5. A book is placed on a table. If the book exerts a force of 15 N'on the table,
how much force does the table exert on the book?
A. ON
C. 9.8 N
B. 3 N
D. 15 N​

Answer:

28.5 m/s

Explanation:

There are 2 different velocities: the train velocity and yours velocity. They're in opposite directions, so one is positive and other is negative. Take the forward direction as the positive:

V = +30 -1.5

V = 28.5 m/s

28.5 m/s forward

Consider the train as a “positive movement” and you as a “negative movement” combine those and take the larger direction

The pH of a 0.29 M solution of a monoprotic weak acid with a Ka of 6.2×10⁻⁶ is 2.94.

To find the pH of a 0.29 M solution of a monoprotic weak acid with a Ka of 6.2×10⁻⁶, we first need to calculate the concentration of H+ ions in the solution.

Ka is the acid dissociation constant, which represents the strength of the acid. It is defined as [H+][A-]/[HA], where [H+] is the concentration of H+ ions, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid.

Since the acid is monoprotic, we can assume that all of the weak acid dissociates into H+ and A-. Therefore, we can write the equation:

Ka = [H+][A-]/[HA] = [H+]²/[HA]

Rearranging this equation, we get:

[H+] = sqrt(Ka x [HA])

Substituting the given values, we get:

[H+] = sqrt(6.2×10⁻⁶ x 0.29) = 1.15×10⁻³ M

Now that we know the concentration of H+ ions in the solution, we can calculate the pH using the formula:

pH = -log[H+]

Substituting the calculated value, we get:

pH = -log(1.15×10−3) = 2.94

Therefore, the pH of a 0.29 M solution of a monoprotic weak acid with a Ka of 6.2×10⁻⁶ is 2.94.

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Answer:

A

Explanation:

No motion, no work.

The formula is W = F * d. If d is 0 then the work is 0.

I misread the original question. The elephant is not going anywhere soon. The girl is moving.

So the answer is A

Answer:

Option A

The man trying to move the elephant.

Explanation:

In the given picture we can see that

We know that

Here,

The girl is moving a wagon that means it displaces

So

W = F • d (distance be x)

W = Fx

Here, It shows work done

Now,

Man unable to move elephant that means it doesn't displaces, d = 0

So,

W = F • d (here d = 0)

W = F • 0

W = 0

Here, It shows no work done.

-TheUnknownScientist 72

Answer: Some elements like potassium, uranium, and thorium are naturally radioactive and give off gamma rays as they decay, but all elements can be excited by collisions with cosmic rays to produce gamma rays. The HEND and Neutron Spectrometers on GRS directly detect scattered neutrons, and the Gamma Sensor detects the gamma rays.

Explanation: searching

The centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8). Formulae used to find the centre of mass are as follows:x bar = (1/M)*∫∫∫x*dV, where M is the total mass of the system y bar = (1/M)*∫∫∫y*dVwhere M is the total mass of the system z bar = (1/M)*∫∫∫z*dV, where M is the total mass of the systemThe region bounded by y=9-x^2 and y=5/2x, and the z-axis is shown in the attached figure.

The two curves intersect at (-3, 15/2) and (3, 15/2). Thus, the total mass of the region is given by M = ∫∫ρ*dA, where ρ = density. We can assume ρ = 1 since no density is given.M = ∫[5/2x, 9-x^2]∫[0, x^2+5/2x]dAy bar = (1/M)*∫∫∫y*dVTherefore,y bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]y*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]ydA...[1].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore,y bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]y*dxdy...[2].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.Substituting the values and evaluating the integral, we get y bar = (1/M)*[(9-5/2)^2/2 - (9-(15/2))^2/2]= (1/M)*(25/2)...[3].

Also, the x coordinate of the center of mass is given by,x bar = (1/M)*∫∫∫x*dVTherefore,x bar = (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]x*dA= (1/M)*∫[5/2x, 9-x^2]∫[0, x^2+5/2x]xdA...[4].

The limits of integration in the above equation are from 5/2x to 9-x^2 for x and from 0 to x^2+5/2x for y.To evaluate the above integral, we need to swap the order of integration. Therefore, x bar = (1/M)*∫[0, 3]∫[5/2, (9-y)^0.5]xy*dxdy...[5].

The limits of integration in the above equation are from 0 to 3 for y and from 5/2 to (9-y)^0.5 for x.

Substituting the values and evaluating the integral, we get x bar = (1/M)*[63/8]= (1/M)*(63/8)...[6]Thus, the centre of mass of the region is bounded by y=9-x^2 y=5/2x, and the z-axis is (3.5, 33/8).

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The estimated force between the marbles, after the transfer of 100 billion electrons, is approximately 5.75 × 10^-5 Newtons.

The force between two charged objects can be estimated using Coulomb's law, which states that the force (F) between two charged particles is directly proportional to the product of their charges (q1 and q2) and inversely proportional to the square of the distance (r) between them. Mathematically, it is expressed as F = \(\frac{k (|q1| |q2|) }{r^{2} }\), where k is the electrostatic constant.

In this scenario, we have two small neutral marbles. When 100 billion electrons (1011 e) are transferred from one marble to the other, one marble gains a net negative charge equal to the charge of the electrons transferred, and the other marble gains an equal positive charge.

To estimate the force, we need to determine the charges involved and the distance between the marbles. The elementary charge (e) is approximately 1.6 × \(10^-19\) Coulombs. Therefore, the charge transferred is approximately (1011 e) x (1.6 × \(10^-19\) C/e) = 1.6 × \(10^-8\) C.

Assuming the marbles have equal but opposite charges, each marble would have a charge of 0.8 × \(10^-8\) C. The distance between the marbles is given as 10 cm, which is equivalent to 0.1 meters. Substituting these values into Coulomb's law, we have F = k (0.8 x \(10^-8\) C * 0.8 × \(10^-8\) C) / (0.1 m)\(^2\).

The electrostatic constant (k) is approximately 8.99 × 10^9 N m^2/C^2.

Calculating the force, we get F ≈ 5.75 × \(10^-5\) N. Therefore, the estimated force between the marbles, after the transfer of 100 billion electrons, is approximately 5.75 × \(10^-5\) Newtons.

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Answer:

the first on the left goes with the 3rd on the right

second left last right

3rd goes with 1st

4th goes with 5th

5th goes with 4th

and last but not least 6th goes with the second

Explanation:

Answer: the initial velocity represented by the graph is 5 m/s

Explanation:

Initial velocity of the object represented by the graph is 5 m/s.

Graph is not seen tin this problem but the question can be like this as shown in the picture.

In this picture we can see that Velocity is increasing linearly with the time. Initially at t = 0 velocity of the object is 5m/s and velocity increases with time. Velocity becomes 10m/s at 1st second, it becomes 15 for 3rd second, it becomes 20 for 4th second and final becomes 25m/s for 5th second.

Acceleration is rate of change of velocity with the time. In this graph we can see that velocity is changing with time hence body is accelerating.

Initial velocity is nothing but the velocity of the object with which it was started. From the graph we can see that the object has started with velocity 5m/s at 0th second(initial stage).

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Answer:

1. the graph is showing the speed of the object at different times.

Explanation:

2. the object is slowing down

Answer: A Neutron.

I know this is correct. Thank's and yw :3

Answer:

"element"= There are four basic sentence patterns based on sentence construction element

Answer:

1st one. Element

2nd one. Compound

Explanation:

Answer: 0.25 m/s

Explanation:  Speed = wavelengt · frequency  

v = λf   and frequency is 1/period  f = 1/T

Then v = λ/T = 5 m / 20 s = 0.25 m/s

Answer:

TRUE

Explanation:

a. The speed of the object after traveling 48.3 m is approximately 20.7 m/s [E]. b. If the initial and final speeds are the same as before, the object will travel approximately 46.5 m.

a. To calculate the speed of the object after traveling a certain distance, we need to consider the work done by friction and the change in kinetic energy.

The work done by friction is given by:

Work = force of friction * distance.

The force of friction can be calculated using the formula:

Force of friction = coefficient of kinetic friction * normal force.

The normal force is the force exerted by the surface perpendicular to the object's motion. On a horizontal surface, the normal force is equal to the object's weight, which can be calculated as:

Weight = mass * gravity.

In this case, the mass of the object is 0.252 kg, and the acceleration due to gravity is approximately 9.8 m/s^2.

Normal force = 0.252 kg * 9.8 m/s^2.

Next, we can calculate the work done by friction:

Work = (coefficient of kinetic friction) * (normal force) * distance.

The change in kinetic energy is equal to the work done by friction:

Change in kinetic energy = Work.

Finally, we can calculate the final speed using the equation:

Final speed^2 = Initial speed^2 + (2 * change in kinetic energy / mass).

Initial speed = 23.4 m/s [E].

Distance = 48.3 m.

Coefficient of kinetic friction = 0.500.

Mass = 0.252 kg.

b. If the initial and final speeds are the same as before, it means the change in kinetic energy is zero. We can use the same formula as in part a to calculate the distance traveled, but this time the change in kinetic energy is set to zero.

Initial speed = 23.4 m/s [E].

Final speed = 20.7 m/s [E].

Coefficient of kinetic friction = 0.475.

Mass = 0.252 kg.

a. The speed of the object after traveling 48.3 m is approximately 20.7 m/s [E].

b. If the initial and final speeds are the same as before, the object will travel approximately 46.5 m. These calculations are based on considering the work done by friction, the change in kinetic energy, and using relevant formulas related to kinetic friction and motion.

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The magnitude of the gravitational force is 7×10⁻⁷ N and the magnitude of the gravitational force due to Jupiter is 1.35×10⁻6 N.

Gravitational potential energy is the energy which a body posses because of its position.

The gravitational potential energy of a body is given as,

= G = Fr²/Mm

Here, (m) is the mass of the body, (F) is the gravitational force and (r) is the height of the body.

The mass of baby is 4.20 kg and mass of father is 100 kg. The distance between them is 0.200 m. Put the values in the above formula as:

= 6.67 X 10⁻¹¹ =  F (0.200)² / 100 X 4.20

= F = 7 X 10⁻⁷ N

The magnitude of the force on the baby due to Jupiter if it is at its closest distance to Earth, some 6.29×1011 m.

Put the values in the above formula again as:

= 6.67 X 10⁻¹¹ =  F (6.29 X 10¹¹)² / 1.9 X 10²⁷ X 4.20

= F = 1.35 X 10⁻⁶ N

Thus, the magnitude of the gravitational force is 7×10⁻⁷ N and the magnitude of the gravitational force due to Jupiter is 1.35×10⁻6 N.

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true

Explanation:

this is because melting point and boiling point decreases down the group because they are held together by attractions between positive nuclei and delocalised electrons

A body's mass is the total amount of its material. Gravitational pull on a body is represented by weight.

The relationship between mass and weight Mass is a measure of inertia, whereas weight is a measure of force.

Both of these names are frequently used in the same sentence. Calculating how much matter a body contains requires knowing its mass.

Weight is a unit of measurement for the force that gravity's acceleration has on a mass.

Weight is a measurement of how the force of gravity works upon a mass, whereas mass is a measure of the amount of matter in a material.

In order to determine how much matter a body contains, we need to use its mass.

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The amount of time that passes from when  this skateboarder begins to slow down until she begins to  move back down the incline is 8.75 seconds.

Given the following data:

To calculate the amount of time that passes from when  this skateboarder begins to slow down until she begins to  move back down the incline, we would apply the first equation of motion;

Mathematically, the first equation of motion for a decelerating object is given by this formula;

\(V=U-at\)

Where:

Substituting the given parameters into the formula, we have;

\(1.75 = 0-(-0.2)t\\\\1.75=0.2t\\\\t=\frac{1.75}{0.2}\)

Time, t = 8.75 seconds.

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To put it another way, the gravitational potential energy directly relates to how high an item is above the ground. Therefore, an object should be raised higher to enhance its gravitational potential energy. The gravitational potential energy increases with height.

The mass and height of an object affect how much gravitational potential energy it has. The more gravitational potential energy is held by an object the heavier it is and the higher it is above the surface of the earth. As weight and height increase, gravitational potential energy rises.

The gravitational potential energy increases as the planet get further away, but the speed and kinetic energy decrease. Energy and angular momentum are conserved throughout the entire orbit. This indicates that throughout the orbit, the Earth's distance from the Sun r changes.

Because an object's gravitational potential energy is precisely proportional to its height above the zero point, doubling its height will result in a doubling of its gravitational potential energy. For every threefold increase in height, the gravitational potential energy triples.

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Answer:

2 m/s

Explanation:

Applying,

The law of conservation of momentum

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m')............... Equation 1

Where m = mass of the first freight car, m' = mass of the second freight car, u = initial velocity of the first freight car, u' = initial velocity of the second freight car, V = final combined velocity/ speed.

make V the subject of the equation

V = (mu+m'u')/(m+m')........... Equation 2

From the question,

Given: m = 1234 kg, m' = 2468 kg, u = 6 m/s, u' = 0 m/s (at rest)

Substitute these values into equation 2

V = [(1234×6)+(2468×0)]/(1234+2468)

V = 7404/3702

V = 2 m/s

Answer:

76 seconds

Explanation:

Using the formula t=vf-vo/a, where t=time, vf= final velocity, v0= initial velocity, and a= acceleration, we can solve for your problem.

Plug in known variables...

t=200-10/a

we can solve for a by using the formula F=ma where f=force, m= mass, and a=acceleration and rearranging it to solve for a.

a=F/m

Plug in known variables...

a=250N/100kg

a=2.5m/s^2

Plug in our newly found acceleration of 2.5 m/s^2 into our first equation and solve....

t=190/2.5

t=76 seconds

The word from the list that best fits the definition increases the number of sunspots that can lead to warmer climates.

Sunspots are transitory spots on the Sun's photosphere that appear to be deeper than the surrounding areas.

They are zones of reduced surface heat caused by magnetic field flux concentrations that prevent convection.

Sunspots usually form in pairs with opposite magnetic polarities. This has an impact on the temperature on Earth, as well as radio reaction. The Earth would presumably be colder if sunspots didn't exist.

When sunspots form, they produce an increase in UV radiation that radiates from the sunspots' outer ring as they approach Earth.

This increase in UV radiation has an impact on the chemistry of the outer environment as well as the Earth's energy balance.

The idea that sunspots have an impact on Earth's ecology is still controversial, although it does exist.

Hence the words from the list that best fits the definition increase the number of sunspots that can lead to warmer climates.

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For a nearsighted eye that can see faraway objects when relaxed but has trouble focusing on nearby objects at x = 2.0, eyeglasses with negative power (concave lenses) should be used to correct the vision.

In nearsightedness (myopia), the eyeball is typically longer or the cornea is more curved than normal, causing light to focus in front of the retina instead of directly on it. This results in blurred vision for objects that are far away while the eye is in a relaxed state.

To correct nearsightedness and achieve normal vision, concave lenses are used. Concave lenses are thinner at the center and thicker at the edges, diverging the light rays before they enter the eye. The power of a lens is measured in diopters (D), and it represents the reciprocal of the focal length in meters.

In this case, the eye can see faraway objects when relaxed, indicating that the eye's accommodation for distance vision is functioning properly. However, the eye has difficulty focusing on an object at x = 2.0, which suggests a problem with near vision. To correct this, eyeglasses with a negative power (concave lenses) are required. The power of the concave lenses would be determined by an eye examination to precisely determine the amount of nearsightedness and the required corrective power. By using the appropriate power of concave lenses, the light entering the eye is properly refracted, allowing for clear vision at the desired distance.

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Answer:

here's the answers!

Explanation:

A mover carries a box up a flight of stairs.

A mover carries a box across a room.

A weightlifter lifts a barbell off the ground.

hope it helps u!

Answer:

A, D, E

Explanation:

Did it

The plate separation of the parallel-plate capacitor is 8.72 × 10−4 m.

To solve for the plate separation of the parallel-plate capacitor, we can use the formula:

C = ε0 * (A/d)

Where:
C = capacitance (6.5 pF)
ε0 = permittivity of vacuum (8.8542 × 10−12 C 2 /N · m2)
A = plate area (6.4 cm2 or 6.4 × 10−4 m2)
d = plate separation (unknown)

Substituting the values given, we have:

6.5 × 10−12 = (8.8542 × 10−12) * (6.4 × 10−4/d)

Simplifying and solving for d, we get:

d = (8.8542 × 10−12 * 6.4 × 10−4) / 6.5 × 10−12
d = 8.72 × 10−4 m

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It accelerates at about 32 feet per second every second, so it starts falling at zero feet per second and, one second later it is traveling at 32 feet per second. That means that its average speed is 16 feet per second, so it will fall 16 feet in the first second.