around a square with diagonal d = 4.6 cm a circle is described. Calculate the perimeter of the circle​

Answer:

Step-by-step explanation:

56.1,12.1,23.6

Answer:

4 = 12

Here is your answer.

Answer:

1x4=4

2x4=8

3x4=12

4x4=16

5x4=20

The scalar projection is 42/13, and the vector projection is 42/169⟨-5,12⟩.

The scalar projection of b onto a can be calculated using the formula \(\frac{a.b}{|a|}\), and the vector projection of b onto a can be calculated using the formula \(\frac{a.b}{|a|^{2} } .a\). The formula for finding the magnitude of a is |a| = √c²+d² if a = ⟨c,d⟩.

a = ⟨−5, 12⟩, b = ⟨4, 6⟩

a⋅b = ⟨−5, 12⟩⟨4, 6⟩

= -20 + 72

= 42

|a| = √[(-5)² + (12)²]

= √25 + 144

= √169

= 13

The scalar projection is

\(\frac{a.b}{|a|}\) = [⟨−5, 12⟩⟨4, 6⟩]/√[(-5)² + (12)²]

= [-20 + 72]/√25 + 144

= 42/√169

= 42/13

The vector projection is

\(\frac{a.b}{|a|^{2} } .a\) = [42/(13)²] ⟨−5, 12⟩

= 42/169⟨−5, 12⟩

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The 4 is the number the student thought about.

To solve this problem, we will use algebraic expressions. First, let us define the unknown number, x. The problem states that "4 times my number increased by 30 equals 70 decreased by the number." This can be translated into the following equation:

4x + 30 = 70 - x

To solve for x, we need to isolate it on one side of the equation. Let's start by moving all the terms with x to the left side and all the constant terms to the right side.

4x + x = 70 - 30x + 4x + x = 40

Simplifying, we get:

10x = 40

Dividing both sides by 10:

x = 4

Therefore, the number that the student thought of is 4.

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Answer:

-82

Step-by-step explanation:

84/21=4

-25x4=-100

-3x-6=18

-100+18=-82

ANSWER:

(a) 1698 bacterias

(b)

(c) 473 bacterias

STEP-BY-STEP EXPLANATION:

(a)

We can propose the following equation of the statement to calculate the initial number of bacteria, just like this:

(b)

Therefore, the function would be:

(c)

The number of bacteria after 10 days will be:

Answer:

the answer is 20cm

Step-by-step explanation:

Area = Length times width

a. Using the smallest possible number of items, is not generally a way to enhance reliability.

b. Measuring something that is minimally important, does not necessarily enhance reliability.

c. Aggregating measurements, is the generally useful way to enhance reliability.

d. Maximizing error variance, is not a way to enhance reliability.

Among the options provided, the generally useful way to enhance reliability is option c: to aggregate your measurements.

Aggregating measurements refers to combining multiple measurements or observations to improve the overall reliability of the data. By taking multiple measurements, you can reduce the impact of random errors and obtain a more accurate estimate of the true value or attribute you are measuring.

Option a, using the smallest possible number of items, is not generally a way to enhance reliability. In fact, having a larger sample size or more data points often improves reliability by reducing the effects of random variations.

Option b, measuring something that is minimally important, does not necessarily enhance reliability. The importance of what is being measured is not directly related to the reliability of the measurements. Reliability focuses on the consistency and accuracy of the measurements themselves.

Option d, maximizing error variance, is not a way to enhance reliability. Error variance refers to the variability or spread of errors in measurement. Maximizing error variance would lead to less reliable measurements as it increases the uncertainty and inconsistency of the data.

In summary, option c, aggregating measurements, is the generally useful way to enhance reliability.

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The angles pairs that match each of the stated angle relationship are:

∠2 and ∠11 → alternate interior angles

∠9 and ∠16 → alternate exterior angles

∠1 and ∠10 → No relationship

∠3 and ∠5 → consecutive interior angles

∠7 and ∠15 → corresponding angles

Alternate Interior angles are angles that are found lying inside different parallel lines that are crossed by a transversal but on alternate sides along the transversal.

Alternate exterior angles are similar to alternate interior angles, but are angles that lie outside different parallel lines that are crossed by a transversal but on alternate sides along the transversal.

Angles that are referred to as corresponding angles are angles that are at relative corners on different parallel lines that are cut across by a transversal.

The angles named in the image above can be marched as follows:

∠2 and ∠11 → alternate interior angles

∠9 and ∠16 → alternate exterior angles

∠1 and ∠10 → No relationship

∠3 and ∠5 → consecutive interior angles

∠7 and ∠15 → corresponding angles

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It will take him 2\(\frac{1}{4}\) hours to travel the entire distance between the two cities. The solution has been obtained by using the arithmetic operations.

What are arithmetic operations?

All real numbers are thought to be sufficiently described by the four basic operations, sometimes referred to as "arithmetic operations." The mathematical operations quotient, product, sum, and difference follow division, multiplication, addition, and subtraction.

It is given that a man traveled \(\frac{1}{3}\) of the distance between 2 cities in \(\frac{3}{4}\) of an hour.

So, using the multiplication, if he travels at the same rate, he will cover the entire distance in,

⇒ Time taken = \(\frac{3}{4}\) * 3

⇒ Time taken = \(\frac{9}{4}\)

⇒ Time taken = 2\(\frac{1}{4}\) hours

Hence, it will take him 2\(\frac{1}{4}\) hours to travel the entire distance between the two cities.

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The series Di-1 (31) evaluates to 31. the series L-1(-2i+6) evaluates to 0.the series Σ((-3):) evaluates to 0.

Given:Di-1 (31)Evaluating the series using summation properties and rules:We need to substitute the i value in the series as it starts from i=1 and ends at i=5.i = 1, Di-1 (31) = D₀(31) = 31i = 2, Di-1 (31) = D₁(31) = 0i = 3, Di-1 (31) = D₂(31) = 0i = 4, Di-1 (31) = D₃(31) = 0i = 5, Di-1 (31) = D₄(31) = 0

Therefore, the series is:Di-1 (31) = 31 + 0 + 0 + 0 + 0 = 31

Hence, the series Di-1 (31) evaluates to 31.

L-1(-2i+6)

Evaluating the series using summation properties and rules:We need to substitute the i value in the series as it starts from i=1 and ends at i=5.i = 1, L-1(-2i+6) = L-3 = 0i = 2, L-1(-2i+6) = L-1(2) = 4i = 3, L-1(-2i+6) = L₁(6) = 4i = 4, L-1(-2i+6) = L₃(10) = -4i = 5, L-1(-2i+6) = L₅(14) = -8

Therefore, the series is:L-1(-2i+6) = 0 + 4 + 4 - 8 = 0

Hence, the series L-1(-2i+6) evaluates to 0.

Σ((-3):)

Evaluating the series using summation properties and rules:We need to substitute the i value in the series as it starts from i=-3 and ends at i=3.i = -3, Σ((-3):) = -3i = -2, Σ((-3):) = -2 + -3i = -1, Σ((-3):) = -1 + -2 + -3i = 0, Σ((-3):) = 0 + -1 + -2 + -3 +i = 1, Σ((-3):) = 1 + 0 + -1 + -2 + -3 +i = 2, Σ((-3):) = 2 + 1 + 0 + -1 + -2 + -3 +i = 3, Σ((-3):) = 3 + 2 + 1 + 0 + -1 + -2 + -3 = -0

Therefore, the series is:Σ((-3):) = -3 - 2 - 1 + 0 + 1 + 2 + 3 = 0

Hence, the series Σ((-3):) evaluates to 0.

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In a turbidity current, submarine sediments flow chaotically downslope in submarine canyons.

Turbidity currents are powerful underwater currents that carry a mixture of water and sediment down submarine canyons and slopes. They are triggered by various mechanisms, such as earthquakes, landslides, or the sudden release of sediment from the seafloor. When these currents occur, they transport sediment in suspension, creating a turbid, muddy water column. As the current flows downslope, it moves with great force and velocity, eroding the canyon walls and depositing sediment along its path.

The sediments carried by turbidity currents can vary in size, ranging from fine silt and clay particles to larger sand and gravel. As the current slows down, it starts to deposit the sediments it carries, forming distinctive sedimentary features like graded bedding and turbidite sequences. Turbidity currents play a crucial role in shaping submarine landscapes, transporting sediment over long distances, and influencing the distribution of marine organisms. Understanding their dynamics and sediment transport processes is important for various scientific disciplines, including sedimentology, geology, and oceanography.

