As a result of friction, the angular speed of a wheel c hanges with time according to d θ d t = ω0 e −σ t , where ω0 and σ are constants. The angular speed changes from an initial angular speed of 2.88 rad/s to 1.38 rad/s in 3.92 s. (a) Determine the magnitude of the angular acceleration after 1.88 s. Answer in units of rad/s 2 . (b) How many revolutions does the wheel make after 2.6 s ? Answer in units of rev. (c) Find the number of revolutions it makes before coming to rest.

Answer:

C

Explanation:

But I’m not quite sure

The kinetic energy of the flywheel after 1 minute of rotation, given that it has a mass of 50 and radius of 40 cm is 32.4 KJ (Option D)

We'll begin by obtaining the velocity of the flywheel. This is shown below:

v = at

v = 0.6 × 60

v = 36 m/s

Finally, we shall determine the kinetic energy of the flywheel. Details below:

KE = ½mv²

KE = ½ × 50 × 36²

KE = 25 × 1296

KE = 32400 J

Divide by 1000 to express in KJ

KE = 32400 / 1000

KE = 32.4 KJ

Thus, the kinetic energy is 32.4 KJ (Option D)

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Interpreting Graphics The velocity-versus-time graph for a shuttle bus moving along a straight path is shown in Figure 13., all the answer is attached.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

a) The time intervals during which the velocity of the shuttle bus is constant: 50 s to 150 s.

b) The time intervals during which the acceleration of the shuttlebus is constant: 500 s to 600s.

c) The value for the average velocity of the shuttle bus during time interval identified in b is: ( -3 +(-5))/2 =m/s = - 4 m/s.

d) The acceleration of the shuttle bus during time interval identified in b = ( -3 +(-5))/(600 - 500) m/s² = 0.02 m/s²

.e) The times at which the velocity of the shuttle bus is zero is : 200s to 300s.

f) The times at which the acceleration of the shuttle bus is zero is : 50s to 150s.

g) The slope of the graph reveals about the acceleration in each time interval that when it is positive the car is accelerated, when it is negative, the car is decelerated.

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It is not recommended to fire a gun straight up into the air.

When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.

Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.

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Answer:

1. Two bright bands would appear on the screen in line with the slits.

2. Waves that make up the radiation collide with each other so that they add together or cancel each other out.

3. Waves that are in phase constructively interfere to create bright bands.

4. Waves that are out of phase destructively interfere to form dark bands.

5. The spacing between the bright fringes will decrease.

6. 581 nm

Explanation:

Answer:

The physical quantities are the quantities that are the base quantities of the measurement. They are known as the fundamental quantities. The units of those units are known as the fundamental units. The derived physical quantities are dependent on the fundamental quantities.

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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Answer:

To determine the height to which the ball rises before it reaches its peak, we need to know the initial velocity of the ball and the acceleration due to gravity. Let's assume the initial velocity of the ball is v and the acceleration due to gravity is g.

The time it takes for the ball to reach its peak is one-half the total hang-time, or 1/2 * 6.25 s = 3.125 s.

The height to which the ball rises can be calculated using the formula:

height = v * t - (1/2) * g * t^2

Substituting in the values we know, we get:

height = v * 3.125 s - (1/2) * g * (3.125 s)^2

To solve for the height, we need to know the value of v and g. Without more information, it is not possible to determine the height to which the ball rises before it reaches its peak.

Explanation:

Answer:

Approximately \(47.9\; {\rm m}\) (assuming that \(g = 9.81\; {\rm m\cdot s^{-2}}\) and that air resistance on the baseball is negligible.)

Explanation:

If the air resistance on the baseball is negligible, the baseball will reach maximum height at exactly \((1/2)\) the time it is in the air. In this example, that will be \(t = (6.25\; {\rm s}) / (2) = 3.125\; {\rm s}\).

When the baseball is at maximum height, the velocity of the baseball will be \(0\). Let \(v_{f}\) denote the velocity of the baseball after a period of \(t\). After \(t = 3.125\; {\rm s}\), the baseball would reach maximum height with a velocity of \(v_{f} = 0\; {\rm m\cdot s^{-1}}\).

Since air resistance is negligible, the acceleration on the baseball will be constantly \(a = (-g) = (-9.81\; {\rm m\cdot s^{-2}})\).

Let \(v_{i}\) denote the initial velocity of this baseball. The SUVAT equation \(v_{f} = v_{i} + a\, t\) relates these quantities. Rearrange this equation and solve for initial velocity \(v_{i}\):

\(\begin{aligned}v_{i} &= v_{f} - a\, t \\ &= (0\; {\rm m\cdot s^{-1}}) - (-9.81\; {\rm m\cdot s^{-2}})\, (3.125\; {\rm s}) \\ &\approx 30.656\; {\rm m\cdot s^{-1}}\end{aligned}\).

The displacement of an object is the change in the position. Let \(x\) denote the displacement of the baseball when its velocity changed from \(v_{i} = 0\; {\rm m\cdot s^{-1}}\) (at starting point) to \(v_{t} \approx 30.656\; {\rm m\cdot s^{-1}}\) (at max height) in \(t = 3.125\; {\rm s}\). Apply the equation \(x = (1/2)\, (v_{i} + v_{t}) \, t\) to find the displacement of this baseball:

\(\begin{aligned}x &= \frac{1}{2}\, (v_{i} + v_{t})\, t \\ &\approx \frac{1}{2}\, (0\; {\rm m\cdot s^{-1}} + 30.565\; {\rm m\cdot s^{-1}})\, (3.125\; {\rm s}) \\ &\approx 47.9\; {\rm m}\end{aligned}\).

In other words, the position of the baseball changed by approximately \(47.9\; {\rm m}\) from the starting point to the position where the baseball reached maximum height. Hence, the maximum height of this baseball would be approximately \(47.9\; {\rm m}\!\).

Answer:

or or or or or or or or or or

Explanation:

dingdongdingdongdingdongbigdogdooooggg

cat is cute. dog is cute. frog not cute.

The kinetic energy of the racing car is approximately 849952.4 J joules.

Kinetic energy is simply a form of energy a particle or object possesses due to its motion.

It is expressed as;

K = (1/2)mv²

Where m is mass of the object and v is its velocity.

Convert the speed from kilometers per hour to meters per second since the units of mass and velocity need to be consistent.

We know that 1 km/h = 0.27777 m/s, so:

120 km/h x (0.27777 m/s/km/h) = 33.3336 m/s (rounded to 4 decimal places)

Now we can substitute the values into the formula:

Kinetic Energy = (1/2) × 1530 kg x (33.3336 m/s)²

Kinetic Energy = 849952.4 J

Therefore, the kinetic energy is approximately 849952.4 joules.

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Answer:

\(-3 m/s^{2}\)

Explanation:

Acceleration on a VT graph is the slope of the line at the given point. We can find the slope at 3 with Δy/Δx. This gives us (4-2)/(3-(-3)) which works out to be -3m/s^2

A truck weighing 5 x 10³ kg force.

A cart weighing 500 kg force.

Moving with the same speed complete their

kinetic energies.

As we know that,

Formula of:

→ Kinetic energy = 1/2 x m x v².

Using this formula in the equation, we get.

(1).

→ For truck = 1/2 x 5 x 10³ x v².-----

→ For cart = 1/2 x 500 x v². -----(2).

Divide equation (1) and (2), we get.

⇒ KE₁/KE₂ = 5 x 10³/5 x 10².

➡ KE₁/KE₂ = 10/1.

⇒ KE₁/KE₂ = 10:1.

