At the end of Ch. 33 may be found this statement: "Although geometry has been studied since antiquity, the development of algorithms for geometric problems is relatively new." Supply your opinion as to why this might be the case. [Use the text box below for your answer. The successful effort will consist of at least 50 words.]

The quotient of 6x^3+2x^2−x and x is 6x^3+2x^2−x divided by x

The value of the quotient 6x^3+2x^2−x by x is 6x^2 + 2x - 1

The quotient expression is given as:

6x^3+2x^2−x divide by x

The above means that,

We divide 6x^2 by x, we divide 2x^2 by x and we divide -x by x.

So, we have:

6x^3+2x^2−x divide by x = 6x^2 + 2x - 1

Hence, the value of the quotient 6x^3+2x^2−x is 6x^2 + 2x - 1

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a) To establish the central lines and control limits for an x and moving r chart for a paper towel process controlled by 24 valves, we need 24 subgroups for the x chart and at least 10-15 subgroups for the moving r chart.

b) One valve can be plotted as many times in succession as necessary

To establish the central lines and control limits for an x and moving r chart, we need to determine the number of subgroups needed. A subgroup is a small sample taken from the process at a particular time.

The number of subgroups required for the x and moving r charts depends on the process stability and the frequency of sampling. Generally, 20-25 subgroups are recommended for an x chart, and at least 10-15 subgroups are recommended for a moving r chart.

Since the paper towel process is controlled by 24 valves, we can use one subgroup for each valve to determine the process variation. Thus, we need 24 subgroups for an x chart, and at least 10-15 subgroups for a moving r chart.

Regarding the second part of the question, one of the valves can be plotted as many times in succession as necessary. However, it is important to ensure that the sampling is random and representative of the overall process. If one valve is plotted too many times in a row, it could skew the data and lead to inaccurate process control limits

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we have the numbers

1/2 and 2/5

the given fractions don't have the same denominator

so

Find out an equivalent fraction

1/2 -----> multiply by 5/5

(1/2)*(5/5)=5/10

2/5 ----> multiply by 2/2

(2/5)*(2/2)=4/10

Now compare the fractions

5/10 is greater than 4/10

so

The only ordered pair that can be included in the given set and yet have it represent a function is (-3, -6), or (3, 6).

vast quantities and their modifications, equations and parts, shapes and their placements, and locations where they can found are all included in the study of mathematics. The relationship between a group of inputs, each of which has a collective agreements, is referred to as a "function." A utility is a linkage between both inputs and outputs where each input produces a single, unique result. Every function has a domain but a codomain, often termed as a scope. F is typically utilised denote functions (x). An x is the input. Based on the following criteria, there are four primary categories of functions that are available: on functions, another functions, so several functions, within functions, and then on functions.

given

A value of x cannot have two outputs, or y-values, therefore start by using the process of elimination to eliminate the response options where the x coordinates have already been utilized in the relation. You now have two choices.

(-2, 2), (-1, 1), (0, 0), (1, 1), (2, 2)

so ( -3 , -6), ( 3, 6 ) as it has both different values of x and y .

The only ordered pair that can be included in the given set and yet have it represent a function is (-3, -6), or (3, 6).

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Answer:

See below

Step-by-step explanation:

Problem 4

\(H_0:p=0.40\\H_a:p>0.40\)

Problem 5

\(H_0:p=0.42\\H_a:p<0.42\)

Make sure to read the problems and translate it into math

The rate at which the top of the ladder is slipping down at the instant when the bottom of the ladder is 15 feet from the base of the building is -75/8 feet per second

The length of the ladder = 17

Consider the length of the base as x and the height is h

The rate at which the ladder is sliding = 5 feet per second

dx/dt = 5

Apply the Pythagorean theorem

x^2 + h^2 = 17^2

h^2 = 289 - x^2

h = \(\sqrt{289-x^2}\)

The rate of change of height with respect to x is

dh/dx = - x / (289 - x^2)^(1/2)

dh/dt = dh/dx × dx/dt

Substitute the values in the equation

= - 15 / (289 - 15^2)^(1/2) × 5

= -15/8 × 5

= -75/8 feet per second

Therefore, the rate of change of height when x = 15 is -75/8 feet per second

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The solutions to the equation with function 10cos(t) = -2 in the interval from 0 to 2π, rounded to the nearest hundredth, are approximately:


t ≈ 1.82 radians or 104.48 degrees
t ≈ 8.11 radians or 464.84 degrees


To solve the equation 10cos(t) = -2 in the interval from 0 to 2π, we can use the inverse cosine function (also known as arccos or cos^-1) to find the values of t that satisfy the equation.

First, let's isolate cos(t) by dividing both sides of the equation by 10:

cos(t) = -2/10

Simplifying further, we have:

cos(t) = -1/5

Now, we need to find the angles in the interval from 0 to 2π whose cosine is -1/5.


To do this, we can use the inverse cosine function (arccos) on a calculator or look up the corresponding angles in a trigonometric table.

Using a calculator, the inverse cosine of -1/5 is approximately 1.8235 radians or 104.48 degrees. However, we need to find all the solutions within the given interval.

