The angular velocity ω is constant, the angular acceleration dos is zero. Link OB has no angular acceleration.
To determine the angular acceleration dos of link OB, we can use the following steps:
Find the linear velocity of point B on link OB. Since the hydraulic cylinder is extending at a constant rate of va = 3.9 m/s, the linear velocity of point A is also 3.9 m/s. Using the velocity ratio equation, we can find the linear velocity of point B:
va / vb = rAO / rOB
where rAO and rOB are the distances from point A and point B to the center of rotation O, respectively. Assuming that point A is fixed and point B is moving, we can solve for vb:
vb = (rOB / rAO) * va
Find the angular velocity of link OB. The angular velocity ω of link OB is related to its linear velocity vb by the following equation:
ω = vb / rOB
where rOB is the length of link OB.
Find the angular acceleration dos of link OB. The angular acceleration α of link OB is related to its angular velocity ω by the following equation:
α = dω / dt
Since the angular velocity ω is constant, the angular acceleration dos is zero. Therefore, link OB has no angular acceleration.
In summary, since link OB is fixed in this scenario and is not rotating, its angular acceleration dos is zero.
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If the total length of a measurement is 10 1/2" what is half of this length?
Answer:
13.335 CM (1 ft, 1.335 cm)
I am 80% sure this is the answer, but i am not too keen on math so if i am wrong let me know and i will try my best to fix it!
I hope this helped! Have a good day :]
Which of following are coding languages used in controlling a robot? *
A. Scratch
B. B/B--
C. C/C++
D. Robot Z
Answer:
C/C++
Explanation:
C/C++
What unit of electricity is used as a signal for a computer?
Answer:
A power supply unit (PSU) converts mains AC to low-voltage regulated DC power for the internal components of a computer. Modern personal computers universally use switched-mode power supplies
Answer:
Volt is the SI (Standard International) unit of electrical potential of the..
Explanation:
two technicians are describing how an air-conditioning system gets rid of the heat. Technician A says that heat always flows from the hotter to the colder object. Technician B says that as refrigerant evaporates, it absorbs heat as it changes from a liquid to a gas. which technician is correct?
Based on the information provided by these technicians, both of them are correct.
How does heat flow?According to heating, ventilation, and air conditioning (HVAC), heat in an air-conditioning system generally flows from the hotter object to the colder object.
As the refrigerant evaporates in a small radiator-type unit (evaporator), it absorbs heat as it changes phase from liquid to gas. Also, as the heat is being absorbed by the refrigerant, the small radiator-type unit (evaporator) becomes cold.
In conclusion, we can logically deduce that both of them are correct.
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Which of the following stability checks is not applied for cellular cofferdams structures. Select one: a. Bursting b. Overturning c. Sliding d. Anchor failure
The stability check that is not applied for cellular cofferdam structures is d. Anchor failure.
Cellular cofferdams are temporary structures used in construction to create a dry work environment in waterlogged areas. They are typically constructed using interlocking cells or compartments filled with soil or other suitable materials. The stability of cellular cofferdams is crucial to ensure the safety and effectiveness of the structure.
The stability checks applied to cellular cofferdams include:
a. Bursting: This check ensures that the cells or compartments of the cofferdam can withstand the pressure exerted by the water or soil outside without experiencing failure or rupture.
b. Overturning: This check verifies that the cofferdam structure is stable against overturning moments caused by lateral forces such as water pressure or soil pressure.
c. Sliding: This check assesses the resistance of the cofferdam against horizontal sliding caused by external forces, such as water currents or soil movement.
These three stability checks focus on the structural integrity and stability of the cofferdam under different loading conditions. However, anchor failure is not typically considered as a specific stability check for cellular cofferdams. Anchors are commonly used in cofferdam construction to provide additional stability and resistance against horizontal forces. However, the failure of individual anchors is not typically assessed as a separate stability check for cellular cofferdams.
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The liquid-phase reaction A + B → C follows an elementary rate law and is carried out isothermally in a flow system. The concentrations of A and B feed streams are 2 M before mixing. The volumetric flow rate of each stream is 5 dm3 /min and the entering temperature is 300 K. The streams are mixed immediately before entering. Two reactors are available: One is a gray 200.0 dm3 CSTR that can be heated to 77°C or cooled to 0°C, and the other is a white 800.0 dm3 PFR operated at 300 K that cannot be heated or cooled but can be painted red or black. (Note: k = 0.07 dm3 /mol*min at 300 K and E = 20 kcal/mol.) How long would it take to achieve 90% conversion in a 200 dm3 batch reactor with CA ° = CB ° = 1 ???? after mixing at a temperature of 70°C?
Answer:
1.887 minutes
Explanation:
We are given k = 0.07 dm3 /mol*min at 300 K and E = 20 kcal/mol = 20000 cal/mol
To solve this, first of all let's calculate the rate constant(k);
For this question, The formula is;
K(t) = k(300K) × exp[(E/R)((1/300) - (1/T2))]
R is gas constant = 1.987 cal/mol.K
For temperature of 70°C which is = 70 + 273K = 343K, we have;
K(343) = 0.07 × exp[(20000/1.987)((1/300) - (1/343))]
K(343) = 4.7 dm³/mol.min
The design equation is;
dX/dt = -(rA/C_Ao) = K•(C_Ao)²•(1 - X)²/(C_Ao) = (KC_Ao)(1 - X)²
Since there is no change in volume by cause of the state at which the reaction is carried out, that is liquid. Thus, integrating and solving for time for a 90% conversion we obtain;
(0.9,0)∫dX/(1 - X)².dX = (KC_Ao)((t, 0)∫dt
So, we'll get;
0.9/(1 - 0.9) = 4.77 × 1 × t
t = 9/4.77
t = 1.887 minutes
Luna drew a scale drawing of the high school. The parking lot, which is 54 meters wide in real life, is 102 centimeters wide in the drawing. What scale did luna use?.
Luna drew a scale drawing of the high school. The parking lot, which is 54 meters wide in real life, is 102 centimeters wide in the drawing. Scale drawings are used to draw shapes in a different proportional size and the scale used in the drawing is 17 centimeters : 9 meters
How to calculate the drawing's scale
The answer to the question is:
54 meters is the actual length.
Size of the scale is 102 centimeters.
The scale is thus:
Scale length equals real length.
This results
Scale: 54 meters at 102 millimeters.
shrink the scale
Scale: 9 meters = 17 millimeters
Your question is incomplete but most probably your full question was
Luna drew a scale drawing of the high school. The parking lot, which is 54 meters wide in real life, is 102 centimeters wide in the drawing. What scale did Luna use? 17 centimeters:___meters
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A non-entrepreneurship, work-based, agricultural type of SAE, in which a student learns and gains skills in a paid or unpaid position describe which type of SAE?
Answer:
Placement.
Explanation:
SAE is an acronym for Supervised Agricultural Experience programs and it is typically a planned, practical-based program designed to help students develop competent skills and experience in their various career choice. Basically, it enhances the academic knowledge and agricultural skills acquired by the students in the classroom.
Generally, there are four (4) main types of Supervised Agricultural Experience Programs;
1. Entrepreneurship SAE.
2. Exploratory SAE.
3. Research and Experimentation SAE.
4. Placement SAE.
A non-entrepreneurship, work-based, agricultural type of Supervised Agricultural Experience program (SAE), in which a student learns and gains skills in a paid or unpaid position describe a placement.
Some examples of organizations or businesses that provide placement SAE to students includes; lawn services, veterinary clinics, soil conservation firms, livestock farms, floral shops, grain farms etc.
Answer:
Placement
Explanation:
Three parallel flow flocculation basins are to be used to treat a flow rate of 3 MGD. What is the design volume, in cubic feet, of one of these tanks if the detention time is 30 minutes
Answer:
2800ft³
Explanation:
The formula used to calculate the volume of one tank is:
Vt = Q x t
We have Q as
Q = (3x10⁶gal/d)/3 tanks
Q = 1x10⁶gals/d per tank
To get volume of one tank
[(30min)x(1x10⁶)x(0.1337)]/1440 min
= 30x1000000x0.1337/1440
= 4011000/1440
= 2,785ft³ or 2800ft³
In conclusion, 2800ft³ is the design volume, in cubic feet, of one of these tanks with detention time as 30 minutes
What is the acceleration of a 0.8 kg vehicle powered by 0.07 N of force?
Using the Newton's second law of motion we will see that the acceleration is 0.0875 m/s^2.
What is the acceleration of the vehicle?The acceleration of a vehicle is determined by the force acting on it and its mass, as described by Newton's second law of motion:
F = m * a
where F is the force acting on the object, m is the mass of the object, and a is the resulting acceleration.
In this case, the force acting on the vehicle is 0.07 N, and the mass of the vehicle is 0.8 kg. Substituting these values into the equation above, we get:
0.07 N = 0.8 kg * a
Solving for a, we get:
a = 0.07 N / 0.8 kg
a = 0.0875 m/s^2
Therefore, the acceleration of the 0.8 kg vehicle powered by 0.07 N of force is 0.0875 m/s^2.
