Answer:
Explanation:
Scientific research conducted by psychologists, organized by topics here, can inform and guide those seeking help with issues that affect their professional lives, family relationships and emotional wellness.Tips for choosing a psychotherapist and answers to financial questions related to therapy.
When faced with important events (stressors) which are threatening or very hard to, psychological symptoms of stress include anxiety and tension, uncontrollable. In general, this refers to high levels of suspicion and mistrust, usually seen in this psychological condition is associated with acute physical sickness
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andrew returns to the top of the hill and starts again
his mass is 67kg.
calculate his momentum when his velocity is 31 m/s
As a result, when Andrew is moving at a speed of 31 m/s, his momentum is 2077 kg*m/s.
What is the kinetic energy equation?Kinetic energy has the following formula: K.E. = 1/2 m v2, where m is the object's mass and v is its square velocity. The kinetic energy is measured in kilogrammes-meters squared per second squared if the mass is measured in kilogrammes and the velocity is measured in metres per second.
An object's mass (m) and velocity (v) can be multiplied to find its momentum (p), which is written as:
p = m * v
Given that Andrew's mass is 67 kg and his velocity is 31 m/s, his momentum can be calculated as:
p = 67 kg * 31 m/s
p = 2077 kg*m/s
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Question:
Andrew is riding his bike up a hill. At some point, he stops and rests at the top of the hill. He then turns around and starts riding down the hill. When he reaches a velocity of 31 m/s, calculate his momentum. Andrew's mass is 67 kg.
question is shown is in the pictures.
please solve for 100pt
The type of dispersion in the Debye model is linear.
When it is at the longer wavelength limit, the density of states is referred to as quadratic.
D(ω) = [3ω²/2π²c³] s rad⁻¹m⁻³
This has a maximum frequency ωD, known as the Debye frequency. In the three dimensions, there are 3 degrees of freedom per atom.
So, the number of phonon modes present here is 3n.
3n = (0→ωD)∫D(ω)dω
Where n is known as the atomic density of the phonon.
We know that, for a frequency that is above the Debye frequency there will be no phonon modes present.
The Debye frequency,
ω³D = 6π²nc³
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Ageostationary satellite for communication seems to be in afixed spot above the equator because it has the same angular velocity as the earth? B.geostationary satellite are placed in orbits of radius 4.2×10power4m use this information to deduce g the acceleration of freely falling body at this height
Explanation:
The gravitational force equation is the following:

Where:
G = Gravitational constant = 
m1 & m2 = the mass of two related objects
r = distance between the two related objects
The problem gives you everything you need to plug into the formula, except for the gravitational constant. Let me know if you need further clarification.
We intend to measure the open-loop gain (LaTeX: A_{open}A o p e n ) of an actual operational amplifier. The magnitude of LaTeX: A_{open}A o p e n is in the range of 106 V/V. However, the signal generator in measurement setup can supply minimal voltage of 1 mV, and the oscilloscope used at amplifier output can measure maximal voltage level of 10 V. Can you design a simple measurement setup using this signal generator and oscilloscope, and accurately measure the LaTeX: A_{open}A o p e n
Answer:
voltage divider, R₂ = 1000 R₁
measuring the output in the resistance R₁
Explanation:
Let's analyze the situation, in an op amp in open gain loop, the gain is maximum G = 10⁶ V / V
in this case the signal generator gives a minimum wave of 1 10⁻³ V, after passing through the amplified it becomes 10³ V which saturates the oscilloscope.
To solve this problem we must use a simple voltage divider, for this we use the fact that in a series circuit the voltage is the sum of the voltages of each element.
If we use two resistors whose relationship is
R₂ / R₁ = 10³
R₂ = 1000 R₁
When measuring the output in the resistance R₁ we have the desired divider, with a tolerance range, for the minimum output of the generator (1 10⁻³V) we have a reading of V = 1 V in the oscilloscope, for which we can use voltage up to 10V on the generator
A box weighing 9,500 N is sliding down on an inclined plane that is 25 degrees above the horizontal ground. The box has an acceleration of 0.55 m/s^2.
a. Draw a free body diagram with Fg, FN, Fa and Ff
b. Find the mass of the box.
c. Find the net force.
d. Find the normal force acting on the box.
e Find the force applied by gravity as the box slides down the box.
f. Find the force of friction between the box and the inclined plane.
The forces that act are;
b)950 Kg
c) 522.5 N
d) 9,500 N
e) 4015 N
f) 9,500 N
g)3444 N
What is the free body diagram?When we talk about the free body diagram, we want to show the diagram that is incorporating all the forces that do act on the object as it is moving down the plane in the object.
b) The mass of the box is; Weight/ acceleration due to gravity = 9500 N/10 m/s^2
= 950 Kg
c) The net force is obtained as mass * acceleration = 950 Kg * 0.55 m/s^2
= 522.5 N
d) The normal force is the weight of the object which is 9,500 N
e) The applied force is obtained as mgsinθ = 950 * 10 * sin 25
= 4015 N
f) The force of gravity is the weight of the box = 9,500 N
e) The frictional force is; μmg cosθ = 0.4 * 950 * 10 * cos 25
=3444 N
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What term describes someone whose biological sex is both male and female
intersex (more specific term: hermaphroditism) might be what you're looking for
The type of spectrum is produced when electromagnetic radiation is emitted or absorbed as electrons change energy levels is an atom is ..
03: Hook's law suggests that F is directly proportional to -x, how much true you have found this statement in your experiment? Explain any differences.
Hooke's Law can be given as follows sometimes:
The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:
F = -kx
Where, F = Restoring force of a spring (Newtons, N)
k = Spring constant (N/m)
x = Displacement of the spring (m)
The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.
Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.
The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.
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The Earth is a sphere with a diameter of about 12,800 kilometers. Scientists believe that the Earth first formed
billion years ago and was larger then than it is now.
The Earth was so hot that all the rock was molten, i.e. in the
state.
We think that about 4.4 billion years ago the Earth had cooled down enough to let a
crust form on the surface.
Answer:
Explanation:
Earth is our home planet. Scientists believe Earth and its moon formed around the same time as the rest of the solar system. They think that was about 4.5 billion years ago. Earth is the fifth-largest planet in the solar system. Its diameter is about 8,000 miles. And Earth is the third-closest planet to the sun. Its average distance from the sun is about 93 million miles. Only Mercury and Venus are closer.
What Are Earth's Different Parts?
Earth consists of land, air, water and life. The land contains mountains, valleys and flat areas. The air is made up of different gases, mainly nitrogen and oxygen. The water includes oceans, lakes, rivers, streams, rain, snow and ice. Life consists of people, animals and plants. There are millions of species, or kinds of life, on Earth. Their sizes range from very tiny to very large.
Below Earth's surface are layers of rock and metal. Temperatures increase with depth, all the way to about 12,000 degrees Fahrenheit at Earth's inner core.
Earth's parts once were seen as largely separate from each other. But now they are viewed together as the "Earth system." Each part connects to and affects each of the other parts. For example:
Clouds in the air drop rain and snow on land.
Water gives life to plants and animals.
Volcanoes on land send gas and dust into the air.
People breathe air and drink water.
Earth system science is the study of interactions between and among Earth's different parts.
Someone please help me! And I will mark you as brainlist!!
1) A ball with a mass of 2.0 kg is thrown upward 1.2m calculate its gravitational potential energy into two significant figures. Gravity = 9.8 N/kg
• 2.4 J
• 1.4 J
• 120 J
• 24 J
2) Translation kinetic energy is defined as the energy of a system due to the motion of the system’s...
• center of mass
• axis of symmetry
• molecules
• rotational movement
PLEASE HELP!!
Answer:
1. G.P.E = 24 J
2. center of mass
Explanation:
Given the following data;
Mass = 2kg
Height, h = 1.2m
Acceleration due to gravity = 9.8 N/kg or m/s².
To find the gravitational potential energy;
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;
\( G.P.E = mgh\)
Where;
G.P.E represents potential energy measured in Joules.m represents the mass of an object. g represents acceleration due to gravity measured in meters per seconds square. h represents the height measured in meters.Substituting into the formula, we have;
\( G.P.E = 2*1.2*9.8 \)
G.P.E = 23.52 to 2 S.F = 24 Joules.
Translation kinetic energy is defined as the energy of a system due to the motion of the system’s center of mass. The center of mass is typically where the mass of the object or particle is concentrated.
A uniform rod of length l and mass m rests on supports at its ends. The right support (white triangle) is quickly removed. a) What is the force from the left support immediately thereafter? A uniform rod of length 2r and moment of inertia rests on top of two supports, each of which is a distance d away from the center where is a constant. The right support (white triangle) is quickly removed. b) What is the force from the left support immediately thereafter?
Answer:
Explanation:
For solving this question we will be using Newton's second law of motion in 2 different formats.
F = ma and \(\tau = I\alpha\)
Here F = net external force applied on the body
m = mass of the body
a = acceleration of the centre of mass of the body
\(\tau\) = net external torque on the body
I = moment of inertia of the body about given axis
\(\alpha\) = angular acceleration of the body
These are 2 forms of Newton's second law of motion first one is from transnational motion and second for rotational motion.
Kindly check the attached images below to see further step by step explanation to the question above.
what is the most effortless walking speed for a person with 90cm long legs if the length of each step is 90cm
Answer:
75 cm/second.
Explanation:
Formula:
Walking speed = stride length / time per step
Walking speed = 90cm/time per step
= 90cm/1.2 seconds (a common estimate time per step)
= 75cm/second.
One molecule of nitrous oxide warms Earth's atmosphere more than one molecule of carbon dioxide. And yet, new reports about global warming and climate change focus substantially on carbon dioxide and rarely mention nitrous oxide or other greenhouse gases that are more potent than carbon dioxide. Why might this be the case? Provide
reasons to justify your opinion.
GIVING BRAINLIEST
There are several reasons why carbon dioxide receives more attention than nitrous oxide or other greenhouse gases in discussions about global warming and climate change. They are:
QuantitySourcesMitigationWhat are the reasons about?Quantity: Carbon dioxide is the most abundant greenhouse gas in the atmosphere, accounting for about 78% of total radiative forcing. Nitrous oxide, on the other hand, is present in much lower concentrations, making up about 6% of total radiative forcing.
Sources: Carbon dioxide is primarily emitted through the burning of fossil fuels (such as coal, oil, and natural gas), which is a major contributor to human activities that drive climate change. Nitrous oxide, on the other hand, is primarily emitted through natural processes such as soil microbial activity and ocean currents.
Mitigation: Carbon dioxide has a relatively long atmospheric lifetime, meaning it stays in the atmosphere for a long time. Therefore, reducing carbon dioxide emissions can have a significant impact on slowing the rate of global warming. Nitrous oxide, however, has a relatively short atmospheric lifetime, meaning it stays in the atmosphere for a shorter time.
Therefore, reducing nitrous oxide emissions may not have as much of an impact on slowing the rate of global warming.
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A child is playing with a toy car, and it accelerates to the south from 1.2m/s to 6.3m/s. if the toy car's acceleration is 2.75m/s2, what is the amount of time that the child takes to accelerate the car? Show all your work.
Answer:
t = 1.9 s
Explanation:
By definition, acceleration is the rate of change of velocity with respect to time, which can be expressed as follows:\(a = \frac{v_{f} -v_{o} }{t_{f} - t_{o} } (1)\)
If we choose t₀ =0, ⇒ tif = tRearranging in (1), we get:\(v_{f} = v_{o} + a*t (2)\)
Solving (2) for t:\(t =\frac{v_{f}-v_{o}}{a} (3)\)
Replacing by the givens in (3):vf = 6.3 m/s
v₀ = 1.2 m/s
a = 2.75 m/s²
\(t =\frac{v_{f}-v_{o}}{a} = t =\frac{6.3m/s-1.2m/s}{2.75m/s2} = 1.9 s (4)\)
Which phrases accurately describe an elliptical galaxy? Check all that apply.
may be egg-shaped
may be spiral-shaped
has no recognizable shape
has no new stars being formed
has almost no gas or dust between stars
Answer:
May be egg shaped
Has no new stars being formed.
Has almost no gas or dust between stars.
Explanation:
Elliptical galaxy is the collection of many stars which are bounded together gravitationally, which is smooth and ellipsoidal and shape and the appearance is featureless.
Elliptical galaxy is ovoid or spherical masses of stars.
It is found in galaxy clusters and compact galaxies.
It has no gas or dust between stars which result in low rates of star formation.
It is formed When two spirals collide, they lose their familiar shape, morphing into the less-structured elliptical galaxies.
Elliptical galaxy is made of old stars and have no gas and dust.
