Answer:
the other force= (16.3i + 14.6j)N
EXPLANATION:
Given:
Mass=2.80-kg
t= 1.2s
Since the object started from rest, the origin is (0,0) which symbolize the the object's initial position.
We will need to calculate the magnitude of the displacement using the below formula;
d = (1/2)at2 + v0t + d0
But note that
d0 = 0,( initial position)
v0 = 0( initial position)
a is the net acceleration
d = √[4.202 + (-3.30)2] m = 5.34 m
Hence, the magnitude of the displacement is 5.34 m, then we can make 'a' the subject of formula in the above expression in order to calculate the value for acceleration, note that d0 = 0,( initial position) and v0 = 0( initial position)
d = (1/2)at2
a = 2d/t2 = 2(5.34)/(1.20)2 m/s2 = 7.42 m/s2
the net acceleration is 7.42 m/s2
Acceleration in terms of the vector can be calculated as
a=2(ri - r0)/t^2
Where t =1.2s which is the time
a= 2(4.2i - 3.30j)/ 1.2^2
a=( 5.83i - 4.58j)m/s
now the net force can now be calculated since we have known the value of acceleration, using the formula below;
F(x) = ma - mg
Where a = 5.83i - 4.58j)m/s and g= 9.8m/s
2.8(5.83i - 4.58j)m/s - (2.80 × 9.8)m/s^2
Therefore, the other force= (16.3i + 14.6j)N
Two particles with charges Q=16 microC and -Q=-16 microC are fixed at the vertices of an equilateral triangle with sides of length a = 8 micrometers. The work required to move a particle with a charge q=19 microC from the other vertex to the centre of the line joining the fixed charges is ...J
The work required to move the particle with a charge of q = 19 microC from the other vertex to the center of the line joining the fixed charges is approximately -2.03 * 10^-14 J.
What is the work required?The work required to move a charge from one point to another in an electric field is given by the equation W = qV, where q is the charge and V is the potential difference.
In this case, the potential at the center of the line joining the two fixed charges can be calculated using Coulomb's law. The potential difference between the center and the third vertex can then be calculated, giving us the work required to move the particle with a charge q = 19 microC.
W = qV = 19 * 10^-6 C * V
Where V is the potential difference, which can be calculated as follows:
V = (1/(4 * pi * epsilon_0)) * ((Q / a) - (q / a))
Where epsilon_0 is the vacuum permittivity and a is the length of the sides of the equilateral triangle.
Substituting the values, we get:
W = 19 * 10^-6 C * (1 / (4 * pi * 8.854 * 10^-12 C^2/Nm^2)) * ((16 * 10^-6 C / 8 * 10^-6 m) - (19 * 10^-6 C / 8 * 10^-6 m))
W = 19 * 10^-6 C * (1 / (4 * pi * 8.854 * 10^-12 C^2/Nm^2)) * (-3 * 10^-6 C / 8 * 10^-6 m)
W = 19 * 10^-6 C * (1 / (4 * pi * 8.854 * 10^-12 C^2/Nm^2)) * (-3 * 10^-6 / 8) J
W = -2.03 * 10^-14 J
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If you throw an object straight up into the air with an initial velocity of 42m/s. What is it’s velocity at the peak of its flight?
A. 42m/s
B. -42m/s
C. 9.8m/s
D. -9.8m/s
E. 0m/s
F. 0m/s2
G. None of these
Which element is usually listed first in the formula of a binary
molecular compound
a the element with the smallest atomic radius
b the element with the lowest electronegativity
C the element with the smallest atomic mass
d the element that is first in alphabetical order help!
Answer: the element with the lowest electronegativity
Explanation:
how we interact to a human person or people in a good way
Answer:
We show concern and show support
A wave with a frequency of 17 Hz has a wavelength of 5 meters. At what speed will this wave travel?
Answer:
85
Explanation:
soln
given that;
frequency=17Hz
wavelength=5m
speed?
formula for wavelength is;
wavelength= speed/frequency
then ; making v the subject formula
we have that v=wavelength*frequency
v=17*5=>85ms
How does an emergency action plan benefit your workplace
assuming all the sunlight is absorbed, what is the radiation-pressure force on the earth? give your answer in newtons.
The radiation pressure force on the earth is 1.15×10⁹ N.
P = I/C
where
I is the intensity
c is the speed of light
In this problem, I=1360W/m² ; substituting this value, we find the radiation pressure:
P= 1360/3×10⁸ = 4.5/10⁶ Pa
The force exerted on the Earth depends on the surface considered. Assuming that the sunlight hits half of the Earth's surface (the half illuminated by the Sun), we have to consider the area of a hemisphere, which is
A= 2πr²
A= 2π(6.37×10⁶)² = 2.55×10¹⁴ m²
And so the force exerted by the sunlight is
F= pA = 1.15×10⁹ N
What is pressure?
Pressure is a force acting perpendicular to the surface of an object per unit area over which this force is distributed. Overpressure is pressure relative to ambient pressure. Pressure is a standard mechanical quantity. Different units are used to express pressure.To know more about pressure, click the link given below:
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What is the atomic number of niobium.
Answer:
41 I believe
Explanation:
Just trust me lol
#5) Which of the following procedures would make
the biggest increase to gravitational force between two
identical objects?
A) Increasing the masses and increasing the distance
between the two objects.
B) Decreasing the masses and decreasing the distance
between the two objects.
C) Increasing the mass and decreasing the distance
between the two objects.
D)Decreasing the masses and increasing the distance
between the two objects.
Answer:
C) Increasing the mass and decreasing the distance
Explanation:
Since the equation for gravitational force is Fg = (Gm₁m₂)/r² where m₁ and m₂ are the masses of the objects and r is the distance between them, increasing the masses and decreasing the distance will produce a larger Fg.
Hope this helps. I'm not great at explaining. I'm new to Brainly
Thanks
if a space rover has a mass of 3900 kg, then what is its weight on earth
Answer:
38 220
Explanation:
Weight =Mg
W=Mg
W = (3900)(9.8)
W = 38 220
One scientific investigation may result in
A.
further investigations.
B.
the generation of new ideas or phenomena to study.
C.
the development of new methods or procedures for investigation.
D.
all of these
A quarterback throws a pass at an angle of 35° above the horizontal with an initial speed of 25 m/s. The ball is caught by the receiver 2.55 seconds later. Determine the distance the ball was thrown.
The distance the ball was thrown is 52.22m by A quarterback throws a pass at an angle of 35° above the horizontal with an initial speed of 25 m/s. The ball is caught by the receiver 2.55 seconds later.
How to calculate distance?Every motion under constant acceleration is projectile motion
Angle above horizontal Ф = 35°, initial speed v1 = 25m/s , time 2.55s
Substituting value in the below equation
x=x₁ + (v₁*cosθ)(t)+1/2 *a*t²
a= 0 as acceleration in horizontal direction is zero
x= 25*cos(35)*2.55
x=52.22 m
Projectile motion is a form of motion in which object influenced when it is launched into the gravitational force from the surface of Earth along a curved path.
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A projectile is launched horizontally on a table that it 40 cm high. The projectile lands 10 m away. What is the horizontal
velocity of the projectile as it leaves the launcher?
The horizontal velocity of the projectile as it leaves the launcher is 35 m/s.
What is the time of motion of the projectile?
The time of motion of the projectile is calculated by applying the following kinematic equation as shown below.
h = vt + ¹/₂gt²
where;
v is the initial vertical velocity = 0t is the time of motiong is acceleration due to gravityh = 0 + ¹/₂gt²
h = ¹/₂gt²
t = √(2h/g)
t = √(2 x 0.4 / 9.8)
t = 0.286 s
The horizontal velocity of the projectile as it leaves the launcher is calculated as follows;
v = x/t
where;
x is the horizontal distancet is the time of motionv = 10 m / 0.286 s
v = 35 m/s
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what is the cause of acid rain?
Do you think Kepler will be able to detect Earth-sized planets in transit?
Answer: Less than 1% of the stars that Kepler will be looking at are closer than 600 light years. Stars farther than 3,000 light years are too faint for Kepler to observe the transits needed to detect Earth-size planets.
Explanation:
A certain electric dipole consists of charges + and − separated by distance , oriented along the -axis as shown in the figure. Find an expression for the magnitude of the electric field of the dipole at a point far away in the -direction, a distance away from the midpoint of the dipole. Assume that is much greater than . Enter your answer in terms of , , , and 0.
I've seen other questions like this but the answers are coming back as incorrect or they have it with k included. Please help!
The magnitude of the electric field of the dipole at a point far away in the -direction, a distance away from the midpoint of the dipole is given by
|E| = |-(p * k) / r^3|
What is magnitude of the electric field?Generally, The electric field of an electric dipole at a point far away from the midpoint of the dipole is given by the following expression:
E = (p * k) / r^3 * (3 *cos(theta) * i^ + sin(theta) * j^)
where:
p is the magnitude of the dipole moment, equal to q * d (q is the charge and d is the distance between the charges)
k is the Coulomb constant (9 x 10^9 N * m^2/C^2)
r is the distance from the dipole to the point where the electric field
is being calculated theta is the angle between the vector pointing from the dipole to the point where the electric field is being calculated and the dipole moment vector (in this case, the -axis) i^ and j^ are the unit vectors in the x and y directions, respectively.
Since the dipole is oriented along the -axis and the point where the electric field is being calculated is far away in the -direction,
theta = pi and the expression for the electric field becomes:
E = (p * k) / r^3 * (3 *cos(pi) * i^ + sin(pi) * j^)
E = -(p * k) / r^3 * (i^)
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PLease HELP WILL GIVE BRAINLY
Finally, observe the values of horizontal acceleration for the point masses and the dynamic models for the man and the boy. What can you say about acceleration?
We can say some external things about body accelaration.
What is body accelaration?Acceleration of a body is the given as change in velocity is the per unit time of a body. That means it is the ratio of to the final velocity - initially the velocity. Accelaration = v - u t .
As per the given question -
We have to observe the value of horizontal accelaration for boy masses
And the dynamics model for the man and boy.
We can say about accelaration that is accelaration rate at which velocity change with time.in terms of both speed and direction.
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when 2cm tall object is placed in front of converging lens,0.5 cm long real image is formed 11cm away from object find its focal length
The focal length of the lens is 14.67 cm.
The focal length of an optical device is a measure of how strongly the machine converges or diverges mildly; it's miles the inverse of the system's optical electricity. A wonderful focal length suggests that a system converges mildly, while a negative focal duration shows that the system diverges mildly.
Calculation:-
himage/h object = f-v/f
0.5/2 = f - 11/f
0.25f = f - 11
11 = f - 0.25f
11 = 0.75f
f = 11/0.75
f = 14.67 cm
The focal length ( f ) is the gap from a lens or reflects the point of interest ( F ). this is the distance from a lens or replicates at which parallel mild rays will meet. The focal period of (left) a concave lens (with a negative focal length), (middle) a convex lens and. (right) a concave replicate.
The distance from the center of the lens to the photo focal factor (=image sensor floor) is referred to as the focal period. Its miles are expressed in millimeter (mm) gadgets. A lens with a brief focal duration is an extensive-perspective lens and one with a protracted focal length is a telephoto lens.
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Question 5 of 25If the distance traveled increases and the time of travel stays the same,happens to the speed?OA. The speed decreases.OB. The speed increases.OC. The speed does not change.O D. The speed goes down, up, and then down again.
Given:
The distance traveled increases and the time of travel stays the same.
To find the change in speed.
Explanation:
The speed is
An object dropped from the window of a tall building hits the ground in 12.0 s. If its acceleration is 9.80 m/s2, the height of the window above the ground is
Answer:
58.8 metres
Explanation:
using the formula
h=ut+½gt
U=0
g=9.8m/s²
t=12.0a
Hence, h= 0.5 × 9.8 × 144
h = 58.8 metres
A person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a
height of 52 m and it lands a distance of 35 m from the base of the cliff. What is the speed at
which the rock was initially kicked?
The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s
What is Speed ?Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s
Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.
The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.
Let us first calculate the time by using the formula
h = ut + 1/2gt²
Where
h = 52 mu = 0Range R = 35 mg = 9.8 m/s²Substitute all the necessary parameters into the formula
52 = 0 + 1/2 × 9.8 × t²
52 = 4.9t²
t² = 52/4.9
t² = 10.6
t = √10.6
t = 3.26 s
The speed at which the rock was initially kicked can be found by
R = Ut
35 = U × 3.26
U = 35/3.26
U = 10.7 m/s
Therefore, rock was initially kicked at a speed of 10.7 m/s
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Why should we invest more money in renewable energy resources
Answer:
It is the smarter option.
Explanation:
Renewable energy is the cheapest source of new power generation for more than two-thirds of the world and has no fuel costs. It can reduce the economic burden of energy bills by eliminating fuel charges — especially when coupled with energy-efficiency upgrades in our homes and businesses.
A ball is launched from the surface of a planet. Air resistance and other frictional forces are neglected. The graph shows the position of the ball every 0.20 s.
a. Use this graph to determine:
I. The components of the initial velocity of the ball
II. The angle to the horizontal the ball was launched at
III. The acceleration of free fall on this planet.
b. Make a copy of the graph and draw two arrows to represent the velocity and the acceleration vectors of the ball at t = 1.0 s.
c. The ball is now launched under identical conditions from the surface of a different planet where the acceleration due to gravity is twice as large. Draw the path of the ball on your graph.
The angle to the horizontal the ball was launched at can be determined using trigonometry. Once you have the initial horizontal and vertical velocities, you can use the tangent function to calculate the launch angle.
What are the velocities ?Velocity is a physical quantity that describes the rate at which an object changes its position. It is a vector quantity, which means it has both magnitude and direction. The magnitude of velocity is the speed of the object, while its direction is the direction of motion.
What is time ?Time is a concept that refers to the sequence of events that occur in a continuous progression, from the past, through the present, and into the future. It is a way to measure the duration or the length of events or periods, and it is a fundamental aspect of our experience and understanding of the world.
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A ladder rests against a vertical wall. There is no friction between the wall and the ladder. The coefficient of static friction between the ladder and the ground is µ =0.611.
Consider the following expressions:
A1: f = Fw
A2: f = Fw sin θ
B1: N =
W
2
B2: N = W
C1: ℓ Fw sin θ = 2 Fw cos θ
C2: ℓ Fw sin θ = ℓ W cos θ
C3: ℓ Fw sin θ =
1
2
ℓ W cos θ ,
where
f: force of friction between the ladder and
the ground,
Fw: normal force on the ladder due to the
wall,
θ: angle between the ladder and the ground,
N: normal force on the ladder due to the
ground,
W: weight of the ladder, and
ℓ: length of the ladder.
(Pt. 1/2) Identify the set of equations which is correct.
1. A2, B2, C1
2. A2, B1, C2
3. A1, B2, C2
4. A2, B1, C1
5. A1, B1, C2
6. A1, B1, C3
7. A1, B1, C1
8. A2, B1, C3
9. A1, B2, C3
10. A1, B2, C1
(Pt.2/2) Determine the smallest angle θ for which the
ladder remains stationary.
Answer in units of °.
Answer:
the answer is Number nine
A fish tank is 20 inches by 12 inches by 12 inches. What is its volume in m * m ^ 3
As the fish tank is 20 inches by 12 inches by 12 inches, its volume is 47194744.32 mm³.
What is volume?The space that any three-dimensional solid occupies is known as its volume. These solids can take the form of a cube, cuboid, cone, cylinder, or sphere.
1 inch = 0.0254 meters.
20 inches = 20 × 0.0254 meters = 0.508 meters = 508 mm.
12 inches = 12 × 0.0254 meters = 0.3048 meters = 304.8 mm.
Hence, The volume of the fish tank = length × width × height
= 508 mm × 304.8 mm × 304.8 mm.
= 47194744.32 mm³
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Using P = M x V what is the momentum of an object with a mass of 750 kg and velocity of 15 m/s
Answer:
p = 11250 kg·m/s
Explanation:
Explanation:
it goes like this p=MV which is
M=750,V=15
p= 750x15=11250n
the top of a swimming pool is at ground level. if the pool is 2.00 m deep, how far below ground level does the bottom of the pool appear to be located when (a) the pool is completely filled with water? (b) half-full answers for part (a):
(a) pool appears to be 1.5 m deep.
(b) if the pool is half filled then p = 1 m and q = - 0.750 m thus the bottom of the pool appears to be 0.750 m below the water surface or 1.75 m below ground level.
for the plane refracting water surface
\(\frac{n_{1} }{p}\) \(\frac{n_{1} }{p} +\frac{n_{2} }{q} =\frac{n_{2}-n_{1}}{R} =Becomes q= -\frac{n_{2}}{n_{1} } p\)
(a) when the pool is full p = 2 m and
\(q= -(\frac{1}{1.33} )(2) =-1.5m .....\)pool appears to be 1.5 m deep
(b) if the pool is half filled then p = 1 m and q = - 0.750 m thus the bottom of the pool appears to be 0.750 m below the water surface or 1.75 m below ground level.
Surface water is water placed on the pinnacle of land forming terrestrial (inland) waterbodies, and can additionally be known as blue water, against seawater and waterbodies like the ocean.
The huge majority of floor water is produced by using precipitation. because the climate warms in the spring, snowmelt runs off toward close by streams and rivers contributing toward a huge portion of human consuming water. levels of surface water lessen due to evaporation as well as water entering into the floor and turning into groundwater. along with getting used for ingesting water, floor water is also used for irrigation, wastewater remedy, cattle, commercial uses, hydropower, and recreation. For USGS water-use reviews, floor water is considered freshwater when it consists of less than 1,000 milligrams in step with a liter (mg/L) of dissolved solids.
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what did Ernest Reuther fourths gold foil experiment show about the nature of Atoms
Answer:
-Positively charged nucleus
-Empty spaced
-Dense core
Explanation:
Monochromatic coherent light shines through a pair of slits. If the wavelength of the light is decreased, which of the following statements are true of the resulting interference pattern? (There could be more than one correct choice.)
a. The distance between the maxima decreases.
b. The distance between the minima decreases.
c. The distance between the maxima stays the same.
d. The distance between the minima increases.
e. The distance between the minima stays the same.
Answer:
he correct answers are a, b
Explanation:
In the two-slit interference phenomenon, the expression for interference is
d sin θ= m λ constructive interference
d sin θ = (m + ½) λ destructive interference
in general this phenomenon occurs for small angles, for which we can write
tanθ = y / L
tan te = sin tea / cos tea = sin tea
sin θ = y / La
un
derestimate the first two equations.
Let's do the calculation for constructive interference
d y / L = m λ
the distance between maximum clos is and
y = (me / d) λ
this is the position of each maximum, the distance between two consecutive maximums
y₂-y₁ = (L 2/d) λ - (L 1 / d) λ₁ y₂ -y₁ = L / d λ
examining this equation if the wavelength decreases the value of y also decreases
the same calculation for destructive interference
d y / L = (m + ½) κ
y = [(m + ½) L / d] λ
again when it decreases the decrease the distance
the correct answers are a, b
A box with a mass of 0.5 slugs lies on an inclined plane making an angle of 30o with the horizontal. If the coefficient of kinetic friction between the box and the plane is 0.4, what is the magnitude of the force that must be applied parallel to the incline to keep the box moving down the incline at a constant speed
Answer: 10.98 N
Explanation:
Given
mass of box is \(m=0.5\ slugs\approx 7.3\ kg\)
The coefficient of kinetic friction is \(\mu= 0.4\)
It is given that on the application of force box started moving with constant speed i.e. there is no net external force
\(\Rightarrow F+mg\sin 30^{\circ}=\mu mg\cos 30^{\circ}\\\Rightarrow F=mg(\mu \cos 30^{\circ}-\sin 30^{\circ})\\\Rightarrow F=7.3\times 9.8(0.866\times0 .4-0.5)=-10.98\ N\\\)
The negative sign indicates direction of force is opposite i.e. it must be applied upwards