Asap please what is the answer???

The expected payout for one draw is $0.19327.

To calculate how much Mark should pay for one draw, we need to determine the probability of drawing each type of card and the corresponding payouts, and then take a weighted average.

There are 13 clubs in the deck, so the probability of drawing a club is 13/52 = 1/4. The payout for a club is $0.50.

There are 4 aces in the deck, so the probability of drawing an ace is 4/52 = 1/13. The payout for an ace is $0.65.

There is only one ace of clubs in the deck, so the probability of drawing the ace of clubs is 1/52. The payout for the ace of clubs is $0.95.

To calculate the weighted average payout, we can multiply the probability of each outcome by its corresponding payout, and then add up the products:

(1/4) x $0.50 + (1/13) x $0.65 + (1/52) x $0.95 = $0.125 + $0.05 + $0.01827

So the expected payout for one draw is $0.19327.

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The rate at which the distance is changing is calculated to be 14.42 miles per hour.

Consider the east direction to be denoted by x and the north direction to be denoted by y, therefore;

dx / dt = 12 mph

dy / dt = 8 mph
x is equal to 4 miles

Consider the distance between them to be s

Time taken by you to travel 4 miles = distance / speed

Time taken by you to travel 4 miles = 4/12 hour

Distance traveled by the friend in that time = speed × time

Distance traveled by the friend in that time = 8 × (4/12) = 2.67 miles

Now we use the Pythagorean theorem,

x^2 + y^2 + s^2 ...... (1)

Substitute, x = 4 miles and y = 2.67 miles

s^2 = 16 + 7.1289 = 23.1289

s = 4.81

Now differentiate equation 1 with respect to t as follows;

2x (dx/dt) + 2y (dy/dt) = 2s (ds/dt)

2(4) (12) + 2(2.67) (8) = 2 (4.81) (ds/dt)

96 + 42.72 = 9.62 (ds/dt)

138.72 = 9.62 (ds/dt)

ds/dt = 138.72/9.62 = 14.42 miles per hour

Thus the distance is changing at the rate of 14.42 miles per hour.

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Answer:

1

Step-by-step explanation:

Substitute the value of the variable into the expression and simplify.

4-2-1=1

Answer:

1

Step-by-step explanation:

a-b+c

=4-2+(-1)

=2-1

=1

As the firm develops a specific sort of sensor and ships them in boxes of four, each sensor weighed 10 grams at first.

In its most basic form, an equation is a mathematical statement that indicates that two mathematical expressions are equal. 3x + 5 = 14, for example, is an equation in which 3x + 5 and 14 are two expressions separated by a 'equal' sign. A mathematical phrase with two equal sides separated by an equal sign is called an equation. An example of an equation is 4 + 6 = 10.

Here,

Let's call the original weight of each sensor "w". The total weight of 4 sensors would be 4w.

With the new design, each sensor weighs 9 grams more, so each sensor weighs w + 9 grams. The total weight of 4 sensors is 76 grams, so we can write an equation:

4(w + 9) = 76

Expanding the left-hand side and solving for w, we have:

4w + 36 = 76

4w = 40

w = 10

So each sensor originally weighed 10 grams as company manufactures a special type of sensor, and packs them in boxes of 4 for shipment.

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Therefore, the angle of rotation at which point A' coincides with point D is 144°.

Pentagons are polygons since they have five sides and five angles. The name "Pentagon" is made up of two other words, Penta and Gonia, both of which signify five angles. A pentagon's sides come together end to end to form the shape. In light of this, a pentagon has five sides.

To find the angle of rotation at which point A' coincides with point D, we need to determine the angle measure of each vertex of the regular pentagon.

In a regular pentagon, each interior angle measures (5-2)*180/5 = 108°. Therefore, the exterior angle at each vertex of the pentagon measures 180 - 108 = 72°.

To rotate the pentagon counterclockwise so that point A' coincides with point D, we need to rotate the pentagon by 2/5 of a full rotation, or 144°.

Therefore, the angle of rotation at which point A' coincides with point D is 144°.

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Riley has a solar panel with a width of 25 inches. To get the proper inclination for her climate, she needs a night triangluar support frame that has one leg twice as long as the other leg. To the nearest tenth.The dimensions of the triangular support frame should be approximately 11.2 inches by 22.4 inches.

To solve this problem, we can use the Pythagorean theorem, which states that for a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Let's call the shorter leg of the triangular support frame "x" inches. Since the other leg is twice as long as the shorter leg, it will be "2x" inches. The solar panel's width (25 inches) will act as the hypotenuse in this case.

According to the Pythagorean theorem: 25^2 = x^2 + (2x)^2 625 = x^2 + 4x^2 Combining the x terms: 625 = 5x^2 Dividing by 5: 125 = x^2 Now, we'll take the square root of both sides: x ≈ 11.2 (to the nearest tenth)

So, the shorter leg (x) should be approximately 11.2 inches long, and the longer leg (2x) should be approximately 22.4 inches long.

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A. N, B ≥ 0 (non-negativity constraint)

B. The recommended investment portfolio (in dollars) for this client can be found by reading the values in cells A1 and B1.

C.  You can solve for the recommended investment portfolio (in dollars) by reading the values in cells A1 and B1.

D. You can solve for the recommended investment portfolio (in dollars) by reading the values in cells A1 and B1.

(a)

The linear programming model to find the best investment strategy for this client can be formulated as follows:

Maximize: 0.09N + 0.08B

Subject to:

N + B ≤ 85 (maximum investment of $85,000)

N ≤ 55 (maximum investment of $55,000 in the internet fund)

6N + 4B ≤ 410 (maximum risk rating of 410 for a moderate investor)

N, B ≥ 0 (non-negativity constraint)

(b)

To solve the problem using Excel Solver, you can set up the following spreadsheet model:

Cell A1: N (amount invested in the internet fund)

Cell B1: B (amount invested in the Blue Chip fund)

Cell C1: =0.09A1 + 0.08B1 (annual return for the portfolio)

Constraints:

Cell A2: ≤ 85

Cell B2: ≤ 85

Cell C2: ≤ 55

Cell D2: ≤ 410

The objective is to maximize the value in cell C1 by changing the values in cells A1 and B1, subject to the constraints.

Using Excel Solver, set the objective to maximize the value in cell C1 by changing the values in cells A1 and B1, subject to the constraints in cells A2, B2, C2, and D2.

The recommended investment portfolio (in dollars) for this client can be found by reading the values in cells A1 and B1.

(b)

For the aggressive investor with a maximum portfolio risk rating of 450, the linear programming model remains the same, except for the constraint on the maximum risk rating.

The new constraint would be: 6N + 4B ≤ 450

Using the same spreadsheet model as before, with the updated constraint, you can solve for the recommended investment portfolio (in dollars) by reading the values in cells A1 and B1.

(d)

For the conservative investor with a maximum portfolio risk rating of 320, the linear programming model remains the same, except for the constraint on the maximum risk rating.

The new constraint would be: 6N + 4B ≤ 320

Using the same spreadsheet model as before, with the updated constraint, you can solve for the recommended investment portfolio (in dollars) by reading the values in cells A1 and B1.

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Answer:

The answer is 6

Step-by-step explanation:

I just took the test and got a 100% on it

In terms of the percentage of downloaded books, the sampling distribution's mean is 0.03 and its standard deviation is 0.0197.

Central Limit Theorem:

The sampling distribution of the sample percentage for a proportion p in a sample of size n will be roughly normal with a mean (μ = p) and standard deviation \(s = \sqrt{\frac{p(1-p)}{n} }\).

In a given year, 3% of books checked out from the library are downloaded.

That means p = 0.03

and n = 75

By the Central Limit Theorem

Mean = μ = p = 0.03

Standard deviation =  \(s = \sqrt{\frac{p(1-p)}{n} }\)

                                   \(s = \sqrt{\frac{(0.03)(0.97)}{75} }\)

                                   \(s=0.0197\)

Hence,

         In terms of the percentage of downloaded books, the sampling distribution's mean is 0.03 and its standard deviation is 0.0197.

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Answer:

Below

Step-by-step explanation:

N, the number can be anything   greater than or equal to 11.5 and less than 12.5  

11.5 ≤  n < 12.5

Step-by-step explanation:

-5x+2y= 4         <==== Multiply entire equation by -3 to get:

15x-6y = -12  

2x+3y= 6          <====  Multiply entire equation by 2 to get :

4x+6y = 12    Add the two underlined equations to eliminate 'y'

19x = 0     so x = 0

sub in x = 0 into any of the equations to find:  y = 2

(0,2)

Given:

Lamont has purchased 20 trading cards.

