at what temperature does a process with [delta]h = 30. kj and [delta]s = 900. j become spontaneous?

Radiation is energy that comes from a source and travels through space at the speed of light. This energy has an electric field and a magnetic field associated with it, and has wave-like properties. You could also call radiation “electromagnetic waves”.

cdc

The answer was 0.33

Explanation: Edge 2021

'datboyjon' answered it before. THX♡

The acceleration of the car with two (2) washers added is equal to 0.33 \(m/s^2\).

Given the following data:

An acceleration can be defined as the rate of change of velocity of an object with respect to time and it is measured in meter per seconds square.

In Science, the average acceleration of an object is calculated by subtracting its initial velocity from the final velocity and dividing by the change in time for the given interval.

Mathematically, average acceleration is given by this formula:

\(a = \frac{V\;-\;U}{t_f-t_i}\)

Where:  

Substituting the given parameters into the formula, we have;

\(a = \frac{0.36\;-\;0.13}{2.61\;-\;1.92}\\\\a=\frac{0.23}{0.69}\)

a = 0.33 \(m/s^2\)

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Answer:

During a solar flare a electrical power will be generated on earth

Answer:

the aurora borealis will be seen in the night sky

Explanation:

I think so..

Answer: \(-\frac{1}{2}\times \frac{d[Br^.]}{dt}=+\frac{d[Br_2]}{dt}\)

Explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

\(2Br^.\rightarrow Br_2\)

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

\(Rate=-\frac{d[Br^.]}{2dt}\)

or \(Rate=+\frac{d[Br_2]}{dt}\)

Thus \(-\frac{d[Br^.]}{2dt}=+\frac{d[Br_2]}{dt}\)

Answer:

Many forms of energy are carried in heat, light, sound, and water waves. Energy is defined as the ability to do work; all forms of energy can be transformed into work. ... Ocean waves offer a very large source of renewable energy. ... 4.18 A). When deep-water waves move into shallow water, they change into breaking waves

Explanation:

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The similarities in the atmospheric compositions of Mars and Venus can be explained by their proximity to the Sun, which is the main source of energy for both planets.

Energy is the capacity to do work. It is a fundamental physical property of objects and is the ability to cause change. Energy exists in many forms, such as kinetic, potential, thermal, electrical, chemical, nuclear and gravitational. All these forms of energy can be transformed from one form to another.

The Sun's radiation is strong enough to drive the same type of chemical reactions on both planets that produce the same type of atmospheres. This is despite the fact that Mars is much farther from the Sun than Venus, and Venus is much larger than Mars. The fact that their atmospheres have the same composition can be attributed to their shared proximity to the Sun and the intense ultraviolet radiation it produces.

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Hi there!

Recall the equation for momentum:

\(\large\boxed{p = mv}\\\)

p = momentum (kgm/s)

m = mass (kg)

v = velocity (m/s)

We can plug in the given values to solve for velocity:

\(-450 = 35v\\\\v = \frac{-450}{35} = \boxed{12.86 m/s}\)

In a loop traverse the sum of the interior angles should be equal to 12, if it has 8 stations.

Traverse Surveying is a popular surveying method.

Surveying is basically of two types:

The errors in the surveying can be found out by angles induced in transverse.

The sum of the measured internal angles should be equal to (2N-4), where N=number of sides of the traverse.

Number of stations = N = 8

Sum of the interior angles = (2N - 4)

Sum = (2*8 - 4)

Sum = 12

The sum of the interior angles should be equal to 12.

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A. The average drift speed of the electrons in the wire is  1.19 x \(10^{-3}\)cm/s.

B. The time it would take an electron to travel 8.84 m is 7.43 x \(10^{5}\)sec

(A) To find the average drift speed of electrons in a wire, we can use the equation:

I = nAvq

Where:
I is the current in Amperes
n is the electron density in electrons per \(cm^{3}\)
A is the cross-sectional area of the wire in \(cm^{2}\)
v is the average drift velocity of electrons in cm/s
q is the charge of an electron, which is 1.6 x \(10^{-19}\) Coulombs

First, we need to find the cross-sectional area of the wire. The formula for the area of a circle is:

A = π\(r^{2}\)

Where:
A is the area of the circle
r is the radius of the circle

Given that the wire diameter is 1.63 mm, we can find the radius by dividing it by 2:

r = 1.63 mm / 2 = 0.815 mm = 0.0815 cm

Now, we can calculate the area:

A = \(π(0.0815 cm)^{2}\) = 0.0209 \(cm^{2}\)

Next, we can rearrange the equation to solve for v:

v = I / (nAq)

Given that the current is 20 A and the electron density is 8.47 x \(10^{24}\)electrons per \(cm^{3}\), we can substitute these values into the equation:

v = 20 A / (8.47 x \(10^{24}\) electrons per cm^3 * 0.0209 cm^2 * 1.6 x \(10^{-19}\) C)

Simplifying the expression:

v = 1.19 x \(10^{-3}\) cm/s

Therefore, the average drift speed of electrons in the 14 gauge wire carrying a maximum current of 20 A is approximately 1.19 x \(10^{-3}\) cm/s.

(B) To calculate the time it would take for an electron to travel a distance of 8.84 m, we can use the formula:

t = d / v

Where:
t is the time in seconds
d is the distance in meters
v is the average drift velocity of electrons in meters per second

Given that the distance is 8.84 m and the average drift velocity is 1.19 x 10^-3 cm/s, we need to convert the velocity to meters per second:

v = 1.19 x \(10^{-3}\) cm/s * 0.01 m/cm = 1.19 x \(10^{-5}\) m/s

Now, we can substitute the values into the formula:

t = 8.84 m / 1.19 x \(10^{-5}\)m/s

Simplifying the expression:

t = 7.43 x \(10^{5}\)s

Therefore, it would take approximately 7.43 x \(10^{5}\) seconds for an electron to travel a distance of 8.84 m.

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R(F) = 4F - 160

a. R¹(P) represents the temperature at which a cricket chirps at a rate of P chirps per minute.

b. R(60) refers to the chirping rate of the cricket when the temperature is 60 degrees Fahrenheit, while R¹(60) represents the temperature at which the cricket chirps at a rate of 60 chirps per minute.

The equation R(F) = 4F - 160 represents the relationship between the temperature of the cricket's environment (F) and its chirping rate (R). By plugging in different temperature values, we can determine the corresponding chirping rate.

For example, when we calculate R(60), we find the chirping rate at 60 degrees Fahrenheit.

In this case, R(60) = 4(60) - 160 = 240 - 160 = 80 chirps per minute.

On the other hand, when we calculate R¹(60), we are looking for the temperature at which the cricket chirps at a rate of 60 chirps per minute. Solving the equation 60 = 4F - 160, we find F = 70 degrees Fahrenheit. Therefore, R¹(60) = 70.

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Answer:

A, B, C, D

Explanation:

Yes, i know it is abcd, but it is correct

Answer:

average speed - b

speed - d

acceleration- c

Instantaneous speed- a

Explanation:

I think I dont really remember

The umbilical region in both humans and dogs is on the surface.

1. The umbilical region refers to the area around the umbilicus or navel.

2. In humans, the umbilical region is located on the surface of the abdomen, specifically in the central region between the lower part of the rib cage and the pubic area.

3. The umbilical region is easily identifiable in humans as the area where the umbilical cord was attached during fetal development.

4. Similarly, in dogs, the umbilical region is also on the surface and can be found in the same location as in humans, between the lower rib cage and the pubic area.

5. Dogs, like humans, have an umbilical cord during their fetal development, which connects to the placenta for nutrient and oxygen exchange.

6. The umbilical region in both humans and dogs is an important anatomical reference point for medical examinations and procedures.

7. The surface location of the umbilical region allows for easy access and assessment of the area.

8. Therefore, in both humans and dogs, the umbilical region is situated on the surface.

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Answer:

The electric field at a point midway between the two charges is 2 x 10⁹ N/C.

Explanation:

Given;

first point charge, Q₁ = 3.0 C

second point charge, Q₂ = 5.0 C

distance between the two point charges, R = 6.0 m

The mid-point between the two charges, r = R/2 = 3.0 m

3.0 C <-------------------->3.0m<----------------------->5.0 C

The forces are acting in opposite direction, the electric field strength of each charge is calculated as;

\(E_1 = \frac{kQ_1}{r^2} (-\bar x)\\\\E_1 = \frac{9\times 10^9 \times 3}{3^2}(-\bar x)\)

\(E_2 = \frac{kQ_1}{r^2} (+\bar x)\\\\E_2 = \frac{9\times 10^9 \times 5}{3^2} (+\bar x)\\\\\)

The net electric field is calculated as;

\(E_{net} = \frac{9\times 10^9 \times 5}{3^2} \ - \ \frac{9\times 10^9 \times 3}{3^2}\\\\E_{net} = \frac{9\times 10^9 }{3^2} (5-3)\\\\E_{net} = 2 \times 10^9 \ N/C\)

Therefore, the electric field at a point midway between the two charges is 2 x 10⁹ N/C.

Answer:

V = ω A sin ω t       can be used to describe SHM

When sin ω t = 1 (the maximum value possible)

V = ω A          at equilibrium sin ω t = 1

Answer:

An acid is a compound that increases hydrogen ions (H+) when it is dissolved in a solution.

all I got

Given that an athlete leaves one end of a pool of length at and arrives at the other end at time . She swims back and arrives at the starting position at time . If she is swimming initially in the positive direction, we need to find her average velocities symbolically in positive and negative direction.

The formula for average velocity is: Average velocity = displacement/time taken We know that the displacement is zero because the athlete returns to the starting point. Hence, the average velocity is zero in both the positive and negative directions. Mathematically, we can write it as: v _avg = 0 (in both directions)Therefore, the average velocities symbolically in both the positive and negative directions are zero.

an athlete leaves one end of a pool of length at and arrives at the other end at time . she swims back and arrives at the starting position at time . if she is swimming initially in the positive direction, determine her average velocities symbolically in the average velocities symbolically in both the positive and negative directions are zero. If she is swimming initially in the positive direction, we need to find her average velocities symbolically in positive and negative direction.

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\(\mathrm {Hey, there!}\)

Let's solve your problem:

We will convert your number, 212°F, to Kelvin and Celsius.

212°F is equal to 100° Celsius.

Now, let's do the Kelvin convert.

To convert Celsius to Kelvin, we have to add 273.5 to the amount of Celsius.

100° + 273.5 = 373.5

We have all our conversions. Finally, let's set them out.

Fahrenheit: 212°F

Celsius: 100°C

Kelvin: 373.5°K

Work= Distance × Force

15 metre × 20 N

300 Joule

Now ,

Power,

2 seconds = 300/2

150 watt

We know that

Unit of Work is Joule

Unit of Power is watt

So,

Work - 300 joule

Power= 150 watt

The term you are looking for is "chemical battery". Chemical batteries work by converting chemical energy into electrical energy through a series of chemical reactions. These reactions take place within the battery's cells, which are composed of two electrodes and an electrolyte.

When the battery is connected to a circuit, the chemical reactions produce an electrical current that can be used to power devices. Chemical batteries are widely used in many applications, including consumer electronics, electric vehicles, and renewable energy systems. They are a crucial component of our modern technological society, and ongoing research is focused on developing more efficient and sustainable battery technologies to meet growing energy demands.

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This set of questions focuses on understanding various properties of waves, including their relationship with speed, frequency, wavelength, and amplitude, as well as how changes in these properties impact the energy of waves.

Waves are a type of energy that can travel through different media, such as air, water, or solids. The properties of waves, including their speed, frequency, wavelength, amplitude, and energy, are interrelated and can be described using various mathematical formulas and proportional relationships.

For example, the speed of a wave (v) can be calculated by multiplying its wavelength (λ) by its frequency (f), which is expressed as v=λf.

This formula shows that waves with longer wavelengths or lower frequencies will travel slower than those with shorter wavelengths or higher frequencies.

Another important property of waves is amplitude, which refers to the maximum displacement of the wave from its rest position.

Changes in amplitude can impact the energy of waves, with larger amplitudes resulting in greater energy.

In order to measure the wavelength of a longitudinal wave, such as a sound wave, one can use a device called an oscilloscope to graph the wave's pressure changes over time.

The wavelength can then be determined by measuring the distance between two points on the graph that correspond to one complete cycle of the wave.

Overall, understanding the properties of waves and how they are interrelated can help us better analyze and predict the behavior of these important forms of energy.

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We have found the magnitude of the magnetic field in the separator, the current of the desired ions in the machine, and the thermal energy produced in the cup in 1.31 hours.

(a) To find the magnitude of the magnetic field in the separator, we can use the centripetal force equation. The centripetal force is equal to the magnetic force acting on the ions.

