At what projection angle will the range of a projectile equal its maximum height?.

The points about the stars from the appendix are: Sirius A is the most luminous star within 12 parsecs. It is also the brightest star in our sky, even though it is not the closest. The list of the brightest stars will include the very luminous hot stars from distances greater than 12 light-years, while the list of the fainter yet closer low-mass stars will not.

The list of stars within 12 light-years is volume-limited, which means that almost all of the stars within that distance are listed regardless of luminosity. Such a list is a better representative of the total population of stars and is more plausible to be dominated by low-mass stars. The list of brightest stars includes only those stars that are above a certain apparent brightness threshold.

Therefore, the faintest nearby stars are excluded, but the brightest and rarer hot stars are included in higher proportion than they are in a volume-limited list.

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Answer:

A ping pong ball

Explanation:

It has the lightest weight among the rest

Answer:

Explanation:

The mass of an object given it's force and acceleration can be found by using the formula

\(m = \frac{f}{a} \\ \)

f is the force

a is the acceleration

From the question we have

\(m = \frac{15}{5} = 3 \\ \)

We have the final answer as

Hope this helps you

The value of force exerted on the women will be normal of the lift in positive x direction .

Acceleration is defined as change of velocity divided by time.

Since lift is moving upward at a steady speed , that means no change of speed has been taken place . hence no acceleration.

There is no external acceleration acting on the lift . Hence there will be  two forces, one is the force of gravity and the other is upward normal force from the elevator.

N = mg if the elevator is at rest or moving at constant velocity

The value of force exerted on the women will be normal of the lift in positive x direction

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Answer:

0.67 ms

Explanation:

The total time it takes the sound to enter and leave the water is t and

t = t' + t" where t' = total time of sound in air = d'/v' where d' = total distance sound travels in water = 2D (since the sound waves passes through the water twice )where D = distance travelled from water to surface of copper block = 0.45 m and v' = speed of sound in water = 1500 m/s and  t" = total time of sound in copper = d"/v" where d" = total distance sound travels in copper block = 2D' (since the sound waves passes through the copper block twice )where D' = thickness of copper block = 0.15 m and v" = speed of sound in water = 4600 m/s

So, t = t' + t"

t = d'/v' + d"/v"

t = 2D/v' + 2D'/v"

Substituting the values of the variables into the equation, we have

t = 2 × 0.45 m/1500 m/s + 2 × 0.15 m/4600 m/s

t = 0.90 m/1500 m/s + 0.30 m/4600 m/s

t = 0.0006 s + 0.000065 s

t = 0.000665 s

t = 0.665 ms

t ≅ 0.67 ms

Note that the sound wave passes through the water and copper block without refracting since it enters perpendicularly. Also, the sound wave passes twice through each of the copper block and water hence the total distance in each material is twice the initial distance or thickness.

Answer:

    t = 6.63 10⁻⁴ s

Explanation:

The speed of sound is constant in a given material medium, so to calculate time we can use the uniform motion relationships

           v = d / t

           t = d / v

the speeds of sound in the three media are

air            v = 343 m / s

water       v₁ = 1493 m / s

copper    v₂ = 5010 m / s

the distance traveled in the water on the round trip is

             d = 2 x

             d₁ = 2 0.45 0.90m

the time to travel this distance is

             t₁ = d₁ / v₁

             t₁ = 0.9 / 1493

             t₁ = 6.028 10⁻⁴ s

the distance in the copper

             d₂ = 2 0.15 m

             d₂ = 0.30 m

the time to travel this distance in copper is

              t₂ = d₂/ v₂

              t₂ = 0.30 / 5010

              t₂ = 5.988 10⁻⁵-5 s

the total travel time is

             t = t₁ + t₂

             t = 6.028 10⁻⁴ + 0.5988 10⁻⁴

             t = 6.6268 10⁻⁴ s

             t = 6.63 10⁻⁴ s

Answer:

It uses x-rays. The image is produced by polarizing exciting hydrogen nuclei of water molecules in the human tissue which will produce the image.  

Answer:

It uses x-rays. The image is produced by polarizing exciting hydrogen nuclei of water molecules in the human tissue which will produce the image.

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Answer:

The magnitude of the couple is 16.25 Nm.