Since cosine is a periodic function, we can add multiples of 2π to the initial solution to find additional solutions. Adding 2π to the initial solution gives us:

t = 1.8235 + 2π

Simplifying, we get:

t ≈ 1.8235 + 6.2832 ≈ 8.1067 radians or 464.84 degrees

So, the solutions to the equation 10cos(t) = -2 in the interval from 0 to 2π, rounded to the nearest hundredth, are approximately:

t ≈ 1.82 radians or 104.48 degrees
t ≈ 8.11 radians or 464.84 degrees

These are the values of t that satisfy the equation 10cos(t) = -2 in the given interval.

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TCP provides error checking to ensure reliable data delivery, making option A the correct answer. Only the propagation delay is not caused by the store-and-forward strategy employed by switching devices.

TCP (Transmission Control Protocol) provides error checking as part of its services. It ensures reliable data delivery by using acknowledgments and sequence numbers to detect and recover from packet loss, errors, or out-of-order delivery. When a TCP receiver receives data, it sends an acknowledgment (ACK) back to the sender to confirm the successful reception of packets. If the sender does not receive an ACK for a particular packet within a specified timeout period, it assumes the packet was lost or damaged and retransmits it.

TCP provides error checking to ensure reliable data delivery, making option A the correct answer.

The propagation delay is the time it takes for a signal to travel from the source to the destination. It is determined by the physical distance between the devices and the speed of signal propagation in the transmission medium. The propagation delay is an inherent characteristic of the medium and cannot be eliminated by switching devices or other strategies.

The other three options—processing delay, queuing delay, and transmission delay—are all caused by the store-and-forward strategy used by switching devices. Processing delay refers to the time taken to examine and process the packet headers. Queuing delay occurs when packets have to wait in a queue before being transmitted. Transmission delay is the time it takes to push the bits onto the transmission medium.

Among the given options, only the propagation delay is not caused by the store-and-forward strategy employed by switching devices.

3. The correct answer is A. The system is very well-engineered.

In a statistical multiplexing system, the queuing delay is the delay experienced by packets waiting in a queue before being transmitted. If the average queuing delay is very close to zero, it indicates that the system is well-engineered and efficiently managing its resources. A well-designed system can minimize or eliminate queuing delays by appropriately allocating resources and ensuring efficient scheduling algorithms.

Traffic intensity, which represents the ratio of the average traffic load to the transmission capacity, does not directly determine the queuing delay. It is possible to have low queuing delays even with high traffic intensity if the system is well-designed.

When the average queuing delay is close to zero, it suggests that the system is well-engineered and efficiently utilizing its resources, as stated in option A.

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The p-value for this hypothesis test for a proportion p is 0.039.

What is a random sample?

In statistics, a simple random sample is a subset of individuals chosen from a larger set in which a subset of individuals is chosen randomly, all with the same probability. It is a process of selecting a sample in a random way.

For the null hypothesis,

H0 : p = 0.63

For the alternative hypothesis,

Ha : p < 0.63

This is a left-tailed test

Considering the population proportion, probability of success, p = 0.63

q = probability of failure = 1 - p

q = 1 - 0.63 = 0.37

Considering the sample,

Sample proportion, P = x/n

Where,

x = number of success = 478

n = number of samples = 800

P = 478/800 = 0.6

We would determine the test statistic which is the z score

z = (P - p)/√pq/n

z = (0.6 - 0.63)/√(0.63 × 0.37)/800 = - 1.76

From the normal distribution table, the area below the test z score in the left tail is 0.039

Thus,

p = 0.039

Hence, the p-value for this hypothesis test for a proportion p is 0.039.

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Answer:

8.33

Step-by-step explanation:

He has to be at work by 10:30, but it takes 20 mins to walk

So, 10:30-20 minutes=10:10

We then look at the arrival time closest to this, which would mean he would arrive at 10.06.

trace this back the bus would gett him at 8:38, but its a 5min walk.

8:38-5 minutes+8.33

hope this helps :)

Answer:

2

Step-by-step explanation:

145 - 75 = 70

70 divided by 35 = 2

2 hours

Answer:

2 hours

Step-by-step explanation:

x is how meany hours he worked and we know that

145=45x+75 is true and when you put 2 in place for x you get 90+75 = 145 and 145=145

Answer:

21.25

Step-by-step explanation:

the tax on $95 is 21.25

Answer:

27/64

(Decimal: 0.421875)

Answer:

(1, -2) minimum

Step-by-step explanation:

its minimum bc thats the least amount you can get since its going down and the point is (1, -2) by looking at the lowest point which is the minimum u can see that.

Answer:

  x = ±1

Step-by-step explanation:

We have to assume you want the solution for y = 0:

  0 = x² -1

  1 = x² . . . . . . add 1

  ±1 = x . . . . . . take the square root

  x = ±1

The exact length of the curve is approximately 191.860 units.

To find the exact length of the curve, we need to use the arc length formula:

L = ∫(a to b) √[1 + (dy/dx)²] dx

where a and b are the endpoints of the curve and dy/dx is the derivative of y with respect to x.

First, we need to find dy/dx:

y = 4x² - ln(x)

dy/dx = 8x - 1/x

Now, we can substitute into the arc length formula:

L = ∫(15 to 34) √[1 + (8x - 1/x)²] dx

This integral is not easy to solve, so we will use a numerical method to approximate the length. We can use Simpson's rule, which gives the following approximation:

L ≈ [f(15) + 4f(24.5) + 2f(34)](34 - 15)/6

where f(x) = √[1 + (8x - 1/x)²].

Evaluating f(x) at each point and plugging into the formula, we get:

L ≈ [√(1 + (815 - 1/15)²) + 4√(1 + (824.5 - 1/24.5)²) + 2√(1 + (8*34 - 1/34)²)](34 - 15)/6

L ≈ 191.860

Therefore, the exact length of the curve is approximately 191.860 units.

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Answer:

If you are looking for volume, it would be 6,000 cm cubed

Step-by-step explanation:

Answer:

6000cm.

Step-by-step explanation:

Volume = Base × h

Base = L × width

Base = 20cm × 10cm

Base = 200cm

Volume = 200cm × 30cm

Volume = 6000cm.

Hope this helps you!

Answer:d

Step-by-step explanation:

Answer:

2\(x^{6}\)\(y^{2}\)

Step-by-step explanation:

Divide 12 by 6

Look where there are more 'x'.

How many more?

Look where there are more 'y'

How many more?

or

\(\frac{x^{a} }{x^{b} }\) = \(x^{a-b}\)

Answer:

y=4x+3

Step-by-step explanation:

find the slope using y2-y1/x2-x1

11-3/2-0

simplify

8/2

simplify

4

find b by using the equation y=mx+b

since we know 4 is the slope, plug it in for m

plug an ordered pair into y=4x+b

3=4(0)+b

3=b

plug b in y=4x+b

y=4x+3

Answer:

DC

Step-by-step explanation:

It is a straight line.

Answer:

C. D-C

Step-by-step explanation:

An arc that measures 180 degrees is a semicircle, and cd is a semicircle.

Answer:

C

Step-by-step explanation:

Answer:

C. 3n+9>21

Step-by-step explanation:

Ignore the 9 for a second and think about the phrase "3 times a number", if we say n is the number, then 3n is 3 times the number n.

Now we need something that is 9 more than this 3n, that means you add 9 to this, so you have 3n+9.

Finally, this 3n+9 is greater than 21, so we have 3n+9>21.

We were told that angle AEc and angle DEF are vertical angle.

Answer:

If you have the volume and radius of the cylinder: 1 Make sure the volume and radius are in the same units (e.g. cm 3 and cm) and radius in is radians. 2 Square the radius. 3 Divide the volume by the radius squared and pi to get the height in the same units as the radius.

Step-by-step explanation:

The length of one side of the new square-shaped garage is 4√3 meters.

A square is a two dimensional figure that has 4 equal sides. The area of a square can be solved by multiplying the length of its side by itself.

A = s^2

where s = side length

If the initial square-shaped garage has an area of 32 square meters and will be increased by 50%, then the new area should be 50% more than the initial area.

new floor area = 50% initial area + initial area

new floor area = 50%(32) + 32

new floor area = 16 + 32

new floor area = 48 square meters

If the new garage has a floor area of 48 square meters, using the formula for the area of a square, solve for the length of its side.

A = s^2

48 = s^2

s = 4√3 meters

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The critical value for a one-mean z-test at the 20% significance level, for a left-tailed test (Ha: μ < μ0), is -0.842.

To determine the critical value for a one-mean z-test at the 20% significance level for a left-tailed test (Ha: μ < μ0), we need to find the z-value that corresponds to an area of 20% in the left tail of the standard normal distribution.

From the given options:

- z0.8 = -0.842

- z0.4 = -0.253

- z0.2 = -0.842

- z0.1 = -1.282

- z0.05 = -1.645

Among these options, the z-value that corresponds to an area of 20% in the left tail of the standard normal distribution is z0.2 = -0.842.

Therefore, the critical value for a one-mean z-test at the 20% significance level, for a left-tailed test (Ha: μ < μ0), is -0.842.

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Dan's weight can be any value between 82 kg and 96 kg

Let's call Steve's weight "x".

According to the problem, Dan weighs 14 kg more than Steve, so Dan's weight would be x + 14.

Together, their weight would be the sum of their weights

x + (x + 14) = 2x + 14

We know that their combined weight is less than 178 kg, so the inequality will be

2x + 14 < 178

Subtracting 14 from both sides

2x < 164

Dividing by 2

x < 82

So Steve's weight is less than 82 kg.

To find the possible range of Dan's weight, we can substitute x + 14 for Dan's weight

(x + 14) < (178 - x)

Simplifying

2x < 164

x < 82

x + 14 < 96

So Dan's weight is less than 96 kg.

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Answer:

Multiply  5 *4  by  5* 8  by adding the exponents

5

12

Raise  

5

to the power of  

12

.

244140625

Step-by-step explanation: