Answer:
The length is \(s = 3.73 \ m\)
Explanation:
From the question we are told that
The speed is \(v = 3.054 \ m/s\)
The acceleration \(a = -0.7762 m/s^2\)
The time taken is \(t = 1.51 \ s\)
Generally from kinematics equation the length of the inclined plane is mathematically represented as
\(s =ut + \frac{1}{2} * at^2\)
=> \(s = 3.054 *1.51 + \frac{1}{2} * (-0.7762) *(1.51)^2\)
=> \(s = 3.73 \ m\)
easy one giving brainly if correct + detailed
Answer:
to the substance being heated
if a substance changes from a vapor to a liquid it ____ HELP FAST
Answer:
Explanation:
Condensing is the word used to indicate the change of state of a substance from vapor to liquid, as in this case. During condensation, the substance releases thermal energy to the environment, therefore the kinetic energy of the molecules in the vapor decreases until they become closer to each other and they start to be affected by the intermolecular forces and so the substance becomes a liquid.
Laser light passing through two small slits produces a bright fringe centered at the midpoint on a distant screen because the light from one slit traveled exactly one wavelength farther than the light from the other slit to get to the midpoint. the slit spacing is large compared to the distance to the screen. the light waves travel the same distance from each slit to the midpoint. the laser light is monochromatic
The monochromatic laser light passing through two small slits with large spacing produces a bright fringe at the midpoint on a distant screen due to constructive interference, which occurs when the light from one slit travels exactly one wavelength farther than the light from the other slit, and both light waves reach the midpoint in phase.
The phenomenon described in your question is known as interference. When a laser beam passes through two small slits that are very close to each other, the light waves interfere with each other and create a pattern of bright and dark fringes on a distant screen. The bright fringe that is centered at the midpoint is caused by constructive interference, where the crests of the waves from one slit coincide with the crests of the waves from the other slit. This occurs because the distance traveled by the light from one slit to the midpoint is exactly one wavelength longer than the distance traveled by the light from the other slit.
It's important to note that for this phenomenon to occur, the slit spacing must be large compared to the distance to the screen, and the laser light must be monochromatic (meaning it contains only one wavelength). Additionally, the light waves must travel the same distance from each slit to the midpoint. These conditions are necessary for the waves to interfere constructively and create a visible interference pattern on the screen.
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A block attached to a spring with unknown spring constant oscillates with a period of 1.8 s . Parts A to D are independent questions, each referring to the initial situation.
Part A
What is the period if the mass is doubled?
Express your answer to two significant figures and include the appropriate units.
T = Part B
What is the period if the mass is halved?
Express your answer to two significant figures and include the appropriate units.
T = Part C
What is the period if the amplitude is doubled?
Express your answer to two significant figures and include the appropriate units.
T = Part D
What is the period if the spring constant is doubled?
Express your answer to two significant figures and include the appropriate units.
A) The period (T) will be approximately 2.6 s if the mass is doubled.
b) The period (T) will be approximately 1.3 s if the mass is halved.
c) The period (T) remains unchanged if the amplitude is doubled.
d) The period (T) remains unchanged if the spring constant is doubled.
For a mass-spring system undergoing simple harmonic motion, the period of oscillation is given by the formula:
T = 2π * √(m/k)
where T is the period, m is the mass of the block, and k is the spring constant.
Part A:Period (T) = 1.8 s, Mass (m) = 2m (doubled)
Using the formula:
T = 2π * √(m/k)
Substituting the given values:
1.8 = 2π * √(2m/k)
Solving for T:
1.8 / (2π) = √(2m/k)
Square both sides:
(1.8 / (2π))² = 2m/k
Simplifying:
(1.8²) / (4π²) = 2m/k
Solving for T:
T = (1.8² * k) / (4π² * 2m)
Calculating:
T ≈ (3.24 * k) / (12.57 * m)
Part B:
Period (T) = 1.8 s
Mass (m) = 0.5m (halved)
Using the formula:
T = 2π * √(m/k)
Substituting the given values:
1.8 = 2π * √(0.5m/k)
Solving for T:
1.8 / (2π) = √(0.5m/k)
Square both sides:
(1.8 / (2π))² = 0.5m/k
Simplifying:
(1.8²) / (4π²) = 0.5m/k
Solving for T:
T = (0.9² * k) / (4π² * 0.5m)
Calculating:
T ≈ (0.81 * k) / (12.57 * m)
In Part C, the period remains unchanged because the period of oscillation in simple harmonic motion is only dependent on the mass and spring constant, not the amplitude.
In Part D, the period also remains unchanged because the period of oscillation is independent of the spring constant.
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Thiết bị nào sau đây không phải là nguồn điện
A. Ắc quy
B. Pin
C. Máy phát điện
D. Bóng đèn điện
A specified volume of space contains an electric field for which the magnitude is given by E=E0cos(ωt). Suppose that E0 = 20 V/m and ω = 1.0 × 107 s−1. What is the maximum displacement current through a 0.40 m2 cross-sectional area of this volume?
Answer: \(0.708\ mA\)
Explanation:
Given
\(E_o=20\ V/m\)
\(\omega =10^7\ s^{-1}\)
Cross-sectional area \(A=0.40\ m^2\)
Current density is given by
\(J=\epsilon_o \dfrac{dE}{dt}\)
Displacement current
\(\Rightarrow I=JA\\\Rightarrow I=8.854\times 10^{-12}\times 20\times 10^7\times 0.4\\\Rightarrow I=0.708\times 10^{-3}\ A\)
The required value of the maximum displacement current of the given space is \(7.08 \times 10^{-4} \;\rm A\).
Given data:
The intensity of electric field is, \(E_{0}=20 \;\rm V/m\).
The angular frequency of electric field is, \(\omega=1.0 \times 10^{7} \;\rm s^{-1}\).
The cross-sectional area of space is, \(A =0.40 \;\rm m^{2}\).
In the given problem, the instantaneous electric field is given by \(E = E_{0} \times cos(\omega t)\)
So, the expression for the current density is,
\(J= \epsilon_{0} \times \dfrac{dE}{dt}\)
Here, \(\epsilon_{0}\) is the permittivity of free space. Solving as,
\(J= \epsilon_{0} \times \dfrac{d(E_{0} \times cos(\omega t))}{dt}\\\\J= -\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)\)
And the expression for the maximum displacement current is,
\(I = J \times A\)
And the maximum displacement current is possible only when, J is positive and J will be positive for \(sin(\omega t)=-1\).
Then solving as,
\(I = (-\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)) \times A\\\\I = (-8.85 \times 10^{-12} \times 20 \times (1.0 \times 10^{7}) \times (-1)) \times 0.40\\\\I = 7.08 \times 10^{-4} \;\rm A\)
Thus, we can conclude that the required value of the maximum displacement current of the given space is \(7.08 \times 10^{-4} \;\rm A\).
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You
are working with a PLM set up with crossed polars. How does the
addition of a polarizer lead to plane-polarized light? How does the
addition of an analyzer lead to crossed polars and a black
backg
1. Unpolarized light is made up of of light waves vibrating in all possible directions perpendicular to the path of propagation.
2. The analyzer is a second type of filter.
How the addition of a polarizer lead to plane-polarized light?Plane-polarized light is a type of light wave in which the electric field vibrations are constrained to a single plane.
This means that the electric field vectors of the light wave all vibrate in the same direction, perpendicular to the direction of propagation of the light wave.
Plane-polarized light can be created by passing unpolarized light through a polarizer. A polarizer is a material that allows only light waves with electric field vibrations parallel to a certain direction to pass through.
How the addition of an analyzer lead to crossed polars and a black backWhen plane-polarized light passes through an analyzer whose transmission axis is perpendicular to the transmission axis of the polarizer, all of the light is blocked.
This is because the electric field vibrations of the plane-polarized light are no longer parallel to the transmission axis of the analyzer. This is why when you have crossed polars, you see a black background.
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Question
You are working with a PLM set up with crossed polars. How does the addition of a polarizer lead to plane-polarized light? How does the addition of an analyzer lead to crossed polars and a black background?
to unknown resistance are connected into grams of a metre bridge the null point is obtained at 40 cm from
The value of the smaller resistance (R₁) of the two resistances is 24 Ω.
To solve this problem, let's denote the unknown resistances as R₁ and R₂, with R₁ being the smaller resistance. We'll use the principle of the meter bridge to determine their values.
In the balanced condition, the ratio of the resistances is given by:
R₁/R₂ = l1/l2
Where l1 and l2 are the lengths of the bridge wire on the left and right sides of the null point, respectively.
Given:
Length of the meter bridge wire = 100 cm
Null point position without the 30 Ω resistor = 40 cm
Null point position with the 30 Ω resistor = 80 cm (shifted by 20 cm)
Using the above equation for both cases, we have:
R₁/R₂ = l1/l2 ... (Equation 1)
(R₁ + 30)/R₂ = (100 - l1)/(100 - l2) ... (Equation 2)
Substituting the given values, we get:
R₁/R₂ = 40/60 ... (Equation 3)
(R₁ + 30)/R₂ = 60/40 ... (Equation 4)
Simplifying Equation 3 and Equation 4, we have:
R₁/R₂ = 2/3 ... (Equation 5)
(R₁ + 30)/R₂ = 3/2 ... (Equation 6)
From Equation 5, we can write:
R₁ = (2/3)R₂ ... (Equation 7)
Substituting Equation 7 into Equation 6, we get:
(2/3)R₂ + 30 = (3/2)R₂
Multiplying both sides by 6 to eliminate fractions:
4R₂ + 180 = 9R₂
5R₂ = 180
R₂ = 36 Ω
Substituting R₂ = 36 Ω into Equation 7, we can find R₁:
R₁ = (2/3)R₂
R₁ = (2/3)(36 Ω)
R₁ = 24 Ω
Therefore, the value of the smaller resistance (R₁) is 24 Ω.
Complete Question: Two unknown resistances are connected in two gaps of a meter-bridge. The null point is obtained at 40 cm from left end. A 30Ω resistance is connected in series with the smaller of the two resistances, the null point shifts by 20 cm to the right end. The value of smaller resistance in Ω is
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Playing shortstop, you pick up a ground ball and throw it to second base. The ball is thrown horizontally with a speed of 13 m/s directly toward point A. When the ball reaches the second baseman 0,44 s later, it is caught at point B. How far were you from the second baseman? What is the distance of the vertical drop, the distance between point A and point B.
You were approximately 5.72 meters away from the second baseman. The vertical drop or distance between point A and point B was approximately 0.4576 meters.
To determine the distance between you (the shortstop) and the second baseman, we can use the formula for horizontal distance (d) traveled by an object moving at a constant horizontal velocity:
d = v * t
where:
- d is the horizontal distance traveled,
- v is the horizontal velocity of the ball,
- t is the time taken.
Given that the horizontal velocity (v) is 13 m/s and the time (t) is 0.44 s, we can calculate the horizontal distance (d) as follows:
d = 13 m/s * 0.44 s = 5.72 meters
So, you were approximately 5.72 meters away from the second baseman.
To find the vertical drop or the distance between point A and point B, we need to calculate the vertical component of the ball's motion. Since the ball is thrown horizontally, it will experience a constant vertical acceleration due to gravity.
The formula to calculate the distance (d) traveled vertically in free fall is:
d = 1/2 * g * t²
where:
- d is the vertical distance traveled,
- g is the acceleration due to gravity (approximately 9.8 m/s²),
- t is the time taken.
Given that the time (t) is 0.44 s, we can calculate the vertical distance (d) as follows:
d = 1/2 * 9.8 m/s² * (0.44 s)² = 0.4576 meters
So, the vertical drop or the distance between point A and point B is approximately 0.4576 meters.
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In slippery conditions, if you turn too fast or hard and the back of your vehicle swerves, ease off the accelerator and ______ in the direction you want the vehicle to go.
Circle the letter of each factor that determines whether a molecule
is polar or nonpolar.
a. the number of atoms in the molecule
b. the type of atoms in the molecule
c. the number of bonds in the molecule
d. the shape of the molecule
How many more neutrons are in a I SOTOPE of copper-14 than in standard carbon atom
Answer:
2 more neutrons
Explanation:
To obtain the answer to the question, let us calculate the number of neutrons in carbon–14 and standard carbon (i.e carbon–12). This can be obtained as follow:
For carbon–14:
Mass number = 14
Proton number = 6
Neutron number =?
Mass number = Proton + Neutron
14 = 6 + Neutron
Collect like terms
14 – 6 = Neutron
8 = Neutron
Neutron number = 8
For carbon–12:
Mass number = 12
Proton number = 6
Neutron number =?
Mass number = Proton + Neutron
12 = 6 + Neutron
Collect like terms
12 – 6 = Neutron
6 = Neutron
Neutron number = 6
SUMMARY:
Neutron number of carbon–14 = 8
Neutron number of carbon–12 = 6
Finally, we shall determine the difference in the neutron number. This can be obtained as follow:
Neutron number of carbon–14 = 8
Neutron number of carbon–12 = 6
Difference =?
Difference = (Neutron number of carbon–14) – (Neutron number of carbon–12)
Difference = 8 – 6
Difference = 2
Therefore, carbon–14 has 2 more neutrons than standard carbon (i.e carbon–12)
A 0.080-kg egg test dummy is fitted with a helmet and attached to a swing. This egg test dummy is pulled back and released, allowing it to collide with a cement block. The impulse on the egg test dummy is - 0.39N.s is over an interval of 0.050 s. What is the magnitude of the force on the egg test dummy during this time interval?
Answer:
7.8 N
Explanation:
Applying,
I = Ft................. Eqaution 1
Where I = Impulse on the egg test dummy, F = Force on the egg test dummy during the time interval, t = time interval
make F the subject of the equation
F = I/t.................. Equation 2
From the question,
Given: T = -0.39 N.s, t = 0.050 s
Substitute these vales into equation 2
F = -0.39/0.050
F = -7.8 N
Hence the force that act on the egg test dummy is 7.8 N
A whale swims at a constant speed of 8 m/s for 17 s. What distance did the whale travel in km?
Answer:
0.136 kmExplanation:
whale speed = 8 m/s for 17 sec.
find distance traveled in km
distance = velocity x time
= 8 m/sec. x 17 sec.
= 136 meters x 1 km
1000 meters
= 0.136 km
Physical science help pls I struggling
The cost of using 50 W for one day or 24 hours is dollar 0.12. The cost of using 800 W for 1 hour is 0.08 dollar.
What is power?Power is the rate of work done energy of an object. Given that the cost of using 1 KWhr energy is dollar 0.10.
Then cost of using 50 W or 0.05 KW in 24 hours is
0.05 × 24 × 0.10 = 0.12 dollar
Cost of using 800 W or 0.08 KW per hour is 0.08 KWhr × 0.10 = dollar 0.08
Similarly, the cost of using 150 W in one month is find as follows:
150 W = 0.15 KW
energy used = 0.15 × 30 × 24 hrs
cost = 0.15 × 30 × 24 hrs × 0.10 = dollar 10.8
The energy causing a cost of 2.5 dollar is 2.5/0.10 = 25 KWhr
power = 25 KWHr/24 hrs = 1.04 KW.
The energy causing a cost of 4 dollars is 4/0.10 = 40 KWhr
power =40 KWHr/24 hrs = 1.6 KW.
The energy causing the cost of 3 dollars = 3/0.10 = 30 KWhr
then time = 30/100 W = 0.3 hr.
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A cross-country runner runs due east for 6 km, then changes course
to E25°N and runs another 9 km. To the nearest tenth of a
kilometre, how far is the runner from her starting point?
The runner is approximately 8.98 km away from her starting point.
To find the distance of the runner from her starting point, we can use the concept of vector addition and trigonometry.
Let's break down the runner's movement into two components:
Eastward component: The runner initially runs due east for 6 km. Since this is in the eastward direction, the magnitude of this component is 6 km in the positive x-direction.
Northward component: After changing course to E25°N, the runner runs another 9 km. This can be broken down into two components: northward and eastward.
Using trigonometry, we can determine the magnitudes of these components:
The northward component is given by 9 km * sin(25°).
The eastward component is given by 9 km * cos(25°).
Now, let's calculate the magnitudes of the components:
Northward component = 9 km * sin(25°) ≈ 3.80 km
Eastward component = 9 km * cos(25°) ≈ 8.13 km
To find the total displacement from the starting point, we can add the magnitudes of the components using vector addition. This can be visualized as creating a right-angled triangle, with the eastward and northward components as the two sides.
Applying the Pythagorean theorem, the total displacement (d) is given by:
d = √((eastward component)^2 + (northward component)^2)
=\(\sqrt{(8.13 km)^2 + (3.80 km)^2}\))
≈ \(\sqrt{(66.16 km^2 + 14.44 km^2}\))
≈ \(\sqrt{80.6 km^2}\)
≈ 8.98 km
Therefore, the runner is approximately 8.98 km away from her starting point.
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When velocity is negative and acceleration is negative, what happens to the object's motion?
Answer:
Speeds up at a negative direction
Explanation:
in the bungee jumping, the rubber rope is used to jump back and forth so that it will turn to original length, this is example of
"In the bungee jumping, the rubber rope is used to jump back and forth so that it will turn to original length, this is example of elasticity or elastic force."
If something is elastic, it can be stretched or compressed and still regain its original shape. Elasticity is the name of this quality. An elastic substance, like a bungee cord, resists changing shape when stretched or compressed.
A person performing a bungee jump typically does it from a height, so they begin with a lot of gravitational potential energy. The potential energy in his body is being transformed into kinetic energy as he falls downhill, helping him to accelerate his downward motion.
The object in motion is accelerating downward as a result of the uneven forces. The speed of the bungee jumper's fall is accelerating. Due to the unbalanced forces acting on the object, gravity and air resistance, the jumper falls with increasing speed.
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the quantum theory suggests that the stable orbits of electrons around a nucleus correspond to standing waves for the orbit. for a hydrogen atom, the radius of the ground state or the first orbit is the bohr's radius, 0.0529 nm. what is the wavelength of the ground state of the hydrogen atom? 0.1587 nm 0.0529 nm zero 0.1058 nm 0.3324 nm
A photon of light with a wavelength of 1.22 10 m interacts with a hydrogen atom that has an electron in the ground state.
What is hydrogen in its ground state?The lowest permitted energy level for hydrogen is the ground state, which also has no angular momentum. The most stable state was the 1s atomic orbital, which contained a single electron.
What is an atom's wavelength?The electron weighs 9.1 10 31 kg (m = 9.1 10 31 kg). We obtain a wavelength of 1010m, or about the size of an atom, from the de Broglie relation. Because of this, we may directly examine the atomic structure of a crystal using electron microscopes.
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CORRECT ANSWER GETS BRAINLIEST!!! (∩^o^)⊃━☆
Each of these simple machines work around a pivot point except the __________.
a.
lever
c.
wedge
b.
pulley
d.
wheel and axle
Answer:
C. Wedge
Explanation:
Answer:
GIVE THE PERSON ABOVE BRAINLIEST UwU
Explanation:
Two persons are applying forces on two opposite sides of a moving cart.
The cart still moves with the same speed in the same direction. What
do you infer about the magnitudes and direction of the forces applied.
Answer:
the force is very strong between
a parallel-plate capacitor has a plate separation of 4.00 mm. 1) if the material between the plates is air, what plate area is required to provide a capacitance of 3.00 pf? (express your answer to three significant figures.)
To get a capacitance of 3.00 pF with a plate separation of 4.00 mm and air between the plates, the plate area required is 1.062 × 10⁻⁵ m² (to 3 significant figures).
The plate separation, d = 4 mm. The capacitance, C = 3 pF = 3 × 10⁻¹² F.
We need to find the plate area, If the material between the plates is air, then the capacitance of a parallel plate capacitor can be given as:
\($$C = \frac{\varepsilon_0A}{d}$$\)
where, ε0 = permittivity of free space = 8.854 × 10⁻¹² F/m.
Substituting the given values in the above formula, we get:
\($$\begin{aligned}C &= \frac{\varepsilon_0A}{d}\\ 3 × 10^{-12} &= \frac{8.854 × 10^{-12} \text{ F/m} × A}{4 × 10^{-3} \text{ m}}\\ A &= \frac{3 × 4 × 10^{-3} \text{ m} × 8.854 × 10^{-12} \text{ F/m}}{8.854 × 10^{-12} \text{ F/m} × 10^{-12}}\\ &= 1.062 × 10^{-5} \text{ m}^2 \end{aligned} $$\)
Therefore, the plate area required to provide a capacitance of 3.00 pF is 1.062 × 10⁻⁵ m² (to three significant figures).
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A person drops two objects from the same height. One object weighs 15 N, and the other weighs 10 N. How does the mass of the objects relate to the force of gravity on them? A. The 10 N object has the same mass as the 15 N object. B. The 10 N object has more mass than the 15 N object. C. The 15 N object has twice the mass of the 10 N object. D. The 15 N object has more mass than the 10 N object. SUR
Answer:
Your answer would be D :)
Explanation:
An object with a higher mass will always fall faster due to gravity acting upon it. 15 N is more massive than the 10 N object, so statement D is correct.
What do scientists hope to learn from missions to visit asteroids?
Answer:
The mission will help scientists investigate how planets formed and how life began, as well as improve our understanding of asteroids that could impact Earth.
Explanation:
Hope this helps :)
Question 4 of 10
When you go along with a group because you don't want to cause trouble, it is
called:
A. informational social influence.
B. normative social influence.
C. attribution
.
D. fundamental social influence.
Answer:
Normative
Explanation:
It is normal occurance but not unnatural
Describe 2 potential problems or limitations of ratio
analysis.
The temperature of 150 grams of water is 25°C. How much energy must be added to this in order to raise the temperature of the water to 55°C? 3,695 cal 450 cal 8,275 cal 4,500 cal
The additional energy density required to get the water's temperature up to 55 degrees is 4,500 cal.
How much energy is required to heat 1 gramme of water by 100 degrees Celsius?1 g of water requires 100 calories to heat from its freezing point of 0 C to its boiling temperature of 100 C. However, in order to turn 1 g of water at 100 °C into 1 g of water vapour at 100 °C, 540 calories of energy are needed. The latent heat of vaporisation is what is causing this.
Water has an energy density of 1 calorie/gram/°C. As a result, the amount of energy needed to raise 150 grammes of water's temperature by 30 degrees Celsius (from 25 to 55 degrees Celsius) can be estimated as follows:
Energy = (mass of water) x (change in temperature) x (specific heat capacity of water)
Energy = 150 g x 30°C x 1 cal/g/°C
Energy = 4,500 calories
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why is it more difficult to stop a sled carrying 2 people on than to stop a sled carrying 1 person if both have the same velocity?
It is more difficult to stop a sled carrying 2 people on than to stop a sled carrying 1 person if both have the same velocity because the sled carrying 2 people has more mass.
The greater the mass of an object, the greater the force required to change its velocity or stop it entirely.
What is the difference between mass and velocity? The difference between mass and velocity is as follows:
Mass is the amount of matter that an object possesses, whereas velocity is the rate at which an object changes position over time. Mass is a scalar quantity that represents an object's resistance to changes in motion, whereas velocity is a vector quantity that represents the rate and direction of motion.
Difficulty in stopping a sled with two persons. The sled with two people has more mass than the sled with one person. It is therefore more difficult to stop. When a sled is sliding on the snow, the force of friction between the sled's runners and the snow is what keeps it from slipping uncontrollably.
As the force of friction opposes the sled's motion, it generates a force that opposes the sled's forward movement. When there are two people on the sled, there is more mass and therefore more resistance to the opposing force created by the friction. Therefore, it is more difficult to stop a sled carrying two people than to stop a sled carrying one person.
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do pennies or feathers have more volume?
Answer:
This relationship explains why you can easily lift a shoebox full of feathers but not one filled with pennies, even though both are the same size. A volume of pennies contains more mass than an equal volume of feathers. The relationship between mass and volume is called density.
A student lifts a basketball to a height of 6 feet and lets the ball drop to the ground. Which statement accurately compares the ball's energy at a height of 6 feet (at rest) and at a height of 2 feet (falling)?
A.
The ball's kinetic energy is the same at both heights, but its potential energy is different.
B.
The ball has less potential energy and more kinetic energy at 6 feet than at 2 feet.
C.
The ball's potential energy is the same at both heights, but its kinetic energy is different.
D.
The ball has more potential energy and less kinetic energy at 6 feet than at 2 feet.
Answer:C
Explanation:
If you are holding the ball that would be the ball would have potential energy since it it not moving. Once you drop the ball it will have kinetic energy since it’s moving. If you drop the ball from 6ft it will have more kinetic since it will have more time to accelerate. If you drop the ball from 2ft then it will have less kinetic energy since it is closer to the ground and won’t have beeping time to accelerate and get rid of the potential energy.
Answer:
c
Explanation: