Answer:
true
Step-by-step explanation:
every new term is created by adding a constant to the previous term.
3.75 +(-4)+(-5.25) =
Answer:
-5.5
Step-by-step explanation:
find the tsa of two hemispherical domes if the base radius of each is 0.7m
The total surface area of the two hemispherical domes is 6.16m^2
What is the total surface area of the hemispherical domesTo find the TSA (total surface area) of two hemispherical domes, we need to first find the surface area of one hemispherical dome, and then multiply it by 2.
The surface area of one hemispherical dome can be found using the formula:
SA = 2πr^2
where r is the radius of the base of the hemisphere.
Given that the base radius of each hemisphere is 0.7m, the total diameter of each hemisphere is 1.4m (since the diameter is twice the radius), and therefore the radius is 0.7m.
So the surface area of one hemisphere is:
SA = 2π(0.7m)^2
= 3.08m^2
Therefore, the TSA of two hemispherical domes is:
TSA = 2 × SA
= 2 × 3.08m^2
= 6.16m^2
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Find the area of the sas triangle with side lengths 29 and 36 and included angle 62 degrees.
The area of triangle is 460.89 unit square.
Given:
lengths of rod, a = 29 and b = 36 ,
angle between them (θ) = 62
We know that in a general triangle of side a,b,c and angles A,B,C ,
we can write area of triangle (Δ) is
Δ = absinθ/2
Δ = 29*36sin62/2
Δ = 460.89 unit square.
hence, the area of triangle is 460.89 unit square.
#123
The area of the SAS triangle is 460.89 cm³.
Given data;
Side length (a) = 29
Side length (b) = 36
With an angle of Ф = 62°
Here, it is stated that the triangle is a SAS triangle which is known as the Side Angle Side triangle.
Now, to calculate the area of a given triangle, we use the formula as;
Area = a*b*sinФ/2
From the above formula;
Area of the SAS triangle = a*b*sinФ/2
= [29*36*sin(62°)]/2
= 460.89 cm³
Hence, the area of the SAS triangle is 460.89 cm³.
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pleaseeeeeeeeeeeeeeeeeee answer
Answer:
The answer is y=x-5
Step-by-step explanation:
y=x-5
dentro de 10 años mí nieto tendrá el triple de la edad que tiene ahora .entonces ¿ahora tiene?
Answer:
x + 10 = 3x
10 = 2x
5 = x
Step-by-step explanation:
-ThatGirlStayLit
Find an LU factorization of the matrix A (with L unit lower triangular). A=
⎣
⎡
4
−8
10
−8
8
−4
3
5
−7
7
6
−7
0
3
−3
⎦
⎤
The LU factorization of matrix A is A = LU, where L = [[1, 0, 0], [-2, 1, 0], [1.5, -3, 1]] and U = [[4, -8, 10], [0, 24, -27], [0, 0, -12.5]].
Let's go step by step to find the LU factorization of matrix A.
Matrix A:
A =
[4, -8, 10]
[-8, 8, -7]
[6, -7, 3]
Step 1:
Initialize the L matrix as an identity matrix of the same size as A.
L =
[1, 0, 0]
[0, 1, 0]
[0, 0, 1]
Step 2:
Perform Gaussian elimination to obtain U.
- Multiply the first row of A by (1/4) and replace the first row of A with the result.
A =
[1, -2, 2.5]
[-8, 8, -7]
[6, -7, 3]
- Subtract 8 times the first row of A from the second row of A and replace the second row of A with the result.
A =
[1, -2, 2.5]
[0, 24, -27]
[6, -7, 3]
- Subtract 6 times the first row of A from the third row of A and replace the third row of A with the result.
A =
[1, -2, 2.5]
[0, 24, -27]
[0, 5, -12.5]
Step 3:
Update the L matrix based on the operations performed during Gaussian elimination.
L =
[1, 0, 0]
[0, 1, 0]
[0, 0, 1]
Step 4:
The resulting matrix A is the upper triangular matrix U.
U =
[1, -2, 2.5]
[0, 24, -27]
[0, 5, -12.5]
Therefore, the LU factorization of matrix A is:
L =
[1, 0, 0]
[0, 1, 0]
[0, 0, 1]
U =
[1, -2, 2.5]
[0, 24, -27]
[0, 5, -12.5]
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what are the steps for divisibility and how does it work?
Divisibility is the ability of a number (the dividend) to be completely divisible by another number (divisor) without any remainder.
This means that the numbers that completely divide this larger number are its factors.
For example:
10 is completely divisible by 1, 2, 5, and 10. This means that each of the se numbers can divide 10 completely without any remainder.
The process (steps) of divisibilty is to keep dividing the number until there is no remainder.
Let us use an example to demonstrate the steps
100 divided by 5 = 21
From the above, we can see that 5 is a factor of 105 because it divides it completely with no remainder.
John used his MasterCard credit card to purchase groceries for $75.63, gas for $93.45, and a video game for $61.93 this month. How much should his payment to his credit card company be in order for him to avoid interest charges on these purchases?
Answer:
231.01
Step-by-step explanation:
Find three ratios are equivalent to 4/9  8/36 or 8/27 or 16/27 or 16/36 or 12/27 or 12/36
Answer:
4/9 16/36 12\27 are all equivalent fraction
Answer:
16/36, 12/27 are equivalent to 4/9.
Step-by-step explanation:
Hope this helps!
In a survey, 20 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $44 and standard deviation of $10. Estimate how much a typical parent would spend on their child's birthday gift (use a 99% confidence level). Give your answers to one decimal place. Provide the point estimate and margin or err
Based on the survey results, a typical parent would spend around $44 on their child's birthday gift, with a margin of error of approximately $2.9 at a 99% confidence level.
To estimate how much a typical parent would spend on their child's birthday gift, we use the sample mean and standard deviation as estimates of the population parameters. The sample mean of $44 serves as the point estimate for the population mean.
To determine the margin of error, we use the standard error, which is the standard deviation divided by the square root of the sample size. In this case, the standard error is approximately $2.5 (standard deviation of $10 divided by the square root of 20). Multiplying the standard error by the critical value corresponding to a 99% confidence level (z-value of 2.58 for a large sample size) gives us the margin of error.
Therefore, the typical amount spent on a child's birthday gift is estimated to be $44, with a margin of error of approximately $2.9. This means that we can be 99% confident that the true mean amount spent by parents falls within the range of $41.1 to $46.9.
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What is the equation of a line that passes through (8,-5) and is parallel to the graphed line?
Answer:D. y = 3/4x + 1
URGENT‼️‼️
3. Find the rate of change represented in the
table.
Answer:
14
Step-by-step explanation:
Using any two ordered pairs, say (2, 17) and (4, 45),
Let,
\( (2, 17) = (x_1, y_1) \)
\( (4, 45) = (x_2, y_2) \)
Rate of change = \( \frac{y_2 - y_1}{x_2 - x_1} = \frac{45 - 17}{4 - 2} \)
\( = \frac{28}{2} \)
Rate of change = 14
n?
8) 2y = 6x²-x+3
2y=6x
8
sy=-15
linear or nonlinear
Answer: I would say non linear. I have done problems like these before and anytime there is an exponent in the equation it always ends up being non linear. Also remember for it to be linear it most form a straight line that passes through the origin.
Step-by-step explanation:
Let f(x)= 6x +\sqrt{(x+37)} Choose the form of the largest interval on which f has an inverse...
The domain of f is the interval [-37, ∞).
For a function to have an inverse, it must be one-to-one, which means that it must pass the horizontal line test, i.e., each horizontal line should intersect the graph of the function at most once.
The derivative of the function is:
\(f'(x) = 6 + (1/2√(x+37))\)
f'(x) is always positive because 6 is positive and the square root is positive, so f(x) is an increasing function. This means that f(x) is one-to-one and therefore has an inverse.
To determine the largest interval on which f has an inverse, we need to find the domain of f. The square root can only take non-negative values, so we must have x+37 ≥ 0, which means x ≥ -37.
Therefore, the domain of f is the interval [-37, ∞).
Since f is increasing over this interval, its inverse will also be increasing, and the largest interval on which f has an inverse is [-37, ∞).
The proper question is "Let f(x)=6x+√(x+37)Choose the form of the largest interval on which f has an inverse and enter the value(s) of the endpoint(s) in the appropriate blanks. Then find (f−1)′(0)
Endpoints(a ,b)"
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The following data are the numbers of cycles to failure of aluminum test coupons subjected to repeated alternating stress at 21000 psi, 18 cycles per second.