He wants to have at least 50 trading cards.

To find:

The inequality for the number of trading cards Lamont needs and solve it.

Solution:

Let x be the number of trading cards Lamont needs.

He has 20 trading cards. So,

Total cards = x + 20

It is given that, he wants to have at least 50 trading cards. It means, total card must be greater than or equal to 50.

\(x+20\geq 50\)

Subtract 20 from both sides.

\(x+20-20\geq 50-20\)

\(x\geq 30\)

Therefore, the required inequality is \(x+20\geq 50\) and solution is \(x\geq 30\).

The number of trading cards that Lamont needs will be at least 30 trading cards.

From the information given, we are informed that Lamont has purchased 20 trading cards and wants to have at least 50 trading cards.

Therefore, the number that will be needed more will be:

= 50 - 20 = 30

Therefore, he'll need at least 30 more cards.

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To find the point where the particle crosses the y-axis, we first need to determine the equation of the tangent line at the point (-8,3) on the ellipse. So, the particle will cross the y-axis at the point (0, 169/3).

To do this, we need to find the derivative of the ellipse equation with respect to x:
(2x)/100 + (2y)/25(dy/dx) = 0
Simplifying this, we get:
dy/dx = - (10x)/(y)
At the point (-8,3), we have:
dy/dx = - (10(-8))/(3) = 80/3
So the equation of the tangent line is:
y - 3 = (80/3)(x + 8)
To find where this line crosses the y-axis, we set x = 0:
y - 3 = (80/3)(0 + 8)
y - 3 = 64
y = 67
Therefore, the particle will cross the y-axis at the point (0,67).

The terms "clockwise", "elliptical path (x^2)/100 + (y^2)/25 = 1", and "ellipse".
To find the point where the particle crosses the y-axis after leaving the orbit at point (-8,3), follow these steps:
1. Determine the slope of the tangent line at point (-8,3). Since the particle is traveling clockwise on the ellipse, we need the derivative of the ellipse equation with respect to x to find the slope. Differentiating implicitly:
2x/100 + 2y(dy/dx)/25 = 0
2. Solve for dy/dx (the slope):
dy/dx = - (2x/100) / (2y/25) = - (25x) / (100y)
3. Plug in the point (-8,3) to find the slope at that point:
m = - (25(-8)) / (100(3)) = 20/3
4. The equation of the tangent line is y - 3 = (20/3)(x + 8), since it passes through (-8,3). To find the point where the particle crosses the y-axis, set x = 0:
y - 3 = (20/3)(0 + 8)
5. Solve for y:
y - 3 = (160/3)
y = (160/3) + 3 = 169/3

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Answer:

3

Step-by-step explanation:

4 ^2+x^2=5^2

5^2-4^2=9

square root of 9=3

The circumference of the circle inscribed in a square of side 14 units is 43.96 units, on the basis of the fact that the diameter of the circle will be equal to the side of the square.

What is circumference?

Circumference is the length of a circle's boundary or the perimeter of any circular object or figure.A circle's circumference or an elliptical two-dimensional figure's perimeter are the same. Either the radius or the diameter of the circle are necessary components to calculate the circumference.

Circumference of circle=2πr       {where r=radius}

                                      =πd         {where d=diameter}

Given that the circle is inscribed in the square & it is the maximum possible circle that would fit inside the square of 14 units.

The diameter of circle= side of square that inscribes circle

                               d   = 14 units

Circumference of circle=πd

                                      =π(14)

                                      =14π      {in terms of π}

Circumference of circle=14π

                                      =14(3.14)            {taking π=3,14}

                                      =43.96 units

Circumference of circle=43.96 units

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The area under the curve between z = −2.0 and z = −1.0 is 0.1359.

We can use tables to find the area under the normal curve between two values of z.

However, tables give areas from z = 0 to z = 3.9 (beyond which there is literally no change). But as the normal curve is symmetric at z = 0, we can use it to find between any two given z values.

For example, for the area under the curve between z = −2.0 and z = −1.0, we can take values for z = 2.0 and z = 1.0; their difference will give the area between z = −2.0 and z = −1.0.

From tables for z = 1.0, we have 0.8413 and for z = 2.0, we have 0.9772 and

Hence, the Area under the curve between z = −2.0 and z = −1.0 is 0.9772−0.8413 = 0.1359.

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Answer:

Step-by-step explanation:

To find the highest common factor (HCF) of 12x^12 and 16x^16, we need to factor both expressions.

12x^12 = 2^2 * 3 * (x^2)^6

16x^16 = 2^4 * (x^2)^8

The common factors of 12x^12 and 16x^16 are 2^2 and (x^2)^6. To find the HCF, we take the product of these common factors:

HCF = 2^2 * (x^2)^6 = 4x^12

Therefore, the highest common factor (HCF) of 12x^12 and 16x^16 is 4x^12.

Answer:

4. rise

match the following definition with the correct term:

the vertical distance between two points on a line

1. run

2. rate of run

3. slope

4. rise

Descriptive and inferential statistics are two branches of statistics that work together to analyze and interpret data. The choice of which type to use depends on specific factors and objectives of the research or analysis being conducted.

Descriptive statistics involve summarizing and presenting data in a meaningful way. They include measures such as central tendency (mean, median, mode), dispersion (standard deviation, range), and graphical representations (histograms, box plots) to describe the characteristics of a dataset. Descriptive statistics provide a clear and concise summary of the data, enabling researchers to understand its distribution and key features.

On the other hand, inferential statistics involve drawing conclusions or making inferences about a population based on a sample. Inferential statistics use probability theory to make estimations, test hypotheses, and assess relationships between variables. They involve techniques such as hypothesis testing, confidence intervals, and regression analysis. Inferential statistics help researchers make generalizations or predictions about a larger population beyond the observed sample.

The choice between descriptive and inferential statistics depends on the research question, objectives, available data, and the level of understanding sought. Descriptive statistics are used to summarize and describe data, while inferential statistics are employed to make broader inferences and draw conclusions about populations. Both types of statistics are valuable and are utilized depending on the specific analysis goals and research context.

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Answer: 3.078139077

Step-by-step explanation:

Use the 1st digit 2 from dividend 2367800.

Since 2 is less than 769231, use the next digit 3 from dividend 2367800 and add 0 to the quotient.

Use the 2nd digit 3 from dividend 2367800.

Since 23 is less than 769231, use the next digit 6 from dividend 2367800 and add 0 to the quotient.

Use the 3rd digit 6 from dividend 2367800

Since 236 is less than 769231, use the next digit 7 from dividend 2367800 and add 0 to the quotient.

Use the 4th digit 7 from dividend 2367800.

Since 2367 is less than 769231, use the next digit 8 from dividend 2367800 and add 0 to the quotient.

Use the 5th digit 8 from dividend 2367800.

Since 23678 is less than 769231, use the next digit 0 from dividend 2367800 and add 0 to the quotient.

Use the 6th digit 0 from dividend 2367800.

Since 236780 is less than 769231, use the next digit 0 from dividend 2367800 and add 0 to the quotient.

Use the 7th digit 0 from dividend 2367800.

Find closest multiple of 769231 to 2367800. We see that 3×769231=2307693 is the nearest. Now subtract 2307693 from 2367800 to get reminder 60107.

Add 3 to quotient.

Quotient: 3

Reminder: 60107

It's not as difficult as it looks.

✨

Answer:

A) v = T/2 - 5

Step-by-step explanation:

T = 10+2v

2v = T-10

v = (T-10)/2 = T/2-5

The equation that describes no. of DVDs that Ingrid can rent is A.              v = (T/2) - 5.

An equation states that terms on both sides of the equality sign are equal.

The monthly membership costs 10 dollars, and The rent for each DVD costs 2 dollars.

No. of DVDs that can be rented is denoted by v based on T.

The equation that describes the total cost of renting DVDs is,

T = 2v + 10.

∴ The equation that describes no. of DVDs that can be rented is

2v = T  - 10.

v = (T/2) - 5.

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The area between the graph of y = x² - 7 and the x-axis, over the interval [2, 3] is 1.33.

Given equation: y = x² - 7

Integrating y with respect to x for the given interval [2,3]

using definite integral:∫[a,b] y dx = ∫[2,3] (x² - 7) dx = [(x³/3) - 7x] [2,3]

Now, putting the limits:((3³/3) - 7(3)) - ((2³/3) - 7(2))= (9 - 21) - (8/3 - 14)= -12 - (-10.67)

Therefore, the area between the graph of y = x² - 7 and the x-axis, over the interval [2, 3] is 1.33.