Answer:

Alpha particle

Explanation:

Alpha particles emitted by radioactive nuclei consist of 2 protons and 2 neutrons bound together which makes it neutral and are able to pass through ordinary matter almost undisturbed

Given data

*The given velocity of the car is v(t)= 10 + 3t + 512

The acceleration of the car is calculated as

Thus, the acceleration of the car at t = 2 s is 3 m/s^2

1,000 J of energy are needed to melt 10 g of a solid substance that is already at its melting point ,  the heat of fusion of the substance is 548 joules .

Heat of fusion, also known as enthalpy of fusion or latent heat of fusion, is the amount of energy required to melt or freeze a substance under constant pressure conditions. When it comes to chemistry, "fusion" is basically synonymous with "melting." In the classroom, heat of fusion is typically used when a substance is at its melting or freezing point. In such instances, most people consider heat of fusion to be a constant.

Water, for example, has a heat of fusion of 334 J/g at its melting point of 0°C. At 0°C, one grams  of liquid water requires 334 Joules of energy to completely freeze into ice. In addition, one grams of ice requires 334 Joules of energy to melt entirely.

q = m×∆Hf

q: Total change in heat energy (in Joules)

∆Hf: Heat of fusion of substance (in Joules per gram)

m: Mass of substance (in grams)

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Answer:

long-term

Explanation:

usually a short term goal is able to be accomplished in a week or two. the question gives a 3 month time frame for the person to build up to the end goal.

Answer:

3.7

Explanation:

The final temperature of the copper metal if 6.5 g coin of copper is heated using 50J is 44.98°C.

Calorimetry is the science of measuring the heat absorbed or evolved during the course of a chemical reaction or change of state.

The amount of heat absorbed or released by a substance can be calculated using the following formula:

Q = mc∆T

Where;

50 = 6.5 × 0.385 × {T - 25}

50 = 2.5025T - 62.5625

112.5625 = 2.5025T

T = 44.98°C

Therefore, 44.98°C is the final temperature of the copper coin.

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Answer:

See Explanation

Explanation:

Temperature affects the amount of sugar that will be dissolved in a liquid. It is general knowledge in chemistry that solutes tend to dissolve in hot solvents compared to cold solvents.

Hence, there is a positive relationship between dissolution of sugar in a liquid and increase in temperature.

To test this hypothesis, the variables are temperature and amount of solute. The volume of solvent and type of solvent must be held constant.

Different amounts of solute are dissolved in the same volume of solvent and heated to a constant temperature and the extent of dissolution of the sugar is observed for each experimental unit.

A control experiment is also set up in which different amount of sugar is dissolved in the same volume of solvent as above without heating and the results are compared.

Answer:

a = 17 m / s²

Explanation:

For this experiment that the astronauts are carrying out, the value of the relation of gravity is cosecant, therefore we can use the kinematic relations

         v² = v₀² + 2a y

They indicate the initial speed 1.2 m / s the final speed 4.3 m / s and the distance remembered 0.5 m

we clear

        a = (v² - v₀²) / 2y

we calculate

       a = (4.3² -1.2²) / 2 0.5

       a = 17 m / s²

this is the gravity of the new planet

The distance r or the charge Q from the given information as there is only one equation for two unknowns. We need another equation to solve for r and Q.

Using the formula for the electric potential due to a point charge Q at a distance r:

\(V = k Q / r\)

where k is the Coulomb constant \((k = 8.99 \times 10^9 Nm^2/C^2)\)

We can find the charge Q of the point charge by rearranging the formula as:

\(Q = V r / k\)

Substituting the given values, we get:

\(Q = (4.98 V) (r) / (8.99 \times 10^9 Nm^2/C^2)\)

Similarly, we can find the electric field magnitude E due to the point charge using the formula:

\(E = k Q / r^2\)

Substituting the given values, we get:

\(E = (8.99 \times 10^9 Nm^2/C^2) (Q) / r^2 = (8.99 \times 10^9 Nm^2/C^2) [(4.98 V)\)(r) / \((8.99 \times\)\(10^9 Nm^2/C^2)] / r^2\)

Simplifying, we get:

\(E = (4.98 V) / r\)

and

\(Q = (4.98 V) (r) / (8.99 \times 10^9 Nm^2/C^2)\)

Note that we cannot determine the distance r or the charge Q from the given information as there is only one equation for two unknowns. We need another equation to solve for r and Q.

