As the name states, the cars of a roller coaster really do coast along the tracks. A motor pulls the cars up a high hill at the beginning of the ride. After the hill, however, the motion of the car is a result of gravity and inertia. As the cars roll down the hill, they must pick up the speed that they need to whiz through the rest of the curves, loops, twists, and bumps in the track. To learn more about designing roller coasters, read the interview with Steve Okamoto.
How did you become a roller coaster designer?
I have been fascinated with roller coasters ever since my first ride on one. I remember going to Disneyland as a kid. My mother was always upset with me because I kept looking over the sides of the rides, trying to figure out how they worked. My interest in finding out how things worked led me to study mechanical engineering. What sort of training do you have I earned a degree in product design. For this degree, I studied mechanical engineering and studio art. Product designers consider an object's form as well as its function.They also take into account the interests and abilities of the
product's consumer. Most rides and parks have some kind of theme, so I must consider marketing goals and concerns in my designs.
What is the nature of your work?
To design a roller coaster, I study site maps of the location. Then, I go to the amusement park to look at the actual site.Because most rides I design are for older parks (few parks are built from scratch), fitting a coaster around, above, and in
between existing rides and buildings is one of my biggest challenges. I also have to design how the parts of the ride will work together. The towers and structures that support the ride have to be strong enough to hold up a track and speeding cars that are full of people. The cars themselves need special wheels to keep them locked onto the track andseat belts or bars to keep the passengers safely inside. It's
like putting together a puzzle, except the pieces haven't
been cut out yet.
What advice do you have for a student who is interested in designing
roller coasters?
Studying math and science is very important. To design a successtulcoaster, I have to understand how energy is converted from one form to another as the cars move along the track. I have to calculate speeds and accelerations of the cars on each part of the
track. They have to go fast enough to make it up the next hill! I rely on my knowledge of geometry and physics to create the roller coaster's curves.loops, and dips. Sammrazie in two paragraphs

Answer:

daddy went to get milk really quick.

Explanation:

he will come back ;)

The magnitude of the external magnetic field is approximately 0.194 Tesla.

To solve this problem, we can use the equation for the magnetic force on a current-carrying wire:

F = BILsinθ

where F is the magnetic force, B is the magnitude of the magnetic field, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field.

Given:

Length of the wire, L = 0.19 m

Current, I = 7.6 A

Angle, θ = 17°

Force, F = 6.2 x \(10^{-3}\)N

Substituting the given values into the equation, we have:

6.2 x \(10^{-3}\) N = B * 0.19 m * 7.6 A * sin(17°)

Simplifying the equation, we can solve for B:

B = (6.2 x \(10^{-3}\) N) / (0.19 m * 7.6 A * sin(17°))

Calculating this expression, we find:

B ≈ 0.194 T

Therefore, the magnitude of the external magnetic field is approximately 0.194 Tesla.

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Every tube in the load must have a companion right across in the rotor holder in order for the centrifuge to be balanced.

In many laboratories, centrifuges are employed to separate fluids, gases, or liquids according to their densities. Centrifuges are often employed in clinical and research facilities for the purification of cells, organelles, viruses, proteins, and nucleic acids.

The separation of different components of whole blood using a centrifuge is an example of its usage in a clinical environment. Serum or plasma is required for several tests and can be obtained by centrifugation.

A full blood sample is allowed to clot at room temperature in order to get serum. The clot is subsequently removed from the sample by centrifugation, leaving a serum supernatant behind.

Plasma, in contrast to serum, is made from whole blood that has not been allowed to clot; it contains serum as well as clotting factors. A full blood sample is taken in tubes that have been anticoagulant-treated in order to get plasma.

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Answer:

True

Explanation:

Because it is:)

Answer:

A peptic ulcer is a sore on the lining of your stomach or the first part of your small intestine (duodenum). If the ulcer is in your stomach, it is called a gastric ulcer. If the ulcer is in your duodenum, it is called a duodenal ulcer

Answer:

A

Explanation:

THAT is th equation for Potential Energy

Answer:

this is question is trying to trick you

Explanation:

it gives long words but all you need to know is just a few

the second law of reflection states that the angle of incidence equals to the angle of reflection

so if the angle of incidence = 30

then

the angle of reflection = 30

hope this helps,

please mark it brainliest

Answer:

b

Explanation:

For C scale  , water freezes at 0 and boils at 100 C

Answer:

You must exert a force of 4.5 N on a book to slide it across a table.

Explanation:

Answer:

a. Pure white

b. Pure black

c. Hybrid

Answer:

drop in water

Explanation:

follow me m mm m

Answer:

magnetic force

Explanation:

when some one gets charged up by maybe static eletricity the person will sustain the energy and the energy will make a force field around the person which can and will attract paper and he will be attractive

Explanation:

Examples for effect of force - example

1) Can change the state of an object(rest to motion/ motion to rest):For example, pushing a heavy stone in order to move it. 2) May change the speed of an object if it is already moving. ... 3) May change the direction of motion of an object

Answer:

5kg

Explanation:

The cart with the least amount of mass will result in the fastest acceleration.

The cart with the fastest acceleration is 5 kg cart because its mass is the smallest.

The given parameters;

According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F = ma

The acceleration of the 5 kg cart is calculated as follows;

\(a = \frac{F}{m} \\\\a = \frac{90}{5} = 18 \ m/s^2\)

The acceleration of the 6 kg cart is calculated as follows;

\(a = \frac{F}{m} \\\\a = \frac{90}{6} = 15 \ m/s^2\)

The acceleration of the 8 kg cart is calculated as follows;

\(a = \frac{F}{m} \\\\a = \frac{90}{8} = 11.25 \ m/s^2\)

The acceleration of the 9 kg cart is calculated as follows;

\(a = \frac{F}{m} \\\\a = \frac{90}{9} = 10 \ m/s^2\)

Thus, the cart with the fastest acceleration is 5 kg cart because its mass is the smallest.

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Answer: There are just simply limits to our perception of light because of our body's disposition and biological components.

Explanation: We can only see the light portion starting off simply because of how our eyes and brain process light. The cones in our eyes that are sensitive to the colors of red, green, and blue can only be stimulated to an extent. There are lights with significantly longer wavelengths such as radio and infrared waves that cannot stimulate these cones. Even other ones such as ultraviolet rays are not detected because they have served as damaging to our bodies, and over time we have evolved to become protected against them. Even when there are established limits to our vision, with a possible slight variation of them from person to person, it does not nullify the idea that there may be plenty of lights and forms of energy outside of our given range.

Answer:

any black ops i started playing crysis 3 its good and gta5

Explanation:

Answer:

Mobile Legend Bang Bang

Explanation:

:) :)

Answer:

False. In case of diffused reflection,each ray obeys the laws of reflection. The laws of reflections are not violated in diffused or irregular reflections.

Answer:

a typical meteorite’s weight, surface area, and coefficient of drag; air density close to Earth

Explanation:

i just took the quiz lol :3

Answer:

The answer is  6.67 Ohms

Explanation:

R = V/I

R = 120v/18A

R = 6.67 Ohms

... NO MATTER how many other devices are connected (in parallel) on the same circuit.

Answer: plants have internal and external structures that support growth and reproduction Examples of internal structures are the xylem and phloem Examples of external structures are the roots and stems. All of these structures provide plants with nutrients and food

Explanation: BRAIN

Answer:

No

Explanation:

Acceleration is the rate of change in velocity. Here the car maintains a constant speed, no change in velocity

Answer:

The correct answer is B. Algae and fungi are biotic; temperature and rainfall are abiotic.. FURTHER EXPLANATION. An ecosystem consists of all living and non-living factors in an environment that interact and that are interdependent with each other.. All living things or factors in an ecosystem are called biotic factors.Examples include organisms like plants, animals, humans, etc.

Explanation:

Answer:

19020.2702703

Answer:

The value we are given in the question is 1.24 * 10^7. This form of writing number is called scientific notation. The standard notation is the normal, regular way of writing numbers. Scientific notation and standard notations are interchangeable.

1.24 * 10^7 written in standard notation will be = 1.24 * 10000000 = 12400000.

Thus, the mass of the meteoroid was 12400000 kg.

Explanation:

The mass of the object that weighs 47.3 lbf on the surface of Planet Quixon, where the acceleration of gravity is one-third that on Earth, is approximately 141.6 lbm.

The weight of an object on Planet Quixon can be calculated using the formula:

w = m * g

where:

w = weight of the object

m = mass of the object

g = acceleration due to gravity

On Planet Quixon, the acceleration due to gravity is one-third the value on Earth. Therefore, the value of g is:

g = (1/3) * 32.2 = 10.73 ft/s²

To find the mass of the object, we rearrange the equation as:

m = w / g

Given that the weight of the object on Planet Quixon is 47.3 lbf, we can convert this to pounds-mass using the conversion factor 1 lbf = 1 lbm * g, where g is the acceleration due to gravity on Earth. Therefore, the weight in pounds-mass is:

47.3 lbf = 47.3 lbm * 32.2 ft/s² / 1 lbf = 1521.06 lbm

Now, we can find the mass of the object on Planet Quixon:

m = w / g = 1521.06 lbm / 10.73 ft/s² ≈ 141.6 lbm

Thus, the mass of the object that weighs 47.3 lbf on the surface of Planet Quixon, where the acceleration of gravity is one-third that on Earth, is approximately 141.6 lbm.

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The flux of the vector field F across the surface S in the indicated direction is -24π.  

We know that the flux of a vector field F across a surface S is given by the surface integral, ∫∫S F ⋅ dS. Here, dS is the surface area element, which is given by dS = ndS, where n is the unit normal to the surface S, and dS is the area element on the surface S. Let us determine the unit normal to the surface S. For the given surface S, we have the equation of the surface in cylindrical coordinates as z = 3r, where r = √(x^2 + y^2) is the radial coordinate. The unit normal to the surface S is then given by n = ( ∂z/∂r)i + ( ∂z/∂θ)j - k, where i, j, and k are the unit vectors along the x, y, and z axes respectively.  

We now evaluate the first integral. ∫∫S x4y dS = ∫₀⁴ ∫₀^(2π) (r cosθ) (4r sinθ) r dz dθ = 4 ∫₀⁴ ∫₀^(2π) r^3 cosθ sinθ dz dθ = 0. Using cylindrical coordinates, we have the equation of the surface S as z = 3r. Hence, z varies from 0 to 4, and r varies from 0 to √(16 − z^2). We now evaluate the second integral. ∫∫S z dS = ∫₀⁴ ∫₀^(2π) (3r) r dθ dz = 3 ∫₀⁴ ∫₀^(2π) r^2 dθ dz = 24π. Hence, we have ∫∫S F ⋅ dS = 3 ∫∫S x4y dS - ∫∫S z dS = 3(0) - 24π = -24π.

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The diffusive flux of oxygen through the LDPE sheet at steady state is approximately 5.11 x 10²⁶ (cm³STP)/(cm².s) at 298 K.

The diffusive flux of a substance is given by Fick's law, which states that the flux is proportional to the concentration gradient across the material and the diffusion coefficient of the substance. Mathematically, it can be expressed as J = -D * (ΔC/Δx), where J is the flux, D is the diffusion coefficient, ΔC is the concentration difference, and Δx is the distance.

In this case, we are given the oxygen pressures at the two faces of the LDPE sheet, which are 1000 kPa and 100 kPa. The concentration difference (ΔC) can be calculated using the ideal gas law: ΔC = ΔP / (RT), where ΔP is the pressure difference, R is the gas constant, and T is the temperature.

Substituting the given values and calculating, we find ΔC = (1000 kPa - 100 kPa) / (8.314 J/(mol·K) * 298 K) ≈ 3.798 x 10⁻³ mol/m^3.

Next, we need to convert the concentration difference to units of (cm³STP)/(cm^3) by multiplying it by Avogadro's number (6.022 x 10²³) and the molar volume at standard temperature and pressure (22.414 cm^3/mol). Thus, ΔC ≈ 3.798 x 10⁻³ mol/m³ * (6.022 x 10²³ cm³/mol) / (22.414 cm³/mol) ≈ 1.022 x 10²⁰ (cm³ STP)/(cm³).

The thickness of the LDPE sheet is given as 2 mm, which is equivalent to 0.2 cm. Using Fick's law, we can calculate the flux:

J = -D * (ΔC/Δx)

Since we are considering steady state conditions, the flux is constant throughout the material. Rearranging the formula, we have D = -J * Δx / ΔC.

The diffusion coefficient is a material-specific property and can vary. However, for simplicity, we can assume a typical value for oxygen diffusion in polymers, which is approximately 1 x 10⁻⁷ (cm²/s).

Substituting the given values, we have D ≈ -J * (0.2 cm) / (1.022 x 10²⁰(cm³ STP)/(cm³)).

Solving for J, we find J ≈ -1 x 10^7 (cm²/s) * (1.022 x 10²⁰ (cm³ STP)/(cm^3)) / (0.2 cm) ≈ -5.11 x 10²⁶ (cm³ STP)/(cm².s).

Since the flux is negative, indicating diffusion from high pressure to low pressure, we take the absolute value to obtain the magnitude of the flux, which is approximately 5.11 x 10²⁶ (cm³ STP)/(cm².s).

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Answer:

I love ur pfp! Ok here's a rough image of how a typical energy diagram works.  You give a little energy (A) and you get the potential that was in there all along.  Kinda like pushing a big rock off a cliff.  You do a little work then get a lot of energy out as the PE turns into other forms.  In a match it's heat and light

Is this correct?

Explanation: