Beyond the blank__ color in the light spectrum is the ultraviolet UV light ( answer in one word ) PLEASE HELP

Answer:

The angle of the Sun is lower during the winter months and higher in the sky during the summer.

Explanation:

i took the test

Answer:

Here you go!!

Explanation:

6.5 moles of gas occupy 1.7 L at 1.3 atm at a temperature of 4.17K.

Ideal gas law is as follows:

PV = nRT

where,

P = Pressure = 1.3 atm

V = Volume = 1.7 L

n = No. of moles = 6.5 moles

R = gas constant = 0.0821 atm L / (mol K)

T = Temperature =?

Substituting the values in the ideal gas law equation to find the temperature, we get,

PV = nRT

1.3 * 1.7 = 6.5 * 0.0821 * T

2.21 = 0.53 * T

∴ T = 2.21/0.53

T = 4.17 K

At temperature 4.17K, 6.5 moles of gas occupy 1.7 L at 1.3 atm.

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Answer:

take 75 gm or it will be overdose

Answer:  d. they are a form of reserve fuel storage

Explanation:

Triglycerides are special type of lipids. They are formed by glycerol with three fatty acid chains. The fatty acid chains can vary in length, they can be saturated or unsaturated with varying composition. It is the most abundant lipid in diet. It is available in plant as well as animal based foods. In case of mammals the triglycerides are stored in the adipose tissue in which they are broken to release energy.

Answer:uclear Force that holds together the nucleus of an atom. electromagnetic force. ... They are unstable because the Strong Force that would hold them together if the protons and neutrons were closer is weakened because the protons and neutrons get too far apart.

Explanation:

in a diatomic nitrogen, the number of electrons that are shared between the nitrogen atoms are three pairs of electrons.

Diatomic nitrogen is a type of nitrogen molecule that has three bonds that are formed between the atoms of nitrogen elements.

Electrons are also defined as the negative charge subatomic particles that revolves round an atom with negative charges.

If in the diatomic nitrogen, three bonds are formed, it means six electrons are involved which is the same as three pairs of electrons.

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Answer:

\([Ag^+]=2.82x10^{-4}M\)

Explanation:

Hello there!

In this case, for the ionization of silver iodide we have:

\(AgI(s)\rightleftharpoons Ag^+(aq)+I^-(aq)\\\\Ksp=[Ag^+][I^-]\)

Now, since we have the effect of iodide ions from the HI, it is possible to compute that concentration as that of the hydrogen ions equals that of the iodide ones:

\([I^-]=[H^+]=10^{-3.55}=2.82x10^{-4}M\)

Now, we can set up the equilibrium expression as shown below:

\(Ksp=8.51x10^{-17}=(x)(x+2.82x10^{-4})\)

Thus, by solving for x which stands for the concentration of both silver and iodide ions at equilibrium, we have:

\(x=[Ag^+]=2.82x10^{-4}M\)

Best regards!

Answer:

1.5x10¯⁴Kg

Explanation:

Data obtained from the question include the following:

Volume = 0.1642mL = 0.1642cm³

Density = 0.917g/cm³

Mass =.?

The Density of a substance is simply defined as the mass per unit volume of the substance. Mathematically, it is represented as:

Density = Mass /volume

With the above formula, we can calculate the mass of the ice as follow:

0.917 = Mass / 0.1642

Cross multiply

Mass = 0.917 x 0.1642

Mass = 0.151g

Finally, we shall convert 0.1506g to kg. This is illustrated below:

1000g = 1k

Therefore, 0.151g = 0.151/1000 = 1.5x10¯⁴Kg

The volume (in mL) of the gas when the barometer reads 740 mmHg is 243.24 mL

The following data were obtained from the question given above:

The new volume of the gas can be obtained by using the Boyle's law equation as shown below:

P₁V₁ = P₂V₂

720 × 250 = 740 × V₂

180000 = 740 × V₂

Divide both sides by 740

V₂ = 180000 / 740

V₂ = 243.24 mL

Thus, we can conclude from the above calculation that the volume is 243.24 mL

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Answer:

7

Explanation:

just add p has 1 o has 4 and h has 2

Answer:

4d¹ electron has quantum numbers

n=4; l=2; ml= -2; ms= 1/2

Explanation:

There are 4 quantum numbers, namely

the principal quantum number (n)

the orbital angular momentum quantum number (l)

the magnetic quantum number (ml)

the electron spin quantum number (ms)

The principal quantum number describes the orbit or shell of the electron

here n = 4 ⇒ electron is in 4th shell

the orbital angular momentum quantum number describes the shape of orbital the electron is present in.

l= 0 ⇒ s-orbital

l= 1 ⇒ p-orbital

l= 2 ⇒ d-orbital

l= 3 ⇒ f-orbital

In our case l= 2 ⇒ p-orbital

ml specifies in which orbital electron is present of given shape

ml has 2l+1 values,which range from -1 to +l

here l = 2 ⇒ ml has 2(2)+1 = 5 values (-2 to +2)

so electron is present in one of the five d-orbitals

ms represents the spin of electron (+1/2 or -1/2)

If  +1/2 represents clockwise then -1/2 represents anti-clockwise and vice-versa.

⇒  4d¹ electron has quantum numbers

n=4; l=2; ml= -2; ms= 1/2.

Hope this helped!

If a certain piece of metal is cooled it will conduct current better is a hypothesis.

When a conductor is connected to a fluctuating magnetic flux, it induces closed loops of electric currents known as eddy currents. They create closed circuits in a plane perpendicular to the magnetic field and are subject to Faraday's law of electromagnetic induction. These currents will flow in a direction that opposes the shift required by the Lenz law.

Eddy currents are created when a conductor is traveling through a magnetic field or when the magnetic field around a conductor at rest changes over time. They arise from variations in the strength and direction of a conductor-linked magnetic field or magnetic flux.

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Answer:

123.1L

Explanation:

Given parameters:

Molarity of Cu(NO₃)₂  = 0.650M

Mass of  Cu(NO₃)₂ = 15g

Unknown:

Volume of  Cu(NO₃)₂ = ?

Solution:

To solve this problem, we have to first find the number of moles of the given mass;

  Number of moles of Cu(NO₃)₂  = \(\frac{mass}{molar mass}\)

   Molar mass of Cu(NO₃)₂  = 63.5 + 2 (14 + 3(16)) = 187.5g/mol

 Number of moles of Cu(NO₃)₂  = \(\frac{15}{187.5}\)  = 0.08 mol

Molarity is given as;

  Molarity  = \(\frac{number of moles }{volume}\)  

         Volume  = \(\frac{number of moles }{molarity }\)  

  Insert the parameters and solve;

        Volume  = \(\frac{0.08}{0.65}\)  = 0.12L

Now mL;

         1L  = 1000mL

        0.12L will give 1000 x 0.12  = 123.1L

Reagent bottles must be closed when not in use because they may contain volatile or sublime substances.

Reagent bottles are most commonly used to store chemical reagents, including acid and alkali solvents that can be safely stored due to anti-corrosion capabilities.

Reagent bottles, often known as graduated bottles, are glass, plastic, borosilicate, or related-substance containers with specific caps or stoppers. They are used in labs to store chemicals in liquid or powder form in cabinets or on shelves.

Some reagent bottles are tinted amber (actinic), brown or red to protect light-sensitive chemical compounds from visible light, ultraviolet and infrared radiation which may alter them; other bottles are tinted blue (cobalt glass) or uranium green for decorative purposes -mostly vintage apothecary sets.

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When an electron falls from a higher energy level to a lower energy level in the hydrogen atom, it emits a photon with a specific wavelength. This wavelength can be used to determine the energy difference between the two energy levels involved in the transition. The energy of a photon is given by:

E = hc/λ

where E is the energy of the photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.

We can use the energy of the photon to determine the energy difference between the initial and final energy levels of the electron in the hydrogen atom. This energy difference is given by:

ΔE = E_initial - E_final

where ΔE is the energy difference, E_initial is the initial energy level, and E_final is the final energy level.

The energy difference can be calculated by rearranging the formula for the energy of the photon as follows:

ΔE = hc/λ

Substituting the given values, we get:

ΔE = (6.626 x 10^-34 J s) x (3.00 x 10^8 m/s) / (434.1 x 10^-9 m)

ΔE = 4.564 x 10^-19 J

The energy difference between the two energy levels is equal to the initial energy level minus the final energy level. The final energy level is n2, and we need to find the initial energy level. Using the formula for the energy levels of the hydrogen atom:

E_n = -13.6 eV / n^2

where E_n is the energy of the nth energy level in electron volts (eV), and n is the principal quantum number.

We can set up the following equation to solve for the initial energy level:

E_initial - E_final = (-13.6 eV / n_initial^2) - (-13.6 eV / n2^2)

Substituting the values of ΔE and n2, we get:

4.564 x 10^-19 J = (-13.6 eV / n_initial^2) - (-13.6 eV / 2^2)

Simplifying this equation and solving for n_initial, we get:

n_initial = 3

Therefore, the initial energy level of the electron in the hydrogen atom was n = 3.

The pH of the solution made by mixing 15.0cm³ 0.1M NaOH and 35.0 cm³ 0.2 M HCOOH would be 2.39.

The first step in solving this problem is to write the balanced chemical equation for the reaction between NaOH and HCOOH:

NaOH + HCOOH → NaCOOH + H2O

Next, we need to calculate the moles of each reactant:

moles NaOH = 0.1 mol/L x 0.015 L = 0.0015 moles

moles HCOOH = 0.2 mol/L x 0.035 L = 0.007 moles

Since NaOH and HCOOH react in a 1:1 stoichiometry, we know that 0.0015 moles of NaOH reacts with 0.0015 moles of HCOOH. This leaves 0.007 - 0.0015 = 0.0055 moles of HCOOH unreacted.

Now, we need to use the equilibrium constant (Ka) for the reaction between HCOOH and water to determine the concentration of H+ ions in the solution:

HCOOH + H2O ⇌ H3O+ + HCOO-

Ka = [H3O+][HCOO-]/[HCOOH]

We are given the value of Ka, so we can use it to find the concentration of H+ ions:

Ka = 1.82 × 10^-4 M

[H3O+] = [HCOO-] = x (let's assume that the initial concentration of HCOOH is much larger than x, so we can assume that x is negligible compared to the initial concentration of HCOOH)

[HCOOH] = 0.0055 moles / 0.05 L = 0.11 M

Ka = (x^2) / (0.11 - x)

Since x is negligible compared to the initial concentration of HCOOH, we can simplify the equation to:

Ka = (x^2) / 0.11

Solving for x, we get:

x = sqrt(Ka * [HCOOH]) = sqrt(1.82 x 10^-4 * 0.11) = 0.0041 M

Therefore, [H+] = 0.0041 M

Finally, we can use the definition of pH to calculate the pH of the solution:

pH = -log[H+] = -log(0.0041) = 2.39

Therefore, the pH of the solution is 2.39.

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Answer:

0.33moles

Explanation:

RAM of;

Na = 23, H=1, C=12, O=16

molar mass of NaHCO= 23+1+12+16= 52g/mol

mole= mass / molar mass

mole = 17.31/52

mole= 0.33moles

Answer: B) 0.005 55 cm

Hope you have a blessed day!

The concentration of A is decreasing faster than A₂ increases.

option C.

The rate of reaction, also known as the reaction rate, is a measure of how quickly a chemical reaction takes place.

Reaction rate represents the change in concentration of reactants or products per unit of time.

