A car with a mass of 1,600 kg is traveling at a speed of 25 m/s. What is the momentum of
the car?
64 kg m/s
0.015 kg m/s
40,000 kg m/s
0.39 kg m/s

Answer:

I would agree with the statement. it's not just the body, but everything that we see is almost 99.9999% empty space

The mass spectrometer separates ions of different masses by utilizing the relationship between the strength of the magnetic field, the accelerating voltage, the charge-to-mass ratio of the ions, and the resulting radius of the circular path

From the formula in the question;

B is a symbol for the magnetic field's intensity as it is applied to the mass spectrometer.

The accelerating voltage used to move the ions is called Vaccelm.

The charge of the ion, specifically its charge-to-mass ratio (q/m), is represented by the letter q.

The mass spectrometer may selectively alter the radius of the circular route for various ions by varying the magnetic field's intensity (B). This makes it possible to spatially segregate ions with various masses based on their various radii. The ions' locations and masses can then be measured using detectors placed along the journey.

Learn more about mass spectrometer:brainly.com/question/29217778

#SPJ1

The focal length of the lens is 2m and the position of the image is 6 m.

The size of the image formed depends on the position of the object from the lens.

\(M = \frac{v}{u}\)

where;

The image distance is calculated as follows;

\(2 = \frac{v}{3} \\\\v = 2(3) \\\\v = 6 \ m\)

The focal length of the lens is calculated as follows;

\(\frac{1}{f} = \frac{1}{v} + \frac{1}{u}\\\\\frac{1}{f} = \frac{1}{6} + \frac{1}{3} \\\\\frac{1}{f} = \frac{3}{6} \\\\f = 2m\)

Learn more about image formed by converging lens here: https://brainly.com/question/22394546

Answer:

The correct answer is D. solids and liquids because their particles are arranged more closely together.

ω = sqrt( k/m )

ω: angular frequency; m: mass; k: spring constant

ω = 2π/T

T: period (how long it takes for one revolution)

T = 4.59s/10rev = 0.459s/rev

ω = 2π/T = ω = 2π/0.459

ω = 13.6889 radians/s

One revolution, or 2π radians, is 8 cm. (4 cm to stretch out, the same 4 cm to retract)

13.6889 radians/s * (4cm/2πradians) = 86.01 cm/s

ω = 86.01 cm/s = 0.086 m/s

Let's take the first example, where mass is 50g and angular freq. is 4.59s.

50g = 0.05 kg (kilograms are standard in SI, not grams, and are used more directly in calculations relating to force)

ω = sqrt( k/m )

0.086 = sqrt( k/0.05 )

Square both sides

0.007396 = k/0.05

multiply both by 0.05

k = 0.0003698 N/m = 3.698 * 10^-4 N/m

Let's graph frequency in relation to mass (mass is the independent variable)

Let's calculate the slope of the period-to-mass graph

m (slope) = (T2 - T1)/(m2 - m1) (change in frequency over change in mass)

Let's use the second example for T2 and T2, and the first for ω1 and m1.

m = (6.32-4.59)/(100-50) = 1.73/50

m = 0.0346 seconds/gram, which means for every gram of mass added, the period for 10 revolutions increases by 0.0346 seconds.

(a)The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).

(b)The weight of Curiosity on Earth is approximately 8820 Newtons.

a) The relationship between weight (P) and mass (m) is given by the formula P = m * g, where g represents the acceleration due to gravity. The units for weight are typically expressed in Newtons (N), while mass is measured in kilograms (kg).

b) To calculate the weight of Curiosity on Mars, we need to determine the acceleration due to gravity on Mars. The acceleration due to gravity on Mars is approximately 3.71 m/s². Using the weight formula, we have P = m * g = 900 kg * 3.71 m/s² = 3339 N. Therefore, the weight of Curiosity on Mars is approximately 3339 Newtons.

c) The weight of Curiosity on Earth is significantly greater compared to its weight on Mars. On Earth, the acceleration due to gravity is approximately 9.8 m/s². Using the weight formula, we have P = m * g = 900 kg * 9.8 m/s² = 8820 N. Therefore, the weight of Curiosity on Earth is approximately 8820 Newtons.

