As the chief design engineer for a major toy company, you are in charge of designing a loop-the-loop toy for youngsters. The idea is that a ball of mass m and radius r will roll down an inclined track and around the loop without slipping. The ball starts from rest at a height h above the tabletop that supports the whole track. The loop radius is R. Determine the minimum height h, in terms of R and r, for which the ball will remain in contact with the track during the whole of its loop-the-loop journey

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Answer:

Explanation:

contents

1. FAILURES OF ARGUMENT:

        Inconsistency,

        Begging the Question,

        Disappearing Hedge,

        Non Sequitur

2. Non Sequitur FALLACIES OF RELEVANCE

3. Non Sequitur FALLACIES OF WEAK INDUCTION

4. Non Sequitur FALLACIES OF PRESUMPTION

5. Non Sequitur FALLACIES OF AMBIGUITY, VAGUENESS, etc.

6. Nasty persuasive rhetoric, a.k.a. SOPHISTRIES

7. OTHER FALLACIES

The efficiency of motor is 90.58%.To determine the efficiency of the motor, we need to calculate the input power and the output power, and then divide the output power by the input power

The input power can be calculated using the formula:

Input Power = Voltage × Current

Given that the voltage is 230 V and the current is 24 A, we have:

Input Power = 230 V × 24 A

Input Power = 5520 W (or 5.52 kW)

The output power of the motor is given as 5 kW (since it is a 5 kW motor).

Now, we can calculate the efficiency:

Efficiency = (Output Power / Input Power) × 100%

Efficiency = (5 kW / 5.52 kW) × 100%

Efficiency ≈ 90.58%

Therefore, the efficiency of this motor is approximately 90.58%.

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The force represented by the arrow at A is the force of gravity .

Thus , we can conclude that the correct answer is option B.

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Answer:

1. The baseball will hit the bat at a force of 1.875 Newtons (N)

2. The basketball is being pushed to roll to the right of its original position with an applied rightward force. There is a force of friction to the left, a normal force of the floor acting upwards on the ball, and a gravity force of the Earth acting downwards on the ball.

Explanation:

1. To calculate force, you just have to multiply mass (m) and acceleration (a). F = m * a --> F = 0.075kg * 25 m/s^2 = 1.875 N.

2. Use your knowledge of different types of forces and free-body diagrams to come to this conclusion.

Answer:

D

Explanation:

Nothing can enter or leave so it remains constant

Answer:

BOTH the size of the force AND the mass of the object

Explanation:

Acceleration of an object is the rate of change of its velocity.

The relation between force, mass and acceleration is given by the formula as follows :

F = ma

m is mass

a is acceleration

It would mean that the change in motion or the acceleration of an object depends on both the size of the force and the mass of the object. Hence, the correct option is (c).

The speed of light in material B is 1.6625 × 108 m/s.

The refractive index of a material is its optical density relative to that of a vacuum.

Material B has a refractive index of nB, and its speed of light is vB.

The speed of light in material A is given as 1.25 x 108 m/s.

The refractive indices of materials A and B have a ratio of nA/nB = 1.33.

We will use the formula:

nA/nB = vB/vA = nA/nB.

Therefore, nA/nB = vB/1.25 x 108 m/s.

This equation can be rearranged to give the speed of light in material B:

vB = nA/nB × 1.25 x 108 m/s.

Therefore, vB = 1.33 × 1.25 × 108 m/s.

We will perform this calculation:

vB = 1.6625 × 108 m/s.

Therefore, the speed of light in material B is 1.6625 × 108 m/s.

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The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

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Answer:

No, positive charges cannot be liberated by the photoelectric effect.

Explanation:

The formulated sentences for each will be:

A: If length is 5cm, width 2cm, height 4cm, volume:  40 cubic centimeters.

B: If the length is 3cm, width 4cm, height 2cm, then Volume is: 24 cubic centimeters.

C:  If the length is 6cm, width 2cm, height 3cm, the  volume is 36 cubic centimeters.

D:  If the length is 3cm, width 2cm, height 4cm, the  volume 24 cubic centimeters.

To calculate the volume of a rectangular prism using multiplication, you need to multiply the length, width, and height of the prism. The multiplication sentence for this is:

Volume = length (m) x width (m) x height (m)

For a. The multiplication sentence for calculating the volume of rectangular prism C is:

b. The multiplication sentence for calculating the volume of rectangular prism B is:

c. The multiplication sentence for calculating the volume of rectangular prism C is:

Lastly, for d. The multiplication sentence for calculating the volume of rectangular prism D is:

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The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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(a) The work done by the donkey on the cart is 59,721.9 J.

(b) The work done by the force of gravity on the cart is -48,434.87 J.

(c) The work done on the cart by friction during this time is 11,315.12 J.

(a) The work done by the donkey on the cart is calculated as follows;

Wd = Fd cosθ

where;

Wd = 375 N x 163 m x cos(12.3)

Wd = 59,721.9 J

(b) The work done by the force of gravity on the cart is calculated as;

Wg =  Fg x d x cosθ

Where;

θ = 90⁰ + 4.03⁰ = 94.03⁰

Wg = (431 kg x 9.81 m/s²) x 163 m x cos (94.03)

Wg = -48,434.87 J

(c) The work done on the cart by friction during this time is calculated as;

Wf = Ff x d x cosθ

where;

Ff = μmg cosθ

Ff = 0.0165 x 431 kg x 9.81 x cos (4.03)

Ff = 69.59 N

Wf = 69.59 x 163 x cos (4.03)

Wf = 11,315.12 J

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The normal force on the block is approximately 20.05 N.

Force describes the interaction between objects or between an object and its environment. It causes a change in the motion of the body it acts upon.

The normal force, which counteracts the force of gravity dragging the block downward, is the force generated by the slope acting perpendicular to its surface. As the incline has no friction, there is no force acting parallel to its surface.

To ascertain the parts of the force of gravity pulling on the block, we can apply trigonometry. There are two parts to the force of gravity: one that is parallel to the incline's surface and the other that is perpendicular to it. The weight of the block, mg, where m is its mass and g is its gravitational acceleration, is equal to the component of gravity perpendicular to the inclination. mg sin θ, where is the angle of the incline, is the component of gravity that is parallel to the incline.

To calculate the acceleration of the block moving down the incline, we can apply Newton's second law, F = ma. The component of gravity parallel to the inclination, or mg sin θ, represents the net force exerted on the block. As a result, we have:

\(mg sin(theta) = ma\)

To solve for a, we obtain:

\(a = g sin(theta)\)

Substituting the given values, we get:

\(a = 9.8 m/s^2 * sin(27°)\) ≈ \(4.69 m/s^2\)

Now that we know the normal force acting on the block, we can use Newton's second law once more. The component of gravity's force perpendicular to the incline is equal in magnitude to the normal force and moves in the opposite direction. As a result, we have:

\(mg cos(theta) = N\)

Inputting the values provided yields:

\(N = 2.3 kg * 9.8 m/s^2 * cos(27°)\) ≈ \(20.05 N\)

Therefore, the normal force on the block is approximately 20.05 N.

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Answer:

The Sun's gravity pulls on the planets, just as Earth's gravity pulls down anything that is not held up by some other force and keeps you and me on the ground.

Explanation:

Hope that helps

answer:

when mass is increased, acceleration decreases

when mass decreases, acceleration increases

Based on Newton's first  and second law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.

Newton's first law of motion first law of motion states that a body at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.

Newton's first law of motion is also called law of inertia because it depends on mass of the object.

An object with a greater mass will require greater force to be stopped or get moving.

Based on Newton's first law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.

Also according to Newton's second law of motion, the force applied to an object is proportional to the product of mass and acceleration of the object. Thus, a baseball with smaller mass will require smaller force to be stopped.

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The angle of the first bright interference maximum (m=1) can be calculated using the equation: θ = sin-1(mλ/d).

An equation is a mathematical expression that uses symbols to describe a relationship between two or more variables. Equations are typically used to express relationships between physical quantities, such as forces and masses, or distances and times. They are also used to describe chemical reactions and other phenomena. Equations can be used to solve for unknown values, or to describe patterns or trends in data. Equations are typically written using algebraic notation, which includes variables, constants, and operators.

Substituting the given values, we get,θ = sin-1(1(580 × 10-9m)/(0.000125m)),θ = 0.00463 radians or 0.2637° .

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Answer: Negative

Explanation: The acceleration along the y-axis for any projectile motion will always be -9.8m/s^2.

