assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1. if p ( z > c ) = 0.2445 p(z>c)=0.2445 , find c. c = c=

Using the quadratic equation of motion, the statements that best describe the squared term −16t² are

A quadratic equation is an equation in which the highest power of the unknown is 2.

Since the height in feet of a thrown football is modeled by the equation f(t) = 6 + 30t − 16t², where time t is measured in seconds. To select the statements that best describe the squared term −16t², we proceed as follows.

Comparing the equation f(t) = 6 + 30t − 16t² with s = h + ut - 1/2at² where

We see that

So, the statements that best describe the squared term −16t² are

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Answer: -2

Step-by-step explanation:

Answer:

-2

Step-by-step explanation:

the - (-6) becomes a + 6

-8 + 6 - 0 = -2

The increase in price (8.20%) is less than the interest she would have paid (12 payments of $7125), it seems that postponing her purchase and saving money was a good trade-off for Dorothy.

The APR (Annual Percentage Rate) for Dave's loan can be calculated

using the formula:

APR = ((Total interest + Service charge) / Principal) * 100

In this case, the total interest is $44.90 and the service charge is $6.40.

The principal is $600. Plugging these values into the formula:

APR = (($44.90 + $6.40) / $600) * 100

Simplifying the equation:

APR = ($51.30 / $600) * 100

APR = 8.55%

For Dorothy, if she bought the dishwasher on credit, the total cost would

be $855.00 after making 12 monthly payments of $7125.

However, if she saved $70.00 a month for one year, she would have

$898.80 in deposits plus interest.

When she goes back to the store, the dishwasher now costs $908.88,

which is an increase of 8.20%.

Since the increase in price (8.20%) is less than the interest she would

have paid (12 payments of $7125), it seems that postponing her purchase

and saving money was a good trade-off for Dorothy.

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Answer:

Step-by-step explanation:

4 days 9 hours 40 minutes

Answer:

D) HL

Step-by-step explanation:

ΔGHJ  ≅ ΔGKJ by HL Congruence rule.

According to the hypotenuse-leg (HL) theorem, a right triangle is congruent if each of its hypotenuse and legs are congruent with their corresponding hypotenuse and legs in another right triangle.

Given:

In ΔGHJ  and  ΔGKJ

<H = <K= 90 degree

GJ= GJ {common}

GH= GK= 8 units.

Thus, ΔGHJ  ≅ ΔGKJ by HL Congruence rule.

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Answer: Its B and C

Which equations shows the variable terms isolated on one side and the constant terms isolated on the other side for the equation 3 x minus 5 = negative 2 x + 10? Select two options.

x = 5

–15 = –5x

5x = 15

–15 = 5x

x = -5

a

so the first one is 817(the amount at the beginning) +19x

817+19x

the second pool is 38x, cause there's no water at the start.

38x

b

it would be 817+19x=38x

36 bc 20 percent of 30 is 6 so just add 6 to thirty and there you go

Answer:

3

Step-by-step explanation:

as far as I can read that, well, the company has a revenue income of 8250000 and their expenditure on purchases is 49% of that amount, how much is that?

\(\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{49\% of 8250000}}{\left( \cfrac{49}{100} \right)8250000}\implies 4042500\)

so on saving 2.05% of purchasing expenses or namely 2.05% of 4042500

\(\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{2.05\% of 4042500}}{\left( \cfrac{2.05}{100} \right)4042500}\implies 82871.25\)

so sales must be increased by that much in order to match the 2.05% of 4042500.

False. Line charts are best suited for representing data that follows a sequential order, such as time series data. Nonsequential data is better represented by other types of charts, like scatter plots or bar graphs.

Line charts are graphical representations of data points connected by lines. They are commonly used to display trends over time or sequential data. For example, they are often used to show the change in stock prices over a period of time or the temperature variations throughout the day. This sequential order is the key feature of line charts.

However, for data that does not follow a sequential order, line charts may not be the best choice. Nonsequential data, such as categorical or unrelated data points, are better represented by other types of charts. Scatter plots, for instance, are useful for showing the relationship between two variables that are not necessarily ordered. Bar graphs can also be used to compare nonsequential data points in different categories.

In summary, line charts are not best suited for representing data that follows a nonsequential order. They are most effective when used to display data that has a clear sequential relationship, allowing for easy interpretation of trends and patterns.

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Simplifying this expression, we get:  f'(t) = 2cos(t)/t * ln(t) - (ln(t))^2sin(t)

To differentiate the function f(t) = (ln(t))^2 cos(t), we will need to use the product rule and the chain rule.

Product rule:

d/dt [f(t)g(t)] = f(t)g'(t) + f'(t)g(t)

Chain rule:

d/dt [f(g(t))] = f'(g(t))g'(t)

Using these rules, we can differentiate f(t) = (ln(t))^2 cos(t) as follows:

f'(t) = 2ln(t)cos(t) d/dt[ln(t)] + (ln(t))^2 d/dt[cos(t)]

To find d/dt[ln(t)] and d/dt[cos(t)], we can use the chain rule and the derivative rules for ln(x) and cos(x), respectively:

d/dt[ln(t)] = 1/t

d/dt[cos(t)] = -sin(t)

Substituting these into the expression for f'(t), we get:

f'(t) = 2ln(t)cos(t) (1/t) - (ln(t))^2sin(t)

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Answer: there is no b and c so you cant find b and c

Step-by-step explanation:

the coordinates of point B are (15, 15).Let's use the midpoint formula to find the coordinates of point b.

Midpoint formula:

The midpoint M of a line segment with endpoints A(x1, y1) and B(x2, y2) is given by:

M((x1 + x2)/2, (y1 + y2)/2)

We are given that the midpoint of the line segment AB is M(9, 8) and A has coordinates (3, 1). Let's substitute these values into the midpoint formula and solve for the coordinates of B:

9 = (3 + x2)/2

Multiplying both sides by 2, we get:

18 = 3 + x2

Subtracting 3 from both sides, we get:

x2 = 15

8 = (1 + y2)/2

Multiplying both sides by 2, we get:

16 = 1 + y2

Subtracting 1 from both sides, we get:

y2 = 15

Therefore, the coordinates of point B are (15, 15).

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Answer:

0.84 pounds

Step-by-step explanation:

Answer:

What is that?

Step-by-step explanation:

Answer:

6.4

Step-by-step explanation:

Answer:

Equation

Step-by-step explanation:

Equation Rate of change: 2/1=2

Graph Rate of Change: -4/1=-4

Answer: Equation has a greater rate of change

Step-by-step explanation:

Equation's rate of change is 2 and graph's rate of change is -4

Answer:

Did you forget to add the rhombus picture?

Step-by-step explanation:

The average rate of change of f(x) for the given values of h are:
When h=0.2, the average rate of change of f(x) is 112.84.
When h=0.1, the average rate of change of f(x) is 206.41.
When h=0.01, the average rate of change of f(x) is 1850.5601.
When h=−0.01, the average rate of change of f(x) is -1807.5399.
When h=−0.1, the average rate of change of f(x) is -171.39.
When h=−0.2, the average rate of change of f(x) is -80.76.

To calculate the average rate of change of f(x) for the given values of h, we need to substitute the values of h into the difference quotient and simplify.

When h=0.2:
f(3+0.2)−f(3)/0.2 = [(3.2^3−15(3.2)) - (3^3−15(3))]/0.2 = (32.768 - 10.2) - (27 - 45)/0.2 = 22.568/0.2 = 112.84

When h=0.1:
f(3+0.1)−f(3)/0.1 = [(3.1^3−15(3.1)) - (3^3−15(3))]/0.1 = (29.791 - 9.15) - (27 - 45)/0.1 = 20.641/0.1 = 206.41

When h=0.01:
f(3+0.01)−f(3)/0.01 = [(3.01^3−15(3.01)) - (3^3−15(3))]/0.01 = (27.270601 - 8.765) - (27 - 45)/0.01 = 18.505601/0.01 = 1850.5601

When h=−0.01:
f(3+(-0.01))−f(3)/(-0.01) = [(2.99^3−15(2.99)) - (3^3−15(3))]/(-0.01) = (26.730399 - 8.655) - (27 - 45)/(-0.01) = 18.075399/(-0.01) = -1807.5399

When h=−0.1:
f(3+(-0.1))−f(3)/(-0.1) = [(2.9^3−15(2.9)) - (3^3−15(3))]/(-0.1) = (24.389 - 8.25) - (27 - 45)/(-0.1) = 17.139/(-0.1) = -171.39

When h=−0.2:
f(3+(-0.2))−f(3)/(-0.2) = [(2.8^3−15(2.8)) - (3^3−15(3))]/(-0.2) = (21.952 - 7.8) - (27 - 45)/(-0.2) = 16.152/(-0.2) = -80.76

Therefore, the average rate of change of f(x) for the given values of h are:
When h=0.2, value is 112.84.
When h=0.1, value is 206.41.
When h=0.01, value is 1850.5601.
When h=−0.01, value is -1807.5399.
When h=−0.1, value is -171.39.
When h=−0.2, value is -80.76.

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Answer:

g(x-5)+8

Step-by-step explanation:

Answer:

C.)

Step-by-step explanation:

1.) First find the slope of the perpendicular line. The slope of the perpendicular line is the number that when multiplied by the slope of the initial line, you get -1. The slope of the line is 3/8, and -8/3 * 3/8 is -1, therefore -8/3 is the slope of the new line.
2.) Now, since we have a slope if you look at the options, there is only one option with the slope -8/3, which is option C.).

Answer:

\( \large{ \bold{f(-2)=9}} \)

Step-by-step explanation:

In order to find f(-2) we substitute the value of x that's -2 into f(x). That is wherever there is x in f (x) you replace it by -2 and solve.

