ASHTON WANTS TO FIND THE VOLUME OF A BLOCK OF WOOD

The volume of gas increases by 25% when the volume falls below 21 with the constant temperature.

PV=nRT is the ideal gas equation.

PV is constant and equals k because the temperature is also constant.

Because there is 20% less pressure, P 2 = 0.8P and PV = V 2 V 2 = 0.8P PV, where PV = 0.8 V and V = 1.25V

Gas volume consequently increases by 25%.

The temperature of a system is constant during an isothermal process, which is a thermodynamic process. Thermal equilibrium is preserved because heat is transferred into or out of the system so slowly.

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Mg (1 mole) + 2HCl (2 mole) → MgCl (1 mole)  + H2 (1 mole)

Therefore, 1 mole of H2(g) are generated by the complete reaction of Mg(s) with excess HCl(aq).

When atoms establish or break chemical bonds, chemical processes take place. Reactants are the substances that begin a chemical reaction, while products are the compounds that are created as a result of the reaction.

A component that is present at the outset of a chemical reaction is known as a reactant. Products are the substance(s) to the right of the arrow. A substance that remains after a chemical reaction is complete is known as a product.

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Answer: the pressure of the gas after the compression is 3.88 atm

Explanation:

The question requires us to calculate the new pressure of a gas, given its initial volume at STP, new volume after compression and temperature after compression.

The following information was provided by the question:

Initial volume = V1 = 0.700 L

Final volume = V2 = 0.200 L

Final temperature = T2 = 30 °C = 303.15 K

To solve this problem, we can apply the equation for ideal gases (shown below) considering the conditions after the compression:

where R is the constant of gases (R = 0.082057 L.atm/K.mol), n is the number of moles of gas, T2 is the temperature after compression and V2 is the volume after compression.

Note that the number of moles of gas remains the same even after compression. Thus, we can calculate this number of moles considering the inital volume at STP, knowing that 1 mol of a gas at Standard Temperature and Pressure corresponds to 22.4 L of this gas:

22.4 L ------------------------- 1 mol

0.700 L ----------------------- x

Solving for x, we'll have:

Therefore, the number of moles before and after compression is 0.0312 mol.

Now that we have the values for n, T2 and V2, we can calculate the pressure after compression (P2):

Therefore, the pressure of the gas after the compression is 3.88 atm.

The correct answer is 25% CH4, 50% O2, 12.5% CO2, and 25% H2O by percentage composition.

According to the chemical equation, for every molecule of CH4 burned, we need two molecules of O2. So we can assume that we have 10 mL of CH4 and 40 mL of O2, which will react completely.

Using the ideal gas law, we can find the number of moles of each gas present:

n(CH4) = (0.020 L)(1.00 atm)/(0.0821 L atm/mol K)(298 K) = 0.000964 mol

n(O2) = (0.080 L)(1.00 atm)/(0.0821 L atm/mol K)(298 K) = 0.00386 mol

From the balanced equation, we see that the volume ratio of CH4 to CO2 to H2O is 1:1:2. Therefore:

n(CO2) = n(CH4) = 0.000964 mol

n(H2O) = 2n(CH4) = 0.00193 mol

The total number of moles in the mixture is:

n(total) = n(CH4) + n(O2) + n(CO2) + n(H2O) = 0.000964 + 0.00386 + 0.000964 + 0.00193 = 0.00772 mol

The percentage composition by volume of each gas is equal to the number of moles of the gas divided by the total number of moles, multiplied by 100%:

% CH4 = (0.000964 mol/0.00772 mol) x 100% = 12.5%

% O2 = (0.00386 mol/0.00772 mol) x 100% = 50%

% CO2 = (0.000964 mol/0.00772 mol) x 100% = 12.5%

% H2O = (0.00193 mol/0.00772 mol) x 100% = 25%

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The best description of the relationship between population size, carrying capacity, and limiting factors is: "The size of a population usually stays near its carrying capacity due to limiting factors."

Carrying capacity refers to the maximum number of individuals that a particular environment can sustainably support. It represents the limit to which a population can grow given the available resources, such as food, water, and habitat. Limiting factors, on the other hand, are the factors that restrict population growth by reducing birth rates, increasing death rates, or limiting access to resources.As a population approaches its carrying capacity, limiting factors come into play and regulate the population size. These limiting factors can include competition for resources, predation, disease, availability of suitable habitat, and other environmental factors. They act as checks on population growth, preventing it from exceeding the carrying capacity of the ecosystem.