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The perimeter of the square is equal to 8 times the radius of the circle.

If the graph of the equation is a circle, we can determine the radius of the circle from the equation. Once we have the radius, we can find the side length of the square using the diameter of the circle, and then calculate the perimeter of the square.

Let's assume the equation of the circle is given as:

(x - a)^2 + (y - b)^2 = r^2

where (a, b) represents the center of the circle and r is the radius.

Since the circle is inscribed in a square, the diameter of the circle is equal to the side length of the square. Thus, the side length of the square is 2r.

The perimeter of the square is given by 4 times the side length:

Perimeter = 4 * 2r

= 8r

Therefore, the perimeter of the square is equal to 8 times the radius of the circle.

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Answer: I think it’s solid B

Step-by-step explanation:

solid B is easy to read and you can find carpet of those measurements a lot easier then solid A or C

The probability that Hannah's number is an even palindrome is 1/45.

There are 45 even palindrome numbers between 1000 and 9999, out of a total of 4500 possible 4-digit numbers.

So, the probability of Hannah writing an even palindrome number is 1/45.

A palindrome number is the same when read from left to right or right to left. There are 90 possible 2-digit palindrome numbers (11, 22, 33, etc.), and 9 possible 1-digit palindrome numbers (1, 2, 3, etc.), making a total of 99 palindrome numbers from 1 to 999. In a 4-digit number, the first and last digits must be the same for it to be a palindrome.

Therefore, the first digit has 9 choices (1-9), and the last digit also has 9 choices. The second digit can be any of the 10 digits (0-9), and the third digit can be any of the 5 remaining even digits (0, 2, 4, 6, 8).

Thus, there are 45 even palindrome numbers between 1000 and 9999.

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Answer:

52

Step-by-step explanation:

False.

The given statement "If a sample of n=5 scores has EX= 10 and EX2 = 100, then SS= 80" is a true statement.

Here is how we can prove it:

To calculate SS, we can use the formula below:

SS = \sum_{i=1}^{n}x_{i}^{2} - \frac{(\sum_{i=1}^{n}x_{i})^2}{n}

Given n = 5, EX = 10, and EX2 = 100

We know that:

EX = \frac{\sum_{i=1}^{n}x_{i}}{n}

Putting the given value of EX = 10, we can find out the value of sum of all n scores.

sum = EX \times n sum = 10 \times 5 sum = 50

Now,

we can use EX2 to find the value of sum of squares of all n scores.

EX2 = \frac{\sum_{i=1}^{n}x_{i}^{2}}{n}

Putting the given value of EX2 = 100, we can find out the value of sum of squares of all n scores.

sum of\;squares = EX2 \times n sum of\;squares = 100 \times 5

sum of\;squares = 500

Now, we can substitute the values of sum and sum of squares in the formula of SS.  

SS = \sum_{i=1}^{n}x_{i}^{2} - \frac{(\sum_{i=1}^{n}x_{i})^2}{n}

SS = 500 - \frac{50^2}{5}

SS = 500 - 500

SS = 0

Therefore, the value of SS is 0 which is not equal to 80.

Hence, the statement "If a sample of n=5 scores has EX= 10 and EX2 = 100, then SS= 80" is false.

False.

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Answer:

Step-by-step explanation:

the sum of the interior angles of a triangles is 180°

so

180 - 39 - 102 =

39

(it is an isosceles triangle)

In the given triangle the value of x° = 39°.

" A triangle is defined as the two dimensional closed shape with three sides , three vertices and three angles enclosed in it."

Theorem used

In ΔABC,

∠A + ∠B + ∠C = 180°

According to the question,

In the given triangle,

∠A represents measure of 102°

∠B represents measure of 39°

∠C represents measure of x°

Substitute the value in the triangle theorem   we get,

102° + 39° + x° = 180°

⇒141° + x° = 180°

⇒ x° = 180° - 141°

⇒ x° = 39°

Hence, in the given triangle the value of x° = 39°.

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Answer:

(1, 3)

Step-by-step explanation:

The substitution method basically means you are replacing anywhere “y” shows up in the first equation with what y equals in the second, which is 3x in this case.

2x + 5y = 17

2x + 5(3x) = 17

So, instead of the y, you’d use 3x. After, you can multiply the 5 and the 3:

2x + 15x = 17

Because 2x and 15x both have x, you can combine them:

17x = 17

And finally, you can divide!

17/17 = 1

x = 1

After that, you just replace “x” with 1 in either equation to get y. The second is simpler, so that’s what I’ve used here.

y = 3x

y = 3(1)

y = 3

Therefore, your answer is (1, 3).

Hope this helps!

After 2 hours, approximately 4.38 grams of Francium remain from the 480-gram sample.

What is Algebraic expression ?

An algebraic expression is a combination of variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division. It may contain one or more terms, with each term separated by a plus or minus sign. Algebraic expressions are used in algebra to represent mathematical relationships and formulas.

a) To write an exponential function that models the mass of Francium remaining after t minutes, we can use the formula:

N = N0 * \((1/2)^{(t / t1/2)}\)

where N is the amount remaining after time t, N0 is the initial amount, t1/2 is the half-life, and (t/t1/2) means raised to the power of t/t1/2.

In this case, the initial amount is 480 grams, the half-life is 22 minutes, and we want to find the amount remaining after t minutes. Therefore, the exponential function that models the mass of Francium remaining after t minutes is:

N = 480 * \((1/2)^{t/22}\)

b) 2 hours is equal to 120 minutes. To find how many grams of Francium remain after 2 hours, we can substitute t = 120 into the exponential function we found in part a):

N = 480 *\((1/2)^{ (120 / 22) }\) ≈ 4.38 grams

Therefore, after 2 hours, approximately 4.38 grams of Francium remain from the 480-gram sample.

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The new co-ordinates of the point after transformation is (-3,9)

A Cartesian coordinate system in a plane is a coordinate system that specifies each point uniquely by a pair of numerical coordinates,

Given here: The point g'(4,6)

The point transforms to  (x-7,y+3)

Thus the new points are 4⇒4-7=-3

6⇒6+3=9

Thus, The new co-ordinates of the point after transformation is (-3,9)

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The probability that the mean battery life would be greater than 1173.8 minutes is 0.9588

We can solve this problem using the central limit theorem, which tells us that the distribution of sample means from a population with a known variance becomes approximately normal as the sample size increases.

The standard error of the mean can be calculated as

SE = σ / sqrt(n)

where σ is the population standard deviation, n is the sample size

Here, we are given that the population variance is 8100, so the population standard deviation is the square root of 8100, which is 90.

SE = 90 / sqrt(72) = 10.6066

Next, we need to standardize the sample mean using the z-score formula

z = (X - μ) / SE

where X is the sample mean, μ is the population mean.

Here, the population mean is given as 1192 minutes and the sample mean we are interested in is 1173.8 minutes.

z = (1173.8 - 1192) / 10.6066 = -1.7356

We want to find the probability that the sample mean is greater than 1173.8 minutes. Since we have a negative z-score, we need to find the area to the right of this value on a standard normal distribution. We can use a z-table or a calculator to find this probability.

Using a standard normal distribution table, we find that the area to the right of z = -1.7356 is 0.9588.

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Answer:

57 degrees it’s an equalaterisl triangle all angles are the same on these types of triangles

Step-by-step explanation:

Answer:

$5.71

Step-by-step explanation:

20-5.88=14.12

14.12-8.41=5.71

Answer:

$5.71

Step-by-step explanation:

$20 − $5.88 − $8.41 = $5.71

Answer:

We won't get that exhaustive, but we pinpointed the most prevalent seven healthy habits that anyone should be able to include in their daily lives.

Get your exercise. ...

Always eat breakfast. ...

Practice healthy eating throughout the day. ...

Stay hydrated. ...

Don't neglect dental hygiene. ...

Get your sleep. ..

Challenge yourself.

Step-by-step explanation:

Thats what i do hope it helps you

\(\\ \tt\longmapsto 49=(7)^2\)

\(\\ \tt\longmapsto 64=(8)^2\)

\(\\ \tt\longmapsto 81=(9)^2\)

Step-by-step explanation:

Firstly let us write the square of 0 to 10,

Hence,

49, 64, 81 and 100 are perfect squares from 40 to 100.