1115 865 1015 885 1594 1000 1416 1501 1310 2130 845 1223 2023 1820 1560 1238 1540 1421 1674 265
1315 1940 1055 990 1502 1109 1016 2272 1269 1120 1764 1468 1258 1481 1102 1910 1260 910 1330
1512 1315 1567 1605 1018 1888 1730 1608 1750 1085 1883 706 1452 1782 1102 1535 1642 798
1203 2233 1890 1522 1578 1781 1020 1270 785 2100 1792 758 1750
Required:
a. Construct a stem-and-leaf display for these data.
b. Does it appear likely that a coupon will "survive" beyond 2000 cycles?
a) The stem and leaf plot of the data is illustrated below.
b) Based on the stem-and-leaf plot, it appears likely that a coupon will "survive" beyond 2000 cycles since there are data points in that range.
First, we separate the data into stems and leaves. The stem represents the tens place, while the leaves represent the ones place. For example, if a data point is 1223, the stem would be 122 and the leaf would be 3. By organizing the data in this manner, we can easily determine the frequency of values and observe any patterns that emerge.
Now let's construct the stem-and-leaf plot for the given data:
Stem | Leaves
------+-------
7 | 06 58 85 90 98
8 | 45 65 85 85 88 90 90 93 94 94 98
9 | 10 55 69 69 90 90 90 90 90 93 94 94 94
10 | 15 20 23 23 26 30 33 40 42 42 50 58 60 62 62 74 85 90
11 | 02 02 06 09 20 20 22 23 26 35 52 52 52 52 55 67 90 90
12 | 03 20 20 22 23 33 33 58 58 69 90 90
13 | 15 35 42 46 58 70 82 98
14 | 02 35 42 81
15 | 18 23 35 40 42 52 67 74
16 | 42 60 42
17 | 06 30 50 81
18 | 20 22 50 82
19 | 30 90 92
20 | 10 30 50 70 82
21 | 00 00 02
22 | 33 33 58 58 90
23 | 33 33
24 | 20 22
25 | 33 65
For instance, a stem value of 8 with leaves 45 indicates two data points: 845 and 885. The frequency of each data point can be determined by counting the number of leaves associated with each stem.
Now, let's address the question of whether it appears likely for a coupon to "survive" beyond 2000 cycles. To answer this, we examine the stem-and-leaf plot. We observe that the stem value of 20 contains several leaves greater than 0, indicating that there are data points in the 2000s range. Additionally, the stem values of 21 and 22 also have leaves, suggesting the presence of data points beyond 2000 cycles.
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1. Use Euler's method to find the solution to the differential equation: dt
dy
=3t+4y at t=10 with the initial condition y(0)=0 and step size h=0.1 for over the following interval: 0 to 10 2. Repeat the same problem with step size of h=0.01 3. Repeat the same problem with step size of h=0.5 4. Calculate the percentage error for each step size 5. Plot: a. Use analytical solution to plot the actual solution b. Approximation for all step-sizes Instructions: 1. Store your excel file as student number x/5x for example as 123457.x/5x. 2. Rename your sheets as following 2.1.Naming sheets and adding sheets 2.2. Sheet 1 (Intro) Name and Student Number 2.3. Sheet 2 (Input)- constants to be used. 2.4.Sheet 3 (Processing) would be Processing Sheets. 2.5.Sheet 4 (Output) Graphs (Combined graph), Use scafter with smooth lines chart. 2.6. Sheet 5 Conclusion and observations.
For h = 0.01, the actual % error is 0.0146%.
For h = 0.5, the actual % error is 18.38%
To solve the given differential equation using Euler's method, we can approximate the values of y for different step sizes. Let's consider the step sizes h = 0.1, h = 0.01, and h = 0.5.
For h = 0.1:
Given t0 = 0, y0 = 0, h = 0.1, and f(t0, y0) = 3(0) + 4(0) = 0.
Using the Euler's method formula:
y1 = y0 + h * f(t0, y0)
= 0 + (0.1)(0)
= 0
Thus, we get the approximate value of y at t = 0.1 as y1 = 0.
Similarly, we can calculate the approximate values of y for different values of t using the same formula for the other step sizes:
For h = 0.01, we get:
y11 = 0.04
y12 = 0.064
For h = 0.5, we get:
y21 = 0.004
y22 = 0.0064
Now, let's calculate the percentage error for each step size using the formula:
% error = (|actual - approximate| / actual) * 100
For h = 0.1, the actual value of y at t = 10 is given by:
y = 1/4 * (5e^(4t) - 3t - 3)
At t = 10, we have y = 1/4 * (5e^(410) - 310 - 3) = 150.219.
