b) A stone is dropped from the roof of a four storey building. The height of
each storey is 4.9m . Taking g =9.8m/s2 , calculate the velocity with
which the stone will hit the ground.

Explanation:

distance is how far they have actually driven. so just add up the distances:

59+97=156km

displacement is how far they are from their starting point. so they drive 59 kilometers east, then 97 kilometers west. so we subtract:

97-59=38km west of Olds

The distance travelled by the family was 156 km.

The displacement of the family is 38 km.

To find the distance and displacement, the given values are 59 km and 97 km.

           Distance of the family is how far they have actually driven . So, we just want to add up the distances.

Adding the given distances,

                        59+97=156km.

Thus, 156 km is the distance travelled by the family.

       Displacement of the family is how far they are from their starting point. so they started driving 59 kilometer east and then 97 kilometers west. We have to subtract the given distances.

Subtracting the given distances,          

                          97-59=38km west of Olds.

Thus, 38 km is the displacement of the family.

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Atoms held together through shared electrons.

A molecule is composed of atoms. Atoms are the smallest particles of a substance which can take part in a chemical reaction. Atoms are composed of electrons and the electrons in the outermost shell of atoms help bond atoms together in a molecule.

Hence, atoms are held together in molecules by electrons so they are held together through shared electrons.

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Answer:

43.3 m/s.

Explanation:

Assuming the potential energy is due to the gravitational potential energy, we can use the conservation of energy to find the kinetic energy:

Total energy = Potential energy + Kinetic energy

Kinetic energy = Total energy - Potential energy

Kinetic energy = 300 J - 40 J = 260 J

However, we need to know the mass of the object to convert the kinetic energy to velocity. We can use the potential energy to find the mass:

Potential energy = mgh

40 J = m(9.81 m/s^2)(300 m)

m = 0.137 kg

Now we can use the kinetic energy to find the velocity:

Kinetic energy = (1/2)mv^2

260 J = (1/2)(0.137 kg)v^2

v^2 = (2*260 J) / 0.137 kg

v = 43.3 m/s (rounded to one decimal place)

Therefore, the kinetic energy is 260 J and the velocity of the object when it reaches the ground is 43.3 m/s.

c.

Explanation:!(*´∇`)ﾉ

Buoyancy force can be calculated with the equation

\(Fb = Vs × D × g\)

where

In this case, the weight of the ball is 5 kg and the density of the ball is 2× 10⁴kg/m³

Therefore the volume is given as

\(v = \frac{m}{d} = \frac{5}{2 \times 10 {}^{4} kgm {}^{ - 3} } \\ v = \: \frac{5}{20000} m {}^{ - 3} \)

Substituting the given values in the equation, we get,

\(Fb=Vs \times D \times g \\ Fb = \frac{5}{20000} m {}^{3} \times 5000kgm {}^{ -3} \\ \times10ms {}^{ - 2} \\ = 12.5N\)

Answer:

a. hydrogen sulfide.

Answer:

Explanation:

Swimming. When you go swimming, your body floats but somewhat sinks as well because we weigh less when we're in the water. We are less dense.

Or taking a bath, the soap sinks to the bottom and the washcloth somewhat floats and sinks because of the air trapped in the middle. But the rest of the washcloth is sinking because it's absorbed the water which makes it denser.

Brainliest??

The work done to stretch the spring 2.0 cm from its equilibrium position is 0.16 J.

To calculate the amount of work required to stretch a spring 2.0 cm from its equilibrium position, you can use the formula for work done on a spring:

W = (1/2) * k * x^2

where W is the work done, k is the spring constant, and x is the displacement of the spring from its equilibrium position.

In this case, the spring constant is 40 N/m, and the displacement is 2.0 cm = 0.02 m. So,

W = (1/2) * 40 N/m * (0.02 m)^2

The work done to stretch the spring 2.0 cm from its equilibrium position is 0.16 J.

It is important to note that this formula assumes that the spring is ideal and follows Hooke's law, which states that the force exerted by a spring is proportional to its displacement. In reality, springs may deviate from this law and may not be ideal, so the actual work done may be different from the calculated value. Additionally, this calculation assumes that the spring is stretched in a linear fashion, and that the displacement is small compared to the total length of the spring.

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Answer:

If I did my calculations correctly then the answer is 11 but I may be weong

Answer:

it's 11

gkccgkxcgikvxxkg

A student pulls a box of books on a smooth horizontal floor with acceleration of the box will be 1.99 m/s.

When we apply a horizontal force on a body kept on horizontal floor, a horizontal force starts opposing the net applied force. This force is called frictional force and is always tangential to the contact surface.

We can also find the normal force on the horizontal surface using the coefficient of friction. The basic formula of friction is f =mu N; from this, we get N = f/mu. mu is the coefficient of friction which tells the measure of friction acting between the surface.

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Answer:

power

Explanation:

google

Answer: A. 50 km/h

Explanation:

3 * 10 = 30

5 * 10 = 50

A  minimum coating thickness of 10.35 cm would be required to render an aircraft invisible to a radar operating at 725 MHz.

In order to determine the minimum thickness of coating required to render an aircraft invisible to a radar operating at 725 MHz, we first need to know the wavelength of the radar signal. The wavelength can be calculated using the formula:

wavelength = speed of light / frequency

The speed of light is approximately 3 x 10^8 meters per second. Converting the frequency of 725 MHz to meters, we get:

wavelength = 3 x 10^8 / (725 x 10^6) = 0.4138 meters

Now, in order to render the aircraft invisible to this radar band, we need the coating thickness to be at least one-quarter of the wavelength. Therefore, the minimum thickness of the coating required would be:

minimum coating thickness = 0.4138 meters / 4 = 0.1035 meters

Converting the thickness to centimeters:

minimum coating thickness = 10.35 cm

Therefore, a minimum coating thickness of 10.35 cm would be required to render an aircraft invisible to a radar operating at 725 MHz.

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Vernier calipers have a resolution of 1/10 of an inch.

To determine the diameter of circular objects, a vernier caliper is typically employed. The vernier caliper's elongated jaws can precisely measure the circumference of rounded objects.

A vernier caliper has two scales: a moving vernier scale in addition to the primary, fixed scale. The primary scale displays millimeter readings.

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If wind is blowing at 20 miles per hour in the direction N30W (30 degrees left of y axis), the express for velocity as a vector v in terms of i and j is  v = v = -10 i + 10√3 j

In this figure it seen that,

v(x) = v sin30 = v/2

v(y) = v cos30 =√3/2 v

where v is velocity of the wind which is 20 miles per hr.

v(x) = 20× sin30 = 20/2 = 10

v(y) = 20× cos30 =√3/2×20 = 10√3

in the vector form it ca be written as,

v = -10 i + 10√3 j

there is negative sign cause it is on negative x axis.

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a) The free body diagram of the ball attached.

b) The surface of the rump pushes the ball is mg ( cos35° + tan35° sin35°)

c) The tension on the wire is mg tan35°.

A free body diagram is a graphical representation used to show the applied forces, moments, and consequent reactions on a body. It shows a body or group of connected bodies along with all the applied forces and reactions that the body experiences.

According to the FBD,

mg sin35° = T cos 35°

T = mg tan35°.

And, N = mg cos 35° + T sin35° = mg ( cos35° + tan35° sin35°)

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Answer:

C)  Total displacement = 1275 m or 1.275 km

Explanation:

We'll break this into two parts:  

1) Displacement during constant speed, and

2) Displacement during the acceleration phase.

Constant Speed

The displacement for this segment is already stated:  1 km.  But the information includes the time, which will allow us to calculate the speed of travel.  We'll need this for the next phase of acceleration.

Distance = Speed x Time

Speed = Distance/Time

Time = 1 minute + 20 sec, or 80 sec.

Speed = 1 km/80 sec

Speed = 0.0125 km/sec

Since we'll be using meters (not km) in the next step, convert 0.0125 km/sec to m/sec with a conversion factor:  

  (0.0125 km/sec)*(1000m/1 km) = 12.5 m/sec

Acceleration Phase

The obect is moving at a speed of 12.5 m/sec (from above) and then accelerates at a rate of 0.125 m/sec^2 for 20 seconds.

The distance (s) an object travels during this acceleration (a) is gven by:

  s = vi*t + (1/2)a*t^2,

where vi is the initial velocity (12.5 m/sec in this case), a is the acceleration (0.125 m/sec^2), and t is the time (20 seconds).

s = (12.5 m/sec)(20 sec) + (1/2)(0.125 m/sec^2)*(20 sec)^2

s = 275 meters

Now add the two distances:

1) Constant Speed Phase = 1000 m

2)  Acceleration Phase    =  275 m

Total displacement = 1275 m or 1.275 km

The value of a^2 is 3600 if Starting from rest, a particle moves along an axis from point A to point B with constant acceleration a = 2.20 m/2 through displacement d = 500 m.

To determine the value of a^2, we need to use the relationship between acceleration, displacement, and time, which is given by the equation:

\(d = 1/2 a t^2\)

First, we can find the time t1 required for the particle to travel from point A to point B by using the equation:

\(d = 1/2 a t1^2\)

Substituting the given values, we get:

\(500 = 1/2 (a) (t1)^2\)

Rearranging and solving for t1:

\(t1 = \sqrt{} (500 / (1/2 a)) = \sqrt{} (1000 / a)\)

Next, we can find the time t2 required for the particle to travel from point B to point C by using the equation:

\(dz = 1/2 a t2^2\)

Substituting the given values, we get:

\(300 = 1/2 (a) (t2)^2\)

Rearranging and solving for t2:

\(t2 =\sqrt{} (300 / (1/2 a)) = \sqrt{} (600 / a)\)

Finally, we can use the total time t to find the value of a by using the equation:

t = t1 + t2

Substituting the values of t1 and t2, we get:

60 = sqrt(1000 / a) + sqrt(600 / a)

Squaring both sides, we get:

\(3600 = 1000 / a + 600 / a + 2 sqrt(1000 * 600) / a\)

Rearranging and solving for a:

\(a = sqrt(3600 * a / (1000 + 600)) = sqrt(3600 * a / 1600)\)

Squaring both sides again, we get:

\(a^2 = 3600 / (1600 / a) = 3600 * a / 1600\)

Rearranging and solving for a^2:

\(a^2 = 3600^2 / 1600 = (60^2)^2 / (40^2) = 3600.\)

So, the value of a^2 is 3600.

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Answer:

155 118 in

Explanation:

3.94 km *  1000 m / km  *  39.37 in / m = 155 118 in

The correct statement regarding the work and impulse required to move a box on the floor from 2v to 3v and from 3v to 4v is Case i requires less work, but i and ii require the same amount of impulse.

W = ΔKE

W = Work done

ΔKE = Change in Kinetic energy

ΔKE = 1 / 2 m ( v2 - v1 )²

J = m Δv

J = Impulse

m = Mass

Δv = Change in velocity

For ( i ),

W = 1 / 2 m ( ( 3 v )² - ( 2 v )² )

W = 1 / 2 m ( 9 v² - 4 v² )

W = 2.5 m v²

J = m ( 3 v - 2 v )

J = m v

For ( ii ),

W = 1 / 2 m ( ( 4 v )² - ( 3 v )² )

W = 1 / 2 m ( 16 v² - 9 v² )

W = 3.5 m v²

J = m ( 4 v - 3 v )

J = m v

Therefore,

i ) W1 < W2

ii ) J1 = J2

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Complete Question:

What is the power in a circuit that has a current of 12 amps and a resistance of 100 ohms?

Answer:

D. 14,400 watts

Explanation:

The electrical power of an electric circuit can be defined as a measure of the rate at which energy is either produced or absorbed in the circuit.

Mathematically, electrical power is given by the formula;

\( Electrical \; power = current * voltage \)

This ultimately implies that, the quantity (current times voltage ) is electrical power and it is measured (S.I units) in Watt (W).

Given the following data;

To find the power in the circuit, we would use the following formula;

Power = I²R

Where;

Power = 12² * 100

Power = 144 * 100

Power = 144,000 Watts

The image of the truck formed by the rear-view mirror is smaller and virtual, located in front of the mirror.

To calculate the size of the image relative to the size of the truck formed by the rear-view mirror, we can use the mirror equation:1/f = 1/u + 1/v,

where f is the focal length (radius of curvature) of the mirror, u is the object distance, and v is the image distance.

Given that the radius of curvature of the mirror is 4m and the truck is located 5m from the mirror, we can determine the object distance:

u = -5m (since the object is behind the mirror and its distance is negative)

Substituting these values into the mirror equation, we get:

1/4 = 1/(-5) + 1/v

Simplifying the equation:

1/v = 1/4 + 1/5

1/v = (5 + 4) / (4 * 5)

1/v = 9/20

v = 20/9

Now, we can calculate the size of the image relative to the size of the truck using the magnification formula:

magnification = -v/u

Substituting the values:

magnification = -(20/9) / (-5)

magnification = 4/9

Therefore, the size of the image relative to the size of the truck is 4/9. This means the image formed by the rear-view mirror is smaller than the actual truck.

As for the position and nature of the image, since the image distance (v) is positive, the image is formed on the same side of the mirror as the object. In this case, it means the image is formed in front of the rear-view mirror. The positive image distance also indicates that the image is virtual.

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Answer:

b) bend away from the normal

Explanation:

According to snell's law , if i be the angle of incidence and r be the angle of refraction

sin i / sin r = 1.33 / 2.42

sin i / sin r = .55

Hence sin r > sin i

r > i

In other words angle of refraction will be more than angle of incidence . So, the ray will bend away from the normal .

When the panels are in the shadow, the power emitted from each panel is 4462.0927 W, therefore the absorbed radiation is insignificant.

Power is defined in physics as the quantity of energy transported or transformed per unit time. The watt is the unit of power in the International System of Units, equivalent to one joule per second. Power is also referred to as activity in ancient writings. A scalar quantity is power. Power may be defined as the pace at which work is completed in a given amount of time. Watt (W) is the SI unit of power, which is joules per second (J/s). Horsepower (hp), which is approximately equivalent to 745.7 watts, is sometimes used to describe the power of motor vehicles and other machinery.

Here,

Emissivity of the panel = 1

Stefan-Boltzmann constant = 5.67*10⁻⁸ W/m²K⁴

Temperature = (273.15+6)

Area of the panel is given by,

A=2*1.8*3.6

A=12.96 m²

The power radiated is given by,

P=εσAT⁴

P=1*5.67*12.96*(273.15+6)*10⁻⁸

P=4462.0927 W

The power radiated from each panel is 4462.0927 W when the panels are in the shade so that the absorbed radiation will be negligible.

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784 N is Zach's weight before the elevator starts braking.

The acceleration acting on the Zach before the elevator starts braking is the only acceleration due to gravity.

W= m g

Where

m is the mass of an object.

g is the acceleration due to gravity.

m= Zach’s mass = 80 kg and g= 9.80 m/s²

Thus,

W= 80 x 9.80

= 784 Newton. (N)

The parameter that demonstrates how heavy an object is is its weight. The weight of an object can be determined by multiplying its mass by the gravitational acceleration.

Therefore, Zach’s apparent weight before the elevator starts braking is 784 N.

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Complete question:

Zach, whose mass is 80 kg, is in an elevator descending at 10 m/s. The elevator takes 3.0 s to brake to a stop on the first floor.

a. What is Zach’s weight before the elevator starts braking?

Answer:

i think its  c

Explanation:

Answer:

So that the researchers know how much of the result is a trick of your mind and how much of the result is real.

Explanation:

So first, in order to answer this question we need to know what a placebo is.

Placebo: any treatment that has no active properties, like a sugar pill.

Now we ask ourselves, how could a placebo be something of interest in human studies?

Our brains are amazing things and can connivence themselves many things.  Hints the phrase "placebo effect" that is very common in the medical field.

The placebo effect (a positive effect produced by a placebo drug or treatment, which cannot be attributed to the properties of the placebo itself, and must therefore be due to the patient's belief in that treatment) is a really good example as to why they are useful in human studies.

How else could you know was a true effect or just something someone believed would happen anyway?

The resistance of a wire with a 0.0298-inch diameter and the same length and substance is 0.0460 ohm. The amount of electric current carried by a specific length of wire's diameter.

A circuit's opposition to electric current flow is measured by its resistance. The Greek letter omega () stands for ohms, which are used to measure resistance. The movement of charges through a conductor is the typical description of electric current. It is the quantity of charge that passes via a conductor's cross-section. The pace at which charges flow through a conductor is another way to define the term "current"

Given that the ratio of resistance to square of the diameter

Given resistance is inversely proportional to square s dimeter

R is directly proportional (1/D^2)

R1/R2 = (D2/D1)^2

R1 =0.381 ohm

R2 = ?

D1=0.01 inches

D2=0.0298 inches

R2 = R1(D1/D2)^2

R2 = 0.409(0.01/0.0298)^2

Resistance of the wire = 0.0460 ohm

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