An example is elliptical galaxy m60 which shines brightly and is egg shaped.
WHAT IS THE MEAING OF- Grouping Data
Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.
It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.
This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.
For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.
Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.
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Do this question by electric flux
A conducting sphere of radius 10cm has an unknown charge. If the electric field 20 cm from the centre of the sphere is \(1.5*10^{3}\) N/C and points radially inwards what is the net charge on the sphere.
Answer:
To find the net charge on the sphere using electric flux, we can use the formula:
Φ = Q/ε0
Where Φ is the electric flux, Q is the charge, and ε0 is the permittivity of free space.
Given that the electric field 20 cm from the center of the sphere is N/C and points radially inwards, we can use the formula for electric field due to a charged sphere to find the charge on the sphere:
E = kQ/r^2
Where E is the electric field, k is Coulomb's constant, Q is the charge, and r is the distance from the center of the sphere.
Substituting the given values, we get:
20 = (1/4πε0)(Q)/(0.2)^2
Solving for Q, we get:
Q = (20)(0.2)^2(4πε0)
Q = 0.64πε0 C
Now, substituting this value of Q in the formula for electric flux, we get: Φ = Q/ε0 = (0.64πε0)/(ε0) = 0.64π C
Therefore, the net charge on the sphere is 0.64π C.
A boy slides a book across the floor, using a force of 5 N over a distance of 2
m. What is the kinetic energy of the book after he slides it? Assume there is
no friction.
A. 5 J
B. 10 J
C. 20 J
D. 2.5 J
SUBMIT
The kinetic energy of the book after it is slids a distance of 2 meters will be 10 Joules.
How to determine the kinetic energy of an object?The work-energy theorem states that "the work done on an object is the change in its kinetic energy".
Hence;
Kinetic energy = work done
Note that: work-done is expressed as:
Work done = f × d
Where f is force applied and d is distance traveled.
Given that:
Force applied f = 5 newton
Distance d = 2 meters
Work done = ?
Plug these values into the above formula and solve for the workdone.
Work done = f × d
Work done = 5N × 2m
Work done = 10Nm
Work done = 10 Joules
Therefore, the kinetic energy is 10 Joules.
Option B) 10 J is the correct answer.
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Water flows at a speed of 13 m/s through a pipe that has a diameter of 1.2 m. What is the
diameter of the smaller end of the pipe that the water comes out with a speed of 30 m/s?
The diameter of the smaller end of the pipe is approximately 0.78 meters.
To determine the diameter of the smaller end of the pipe, we can use the principle of conservation of mass. According to this principle, the mass flow rate of water should remain constant throughout the pipe.
The mass flow rate is given by the equation:
Mass flow rate = density of water * cross-sectional area * velocity
Since the density of the water remains constant, we can write:
Cross-sectional area1 * velocity1 = Cross-sectional area2 * velocity2
Given that the velocity1 is 13 m/s, the diameter1 is 1.2 m, and the velocity2 is 30 m/s, we can solve for the diameter2 using the equation:
(pi * (diameter1/2)^2) * velocity1 = (pi * (diameter2/2)^2) * velocity2
Simplifying the equation:
(1.2/2)^2 * 13 = (diameter2/2)^2 * 30
Calculating the equation:
(0.6)^2 * 13 = (diameter2/2)^2 * 30
0.36 * 13 = (diameter2/2)^2 * 30
4.68 = (diameter2/2)^2 * 30
Dividing both sides by 30:
0.156 = (diameter2/2)^2
Taking the square root of both sides:
0.39 = diameter2/2
Multiplying both sides by 2:
0.78 = diameter2
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An aseroid with a mass of 8.4x10^8 kg and a planet with a mass of 6.2x10^23 kg come close to each other by a distance of 8x10^5 m. what is the force of gravity that the asteroid and the planet have on each other ?
So, the force of gravity that the asteroid and the planet have on each other approximately
\( \boxed{\sf{5.43 \times 10^{10} \: N}} \)
IntroductionHi ! Now, I will help to discuss about the gravitational force between two objects. We already know that gravitational force occurs when two or more objects interact with each other at a certain distance and generally orbit each other to their center of mass. For the gravitational force between two objects, it can be calculated using the following formula :
\( \boxed{\sf{\bold{F = G \times \frac{m_1 \times m_2}{r^2}}}} \)
With the following condition :
F = gravitational force (N)G = gravity constant ≈ \( \sf{6.67 \times 10^{-11}} \) N.m²/kg²\( \sf{m_1} \) = mass of the first object (kg)\( \sf{m_2} \) = mass of the second object (kg)r = distance between two objects (m)Problem SolvingWe know that :
G = gravity constant ≈ \( \sf{6.67 \times 10^{-11}} \) N.m²/kg²\( \sf{m_1} \) = mass of the first object = \( \sf{8.4 \times 10^8} \) kg.\( \sf{m_2} \) = mass of the second object = \( \sf{6.2 \times 10^{23}} \) kg.r = distance between two objects = \( \sf{8 \times 10^5} \)What was asked :
F = gravitational force = ... NStep by step :
\( \sf{F = G \times \frac{m_1 \times m_2}{r^2}} \)
\( \sf{F = 6.67 \times 10^{-11} \times \frac{8.4 \cdot 10^8 \times 6.2 \cdot 10^{23}}{(8 \times 10^5)^2}} \)
\( \sf{F = \frac{347.374 \times 10^{-11 + 8 + 23}}{64 \times 10^10}} \)
\( \sf{F \approx 5.43 \times 10^{20 - 10}} \)
\( \boxed{\sf{F \approx 5.43 \times 10^{10} \: N}} \)
ConclusionSo, the force of gravity that the asteroid and the planet have on each other approximately
\( \boxed{\sf{5.43 \times 10^{10} \: N}} \)
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8. How much power is used if you use a 20 N force to push a shopping cart 3.5 m in 2 s?
The power used, given that a force of 20 N is used to push the shopping cart 3.5 m in 2 seconds is 35 W
How do i determine the power used?First, we shall determine the work done in pushing the cart. Details below:
Force used (F) = 20 NDistance (d) = 3.5 mWork done (Wd) = ?Wd = Fd
Wd = 20 × 3.5
Wd = 70 J
Finally, we shall determine the power used in pushing the cart. Details below:
Work done (Wd) = 70 JTime (t) = 2 secondsPower used (P) = ?P = Wd / t
P = 70 / 2
P = 35 W
Thus, we can conclude that the power used is 35 W
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3) Vector A is 2.8 cm at 60° above the positive x-axis. Vector B is 1.90 cm at 60 below the
positive x-axis. Use components to find the following
a) A+ B
b) A-B
c) B-A
The following vector components are:
a) A+ B - 84.21°
b) A-B - 18.74°
c) B-A - -84.21°
How to find vector components?To use components to find the given vectors, break each vector into its x and y components using trigonometry.
Assume the positive x-axis points to the right and the positive y-axis points up.
For vector A, the magnitude of the x-component is given by Acos(60°) and the magnitude of the y-component is given by Asin(60°),
Ax = Acos(60°) = 2.8 cm × 0.5 = 1.4 cm
Ay = Asin(60°) = 2.8 cm × 0.866 = 2.425 cm
For vector B, the negative sign since the vector is below the x-axis,
Bx = Bcos(60°) = 1.9 cm × 0.5 = 0.95 cm
By = -Bsin(60°) = -1.9 cm × 0.866 = -1.6494 cm
a) To find A + B, add the x and y components separately:
(A + B)x = Ax + Bx = 1.4 cm + 0.95 cm = 2.35 cm
(A + B)y = Ay + By = 2.425 cm - 1.6494 cm = 0.7756 cm
Then, the vector A + B has a magnitude of √[(2.35 cm)² + (0.7756 cm)²] = 2.466 cm and an angle of tan⁻¹(0.7756 cm / 2.35 cm) = 18.74° above the positive x-axis.
b) To find A - B, subtract the x and y components separately:
(A - B)x = Ax - Bx = 1.4 cm - 0.95 cm = 0.45 cm
(A - B)y = Ay - By = 2.425 cm + 1.6494 cm = 4.0744 cm
Then, the vector A - B has a magnitude of √[(0.45 cm)² + (4.0744 cm)²] = 4.091 cm and an angle of tan⁻¹(4.0744 cm / 0.45 cm) = 84.21° above the positive x-axis.
c) To find B - A, subtract the x and y components separately:
(B - A)x = Bx - Ax = 0.95 cm - 1.4 cm = -0.45 cm
(B - A)y = By - Ay = -1.6494 cm - 2.425 cm = -4.0744 cm
Then, the vector B - A has a magnitude of √[(-0.45 cm)² + (-4.0744 cm)²] = 4.091 cm and an angle of tan⁻¹(-4.0744 cm / -0.45 cm) = -84.21° below the positive x-axis.
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A scale measures the weight of a light object to be 11.000 lbs ± 0.034 lbs. what is the uncertainty if this same scale is use to measure an object that weights 78.000 lbs? Assume that the percent uncertainty of the scale remains constant
1)0.034lbs
2)0.044lbs
3)0.310lbs
4)0.240Ibls
The uncertainty of the heavy object if the scale remains constant is 0.24 lbs.
What is uncertainty in measurement?This is the error associated in an attempt measure the object accurately.The percent uncertainty in measuring the light weight object is calculated as follows;
\(= \frac{0.034}{11} \times 100\%\\\\= 0.309\%\)
The uncertainty of the heavy object if the scale remains constant is calculated as follows;
\(= \frac{0.309}{100} \times 78.0 \ lbs\\\\= 0.24 \ lbs\)
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experiments allow psychologists to isolate different effects by manipulating an independent variable, and keeping other variables constant. true or false?
Answer:
True
Explanation:
the independent variable would be like if the psychologist is experimenting the impact of sleep deprivation, sleep deprivation would be the independent variable that is being manipulated or changing its level systematically in the experiment.
What is the average velocity of atoms in 1.00 mol of neon (a monatomic gas) at 288K?Use the equation 1/2mv^2 =3/2nRTFor m use 0.01000 kg. Remember that R-8.31 J/(mol.K).A. 847 m/sB. 718,000 m/sC. 8.47 m/sD. 71.8 m/s
the Given
*The number of mol of neon is n = 1 mol.
*The temperature of the neon gas is T = 288 K.
*The mass of the neon gas is m = 0.01 kg.
*The gas constant R is R = 8.31 J/(mol.K).
To find: The average velocity of atoms of neon (v).
According to the given equation,
\(\frac{1}{2}mv^2=\frac{3}{2}nRT\)Substitute the known values.
\(\begin{gathered} \frac{1}{2}\times0.01\text{ kg}\times v^2=\frac{3}{2}\times1\text{ mol}\times8.31\text{ J/mol.K}\times288\text{ K} \\ 5\times10^{-3}\text{ kg}\times v^2=\frac{3}{2}\times2393.28\text{ J} \\ 5\times10^{-3}\text{ kg}\times v^2=3589.92\text{ J}\times\frac{1\frac{kg.m^2}{s^2}}{1\text{ J}} \\ v^2=\frac{3589.92\text{ }\frac{kg.m^2}{s^2}}{5\times10^{-3}\text{ kg}} \\ v^2=717984\frac{m^2}{s^2} \\ v=\sqrt[]{717984\frac{m^2}{s^2}} \\ v=847.33\text{ m/s} \\ v\cong847\text{ m/s} \end{gathered}\)The average velocity of atoms of neon is 847.33 m/s. Thus, option (A) is the correct answer.
If Ted traveled 0KM In 60Mins/1hr what is his average speed?
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The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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A block of wood is attached to a very lightweight metal rod, which is attached to a fixed pivot point on a table. The block is able to slide on the table with negligible friction, and the pivot is also free to rotate with negligible friction. The block's mass is M and the rod's length is ℓ. A bullet is moving parallel to the table and perpendicular to the rod when it collides and embeds within the block. The bullet's speed just before entering the block is v and its mass is m.
1. Find the angular momentum of the combined bullet–block system about the vertical pivot axis. (Use any variable or symbol stated above as necessary. Enter the magnitude.)
2. Find the fraction of the original kinetic energy of the bullet that is converted into internal energy within the bullet-block system during the collision. (Use any variable or symbol stated above as necessary.)
1. The angular momentum of the combined bullet-block system about the vertical pivot axis is 0.
2. The fraction of the original kinetic energy of the bullet converted into internal energy within the bullet-block system during the collision is given by [m * v² - (M + m) * V²] / [m * v²].
1. To find the angular momentum of the combined bullet-block system about the vertical pivot axis, we need to consider the initial and final angular momentum.
Initially, before the collision, the bullet has no angular momentum about the pivot axis since it is moving parallel to the table and perpendicular to the rod.
After the collision, when the bullet embeds within the block, the combined bullet-block system starts rotating about the pivot axis due to the conservation of angular momentum.
The angular momentum of the system can be calculated using the formula:
Angular momentum = moment of inertia × angular velocity
The moment of inertia of the system depends on the distribution of mass and the axis of rotation. Assuming the block and bullet have negligible rotational inertia compared to the rod, we can consider the moment of inertia to be that of the rod.
The moment of inertia of a rod rotating about one end (pivot) is given by:
I = (1/3) * M * ℓ²
where M is the mass of the block, and ℓ is the length of the rod.
The angular velocity (ω) can be determined by considering the conservation of angular momentum:
Initial angular momentum = Final angular momentum
0 = (1/3) * M * ℓ² * ω
Since the initial angular momentum is zero, the final angular momentum of the system is also zero.
Therefore, the angular momentum of the combined bullet-block system about the vertical pivot axis is 0.
2. To find the fraction of the original kinetic energy of the bullet that is converted into internal energy within the bullet-block system during the collision, we can use the principle of conservation of kinetic energy.
The initial kinetic energy of the bullet before the collision is given by:
Initial kinetic energy = (1/2) * m * v²
After the collision, the bullet embeds within the block, and both the bullet and the block gain internal kinetic energy due to their rotational motion.
The final kinetic energy of the bullet-block system is given by:
Final kinetic energy = (1/2) * (M + m) * V²
where V is the final velocity of the combined bullet-block system after the collision.
Since the bullet and block are now rotating about the pivot axis, part of the initial kinetic energy is converted into internal rotational kinetic energy.
The fraction of the original kinetic energy converted into internal energy can be calculated as:
Fraction of kinetic energy converted = (Initial kinetic energy - Final kinetic energy) / Initial kinetic energy
Substituting the values:
Fraction of kinetic energy converted = [(1/2) * m * v² - (1/2) * (M + m) * V²] / [(1/2) * m * v²]
Simplifying the equation, we can cancel out common terms:
Fraction of kinetic energy converted = [m * v² - (M + m) * V²] / [m * v²]
Therefore, the fraction of the original kinetic energy of the bullet converted into internal energy within the bullet-block system during the collision is given by [m * v² - (M + m) * V²] / [m * v²].
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Is Saturn less dense than water which has a
density of 997 kg/m³? Find out by calculating the density of Saturn in kg/m³. The mass of Saturn is 5.68 x 1026 kg, and its radius is 5.6 x 107 m.
Density of Saturn:
The density of water at STP, which is \(997 kg/m^3\), we can see that Saturn is less dense than water.
To determine whether Saturn is less dense than water, we must compute its density and compare it to the density of water at standard temperature and pressure (STP), which is \(997 kg/m^3\).
Saturn's density can be computed using the following formula:
density equals mass divided by volume
Saturn's mass and volume may be computed given its mass and radius.
The volume of Saturn can be determined using the sphere volume formula:
volume =\((4/3) \pi (r^3)\)
where r is Saturn's radius.
Filling in the blanks:
volume = \((4/3) \pi (5.6 \times 107) m^3\)
8.27 x 1023 \(m^3\)volume
Saturn's mass is given as \(5.68 \times 10^{26} kg.\)
We can now compute Saturn's density:
density equals mass divided by volume
density= \((5.68 x 10^{26 }kg\)) /\((8.27 \times 10^{23 }\)m³) a density of\(687 kg/m^3\)
This is due to the fact that Saturn is mostly made up of hydrogen and helium, which are far less dense than water. In reality, Saturn is the least dense planet in the Solar System, and it would float in a large enough body of water.
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explain the appearance of a white cloth with blue stripes in a yellow light
Yellow light is produced by combining red and green lights. The counterpart of blue light with yellow light is blue light combined with red lights. Three basic colours of light are combined to produce white light.
Does blue light absorb yellow light?Blue light can be absorbed by a yellow pigment. So light that shines just on paper is therefore depleted of blue. Red light is now gone. The paper will seem red if it reflects the red light.
Why does anything appear blue in white light?White light causes an object to seem blue since it reflects just blue light and absorbs all other colours. Since there isn't any colour to reflect whenever that object is placed in red light, it absorbs all of the red light that strikes it and appears black.
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