The centripetal force is given by F = mv²/r, where m is the mass of the ions, v is the velocity of the ions, and r is the radius of the path.

The magnetic force is given by F = qvB, where q is the charge of the ions, v is the velocity of the ions, and B is the magnetic field.

Setting the two forces equal to each other and solving for B, we get:

mv²/r = qvB
B = mv/rq

Substituting the given values, we have:

m = 3.92 x 10⁻²⁵ kg
v = √(2qV/m), where V is the potential difference and q is the charge
r = 1.31 m
q = 3.20 x 10⁻¹⁹ C

Using these values, we can calculate the magnetic field magnitude in the separator.

(b) To calculate the current of the desired ions in the machine, we need to find the number of ions passing through the slit per second.

First, we need to find the velocity of the ions using the kinetic energy equation: KE = 1/2 mv². Rearranging the equation, we get v = √(2KE/m), where KE is the kinetic energy.

Given that 1.12 mg of material is separated per hour, we can convert it to kg/s: 1.12 mg/s = 1.12 x 10⁻⁶ kg/s.

Using the kinetic energy equation and the mass, we can find the velocity.

Finally, the current is given by I = nqv, where n is the number of ions per second passing through the slit.

(c) To find the thermal energy produced in the cup, we can use the formula E = mcΔT, where E is the thermal energy, m is the mass of the material collected, c is the specific heat capacity, and ΔT is the change in temperature.

Given that the time is 1.31 hours and the mass is 1.12 mg, we can convert the mass to kg and calculate the thermal energy.

we have found the magnitude of the magnetic field in the separator, the current of the desired ions in the machine, and the thermal energy produced in the cup in 1.31 hours.

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Answer:

Roughly 4.5 billion years

Part A :The position of the particle in vector form is given by\(r⃗ (t)=R[cos(ωt)i^+sin(ωt)j^]\)where R is the radius of the circle and ω is the angular velocity.The velocity of the particle is given by taking the derivative of the position vector with respect to time.

Taking derivative with respect to time on both side we get \(v⃗ (t)=d/dt R[cos(ωt)i^+sin(ωt)j^]= R[-in(ωt)ωi^+cos(ωt)ωj^]=ωR[-sin(ωt)i^+cos(ωt)j^]v⃗ (t)=ωR[-sin(ωt)i^+cos(ωt)j^]\)Thus the velocity of the mass at a time t is given by \(v⃗ (t)=ωR[-sin(ωt)i^+cos(ωt)j^]\).

Part B :

We have to find the velocity at time -t. The velocity of the particle is given by taking the derivative of the position vector with respect to time. Thus the velocity of the mass at a time -t is given by \(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)

\(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)Part C :

The average acceleration of the particle can be computed using the formulaa = \(Δv/Δt\)The velocity at time t is given by\(v⃗ (t) = ωR[-sin(ωt)i^+cos(ωt)j^]\)

The velocity at time -t is given by \(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)

\(v⃗ (-t) = ωR[sin(ωt)i^ - cos(ωt)j^]\)The change in velocity over the interval from -t to t is therefore

\(Δv = v(t) - v(-t) = 2ωR[sin(ωt)i^ + cos(ωt)j^]\)

The time interval over which this change occurs is\(Δt = 2t\)Thus the average acceleration of the particle is given by a = \(Δv/Δt = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\)

\(a = Δv/Δt = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\)

The acceleration can be expressed in terms of R, ω, t, and the unit vectors \(i^ and j^\) as \(a = ω^2R[sin(ωt)i^ + cos(ωt)j^]/t\).

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The planetary body with the fastest orbit is Mercury, and the one with the slowest orbit is Neptune.

There is a general pattern between orbital velocity and orbital radius known as Kepler's second law of planetary motion. According to this law, a planet sweeps out equal areas in equal times as it orbits the Sun. This implies that planets closer to the Sun have smaller orbital radii and must travel faster to cover the same area in the same amount of time.

The relationship between orbital velocity and orbital radius can be expressed as v ∝ 1/r, where v represents the orbital velocity and r denotes the orbital radius. This relationship shows that as the orbital radius increases, the orbital velocity decreases. In other words, planets farther from the Sun have slower orbital velocities compared to those closer to the Sun.