Answer:

Doppler Radar gathers information about precipitation by sending out pulses of ___Radio wave___ energy

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Answer:

Explanation:

Due to first charge , electric field at origin will be oriented towards - ve of y axis.

magnitude

Ey = -8.99 x 10⁹ x 4.1 x 10⁻⁹ / 1.08² j

= - 31.6 j N/C

Due to second charge electric field at origin

= 8.99 x 10⁹ x 3.6  x 10⁻⁹ / 1.2²+ .6²

= 8.99 x 10⁹ x 3.6  x 10⁻⁹ / 1.8

= 18 N/C

It is making angle θ where

Tanθ = .6 / 1.2

= 26.55°

this field in vector form

= - 18 cos 26.55 i - 18 sin26.55 j

= - 16.10 i - 8.04 j

Total field

= - 16.10 i - 8.04 j + ( - 31.6 j )

= -16.1 i - 39.64 j .

Ex = - 16.1 i

Ey = - 39.64 j .

Answer:

1. The expansion rate of the universe, often measured using the Hubble Constant.

2. The cooling of the cosmic microwave background radiation.

3. The chemical abundances of light elements like helium and deuterium.

4. The abundance of elements heavier than hydrogen and helium created by stellar nucleosynthesis.

5. The redshift of galaxies and other distant objects.

Explanation:

Answer:

-100m/s not shure tho thx tho

Answer:

the glove could be heavy so slowing down his power

Explanation:

JUST GUESSED

Answer:

I'm pretty sure that the answer is C. Hope this helps.

Explanation:

Answer:

Answer is A. Under any conditions

Explanation:

Just got it correct on A p e x

Answer:

b. the cylinder

Explanation:

From the information given:

We understood that the mass of the sphere, cylinder, and rod length is the same with the same angular speed.

Taking their moments:

For the solid sphere; \(\text{The moment of inertia :}\) \(I_s\) = \(\dfrac{2}{5} \times m \times r^2\)

The moment of inertia of the cylinder, \(I_c = 0.5\times m \times r^2\)

The moment of inertia of rod, \(I_r =\dfrac{ m * r^2 }{12}\)

The rotational kinetic energy is directly corresponding to the moment of inertia.

Thus, the cylinder has the greatest rotational kinetic energy.

Answer:

\(B=\frac{\mu_o \epsilon_o R_o^2V_o}{2rd}cos(\omega t)\)

Explanation:

By the information of the statement you have that the sinusoidal potential difference is given by:

\(V=V_osin(\omega t)=V_osin(2\pi ft)=150sin(2\pi (60)t)\)    (1)

In order to calculate the induced magnetic field in between the plates, you first take into account the following formula, which is the Ampere-Maxwell law:

\(\int B\cdot ds=\mu_o \epsilon_o\frac{d\Phi_E}{dt}+\mu_oI_c\)           (2)

B: induced magnetic field

μo: magnetic permeability of vacuum = 4π*10^-7 A/T

εo: dielectric permittivity of vacuum = 8.85*10^-12 C^2/Nm^2

Ic: conduction current

ФE: electric flux

There is no conduction current in between the plates, then Ic = 0A

Next, you calculate dФE/dt, as follow:

The electric field, and the electric flux, are:

\(E=\frac{V}{d}=\frac{V_osin(\omega t)}{d}\\\\\Phi_E=EA\)

d: separation between plates = 5.0mm = 5.0*10^-3 m

A: area of the circular plates = \(\pi R_o^2\)

Ro: radius of the circular capacitor = 3.0cm = 0.03m

Thus, dФE/dt is:

\(\frac{d\Phi_E}{dt}=\frac{d(EA)}{dt}=\pi R_o^2\frac{d}{dt}[\frac{V_osin(\omega t)}{d}]\\\\\frac{d\Phi_E}{dt}=\frac{\pi \omega R_o^2 V_o}{d}cos(\omega t)\)       (3)

The induced magnetic field is calculated by taking into account that the integral of the equation (2) is:

\(\int B \cdot ds=B\int ds=B(2\pi r)\)         (4)

Next, you replace the results of (3) and (4) into the equation (2) and you solve for B:

\(B(2\pi r)=\mu_o \epsilon_o (\frac{\pi \omega R_o^2 V_o}{d}cos(\omega t))\\\\B=\frac{\mu_o \epsilon_o R_o^2V_o}{2rd}cos(\omega t)\)   (5)

The last expression is de induced magnetic field in between the plates in terms of t and r

Another way of expressing the  formula (5) is as follow:

\(B=B_ocos(\omega t)\\\\B_o=\frac{\mu_o \epsilon_o R_o^2V_o}{2rd}\)