Therefore, the size of a population usually stays near its carrying capacity because the limiting factors ensure that the population does not exceed the available resources and ecological limits of the environment. If the population surpasses the carrying capacity, the limiting factors will intensify, causing a decline in resources and an increase in mortality rates, which ultimately brings the population back towards the carrying capacity.It's important to note that the relationship between population size, carrying capacity, and limiting factors is dynamic and can vary depending on various ecological and environmental factors.

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The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

Option D

Explanation:

The expected configuration of configuration is

\(\\ \sf{:}\!\!\implies 1s^22s^22p^63s^23p^64s^23d^4\)

\(\sf {:}\!\!\!\rightarrowtail \)

As per the standard data, the heat evolved during one mole of calcium carbonate decomposes is 177.8 KJ. Thus 15 g or 0.15 moles of calcium carbonate when decomposed will produce 26.67 KJ of heat.

Reaction enthalpy of a substance is the heat evolved or absorbed during a reaction. Reaction enthalpy is negative for an exothermic reaction and positive for an endothermic reaction.

Molar mass of calcium carbonate = 100 g.

no.of moles in 15 g = 15 /100 = 0.15 moles.

One mole or 100 g of calcium carbonate decompose to evolve 177.8 KJ according to the scientific record.

Thus, heat evolved by the decomposition of 0.15 moles is 0.15 × 177.8 KJ = 26.67 KJ.

Hence, the heat evolved during the decomposition of 15 g of calcium carbonate is 26.67 KJ.

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Answer:

One of the organelles in eukaryotic cells that carry out digestion and waste removal.

Answer:

It's X

Explanation:

The decreasing order of lattice energy realesed is GaN>CaS>LICI>RbBr.

The lattice energy depends on the following two factors. They are product of charges of the compound and radius of the ions.

Higher the charge of ions, higher will be the lattice energy. Smaller the radius of ion, larger will be the lattice energy.

Consider the given compounds as follows: LiCl, CaS, GaN and RbBr

The charges of ions of given compounds are Li⁺, Cl⁻, Ca²⁺, S²⁻, Ga³⁺,N³, Rb⁺ and Br⁻. So, in the given compounds GaN has higher lattice energy. After GaN, CaS has higher lattice energy. Out of two compounds LiCl and RbBr, Li has less ionic well as ionic radius than Rb. Since in groups from top top to bottom atomic size increases as well as ionic radius.

Therefore, LiCl has higher lattice energy than RbBr.

Hence, the decreasing order of lattice energy realesed is GaN> CaS>LICI>RbBr

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BaO has ionic bonds because of electronegative difference.

Ionic bonds, also known as electrovalent bonds, are a type of linkage created in a chemical compound by the electrostatic attraction of ions with opposing charges. When the valence (outermost) electrons of one atom are permanently transferred to another atom, a bond of this kind is created. If an atom gains electrons, it becomes a negatively charged ion (cation), while if it loses them, it becomes a positively charged ion (cation) (anion). Following is a brief discussion of ionic bonds. To learn more, go to chemical bonding: the ionic bonding process.

Ionic or electrovalent compounds are produced by ionic bonding, and the compounds formed between nonmetals and alkali and alkaline-earth metals serve as the best examples of this type of compound. Actually, a polar covalent bond is the extreme form of an ionic bond.

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The amount of nitrogen oxide in the air sample is determined as 7.01 ppb.

The amount of Nitrogen oxide (NO2) in the air in parts per billion (ppb) is calculated as follows;

12 micrograms of NO2 = 12 μg = 12 x 10⁻⁶ g

PV = nRT

V = nRT/P

Where;

n = m/M

M = molar mass of NO2 = 46

n =  12 x 10⁻⁶/46

n = 2.73 x 10⁻⁷ mole

V = (2.73 x 10⁻⁷ x 0.082057 x 313)/(1)

V = 7.01 x 10⁻⁶ L

V =  7.01 x 10⁻⁹ m³

= (Volume of NO2)/(volume of air) x 10⁹

= (7.01 x 10⁻⁹)/(1) x  10⁹

= 7.01 ppb

Thus, the amount of nitrogen oxide in the air sample is determined as 7.01 ppb.

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The frequency of this radiation of a quantum of energy 4.14 *10-14 J is calculated to be 2.58 *10-15 Hz.

The Photoelectric Effect occurs when electrons are released from a metal surface when light strikes it. It was once thought that the greater the intensity of incoming light, the greater its energy, independent of hue. The light was viewed and treated as a wave, however, the wave phenomenon could not explain light's photoelectric actions.

The Quantum, according to Max Planck, is the smallest unit of energy that is released or absorbed in the form of electromagnetic radiation. The energy released or absorbed is proportional to the frequency of the radiation. It may be expressed mathematically as:

E= hc/λ

or

E= hf        ( because, f = c/λ)

where,

E= Energy of the particle

h= Planck's constant

c= speed of light

λ= wavelength of the particle

f = frequency of the radiation

Thus, E= hf

Given,

E = 4,14*10-14J

E= 1.71017356 * 10^20 eV

h= 6.626 *10-34 m2Kg/s

E=hf

f= E/h

f= (1.71017356 * 10^20 eV) / (6.626 *10-34 m2Kg/s)

f= C

Thus, the frequency of this radiation is 6.626 *10-34 m2Kg/s.

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To solve this, we must know each and every concept related to surface tension and viscosity as well. Therefore, mx will be less than my at liquid air interface.

The tendency to reduce surface area produced by the tension of a liquid's surface film as a result of the surface layer's particles being drawn to the liquid's bulk is called  surface tension.

Surface tension is caused by a net inward force that makes the surface operate like an elastic membrane on which objects may float freely. This net inward force is caused by a stronger cohesion between liquid molecules than adhesion between liquid and air molecules.

There is less surface tension in liquid x. As a result, it is unable to contain as many wax particles on its surface as liquid Y can. The liquids will combine uniformly. It is possible to combine two liquids with viscosities that are either lower or greater than the initial liquids.

Therefore, mx will be less than my at liquid air interface.

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Answer:

B. Ni

D. Sn

Explanation:

Electrode Potential is the potential difference set up between an element and a solution of its ion. It is a measure of the tendency of an element to form ions.

The electrode potentials vary from one metal ion or metal system to another and the value depends on:

concentration of ions in the solution

the temperature at which the measurement is made , and

the overall energy change.

When two half-cells are joined together through a salt bridge, the e.m.f (electromotive force) of the cell formed is the algebraic difference between the two electrode potentials.

However, the set up in which chemical energy is converted to electrical energy is known as an Electrochemical cell. It consists of two half cells ;

an oxidation half-cell reaction  

a reduction  half cell reaction.

From the information given:

the standard reduction potential for each metal under standard conditions in the electrochemical series is as follows :

\(E^0 _{Pb} = -0.126 \ V\)

\(E^0 _{Cr} = - 0.74 \ V\)

\(E^0 _{Ni} =- 0.23 \ V\)

\(E^0 _{Zn} =- 0.76 \ V\)

\(E^0 _{Sn} = -0.13 \ V\)

\(E^0 _{Cd} = - 0.40 \ V\)

We will realize that  Ni and Sn have reduction values in between Pb and Cd.

Thus , Ni can be oxidized by Pb2+  solution  but not with a Cd2+ solution

The metal(s) that can be oxidized with a \(Pb^{2+}\) solution

B. Ni

D. Sn

It is the potential contrast set up between a component and an answer of its particle. It is a proportion of the inclination of a component to shape particles. The cathode possibilities shift from one metal particle or metal framework to another and the worth relies upon:

Centralization of particles in the arrangement, the temperature at which the estimation is made , and the general energy change.

Whenever two half-cells are combined through a salt scaffold, the e.m.f (electromotive power) of the cell shaped is the mathematical contrast between the two terminal possibilities.

However, the set up in which chemical energy is converted to electrical energy is known as an Electrochemical cell. It consists of two half cells ;

an oxidation half-cell reaction  and a reduction  half cell reaction.

On seeing the values of electrode potential from electrochemical series we observe that  Ni and Sn have reduction values in between Pb and Cd.

Thus , Ni and Sn can be oxidized by  \(Pb^{2+}\) solution but not with a \(Cd^{2+}\)solution.

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Answer:

I think emi should put it in a metal container and put it in the direction of the sun cause this will help produce heat as the sun shines on the metal container

(i) A mole is the amount of a substance containing 6.022 × 10²³ particles.

(ii) Compounds are formed by the chemical bonding of different elements.

(iii) Molecular mass is the sum of atomic masses in a molecule.

(iv) There are two types of mix homogeneous and heterogeneous mixtures.

(v) Free radicals are highly reactive species with unpaired electrons.

(vi) Gram formula mass is the sum of atomic masses expressed in grams per mole.

(i) Mole: A mole is defined as the quantity of a substance that has an equal number of particles that are in 12 grams of carbon-12.

It is denoted by mol and is used in chemistry to measure quantities of atoms or molecules.

Example:1 mol of oxygen gas contains 6.022 × 10²³ oxygen molecules.

(ii) Compounds: Compounds are substances made up of two or more different elements that are chemically bonded together.

They can be broken down into simpler substances through chemical reactions.

Example:Water (H2O) is a compound made up of two hydrogen atoms and one oxygen atom that are chemically bonded together.

(iii) Molecular Mass: The molecular mass of a compound is the sum of the atomic masses of all the atoms in the molecule.

It is expressed in atomic mass units (amu) or grams per mole.

Example:The molecular mass of water (H2O) is 18.015 amu.

(iv) Types of Mixture: A mixture is a combination of two or more substances that are not chemically combined.

There are two types of mixtures - homogeneous and heterogeneous.

Example:A homogeneous mixture is a solution, such as saltwater, where the solute (salt) is evenly distributed in the solvent (water).

A heterogeneous mixture is a mixture that is not evenly distributed, such as oil and water.

(v) Free Radical: A free radical is an atom or molecule that has an unpaired electron in its outer shell and is highly reactive. They can be both harmful and helpful to the human body.

Example:A common free radical is the hydroxyl radical (OH·) that is formed by the body during metabolism.

(vi) Gram formula mass: The gram formula mass is the sum of the atomic masses of all the atoms in a compound.

It is expressed in grams per mole and is used to determine the mass of a certain number of molecules or atoms.

Example:The gram formula mass of water (H2O) is 18.015 g/mol.

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Answer/Explanation:

With oxygen, it is what you breathe in so obviously, it is going to move around into your body. But with carbon dioxide, it is what you breathe out. When you breathe in, your body takes in the oxygen and the releases the carbon dioxide. Carbon dioxide is what plants actually consume, while they release oxygen.

I hope this helps!

-No one

Answer: The energy of a photon that has a wavelength of 965 nm is \(2.06\times 10^{-16}J\)

Explanation:

The relation between energy and wavelength of light is given by Planck's equation, which is:

\(E=\frac{hc}{\lambda}\)

where,

E = energy of the photon =

h = Planck's constant  = \(6.626\times 10^{-34}Js\)

c = speed of light  = \(3\times 10^8m/s\)

\(\lambda\) = wavelength of light  = 965 nm = \(965\times 10^{-9}m\)     \((1nm=10^{-9}m)\)

Putting in the values we get:

\(E=\frac{6.626\times 10^{-34}\times 3\times 10^8m/s}{965\times 10^{-9}m}=2.06\times 10^{-16}J\)

Thus the energy of a photon that has a wavelength of 965 nm is \(2.06\times 10^{-16}J\)

\(K_{sp}\) of the compound is found to be  5.04 ×\(10^{-10}\).

Solubility :Solubility can be define as the amount of a substance that dissolves or mixes in a given amount of solvent at specific conditions.

Solubility equilibrium

Ksp = \([A^{+} ]^{a}\) \([B^{-} ]^{b}\)

Ksp = solubility product constant

A+ = cation in an aquious solution

B- = anion in an aqueous solution

a, b = relative concentrations of a and b

Given,

Solubility = s = 3.60 × \(10^{-2}\) g/L

molar mass = 288 g/ mol

∴ s= 3.60 × \(10^{-2}\) g/L ÷ 288 g/ mol = 1.25 ×\(10^{-4}\) mol/ L

Reaction:

MX3 ⇄ M + 3X

           s       3s

\(K_{sp}\) =[ \(M^{+3}\)] [ \(X^{-1}\)\(]^{3}\) = solubility product

∴ \(K_{sp}\) =\([s]^{} [3s]^{3}\)

∴ \(K_{sp}\) = 3 \(s^{4}\)

∴ \(K_{sp}\) = 3 × (3.60 × \(10^{-2}\) \()^{4}\)

∴ \(K_{sp}\) = 503.8848 ×\(10^{-8}\)  = 5.04 ×\(10^{-10}\)

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Answer:

what is this i dont know what kind of math this is

Answer:

the answer is distillate

Answer:

40,113 years

Explanation:

To find the age of the sample, you need to use the half-life formula:

\(N(t)=N_0(\frac{1}{2})^{t/h\)

In this formula:

------> N(t) = current mass (g)

------> N₀ = initial mass (g)

------> t = time passed (yrs)

------> h = half-life (yrs)

You can plug the given values into the equation and rearrange the formula to find "t".

N(t) = 0.781 g                       t = ? yrs

N₀ = 100 g                           h = 5730 yrs

\(N(t)=N_0(\frac{1}{2})^{t/h\)                                           <----- Half-life formula

\(0.781=100(\frac{1}{2})^{t/5730}\)                                     <----- Insert values

\(0.00781=(\frac{1}{2})^{t/5730}\)                                       <----- Divide both sides by 100

\(log_{1/2}(0.00781)=log_{1/2}((\frac{1}{2})^ {t/5730})\)               <----- Take \(log_{1/2}\) of both sides

\(7.00 = \frac{t}{5730}\)                                                   <----- Solve \(log_{1/2}\)

\(40,113 = t\)                                                   <----- Multiply both sides by 5730

The given sample is 40,113 years .

Half-life, in radioactivity, is the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay.

Half-life formula,

\(\rm N(t)\;=N_0(\dfrac{1}{2})^\frac{t}{t1/2}\)   .......(1)

where,

N(t)=current mass

N₀=initial mass

t=time period

h=half -life

Given,

N(t)=0.781g, t=? yrs, N₀=100g, h=5730 years

\(\rm N(t)\;=N_0(\dfrac{1}{2})^\frac{t}{t1/2}\)

put the values, in ......(1)

0.781=100(1/2) \(t/5730\\\)

log₁/₂(0.00781)=log₁/₂ ( 1/2)\(t/5730\)

7=t/5730

40,113=t

Hence, the given sample is 40,113 years .

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37.06 percent is the percent of water in the compound

What is Washing Soda ?

Washing soda, also known as sodium carbonate, is a white crystalline powder that is commonly used as a cleaning and laundry aid. It is a strong alkaline substance and has a high pH, making it an effective cleaning agent for removing dirt, grease, and stains. Washing soda is often used as a household cleaner for tasks such as removing grease from ovens and pots and pans, cleaning tile and grout, and unclogging drains. In laundry, it can be used to remove stubborn stains, brighten clothes, and soften hard water. Washing soda can also be used in industrial applications, such as in the manufacture of glass, paper, and soap. It is a water-soluble compound and is generally considered safe for use, although it should be handled with care and not ingested, as it is a strong alkali and can be harmful if ingested in large quantities.

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Answer:

true fats; triglycerides

Explanation:

The chemical formulas for the ions and compounds you listed:

Copper (II) ion: Cu²⁺

Bromide ion: Br⁻

Magnesium ion: Mg²⁺

Phosphide ion: P³⁻

Copper (I) Bromide: CuBr

Sulfur Dichloride: SCl₂

Barium Fluoride: BaF₂

Magnesium Phosphate: Mg₃(PO₄)₂

Lithium Permanganate: LiMnO₄

Strontium Sulfite: SrSO₃

Nitrogen Monoxide: NO

Diselenium Tetraoxide: Se₂O₄

Aluminum Sulfide: Al₂S₃

Tin (IV) Iodide: SnI₄

Beryllium Oxide: BeO

Potassium Hydroxide: KOH

Copper (II) ion: Cu²⁺

Copper (II) ion has a charge of 2+ and is represented by Cu²⁺. This means that copper has lost two electrons, resulting in a 2+ charge.

Bromide ion: Br⁻

The bromide ion has a charge of 1- and is represented by Br⁻. This means that bromine has gained one electron, resulting in a 1- charge.

Magnesium ion: Mg²⁺

The magnesium ion has a charge of 2+ and is represented by Mg²⁺. This means that magnesium has lost two electrons, resulting in a 2+ charge.