The difference in weight between Earth and Mars is important because weight is directly related to the force of gravity. The greater weight on Earth indicates a stronger gravitational force, which affects the overall dynamics and requirements for missions like Curiosity.

It affects the launch and landing processes, the structural integrity of the spacecraft, the fuel and energy requirements, and the ability to conduct experiments and operate the robotic systems effectively. Understanding these differences is crucial for mission planning, spacecraft design, and mission success.

For more questions on Newtons, click on:

https://brainly.com/question/28171613

#SPJ8

355.7 meter/ sec is the speed of sound in air at 108°F temperature because with the increase in temperature the speed of sound increases.

The speed of sound is directly proportional to the temperature. We know that directly proportional means when the temperature increases, the speed of sound also increases while on the other hand, when the temperature decreases, the speed of sound also decreases which shows direct relationship. That's why the speed of sound is 355.7 meter/ sec in air at 108°F temperature.

So we can conclude that 355.7 meter/ sec is the speed of sound in air at 108°F temperature because with the increase in temperature the speed of sound increase.

Learn more about speed here: https://brainly.com/question/13943409

#SPJ1

Answer:

Attitude, motivation and determination

Explanation:

Let me know if I'm right.

The factors leading to the success through the challenging physical activities are Attitude, motivation and determination.

Although the information regarding the live session is not mentioned, but as a general point of view, the major factors that need to considered while undergoing through the challenging physical activities are as follows:

Thus, we can conclude that the factors leading to the success through the challenging physical activities are Attitude, motivation and determination.

Learn more about the factors affecting the success here:

https://brainly.com/question/13958968

Answer:

The mass of the planet  is \(1.9407\times10^{27}\ kg\)

Explanation:

Given that,

Time period = 42 hours = 151200 sec

Orbital radius = 0.002819 AU = 421716397.5 m

Mass of moon \(m=8.932\times10^{22}\ kg\)

We need to calculate the mass of the planet

Using Kepler’s third law

\(T^2\propto a^3\)

\(T^2=\dfrac{4\pi^2}{G(M+m)}\times a^3\)

Where, a = orbital radius

T = time period

G = gravitational constant

M = mass of moon

m = mass of planet

Put the value into the formula

\((151200)^2=\dfrac{4\pi^2}{6.673\times10^{-11}(8.932\times10^{22}+m)}\times(421716397.5)^3\)

\((8.932\times10^{22}+m)=\dfrac{4\pi^2}{6.673\times10^{-11}}\times\dfrac{(421716397.5)^3}{(151200)^2}\)

\((8.932\times10^{22}+m)=1.94087\times10^{27}\)

\(m=1.94087\times10^{27}-8.932\times10^{22}\)

\(m=1.9407\times10^{27}\ kg\)

Hence, The mass of the planet  is \(1.9407\times10^{27}\ kg\)

If a submarine is sitting at a depth of 180m below the surface of the ocean. If the surface atmosphere is 100,000Pa, so The pressure acting on that submarine 1,934,896 Pa.

The pressure acting on the submarine that is sitting at a depth of 180 m below the surface of the ocean is calculated using the formula: pressure = density x gravitational acceleration x depth. However, the density of seawater is higher than that of freshwater. Therefore, the formula to calculate pressure in seawater is given as pressure = density of seawater x gravitational acceleration x depth.

To calculate the pressure acting on the submarine, we need to know the density of seawater at a depth of 180 m. The density of seawater changes with depth and temperature. At a depth of 180 m, the temperature of seawater is around 5°C. Using a density calculator, we can find that the density of seawater at this temperature and depth is approximately 1046 kg/m³.

We can now calculate the pressure acting on the submarine using the formula: pressure = density of seawater x gravitational acceleration x depth = 1046 kg/m³ x 9.8 m/s² x 180 m = 1,834,896 Pa.

Therefore, the pressure acting on the submarine that is sitting at a depth of 180 m below the surface of the ocean is approximately 1,834,896 Pa. This pressure is in addition to the atmospheric pressure of 100,000 Pa at the surface of the ocean. Hence, the total pressure acting on the submarine is the sum of these two pressures, which is 1,934,896 Pa.

For more question  submarine

https://brainly.com/question/14839260

#SPJ8

Given:

The force of repulsion between the electrons is,

The charge of each electron is,

To find:

The distance between the electrons

Explanation:

The force between two electrons at a distance 'r' is,

Substituting the values, we get,

Hence, the distance between the electrons is 5.03 m.

Answer:

The tension in string will be "3.62 N".

Explanation:

The given values are:

Length of string:

l = 3 ft

or,

 = 0.9144 m

frequency,

f = 60 Hz

Weight,

= 0.096 lb

or,

= 0.0435 kgm/s²

Now,

The mass will be:

= \(\frac{0.0435}{9.8}\)

= \(0.0044 \ kg\)

As we know,

⇒  \(\lambda=\frac{2L}{n}\)

On substituting the values, we get

⇒     \(=\frac{2\times 0.9144}{4}\)

⇒     \(=0.4572 \ m\)

or,

⇒  \(v=f \lambda\)

⇒      \(=0.4572\times 60\)

⇒      \(=27.432 \ m/s\)

Now,

⇒  \(v=\sqrt{\frac{T}{\mu} }\)

or,

⇒  \(T=\frac{m}{l}\times v^2\)

On putting the above given values, we get

⇒      \(=\frac{0.0044}{0.9144}\times (27.432)^2\)

⇒      \(=\frac{752.51\times 0.0044}{0.9144}\)

⇒      \(=3.62 \ N\)

The motorcycle had covered a distance of 16 meters in half the total time.

a) To calculate the acceleration, we can use the formula:

a = (v - u) / t

where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.

Given:

u = 0 m/s (initial velocity)

v = ? (final velocity)

t = 4 s (time)

s = 64 m (distance)

Using the equation of motion:

s = ut + 1/2at^2

We can rearrange the equation to solve for acceleration:

a = 2s / t^2

a = 2(64) / (4)^2

a = 128 / 16

a = 8 m/s^2

Therefore, the acceleration of the motorcycle is 8 m/s^2.

b) To find the final velocity, we can use the formula:

v = u + at

v = 0 + (8)(4)

v = 32 m/s

Therefore, the final velocity of the motorcycle is 32 m/s.

c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:

s = ut + 1/2at^2

32 = 0 + 1/2(8)t^2

16 = 4t^2

t^2 = 4

t = 2 s

Therefore, the motorcycle had covered half the total distance at 2 seconds.

d) To calculate the distance covered in half the total time, we use the formula:

s = ut + 1/2at^2

s = 0 + 1/2(8)(2)^2

s = 0 + 1/2(8)(4)

s = 0 + 16

s = 16 m

for such more questions  distance

https://brainly.com/question/26550516

#SPJ11

We can use the following data to get the values of acceleration and the distance covered at top speed:

Maximum speed is 20 m/s (v_max).

Time (t) = 21 seconds

(d) = 270 m is the total distance travelled.

Find the acceleration (A) first:

Applying the equation v = u + at

where an is the acceleration, t is the elapsed time, u is the beginning velocity, and v is the end velocity.

Given: The bus will begin at rest with an initial velocity of 0 metres per second (u).

The formula can be rearranged as follows:

a = (v - u) / t

a = (20 m/s - 0 m/s) / 21 seconds

0.952 m/s2 a = 20 m/s / 21 sec

Therefore, the acceleration of the bus is approximately 0.952 m/s².

Next, let's find the distance traveled at maximum speed (B):

Since the bus starts from rest, it takes time to accelerate to its maximum speed and then decelerate to stop. The distance traveled at maximum speed can be found by subtracting the distances covered during acceleration and deceleration from the total distance.

Distance during acceleration = (1/2) * a * t^2

Distance during deceleration = (1/2) * a * t^2

Distance traveled at maximum speed = Total distance - (Distance during acceleration + Distance during deceleration)

B = d - (0.5 * a * t^2 + 0.5 * a * t^2)

B = 270 m - (0.5 * 0.952 m/s² * (21 sec)^2 + 0.5 * 0.952 m/s² * (21 sec)^2)

B = 270 m - (0.952 m/s² * (21 sec)^2)

B = 270 m - 220.392 m

B ≈ 49.608 m

Therefore, the distance traveled at maximum speed is approximately 49.608 m

For more such question on acceleration

https://brainly.com/question/460763

#SPJ11

a) The main advantages of an epicyclic gearbox are:

b) i) Using the formula for the gear ratio of an epicyclic gear train:

T4/T3 = (t2/t1) x (t5/t2) x (t4/t5)

T4/30 = (1/2) x (60/20) x (40/60)

T4 = 40 Nm

ii) From the law of gearing for an epicyclic gear train:

w21 = (t3/t2) x (t5/t4) x w31 - (t3/t2) x w2

Substituting the given values:

w21 = (30/20) x (60/40) x 200 - (30/20) x 100

w21 = 150 rad/s

iii) The fixing couple that must be applied to wheel 5 can be found from the power transmitted by the gear train:

P = w3 x T3 = w2 x T2 = w1 x T1

Substituting the given values:

9 kW = 200 rad/s x 30 Nm = w2 x T2 = w2 x 20 Nm

w2 = 450 rad/s

T2 = (9 kW) / (450 rad/s) = 20 Nm

The fixing couple that must be applied to wheel 5 is equal in magnitude and opposite in direction to T2, so it is -20 Nm.

iv) The tangential force at the pitch point between wheels 3 and 4 can be found from the formula:

Ft = (2 x Pd) / (m x z3)

where Pd is the diametral pitch, m is the module, and z3 is the number of teeth on wheel 3.

Substituting the given values:

Pd = 25.4 / 5 = 5.08 teeth/inch

z3 = t3 / m = 30 / 5 = 6 teeth

Ft = (2 x 5.08) / (5 x 6) = 0.846 N

Find out more on gearbox here: https://brainly.com/question/16782058

#SPJ1

Answer:

A.gasses can change volume, and liquids cannot

Explanation:

if you pour a glass of water you don't have to worry about it expanding such that it overflows. however if you air up a ballon you may notice that it becomes lager the warmer it gets and smaller the cooler it gets

The angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec

The angular velocity (ω) of an object is the rate at which the object's angle position is changing in relation to time.

For a wheel attached to an incline angle, the angular velocity can be computed by considering the conservation of energy theorem.

As such the total kinetic energy (K.E) and rotational kinetic energy (R.K.E) at a point is equal to the total potential energy (P.E) at the other point.

i.e.

P.E = K.E + R.K.E

\(\mathbf{mgh = \dfrac{1}{2}m(r \times \omega)^2 + \dfrac{1}{2}\times I \times \omega^2}\)

\(\mathbf{gh = \dfrac{1}{2}(r \times \omega)^2 + \dfrac{1}{2}\times r^2 \times \omega^2}\)

\(\mathbf{2 \times \dfrac{gh}{r^2} =\omega^2 + \omega^2}\)

\(\mathbf{2 \omega^2=2 \times \dfrac{9.81 \times 8 m }{2.0 ^2} }\)

\(\mathbf{\omega^2=\dfrac{39.24 }{2}}\)

\(\mathbf{\omega=\sqrt{19.62 } \ rad/sec}\)

\(\mathbf{\omega=4.429 \ rad/sec}\)

Therefore, we can conclude that the angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec

Learn more about angular velocity here:

https://brainly.com/question/1452612

The angular velocity of the wheel depends on the mass, radius and the

mode of rotation of the wheel (with or without slipping).

Reasons:

The given parameters are;

Radius of the wheel, r = 2.0 m

Height of the incline, h = 8.0 m

Required:

Angular velocity of the wheel at the bottom of the incline.

Solution:

The potential energy of the wheel at the top of the hill, P.E. = m·g·h

\(Sum \ of \ the \ kinetic \ energy \ of \ the \ wheel, \ K.E. = \mathbf{\displaystyle \frac{1}{2} \cdot m \cdot v^2 + \frac{1}{2} \cdot I \cdot \omega ^2}\)

Where;

v = The translational velocity of the wheel = ω·r

I = The moment of inertia of the wheel = m·r²

Therefore'

\(Sum \ of \ K.E. = \displaystyle \frac{1}{2} \cdot m \cdot (\omega \cdot r)^2 + \frac{1}{2} \cdot m \cdot r^2 \cdot \omega ^2 = \mathbf{m \cdot r^2 \cdot \omega^2}\)

At the bottom of the hill, the potential energy is converted to kinetic energy

Therefore;

P.E. = Sum of K.E.

m·g·h = m·r²·ω²

g·h = r²·ω²

\(\displaystyle \omega = \sqrt{ \frac{g \cdot h}{r^2} } = \mathbf{ \frac{\sqrt{g \cdot h} }{r}}\)

Where;

g = Acceleration due to gravity ≈ 9.81 m/s²

Therefore;

\(\displaystyle \omega = \frac{\sqrt{9.81 \times 8} }{2} \approx \mathbf{ 4.43}\)

Learn more about the law of conservation of energy here:

https://brainly.com/question/4723473

https://brainly.com/question/2292427

https://brainly.com/question/816294

Answer:

no idea what this means

Explanation:

yeah

Answer:

I think B tell me if it's right

Explanation:

If an engineer is designing a tire for heavy machinery then a statement that describes the clearest criterion for the solution would be that it must function safely under the load of 4500 kg, therefore the correct answer is option C.

Mechanical advantage is defined as a measure of the ratio of output force to input force in a system, It is used to analyze the forces in simple machines like levers and pulleys.

Mechanical advantage = output force(load) /input force (effort)

As given in the problem statement that an engineer is designing a tire for heavy machinery and we have to find the statement which describes the clearest criterion for the solution,

As he is designing heavy machinery that must be able to support a large amount of weight,

Thu, the best option that is satisfying the criteria is option C.

Learn more about Mechanical advantages, here

brainly.com/question/16617083

#SPJ6

Answer:

observed frequency =  109.68 Hz

Explanation:

given data

speed u = 20.9 m/s

frequency f = 103 Hz

solution

we consider here speed of sound (v)  is 343 m/s

so observed frequency is express as

observed frequency = f × \(\frac{v}{v-u}\)     ...............1

put here value and we get

observed frequency =  103 × \frac{343}{343-20.9}

observed frequency =  109.68 Hz

Explanation:

The most established layers are on the base, and the most youthful layers are on the top. Since dregs here and there incorporate once-living creatures, sedimentary stone regularly contains a great deal of fossils. Fossils are once living beings that have been transformed into rock, fit as a fiddle or type of the creature can in any case be seen.

Answer:

The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

Explanation:

Given that,

Length of plates = 8 cm

Width = 5.52 cm

Distance = 1.99 cm

Dielectric constant = 2.6

Length = 4.4 cm

Potential = 0.8 V

We need to calculate the initial capacitance

Using formula of capacitance

\(C=\dfrac{\epsilon_{0}A}{d}\)

Put the value into the formula

\(C=\dfrac{8.85\times10^{-12}\times8\times5.52\times10^{-4}}{1.99\times10^{-2}}\)

\(C=1.96\times10^{-12}\)

We need to calculate the final capacitance

Using formula of capacitance

\(C'=\dfrac{\epsilon_{0}A_{1}}{d}+\dfrac{k\epsilon_{0}A_{2}}{d}\)

Put the value into the formula

\(C'=(\dfrac{8.85\times10^{-12}}{1.99\times10^{-2}})((4.4\times5.52)+(3.6\times5.52)2.6)\times10^{-4}\)

\(C'=3.37\times10^{-12}\)

We need to calculate the  ratio of the new potential energy to the potential energy before the insertion of the dielectric

Using formula of energy

\(\dfrac{E}{E'}=\dfrac{\dfrac{1}{2}CV^2}{\dfrac{1}{2}C'V^2}\)

Put the value into the formula

\(\dfrac{E}{E'}=\dfrac{1.96\times10^{-12}}{3.37\times10^{-12}}\)

\(\dfrac{E}{E'}=0.58\)

Hence, The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

As a result, the picture behind the mirror is virtual, upright, and enlarged.

You will find that the properties of an image (SALT) created in a concave mirror depend on the object's position. A) if the item is larger than C. Size, attitude, and location are all important considerations.

The image will be true, but reversed and much reduced. To obtain a crisp flame image, move the burning candle towards the mirror while moving the screen away from it. The size of the inverted picture grows.

Concave mirrors may create both physical and virtual images. A virtual and enlarged picture is produced when the item gets closer to the mirror. When the item is placed further away from the mirror,.

learn more about Concave mirrors

https://brainly.com/question/27841226

#SPJ1

The final velocities of the car and truck just after the collision will be as per the conservation of momentum.

Momentum is defined as product of mass and velocity of the body. It is denoted by letter p and it is expressed in kg.m/s. Mathematically p = mv. it discuss the moment of the body. body having zero mass or velocity has zero momentum. The dimensions of the momentum is [M¹ L¹ T⁻¹].

According to conservation of momentum, Initial momentum will be equal to the final momentum. In the elastic collision there is no loss of energy, both energy and momentum is conserved.

if the the car is coming with velocity equal to the mass of the truck and truck is coming with mass of the car, then they have same momentum in opposite direction when they collide each other the final velocity of both car and truck becomes zero.

To know more about momentum :

https://brainly.com/question/20301772

#SPJ1.

Interpreting Graphics The velocity-versus-time graph for a shuttle bus moving along a straight path is shown in Figure 13., all the answer is attached.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

a) The time intervals during which the velocity of the shuttle bus is constant: 50 s to 150 s.

b) The time intervals during which the acceleration of the shuttlebus is constant: 500 s to 600s.

c) The value for the average velocity of the shuttle bus during time interval identified in b is: ( -3 +(-5))/2 =m/s = - 4 m/s.

d) The acceleration of the shuttle bus during time interval identified in b = ( -3 +(-5))/(600 - 500) m/s² = 0.02 m/s²

.e) The times at which the velocity of the shuttle bus is zero is : 200s to 300s.

f) The times at which the acceleration of the shuttle bus is zero is : 50s to 150s.

g) The slope of the graph reveals about the acceleration in each time interval that when it is positive the car is accelerated, when it is negative, the car is decelerated.

Learn more about velocity here:

https://brainly.com/question/18084516

#SPJ1

Answer:

It is not possible to calculate the time it took to go up to 3 meters.

Explanation:

There are all forces that apply to this situation like gravity, friction, torque, and efficiency. To answer this question, I might need the specifications given before to answer this question.

Even without wind the sun help evaporate the water so it would dry faster. The other towel is in a bag so the moist and water has nowhere to go, therefor staying in the towel.

Answer:

   \(c_{e1} = \frac{(m_2 c_{e2} \ + m_3 c_{e3} ) \ (T_{Teq} - T_2) }{m_1 (T_1 - T_{eq}) }\)

Explanation:

This is a calorimeter problem where the heat released by the console is equal to the heat absorbed by the cupcake and the plate.

           Q_c = Q_{abs}

where the heat is given by the expression

           Q = m c_e ΔT

            m₁ c_{e1) (T₁-T_{eq}) = m₂ c_{e2} (T_{eq} -T₂) + m₃ c_{e3} (T_{eq}- T₁)

note that the temperature variations have been placed so that they have been positive

They ask us for the specific heat of the console

           \(c_{e1} = \frac{(m_2 c_{e2} \ + m_3 c_{e3} ) \ (T_{Teq} - T_2) }{m_1 (T_1 - T_{eq}) }\)

Answer:

0.63 s

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 50 g

Extention (e) = 10 cm

Period (T) =?

Next, we obtained 50 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

50 g = 50 g × 1 Kg / 1000 g

50 g = 0.05 kg

Next, we shall convert 10 cm to m. This is illustrated below:

100 cm = 1 m

Therefore,

10 cm = 10 cm × 1 m / 100 cm

10 cm = 0.1 m

Next, we shall determine the force exerted on the spring. This can be obtained as follow:

Mass = 0.05 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Force (F) =?

F = mg

F = 0.05 × 9.8

F = 0.49 N

Next, we shall determine the spring constant of the spring.

Extention (e) = 0.1 m

Force (F) = 0.49 N

Spring constant (K) =?

F = Ke

0.49 = K × 0.1

Divide both side by 0.1

K = 0.49 /0.1

K = 4.9 N/m

Finally, we shall determine the period as follow:

Mass = 0.05 Kg

Spring constant (K) = 4.9 N/m

Pi (π) = 3.14

Period (T) =?

T = 2π√(m/k)

T = 2 × 3.14 × √(0.05 / 4.9)

T = 6.28 × √(0.05 / 4.9)

T = 0.63 s

Thus, the period of oscillation is 0.63 s