×10⁻⁶m))cos20°

h=70.8m

∴The capillary rise is h=70.8m

Capillary effect, also known as capillary action or wicking, is the ability of a liquid to flow against gravity in narrow spaces due to the interaction between the liquid and the surface of the container it is in. The height that the liquid can rise is dependent on the diameter of the tube or material it is in, the properties of the liquid, and the properties of the container. Capillary action is important in many natural and technological processes, such as plant water uptake, inkjet printing, and the functioning of some medical devices.

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Answer:

0.0542 M

Explanation:

Let;

CA = concentration of Ce4+ solution = 0.1741 M

VA = volume of Ce4+ solution = 18.68 mL

CB = concentration of H3AsO3 = ?

VB  = volume of H3AsO3 = 30.00 mL

NA = Number of moles of Ce4+ solution = 2

NB = Number of moles of H3AsO3  = 1

From;

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB = CAVANB/VBNA

CB = 0.1741 * 18.68 * 1/30.00 * 2

CB = 0.0542 M

Answer:

0.791 moles are present in the sample

Explanation:

To convert mass to moles of a substance you must find the molar mass of the susbtance.

The molar mass of C₂H₆ is:

2C = 12.01g/mol*2 = 24.02g/mol

6H = 1.01g/mol*6 = 6.06g/mol

Molar mass = 24.02g/mol + 6.06g/mol = 30.08g/mol is the molar mass of C₂H₆

And the moles of 23.8g of this substance are:

23.8g * (1mol / 30.08g) =

The reaction time decreases as the temperature increases of the reaction mixture increases.

A sample record of results is:

An increase in temperature leads to an increase in reaction rate or a decrease in reaction time.

The increase in temperature provides more thermal energy to the reactant molecules, which leads to an increase in the average kinetic energy of the molecules. As a result, more reactant molecules have sufficient energy to overcome the activation energy barrier and undergo successful collisions, leading to an increased reaction rate.

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Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

1. We are given :

• n = 4.12 mol

• at STP , we know that :

According to avogadro's law at STP 1 mole of gas occupy volume 22.414 L

2. Calculations :

If 1 mole : 22.424L

then,4.12mole : x L .......(do a cross multiply)

Therefore ; x L = 4.12Mole * 22.424L/ 1 mole

=92.38 Litres

≈92.4 L

• This means that 4.12 mol sample of hydrogen gas will occupy ,92.4 Litres

Answer:

4 digits that are 7,5,0,0

Explanation:

To solve this question we have to use a conversion factor, we know that 1kJ=0.239Cal. Use this conversion factor to find the answer:

The correct answer is 808Cal.

Answer:

He proposed a model of the atom that consisted of a positively charged sphere with negatively charged electrons embedded in it. This model was later called the plum pudding model. Thomson’s discovery of the electron showed that atoms were not indivisible, as previously thought, but composed of smaller subatomic particles. His model also explained some phenomena such as cathode rays and electric currents. Thomson’s work helped advance our understanding of the structure and nature of the atom.

Explanation:

The balanced molecular equation for the reaction between solid aluminum and a solution of copper(II) chloride is: 2Al(s) + 3CuCl2(aq) → 3Cu(s) + 2AlCl3(aq).

Aluminium and copper(II) chloride react very vigorously, causing the reaction mixture to become extremely hot as heat is produced, the aluminium foil to dissolve, a reddish brown solid to appear, and gas bubbles to be released.

The aluminium foil disintegrates, heat is released, the copper(II) ions' blue colour disappears, and a new, reddish-brown solid develops in the reaction mixture.

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