Answer:
48384 cm^3
Step-by-step explanation:
V = w x l x h = A x h = 672 x 72 = 48384 cm^3
The table represents the number of cheese crackers in the lunchboxes of 9 boys and 9 girls. By looking at the table, does it appear that the degree of variability for the boys' data is greater, less, or the same as the girls' data? Compute the interquartile range of each data set. Using the interquartile range, compare the degree of variability between the data sets. Explain how the comparison supports your first answer. Responses
The boys' data has a greater degree of variability
How to solveThe table displays the number of cheesy biscuits within lunchboxes for a group of 18 children, comprising 9 boys and 9 girls.
It outlines individual values for both sets of data:
Boys: 5, 7, 9, 11, 13, 15, 18, 20, 22
Girls: 8, 10, 12, 12, 13, 14, 15, 16, 18.
Upon calculating the interquartile range (IQR) for each respective dataset.
The following values were obtained: Boys' IQR calculates to an approximately higher value of 11 as compared to the girls who have an IQR of nearly five points lower than that of the former at only five points in magnitude.
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The table below represents the number of cheese crackers in the lunchboxes of 9 boys and 9 girls:
Boys Girls
5 8
7 10
9 12
11 12
13 13
15 14
18 15
20 16
22 18
Examining the table, is the degree of variability in the boys' data greater, lesser, or equal to the girls'? Work out the interquartile range of each set. Utilizing the interquartile range, compare the magnitude of variability between the two sets. Describe how the comparison affirms your first answer.
Please help me I on 1-15 it’s past due ty!!❤️
Answer:
Problem 1 all you need to do is move the decimal place over four times as it says in your text book. Start out by making the decimal point visible by doing this 58,927. right there then move it over four times like this 5,892.7 one 589.27 two 58.927 three 5.8927 four. When they say move it over four places that's what it means. Now you should be able to do the rest on your own. GOOD LUCK!!!
Each year on Mother's Day, Bert gives his mom a handmade card. This year, he's making her
a card shaped like a trapezoid that opens to reveal pop-up roses. The trapezoid has a height
of 6 inches. One of the bases is 5 inches long, and the other base is 8 inches long.
What is the area of the trapezoid?
Answer: 39 square inches
Step-by-step explanation:
area of trapezium = 0.5 X (sum of parallel sides) X height
= 0.5 X (5 +8) X 6
= 0.5 X 13 X 6
= 39 (square inches)
Solve (3x^2 - 1) (×^2 + 4) and classify the polynomial.
Answer:
Step-by-step explanation:
Who can solve for Y ? 2y < -4
Answer:
y < -2
Step-by-step explanation:
2y < -4
Divide both sides by 2.
y < -2
Answer:
y <-2. :::::::::::::::::::::::
Step-by-step explanation:
2y< -4 ==> y<-2
1a) The sum of the interior angles of a triangle depends on the lengths of each side. True or False?
The inside angles of any triangle always add to 180 degrees. This is regardless of what the side lengths are.
Answer: False.
Step-by-step explanation:
No matter the length of a triangle's sides, the interior angles will always add up to 180 degrees (on a singular place). You can see a visual of this attached.
The maximum value of y = cos x for -π/2 < x < π/2
0
1
π
Answer:
(0,1)
Step-by-step explanation:
Dhani has 4 cards numbered 1 through 4. He removes 2 cards at random and adds their values. What is the probability that the sum is less than or equal to 5?
Answer:
2/3
----------------------
THIS IS URGENT!
In orde to keep a specific bacteria alive,the temperature in a science lab cannot exceed -20 degrees farenheit. The electricity went out when the temperature was -72 degrees farenheit,but it increasing at a rate of 6.5 degrees per hour. How many hours do scientists have until the bacteria is not safe?
Which function is a quadratic function? A. c(x) = 6x + 3x3 B. d(x) = x – 8x4 C. p(x) = –5x – x2 D. k(x) = 2x2 + 9x4
This is the same as p(x) = -x^2-5x
The degree is the largest exponent to determine what kind of polynomial we're dealing with.
For choice C, the degree is 2, so we have a quadratic here.
-----------
Extra info:
Choice A is cubic because the largest exponent is 3 (degree = 3)Choice B is a quartic of degree 4Choice D is the same story as choice Bthe equation of the plane that passes through points (1, 1, 1), (2, 0, 3), and (-1, 4, 2) is ax by cz d
The equation of the plane is ax + by + cz + d = 0, where a = -1, b = -5, c = -5, and d = 11.
The equation of the plane that passes through points (1, 1, 1), (2, 0, 3), and (-1, 4, 2) can be found using the point-normal form of the equation of a plane.
To find the normal vector of the plane, we can take the cross product of two vectors formed by the given points. Let's call the vectors formed by (1, 1, 1) and (2, 0, 3) as vector A, and the vectors formed by (1, 1, 1) and (-1, 4, 2) as vector B.
Vector A = (2-1, 0-1, 3-1) = (1, -1, 2)
Vector B = (-1-1, 4-1, 2-1) = (-2, 3, 1)
Now, taking the cross product of A and B, we get the normal vector of the plane:
Normal vector = A x B = (1, -1, 2) x (-2, 3, 1) = (-1, -5, -5)
Using the normal vector and one of the given points (let's use (1, 1, 1)), we can write the equation of the plane as:
-1(x - 1) - 5(y - 1) - 5(z - 1) = 0
Simplifying the equation, we get:
-x - 5y - 5z + 11 = 0
So, the equation of the plane is ax + by + cz + d = 0, where a = -1, b = -5, c = -5, and d = 11.
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Describe the UDP segment fields with the segment structure diagram.
UDP (User Datagram Protocol) is a transport layer protocol that provides a lightweight, connectionless communication mechanism in IP networks.
The UDP segment consists of several fields that carry information necessary for the delivery of data. The segment structure diagram illustrates the different fields within a UDP segment:
0 7 8 15 16 23 24 31
+--------+--------+--------+--------+
| Source Port | Destination |
| | Port |
+--------+--------+--------+--------+
| Length | Checksum |
+--------+--------+--------+--------+
| |
| Data (if any) |
| |
+---------------------------+
The fields in the UDP segment include:
Source Port (16 bits): Identifies the source application or process port number.
Destination Port (16 bits): Specifies the destination application or process port number.
Length (16 bits): Indicates the length of the UDP segment, including the header and the data, in bytes.
Checksum (16 bits): Provides error detection by verifying the integrity of the UDP segment.
Data: Contains the actual payload or application data being transmitted.
The UDP segment is a minimalistic and simple structure, primarily focused on providing an efficient and lightweight transport mechanism without the overhead of error recovery and flow control present in TCP (Transmission Control Protocol).
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Carlos picked one of four equations in the table to solve. Carlos correctly solved the equation he chose. His answer was x = 5.
Equation 1 6x + 40 = 82
Equation 2 12x- 1 = 2
Equation 3 2x + 21 = 31
Equation 4 18x+ 9 = 13
Which equation did Carlos choose to solve?
The number of rugby supporters at a match is 498000 correct to the nearest 1000 write down the error interval for the number of supporters at the match.
Answer:
1000/2=500
Max=498000+500=498500
Min=498000-500=497,500
497500≤c<498500
Step-by-step explanation:
help pls I will give you brainlist Homework #25
Why Is a Party Like Pouring Oil Into a Car? Do each exercise and find your answer at the bottom of the page. Write the letter of Ihe exercise in the box above or below the answer:
I. Find the measure of the angle that is complementary to the angle having the measure given:
20° 67° 14° 81° 45°
II. Find the measure of the angle that is supplementary to the angle having the measure given.
III. Find the angle measure that is not given.
I.
The measure of the angle that is complementary to the angle 20° is 70°, 67° is 23°, 14° is 76°, 81° is 9° and 45° is 45°.
The sum of the complementary angles is 90°
Thus,
The complement of the angle 20° is 90°-20°=70°
The complement of the angle 67° is 90°-67°=23°
The complement of the angle 14° is 90°-14°=76°
The complement of the angle 81° is 90°-81°=9°
The complement of the angle 45° is 90°-45°=45°
II.
The measure of the angle that is supplementary to the angle 120° is 60°, 56° is 124°, 29° is 151°, 162° is 18° and 83° is 97°.
The sum of the supplementary angles is 180°
Thus,
The supplement of the angle 120° is 180°-120°=60°
The supplement of the angle 56° is 180°-56°=124°
The supplement of the angle 29° is 180°-29°=151°
The supplement of the angle 162° is 180°-162°=18°
The supplement of the angle 83° is 180°-83°=97°
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Please help me solve this. With Reasoning
6 2/5 - 4 2/3
Answer:
1 and 11/15.
Step-by-step explanation:
To solve, we can separate the integers from the fractions.
(6 - 4) + (2/5 - 2/3)
= 2 + (6/15 - 10/15)
= 2 + (-4/15)
= 1 + 15/15 - 4/15
= 1 + 11/15
= 1 and 11/15
Hope this helps!
PLEASE PLEASE HELP :)))))
Answer:
below
Step-by-step explanation:
Part A)
The radius of a circle is half of its diameter.
Therefore, the radius of the circle is:
radius = diameter/2 = 8cm/2 = 4cm
So, the radius of the circle is 4cm.
You can also find radius by just dividing the diameter in half, or by 2.
Part B)
The area of a circle can be found using the formula:
Area = πr^2
where π is the mathematical constant pi (approximated as 3.14), and r is the radius of the circle.
Substituting the values given in the question, we get:
Area = πr^2
= 3.14 × (4cm)^2
= 3.14 × 16cm^2
Therefore, the area of the circle is:Area = 50.24cm^2 (rounded to two decimal places)
So, the area of the circle with a diameter of 8cm is 50.24cm^2.
which is a factor of 6z² - 3z - 2 +4z?
The answer is ( 2x-1) (3X+2)
In mathematics, factorization or factoring consists of writing a number or another mathematical object as a product of several factors, usually smaller or simpler objects of the same kind. For example, 3 × 5 is a factorization of the integer 15, and is a factorization of the polynomial x² – 4.
STEP 1-: Combine like terms
6z²-3Z-2+4Z
6Z²+1Z-2
STEP 2-: Multiply by 1
6Z²+1Z-2
6Z²+Z-2
STEP 3-: Use the sum-product pattern
6Z²-3Z-2+4Z
6Z²+4Z-3Z-2
STEP4-: Common factor from the two pairs
6Z²+4Z-3Z-2
2Z(3Z+20) -1 (3Z+2)
STEP 5-:Rewrite in factored form
2Z(3Z+20) -1 (3Z+2)
(2Z-1) (3Z+2)
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cly cloudy
Watch help video
Solve for x, rounding to the nearest hundredth.
110 • 10^4x = 55
\(110\cdot 10^{4x}=55\implies 10^{4x}=\cfrac{55}{110}\implies 10^{4x}=\cfrac{1}{2}\implies 10^{4x}=2^{-1} \\\\\\ \log\left( 10^{4x} \right)=\log\left( 2^{-1} \right)\implies 4x\log_{10}\left( 10 \right)=-1\log_{10}(2)\implies 4x(1)=-\log(2) \\\\\\ 4x=-\log(2)\implies x=-\cfrac{\log(2)}{4}\implies {\LARGE \begin{array}{llll} x\approx -0.08 \end{array}}\)
The sum of four consecutive integers is 298. What is the largest integer?
Answer:
largest number =76
Step-by-step explanation:
let the consecutive integers be x,x+1,x+2,x+3
x+x+1+x+2+x+3=298
4x+6=298
4x=298-6
4x=292
x=292/4=73
numbers are 73,74,75,76
kiro and lito were assigned the same book to read for a class. kiro started reading on Saturday, and he's reading 20 pages a day. Lito didn't start until Sunday, but he is reading 25 pages a day. How many days will it take Lito to catch up to kiro and how many pages will they have each read?
what system of equations represents this situation and how do you solve it?
4
well located at point A,B,C,D respectively. ABCD form a square.
when water is pumped out from A only. the drawdown at the center of
square is 15ft
4 wells located at point A,B,C,D, respectively. ABCD form a square. When water is pumped out from A only, the drawdown at the center of square is 15 ft. If water is pumped out from A, B, C with same rate while water is pumped into ground at D with the same rate, What is the drawdown(ft) at the center of ABCD square?
When water is pumped out from well A in a square formed by wells A, B, C, and D, the drawdown at the center is 15 ft. If water is pumped out from A, B, and C while pumped into D, the drawdown at the center is uncertain.
In the given scenario, pumping water out only from well A causes a drawdown of 15 ft at the center of the square formed by wells A, B, C, and D. However, when water is simultaneously pumped out from wells A, B, and C, while being replenished at well D, determining the drawdown at the center becomes more complex. The drawdown at the center of the square will depend on various factors such as the rate of pumping, the permeability of the aquifer, the distance between the wells, and the properties of the surrounding geology. Without specific information regarding these factors, it is not possible to determine the exact drawdown at the center.
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Identify the expressions for which limits exist.
Answer:
Step-by-step explanation:
Limits exist for:
\(\lim_{x \to4 \4} \frac{x^2 -x-12}{4-x}\) = \(\frac{(x-4)(x+3)}{4-x}\) = ( - 1 )( x + 3 ) = - 7
\(\lim_{x \to \ 2} \frac{x^2 +2x-8}{2-x}\) = \(\frac{(x+4)(x-2)}{2-x}\) = ( - 1 )( x + 4 ) = - 6
\(\lim_{x \to2 } \frac{x^2 +3x - 10}{x^2 -4}\) = \(\frac{(x+5)(x-2)}{(x+2)(x-2)}\) = \(\frac{x+5}{x+2}\) = \(\frac{7}{4}\)
Collect like terms: a) a³, a², 2ab, 2a², a, -a²
Answer:
-a²,a, a²,2a²,a³,2ab
Step-by-step explanation:
-------
Find all points on the y-axis that are 5 units from the point (4, 6). (smaller y-value)(x, y) = (larger y-value)
Step 1:
Write the parent coordinates
(4 , 6)
Step 2
The point can bo on the positive y-axis or on the negative y-axis.
New coordinates
( 4 + 5, 6 + 5)
= (9 , 11)
Or
( 4 - 5, 6 - 5)
= (-1 , 1)
Final answer
Smaller y-value = 1
Larger y-value = 11
Please help with this question
Answer:
picture A goes with c y= 2x^2
im not sure about B and C sorry but i got A for you
Step-by-step explanatioxn:
Answer:
a) C
b) A
c) B
Step-by-step explanation:
Please see the attached screenshot for details.
Graph A represents y = x² - 1, which is the vertical translation of the graph 1 unit down.
Graph B represents y = 2x², which is the narrowing of the parent graph, y = x².
Graph C represents y = x² - 1, which is the horizontal shifting of the parent graph, 1 unit to the left.
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1-87 Plot the points A(3,2) B(3,6) C(5,4) on a piece of graph paper and translate the figure up 2 units
and left 5 unita.
the points will become from ( x , y ) to ( x - 5 , y + 2) and these has been plotted on the graph.
We are given the coordinates of the points:
A (3 , 2)
B (3 , 6)
C (5 , 4)
We need to plot them on the graph paper.
Now, we need to translate the points 2 units to the up and 5 units to the left.
So, the coordinates will change from ( x , y ) to ( x - 5 , y + 2)
So, we get that:
A (3 , 2) will become A' ( - 2 , 4)
B (3 , 6) will become B' ( - 2 , 8)
C (5 , 4) will become C' ( 0 , 6)
Therefore, we get that, the points will become from ( x , y ) to ( x - 5 , y + 2) and these has been plotted on the graph.
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what is the sigh of 48 2/9 + (-39 8/9)
Choose 1 answer:
Positive
ON
Negative
Neither positive nor negative-the sum is zero.
Answer:
NEGATIVE SIGH
Step-by-step explanation:
The Answer is 24
Answer:
the answer is positive
Identify the independent and dependent variable for the given situation. The amount of
distance covered by a car in a certain amount of time.
Answer:
distance = independant; time = dependant
Step-by-step explanation:
You are able to change the distance you travel, making it the independant. As you go farther, the time increases, so it is dependant on the distance traveled, therefore it is the dependant.
An engineer is designing a fuel tank in the shape of a cylinder. The tank must have a volume of 3,500 cubic inches. The height of the cylinder must be twice the radius. What is the approximate radius of the cylinder?.
An engineer is designing a fuel tank in the shape of a cylinder, the approximate radius of the cylinder is 8.2 inches.
Volume:
V = πr²h
Height:
h = 2r
V = πr²h
V= πr²(2r)
V= 2πr³
And we know that the volume must be 3,500 in³, now we can replace that and solve for R, we will get:
V= πr²h
3500 = 3.14 x 2 x (r)³
r = 8.2 inch
The cylinder's approximate radius must be 8.2 inches.
One of the most fundamental curvilinear geometric shapes, a cylinder has historically been a three-dimensional solid. It is regarded as a prism with a circle as its base in basic geometry. In several contemporary fields of geometry and topology, a cylinder can alternatively be characterised as an infinitely curved surface.
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