as a rock slides from a to b along the inside of this frictionless hemispherical bowl, mechanical energy is conserved. why? ignore air resistance

Answer:

Boiling a kettle is an example of both thermal and kinetic energy. Thermal energy comes from a substance whose molecules and atoms are vibrating faster due to a rise in temperature. Heat energy is another name for thermal energy. Kinetic energy is the energy of a moving object.

it's kinetic!

Responder:

Explicación:

La fórmula se utiliza para convertir grados Celsius (° C) en grados Fahrenheit (° F).

x ° C = (y ° F - 32) × 5/9.

Convertir 24 ° C a Fahrenheit

24 = (y ° F - 32) × 5/9.

24 * 9 = 5 (y ° F-32)

216 = 5 años ° F-160

5 ° F = 216 + 160

5 ° F = 376

y ° F = 376/5

y ° F = 75.2

24 ° C = 75.2 ° F

Para convertir Kelvin a Fahrenheit, usaremos la expresión;

(K - 273.15) × 9/5 + 32

Dado K = 24kelvin

24K a ° F = (24− 273.15) × 9/5 + 32

= -249.15 (9/5) + 32

= -448.47 + 32

= -416.47 ° F

24K = = -416.47 ° F

Answer:

Explanation:

The average speed of the car can be found by using the formula

\(s = \frac{d}{t} \\ \)

d is the distance

t is the time taken

From the question we have

\(s = \frac{300}{6} = 50 \\ \)

We have the final answer as

Hope this helps you

Answer:

50mph

Explanation:

Just do\(\frac{300}{6}\) (aka 300 divided by 6)

And you'll get 50 as your answer!

Hope this helps! Ty!

The tension in the rope is 150 N.

The tension in the rope would be 150 N.

What are the given values?

Given,Mass of the engine = 135 kg

Mass of the pulley system = 6.65 kg

Acceleration due to gravity = 9.8 m/s²

Formula to calculate tension,T = m(g + a)

Where,T is the tension in the rope,m is the mass of the engine, and

a is the acceleration of the system.Here, the pulley system is at rest.

So, acceleration of the system is zero. Hence,a = 0

Substituting the given values in the above formula,T = 135 kg × (9.8 m/s² + 0)T = 1323 N

Now, the pulley system multiplies the tension by a factor of two.

Tension in the rope,T = 1323/2 N = 661.5 N= 662 N

Therefore, the tension in the rope is 150 N.

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The half-life of a first-order reaction is a constant that is related to the rate constant for the reaction: t1/2 = 0.693/k.

It is used in life-science laboratories in applications in which lower energy beta emissions are advantageous such as DNA sequencing. P can be used to label nucleotides. It is less energetic than 32P, giving a better resolution.

Phosphorus 33 is an artificial radioactive element. It is produced with a low yield by the neutron bombardment of phosphorus 31 (stable). The phosphorus 33 has a radioactive period of 25.3 days.

Phosphorus-33 atom is the radioactive isotope of phosphorus with relative atomic mass 32.971725, half-life of 25.34 days and nuclear spin (1)/2.

Phosphorus was discovered by the German merchant Hennig Brand in 1669.

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Answer:

17

Explanation:

121354

Answer:

\(t_{1/2}=6 h\)

Explanation:

Let's use the decay equation.

\(A=A_{0}e^{-\lambda t}\)

Where:

We know that \(\lambda=\frac{ln(2)}{t_{1/2}}\)

So we have:

\(\lambda=\frac{ln(A/A_{0})}{t}\)

\(\frac{ln(2)}{t_{1/2}}=\frac{ln(A/A_{0})}{t}\)

\(t_{1/2}=\frac{t*ln(2)}{ln(A/A_{0})}\)

\(t_{1/2}=6 h\)

Therefore, the half-life of the source is 6 hours.

I hope it helps you!

To establish that the universe was very, very large, Edwin Hubble used observations of galaxies and their redshifts.

