ASAP!! If quadrilateral PQRS is a square, what are the coordinates of point E?

To find the volume of a prism, we need to first identify the formula for its volume. The formula for the volume of a prism is given by multiplying the base area (B) by the height (h). Therefore, the volume of the given prism is V=Bh.

We are given that the base area of the prism is B, which means that the area of the base of the prism is known. The base of a prism can be any polygon, such as a rectangle, triangle, or square. The formula for finding the area of different polygons is different, but it always involves finding the product of the length and width of the base.

Once we know the base area, we need to find the height of the prism. The height is the distance between the two parallel bases of the prism. It can be calculated by dividing the volume of the prism by the base area. Therefore, h=V/B.

To summarize, the volume of the prism is V=Bh, where B is the base area of the prism and h is its height. Once we know the base area, we can calculate the volume of the prism by multiplying it by its height. Remember to include the appropriate units (e.g., cubic centimeters or cubic inches) in your final answer.

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Answer: - 13

USE BEDMAS to solve:

-3 · 5 + (-1)^4 · 8 - 6

= -3 · 5 + 1 · 8 - 6

= -15 + 8 - 6

= -13

Answer: -13

Step-by-step explanation:

used a calculator to solve

The change-of-coordinates matrix from c to b is:

Q = [−2/5 3/5; 4/5 4/5]

To express the basis vectors of c in terms of the basis vectors of b.

This can be done by solving the equation [c1, c2] = [b1, b2]P, where P is the change-of-coordinates matrix from b to c.

We can write out the equation in components as follows:

1 3 = -3x + 2y

4 4 -4x + 3y

Solving this system of equations, we get x = -4/5 and y = 3/5. Therefore, the change-of-coordinates matrix from b to c is:

P = [−4/5 3/5; 2/5 1/5]

To find the change-of-coordinates matrix from c to b, we need to express the basis vectors of b in terms of the basis vectors of c.

This can be done by solving the equation [b1, b2] = [c1, c2]Q, where Q is the change-of-coordinates matrix from c to b.

We can write out the equation in components as follows:

-3 2 = 1x + 3y

-4 3 4x + 4y

Solving this system of equations, we get x = -2/5 and y = 3/5. Therefore, the change-of-coordinates matrix from c to b is:

Q = [−2/5 3/5; 4/5 4/5]

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Answer:

(x - 7)² + (y - 4)² = 49

Step-by-step explanation:

Given

Equation: x² + y² = 49

Required:

New Equation when translated 7 units right and 4 units up

Taking it one step at a time.

When the equation is translated 7 units right, this implies a negative unit along the x axis.

The equation becomes

(x - 7)² + y² = 49

When the equation is translated 4 units up, this implies a negative unit along the y axis.

(x - 7)² + (y - 4)² = 49

The expression can be further simplified but it's best left in the form of

(x - 7)² + (y - 4)² = 49

_____________________________________________________

\(4+2\times (-4)+8\times (-1)\)

_____________________________________________________

\(4-2\times 4+8\times (-1)\)

\(4-2\times 4-8\)

______________________________________________________

\(4-8-8\)

______________________________________________________

\(-4-8\)

\(-12\)

I hope this helps you

:)

Answer:

\((-\frac{2}{7},-\frac{65}{7} )\)

Step-by-step explanation:

By steps in the image:

Step 1:

To eliminate, you need one of the coefficients to be the same in both equations. We will use the term "-6x" found in the first equation.

To get this, multiply the entire second equation by 6 and simplify using the distributive property. The new equation is:

\(6x-6y=54\)

Step 2:

Now you need to subtract the first equation and the new version of the second equation. By doing this, the "-6x" in both equations will cancel each other out.

Step 3:

Solve for x in the given equation by:

Step 4:

Solve for y by:

Solution:

\((-\frac{2}{7},-\frac{65}{7} )\)

:Done

Answer:

it's super easy

7¹⁵/7¹⁴

7¹⁵-¹⁴

7¹ or 7

Step-by-step explanation:

I know it helped you :)

The transformations of the triangle ABC to A'B'C' are (a) and (e)

From the question, we have the following parameters that can be used in our computation:

ABC = (-6, 2), (-4, 6) and (-2, 2)

Rotate the triangle by 180 degrees

So, we have the following representation

Image 1 of ABC = (6, -2), (4, -6) and (2, -2)

Translate the triangle 1 units left

So, we have the following representation

A'B'C' = (5, -2), (3, -6) and (1, -2) ---- option (a)

Another possible sequence is as follows

Reflect the triangle across the x and y axes

So, we have the following representation

Image 1 of ABC = (6, -2), (4, -6) and (2, -2)

Translate the triangle 1 units left

So, we have the following representation

A'B'C' = (5, -2), (3, -6) and (1, -2) ---- option (e)

Hence, the transformations are (a) and (e)

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Answer:

a

Step-by-step explanation:

The example of quantitative data among the given options is option A. North America is moving across Earth's surface several centimeters per year

Quantitative data refers to numerical or measurable information. In option A, the statement provides specific numerical measurements by stating that North America is moving across Earth's surface several centimeters per year. This information can be quantified and measured, making it an example of quantitative data.

Options B, C, D, and E do not provide numerical or measurable information. They describe qualitative characteristics or observations that cannot be easily quantified or measured.

B. The river has flooded a low-lying area describes a qualitative observation of a flood occurrence.

C. The volcano is releasing much steam describes a qualitative observation of steam release.

D. Volcanoes are dangerous makes a general statement without providing specific numerical information.

E. When held, one rock feels heavier than another rock is a subjective comparison and does not provide specific quantitative measurements.

Therefore, option A is the example of quantitative data as it provides numerical information that can be measured and quantified.

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Answer:

0.65 grams

Step-by-step explanation:

0.5 of a banana is 1/2 of a banana. A full banana has 1.3g which means we can divide this by 2 to find the amount of protein in half a banana. 1.3 ÷ 2 = 0.65. There is 0.65g of protein in 0.5 of a banana.

Hope this helps!

Protein is 0.65 gram in 0.5 of a banana.

How much protein is in 0.5 of a banana?

By Unitary method,we can solve this problem.

But now question is what is the use of Unitary method ?

By some examples we can understand this concept.

Let cost of 5 pens is 50 rupees.

By Unitary method, cost of 1 pen is

\(\frac{50}{5} \\ = 10 \: rupees\)

Cost of 100 pens is \((100 \times 10) = 1000 \: rupees\)

Again length of 1 rope is 5 m

Then by Unitary method length of 5 rope is \((5 \times 5) = 25 \: m\)

Here given,One banana contains 1.3 grams of protein.

According to question we can say one banana has 1.3 grams of protein.

We want to find quantity of protein in 0.5 banana.

We know,

\(0.5 \: of \: banana = \frac{1}{2} \: of \: banana\)

Here quantity of protein in 1 banana is 1.3 grams

So,by Unitary method quantity of protein in \( \frac{1}{2} \) banana is

\((1.3 \times \frac{1}{2} ) \: grams \\ = \frac{13}{10} \times \frac{1}{2} \\ = 0.65 \: grams\)

Therefore 0.5 banana contain 0.65 grams protein.

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To make parallelogram WXYZ a square, the following conditions must be met:

1. All four sides of the parallelogram must have equal length.

2. The angles between adjacent sides must be 90 degrees.

Since a square is a special type of parallelogram with all sides equal and all angles equal to 90 degrees, we can determine the value of m that would make WXYZ a square by ensuring that these conditions are met. To find the value of m, we need more information about the dimensions or properties of the parallelogram WXYZ. Please provide additional details or measurements related to the parallelogram. The diagonals of a square are equal in length and bisect each other at 90-degree angles. The perimeter of a square is the sum of all four sides, and the area of a square is calculated by squaring the length of one side.In order for parallelogram WXYZ to be a square, it must have congruent sides and right angles at each vertex.

Since opposite sides of a parallelogram are congruent, we can equate the lengths of adjacent sides to find the value of m that would make it a square.

Let's assume that WX and XY are adjacent sides of the parallelogram.

If WX = XY, then the parallelogram would have congruent sides.

Let's say WX = m and XY = m.

To form a square, the angles at each vertex must be right angles. This means that WX and XY must be perpendicular to each other.

In a square, opposite sides are parallel, so the slopes of WX and XY must be negative reciprocals of each other.

The slope of WX can be represented as (change in y) / (change in x). Since it is perpendicular to XY, its slope will be the negative reciprocal of the slope of XY.

Let's assume the slope of XY is denoted as a. Then the slope of WX would be -1/a.

