(b) By what value did region 2 attenuate the E field? Show that for 2 interfacing media (a conductor and a dielectric), the tangential component of the magnetic field, H₁, is equal to the surface current density, Js, on the conductor.​

The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.

Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.

Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.

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As the  runner runs the 100-m dash in 8.2 s, the average speed of the runner is 12.20 meter/second.

The speed of an object, also known as v in kinematics, is the size of the change in that object's position over time or the size of the change in that object's position per unit of time, making it a scalar quantity.

The distance travelled by an object in a time interval is divided by the length of the interval to determine its average speed.

As the  runner runs the 100-m dash in 8.2 s, the average speed of the runner is = (100 ÷ 8.2) meter/second

= 12.20 meter/second.

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Answer:

The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

Explanation:

We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.

Now, the acceleration due to gravity is defined through the following equation:

\(mg = GMm/R^2\)

where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.

Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get

g = 0.0123 m/s^2.

Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

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Answer:

Momentum

Explanation:

In order for an object's momentum to change,a force must be applied for a period of time

Answer:

i think A

Explanation:

The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

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The external structure of a solid  refers to the overall structure of the solid due to the arrangement of its particles..

The internal structure of a solid is the the arrangement of unit particles in the internal space of the solid.

A solid is a substance which has a definite shape and volume.

Solids are one of the three states of matter.

The particles in a solid are arrange in regular repeating patterns due to the strong intermolecular forces of attraction between the particles in the solid.

The external structure of a solid refers to the overall structure of the solid due to the arrangement of its particles.

The external structure of a solid may be a crystal or amorphous in shape.

The internal structure of a solid is the the arrangement of unit particles in the internal space of the solid.

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The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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Answer:

from high temperature to low temperature areas

Explanation:

If it is correct, could you please give me brainliest? I would really appreciate it! Thank you!

Answer:

kinetic energy of the train = 2,910.6 x 10⁷ joule

Explanation:

Given:

Mass of train = 3.3 x 10⁷ kg

Speed of train = 42 m/s

Find:

kinetic energy of the train

Computation:

kinetic energy = (1/2)(m)(v²)

kinetic energy of the train = (1/2)(3.3 x 10⁷)(42²)

kinetic energy of the train = (1/2)(3.3 x 10⁷)(1,764)

kinetic energy of the train = (3.3 x 10⁷)(882)

kinetic energy of the train = 2,910.6 x 10⁷ joule

Answer: The initial kinetic energy of the train is \(2910.6 \times 10^{7} J\).

Explanation:

Given: Mass = \(3.3 \times 10^{7} kg\)

Speed = 42 m/s

Kinetic energy is the energy acquired by an object due to its motion.

Formula to calculate kinetic energy is as follows.

\(K.E = \frac{1}{2}mv^{2}\)

where,

m = mass of object

v = speed of object

Substitute the values into above formula as follows.

\(K.E = \frac{1}{2}mv^{2}\\= \frac{1}{2} \times 3.3 \times 10^{7} kg \times (42 m/s)^{2}\\= 2910.6 \times 10^{7} kg m^{2}/s^{2} (1 J = 1 kg m^{2}/s^{2})\\= 2910.6 \times 10^{7} J\)

Thus, we can conclude that the initial kinetic energy of the train is \(2910.6 \times 10^{7} J\).

A typical 16-line poem that described centripetal force can be found below.

In circular motion, a force we call,

Centripetal, it keeps things in thrall.

Directed towards the center of the path,

Without it, objects would face a wrath.

Angular velocity is key,

The rate of change of the angle we see.

And the radius of the circle too,

Both play a role in what we must do.

The mass of the object cannot be ignored,

It factors in with gravity's cord.

As the force pulls towards the center,

Centripetal force is what we enter.

It is the sum of all the forces in play,

Equal to mass times velocity squared, we say.

And if the force is too weak or too strong,

Off the circular path, the object goes wrong.

Thus, centripetal force is what we need,

To keep objects moving at the speed,

In a circular path, they're meant to be,

A force that keeps them in harmony.

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Answer:

Explanation:

momentum of sedan of 1600 kg = 1600x v , where v is its velocity

momentum of suv of 2300 kg = 2300 x u where u is its velocity .

force of friction = ( 1600 + 2300 ) x 9.8 x  .75 ( fiction = μ mg )

= 28665 N

distance by which friction acted = √ (5.54² + 6.19²)

= 8.3 m

work done by friction

= 28665 x 8.3

= 237919.5 J

Total kinetic energy of cars = work done by friction

1/2 x 1600 x v² + 1/2 x 2300 u² = 237919.5

16 v² + 23 u² = 4758.4

1600 x v / 2300 u = 6.19 / 5.54

v / u = 1.6

v = 1.6 u

putting this equation in fist equation

40.96 u² + 23 u² = 4758.4

= 63.96 u² = 4758.4

u² = 74.4

u = 8.62 m /s

v = 13.8  m /s

Answer: Refraction

Explanation:

The observation of a wet spot on a hot highway in the summer season is caused by refraction. Therefore, option (C) is correct.

Refraction can be defined as the redirection of light as it passes from one medium to another medium. The redirection of light is caused by a change in the medium or by the wave's change in speed.

Refraction of light can be described as an observed phenomenon, but other waves such as sound waves and water waves also experience refraction.

Refraction of light obeys Snell's law that the ratio of the sines of the angle of incidence and refraction must be equal to the ratio of phase velocities in the two media to the refractive index of the two media.

When the sunlight makes a blacktop hot highway. The appearance of the wet spot is bright because of the refraction of light from the sky.

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Answer:

12

Explanation:

the numbers are swapped so by conclusionn it is 12

Answer:

+20 e

Explanation:

"Initially, sphere A has charge of -50 e and sphere B has a charge of +20 e. The spheres are made of conducting material and are identical in size."

- textbook

Hope this helps :)

v = s/t

44 m/s = 3.5 m/t

t = 3.5 m : 44 m/s

t = 0.08 s

a = v/t

a = 44 m/s/0.08 s

a = 550 m/s²

a : g = 550 m/s² : 10 m/s²

a : g = 55 : 1

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Answer:

direction of the net electric field will depend on the signs and locations of the charges. If the net electric field is positive, it means the field points away from the charges. If the net electric field is negative, it means the field points towards the charge

Explanation:

E = k * q / r^2

where E is the electric field, k is the electrostatic constant (8.99 x 10^9 N m^2/C^2), q is the charge, and r is the distance from the charge to the point where we want to find the electric field.

Let's calculate the net electric field at the given points:

(a) x = 0 cm:

For the first charge, q1 = +6.27 μC, the distance r1 = 3.00 cm = 0.03 m.

The electric field due to q1 at x = 0 cm is:

E1 = k * q1 / r1^2

For the second charge, q2 = -20.4 μC, the distance r2 = 9.00 cm = 0.09 m.

The electric field due to q2 at x = 0 cm is:

E2 = k * q2 / r2^2

To find the net electric field, we need to add the electric fields vectorially:

E_net = E1 + E2

(b) x = +6.00 cm:

For the first charge, q1 = +6.27 μC, the distance r1 = 6.00 cm = 0.06 m.

The electric field due to q1 at x = +6.00 cm is:

E1 = k * q1 / r1^2

For the second charge, q2 = -20.4 μC, the distance r2 = 6.00 cm = 0.06 m.

The electric field due to q2 at x = +6.00 cm is:

E2 = k * q2 / r2^2

To find the net electric field, we need to add the electric fields vectorially:

E_net = E1 + E2

Answer:

Fuerza, F = 0.001 Newton

Explanation:

Dados los siguientes datos;

Intensidad del campo eléctrico = 5 * 10² N/C

Carga = 2 microculombios = 2 * 10^{-6} culombios

Para encontrar la fuerza que actúa sobre la carga;

Matemáticamente, la intensidad del campo eléctrico viene dada por la fórmula;

Intensidad del campo eléctrico = fuerza/carga

F = E * Q

F = 5 * 10² * 2 * 10^{-6}

Fuerza, F = 0.001 Newton

Answer:

Given that,  

Speed = v  

Radius = r  

We have to ascertain the precise speed  

Utilizing equation of speed  

Where, v = velocity/speed

r = radius  

= precise speed/ angular velocity

Angular Velocity :  

The precise speed is characterized by the speed of turn.  

The precise speed is straightforwardly corresponding to the direct speed and contrarily relative to the range of the molecule.  

Subsequently, The precise speed is v/r

Change in velocity per unit time.

Explanation

Acceleration is defined as rate of change of velocity w.r.t time.

\(\boxed{\sf Acceleration=\dfrac{dv}{dt}}\)

Let the circumference of the circle be 10L.

A moves at 10L/2 = 5L per hour

B moves at 10L/5 = 2L per hour

Therefore it takes 10L/(5L+2L) = 10/7 hours

The magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s

The rotating equivalent of linear momentum in physics is called angular momentum. Because it is a conserved quantity—the total angular momentum of a closed system stays constant—it is significant in physics. Both the direction and the amplitude of angular momentum are preserved.

Given the density of air to be 1.29 kg/m3 and a wind speed of 73.0 mi/h

We have to find the magnitude of the angular momentum

Let,

ρ = Density of air = 1.29 kg/m^3

v = Speed of wind = 73.0 mi/h = 0.032 km/s

M = angular momentum of air

Let the volume of air be 1 m^3

Mass = Volume x ρ = 1 x 1.29 = 1.29 kg

Momentum = M = mass x velocity

Momentum = 1.29 x 0.0032

Momentum = 4.128 x 10^(-3) kg·m^2/s

Hence the magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s

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Answer:

The force of the tires against the road and the force of the road on the tires

Explanation:

right on edge(2021)

A car is moving east along a straight, level road at a constant velocity. The force of the tires against the road and the force of the road on the tires. Thus option A is correct

Force is defined as an outside force that has the power to alter the motion or rest of a body.

It can be defined as a push or pull exerted on an object as a result of the interaction of the object with another object.

It can also be defined as a push or a pull that modifies or tends to modifies an object's uniform motion, state of rest, or modifies the object's direction or shape It either accelerates items or increases their overall pressure.

The joule is the accepted unit of energy in electronics and most other branches of science. The amount of energy expended when a force of one newton is applied across a displacement of one meter is known as a joule.

There are seven types of force.

Thus, a car is moving east along a straight, level road at a constant velocity. The force of the tires against the road and the force of the road on the tires. Thus option A is correct

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1) The displacement is 0 mi. Option A

2) The average speed is 20 mi/hr. Option C

3) The average velocity is 0 mi/hr. option A

We know that when we talk about the speed, we would look at the ratio of the average distance to the average time that is taken and this would span the entire journey not only a section of the journey.

We must note that the displacement is a vector quantity and as such, we have to look at the direction of the motion of the object.

Displacement = 5 miles - 5 miles = 0 miles

Average speed = Total distance/ Time = 5 miles + 5 miles/ 0.5 hr = 20 mi/hr

Average velocity = Displacement/Time = 0 miles// 0.5 hr =  0 mi/hr

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Answer:

The intensity of the sound in W/m² is 1 x 10⁻⁶ W/m².

Explanation:

Given;

intensity of the sound level, dB = 60 dB

The intensity of the sound in W/m² is calculated as;

\(dB = 10 Log[\frac{I}{I_o} ]\\\\\)

where;

I₀ is threshold of hearing = 1 x 10⁻¹² W/m²

I is intensity of the sound in W/m²

Substitute the given values and for I;

\(dB = 10 Log[\frac{I}{I_o} ]\\\\60 = 10 Log[\frac{I}{I_o} ]\\\\6 = Log[\frac{I}{I_o} ]\\\\10^6 = \frac{I}{I_o} \\\\I = 10^6 \ \times \ I_o\\\\I = 10^6 \ \times \ 1^{-12} \ W/m^2 \\\\I = 1\ \times \ 10^{-6} \ W/m^2\)

Therefore, the intensity of the sound in W/m² is 1 x 10⁻⁶ W/m².

Answer:

Mass, m = 6.18 kg

Explanation:

Given the following data;

Frequency, F = 10 Hz

Spring constant, k = 250 N/m

We know that pie, π = 22/7

To find the mass, we would use the following formula;

F = 1/2π√(k/m)

Where;

F is the frequency of oscillation.

k is the spring constant.

m is the mass of the spring.

Substituting into the formula, we have;

10 = 1/2 * 22/7 * √250/m

10 = 22/14 * √250/m

Cross-multiplying, we have;

140 = 22 * √250/m

Dividing both sides by 22, we have;

140/22 = √250/m

6.36 = √250/m

Taking the square of both sides, we have;

6.36² = (√250/m)²

40.45 = 250/m

Cross-multiplying, we have;

40.45m = 250

Mass, m = 250/40.45

Mass, m = 6.18 kg

Answer:

The second independent variable in a 2x4x3 factorial design has 4 levels.

Explanation:

In order to plot each sieve % on the distribution curve, you must divide the entire mass of the sample material by the weight that was either retained or that passed thru every sieve.

As the asymmetric energy sieve method directly provides weight distribution, sieve methodology provides sieve diameter, which is determined as the micrometer of the globe that passes through the sieve aperture. By using the sieve process, particles of sizes between 50 and 1500 m are estimated.

Adaptive mien scattering and laser particulate analyzers are two of the primary categories of particle size analyzers. Particles in solutions are measured by dynamic light diffracted analyzers between 0.6 nm and For particle in a substance that are between 10 nm and 3 mm in size, analyzers are utilized.

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Answer:

-12.1

Explanation:

i’m almost sure this is it, i’m checking my old answers

if not let me know and i’ll give you some more answers