Explanation:

A couple is a force that always produce a turning effect of objects on which it is applied. It has applications in doors, taps, revolving doors etc. Couple is a two equal but opposite force applied on an object.

couple = force x length

From the given question, the couple acting on the ring can be determined as;

couple = 25 x 0.65

           = 16.25 Nm

The magnitude of the couple is 16.25 Nm.

The mass can be calculated by dividing the net force acting on an object by the acceleration of the object. When talking about net force, we use the units kilogram meter per second squared. This is also known as a Newton. The units for acceleration is meters per seconds squared, and the units for mass are kilograms.

The time taken to cause 40 watts of power with 7 J of work being done will be 0.175 seconds.

Power is defined as the work done by the body per second. In other words, power is the rate of doing work. The amount of energy transferred or converted per unit of time is referred to as power.

The watt is the unit of power in the International System of Units, equal to one joule per second. Power is sometimes referred to as activity in older works. A scalar quantity is a power.

Given that the power is 40 watts and the work is 7 J. The time will be calculated as:-

Power = Work / Time

40 = 7 / Time

Time = 7 / 40

Time = 0.175 seconds

Therefore, the time will be 0.175 seconds.

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Answer:

Dark matter?

Explanation:

Answer:

matter

Explanation:

The purpose of the helical structure in a traveling-wave tube is to (d) enhance the bunching effect that occurs for the positive charge carriers in the electron beam.

The helical structure in a traveling-wave tube serves as an interaction circuit between the electron beam and the electromagnetic wave. The interaction between the beam and the wave leads to a phenomenon known as bunching, where the electrons in the beam are grouped together in a more compact manner. Bunching is crucial for efficient energy transfer from the electron beam to the electromagnetic wave.

The helical structure plays a key role in enhancing this bunching effect. As the electron beam travels through the helix, the helical structure provides a periodic electric field that interacts with the beam. This interaction causes the electrons to experience a force that synchronizes their motion with the electromagnetic wave. The synchronized motion results in the formation of electron bunches or density modulations within the beam.

By enhancing the bunching effect, the helical structure increases the efficiency of energy transfer from the electron beam to the electromagnetic wave. The bunches of electrons in the beam interact more effectively with the electromagnetic wave, leading to greater amplification and modulation of the signal carried by the wave.

It's important to note that the other options mentioned, such as (a) forming a helical resonator, (b) serving as an inductor, or (c) reducing the speed of the electromagnetic wave, are not the primary functions of the helical structure in a traveling-wave tube. While resonators and inductors can be present in the design of a traveling-wave tube, their functions are separate from the role of the helical structure in enhancing bunching and facilitating efficient energy transfer.

Therefore, in a traveling-wave tube, the primary purpose of the helical structure is to enhance the bunching effect for positive charge carriers in the electron beam, leading to improved energy transfer and amplification of the signal carried by the electromagnetic wave.

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Answer:   Electromagnetism and sound

Answer:

b.positive and decreasing in magnitude.

Explanation:

The kinematics of a body can be calculated by means of the following expression.

\(v_{f}=v_{o}-g*t\)

where:

vf = final velocity [m/s]

vo = initial velocity = 40 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time [s]

As we can see from the above equation, the final velocity of a body decreases its initial velocity as time increases. That is, as the body rises, the velocity decreases.

Maximum static friction is usually greater than the kinetic friction of the SAME object.

Friction is the pressure that opposes the movement of a stable item over another. There are in particular 4 forms of friction: static friction, sliding friction, rolling friction, and fluid friction.  

Static friction is pressure that maintains an item at rest.

Static friction definition may be written as:

Friction is skilled when people try and flow a desk-bound item on a floor, without truly triggering any relative movement between the frame and the floor on which it is.

Kinetic friction is a pressure that acts among shifting surfaces. A frameshifting at the floor stories a pressure withinside the contrary route of its movement.

The importance of the pressure will rely upon the coefficient of kinetic friction between the 2 materials.

Since the maximum Static friction might be executed when the body is about to move

Thus,

we can conclude that the maximum static function will be greater than the kinetic friction of the same object and same surface.

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The acceleration of a proton in an electric field of 700 N/C is 4.4x10^-14 m/s^2, in the direction of the field.

The acceleration of a charged particle in an electric field is given by the formula a = F/m, where F is the electric force acting on the particle and m is its mass. For a proton of mass 1.67x10^-27 kg and charge 1.6x10^-19 C, the electric force is F = qE, where E is the electric field intensity.

Plugging in the values, we get F = 1.6x10^-19 C x 700 N/C = 1.12x10^-16 N. Therefore, the acceleration of the proton is a = F/m = 1.12x10^-16 N / 1.67x10^-27 kg = 6.69x10^10 m/s^2. However, since this value is very large, we need to convert it to nanometers per second squared (nm/s^2) to make it more meaningful.

This gives us a value of 4.4x10^-14 m/s^2, which is the magnitude of the acceleration. The direction of the acceleration is the same as the direction of the electric field, which in this case is the positive x-axis.

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Answer:

300 kg x cm/s / 100 = 3 kg x m/s.

Answer:

mercury

Explanation:

edge 2020

Answer:

5 years\(\)

The statement "They have a positive charge and are present in the nucleus of an atom along with the neutrons" correctly describes protons.

Protons are small particles that make up the nucleus of an atom. They carry a positive charge and have a mass of approximately 1 atomic mass unit. The number of protons within an atom's nucleus defines its atomic number and thus its identity as an element.

For instance, carbon atoms have 6 protons, and oxygen atoms have 8 protons. Protons are vital building blocks of all atoms and play a significant role in the chemical behavior and reactions of elements.

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Answer:

Approximately 26.33 m/s.

Explanation:

We can apply one of the four kinematic equations:

\(\displaystyle \Delta d = \frac{1}{2}\left( v_f + v_i\right)t\)

Since the car slides to a stop after traveling 7.9 meters in 0.6 seconds, Δd = 7.9, t = 0.6, and v_f = 0. Substitute and solve for v_i:

\(\displaystyle \begin{aligned} (7.9 \text{ m}) &= \frac{1}{2}\left((0\text{ m/s}) + v_i)(0.6\text{ s}) \\ \\ v_i &=\frac{79}{3} \text{ m/s} \approx 26.33 \text{ m/s} \end{aligned}\)

In conclusion, the initial velocity of the car is about 26.33 m/s.

Answer:

232 N

Explanation:

By Hooke's law, the force applied to a spring is proportional to the stretch of the spring, so

F = kx

Where F is the force, k is the spring constant and x is how much it is stretched.

So, replacing k by 58N/cm and x by 4 cm, we get

F = (58 N/cm)(4 cm)

F = 232 N

Therefore, the force applied is 232 N

1/second Equals 1.99 x 10-7 radians. Earth rotates at a rate of 1.99 x 10-7 per second.

If the angles were not approximately 1 one of, then the radius times the angle's measurement in radians, or the width of a arc s = r, would be the ratio of the distance by the point located on the circle. The result of substituting into the linear speed formula is v = r t or v = r t.

A pseudovector used in physics to express how quickly the angular location or orientation of an item changes over time is called an angular velocity or rotational velocity.

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Nitrile Gloves  gloves are safe for working with electricity.

A synthetic rubber made from acrylonitrile and butadiene, nitrile rubber is also referred to as nitrile butadiene rubber, NBR, Buna-N, and acrylonitrile butadiene rubber. Trade names like Perbunan, Nipol, Krynac, and Europrene are also used. Being resistant to chemicals, fuel, and oil makes this rubber special.

These gloves are therefore the best option for anyone who must handle potentially dangerous and caustic chemicals. Being incredibly puncture-resistant and removing the possibility of latex allergic reactions, they are also ideal for the majority of medical settings.

The robust barrier of protection provided by nitrile gloves can help keep the wearer safe from chemicals, acids, and oils. Latex-free: Nitrile gloves are excellent for anyone with sensitive skin or a latex allergy because they are latex-free, unlike natural rubber gloves.

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When you push down a box at an angle theta with respect to the horizontal and the box is at rest on a rough surface, several factors come into play.

1. The force of gravity acts vertically downward on the box. This force can be decomposed into two components: a vertical component (mg) and a horizontal component (0).

2. The normal force, which is the force exerted by the surface on the box, acts perpendicular to the surface. It balances the vertical component of the gravitational force, ensuring that the box does not sink into the surface.

3. Since the box is at rest, the static friction force opposes the horizontal component of the gravitational force. This friction force arises due to the roughness of the surface and prevents the box from sliding down.

4. The magnitude of the static friction force can be calculated using the equation fs ≤ μs * N, where fs is the static friction force, μs is the coefficient of static friction, and N is the normal force. If the applied force is less than or equal to the maximum static friction force, the box remains at rest. If the applied force exceeds this maximum, the box will start to slide.

To summarize, when you push down a box at an angle theta on a rough surface, the vertical component of the gravitational force is balanced by the normal force, while the horizontal component is counteracted by the static friction force. The box will remain at rest as long as the applied force does not exceed the maximum static friction force.

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Complete Question- You push down on a box, as shown, at an angle with respect to the horizontal. The box is at rest on a rough surface and the coefficient of static friction is μs.

Fm

a) Draw a free-body diagram for the box.

b) Show that for a given angle that the force necessary to start the box moving is F> Hsmg sec 1-μs tan 0

c) For what angle will the box never move?

b) Show that for a given angle that the force necessary to start the box moving is F> Hsmg sec 1-μs tan 0

c) For what angle will the box never move?

Answer: A

Explanation:

The right answer is D. The stone hurled from the cliff's apex.

The entire journey that an object has taken can be used to define distance. The entire distance travelled by a car, for instance, would be 13 km if it traveled 5 km east, 8 km north, and back again.

It condenses the entire world—or only a portion of it—onto a small piece of paper. Cartographers take care to accurately depict the distances between the two locations when creating a map. This aids in determining the precise distance between two locations.

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The speed of the hot dog cart going at point B wen jasmine finally wakes up is 21.36 m/s.

Mass of the cart = m = 327 Kg

Speed of the cart while rolling downhill = v = 2.9 m/s

Height of the hill = h = 50 m

Height at point B = h' = 30 m

Speed of the cart when jasmine wakes up = v' =

Using the conservation of energy theorem,

= sum of kinetic and potential energy initially = sum of kinetic energy finally at point B

= mgh + (1/2)mv² = (1/2)mv'²

= gh + (1/2)v² = (1/2)v'²

= 9.81 X (50-30) + (1/2) X 2.9² = (1/2)v'²

= v'² = 21.36 m/s

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The galaxy comprises of various stars. We are unlikely to find earth-like planets around halo stars in the galaxy because Halo stars need few heavy elements to create rocky planets.

A galaxy is a massive cluster of stars held together by t he effect of gravity.

Halo stars formed in an environment where there were few heavy elements to create rocky planets.

Thus, we are unlikely to find earth-like planets around halo stars in the galaxy because Halo stars need few heavy elements to create rocky planets.

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Measuring forces

1) The combined force of two rubber bands is twice as much as the force of one rubber band.

This is because the force of each rubber band is added together to create the combined force.

2) Use six rubber bands stretched to the same standard length and combine their forces together.

To create a force six times as large as the force created by one rubber band, you could use six rubber bands stretched to the same standard length and combine their forces together.

3) Measure the length of the rubber band when it was stretched

To assure that the forces were the same, you could measure the length of the rubber band when it was stretched to create the initial force and then stretch the rubber band to the same length again to create the same force.

4) Yes, they can provide a convenient way.

Side-by-side rubber bands can provide a convenient way of accurately reproducing forces of many different sizes if they are all stretched to the same standard length. This is because the force created by each rubber band can be added together to create a combined force of any desired size.

Relationship between acceleration and force
1) There is a simple mathematical relationship between the acceleration of a cart and the force applied to the cart.

The equation for this relationship is F=ma, where F is the force applied to the cart, m is the mass of the cart, and a is the acceleration of the cart. This equation shows that the acceleration of the cart is directly proportional to the force applied to the cart and inversely proportional to the mass of the cart.

2) The acceleration of the cart would also increase by a factor of 10.

This is because the acceleration of the cart is directly proportional to the force applied to the cart. The acceleration-time graph of the cart's motion would show a steeper slope, indicating a larger acceleration.

3) The acceleration-time graph of the cart's motion would show a steeper slope, indicating a larger acceleration.

This is because the acceleration of the cart is directly proportional to the force applied to the cart.

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