This pattern is consistent with observations in our solar system. The inner planets, such as Mercury, have smaller orbital radii and faster orbital velocities, while the outer planets, like Neptune, have larger orbital radii and slower orbital velocities.

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a) Answer: On the equator, the Circle of Illumination divides the earth into two equal parts, with each part receiving 12 hours of daylight and 12 hours of darkness.

The equator receives an equal day and night (12 hours each) regardless of the day of the year due to the Circle of Illumination, which is a line that separates the day side of the earth from the night side of the earth. The Circle of Illumination separates the sunlit and dark sides of the earth. The earth's axis is at a 23.5-degree angle to the plane of its orbit around the sun, causing different latitudes to receive different amounts of sunlight throughout the year. On the equator, the Circle of Illumination divides the earth into two equal parts, with each part receiving 12 hours of daylight and 12 hours of darkness.

b)  Answer: The earth's axis is tilted at 23.5°, and during the December solstice, the North Pole is tilted away from the sun, causing the Arctic Circle and areas beyond it to experience a full day of daylight because the sun is above the horizon for 24 hours.

On December 22nd, between the latitudes of the Tropic of Cancer (23.5°N) and the Arctic Circle (66.5°N), 24 hours of daylight is experienced. This occurs because the earth's axis is tilted at 23.5°, and during the December solstice, the North Pole is tilted away from the sun, causing the Arctic Circle and areas beyond it to experience a full day of daylight because the sun is above the horizon for 24 hours.

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If I wanted to search for faint rings around a giant planet, the best option to make my observations is e)after the spacecraft passed the planet. So, correct option is e.

Planets having faint rings are:

Saturn -it is considered as the most attractive planet with rings in our Solar System, since they are made up of a very large ring system, which even has different areas and interior systems. Composition of rings are mostly of dust and ice particles.

Uranus-This planet too has a ring system. It is a less colorful system than that of Saturn, but more colorful than that of Jupiter. It is made up of a total of 13 well-defined and structured rings.

Neptune-The last planets in the Solar System  (since Pluto is not considered as the planet because of its extinction) that has a ring system is Neptune. This ring system looks similar to  Jupiter’s, very faint and difficult to identify without taking  help of very special equipment and space telescopes. It is composed mainly of the silicates, ice and some of organic compounds.

Hence, option e is correct.

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(Complete question) is:

If you wanted to search for faint rings around a giant planet by sending a spacecraft on a flyby, it would be best to make your observations.

Choose one:

a. while orbiting the planet.

b. as the spacecraft approached the planet.

c. during the closest flyby.

d. while orbiting one of its moons.

e. after the spacecraft passed the planet.

Gravity, friction, and drag force are the forces that are acted on a car.

Gravity is defined as a force by which one body attracts other objects toward its center. Friction is the force that resists the relative motion of solid surfaces, fluid, and material that are sliding against each other. There are several types of friction force i.e. Dry friction is a type of force that opposes the relative motion of two solid surfaces that are in contact with each other.

Drag is a mechanical force that is generated by the interaction and physical contact of a solid body with a liquid or gas. It is not produced by a field force, gravitational field, or an electromagnetic field, in which one object can affect another object without any physical contact with each other.

So we can conclude that the forces acting on the car are gravity, friction and drag force.

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1. The acceleration of the cyclist is 0.42 m/s²

2. The total distance travelled by the cyclist is 2437.5 m

1. How to determine the acceleration    

We can obtain the acceleration of theration of the cyclist as follow:

a = (v – u) / t

a = (25 – 12.5) / 30

a = 12.5 / 30

a = 0.42 m/s²

Thus, the acceleration is 0.42 m/s²

2. How to determine the total distance

We'll begin by obtaining the distance travelled in the first 30 s. This can be obtained as follow:

s = (u + v)t / 2

s = [(12.5 + 25) × 30] / 2

s = [37.5 × 30] / 2

s = 1125 / 2

s = 562.5 m

Next, we shall determine the distance in the next 60 second.

s = vt

s = 25 × 60

s = 1500 m

Next, we shall determine the distance in the last 15 seconds.

s = (u + v)t / 2

s = [(25 + 0) × 15] / 2

s = [25 × 30] / 2

s = 750 / 2

s = 375 m

Finally, we shall determine the total distance travelled.

Total distance = 562.5 + 1500 + 375

Total distance = 2437.5 m

Thus, the total distance travelled is 2437.5 m

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