Edwin Hubble, an American astronomer, made groundbreaking discoveries that revolutionized our understanding of the universe. One of his key contributions was the realization that galaxies exist beyond the boundaries of our Milky Way and that the universe is much larger than previously believed. Hubble observed numerous galaxies and noticed that their light exhibited a redshift. This redshift phenomenon occurs when light waves from distant objects stretch as the universe expands, causing the wavelengths to appear longer, shifting towards the red end of the spectrum. Hubble's observations showed a correlation between the distance of galaxies and the magnitude of their redshifts.

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When a car is stopped abruptly by an impact, the airbags are inflated.

An airbag is an inflatable safety device designed to protect the occupants of a car in case of a collision. The airbags are part of an occupant restraint system and are also referred to as air cushion restraint system. Airbags supplement the basic protection offered by seat belts.

When a car is stopped abruptly by an impact, all bodies or objects that are not firmly fixed to the car will continue to move at the impact speed. The sensors measure this acceleration and relay it to the control unit as usable data.

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Answer:

Periods are horizontal rows (across) the periodic table, while groups are vertical columns (down) the table. Atomic number increases as you move down a group or across a period. Beside above, what do columns mean in the periodic table? The periodic table also has a special name for its vertical columns.

Explanation:

(a) The distance travelled by the object is  100 m.

(b) The displacement of the object in time interval between t = 0 s and t = 10 s is 60 m.

(a) The distance travelled by the object is calculated from the total area of the curve.

total distance = area of triangle 1 + area of triangle 2 + area of rectangle.

total distance = (¹/₂ x base x height)₁ +  (¹/₂ x base x height)₂ + length x width

total distance = (¹/₂ x 6 s x 20 m/s) +  (¹/₂ (8 - 6) 20) + (10 - 0)(10 - 8)

total distance =  60 m + 20 m + 20 m

total distance = 100 m

(b) The displacement of the object in time interval between t = 0 s and t = 10 s is calculated as follows;

displacement = final position - initial position

displacement =  (¹/₂ x base x height)₁ +  (¹/₂ x base x height)₂ + length x width

displacement = (¹/₂ x 6 s x 20 m/s) +  (¹/₂ (8 - 6) (-20)) + (10 - 0)(10 - 8)

displacement = 60 m - 20 m + 20 m = 60 m

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Answer:

The ratio of effusion rates of hydrogen gas to argon gas is approximately 4.47:1.

Explanation:

The ratio of effusion rates of two gases can be determined using Graham's law of effusion. According to Graham's law, the ratio of the effusion rates of two gases is equal to the square root of the inverse ratio of their molar masses.

In this case, we need to find the ratio of the effusion rates of hydrogen gas (H2) and argon gas (Ar).

The molar mass of hydrogen gas (H2) is approximately 2 g/mol, and the molar mass of argon gas (Ar) is approximately 40 g/mol.

Using Graham's law, the ratio of effusion rates (R) can be calculated as:

R = √(M2/M1)

R = √(40/2) = √(20) = 4.47

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Answer:

One immediate division you might have seen on the periodic table is that the elements and their corresponding boxes are organized into vertical (up and down) columns and horizontal (left to right) rows. This link shows a periodic table with the columns (groups) and rows (periods) labeled. You should open that link up and keep it with you to compare with the explanations and examples in this section. In chemistry, we call the vertical organization either columns or groups. Whereas, the horizontal organization is called rows or periods. The columns or groups are usually labeled at the top of the periodic table by numbers; 1 through 18. On they periodic table that you have open one example of a group is group 17. It contains the elements fluorine, chlorine, bromine, iodine, and so on. The periods on most periodic tables are label on the left side of the periodic table by number 1 through 7. On the periodic table you have open one example of is period 4. It contains the elements potassium, calcium, scandium, titanium, and so on. In general, knowing the groups is a lot more important than knowing the periods. A lot of common properties between elements are shared if they are in the same group. For example, fluorine and chlorine are both in the same group and are both gases at a normal room temperature.

Explanation:

a. The work done by the applied force is equal to the force applied times the distance it was applied over. Therefore, the work done by the applied force is 810 J.

b. The increase in internal energy due to friction is equal to the friction force times the distance over which it is applied. Therefore, the increase in internal energy due to friction is 596.77 J.

c. The work done by the normal force is equal to the normal force times the distance it is applied over. Therefore, the work done by the normal force is 0J.

d. The work done by the gravitational force is equal to the gravitational force times the distance it is applied over. Therefore, the work done by the gravitational force is 0J.

e. The change in kinetic energy of the box is equal to the final kinetic energy minus the initial kinetic energy. Therefore, the change in kinetic energy of the box is  0J.

f. To find the final speed of the box, we will use the work-energy theorem which states that the work done is equal to the change in kinetic energy. Therefore, the final speed is equal to 3.37 m/s.

a. The work done by the applied force in pushing a 37.5 kg box initially at rest for 5.40 m along a rough, horizontal floor with a constant applied horizontal force of 150 N and a coefficient of friction of 0.300 is given by the following formula:

Work done by the applied force = F × d

Work done by the applied force = 150 N × 5.40 m

Work done by the applied force = 810 J

b. The increase in internal energy in the box-floor system due to friction is the product of the coefficient of friction between box and floor, the normal force, and the distance the box is moved over the floor.

The formula for calculating the increase in internal energy in the box-floor system due to friction is given as follows:

Increase in internal energy due to friction = frictional force × distance

Increase in internal energy due to friction = \(\mu_k \times N \times d\)

where \(\mu_k\) is the coefficient of friction, N is the normal force, and d is the distance the box is moved over the floor.

The formula for calculating the normal force is given as follows:

N = mg where m is the mass of the box and g is the acceleration due to gravity.

N = 37.5 kg × 9.81 m/s²

N = 367.9 N

The formula for calculating the frictional force is given as follows:

The increase in internal energy due to friction is given as follows:

Increase in internal energy due to friction = frictional force × distance

Increase in internal energy due to friction = 110.37 N × 5.40 m

Increase in internal energy due to friction = 596.77 J

c. The work done by the normal force is equal to zero as there is no displacement in the normal direction. This is because the normal force acts in the upward direction, perpendicular to the horizontal displacement of the box. Therefore, the work done by the normal force is zero.

d. The work done by the gravitational force is given as follows:Work done by the gravitational force = mgh where m is the mass of the box, g is the acceleration due to gravity, and h is the height through which the box is lifted.Work done by the gravitational force = 37.5 kg × 9.81 m/s² × 0 m= 0J

Work done by the gravitational force = 0 J

e. The change in kinetic energy of the box is given by the following formula:

Change in kinetic energy = 1/2 × mv² - 1/2 × mu²

where m is the mass of the box, u is the initial velocity of the box, and v is the final velocity of the box.

Since the box is initially at rest, the initial velocity of the box is zero.

Change in kinetic energy = 1/2 × 37.5 kg × v² - 1/2 × 37.5 kg × 0²

Change in kinetic energy = 1/2 × 37.5 kg × v²

The final speed of the box is given by the following formula:

Change in kinetic energy = Work done by the applied force - Work done by the force of friction - Work done by the gravitational force

This is because the box starts from rest and ends up moving with a final velocity v after being acted upon by the applied force, force of friction, and gravitational force.

Therefore, the work done by these forces results in the change in kinetic energy of the box.

Change in kinetic energy = 810 J - 596.77 J - 0 J

Change in kinetic energy = 213.23 J

\(Change in kinetic energy = 1\frac{1}{2}\times m \times v^2\\213.23=\dfrac{1}{2} \times37.5 kg \times v^2 \\v^2 = 11.35 m^2/s^2\\v = \sqrt(11.35 m^2/s^2)\\ =3.37 m/s\)

Therefore, the final speed of the box is approximately 3.37 m/s.

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The wavelength of the radio waves having a frequency of 106.9 MHz is 2.80 m

How do I determine the wavelength of light?

The speed of wave is related to wavelength and frequency according to the following formula:

Velocity (v) = wavelength (λ) × frequency (f)

v = λf

From the question given above, the following data were obtained:

The wavelength of the radio waves can be obtained as follow:

Velocity (v) = wavelength (λ) × frequency (f)

3×10⁸ = wavelength × 106.9×10⁶

Divide both sides by 106.9×10⁶

Wavelength = 3×10⁸ / 106.9×10⁶

Wavelength = 2.80 m

Thus, from the above calculation, we can conclude that the wavelength is 2.80 m

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Calculate the specific heat capacity of the lime juice.

The heat of fusion indicates the energy required to convert 1 g of solid to liquid at the same temperature. 250 x 332 Joules are required to melt 250 g of ice. For example, let's look at the energy required to melt 1 kg of ice at 0°C to produce 1 kg of water at 0°C.

For example, consider the energy required to melt 1 kg of ice at 0 °C to produce 1 kg of water at 0 °C. Using the temperature change equation and the water values ​​in Table 1, we find that Q = mLf = 1.0 kg,  334 kJ/kg = 334 kJ is the energy to melt 1 kilogram of ice. The specific heat capacity of lemonade is about the same as that of water c = 4186 J/kg°C.

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(a) The energy needed to melt the ice is 27200 J.

(b) The formula to calculate the energy gained by the melted ice is Q = mCΔT.

(c) The energy gained by the melted ice from lemonade is 2688 J.

(d) The lost energy by the lime juice is 29888 J.

(e) The specific heat capacity of the lime juice is 4.447 J/ g °C.

The mass of ice is 80 grams.

The temperature of lemonade decreases from 29 °C to 8 °C.

The mass of lemonade, M = 0.32 kg = 320 g

The specific latent heat of fusion of ice = 3.4 × 10⁵ J/kg

Specific heat capacity of water = 4.2 × 10³ J/kg °C

a) The heat energy required to melt 1 kg of ice = 3.4 × 10⁵ J

So, the heat energy to melt 1 gram of ice = 340 J

Therefore, the energy required to melt 80 grams of ice = 340 × 80 = 27200 J

b) The formula for the energy gained by the melted ice from the lemonade is:

Q = mCΔT

Where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.

c) The energy gained by the melting of ice at 0 °C, Q = mCΔT

Q = 80 × 4.2 × ( 8 °C - 0 °C)

Q = 2688 J

d) The energy lost by the lime juice is energy gained by ice and water.

Lost energy by lime juice = 27200 J + 2688 J = 29888 J

e) Let's say C' is the specific heat capacity of the lime juice.

Then,

Q = MC'ΔT

Q = 320 g × C' × ( 29 - 8 )

Q = 6720C'

In equilibrium,

Heat lost = heat gained

6720C' = 29888 J

C' = 4.447 J/ g °C

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Answer:

object stop

Explanation:

Answer:

Explanation:

If the force of 2000 N is directed towards the right and the friction is directed towards the left, the 2000 N force is positive and the other is negative. To find the resultant force:

2000 - 500 = 1500 N to the right

First, for this problem, we will need to know the formula for time dilation

Where t is the time in the reference frame on earth

t0 is the time on the ship

v is the velocity relative to lightspeed

and c is light speed in a vacuum

For this problem, we will need to convert .93x10^8 to a fraction of light speed.

.93x10^8 = .31c

Now, we can plug in the numbers we get from the given

t0 = 6 hours since the ship has been in the air for 6 hours

t = 6.31089

For the answer to be valid, we will convert .31089 to minutes by multiplying it by 60 (60 minutes in a hour)

18.654 minutes

magnetic field of a solenoid is B  = 8.33*10^-4 T

Moreover, Length of the solenoid L  = 2.6 m

Number of turns  N  = 690

current in the magnetic field  is  i  = 2.5 A

magnetic field of a solenoid is B  = μ 0 N * i / L

                                                         = 4π*10^-7 * 690 * 2.5A / 2.6

                                                         = 8.33*10^-4 T

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Answer: (a) The velocity of the ball at its highest point is 10.12 m/s

              (b) The height that the ball goes is 1.13 m.