Phosphide ion: P³⁻

The phosphide ion has a charge of 3- and is represented by P³⁻. This means that phosphorus has gained three electrons, resulting in a 3- charge.

Copper (I) Bromide: CuBr

Copper (I) bromide is a compound formed by combining copper (I) ion (Cu⁺) and bromide ion (Br⁻). The charges of the ions balance each other, resulting in a neutral compound.

Sulfur Dichloride: SCl₂

Sulfur dichloride is a compound consisting of one sulfur atom (S) and two chlorine atoms (Cl). The subscript "2" indicates the presence of two chlorine atoms.

Barium Fluoride: BaF₂

Barium fluoride is a compound composed of one barium ion (Ba²⁺) and two fluoride ions (F⁻). The charges of the ions balance each other, resulting in a neutral compound.

Magnesium Phosphate: Mg₃(PO₄)₂

Magnesium phosphate is a compound consisting of one magnesium ion (Mg²⁺) and two phosphate ions (PO₄³⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "3" indicates the presence of three magnesium ions, and the subscript "2" indicates the presence of two phosphate ions.

Lithium Permanganate: LiMnO₄

Lithium permanganate is a compound composed of one lithium ion (Li⁺) and one permanganate ion (MnO₄⁻). The charges of the ions balance each other, resulting in a neutral compound.

Strontium Sulfite: SrSO₃

Strontium sulfite is a compound consisting of one strontium ion (Sr²⁺) and one sulfite ion (SO₃²⁻). The charges of the ions balance each other, resulting in a neutral compound.

Nitrogen Monoxide: NO

Nitrogen monoxide is a compound composed of one nitrogen atom (N) and one oxygen atom (O). Since the compound does not contain ions, it is represented by its elemental symbols.

Diselenium Tetraoxide: Se₂O₄

Diselenium tetraoxide is a compound consisting of two selenium atoms (Se) and four oxygen atoms (O). The prefix "di-" indicates the presence of two selenium atoms.

Aluminum Sulfide: Al₂S₃

Aluminum sulfide is a compound composed of two aluminum ions (Al³⁺) and three sulfide ions (S²⁻). The charges of the ions balance each other, resulting in a neutral compound. The subscript "

2" indicates the presence of two aluminum ions, and the subscript "3" indicates the presence of three sulfide ions.

Tin (IV) Iodide: SnI₄

Tin (IV) iodide is a compound formed by combining tin (IV) ion (Sn⁴⁺) and iodide ion (I⁻). The charges of the ions balance each other, resulting in a neutral compound.

Beryllium Oxide: BeO

Beryllium oxide is a compound composed of one beryllium ion (Be²⁺) and one oxygen ion (O²⁻). The charges of the ions balance each other, resulting in a neutral compound.

Potassium Hydroxide: KOH

Potassium hydroxide is a compound consisting of one potassium ion (K⁺) and one hydroxide ion (OH⁻). The charges of the ions balance each other, resulting in a neutral compound.

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The molarity of the bleach solution is 0.0635 M.

First we need to know the number of moles of solute (in this case, NaOCI) and the volume of the solution in liters.

First, we need to convert the mass of NaOCI to moles using its molar mass:

molar mass of NaOCI = 23.0 g/mol (for Na) + 16.0 g/mol (for O) + 35.5 g/mol (for Cl) + 1.0 g/mol (for I) = 74.5 g/mol

moles of NaOCI = mass / molar mass = 9.50 g / 74.5 g/mol = 0.127 moles

Next, we need to convert the volume of the solution to liters:

volume = 2,000 ml = 2,000 / 1,000 L = 2.0 L

Now we can calculate the molarity of the solution:

Molarity (M) = moles of solute / volume of solution in liters

M = 0.127 moles / 2.0 L = 0.0635 M

Therefore, the molarity of the bleach solution is 0.0635 M.

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Answer:

burning fossil fuels, like coal.

Explanation:

Generated greenhouse gases which trap heat in the Earth.

Answer:

False

Explanation:

Hello,

In this case, it is possible to substantiate that the statement is false, since the entropy of sucrose is greater than the entropy of ribose due to the fact that molar mass of the sucrose (342 g/mol) is greater than the molar mass of ribose (150 g/mol) and the general rule states that the greater the molar mass the greater the entropy.

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