A flywheel (I= 50 kg-m²) starting from rest acquires an angular velocity of 200.0 rad/s while subject to a constant torque from a motor for 5 s.
(a) What isthe angular acceleration of the flywheel?
(b) What is the magnitude of the torque?

Answers

Answer 1

Explanation:

(a) Given:

ω₀ = 0 rad/s

ω = 200.0 rad/s

t = 5 s

Find: α

ω = αt + ω₀

200.0 rad/s = α (5 s) + 0 rad/s

α = 40 rad/s²

(b) ∑τ = Iα

τ = (50 kg m²) (40 rad/s²)

τ = 2000 Nm

Answer 2

The angular velocity is:

(a) Given:

ω₀ = 0 rad/s

ω = 200.0 rad/s

t = 5 s

Find: a

ω = αt + ω₀

200.0 rad/s = α (5 s) + 0 rad/s

α = 40 rad/s²

(b) ∑τ = Iα

τ = (50 kg m²) (40 rad/s²)

τ = 2000 Nm

What is a constant torque motor?

A regular torque motor is a brushless motor, which reduces warmness in the rotor and stator area. they are eighty% green as compared to p.c automobiles which are rated at 60% green. Additionally, they don't want a capacitor to start and run.

A regular torque load means that the torque required to maintain the burden of walking is identical at all speeds. A good instance is a drum-kind hoist, in which the torque required varies with the load at the hook, but no longer with the speed of hoisting.

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Related Questions

You have a summer job operating a movable, hand-powered crane in a distribution center for a building supply company. The figure below shows the pulley arrangement of the crane. Using this cranevou find it necessary to exert a force of 122 N to support a load. Determine the following.

You have a summer job operating a movable, hand-powered crane in a distribution center for a building
You have a summer job operating a movable, hand-powered crane in a distribution center for a building

Answers

ANSWER:

(a) 3

(b) 37.35 kg

(c) 488 N

STEP-BY-STEP EXPLANATION:

Given:

T = 122 N

(a)

We make the balance of force to be able to determine the weight, just like this:

\(\begin{gathered} F_y=0 \\ \\ 3T-W=0 \\ \\ W=3T \end{gathered}\)

Now, the formula to calculate the mechanical advantage is the following:

\(\begin{gathered} MA=\frac{W}{T} \\ \\ \text{ We replacing} \\ \\ MA=\frac{3T}{T} \\ \\ MA=3 \end{gathered}\)

(b)

The mass is calculated using the following formula:

\(\begin{gathered} W=m\cdot g \\ \\ m=\frac{W}{g} \\ \\ m=\frac{3T}{g} \\ \\ \text{ We replacing} \\ \\ m=\frac{(3)(122)}{9.8} \\ \\ m=\:37.35\text{ kg} \end{gathered}\)

(c)

We can calculate this force (tension) by the following force balance:

\(\begin{gathered} \text{ The top pulley pulling up the center pulley with the following magnitude:} \\ \\ T_1-2T=0\rightarrow T_1=2T \\ \\ \text{ We have the tension up on the pin T0, this is equal to the force that pulls the crane down} \\ \\ T_0-2T-T_1=0 \\ \\ \text{ We replacing} \\ \\ T_0-2T-2T=0 \\ \\ T_0=4T \\ \\ T_0=(4)(122) \\ \\ T_0=488\text{ N} \end{gathered}\)

prepare a report on why a vehicle needs to be maintained/serviced after a certain period of time. How is servicing different in a petrol/diesel and electric vehicle?​

Answers

Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

Why should cars be maintained and / or serviced ?

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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True or false All plant and animal cells undergo cellular respiration.

Answers

Answer: true

Explanation:

Shawn and his bike have a total mass of 49.9 kg. Shawn rides his bike 0.92 km in 15.4 min at a constant velocity. The acceleration of gravity is 9.8 m/s 2 . What is Shawn’s kinetic energy? Answer in units of J.

Answers

Answer:

0 J

Explanation:

KE = .5(m)(v2-v1)

if velocity is constant v2 = v1, then v2 - v1 = 0

therefore if (v2-v1) = 0, then KE must also be equal to 0

Question 20
An 10,000.0 kg truck starts off from rest and reaches a velocity of 16.1 m/s in 4.6
seconds.
What is the truck's accelerſation? Round your answer to one decimal.

Answers

Answer:

\(\huge\boxed{\sf a = 3.5 \ m/s^2}\)

Explanation:

Given data:

Initial velocity = \(V_i\) = 0 m/s

Final velocity = \(V_f\) = 16.1 m.s

Time = t = 4.5 seconds

Required:

Acceleration = a = ?

Formula:

\(\displaystyle a = \frac{V_f-V_i}{t}\)

Solution:

Put the given data in the above formula.

\(\displaystyle a = \frac{16.1-0}{4.6} \\\\a = \frac{16.1}{4.6} \\\\a = 3.5 \ m/s^2\\\\\rule[225]{225}{2}\)

Velocity is the speed at which an object moves in a specific direction. It's measured in meters per second, minute or hour in a particular direction—like miles per hour going north, kilometers per minute west or meters per second up. Velocity tells us both the speed and direction we are traveling. Acceleration is a change in velocity. It's measured by subtracting the object's starting velocity from the final velocity, divided by the time this change in velocity took. We usually think of acceleration as speeding up, but it can also mean slowing down. We call this negative acceleration or deceleration. If a car was driving 45 miles per hour northeast, and is now driving 30 miles per hour north, A the car’s velocity decelerated. B the car’s velocity accelerated. C the car’s velocity remained unchanged. D the car’s acceleration is 30 miles per hour.

Answers

Answer:

Option A. The car’s velocity decelerated

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 45 mph Northeast

Final velocity (v) = 30 mph North

Now, if we take the difference between the car's final velocity and it's Initial velocity, we shall obtained:

Difference in velocity = v – u

Difference in velocity = 30 – 45

Difference in velocity = –15 mph

Since the difference between the final velocity and the initial velocity of the car is negative, it implies that the car's velocity decelerated.

Thus, option A gives the correct answer to the question

A 200 kg car has a constant velocity of 40 m/s. Suddenly the driver steps on the
brakes, and the force of friction that slows down the car is 1,000 N. What is the
acceleration of the car?

Answers

Answer:

acceleration =Force/mass

a=1000/200=5m/s

experiment to show that light travels in a straight line​

Answers

The answer here
Two experiments are used to demonstrate how light travels in straight lines. In the first example, the presenter arranges three pieces of card, with holes in, in an uneven line. The light stops and cannot travel through all three cards. When she arranges the holes in a straight line, the light can travel through.

Help me in PE plzzzzzz

Help me in PE plzzzzzz

Answers

Answer:

Balance. Eyes. Elbow. Follow-Through

Explanation:

Answer:

you have to take 4 to 5 steps to do the step

Explanation:

A piston–cylinder device with a set of stops initially contains 0.6 kg of steam at 1.0 MPa and
400°C. The location of the stops corresponds to 40 percent of the initial volume. Now the
steam is cooled. Determine the compression work if the final state is
a) 1.0 MPa and 250°C and
b) 500 kPa.
c) Also determine the temperature at the final state in part b.

Answers

A piston-work cylinder device with a set of stops initially contains 0.6 kg of steam at 1.0 MPa and 400°C. The location of the stops corresponds to 40 percent of the initial volume. Now the steam is cooled. compression work is 44.32 KJ,

The amount of labor put into the piston to cause its reciprocating motion is known as the piston work. It is calculated by multiplying the piston's displacement by the net force.

An expanding gas cylinder's force output is transferred by pistons to the crankshaft, which then drives the flywheel's rotation. A reciprocating engine is a device like this.

Piston work is the effort made by the piston to make its reciprocating motion. The piston's displacement is calculated by multiplying it by the net force.

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how do you mountaineers reduce the effects of changes in atmospheric pressure?

Answers

Essentially belly breathing with forceful exhale, the pressure breath helps to improve gas exchange across the alveoli by increasing the pressure of the lungs . The pressure breaths helps to combat the effects caused by decreasing atmospheric pressure as climbers gain altitude

If you increase the frequency of a sound wave four times, what will happen to its speed?
А
The speed will increase four times.
B.
The speed will decrease four times,
C. The speed will remain the same.
D.
The speed will increase twice.
E.
The speed will decrease twice.

Answers

The answer is C wave frequency does not affect wave speed

A 2.40 kg ball is attached to an unknown spring and allowed to oscillate. The figure below shows a graph of the ball’s position �� as a function of time . What are the oscillation’s: a. period; b. frequency; c. angular frequency; d. amplitude; and e. What is the force constant of the spring?

Answers

(a) The period of the oscillation is 0.8 s.

(b) The frequency of the oscillation is 1.25 Hz.

(c) The angular frequency of the oscillation is 7.885 rad/s.

(d) The amplitude of the oscillation is 3 cm.

(e) The force constant of the spring is 148.1 N/m.

The given parameters:

Mass of the ball, m = 2.4 kg

From the given graph, we can determine the missing parameters.

The amplitude of the wave is the maximum displacement, A = 3 cm

The period of the oscillation is the time taken to make one complete cycle.

T = 0.8 s

The frequency of the oscillation is calculated as follows;

\(f = \frac{1}{T} \\\\f = \frac{1 }{0.8} \\\\f = 1.25 \ Hz\)

The angular frequency of the oscillation is calculated as follows;

\(\omega = 2\pi f\\\\\omega = 2\pi \times 1.25\\\\\omega = 7.855 \ rad/s\)

The force constant of the spring is calculated as follows;

\(\omega = \sqrt{\frac{k}{m} } \\\\\omega ^2 = \frac{k}{m} \\\\ k = \omega ^2 m\\\\k = (7.855)^2 \times 2.4\\\\k = 148.1 \ N/m\)

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A 2.40 kg ball is attached to an unknown spring and allowed to oscillate. The figure below shows a graph

when air mass is caught between two cold fronts the result is a _______ front.

Answer choices
A.occluded
B.warm
C.cold
D.stationary​

Answers

A. Occluded
Explanation- At an occluded front, the cold air mass from the cold front meets the cool air that was ahead of the warm front.

A wire is attached to the ceiling so that the current flows south to north. A student is standing directly below the wire facing north. What is the direction of the B-field (caused by the current in the wire) at this observation point

Answers

Answer:

If one wraps the fingers around the wire and points the thumb in the direction of the "conventional" current the fingers will point towards the North pole - the direction of the B-field.

In this case the B-field is pointed "West".

if i put my spoon in the microwave what will happen

Answers

If you put your spoon in the microwave, nothing will happen to it as long as it has round edges and it is not touching any sides of the microwave.

Putting a spoon in the microwave

Spoons are generally made from stainless steel. Stainless steels are iron and chromium. In some cases, other metals such as nickel are thrown into the mix.

Thus, being made of metals, these stainless steels are good conductors of heat and electricity.

A microwave works by heating foods put into it using electromagnetic radiation in the microwave frequency range. Electromagnetic radiation causes the molecules of food to rotate and produce thermal energy.

If the spoon touches the side of the microwave, sparks may result. Otherwise, it is totally fine because spoons usually have round edges. With rough edges,  the waves may be reflected back and forth and create sparks.

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edictions: On
Analyze different investments for corporate accounts.
Peixotto Media is a small video game developer founded by two people 12 years
ago. Since then, it has grown and expanded. Now its founders, who are today its co-
presidents, have decided to incorporate. They have an initial public offering (IPO) of
its stock. John William has been following Peixotto Media's development ever since
it was a small operation and he was a high-school indie gamer. He is very excited
about the opportunity to become a co-owner of this company.
1. Peixotto Media's charter authorizes the sale of 35,000,000 shares of stock, but it
will begin by offering 20,000 of them at a par value of $4 per share. John William
currently has $500 that he would like to invest in this company's stocks.
a. How much stock will John William be able to purchase? (2 points)
b. What privileges will John William have as a shareholder in Peixotto Media? (3
Qoints)
Accessibility: Investigate
O Search
Focus

edictions: OnAnalyze different investments for corporate accounts.Peixotto Media is a small video game

Answers

1. (a) Peixotto Media's charter authorizes the sale of 35,000,000 shares of stock, but it will begin by offering 20,000 of them at a par value of $4 per share. John William currently has $500 that he would like to invest in this company's stocks. John William will be able to purchase 125 shares of Peixotto Media stock.

(b) Privileges John William will have as a shareholder in Peixotto Media are Voting Rights, Dividend Payments, Capital Appreciation etc.

(a) In order to calculate how much stock John William will be able to purchase, we need to determine how many shares he can buy with his available funds. The par value per share is $4, so to find the number of shares he can buy, we divide his investment amount ($500) by the par value per share ($4):

Number of shares = Investment amount / Par value per share

Number of shares = $500 / $4 = 125 shares

Therefore, John William will be able to purchase 125 shares of Peixotto Media stock.

(b) As a shareholder in Peixotto Media, John William will have certain privileges. These privileges typically include:

Voting Rights: Shareholders are generally entitled to vote on matters that affect the company, such as electing the board of directors or approving major corporate decisions.

Dividend Payments: If the company declares dividends, shareholders may receive a portion of the company's profits in the form of dividend payments.

Capital Appreciation: If the value of the company's stock increases, shareholders can benefit from capital appreciation by selling their shares at a higher price than what they initially paid.

Information Rights: Shareholders have the right to access certain company information, such as financial reports or annual statements, to stay informed about the company's performance.

Liquidation Preference: In the event of the company's liquidation or bankruptcy, shareholders may have a claim on the company's assets after other obligations are fulfilled.

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What is the daughter nucleus (nuclide) produced when bi213 undergoes alpha decay? replace the question marks with the proper integers or symbols.

Answers

The equation is;

213/83 Bi ----> 209/81Tl + 4/2 He

What is the alpha decay of Bi-213?

In this decay process, the unstable Bi-213 nucleus emits an alpha particle, which consists of two protons and two neutrons (also known as a helium-4 nucleus).

As a result of this emission, the daughter nucleus Tl-209 is formed with a decrease of four in the atomic number and a decrease of eight in the mass number. The alpha particle, He-4, has an atomic number of 2 and a mass number of 4, and is emitted with high kinetic energy.

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A 1.0 kg block is pushed 20 m at a con-
stant velocity up a vertical wall by a constant
force applied at an angle of 26.0° with the
horizontal, as shown in the figure.
The acceleration of gravity is 9.81 m/s².
1 kg
Drawing not to scale.
If the coefficient of kinetic friction between
the block and the wall is 0.20, find
a) the work done by the force on the block.
Answer in units of J.
Answer in units of J
part 2 of 3
b) the work done by gravity on the block.
Answer in units of J.
c) the magnitude of the normal force between the block and the wall.

Answers

A 1.0 kg block is pushed 20 m at a constant velocity up a vertical wall by a constant force applied at an angle of 26.0° with the horizontal.The acceleration of gravity is 9.81 m/s². Thus, calculated values are:

a)  the work done by the force on the block: 19.62 J

b)  the work done by gravity on the block: -19.62 J

c) the magnitude of the normal force between the block and the wall:  17.7 N

What is acceleration?

Anything that causes a change in velocity is referred to as an acceleration. You can only accelerate by changing the speed, direction, or both as velocity is a function of both speed and direction.

let m = 1.0 kg

d = 2.0 m

θ = 29°

let, F is the applied force.

let, Fx and Fy are components of F.

As the block is moving upward with constant velocity, net force acting on the block must be zero.

F×nety = 0

or, Fy - m×g = 0

or, Fy = m×g

or, Fy = 1×9.81 N

or, Fy = 9.81 N

a) The work done by the force on the block, WF = Fy×d×cos(0°)

= (9.81×2) J

= 19.62 J

b) The work done by gravity, Wg = Fg×d×cos(180°)

= 1 ×9.81×2×(-1)

= -19.62 J

c) we know, Fy = F×sin(29°)

Fx = F×cos(29°)

Fy/Fx = tan(29°)

Fx = Fy/tan(29°)

Fx = 9.81/tan(29)

Fx = 17.7 N

now use, Fnetx = 0

or, Fx - N = 0

or, N = Fx

or, N = 17.7 N

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N
Using the graph below, how many adults do NOT carpool to work?
Transportation to Work
Account
80
ashboard
70
60
50
Dunes
Number of Adults
40
30
Hondar
20
10
DOK
0
Bus
Walk
Car
Carpool
Method of Transportation
cory
2
160
O 15
50
130

NUsing the graph below, how many adults do NOT carpool to work?Transportation to WorkAccount80ashboard706050DunesNumber

Answers

Answer:130

Explanation:just answered it

Describe the mechanisms by which out-of-plane deformation in the laser forming
process can occur. As part of your answer, identify the mechanism of laser forming
which is active for the experimental results provided.

Describe the mechanisms by which out-of-plane deformation in the laser formingprocess can occur. As part

Answers

The mechanisms by which out-of-plane deformation in the laser forming process can occur include:

Temperature gradient mechanismBuckling mechanismUpsetting mechanism.

What is Temperature gradient mechanism?

This is the mechanism which involves bending the sheet to a laser light source.

The experiment shown in this scenario depicts it as one plane of the sheet can be seen raised.

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You perform an experiment to test how far a cannon will shoot a performer at
different angles. The data are shown below.
Angle
Distance (feet)
110
32°
36°
120
40°
128
440
133
48°
127
52
119
56°
109
60°
100
64°
91
68°
77
72°
63
At which angle will the performer travel the longest distance?

You perform an experiment to test how far a cannon will shoot a performer atdifferent angles. The data

Answers

Answer:

44°

Explanation:

Look for the longest distance under the 'Distance ' column....look to the left to find the corresponding angle

  Table clearly shows that the longest distance (133 ft) occurs at angle of 44°

Infrared radiation from the center of our Galaxy with a wavelength of about 2 µm (2 ✕ 10−6 m) comes mainly from cool stars. What is the surface temperature (in K) of those stars?

Answers

The surface temperature of the stars whose infrared radiation have a wavelength of  2 µm is 1.45×10³ K.

What is temperature?

Temperature is the measure of hotness or coldness of a thing or place.

To calculate the temperature of the stars, we use the formula below.

Formula:

T = b/λ.......... Equation 1

Where:

T = Temperature of the starsλ = Wavelength of the starsb = Wein's constant

From the question,

Given:

λ = 2×10⁻⁶ mb = 2.9×10⁻³ m⋅K

Substitute these values into equation 1

T = 2.9×10⁻³ / 2×10⁻⁶T = 1.45×10³ K

Hence, the surface temperature of the stars is 1.45×10³ K.

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determine the force exerted by the bicep muscle, assuming that the hand is holding a ball with a mass of 5.00kg. Assume that the mass of the forearm is 8.50kg with the center of the mass located 20.0cm away from the elbow joint. Assume also that the center of the mass of the ball in the hand is 30.0 cm away from the elbow joint.

Answers

In the event when the hand is carrying a ball with a mass of 5.00 kg, the bicep muscle will exert  132.3 N of force. Let's say the forearm weighs 8.50 kg, with the mass's centre 20.0 cm from the elbow.

M = the ball's mass

mass of the forearm is mf.

rf = distance of centre of mass of forearm from elbow, which is 20 cm (0.20 m) away from elbow, and rb = distance of ball from elbow

force exerted by the biceps, F

r = distance of biceps force from elbow

Using elbow-based torque equilibrium

F r = mf rf + mb rb

using the equilibrium of force in the vertical direction, F r = 3.2 eq-1 where F r = 5 x 0.30 + 8.50 x 0.20

F = mb + mf g

F = 8.50* 9.8 + 5 * 9.8

F = 132.3 N

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1. For the masses shown with the indicated velocities. Consider the increasing
direction of the x-axis toward the right.
9.0 kg 4.0 m/s
8.0 m/s
6.0 kg
a) Find the magnitude of the momentum of the system. (Do not include the units
in the answer)
Your answer
b) What is the direction of the momentum of the system?
Choose
c) Determine the total kinetic Energy of the System. (Do not include the units in
the answer)
Your answer

Answers

Momentum=mv =9x4=36
=8x6=48




A man driving a car at 35 mph hits his brakes suddenly to avoid hitting a dog.
Everything in the front seat of his car slides forward and into the floorboard. Which of
Newton's laws does this illustrate?

Answers

Answer:

Inertia; Newton's First Law

Explanation:

When you hit you're breaks, the force you feel that pulls you forward is due to inertia.

Newton's first law says that "every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force." The question is a perfect example of this.

It is due to the inertia of motion of the objects that they fall on the floor bed. This is also called Newton's first law of motion.

What is the name of Newton's first law of motion?

Newton's first law of motion is known as the law of inertia.

Given is a man who is driving a car at 35 mph hits his brakes suddenly in order to avoid hitting a dog. During the incident, everything in the front seat of his car slides forward and into the floorboard.

The property of body by virtue of which it resist any change in its state of rest or uniform motion is called inertia of body. When the car was moving at 35 mph, every object on front seat was also moving with the same speed. However, when the brakes were applied, they were applied on the car and not on the objects in the front seat. Hence, they keep moving forward and stop only when they strike and fall down. This is called inertia of motion. This is Newton's first law of motion.

Therefore, it is due to the inertia of motion of the objects that they fall on the floor bed. This is also called Newton's first law of motion.

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A uniform bar of length 24 m and...

A uniform bar of length 24 m and...
A uniform bar of length 24 m and...
A uniform bar of length 24 m and...

Answers

The magnitude of horizontal force, is 33.27 N.

Length of the uniform bar, L = 24 m

Mass of the uniform bar, m = 5 kg

Angle between the cord and the bar, θ₁ = 90°

Angle between the cord and the wall, θ₂ = 50°

For the horizontal equilibrium,

Hₓ = T sinθ₂

Hₓ = T x sin 50

Hₓ = 0.766 T

For the vertical equilibrium,

Hy + T cosθ₂ = mg

Hy + T cos 50 = 5 x 9.8

Hy + 0.642 T = 49 N

For rotational equilibrium,

mg (L/2) = T x L

So,

T = mg/2 = 5 x 9.8/2

T = 24.5 N

Therefore, the magnitude of horizontal force,

Hy = 49 - (0.642 x 24.5)

Hy = 49 - 15.73

Hy = 33.27 N

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A rollercoaster car passes the hill which is 5.5m above the ground at speed 9.3m/s, and rolls over the second hill which is 2.5m above the ground, and heads toward the third hill which is 4.0 m higher than the first one. If the track is frictionless,
a. What maximum height will the car climb on the third hill? [h max = 9.9m, so car will climb the entire 9.5m hill]
b. Will the speed of the car on top of the hill 3 be lower or higher than its speed on the top of the hill one? [lower]
c. Calculate the speed of the car when it is 1m lower than the top of the third hill. [5.3m/s]

Would somebody kindly go over the questions :D

Answers

Answer:

Explanation:

Without friction, a roller coaster continuously converts potential energy to kinetic energy and back again. Total energy will be constant.

Let m be the mass of the car and ground level is the origin.

on the 5.5 m hill, total energy is

E = PE + KE

E = mgh + ½mv²  

E = m(9.8)(5.5) + ½m(9.3)² = 97m J

a) The maximum height will occur when the total energy is all potential energy.

E = mgh

h = E/mg

h = 97m/m(9.8) = 9.9 m  

As this value is greater than the height of the third hill at 5.5 + 4.0 = 9.5 m The car will cross the last hill with some remaining velocity in kinetic energy.

b) As 9.5 m is greater than 9.3 m, the 9.5 m hill will have more of the total energy of the system as potential energy, This mean there is less kinetic energy and therefore less velocity (and speed) on top of the 9.5 m hill.

c) KE = E - PE

KE = 97m - m(9.8)(9.5 - 1.0)

KE = 97m = 83.3m

KE = 13.7m = ½m

v² = √(2(13.7)

v = 5.2345...

v = 5.2 m/s

Rashad and Carlos measure the length, width and height of a textbook at 6 cm, 4 cm, and 3respectively. What is the volume of the textbook?

Answers

Answer:

72 cm³

Explanation:

The volume of a textbook can be calculated as

Volume = Length x Width x Height

Replacing the length by 6 cm, the width by 4 cm, and the height by 3 cm, we get:

Volume = 6 cm x 4 cm x 3 cm

Volume = 72 cm³

Therefore, the volume of the textbook is 72 cm³

It’s important to measure exercise shoes with the type of exercise in which you will be participating.

Answers

Answer:

True

Explanation

the right shoes will help with the comfort & it will help with limits you have on your legs.. Weights, posture,& will help with injury...

Other Questions
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