Mass of ball, m = 0.48 kg

Initial velocity, u = 8.8 m/s

Initial angle, θ = 36°

Using the principle of conservation of energy, the final velocity at the highest point can be found. The potential energy of the ball is converted into kinetic energy at its highest point, where the ball will stop momentarily. Then, we know that the total energy at the top will be equal to the potential energy at the beginning. That is, Initial Potential Energy + Initial Kinetic Energy = Final Potential Energy∴

mgh + 1/2mu² = mgh(max) where h(max) is the maximum height the ball attains. At this point, the kinetic energy will be zero. Therefore,0.5mv² + mgh = mgh(max). Since the kinetic energy of the ball at the top is zero, the total energy at the top of the projectile’s trajectory is the potential energy at the start of the trajectory, which is mgh.∴ v = √(2gh).

This is the velocity at the maximum height.

(a) Speed at its highest point:

Initial velocity of ball, u = 8.8 m/s

Angle made with horizontal, θ = 36°

The vertical component of velocity, v_y = usinθv_y = 8.8 sin 36°v_y = 5.0 m/s

Now using the formula, v = √(u² + v_y²)v = √(8.8² + 5.0²)v = √(77.44 + 25)v = √102.44v = 10.12 m/s

Therefore, the velocity of the ball at its highest point is 10.12 m/s

(b) How high does it go: lets calculate the potential energy at the initial position. Potential energy, Ep = mgh

Ep = 0.48 * 9.8 * 0Ep = 0 J. The total energy at the top will be equal to the potential energy at the beginning. That is, Initial Potential Energy + Initial Kinetic Energy = Final Potential Energy∴ mgh + 1/2mu² = mgh(max). Substituting the values,0.48*9.8*h(max) + 0.5*0.48*8.8² = 0.48*9.8*0hmax = (0.5*0.48*8.8²)/(0.48*9.8)h(max) = 1.13 m.

Therefore, the height that the ball goes is 1.13 m.

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Answer:

Electric Current

Explanation:

Answer:

In this lab, we used a virtual spectrometer to analyze the elements present in unknown astronomical objects. We observed that Moon One had hydrogen, helium, and carbon present, while Moon Two had hydrogen, helium, lithium, sodium, carbon, and nitrogen present. Planet One had hydrogen, helium, lithium, sodium, and carbon present, while Planet Two had hydrogen, helium, lithium, sodium, carbon, and nitrogen present.

It is essential to use many types of equipment when studying space because the electromagnetic spectrum is made up of many different wavelengths and frequencies, and each one provides different information. If carbon was the most common element found in the moons and planets, oxygen would be missing, which is necessary for the carbon cycle to occur. The electromagnetic spectrum helps us find out the make-up of stars by allowing us to detect the different wavelengths and frequencies of light they emit, which can tell us the elements they are composed of.

It is useful to determine the elements that a planet or moon is made up of because it can provide insight into the planet's atmosphere, climate, and potential for life. Knowing the elements present can also help us understand the history of the planet or moon, such as how it was formed and how it has evolved over time.

Resistance  =  (voltage) divided by (current)

                                             =  (120 V)  /  (0.5 Amp)

                                             =          240 ohms .

Explanation:

more massive objects will attract each other with a greater gravitational force.

When a charged body is placed near the conductor, the opposite charge is appeared on the one side of the uncharged conductor body near the charged body under the effect of induction.

The opposite charge on the another body is also known as the induced charge.

The perpex rod in the given question is charged.

let the charge on the perpex is positive as shown in the figure.

Then, the polystrene sphers (insulator uncharged sphere) will not have any charge induced as the charges are not free to move inside the insulator.

Thus, when a charged perspex rod is placed close to a suspended polystyrene sphere then the induced charge on the sphere is not observed under the phenomenon of induction process and sphere remain uncharged.

For this problem, lets use the kinetic energy formula

Where m is equal to mass and v is equal to velocity

In our given, we have:

velocity = 60 m/s

kinetic energy = 6,025,000 J

Plug these numbers into the formula to get the mass

m = 3347.222 kg