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Thin cuts called Sipes allow the tread pattern blocks to flex during stops and starts? Group of answer choices True False
Answer:
I think its True
it should be True
One of the principles of supply chain strategy
The principle of supply chain strategy is Segregate customers on the basis of service needs of different groups and follow the supply chain to deliver goods and services to the consumers profitably.
What is supply chain?Supply chain is the group of activities performed by an organization to deliver goods and services to the consumer end.
Thus, one of the principle of supply chain strategy is separate the customers on the basis of service needs of different groups and follow the supply chain to deliver goods and services to the consumers so that they earn profit.
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19. Write down the reason for the preparation of 350 mL mud in pilot test applications in the laboratory 20. What features of the mud are controlled by the chemicals added to the drilling mud? Make a list of them without explanation. 21. What chemical would you use to remove the calcium from the mud that was contaminated by cement or lime?
The preparation of 350 mL mud in pilot test applications in the laboratory is necessary to test the properties of the mud before it is used in larger quantities.
The pilot test provides an opportunity to evaluate the mud's performance under controlled conditions and make necessary adjustments to the mud composition before drilling operations commence. The pilot test is also useful for identifying any potential problems and ensuring that the mud is suitable for the drilling application.
20. The chemicals added to the drilling mud play a crucial role in controlling various features of the mud, including its density, viscosity, pH level, and fluid loss. They also help to prevent the formation of solids in the mud and control the growth of microorganisms. Some of the other features controlled by the chemicals include:
- Emulsion stability
- Lubricity
- Corrosion inhibition
- Filtration control
- Shale stabilization
- Thermal stability
- Defoaming
21. To remove calcium from the mud that has been contaminated by cement or lime, one could use a chelating agent such as ethylenediaminetetraacetic acid (EDTA). This chemical forms a complex with calcium ions, which are then removed from the mud by filtration or settling. Other chemicals that may be effective in removing calcium include ammonium citrate, hydrochloric acid, and sodium carbonate. The choice of chemical will depend on the specific situation and the nature of the mud contamination.
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Problem 3. The uniform beam is supported by two rods AB and CD that have cross-sectional areas of 10 mm2 and 15mm2, respectively. Determine the intensity w of the distributed load so that the average normal stress in each rod does not exceed 300 kPa.
Answer:
hello the diagram related to your question is missing attached below is the required diagram.
The value of AC = 6m
answer 2.25 N
Explanation:
From the diagram attached below
average intensity of loading = w/2
Total load due to linearly varying load = \(\frac{wL}{2}\)
w = maximum intensity of load , L = span of varying load
since AC = 6m( L ) then
Total load due to linearly varying load = 3w ------ ( 1 )
attached below is the detailed solution of the given problem
the fixed scale specifies 10.5 millimeters and the thimble specifies 30 hundredths of a mm. what is the total value shown by the micrometer when you add these readings together
Answer:
10.80 mm
Explanation:
Given that the reading of the fixed scale is : 10.5 mm
The thimble scale specifies : 0.30 mm
The micrometer reading will be : 10.5 + 0.30 =10.80 mm
An AC bridge has 4 arms. In arm AB, a 120 kilo-ohm resistor and a 47 microfarads capacitor are connected in parallel while arm BC has 330 microfarads capacitor. If arm AD has a 330 kilo-ohm resistor, calculate the value of the unknown capacitor and resistor in arm CD connected in series. (AC power is supplied through A and C while the detector is connected across BD)
The unknown capacitor in arm CD must have a value of 330 microfarads, and the unknown resistor must have a value of 100 kilo-ohms.
To solve the problem, use the following formula:
Cseries = C1 x C2 / (C1 + C2)
Where C1 is the value of the capacitor in arm AB (47 microfarads) and C2 is the value of the capacitor in arm BC (330 microfarads).
Therefore, Cseries = 330 microfarads.
Also, the total resistance of arms CD is the sum of the resistance of the resistor (R) and the reciprocal of the capacitive reactance of the capacitor (1/Xc).
Using the following formula:
Rtotal = R + 1/Xc
Where Xc = 1/2πfC,
f is the frequency and C is the capacitance.
For this problem,
Xc = 1/2π(50)(330 x 10-6)
=> 100 kilo-ohm.
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Recent research has identified mold-surface textures that will either (a) inhibit a solidified steel from separating from the mold or (b) force it to stay in contact in continuous casting. What is the advantage of a mold that maintains intimate contact with the steel
Answer:
faster heat conduction
Explanation:
The advantage of mold that maintains intimate contact with the material is that thermal contact resistance between the two is going to be reduced. That is, it would be lower.