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Answer:

0.3 newtons

Explanation:

If the coefficient of kinetic friction between a crate and the floor is 0.20, then the fore needed to slide a 92 kg crate uniformly across the floor would be 180.504 N

Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact.

The friction force prevents any two surfaces of objects from easily sliding over each other or slipping across one another. It depends upon the force applied to the object.

As given in the problem If the coefficient of kinetic friction between a crate and the floor is 0.20

The force needed = μN

where μ is the coefficient of the kinetic friction

μ =0.2

N is the normal force

N = mg

N = 92×9.81 N

Force needed to slide = 0.20× 92×9.81

                                     =180.504 N

Thus, The force needed to slide a 92 kg crate uniformly across the floor would be 180.504 N

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Answer:

proton and neutrons

Explanation:

electron has negligible mass

Answer:

The answer is D) crystal structure.

Explanation:

Answer:

remeber me u wher rude to me so ur points are mine now

Explanation:

The matchup are given below

9. Friction charges: Charging by rubbing (C)

10. Loss electrons: Positive charges (B)

11. Like charges: Repel forces (A)

12. Unlike charges: Attracting forces (D)

13. Neutral charges: Charging by induction (E)

14. If Charge Q1 attracts Q2 and charges Q2 repels charge Q3, the correct sign of their charges is: Unlike charges (D)

15.The electric field strength at a point is defined by the force of: Test charge (B)

16. Orbital velocity of a satellite does not depend on: Mass of earth (A)

17. When a planet moves around the sun: The angular moment remains conserved (A)

18. Kepler's law of area is a consequence of: conservation of angular moment (D)

18. If a current of 4A flows through a 2011 ohm resistor, the power lost in the resistor is: 80W (B)

20. If a boy observed that a pen rubbed on his dry hair attracted a nearby neutral piece of paper, the cause of the attraction is: Electrostatic forces (D)

21. If the distance from a point in the electric field is decreased by half, the electric potential at that point will: Increase four times (C)

22. The potential difference between the plates of a parallel plate capacitor with a distance of 1cm between plates and electric field strength of 10J/c is: 0.13V/c (B)

The term "Friction charges" refers to the process of charging an object by rubbing it against another material. When two materials are rubbed together, electrons can be transferred from one material to the other, creating a static electric charge. The resulting charge on the object is referred to as "friction charges."

Therefore, in terms of Loss electrons: The term "Loss electrons" refers to a situation in which an object loses electrons and becomes positively charged. This can occur when electrons are transferred from the object to another material through a process such as friction charging or electrical discharge. When an object loses electrons, it has a surplus of positively charged particles and is said to have a positive charge.

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There are six half lives that have passed within 34,200 years. When we assume that we have some of the products present initially, then we overestimate the age of the sample.

The half life is the time taken to obtain only half of the number of atoms that were originally present in the radioactive material. We know that living things do contain the carbon- 14 isotope together with the carbon - 12 isotope in the substance. When the organism dies, the carbon - 14 which is radioactive begins to decay and its half life could be used to estimate the age of the sample as we know.

Given that after each half life, we have only half of the original amount that remains. We would have 1/64 of the original amount left after six half lives and this means that 34,200 years have passed.

If we  the daughter product of carbon-14 is present in the sample when it forms (even before any radioactive decay happens), then we would over estimate the  age of the sample.

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Answer:

The kinetic energy is proportional to the square of the speed, so doubling the speed increases the kinetic energy by a factor of 4.

Answer:

False

Explanation:

A land breeze is when air flows from land to water. The question above is describing a sea breeze, which is when cool ocean air blows toward land.