at one point in the above scehem both iron and nickel co exist in solution and can be seperated using 15 ammonia

Answer:

The correct answers are

Particles are dissolved

and light beam passes through invisibility

Explanation:

Odyssey

37.5 moles of iron will produce 2990.31 grams of Fe₂O₃.

To determine the number of grams of Fe₂O₃ produced from 37.5 moles of iron (Fe), we need to use the balanced chemical equation for the reaction in which iron reacts to form Fe₂O₃.

The balanced equation for the reaction is:

4Fe + 3O₂ -> 2Fe₂O₃

From the balanced equation, we can see that 4 moles of iron react to produce 2 moles of Fe₂O₃. This means that the molar ratio between Fe and Fe₂O₃ is 4:2 or 2:1.

Now, we can set up a simple proportion to calculate the number of moles of Fe₂O₃ produced:

(37.5 moles Fe) * (2 moles Fe₂O₃ / 4 moles Fe) = 18.75 moles Fe2O3

So, 37.5 moles of iron will produce 18.75 moles of Fe₂O₃.

To convert moles to grams, we need to use the molar mass of Fe₂O₃. The molar mass of Fe₂O₃ can be calculated by adding the atomic masses of iron (Fe) and oxygen (O) in the compound:

(2 x atomic mass of Fe) + (3 x atomic mass of O) = (2 x 55.845 g/mol) + (3 x 16.00 g/mol) = 159.69 g/mol

Now, we can calculate the mass of Fe₂O₃ produced:

Mass = moles x molar mass

Mass = 18.75 moles x 159.69 g/mol = 2990.31 grams

Therefore, 37.5 moles of iron will produce 2990.31 grams of Fe₂O₃.

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5.1g of iron is needed to prepare 11.86 g of the iron chloride product if, under the conditions of the reaction, the electron configuration of the iron cation in the product is 1s22s22p63s23p63d6

Define electronic configuration.

The distribution of electrons in an element's atomic orbitals is described by the element's electron configuration. Atomic electron configurations adhere to a standard nomenclature in which all atomic subshells that contain electrons are arranged in a sequence with the number of electrons they each hold expressed in superscript.

Only ferrous chloride (FeCl2) is produced when metallic iron is treated with hydrochloric acid. The other product released is hydrogen gas. Ferric chloride (FeCl3) is created when iron is heated in the presence of chlorine gas.

Fe + Cl2 → FeCl2

1 mole iron reacts to give 1 mole FeCl2

No. of moles of Fe and FeCl2 are 1.

55g of Fe produces 126g of FeCl2

So 11.86g of FeCl2 is formed from 55*11.86/126 i.e. 5.1g

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Answer:

a is the answer I know and if I'm right mark me brainlest

Answer:

Carbon and Oxygen, Argon and Helium.

Explanation:

noble gases have full outer shells of electrons, and so cannot share other atoms' electrons to form bonds. sodium and chlorine form an ionic bond.

the element is in group 2

Utilizing several well pads can drastically minimize the quantity of well pads, access roads, pipeline routes, and production facilities, decreasing habitat disruption, negative effects on the general population, and the environmental footprint overall.

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Butane < acetone < 1-propanol  is a list of the compounds in order of increasing boiling points.

The intermolecular interactions between molecules in a compound play a major role in boiling point. Higher boiling temperatures are a result of greater intermolecular interactions, bigger masses, and less branching.

The highest boiling point is for HF. As we go from HF to HI, the van der Waals forces of attraction between all hydrogen halides get stronger.

Boiling point rises as the difference in electronegativity grows. Additionally, the bp grows as the molecule's size does. So the sequence is CO2, CS2, CCl4, and then H2O.

Van der Waals attraction and dipole-dipole attraction draw acetone molecules together.

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The future value of the cash flows in Year 4, given a discount rate of 9 percent, is $3,109.37.

To calculate the future value, we can use the formula for the future value of a series of cash flows. We multiply each cash flow by its corresponding discount factor, which is determined by raising (1 + discount rate) to the power of the number of periods.

In this case, the future value of the cash flows in Year 4 can be calculated as follows:

Future Value = ($1,040 / (1 + 0.09)^1) + ($1,270 / (1 + 0.09)^2) + ($1,490 / (1 + 0.09)^3) + ($2,230 / (1 + 0.09)^4) = $3,109.37.

This calculation takes into account the time value of money, reflecting the fact that receiving cash flows in the future is less valuable than receiving them in the present. The discount rate of 9 percent represents the required return or opportunity cost of investing in this project. By calculating the future value, we can assess the total worth of the cash flows at the end of Year 4.

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When 1.34 g Zn(s) reacts with 60.0 mL of 0.750 M HCl(aq) , 3.14 kJ of heat are produced.the answer is not one of the choices given.

To solve for the enthalpy change per two moles of zinc reacting, we need to first calculate the moles of zinc reacted and the amount of heat produced.
The moles of zinc reacted can be found using its molar mass:
1.34 g Zn ÷ 65.38 g/mol Zn = 0.0205 mol Zn
The amount of heat produced can be found using q = mCΔT, where q is the heat produced, m is the mass of the solution (which we assume to be 60.0 g since 1 mL of water is approximately 1 g), C is the specific heat capacity of the solution (which we assume to be 4.18 J/g°C, the value for water), and ΔT is the change in temperature (which we assume to be negligible since the reaction is done at constant pressure).
q = (60.0 g)(4.18 J/g°C)(0°C) = 0 J
However, we are given that 3.14 kJ of heat are produced, which is equivalent to 3140 J. Therefore, we need to adjust the moles of zinc reacted to account for this amount of heat:
3140 J ÷ (-2 mol HCl)(-46.1 J/mol°C) = 0.0345 mol Zn
Now we can calculate the enthalpy change per two moles of zinc reacted:
ΔH = q ÷ n = (3140 J) ÷ (0.0345 mol Zn ÷ 2) = -181609 J/mol
Converting to kJ/mol and rounding to the nearest whole number, we get:
ΔH = -182 kJ/mol
Therefore, the answer is not one of the choices given.

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Mole measure the number of elementary entities of a given substance that are present in a given sample. Therefore,  the volume of oxygen needed to completely react with 171.9 g of S8 at STP is 180.09L.

The SI unit of amount of substance in chemistry is mole. The mole is used to measure the quantity or amount of substance. We know one mole of any element contains 6.022×10²³ atoms which is also called Avogadro number.

S\(_8\)(s) +12O\(_2\)(g) →8SO\(_3\)(l)

171.9 g of S8

mole of  S\(_8\)=  171.9 g/ 256.52g/mol

                 =0.67mol

The mole of oxygen = 12×0.67

                                = 8.04mol

volume of oxygen= 22.4× 8.04

                            =180.09L

Therefore,  the volume of oxygen needed to completely react with 171.9 g of S8 at STP is 180.09L.

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Answer:

6g/mL

Explanation:

Given parameters;

Mass of the unknown substance  = 18g

Volume of water before the mass is introduced  = 5mL

Volume of water after the mass is introduced  = 8mL

Unknown:

Density of the mass = ?

Solution:

Density is the mass per unit volume of a substance.

             Density  = \(\frac{mass}{volume}\)

Mass is the amount of matter in a substance

Volume is the space occupied by a body

Volume of the body  = 8mL - 5mL = 3mL

Insert the parameters and solve;

             Density  = \(\frac{18g}{3mL}\)   = 6g/mL

Answer:

I think its 6g or 16g but im pretty sure its 6g

Explanation:

In general, the arming time of a munition refers to the time required for the munition's fuse to become active and enable the explosive charge to detonate. The arming time can vary depending on several factors, including the type of fuse used, the specific munition model.

Tail fuzes like the M905 tail fuze are designed to be used with certain types of munitions, such as bombs, and are typically armed by the motion or rotation of the munition during its descent or trajectory. The arming time of a tail fuze can depend on several factors, including the munition's velocity, the altitude of the munition, and the specific settings on the fuze.