Consequently, what would be happening would be heat getting conducted faster, this would then allow for higher traverse speeds or it could allow for the usage of shorter molds.
Most cylinder wear occurs at the top of ring travel true or false
Answer:
true
I hope it helps mate
I will always help you understanding your assingments
enjoy your day
#Captainpower:)
A project ha following time chedule: Activity Time in Week Activity Time in Week 1-2 4 5-7 8 1-3 1 6-8 1 2-4 1 7-8 2 3-4 1 8-9 1 3-5 6 8-10 8 4-9 5 9-10 7 5-6 4 Contruct the network and compute: (1) TE and TL for each event (2) Float for each activity (3) Critical path and it duration
(1) TE and TL for each event
Event 1: TE=0, TL=0
Event 2: TE=4, TL=4
Event 3: TE=1, TL=5
Event 4: TE=2, TL=6
Event 5: TE=6, TL=12
Event 6: TE=1, TL=2
Event 7: TE=8, TL=16
Event 8: TE=9, TL=17
Event 9: TE=8, TL=18
Event 10: TE=16, TL=23
(2) Float for each activity
Activity 1-2: Float=0
Activity 1-3: Float=3
Activity 2-4: Float=2
Activity 3-4: Float=1
Activity 3-5: Float=0
Activity 4-9: Float=0
Activity 5-6: Float=0
Activity 5-7: Float=0
Activity 6-8: Float=7
Activity 7-8: Float=6
Activity 8-9: Float=5
Activity 8-10: Float=0
Activity 9-10: Float=0
(3) The critical path for this project is: 3-4, 4-9, 5-7, 7-8, 8-10, 9-10, with a total duration of 23 weeks.
THE SOLUTIONTo construct the network and compute the requested information, we first need to create a list of events and activities.From the given schedule, we can identify the following events and activities:Events:1, 2, 3, 4, 5, 6, 7, 8, 9, 10
Activities:1-2: 4 weeks
1-3: 1 week
2-4: 1 week
3-4: 1 week
3-5: 6 weeks
4-9: 5 weeks
5-6: 4 weeks
5-7: 8 weeks
6-8: 1 week
7-8: 2 weeks
8-9: 1 week
8-10: 8 weeks
9-10: 7 weeks
Now we can compute the TE (time when an event is expected to start) and TL (time when an event is expected to be completed) for each event, as well as the float (amount of time that an activity can be delayed without delaying the project completion) for each activity.TE and TL for each event:Event 1: TE=0, TL=0
Event 2: TE=4, TL=4
Event 3: TE=1, TL=5
Event 4: TE=2, TL=6
Event 5: TE=6, TL=12
Event 6: TE=1, TL=2
Event 7: TE=8, TL=16
Event 8: TE=9, TL=17
Event 9: TE=8, TL=18
Event 10: TE=16, TL=23
Float for each activity:Activity 1-2: Float=0
Activity 1-3: Float=3
Activity 2-4: Float=2
Activity 3-4: Float=1
Activity 3-5: Float=0
Activity 4-9: Float=0
Activity 5-6: Float=0
Activity 5-7: Float=0
Activity 6-8: Float=7
Activity 7-8: Float=6
Activity 8-9: Float=5
Activity 8-10: Float=0
Activity 9-10: Float=0
The critical path is the sequence of activities that have zero float, meaning they cannot be delayed without delaying the project completion. The critical path for this project is: 3-4, 4-9, 5-7, 7-8, 8-10, 9-10, with a total duration of 23 weeks.Learn more about Construct Network here:
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space probes often visit several planets before getting to their final destinations. the main reason they do this is to
One of the main motives is to gain momentum and save fuel by utilising the gravitational pull of these planets. This method is often referred to as gravitational slingshot or gravity help.
What is a space probe's primary function?An autonomous, unpiloted spacecraft used to research space and gather scientific data is called a space probe. A space probe is launched from Earth with a set of scientific instruments and tools to study the atmosphere and composition of space as well as other planets, moons, and celestial bodies.
Why is it necessary to go into space to study the distant planets?Scientists and technologists are working to find ways to study stars, planets, moons, and galaxies outside of our solar system even as we research the Sun and adjacent planets.
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A good way to track problems that need to be solved later in the day or week is with
How often might ergonomic training be offered in the workplace
Answer:
'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?
'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?v'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'स माचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?'समाचार पत्र में लेख लिखना' किस मौलिक अधिकार का उदाहरण है?
Explanation:
"Aking Pangako"
Meron akong pangako,hindi mapapako
Upang hindi makasakit,sa damdamin ng ibang tao
Simple man o mahirap,piliting magampanan
Dahil tayo ay Pilipino,Tuloy ang pangako
Aking kaibigan, wag kang sasama ang loob
Kapag ako'y nangako,baka ito'y mapako
Gagampanan ko na,aking mga pangako
Upang 'di mag hiwalay,magkaibigang tunay.
What does efficiency measure?
Answer:
Efficiency is defined as any performance that uses the fewest number of inputs to produce the greatest number of outputs. Simply put, you're efficient if you get more out of less.
Explanation:
Which of the following parts is unique to a preset hub?
a. A specialized adjusting nut
b. A metal sleeve between the tapered roller bearings
c. A ProTORQ adjusting nut
d. A long-life hub seal
A ProTORQ adjustable nut is unique to a preset hub. Wheel hub assemblies that are pre-adjusted and sealed at the factory are known as preset hubs. They are meant to simplify the installation process.
What is a tapered roller bearing used for?These bearings, which are frequently used in gearboxes, hoisting apparatus, rolling mills, and mining equipment, can support strong radial loads and axial loads in both directions, depending on the design.
Are tapered roller bearings adjustable?The word "setting" for tapered roller bearings refers to the precise amount of end play (axial clearance) or preload (axial interference) present within a mounted bearing. The freedom to easily alter and optimise configuration at the time of assembly is an inherent advantage of tapered
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Positive correlations of handle steeper incline of bicycle is what? a. Light weight frame b. Suspension. C. More gears. D. Soft comfort seat. E. Lights. Give me answer from objectives
Positive correlations of handle steeper incline of bicycle is a. Light weight frame.
What is the Positive correlations?A positive relationship implies that as one variable increments, the other variable moreover increments. Within the setting of cycling, handle steepness can influence the rider's pose and consolation level, which in turn can impact components such as speed, continuance , and generally performance.
Hence, Components which will influence the relationship between handle steepness and cycling execution might incorporate the rider's wellness level, the landscape being ridden on, the sort and quality of the bike components, and other person inclinations or variables.
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What cell type has no membrane-bound organelles, has DNA that is found in an area called the
nucleoid, and is very small?
A. Eukaryotic cell
B. Prokaryotic cell
C. Animal cell
D. Plant cell
Answer:
Prokaryotic cell
Explanation:
Which of the following is NOT a good way to handle used oil filters
The option that is NOT a good way to handle used oil filters is: "Keep them in the car" (Option D)
Are used Oil Filters useful?
Re-refining is an excellent method of disposing of leftover motor oil since it is ecologically beneficial and transforms wasted oil into a renewable resource. Refining leftover motor oil lessens a country's dependency on imported crude oil. At the moment of disposal, used motor oil filters retain oil.
Oil filters must also be disposed of appropriately since they contain trace quantities of spent oil. You have three alternatives for disposing of used oil filters: pierce and hot-drain the filter, smash the filter, or take the filter to a body shop or local recycling center that accepts used oil filters.
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Full Question:
Which of the following is NOT a good way to handle used oil filters
Drain for at least 24 hours, crush recycle used oil filters.Keep them in the care
What is the predicted value of miles per gallon for a car that has 2.78 (2,780 lbs) weight and 225 horsepower? Suppose that this car achieves 18 miles per gallon, what is the residual based on this actual value and the value that is predicted using the regression equation?
a. mpg = 36.094 - 3.662(wt) - 0.030(hp)
b. mpg = 36.037 - 3.648 (wt) - 0.030 (hp)
Therefore, the residual based on the actual value of 18 miles per gallon and the value predicted using the regression equation a. is -2.194.
Using equation a.
mpg = 36.094 - 3.662(wt) - 0.030(hp)
mpg = 36.094 - 3.662(2780) - 0.030(225)
mpg = 20.194
Therefore, the predicted value of miles per gallon for a car that has 2.78 (2,780 lbs) weight and 225 horsepower is 20.194 miles per gallon.
To calculate the residual:
Residual = Actual value - Predicted value
Residual = 18 - 20.194
Residual = -2.194
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regarding the hazardous mechanical motions of all machines, and the dangers they present what is the first step
Answer:
so it would be recognizing them
Explanation:
Hazardous Motions—including rotating machine parts, reciprocating motions (sliding parts or up/down motion), and transverse motions (materials moving in a continuous line). Points of Operation—the areas where the machine cuts, shapes, bores or forms the stock being fed through it.
Convert 273.15 mL at 166.0 mm of Hg to its new volume at standard pressure.
Answer:
(166.0 mm Hg) (273.15 mL) = (760.0 mm Hg) (x)