Using definite integral ∫[a,b] y dx = ∫[2,3] (x² - 7) dx for the given interval [2,3].

Putting the limits:((3³/3) - 7(3)) - ((2³/3) - 7(2))= (9 - 21) - (8/3 - 14)= -12 - (-10.67)

Therefore, the area between the graph of y = x² - 7 and the x-axis, over the interval [2, 3] is 1.33.

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Answer:

Lower Quartile: 7

Median: 12

Upper Quartile: 16.5

Step-by-step explanation:

First, to find anything you must reorganize the numbers according from smallest to biggest. In this case, it would be:

4, 6, 8, 9, 10, 14, 15, 16, 17, 18

Let's find the median first. The median is in the middle of the data set, and there are 10 numbers in this data set. We need to find the middle of two numbers to find the median, 10 and 14, which would be 12.

To find the lower quartile, you must look at the numbers below the median. Those would include 4, 6, 8, and 9. There is a even number of digits, meaning that we might find the middle of two numbers, 6 and 8, which is 7.

Then, the Upper Quartile which is the same process. Look at 15, 16, 17, and 18. It is a even number of digits so we need to find the middle of 16 and 17, which would equal 16.5.

Hope this helped!

The curve defined by the equation -8x^2 + 5xy + y^3 = -149 represents a relationship between the variables x and y. This equation defines a curve in the two-dimensional plane

We need to analyze the curve defined by the equation -8x^2+5xy+y^3=-149. This curve is a 2-dimensional object that can be plotted on a Cartesian coordinate system. In order to plot the curve, we need to first rewrite the equation in terms of y. Once we have the equation in terms of y, we can plot the curve by choosing different values of x and solving for y. This will give us a set of points that we can then plot on a graph. By connecting these points, we can create a visual representation of the curve.

In conclusion, to analyze the curve defined by the equation -8x^2+5xy+y^3=-149, we need to rewrite the equation in terms of y and then plot the curve by choosing different values of x and solving for y. This will give us a set of points that we can then plot on a graph. By connecting these points, we can create a visual representation of the curve.
To consider the curve defined by the equation -8x^2 + 5xy + y^3 = -149, we can analyze its features and discuss some of its properties. This curve is a type of implicit function, meaning that it is not possible to isolate either x or y to create an explicit function. Nonetheless, the equation is still useful for understanding the relationship between x and y.

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 From the list of numbers presented:

 we can determine that this is a infinite serie.

      A sequence is an order of elements that are governed by a pattern, that is, it has variations between each element that remain constant and allow us to determine values before or after the known elements.

 A sequence maintains an order, and this numerical order can be finite or infinite, in the given case we have the following list:

4/3, 7/3, 10/3, 13/3, 16/3

(1 + 3x)/3

  In this series we have the initial value of the same, but we do not know the final value, although we know its behavior, we can say that this series has no end, it is an infinite serie.

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Answer:

Options A, B and C are correct.

Step-by-step explanation:

The given expression is

\(-2\left(-8x-4y+\dfrac{3}{4}\right)\)

Using distributive property, we get

\(-2(-8x)-2(-4y)-2\left(\dfrac{3}{4}\right)\)

\(16x+8y-\dfrac{6}{4}\)

\(16x+8y-\dfrac{3}{2}\)

\(16x+8y-1\dfrac{1}{2}\)

It is given that Daniel expanded the expression as

\(-2\left(-8x-4\dfrac{3}{4}\right)=-10x-8y-1\dfrac{1}{4}\)

The first term should be positive.

The second term should be positive.

The last term should be Negative 1 and one-half, not Negative 1 and one-fourth.

Therefore, options A, B and C are correct.

Answer:

Option 1,2,3

Step-by-step explanation:

got it right

Answer :with what

Step-by-step explanation:

Fraction 12 over 2 can be used to calculate the rate per second at which the machine launches the balls

The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is

m=y₂-y₁/x₂-x₁

The x axis label is Time in seconds, and the x axis values are from 0 to 10 in increments of 2 for each grid line.

The y axis label is Number of Balls, and the y axis values from 0 to 60 in increments of 12 for each grid line

A line is shown connecting points on ordered pair (2, 12) and (4, 24) and (6, 36) and (8, 48)

m=24-12/4-2

m=12/2

Hence,  fraction 12 over 2 can be used to calculate the rate per second at which the machine launches the balls

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