The given relationship between the two concentrations;

2A  ⇆  A₂

make A₁ the subject of the formula;

A =  ⇆  A₂ / 2

From the equation given above we can see that the concentration A is decreasing at a faster rate compared to concentration of A₂.

Thus, according to the graph, the concentration of A is decreasing faster than A₂ increases.

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Answer: 9.27 g/mL

Explanation:

\(d=\frac{m}{v}=\frac{18.53}{2.0}=\boxed{9.27 \text{ g/mL}}\)

Answer:

See explanation below

Explanation:

In this case, we can explain this in a very basic way.

We know that heavier objects will go always at the bottom when we are carrying two objects, one heavier than the other right?

In the same manner works the density of two liquids. In this case, we have a mix of water and bromoethane. Bromoethane is an organic compound and it's less polar than water which is extremely polar. When we mix these two liquids, we can see that both of them are insoluble, so no matter how much we shake the funnel, the liquids will not mix to form a solution.

Instead of that, both of them will be in the funnel, and they'll be gradually separating into two layers. The bromoethane has a higher density than water, this means that in the bottom layer we will have the bromoethane and in the top layer we will have the water.

In case you are wondering what happens if we added water first and then, the bromoethane?, it will happen the same, it does not matter the order you add the liquid, because density here is a very important factor, so when the water is added no matter which position, it will go to the top layer after the bromoethane is added.

Now when the hexane is added, it will form now three layers, and again, density plays an important factor. The higher density will go to the bottom, and the lowest to the top.

In this case, the order of layer will be:

Top layer: hexane (d = 0.66 g/mL)

Middle layer: water (d = 1 g/mL)

Bottom layer: bromoethane (d = 1.46 g/mL)

Hope this helps

1. The rms speed of O₂ molecules at 427 K is 576.9 m/s

2. The rms speed of He atoms at 427 K is 1631.7 m/s

The rms speed of the various elements can be obtained as follow:

1. For O₂ molecules

rms speed = √(3RT / μ)

rms speed of O₂ molecules = √(3 × 8.314 × 427 / 0.032)

rms speed of O₂ molecules = 576.9 m/s

2. For He atoms

rms speed = √(3RT / μ)

rms speed of He atoms = √(3 × 8.314 × 427 / 0.004)

rms speed of He atoms = 1631.7 m/s

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Answer:

71 graham formal.

Dont get mad if i am wrong 0-0

Explanation:

Based on the information provided, we have a reaction between hydrogen iodide (HI) gas and hydrogen gas (H₂) to form iodine gas (I₂). The equilibrium is represented by the equation:

2HI(g) = H₂(g) + I₂(g)

The concentration values given in the table correspond to the concentrations of H₂ and HI at different times.

a) From t=0 s to t=5 s: Without the specific graph mentioned in Figure 7.10, it is difficult to provide a precise explanation of the physical situation in the container during this time period. However, based on the equilibrium reaction given, we can make some general observations. At the start (t=0 s), the concentrations of H₂ and HI may be high. As time progresses, the reaction proceeds, and the concentrations of H₂ and HI may decrease while the concentration of I₂ increases. The specific behavior will depend on the rate of the forward and reverse reactions.

b) External factor altered at t=5 s: To bring about a change in the shape of the graph at t=5 s, some external factor must have been altered. The most likely factor is the total pressure within the container. Since the reaction involves gases, changes in pressure can affect the equilibrium position. However, according to the information given, a change in pressure will not affect equilibrium in this case since the number of moles of gas is the same on both sides of the equation. Therefore, if the shape of the graph changes at t=5 s, some other external factor, such as temperature or the addition of a catalyst, must have been altered.

c) Calculation of K at t=3 s: The equilibrium constant (K) can be calculated at any given time using the concentrations of the reactants and products. However, the concentrations of H₂ and HI at t=3 s are not provided in the information given. Without the necessary data, it is not possible to calculate K at t=3 s.

Lastly, the statement "1 dm³ COCI, decomposes" seems incomplete. If you provide additional information or clarify the question, I'll be happy to assist you further.