It's important to note that discussing specific arming times of military munitions is not recommended, as it can be considered sensitive information that should only be handled by authorized personnel with the proper clearance and training to ensure public safety and security.

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Alkyl bromides, alkyl iodides, and alkyl chlorides are all typical reactants in laboratory nucleophilic substitution processes. The best leaving group among the four common halides (F, Cl, Br, and I) is iodide, which is the least basic of them all.

Do Sn1 or Sn2 require an excellent leaving group?

Sn1 and Sn2: Since both sn1 and sn2 reactions need strong leaving groups, the type of leaving group has no effect on the reaction. A extremely weak leaving group, however, might stop either reaction from happening at all.

What is nucleophilic substitution with leaving group ability?

When an electrophile that is positively charged attacks a nucleophile that is rich in electrons, the leaving group from the nucleophile is replaced.

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The moment in a titration where exactly enough titrant has been added to completely react with the analyte is called  "equivalence point ".

The titration's equivalence point occurs when precisely the right amount of titrant has just been added to cause the analyte to totally react.

The point during which chemically equivalent amounts of reactants have been combined is known as the equivalence point, also known as the stoichiometric point, in a chemical process. The equivalence point for an acid-base reaction is the point at which, in accordance with the chemical reaction, equal amounts of acid and base would neutralize one another.

Therefore, the moment in a titration where exactly enough titrant has been added to completely react with the analyte is called  "equivalence point ".

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Answer:

An aqueous solution is water that contains one or more dissolved substances. The dissolved substances in an aqueous solution may be solids, gases, or other liquids.

Answer:

b

Explanation:

The limited change in entropy in the reaction Cl₂(g) + Br₂(g) → 2 BrCl(g) at 25 °C can be attributed to the similar molecular complexity of the reactants and products and the lack of significant changes in molecular motion.

The change in entropy for a chemical reaction is influenced by various factors, including the number of gaseous molecules involved, the complexity of the reactants and products, and the temperature. In the given reaction, Cl₂(g) and Br₂(g) combine to form 2 BrCl(g) molecules.

The limited change in entropy can be attributed to the nature of the reactants and products. Both Cl₂(g) and Br₂(g) are diatomic molecules, meaning they consist of two atoms bonded together. When they react to form BrCl(g), which is also a diatomic molecule, the overall molecular complexity remains relatively constant. As a result, there is no significant increase in the number of possible microstates (ways the molecules can be arranged) during the reaction, leading to a small change in entropy.

Furthermore, since all the reactants and products are in the gaseous state, the contribution of entropy due to changes in molecular motion is already accounted for. At a fixed temperature of 25 °C, the molecular motion is not significantly altered, and hence, the entropy change is not substantial.

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Answer:

Yes it is a colligative Property

Explanation:

There is freezing point depression, boiling point elevation, Osmotic Pressure, Vapor Pressure Lowering

Answer:

Answer

Change in temperature

It is an example of an endothermic reaction. It is absorbing heat.

The decarboxylation of the pyruvate-Tpp intermediate and the decarboxylation of a molecule have some similarities in their structures. Let's break down these processes step by step to better understand the similarities.

Decarboxylation of the pyruvate-Tpp intermediate Pyruvate, a three-carbon molecule, is initially converted to an intermediate called pyruvate-Tpp (Thiamine Pyrophosphate). The pyruvate-Tpp intermediate undergoes decarboxylation, where a carboxyl group (-COOH) is removed from the molecule.
 
Both the decarboxylation of the pyruvate-Tpp intermediate and the decarboxylation of other molecules share the common feature of removing a carboxyl group. However, the specific molecules involved and the enzymes or catalysts facilitating the reaction may differ.

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Answer:

C

Explanation:

Primary succession occurs when pioneer species move into an area that has no plants. This happens because of Mosses and lichens that can grow on rocky surfaces and the correct option is option B.

Primary succession refers to the establishment of a community in an uninhabited area such as rocks.

It is a type of ecological succession (the evolution of a biological community’s ecological structure) in which plants and animals first colonize a barren, lifeless habitat.

Species that arrive first in the newly created environment are called pioneer species, and through their interactions they build a simple initial biological community.

Therefore, Primary succession occurs when pioneer species move into an area that has no plants. This happens because of Mosses and lichens that can grow on rocky surfaces and the correct option is option B.

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Explanation:

REFER TO THE ATTACHMENT ABOVE.....

Due to the hydrogen bonding between the molecules of ethanol and water, it is True.

Water and ethanol form weak hydrogen bonds with aromatic hydrogen atoms and strong hydrogen bonds with the hydroxyl, carbonyl, and ether groups in chrysin/galangin. Although less frequently than in water, ethanol molecules can form hydrogen bonds with one another. The fact that there is only one hydrogen with a significant Positive charge in each ethanol molecule limits the hydrogen bonding. Between adjoining hydrogen and oxygen atoms of nearby water molecules, hydrogen bonds are formed. A bond called a hydrogen bond is produced by the attraction between individual water molecules.

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The balanced chemical reaction will be;Ba3N2 + 6H2O → 3Ba(OH)2 + 2NH3. The values of w, x, y, and z are w = 2z and w = y = 3x.

The given chemical reaction is unbalanced. So, we have to balance it. Let the coefficient of Ba3N2 is w, the coefficient of H2O is x, the coefficient of Ba(OH)2 is y, and the coefficient of NH3 is z. So, the balanced chemical reaction is: wBa3N2 + x6H2O → y3Ba(OH)2 + z2NH3

Coefficient of Ba: 3w = 3y  => w = y

Coefficient of N: 2z = w => w = 2z

Coefficient of H: 6x = 2z  => z = 3x

Coefficient of O: 2y = 6x  => y = 3x

So, the final coefficients are: w = y = 3x and w = 2z

The balanced chemical reaction is; Ba3N2 + 6H2O → 3Ba(OH)2 + 2NH3. Hence, the values of w, x, y, and z are w = 2z and w = y = 3x.

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Answer:

199.26 or with sig figs 2.0 x 10^2

Explanation: you take the # of molecules and divide it by avagadros number which is 6.022141 x 10^23

The high-energy compound GTP produced by the reaction catalyzed by succinyl-CoA synthetase can transfer its energy to the cellular ATP pool via substrate-level phosphorylation.

In the substrate-level phosphorylation process, the phosphate group from GTP is transferred directly to ADP, forming ATP and GDP as byproducts. This reaction is catalyzed by the enzyme nucleoside diphosphate kinase, which is found in the cytoplasm and mitochondria of cells.

GTP (guanosine triphosphate) and ATP (adenosine triphosphate) are nucleotide triphosphates that play vital roles in cellular energy metabolism but differ. ATP is typically present in higher concentrations in the cell than GTP. GTP is often used in protein synthesis and signal transduction, while ATP is the primary molecule for cellular energy transfer and storage.

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The given examples depict law of reciprocal proportions.

Jeremias Ritcher put forward the law of reciprocal proportions in 1792. The ratio of the masses in which they do so is either the same or a simple multiple of the mass ratio in which they combine, according to the statement, "If two different elements combine independently with the same weight of a third element."

a. Metal oxide contains

M = 0.46 g.

O = 0.77−0.46 = 0.31 g

Therefore, weight of oxygen that combines with 1g of

Metal = 0.31/0.46 = 0.674 g

b. 0.82g of Metal liberates H₂ = 0.00009 × 760 = 0.068g

Thus, the weight of H₂ that will be liberated by 1g of

Metal = 0.068/0.82 = 0.083 g

According to (a) and (b) the ratio of the weight of O:H that combine with or is displaced by the same weight of metal is 0.674:0.083 or 8:1.

Again according (c ), 1.25g of water contains

O= 1.12g and

H 1.25 − 1.11 = 0.14g

Therefore, The ratio of O:H::1.11:0.14 or 8:1

Hence, that ratio being the same, the law of reciprocal proportions is illustrated.

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Answer: a compound!

Explanation: a compound is something that contains two or more elements that are chemically combined in a fixed proportion!

Answer:

sorry we don't know the answer.