Be(OH)2 is solid why?​

Answer:

Decreases

Explanation:

Fatty acid which have the double bond or triple bond are called unsaturated fatty acids. Because of the double or triple bond, unsaturated fatty acids are loosely packed and form some distance among molecules which lowers the melting point of unsaturated fatty acids.

So, if the unsaturation of fatty acid will increase, it leads to more branched and loosely packed molecules and decreases the melting temperature accordingly.

Perch, frog, pigeon, and other species evolution would not have arisen prior to the derived shared trait of jaws and after the common ancestor.

The development of jaws in the bodies of our ancestors was a critical phase in the evolution of vertebrates, including humans. The earliest jawed vertebrates, called gnathostomes, descended from jawless fish and appeared in the fossil record around 420 million years ago.

Rats and people are both warm-blooded creatures that give birth to live children; both have similar organs, such as hearts and livers; both have comparable neurological systems; both employ comparable hormones to regulate body functions.

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Answer:

This means that one mole of water molecules has a mass of 18.015g.

42.3g * 1 mole H2O/18.015g

= 2.3480 moles H2O

We are using the avogadros number to find the number of molecules of water

2.3480 H2O * 6.022*10^ 23moles/ 1mole of H2O

That's 2.3480 multiplied by 6.022*10^23 divided by 1 mole of H2O

Number of molecules = 1.4140 *10^24 molecules

Answer:

0.181 M

Explanation:

Begin by finding the total moles by using the volume and molarity given:

\(\frac{3.25 mol}{1000 mL} x \frac{25.0 mL}{1} = 0.08125 mol\)

(Remember molarity is mol/L, which is equal to mol/1000 mL.)

Divide the moles by the volume after dilution:

\(\frac{0.08125 mol}{450.0 mL} x \frac{1000 mL}{1 L} = \frac{0.181 mol}{L} = 0.181 M\)

The concentration of the diluted solution is 0.181 M.

Phosphatidylserine is a type of phospholipid that is mainly found in cell membranes. Its structure is made up of two fatty acid chains, a phosphate group, a serine molecule, and a glycerol molecule.

The fatty acid chains are hydrophobic, meaning they repel water, while the phosphate group and serine molecule are hydrophilic, meaning they attract water.

The glycerol molecule acts as a bridge that connects the two fatty acid chains to the phosphate group and serine molecule.
The structure of phosphatidylserine is important for its function in the cell membrane.

Because of the hydrophobic and hydrophilic components of its structure, phosphatidylserine is able to form a lipid bilayer, which is a barrier that separates the inside of the cell from the outside environment.

The hydrophilic heads of the phosphatidylserine molecules face outward and interact with water, while the hydrophobic tails face inward and repel water.
Phosphatidylserine also plays a role in cell signaling and apoptosis, which is programmed cell death.

It acts as a signaling molecule by binding to proteins that are involved in cellular pathways.

In addition, phosphatidylserine is translocated to the outer leaflet of the cell membrane during apoptosis, which signals to immune cells that the cell is ready to be removed.
In conclusion, the structure of phosphatidylserine is made up of two fatty acid chains, a phosphate group, a serine molecule, and a glycerol molecule. Its hydrophobic and hydrophilic components allow it to form a lipid bilayer in cell membranes, and it also plays a role in cell signaling and apoptosis.

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Answer:

False. Energy can only be released when bonds are broken. consider the result when atoms are tron appart.

One mole or 12 g of carbon reacts with one of oxygen molecule weighs 32 g will produce one mole of carbon dioxide. One mole of carbon dioxide weighs 44 g.

Carbon dioxide is an inorganic gas formed by the covalent bonding between carbon and oxygen gas. Carbon dioxide is an essential gas to maintain the living atmosphere in earth.

The balanced chemical equation of the reaction between oxygen gas and carbon is given below:

\(\rm C+O_{2} \rightarrow CO_{2}\)

As per this equation, one mole of carbon reacts with one mole of oxygen gas:

Atomic mass of carbon = 12g

molecular mass of oxygen = 32 g

then molar mass of carbon dioxide = 32+ 12 = 44 h=g.

Therefore, 44 g of carbon dioxide is produced in this reaction.

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Answer:

4.15×10²² atoms of C are contained in 1 g of butane.

Explanation:

Formula for butane is C₄H₁₀

1 mol of butane contains 4 moles of carbon and 10 moles of H

Molecular weight is 58 g/mol

In conclussion we can say that 58 g of butane contain 4 moles of C and 10 moles of H

We prepare the rule of three:

1 g . 4 moles of C / 58g = 0.0689 moles of C

Now we can count the atoms by NA. We know that 6.02×10²³  particles are contained in 1 mol of anything.

0.0689 mol . 6.02×10²³ atoms / 1mol = 4.15×10²²

4.15×10²² atoms of C are contained in 1 g of butane.

When designing a scientific question, you should ensure the question is:

A scientific question is an inquiry that scientists examine via methods such as observation, experimentation or data collection leading to an answer.

They often require specific parameters for setting up experiments along with means for measuring outcomes or phenomenon under investigation while also needing testable results to establish validity. As such successful ones must possess traits like precision in defining boundaries within which observations will take place making them measurable so they may produce documented evidence supporting the validity of their findings

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Answer:

Voltage is the measure of electric potential energy per unit charge, current is the flow of electric charge through a circuit, and resistance is the property of a material that opposes the flow of electric current.

Ohm's Law relates these three concepts by stating that current is directly proportional to voltage and inversely proportional to resistance.

Hope this helps!

Answer:

umm translate

Explanation:

By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers.

By removing the need to build additional transmission lines and equipment, energy storage may reduce costs for utilities and their customers. Energy storage's inherent ability to offer backup power in the event of grid failure is a feature that both residential consumers and commercial owners find highly desirable.

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The balanced chemical equations of the reactions are given below:

1. Mg (s) + 2 H₂O (l) ----> Mg(OH)₂ (s) + H₂ (g)

2. 2 Li (s) +  2 H₂O (l) ----> LiOH (aq) + H₂ (g)

A balanced chemical equation is an equation in which the number of moles of atoms of elements in a given reaction is equal to the sum of the number of moles of atoms of each element that is produced.

A balanced chemical equation is in accordance with the law of conservation of mass which states that matter can neither be created nor destroyed.

When balancing chemical equations, numerical coefficients are added in front of moles of atoms of an element or moles of a given compound taking part in the reaction.

The balanced chemical equation of the reaction of magnesium and water as well as the reaction of lithium and water is given below:

Magnesium and water:

Mg (s) + 2 H₂O (l) ----> Mg(OH)₂ (s) + H₂ (g)

Lithium and water:

2 Li (s) +  2 H₂O (l) ----> LiOH (aq) + H₂ (g)

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The intermolecular force between bromine and benzene is primarily a van der Waals force known as London dispersion forces.

London dispersion forces occur due to temporary fluctuations in electron distribution, creating temporary dipoles in molecules. In the case of bromine and benzene, both molecules are nonpolar, meaning they have no permanent dipole. However, they still experience London dispersion forces.

Benzene is a cyclic aromatic hydrocarbon with a hexagonal ring structure. It consists of delocalized π electrons above and below the plane of the molecule. Bromine is a halogen element with seven valence electrons, which forms diatomic molecules. In the solid or liquid state, bromine molecules exist as Br2.

The London dispersion forces between bromine and benzene arise from the temporary shifts in electron density within their electron clouds. The π electrons in benzene induce temporary dipoles in the bromine molecules, resulting in attractive forces between them. These temporary dipoles continuously form and break due to electron movements, resulting in an overall attractive force between the bromine and benzene molecules.

While London dispersion forces are generally weaker than other intermolecular forces like dipole-dipole interactions or hydrogen bonding, they still contribute to the stability of the system and affect properties such as boiling points and melting points.

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Answer:

metallic bonding

Explanation:

Copper wire consists of Cu nuclei (that are positively charged due to the positively charged protons) that are surrounded by a "sea" of delocalized electrons (that are negatively charged that move freely throughout the material which is known as metallic bonding.

Answer:

Metallic bonding.

Explanation:

Pure copper is neither covalent nor ironic. It is a bonding called metallic bonding.

Answer:

0.430 Litre

Explanation:

The first thing that you need to do here is to convert the mass of lithium bromide to moles by using the compound's molar mass.\(100g \frac{1 moleNaCl}{58.5g} = 1.71 moles of NaCl\)

Now, the molarity of the solution is simply a measure of the number of moles of solute, which in your case is NaCl, present for every 1.00 L of the solution.

In order to have a 4.00-M solution of NaCl, you need to have 4.00 moles of NaCl for every 1.00 L of this solution.

You know that your sample contains 1.71 moles of NaCl, so you can use the molarity of the solution as a conversion factor to determine how many liters of this solution can be made.

\(1.71 mole NaCl \frac{ 1 L Solution}{4 mole NaCl} = 0.43 L solution\).

Answer:

D 4,3,2

Explanation:

4 Co + 3 O2 ----> 2 Co2O3

Answer:

The most abundant chemical/gas is Nitrogen, which makes up about 78% and Oxygen at second place with approximately 21%

Answer:

Nitrogen and Oxygen because about 70% of air is nitrogen and around 20% of air is Oxygen.

Hope this helps!

The balanced redox reaction is

\(3F(e)_3+ + 2N O^{-2} + 4H_2O\)→ \(3F(e)_2+ + 2N O^{-3} + 4H+\)

Let's start balancing the redox reaction. Here is the given redox reaction:

\(3F(e)_3+ + 2N O^{-2} + 4H_2O\) → \(F(e)_2+ + H+ + N O^{-3}\)

Step 1: Separate the redox reaction into two half-reactions.Half-reaction 1: \(F(e)_3+\)→ \(F(e)_2+\) Half-reaction 2: \(N O^{-2}+ H_2O\) → \(N O^{-3}+ H+\)

Step 2: Balance the elements other than H and O in each half-reaction. Balanced Half-reaction 1: \(F(e)_3+\) →\(F(e)_2+\)Balanced Half-reaction 2: \(N O^{-2} + H_2O\) → \(N O^{-3} + H+\)

Step 3: Balance the oxygen atoms by adding H2O to the side that needs oxygen . Balanced Half-reaction 1: \(F(e)_3+\) → \(F(e)_2+\) Balanced Half-reaction 2: \(N O^{-2}+ H_2O\) →\(N O^{-3} + H+ + H_2O\)

Step 4: Balance the hydrogen atoms by adding H+ to the side that needs hydrogen . Balanced Half-reaction 1: \(F(e)_3+\) → \(F(e)_2+\) + e− + H+Balanced Half-reaction 2: \(N O^{-2} + H_2O + H+ - > N O{-3}+ H+ + H_2O + e^-\)

Step 5: Determine the number of electrons required to balance the half-reaction . Balanced Half-reaction 1: \(F(e)_3+ - > F(e)_2+ + e^{-}+ H+\) [3 electrons are required]Balanced Half-reaction 2: \(N O^{2} + H_2O + H+ - > N O^{-3} + H+ + H_2O + e^-\)[2 electrons are required]

Step 6: Multiply the half-reactions by integers to make the number of electrons equal for both half-reactions.Balanced Half-reaction 1:\(3(F(e)_3+ - > F(e)_2+ + e^{-} + H+\) ).Balanced Half-reaction 2: \(2(N O^{-2} + H_2O + H+ - > N O^{-3}+ H+ + H_2O + e^{-})\)

Step 7: Add the balanced half-reactions together\(3F(e)_3+ + 2N O^{-2} + 4H+ - > 3F(e)_2+ + 2N O^{-3} + 2H_2O\) .The balanced redox reaction is:\(3F(e)_3+ + 2N O{-2} + 4H_2O - > 3F(e)_2+ + 2N O^{-3} + 4H+\)

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Answer:

Paraffin Wax

Explanation:

Paraffin wax is one of the most widely used waxes for candle making. A cheaper alternative, it is a derivable from petroleum, coal or oil. This wax is white and odorless and will keep a consistent appearance throughout your candle's life.

Answer:

the compound is bromine trifluoride

Explanation:

it contains 58.37 as there is no compound with 58.4 bromine formula brf3

Answer: 0.375L

Explanation: Using M1V1=M2V2, we can solve for V1.

12M*V1=1.5M*3.0L

V1 = \(\frac{1.5M*3.0L}{12M}\)

V1 = 0.375L.

0.375 L volume of the solution she needed to prepare 3.0 L of a 1.5 M HCl solution.

A homogenous mixture of one or more solutes that have been dissolved in a solvent is known as a solution. The material that a solute dissolves in to create a homogenous mixture is known as a solvent.

The component that dissolves in a solvent to create a homogenous mixture is known as a solute.

M₁ is the initial concentration of HCl solution = 12.0 M

V₁ is the volume of initial HCl solution that is needed

M₂ is the final concentration of HCl solution = 1.5 M

V₂  is the final volume of HCl solution to be prepared = 3.0 L

To find V₁, we get

V₁ = (M₂ V₂) / M₁

calculating the values, we will get:

V₁ = 1.5 M x 3.0 L / 12.0 M

= 0.375 L

Therefore, tech required to take 0.375 L of the 12.0 M HCl solution and dilute it to  3.0 L to make a 1.5 M HCl solution.

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ANSWER

The volume of iron (III) oxide is 16962.04 Liters

STEP-BY-STEP EXPLANATION:

Given information

The density of iron (III) oxide = 5.242 g/cm^3

The mass of iron (III) oxide = 88,915 kg

Let x represents the volume in liters of iron (III) oxide

The first step is to convert the mass from kilograms to grams for unit consistency since the density is already measured in g/cm^3

Recall that, 1 kg is equivalent to 1000 g according to the standard international unit

let x represents the mass to be converted to grams

From the calculation above, you will see that the mass of iron (III) oxide in grams is 88915000 grams.

The next step is to find the volume of iron (III) oxide using the below formula

The next step is to convert the cubic centimeters to liters

According to the standard international unit, 1 cm^3 is equivalent to 0.001 L

Therefore, the volume of iron (III) oxide is 16962.04 Liters

The heat capacity for the metals are;

Aluminum -  0.89

Copper - 0.11

Iron - 0.44

Lead - 0.12

The specific heat of a substance is denoted by the symbol "C" and is typically measured in units of J/g·°C (joules per gram per degree Celsius) or cal/g·°C (calories per gram per degree Celsius).

The specific h

We have that;

For Aluminum;

c = 4.184 * 39.85 * 4.7/11.98 * 72.9

= 783.6/873.3

= 0.89

For Copper;

c =  4.184 * 12.14 * 1.9/12.14 * 75.4

= 96.5/915.3

= 0.11

For Iron

c =  4.184 * 40.24 * 2.4/12.31 * 75.1

= 404.1/924.5

= 0.44

For Lead

c = 4.184 * 39.65 * 0.7/12.46 * 76.7

c = 116.1/955.68

= 0.12

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Answer:

Hmm

Explanation:

Elemental antimony adults a layer structure (space group R3m No.166) in which layers consist of fused, ruffled, six-membered rings. The nearest and the next nearest neighbors form and irregular octahedral complex, with the 3 atoms in each layer slightly closer than 3 atoms in the next

Electric configuration : 4d^10 5s^2 5p^3

Answer:

Explanation:

1 . The strongest force observed at the surface of glass is:__DIPOLE______

2. . Water is__POLAR_________ and interacts, generating adhesive interactions with the only weak dispersion strong hydrogen bonding polar glass.

3 . Hexane is_NON-POLAR _______ and interacts, generating__ONLY WEAK __________ adhesive interactions with the glass.

The mass of 4.35 × 10^-2 mol of NaOH is 1.74 grams.

Given

Number of moles = 4.35 x 10^-2

First, we calculate the molar mass of NaOH,

Molar mass of NaOH = (1 × atomic mass of Na) + (1 × atomic mass of O) + (1 × atomic mass of H)

= (1 × 22.99 g/mol) + (1 × 16.00 g/mol) + (1 × 1.01 g/mol) = 40.00 g/mol

Molar mass of NaOH = 40.00 g/mol

Mass of NaOH = Number of moles × Molar mass

                          = 4.35 × 10^-2 mol × 40.00 g/mol  

Mass of NaOH  = 1.74 g

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