We can now equate the slopes of WX and XY:

-1/a = (change in y) / (change in x)

Simplifying this equation, we get:

a = -1

Therefore, the slope of XY is -1.

Now, we can equate the lengths of WX and XY:

m = m

Since WX = XY and both sides have length m, we can say that m = m.

So, any value of m would make parallelogram WXYZ a square as long as the sides WX and XY are congruent and perpendicular to each other, with a slope of -1.

hence, the value of m = -1.

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Answer:

A:4/5

Step-by-step explanation:

plug in the numbers into their respective variables and get
4/(3+2)

Add 3 and 2 and final answer is

4/5

Given:

The figure of a rhombus.

To find:

The value of x.

Solution:

We know that, if two lines intersect each other, then the vertically opposite angles are equal.

From the given figure it is clear that the diagonals intersect each other and construct two pairs of vertically opposite angles.

Since \(95^\circ\) and \(x^\circ\) are vertically opposite angles, therefore

\(x^\circ=95^\circ\)

Hence, the value of x is 95°.

\(\:\: \:\: \:\star\) We are asked to find out the distance between (1,5) and (-6,-2).We know the formula to find the distance between two points is given by -

\( \:\: \star \underline{ \sf{ Distance = \sqrt{ (y_2 -y_1)^2 + (x_2-x_1)^2}}}\\\)

As per question, points are -

Now that we are given the points, so we can put them into the formula and solve for distance between them.Which is -

\(\:\: \:\: \:\star \underline{ \sf{ Distance = \sqrt{ (y_2 -y_1)^2 + (x_2-x_1)^2}}}\\\)

\( \longrightarrow \sf Distance_{(AB)} = \sqrt{ (-2-5)^2 + (-6-1)^2 }\\\)

\(\:\:\:\:\:\longrightarrow \sf Distance_{(AB)}= \sqrt{ (-7)^2 + (-7)^2 }\\\)

\(\:\:\:\:\longrightarrow \sf Distance_{(AB)} = \sqrt{ 49+49 }\\\)

\(\: \:\:\:\: \:\longrightarrow \sf Distance _{(AB)}= \sqrt{ 98}\\\)

\(\: \:\:\: \:\longrightarrow \sf Distance_{(AB)} = \sqrt{49 \times 2}\\\)

\(\:\: \:\: \:\:\longrightarrow \sf\underline{ Distance_{(AB)} = 7√2}\\\)

\(\: \:\:\: \:\:\longrightarrow \sf Distance_{(AB) }= 9.89949......\\\)

\(\: \:\:\: \:\:\longrightarrow \sf \underline{Distance_{(AB) }= 9.9\:(Approx)}\\\)

Therefore, the distance between (1,5) and (-6,-2) is 7√2 or, 9.9 ( Approx).

Answer:

GCF(2y²z ​, 8yz²) = 2yz

Step-by-step explanation:

2y²z = (2yz) × y

8yz² = (2yz) × 4z

then

GCF(2y²z ​, 8yz²) = 2yz

Answer:

7.07 i believe since 10 divided by 2 sqr root is 7.07, and AC and CA are equal

Step-by-step explanation:

Step-by-step explanation:

for AC

\(sin(45) = \frac{x}{10} \)

rearrange and solve for x

\(10sin(45) = x\)

then do the same process with BA

18. An infant weighs 11 pounds which is equivalent to 4.98 kg. Using the 100/50/20 Rule, the required amount of fluid per day for an infant between 11-20 kg is 50 ml/kg/day. So, the required amount of fluid per day in ml is 4.98 kg x 50 ml/kg/day = 249 ml/day.

19. A child weighs 31lbs and 8 ozs which is equivalent to 14.21 kg. Using the 100/50/24 Rule, the required amount of fluid per day for a child over 20 kg is 20 ml/kg/day. So, the required amount of fluid per day in ml is 14.21 kg x 20 ml/kg/day = 284.2 ml/day.

If no oral fluids are consumed, the hourly IV flow rate to maintain proper hydration would be: 284.2 ml/day / 24 hours/day = 11.8 ml/hour.

The question is about fluid requirements for infants and children, and it is using the 100/50/20 Rule for Daily Fluid Requirements (DFR) to calculate the required amount of fluid per day for different weight ranges. The 100/50/20 Rule is a guideline used to determine the appropriate amount of fluid that infants and children should receive on a daily basis based on their weight. The rule states that for infants and children up to 10 kg, the recommended fluid intake is 100 ml/kg/day, for those between 11-20 kg it is 50 ml/kg/day, and for those over 20 kg it is 20 ml/kg/day.