We have

\( \large{f(-2) = -3 - 6(-2)\\= -3--12 = -3+12 = 9} \)

We have the final answer as

\( \large{f(-2)=9} \)

Hope this helps you

36 pounds is equal to 16.344 kilograms.

Given that we need to convert 36 pounds to kilograms.

We have 1 pound = 0.454 kilogram,

To convert pounds to kilograms, we use the conversion factor of 1 pound = 0.454 kilogram.

Given that we have 36 pounds, we can multiply this value by the conversion factor to find the equivalent weight in kilograms:

36 pounds x 0.454 kilogram/pound = 16.344 kilograms

Therefore, 36 pounds is equal to 16.344 kilograms.

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In the statistics the type 1 error means rejection of the null hypothesis in the case of when it is actually true.

In the field of statistics,

Type 1 error represents that there is a rejection of the Null hypothesis in the case when it is actually true.

This implies that the concluding results are actually statistically significant.

But in reality the result is due to unrelated factors or purely by coincidence or chance.

The risk representing the taking of this error as significant level alpha with some value.

Therefore, the type one error in statistics represents that rejection of Null hypothesis.

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y = mx +c

Substitute the values,

-4 = -1(2) + c

c = -2

Thus, the equation is y= -x -2

Answer:

The origin is included in the shaded region and the shaded region is below the line.

Explanation:

First, let's graph the line that separates the region: y = 1/3 x + 4

So, to graph the line, we need to find two points in the line as follows:

If x = 0, then y is equal to:

y = 1/3 (0) + 4

y = 4

If x = 3, then y is equal to:

y = 1/3 (3) + 4

y = 1 + 4

y = 5

So, using the points (0, 4) and (3, 5), we get:

Now, we can determine whether the origin is included or not replacing x and y by the coordinates of the origin (0, 0) and determine if this point satisfies the inequality. So:

y < 1/3x + 4​

0 < 1/3(0) + 4

0 < 0 + 4

0 < 4

Since 0 is less than 4, the origin is included in the shaded region, so the shaded region is below the line.

the size of the union of the three sets is: |A ∪ B ∪ C| = |A| + |B| + |C| - |A ∩ B| - |A ∩ C| - |B ∩ C| + |A ∩ B ∩ C| = 3  × 24 million - 3 × 1.4 million + 1.2 million ≈ 69 million

A combination is a way of selecting a subset of objects from a larger set without regard to their order. The formula for the number of combinations of n objects taken r at a time is:
C(n, r) = n! / (r! ×  (n - r)!)
where n! means the factorial of n, which is the product of all positive integers up to n. For example, 5! = 5 ×  4 ×  3 ×  2 ×  1 = 120.
To apply this formula to our problem, we first need to count the total number of coins in the pile. Since there are at least 16 of each type, the minimum total is:
16 + 16 + 16 + 16 = 64
But there could be more coins of each type, so the total could be larger than 64. However, we don't need to know the exact number, only that it is large enough to allow us to choose 16 coins from it.
Using the formula for combinations, we can calculate the number of different collections of 16 coins that can be chosen from the pile:
C(64, 16) = 64! / (16! × (64 - 16)!) ≈ 1.1 billion
That's a very large number! It means there are over a billion ways to choose 16 coins from a pile that contains at least 16 of each type.
To answer the second part of the question, we need to count the number of collections that contain at least 3 coins of each type. One way to do this is to use the inclusion-exclusion principle, which says that the number of elements in the union of two or more sets is equal to the sum of their individual sizes minus the sizes of their intersections, plus the sizes of the intersections of all possible pairs, minus the size of the intersection of all three sets, and so on.
In this case, we can consider three sets:
- A: collections with at least 3 pennies
- B: collections with at least 3 nickels
- C: collections with at least 3 dimes
- D: collections with at least 3 quarters
The size of each set can be calculated using combinations:
|A| = C(48, 13) ≈ 24 million
|B| = C(48, 13) ≈ 24 million
|C| = C(48, 13) ≈ 24 million
|D| = C(48, 13) ≈ 24 million
Note that we have to choose 3 coins of each type first, leaving 4 coins to be chosen from the remaining 48 coins.
The size of the intersection of any two sets can be calculated similarly:
|A ∩ B| = C(43, 10) ≈ 1.4 million
|A ∩ C| = C(43, 10) ≈ 1.4 million
|A ∩ D| = C(43, 10) ≈ 1.4 million
|B ∩ C| = C(43, 10) ≈ 1.4 million
|B ∩ D| = C(43, 10) ≈ 1.4 million
|C ∩ D| = C(43, 10) ≈ 1.4 million
Note that we have to choose 3 coins of each type first, leaving 1 coin to be chosen from the remaining 43 coins.
The size of the intersection of all three sets can also be calculated:
|A ∩ B ∩ C| = C(38, 7) ≈ 1.2 million
Note that we have to choose 3 coins of each type first, leaving 1 coin to be chosen from the remaining 38 coins.

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Answer:

-112

Step-by-step explanation: