1 Line AB passes through the points A(-1, -2) and B(3,8). Would AB be parallel to a line whose slope is equal to 3?

Answer:

16

Step-by-step explanation:

To find the median, we find the middle of the data set.

7, 9, 11, 14, 18, 20, 30, 35

There are 8 values

7, 9, 11,    14, 18,     20, 30, 35

The median is between the 4th and 5th numbers

We need to find the mean of the middle two numbers

(14+18)/2 =32/2= 16

Answer:

16

Step-by-step explanation:

             \(\sf (\frac{n+1}{2}\:)^ t^h \:data\)

       Here,

             n ⇒ number of terms

Let us find it now.

7, 9, 11, 14, 18, 20, 30, 35

\(\sf Median=\sf (\frac{n+1}{2}\:)^ t^h \:data\\\\\sf Median=\sf (\frac{8+1}{2}\:)^ t^h \:data\\\\\sf Median=\sf 4.5^ t^h \:data\)

In this case, add 4th and 5th data and divide it by 2.

\(\sf Median = \frac{14+18}{2}\\\\ \sf Median = \frac{32}{2}\\\\\sf Median = 16\)

Answer:

61.3737378

Step-by-step explanation:

First find the ten millionth digit, and the digit after it.

The digit "8", the seventh digit to the right of the decimal point is the ten millionth digit.

As the digit after "8" is 4, which is less than 5, so simply round the digit "4" down.

Thus the answer is 61.3737378

Answer:

Figure C

Step-by-step explanation:

Answer:37.68/18.84

Step-by-step explanation:.

Answer:

6 35/100 or six and 35 of 100

Step-by-step explanation:

Answer:

6 And 7/20

Next time use a calculator this is a pretty easy question its just simple division

Answer:

Show that the ratios StartFraction UV/XY, WU/ZX, and WV/ZY are equivalent.

Step-by-step explanation:

I just took the quiz and got it right. Hope this helps :)

Two triangles are similar but not congruent if they have three congruent angles but the side lengths are not equal

The two triangles can be shown to be similar given that the ratios of the corresponding sides ΔWUV and ΔYXZ are constant

Reason:

Known parameters are;

ΔWUV and ΔXZY are shown

∠VUW ≅ ∠YXZ

∠UWV ≅ ∠XZY

∠UVW ≅ ∠ZYX

Length of side \(\overline {VW}\) = 60

Length of side \(\overline {VU}\) = 50

Length of side \(\overline {UW}\) = 40

Length of side \(\overline {ZY}\) = 48

Length of side \(\overline {YX}\) = 40

Length of side \(\overline {XZ}\) = 32

The ratio of the sides are;

\(\dfrac{\overline {VW}}{\overline {ZY}} = \dfrac{60}{48} = \dfrac{5}{4}\)

\(\dfrac{\overline {VU}}{\overline {YX}} = \dfrac{50}{40} = \dfrac{5}{4}\)

\(\dfrac{\overline {UW}}{\overline {XZ}} = \dfrac{40}{32} = \dfrac{5}{4}\)

Therefore, given that  the angles of ΔWUV and ΔXZY are all congruent, and the sides of triangle ΔWUV and ΔXZY have a constant proportion, we have that the two triangles are congruent by Side-Side-Side SSS congruency theorem,  and we have;

ΔWUV ~ ΔYXZ given that ΔYXZ is scaled drawing of ΔWUV

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The value of 'n' for which the division of x^(2n-1) by x + 3 leaves a remainder of -80 is n = 1.

To find the value of 'n' for which the division of x^(2n-1) by x + 3 leaves a remainder of -80, we can use polynomial long division. Let's perform the division step by step:

Write the dividend and divisor in polynomial long division format:

_________________________

x + 3 │ x^(2n-1) + 0x^(2n-2) + 0x^(2n-3) + ...

Divide the leading term of the dividend (x^(2n-1)) by the leading term of the divisor (x). The result is x^(2n-1)/x = x^(2n-2).

Multiply the divisor (x + 3) by the quotient obtained in the previous step (x^(2n-2)). The result is x^(2n-2) * (x + 3) = x^(2n-1) + 3x^(2n-2).

Subtract the result obtained in step 3 from the original dividend:

x^(2n-1) + 0x^(2n-2) + 0x^(2n-3) + ... - (x^(2n-1) + 3x^(2n-2)) = -3x^(2n-2) + 0x^(2n-3) + ...

Bring down the next term of the dividend (which is 0x^(2n-3)) and repeat steps 2-4 until the remainder is constant.

Since we are given that the remainder is -80, we can set the remainder equal to -80 and solve for 'n'.

-3x^(2n-2) + 0x^(2n-3) + ... = -80

Since the remainder is constant (-80), it means that all the terms with x have been canceled out in the division process. Therefore, we can deduce that the highest power of x in the divisor (x + 3) is 0.

This implies that x^(2n-2) = 0, and for any value of 'n', the exponent 2n-2 should be equal to zero. Solving this equation:

2n-2 = 0

2n = 2

n = 1

Therefore, the value of 'n' for which the division of x^(2n-1) by x + 3 leaves a remainder of -80 is n = 1.

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Answer:

I think the 1st one (on the left) is linear, the rest in nonlinear

Step-by-step explanation:

Answer:

-5u^3 - 5u^2  + 3.

Step-by-step explanation:

(u^3 + 3u^2 + 3) + (-6u^3 - 8u^2)

= u^3 + 3u^2 + 3 - 6u^3 - 8u^2

= u^3  - 6u^3 + 3u^2 - 8u^2 + 3

= -5u^3 - 5u^2  + 3.

Answer:

D

Step-by-step explanation:

\(-5+2(7b+6)\geq 10b+7(1+11b)\\-5+14b+12\geq 10b+7+77b\\70b\leq 0\\b\leq 0\)

Answer:

311.3 feet

Step-by-step explanation:

1 yard = 3 feet

Therefore, 103.76 yards = 311.28 feet (by multiplying 103.76 by 3)

Rounding to the nearest tenth gives us 311.3 feet.

The solution to the system of equations is x = 1 and y = -3.

To solve the system of equations using the substitution or elimination method, let's start with the substitution method.

Given equations:

y = 4x - 7

4x + 2y = -2

We'll solve equation 1) for y and substitute it into equation 2):

Substituting y from equation 1) into equation 2):

4x + 2(4x - 7) = -2

4x + 8x - 14 = -2

12x - 14 = -2

Now, we'll solve this equation for x:

12x = -2 + 14

12x = 12

x = 12/12

x = 1

Now that we have the value of x, we can substitute it back into equation 1) to find y:

y = 4(1) - 7

y = 4 - 7

y = -3

Therefore, the solution to the system of equations is x = 1 and y = -3.

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The perimeter of the given shape as represented in the task content is; 29 cm.

It follows from the task content that the perimeter of the given shape on the centimeter grid as required is to be determined.

Since each grid line has 1cm as it's length;

The perimeter of the shape is the sum of all side lengths of the shape;

Perimeter, P = 6+2+3+2+2+1+3+2+2+2+2+1

P = 29 cm

Hence, the perimeter of the shape is; 29 cm.

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First we can multiply both sides of the equation by 2 to get rid of the fraction.

(for the left side, the top doesn't change!)

12w - 20 = 12 - 4w

Then we can solve by adding 20 and 4w to both sides.

16w = 32

Last, divde both sides by 16.

w = 2

So our answer is the third option, w = 2

Answer:

Answer is w = -4

Step-by-step explanation:

\( \frac{12w - 20}{2} = 6 - 2w \\ 12w \div 2 = 6 \\ so \: we \: get \: 6 - 2w \\ now \: 6 - 2w = - 4\)

hope it helps

Answer: 81y^2

Step-by-step explanation: a^2-2ab+b^2=(a-b)^2 Plug values and solve.

Answer:

7a+14

Step-by-step explanation:

You distribute the 7 across the equation (7xa)+(7x2) = 7a=14

The rock will take 10.25 seconds to hit the ground, as the amount determined by the formula h=352-16t^(2).

The given equation is h=352-16t^(2). This equation can be used to calculate the time it will take for a rock to hit the ground after it has been dropped from a tower that is 352 feet high. The equation states that the rock's height (h) is equal to 352 minus 16 times the square of the time (t). To find the time it will take for the rock to hit the ground (h=0), we can rearrange the equation to solve for t. The rearranged equation is t=sqrt((352-0)/16), which simplifies to t=10.25. This means that the rock will take 10.25 seconds to hit the ground. This can also be expressed in tenths of a second as 102.5, which is the same as 10.25 seconds.

t= sqrt((352-0)/16)

t= sqrt(22)/4

t= 10.25

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Given:

Rate = 8.5 percent

Compounded quarterly

To determine the effective a

If the paper is a bond paper, then we need between an amount of 16750 and 22334 folds for a height of 67 inches.

In this problem we need to determine that number of elements in a paper whose folds creates a height to the height of the person. We assume that paper is a bond papel, whose thickness is 0.003 to 0.004 inches. The number of folds is equal to the height of the student in inches divided by the thickness, also in inches.

Let suppose that the height of the student is 67 inches (approx. 170 cm), then the number of papers in a batch with same height is:

n = 67 in / 0.003 in

n = 22334

n = 67 in / 0.004 in

n = 16750

If the paper is a bond paper, then we need between an amount of 16750 and 22334 folds for a height of 67 inches.

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Answer:

0, 30, 45, 60, 90

Step-by-step explanation:

To sum up, triangles hold a crucial place in the field of mathematics due to their significant properties as basic geometric shapes.

A polygon that possesses three sides and three angles is commonly referred to as a triangle. The total of the internal angles in a triangle is invariably 180 degrees.

There are different types of triangles, which can be distinguished by their angles and the lengths of their sides.

For instance, some of the classifications include equilateral, isosceles, and scalene triangles.

A wide range of mathematical disciplines such as geometry, trigonometry, and calculus rely heavily on their usage.

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The question in English:

A conclusion about mathematical triangles

In this example, process A completed its final quantum in q4, process B completed its final quantum in q4, and process C completed its final quantum in q4.

To determine which queue each process is in when it begins its final quantum, we need to know the length of time each process has been running and how many times it has already used each queue's quantum. Without that information, we cannot determine which queue a process will be in at a specific point in time. However, we can provide an example of how a process might move between the queues over time.

Let's consider the following three processes:

Process A - CPU burst time = 100s

Process B - CPU burst time = 30s

Process C - CPU burst time = 50s

Assume that all three processes arrive at the scheduler at the same time and are added to q1, the highest priority queue.

When the scheduler begins, it will select the first process in q1, which is process A. Since q1 has a quantum of 5s, process A will run for 5s before it is preempted and placed at the back of q2.

The next process in q1 is B. B will also run for 5s before being preempted and placed at the back of q2.

Next, the scheduler will select process C from q1. C will run for 5s before being preempted and placed at the back of q2.

Now the scheduler has completed one round-robin cycle through q1, and all the processes in q1 have used up their q1 quantum. The scheduler will move on to q2 and select the first process in that queue, which is process A. Since q2 has a quantum of 10s, process A will run for an additional 5s before being preempted and placed at the back of q3.

The next process in q2 is B. B will run for 10s before being preempted and placed at the back of q3.

Next, the scheduler will select process C from q2. C will run for 10s before being preempted and placed at the back of q3.

Now the scheduler has completed one round-robin cycle through q2, and all the processes in q2 have used up their q2 quantum. The scheduler will move on to q3 and select the first process in that queue, which is process A. Since q3 has a quantum of 20s, process A will run for an additional 10s before being preempted and placed at the back of q4.

The next process in q3 is B. B will run for 20s before being preempted and placed at the back of q4.

Next, the scheduler will select process C from q3. C will run for 20s before being preempted and placed at the back of q4.

Now the scheduler has completed one round-robin cycle through q3, and all the processes in q3 have used up their q3 quantum. The scheduler will move on to q4 and select the first process in that queue, which is process A. Since q4 has a quantum of 40s, process A will run for an additional 20s before completing its CPU burst.

The next process in q4 is B. B will run for 30s before completing its CPU burst.

Finally, the scheduler will select process C from q4. C will run for 40s before completing its CPU burst.

However, it's important to note that the exact behavior of the scheduler will depend on the length of time each process has been running and how many times it has already used each queue's.

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Answer:

1/2

Step-by-step explanation:

slope is 3/6 simplified is 1/2

Answer:

the slope is 1/2 simplified

Step-by-step explanation:

Formula: M=rise/run

rise=3

run=6

3/6= 1/2

Using relations in a right triangle, it is found that the length of AC is of 14 cm.

The relations in a right triangle are given as follows:

Researching this problem on the internet, we have that:

Hence the hypotenuse is found as follows:

sin(A) = 48/h

0.96 = 48/h

h = 48/0.96

h = 50 cm.

The length of side AC is the other leg of the triangle, found using the Pythagorean Theorem, hence:

\(x^2 + 48^2 = 50^2\)

\(x^2 = \sqrt{50^2 - 48^2}\)

x = 14 cm.

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Answer:

x = -7

Step-by-step explanation:

y = -16 is a horizontal line that crosses the y-axis at (0,-16)

a line perpendicular would have to be vertical and cross the x-axis at -7

therefore, the equation would be x = -7

Answer:

2

Step-by-step explanation:

We have a multiplication problem within a whole number and a fraction.

When multiplying fractions with whole numbers, you always multiply the whole number with the numerator of the fraction.

\(\frac{numerator}{denominator}\)

\(\frac{4}{8} *4\)

\(\frac{4*4}{8}\)

\(\frac{16}{8}\)

Divide 16 by 8 :

\(2\)

Answer:

To find the area of the shaded region, we need to first find the x-coordinates of the points where the two functions intersect. We can set f(x) = g(x) and solve for x:

x^4 - 12x^3 + 48x^2 = 44x + 105

x^4 - 12x^3 + 48x^2 - 44x - 105 = 0

We can use a numerical method, such as the Newton-Raphson method, to approximate the roots of this equation. Using a graphing calculator or computer algebra system, we can find that the roots are approximately:

x = -1.932, x = 0.695, x = 4.149

Note that the root x = -1.932 is outside the given interval [3, 4], so we can ignore it.

The shaded region is bounded by the x-axis, the line y = 340, and the graphs of f(x) and g(x) between x = 3 and x = 4. To find the area of this region, we can integrate the difference between the two functions over this interval:

A = ∫3^4 [g(x) - f(x)] dx

A = ∫3^4 [44x + 105 - (x^4 - 12x^3 + 48x^2)] dx

A = ∫3^4 [-x^4 + 12x^3 - 48x^2 + 44x + 105] dx

We can integrate term by term using the power rule:

A = [-x^5/5 + 3x^4 - 16x^3 + 22x^2 + 105x]3^4

A = [-1024/5 + 192 - 192 + 22 + 105] - [-81/5 + 108 - 192 + 66 + 105]

A = 347.2

Therefore, the area of the shaded region is approximately 347.2 square units.