The question also asking about the hourly IV flow rate to maintain proper hydration if no oral fluids are consumed.

This subject is part of pediatrics, more specifically in the field of fluid and electrolyte balance and management.

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Answer:

a) 12:12 simplified version is 1:1

b) 5:12:12 cannot be simplified

c) 12:5:12 cannot be simplified

d) 0.50:3.00:0.60

Step-by-step explanation:

Answer: 26.4 ft.

Step-by-step explanation: To find the numerical value of 8 meters in feet you need to use unit multipliers. In this case, you need to multiply 8 meters by 3.3 ft / 1 meter. This would cancel out the meters, making the unit feet. 8*3.3 = 26.4, so the answer is 26.4 ft.

Answer:

7. b

8. a

Step-by-step explanation:

Answer:

i dont know

Step-by-step explanation:

i dont know mother fucker

Answer:

-3

Step-by-step explanation:

Answer: -3

Step-by-step explanation: The additive inverse tells us that if we

add a number and the opposite of that number, the result will be 0.

So in this problem, 3 + (-3) = 0.

In summary, the Fourier coefficients for the periodic function y(t) = -3 on the interval -5 ≤ t ≤ 5 are:

c₀ = -3 (DC component)

cₙ = 0 for n ≠ 0 (other coefficients)

To find the Fourier coefficients of the periodic function y(t) = -3 on the interval -5 ≤ t ≤ 5, we can use the formula for Fourier series coefficients:

cn = (1/T) ∫[t₀-T/2, t₀+T/2] y(t) \(e^{(-i2\pi nt/T)}\) dt

where T is the period of the function and n is an integer.

In this case, the function y(t) is constant, y(t) = -3, and the period is T = 10 (since the interval -5 ≤ t ≤ 5 spans 10 units).

To find the Fourier coefficient c₀ (corresponding to the DC component or the average value of the function), we use the formula:

c₀ = (1/T) ∫[-T/2, T/2] y(t) dt

Substituting the given values:

c₀ = (1/10) ∫[-5, 5] (-3) dt

  = (-3/10) \([t]_{-5}^{5}\)

  = (-3/10) [5 - (-5)]

  = (-3/10) [10]

  = -3

Therefore, the DC component (c₀) of the Fourier series of y(t) is -3.

For the other coefficients (cₙ where n ≠ 0), we can calculate them using the formula:

cₙ = (1/T) ∫[-T/2, T/2] y(t)\(e^{(-i2\pi nt/T) }\)dt

Since y(t) is constant, the integral becomes:

cₙ = (1/T) ∫[-T/2, T/2] (-3) \(e^{(-i2\pi nt/T)}\) dt

  = (-3/T) ∫[-T/2, T/2] \(e^{(-i2\pi nt/T)}\) dt

The integral of e^(-i2πnt/T) over the interval [-T/2, T/2] evaluates to 0 when n ≠ 0. This is because the exponential function oscillates and integrates to zero over a symmetric interval.

all the coefficients cₙ for n ≠ 0 are zero.

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Fraction 12 over 2 can be used to calculate the rate per second at which the machine launches the balls

The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is

m=y₂-y₁/x₂-x₁

The x axis label is Time in seconds, and the x axis values are from 0 to 10 in increments of 2 for each grid line.

The y axis label is Number of Balls, and the y axis values from 0 to 60 in increments of 12 for each grid line

A line is shown connecting points on ordered pair (2, 12) and (4, 24) and (6, 36) and (8, 48)

m=24-12/4-2

m=12/2

Hence,  fraction 12 over 2 can be used to calculate the rate per second at which the machine launches the balls

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A provision that ensures performance fees are not earned until the value of a fund exceeds its previous highest level is referred to as High-water mark

A high-water mark is the highest peak in value that an investment fund or account has reached. This term is often used in the context of fund manager compensation, which is performance-based.

The high-water mark ensures the manager does not get paid large sums for poor performance. If the manager loses money over a period, he must get the fund above the high-water mark before receiving a performance bonus

With a high-water mark, the investor pays a fee that only covers the amount the fund earned between the point of entry and its highest level.

The high-water mark prevents this "double fee" from occurring.

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