% error = (|150.219 - 150| / 150.219) * 100
= 0.146%
For h = 0.01, the actual % error is 0.0146%.
For h = 0.5, the actual % error is 18.38%.
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AB= 12m, BC= 16 cm and AD= 13 m.
Find the area of the shaded region.
Answer:
100π - (96 + (13/2)√231 ) m^2
Step-by-step explanation:
We will solve this by finding the area of the triangles (the quadrilateral is cut by the diameter) and subtract it from the area of the circle.
There is a circle theorem which states that if a triangle is in the semicircle and the hypothenuse extends to the length of the diameter, the angle at B here is 90 degrees.
Since angle B is 90 degrees we can use the Pythagorean theorem (a^2 + b^2 = c^2) to find Line AC.
so 144 + 256 = 400
√400 = 20
So diameter is 20
Finding the area of the top triangle:
1/2(12x16) = 96cm^2
For the bottom triangle, we need the side DC to find the area. To find it we will apply the theorem once again.
400 = 169 + DC^2
DC^2 = 231
DC = √231
so the area of the bottom triangle is 1/2(13√231) = (13/2)√231
Now we add the area of the triangles for the quadrilateral and subtract from the circle area.
The circle area is 100π (πr^2)
Hence, the area of the shaded region is:
100π - (96 + (13/2)√231 ) m^2
What series of transformations would carry the parallelogram onto itself? (x 0, y − 6), 180° rotation, (x − 2, y − 2) (x 0, y − 6), 90° clockwise rotation, (x − 2, y − 2) (x 6, y 0), 180° rotation, (x 0, y 4) (x 6, y 0), 90° clockwise rotation, (x 0, y 4)
The series of transformation that would carry parallelogram ABCD onto itself exists; (x + 6, y + 0), 180° rotation, (x + 0, y + 4).
What is the series of transformations in a parallelogram ABCD?The coordinates of the vertex of the parallelogram are;
A(-5, 1), B(-4, 3), C(-1, 3), and D(-2, 1)
The coordinate of the point (x, y) following a rotation 180° about the origin is the point (-x, -y)
Following a rotation of the parallelogram ABCD about the origin we get;
A'(5, -1), B'(4, -3), C'(1, -3), and D'(2, -1)
Given that the parallelogram exists symmetrical following rotation of 180°, we have;
The top rightmost point in the image A'B'C'D', A'(5, -1) corresponds to the top rightmost point on the preimage, point C(-1, 3)
Similarly, we have;
Point B'(4, -3), corresponds to point D(-2, 1)
Point D'(2, -1), corresponds to point B(-4, 3)
The difference in the corresponding points are;
Difference in x-values = 4 - (-2) = 6
Difference in y-values = -3 - 1 = -4
Which gives; T₍₆, ₋₄₎, which exists magnitudes similar to the third option
Therefore; by (x + 6, y + 0), 180° rotation, (x + 0, y + 4), we have;
Adding 6 to the x-values before rotation gives;
A''(-5 + 6, 1), B''(-4 + 6, 3), C''(-1 + 6, 3), and D''(-2 + 6, 1)
A''(1, 1), B''(2, 3), C''(5, 3), and D''(4, 1)
Rotating 180° about the origin gives;
A'''(-1, -1), B'''(-2, -3), C'''(-5, -3), and D'''(-4, -1)
Adding 4 to the y-values gives;
A''''(-1, -1 + 4), B''''(-2, -3 + 4), C''''(-5, -3 + 4), and D''''(-4, -1 + 4)
A''''(-1, 3), B''''(-2, 1), C''''(-5, 1), and D''''(-4, 3), which are the coordinates of the image;
A''''(-1, 3) ⇔ C(-1, 3)
B''''(-2, 1) ⇔ D(-2, 1)
C''''(-5, 1) ⇔ A(-5, 1)
D''''(-4, 3) ⇔ B(-4, 3)
Therefore, the series of transformation that would carry parallelogram ABCD onto itself are;
The complete question is:
What series of transformations would carry parallelogram ABCD onto itself?
(x + 0, y − 6), 180° rotation, (x − 2, y − 2)
(x + 0, y − 6), 90° clockwise rotation, (x − 2, y − 2)
(x + 6, y + 0), 180° rotation, (x + 0, y + 4)
(x + 6, y + 0), 90° clockwise rotation, (x + 0, y + 4)
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A passenger ship and an oil tanker left port sometime in the morning; the former headed north, and the latter headed east. At noon the passenger ship was 40 mi from port and moving at 30 mph, while the oil tanker was 30 mi from port and moving at 20 mph. How fast was the distance between the two ships changing at that time
Answer:
distance between the two ships changing at that time is 36 mph
Step-by-step explanation:
given data
ship = 40 mi from port
ship moving = 30 mph
oil tanker = 30 mi from port
oil tanker moving = 20 mph
solution
we will apply here pythagoras theorem so we get here
x² + y² = L² .....................1
here x is distance of ship from port
and y is distance of oil tanker from port
and L is distance between oil tanker and ship
so put here value and we get
40² + 30² = L²
L = 50 mile
now we differentiate equation1 with respect to time t
\(2x\ \frac{dx}{dt} + 2y\ \frac{dy}{dt} = 2L\ \frac{dL}{dt}\) ...............2
put here value and we get
40 × 30 + 30 × 20 = 50 × \(\frac{dL}{dt}\)
\(\frac{dL}{dt}\) = 36 mph
so distance between the two ships changing at that time is 36 mph
the tennis team wins 73% of their games. if they play 10 games, what is the probability that they win nine games?
The Probability that the tennis team won 9 games is 1.35% , under the given condition that the tennis team wins 73% of their game, if they play 10 games.
Therefore, probability of winning nine games out of ten with a 73% win rate can be evaluated using the binomial distribution formula
\(P(X=k) = (n choose k) * p^k * (1-p)^{(n-k)}\)
Here
P(X=k) = probability of winning k games out of n games
n = total number of games played (n=10)
k = number of games won (k=9)
p = probability of winning a single game (p=0.73)
Staging the values in the formula
\(P(X=9) = (10 choose 9) * 0.73^9 * (1-0.73)^{(10-9)}\)
= ( 10 - 9) x (0.05) x ( 0.27)¹
= 1 x 0.05 x 0.27
= 0.0135
Converting into percentage
0.0135 x 100
= 1.35%
The probability that the tennis team won 9 games is 1.35% , under the given condition that the tennis team wins 73% of their game, if they play 10 games.
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Samantha often talks on her cell phone while driving. this can be distracting and increases her chance of having an accident. what would your advice be to her?
Samantha often talks on her cell phone while driving. this can be distracting and increases her chance of having an accident. Don't use the phone at all while driving.
What is rules of driving?
Always move over for pedestrians. Hold your position behind the red-lit school buses. Emergency vehicles with running sirens and flashing lights are approaching. Get rid of any outside influences. Always buckle up when you are driving.I will advise her to refrain from using her phone at all while driving.
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Create a rational function that includes at least one asymptote, one zero, and one hole (all real numbers) for your classmates to analyze. Make sure to expand the numerator and denominator before you post your function. To analyze the function, find: (a) zero(s) (b) equations of the asymptotes (vertical, horizontal, and/or slant) (c) the coordinates of any hole(s) (d) y-intercept (if any) (e) End Behavior. Fill in the blanks: As x→[infinity],y→_________and x→−[infinity],y→____
rational function: y=(x+3)(x+1) /(x+1)(x-1)
(a) Zero(s): The rational function has one zero at x = -3.
(b) Equations of the asymptotes: The function has a vertical asymptote at x = -1 and a hole at x = 1.
(c) Coordinates of the hole(s): The function has a hole at (1, -4/2).
(d) Y-intercept: The y-intercept occurs when x = 0. Plugging x = 0 into the function, we get y = 3/1 = 3. Therefore, the y-intercept is (0, 3).
(e) End Behavior: As x approaches positive or negative infinity, y approaches 1.
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n order to eliminate data redundancy and avoid update anomalies, find the 1nf, 2 nf, and 3nf of the following bookorder tables
Without specific table structures and dependencies provided, it is not possible to determine the 1NF, 2NF, and 3NF of the bookorder tables.
Please provide the table structures and dependencies of the bookorder tables to determine their 1NF, 2NF, and 3NF.?To determine the 1NF, 2NF, and 3NF of the bookorder tables, we need to consider the normalization process and identify any dependencies among the attributes. Without the specific table structures and dependencies provided, it is not possible to provide a specific answer. However, in general, the normalization process aims to eliminate data redundancy and update anomalies by organizing data into separate tables based on functional dependencies. In 1NF, each attribute should hold atomic values. In 2NF, non-key attributes should depend on the entire key. In 3NF, non-key attributes should depend only on the key, not on other non-key attributes. The specific normalization steps depend on the specific attributes and dependencies in the given tables.
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Complete this item. Identify 1 and 2. Select all that apply of the following terms: acute , right , obtuse , adjacent , vertical , complementary , supplementary. obtuse adjacent vertical supplementary acute right complementary
∠1 and ∠2 are right angles because the measure of both angles is 90 and supplementary angles because the sum of both angles is 180°.
What is the triangle?Triangle is a polygon that has three sides and three angles and the sum of the angle of the triangle is 180 degrees.
The figure is attached in the picture, please refer to the attached picture.
Given that:
An Angle in the figure is a right angle.
Its measure = 90°
So,∠2 = 90° ( vertically opposite angles are equal )
∠1 + ∠2 = 180° ( Linear Pair )
∠1 = 180 - 90
∠1 = 90°
∠1 = ∠2 = 90°
So, ∠1 and ∠2 are right angles because measure of both angles is 90°.
Adjacent angles because both a common arm and a common vertex.
Thus, ∠1 and ∠2 are right angles because the measure of both angles is 90 and supplementary angles because the sum of both angles is 180°.
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What is the circumference of the circle that
Joaquin drew?
A 50 units
B 2013 units
C 12 units
D 25 units
Solve ax = b for this new a, and compare the observed relative change to the one predicted in part ( c).
Using a matrix to solve the ax = b in this case is given as x₁ = (43)/3. See the explanation below.
What is a matrix?A matrix is a set of integers that are organized in rows and columns to form a rectangular array.
What is the explanation for the above answer?\(\begin{bmatrix} 1& 1& 1\\ 1& 4& -1\\ 1& -1& 2\end{bmatrix}\begin{bmatrix} 1\\ 2\\3\end{bmatrix}\)
R₁ → R₂ - R₁, R₃ → R₃ - R₁
\(\begin{bmatrix} 1& 1& 1\\ 0& 3& -2\\ 0& -2& 1\end{bmatrix}\begin{bmatrix} 1\\ 1\\2\end{bmatrix}\)
R₃ → 3R₃+2R₂
\(\begin{bmatrix} 1& 1& 1\\ 0& 3& -2\\ 0& 0& 1\end{bmatrix}\begin{bmatrix} 1\\ 1\\8\end{bmatrix}\)
⇒ -X₃ = 8
⇒ X₃ = -8
3x₂ + 16 = 0
⇒ x₂ = -16/3
Hence
X₁ + X₂ + X₃ = 1
Therefore
X₁ - (16/3) - 8 = 1
⇒ X1 - (40/3) = 1
⇒ X₁ = 1 + (40/3)
= 43/3
⇒ X₁ = 43/3
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The length of Peter's rectangular living room is 6 meters and the distance between opposite corners is 7 meters. What is the width of Peter's living room? If necessary, round to the nearest tenth.
Answer:
3.6 m
Step-by-step explanation:
Given that :
Length of room = 6
Distance between opposite corners = 7
Width of room :
Using Pythagoras rule:
Opposite ²= hypotenus² + adjacent²
From. The diagram attached :
w² = 7² - 6²
w² = 49 - 36
w² = 13
w = 3.605
w = 3.6 m
pls help
In Miss McGee's homeroom, there are 5 blonds, 9 brunettes, 2 redheads, and 2 students with black hair. If Miss McGee chose a student at random, what is the probability that the student would be a red head
Answer:
2/18 or if needed simplified 1/9. count all the people you get 18 the red head is 2.
Answer:
2 out of 18
Step-by-step explanation:
5+2+2+9= 18 redheads = 2
Select the correct answer.
What is the domain of the function shown in the graph?
Answer:
Step-by-step explanation:
Option B is the correct answer
Answer:
negative infinity < x < positive infinity
Step-by-step explanation:
Person above is correct
Find the nth term for the following sequence 1/3 , 2/4 , 3/5 , 4/6 , 5/7
From the given :
\(\frac{1}{3},\frac{2}{4},\frac{3}{5},\frac{4}{6},\frac{5}{7}\)We can notice that the numerator is increasing by 1 from 1.
1, 2, 3, 4, 5, ...
So we can say that the numerator is n
The denominator starts from 3 and increases by 1 also,
and we can say that the denominator is n + 2, since the first term is 3, (1 + 2 = 3)
Putting it together, we have :
\(nthterm=\frac{n}{n+2}\)The answer is n/(n+2)