An object is fired from the ground at 100. m/s at an angle of 30° with the horizontal.
a) Calculate the horizontal and vertical components of the initial velocity
b) After 2.0 seconds, how far has the object traveled in the horizontal direction?
c) How high is the object at this point

The conduction of current on the postsynaptic neuron in an electrical synapse occurs through direct flow of ions between the presynaptic and postsynaptic neurons.

In electrical synapses, the conduction of current on the postsynaptic neuron occurs through direct flow of ions between the presynaptic and postsynaptic neurons. These synapses are formed by specialized structures called gap junctions, which create channels between the cells, allowing ions to pass through. The channels are formed by connexin proteins that span the plasma membranes of adjacent neurons.

When an action potential reaches the presynaptic neuron, it depolarizes the cell membrane and triggers the opening of voltage-gated ion channels. This results in the influx of positively charged ions, such as sodium (Na+), into the presynaptic neuron. As a result, the electrical potential of the presynaptic neuron becomes more positive.

Due to the direct connection provided by the gap junctions, these positive ions can flow through the channels into the postsynaptic neuron. This movement of ions generates an electrical current that spreads across the postsynaptic neuron. The current causes depolarization of the postsynaptic membrane, leading to the initiation of an action potential in the postsynaptic neuron.

The strength of the electrical synapse is determined by the size of the gap junctions and the number of connexin proteins present. The larger the gap junctions and the more connexin proteins, the more ions can pass through, resulting in a stronger electrical coupling between the neurons.

at electrical synapses, the conduction of current on the postsynaptic neuron occurs through the direct flow of ions between the presynaptic and postsynaptic neurons via specialized gap junctions. This direct electrical coupling allows for rapid and synchronized transmission of signals. Electrical synapses are particularly important in neural circuits that require fast and coordinated communication, such as in reflex arcs or the synchronization of cardiac muscle cells.

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Increasing the pressure inside the extruder barrel is not a function of the screen pack and breaker plate.

The screen pack and breaker plate have several functions, including:
1. Filtering out contaminants and impurities from the molten plastic.
2. Creating uniform melt flow.
3. Reducing pressure fluctuations.
However, they do not serve to increase the pressure inside the extruder barrel.

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Answer:

216.32kN

Explanation:

Force can be expressed according to the formula;

Force = mass ×acceleration

Given

Mass = 1250kg

Velocity = 4.16m/s

Distance = 0.05m

We can get the acceleration first using the equation of motion

v² = u²+2as

4.16² = 0²+2a(0.05)

17.3056 = 0.1a

a = 17.3056/0.1

a = 173.056m/s²

Get the force required

Force = 1250×173.056

Force = 216,320N

Force = 216.32kN

Hence the force constant of the material is 216.32kN

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 2 × 9.8

We have the final answer as

Hope this helps you

Radio waves are transverse waves that disturb electromagnetic fields.

Electromagnetic field, a feature of space brought on by the movement of an electric charge. Only an electric field will be generated by a stationary charge in the surrounding area. A magnetic field is also created if the charge is in motion.

A changing magnetic field can also create an electric field. An electromagnetic field is created by the mutual interaction of electric and magnetic fields. This field is thought to exist independently of any charges or currents (a stream of moving charges) to which it may be related. It is possible to think of this electromagnetic field in some situations as an electromagnetic energy-transporting wave.

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The frictional force when the box has a constant velocity of 6 m/s is -30 N

We'll begin by obtaining the acceleration of the box. This can be obtained as follow:

Acceleration = velocity / time

Acceleration = 6 / 2

Acceleration = 3 m/s²

Next, we shall determine the net force on the box. This is shown below:

Net force = mass × acceleration

Net force = 14 × 3

Net force = 42 N

Finally, we shall determine the frictional force. Details below

Net force = Force applied - frictional force

42 = 12 - frictional force

Rearrange

Frictional force = 12 - 42

Frictional force = -30 N

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Answer:

1.2 meters

Explanation:

The work done by a force of a particular magnitude is defined as the product of the force in the direction of the displacement of the object and the magnitude of this displacement. Work done can be calculated by multiplying Force and Distance in the direction of force as follows.

W = F × d

W = work (J),

F = force (N),

d = shift or displacement (m).

The magnitude of the total friction force exerted by the road on the tires at B will be 919.46 lb.

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. Its unit is Newton (N).

Mathematically, it is defined as the product of the coefficient of friction and normal reaction.

The given data in the problem is;

The weight is,W= 3,220 lb

The speed is,u= 60 mi/hr

The reducing speed is,v= 45 mi/hr

The distance traveled is,d= 300 ft

The radius of curvature of the path of the car at B is,R= 600 ft.

1 mile = 5280 ft

From the Newtons' equation of motion;

\(\rm v^2 = u^2 +2ad \\\\ \rm (45 \times \frac{5280}{3600} )^2 = (60 \times \frac{5280}{3600} )^2 +2a\times 300 \\\\\)

The tangential accelerations are;

\(\rm a_t = \frac{66^2 -88^2}{600} \\\\ \rm a_t = -5.65 ft/sec^2 \\\\\)

The force is found as;

\(\rm \sum F = ma \\\\ \frac{3220}{32.2} \times -5.65 \\\\ F_T= 565 \ lb\)

The normal force  is;

\(\rm F_n = \frac{3220}{32.2} \times \frac{66^2}{600} \\\\ F_N =726 \ lb\)

The net or the total friction force exerted by the road on the tires at B. is found as;

\(\rm F = \sqrt{(565)^2+(726)^2} \\\ F = 919.946 \ lb\)

Hence, the magnitude of the total friction force exerted by the road on the tires at B will be 919.46 lb.

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The measurement of body temperature is an example of a variable that uses option A, interval scale.

A scale with an interval has order and a meaningful difference between two values. Temperature (Fahrenheit), temperature (Celsius), pH, SAT score (200-800), and credit score are a few examples of interval variables (300-850).

One variable that uses interval scale is the measurement of body temperature.

Only ratio scales have a genuine zero, even though interval and ratio data can both be categorized, sorted, and spaced equally apart between consecutive values. As 0 is not the lowest attainable temperature, temperature in Celsius or Fahrenheit, for instance, is measured on an interval scale.

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Answer:

216 J

Explanation:

h = 1.8

a = 9.8

m = 12.2

GPE = HAM = 216

The gravitational potential energy of a suitcase weighing 120 N sits on a counter 1.8 m high in the airport is 216 Joules.

Gravitational potential energy is the energy which is present inside the body of an object which is at rest. This energy is transformed into kinetic energy as soon as the object changes its state of rest to motion.

The gravitational potential energy of an object can be calculated through the formula:

GPE = m × g × h

where, GPE = Gravitational Potential Energy,

m = mass of the object,

h = height covered by the object

w = m × g

where, w = weight of the object

So, the gravitational potential energy of the object is:

GPE = 120 × 1.8

GPE = 216 Joules

Therefore, the gravitational potential energy of the suitcase is 216 Joules.

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Answer:

the answer is  b

Explanation:

The particles in the cold water moved at a slow rate until an increase in temperature caused an increase in particle motion in the hot tea.

According to the kinetic theory of matter, the particles that compose matter are in constant random motion. The particles collide frequently with each other as well as with the walls of the container.

The temperature of the system refers to the average kinetic energy of the molecules of the body. At a lower temperature, the speed of the particles of water is slow. As the temperature increases, more kinetic energy is imparted to the molecules of water and they move faster.

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The maximum force that the athlete exerts on the bag is NEGATIVE 1,500 N and in the OPPOSITE DIRECTION of the force that the bag exerts on the athlete.

Newton's third law of motion states action and reaction are equal and opposite. That is the force applied to an object is equal in magnitude to force experienced by the object but in opposite direction.

From the given question, when the bag exert a certain on the athlete, the athlete also exerts similar force to the bag but in opposite direction.

Thus, the complete sentence is as follows;

The maximum force that the athlete exerts on the bag is NEGATIVE 1,500 N and in the OPPOSITE DIRECTION of the force that the bag exerts on the athlete.

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The farthest away a target could be hit by a shell is approximately 1000 yards (rounded to the nearest whole number).

To solve the problem, we need to find the total distance that the shell can travel before it bursts.

The distance that the shell can travel is:

distance = rate × time

We are given that the shell can travel 500 yards in 1.5 seconds, so its speed is:

rate = distance ÷ time = 500 yards ÷ 1.5 seconds = 333.33 yards/second

Now we need to take into account the time it takes for the fuse to go off. Since it takes 3 seconds for the fuse to go off, the shell will have traveled:

distance = rate × time = 333.33 yards/second × (1.5 seconds + 3 seconds) = 999.99 yards

Therefore, the farthest away a target could be hit by a shell is approximately 1000 yards (rounded to the nearest whole number).

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Answer:

10.4

is your answer

I hope it helps mate

have a great day

I will always help you understanding your assingments

#Captainpower:)

Answer:

d = 6 km

Explanation:

In this case we have the relative speed of the boot changes, suppose that the boat and the river have the same direction when the boat goes from A to point B

       vbr = vrt + vbt

        vbr = 2 + 4

        vbr = 6 km / h

        v₁ = 6 km / h

velocity is constant

         v₁ = d / t₁

         t₁ = d / v₁

when the boat returns to the starting point the speed is both opposite

        vbr = vbt - vrt

        vbr = 4-2

        vbr = 2 km / h

        v₂ = 2 km / h

as the speed is constant

         t₂ = d / v₂

they also indicate that the total time is 4 h

       t₁ + t₂ = 4

we substitute

       4 = d / v₁ + d / v₂

       4 = d (1 / v₁ + 1 / v₂)

       d = 4 / (1 / v₁ + 1 / v₂)

let's calculate

       d = 4 / (1/6 + 1/2)

       d = 4 / 0.6666 67

       d = 6 km

A measure of mass per unit of volume. It is how much material a certain volume contains. ... If the volume of the object stays the same but the mass of the object increases then its density becomes greater.

The second player exerts a force of 495 N on the first player. It is worth noting that this force is equal and opposite to the force exerted by the first player on the second player, as dictated by Newton's Third Law.

To calculate the force exerted by the second player, we can use the formula:

Force = mass x acceleration

We can rearrange this formula to solve for acceleration:

Acceleration = Force / mass

For the second player:

Acceleration = 630 N / 140 kg

Acceleration = 4.5 m/s^2

Now that we know the acceleration, we can use it to calculate the force exerted by the second player on the first player:

Force = mass x acceleration

Force = 110 kg x 4.5 m/s^2

Force = 495 N

Therefore, the second player exerts a force of 495 N on the first player. It is worth noting that this force is equal and opposite to the force exerted by the first player on the second player, as dictated by Newton's Third Law.

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The charge to mass ratio of the electron (in 10^11 C/kg) can be determined by using the formula below, where e is the charge on an electron, and m is its mass:`e/m`

We can substitute the given charge of an electron as follows:`e = -1.60x10^-19 C`The mass of an electron is given by `9.11x10^-31 kg`.Therefore, the charge to mass ratio of the electron can be found as shown:`(-1.60x10^-19 C) / (9.11x10^-31 kg)`Multiplying by `10^11 C/kg` on both the numerator and the denominator:`= (-1.60x10^-19 C / 9.11x10^-31 kg) x (10^11 C/kg / 10^11 C/kg)`Simplifying:`= (-1.60 / 9.11) x 10^-8 (10^11 C/kg)`Therefore, the charge to mass ratio of the electron is:`= -0.175 x 10^3 C/kg = -1.75 x 10^11 C/kg.Given that the charge of an electron is -1.60x10^-19 C, we can find the charge to mass ratio of an electron by using the formula `e/m` where e is the charge of an electron and m is its mass.

To solve for the charge to mass ratio of the electron, we substitute the given values of e and m into the equation:`e/m = (-1.60x10^-19 C) / (9.11x10^-31 kg)`This simplifies to:`= -1.75 x 10^11 C/kg`Therefore, the charge to mass ratio of the electron is -1.75 x 10^11 C/kg.

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Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass = 244 g

volume = 90 mL

So we have

\(density = \frac{244}{90} = \frac{122}{45} \\ = 2.71111111...\)

We have the final answer as

Hope this helps you

Answer:

10.21 m/s

Explanation:

∆x =( v ^2 sin(2θ))/ g

rearrange this to get

v=√Δx·(g÷ sin(2θ))

Plug it in

v=√10·(-9.8÷sin(2·35))

Solve

v=10.21

Answer:

2ohms resistor

Explanation:

According to ohms law

V= IR

V is the potential difference

I is the current

R is the resistance

Since they have the same potential difference, this shows that they are connected in parallel

Let assume V = 20V

For the 4ohms resistor

I = V/R

I = 20/4

I = 5A

For the two ohms resistor

I = V/R

I = 20/2

I = 10A

This shows that the 2ohms resistor will have the bigger current because the smaller the load, the bigger the current and vice versa

Answer:

2

Explanation:

The language of the given pushdown automaton (PDA) can be described as follows:

The PDA has a stack alphabet consisting of symbols 'a', 'b', 'z', '6', '1', '۸', '2', '9', '0', 'x', 'y'. 'z' represents the stack end symbol.

The transitions of the pushdown automaton (PDA) are as follows:

Thus, the language accepted by this PDA is characterized by a sequence of 'a's followed by a sequence of 'b's, where the number of 'b's is three times the number of 'a's, and each 'b' is followed by a corresponding sequence of '90', '91', '92', 'a', 'b', 'b', 'b', '1', 'b', 'b', '1', and ending with '1'.

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(A) The angle of this in polar coordinates is 30⁰.

(B) The North/South and East/West components of its displacement is 250 m and 433 m respectively.

60° N of W lies in the fourth quadrant;

θ = 90 - 60 = 30⁰

in polar coordinate = (r,θ) = (500 m, 30⁰)

Dy = D sinθ

Dy = 500 m x sin(30) = 250 m

Dx = D cosθ

Dx = 500 m x cos(30) = 433 m

Thus, the angle of this in polar coordinates is 30⁰.

The North/South and East/West components of its displacement is 250 m and 433 m respectively.

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Answer:

Explanation:

C. Adding salt to water increases the boiling point and decreases the freezing point.

The mass of E is 28/3, and the center of mass is located at (35/36, 0, 7/4).

We can use the triple integral to find the mass and center of mass of the solid E:

The limits of integration for x are from 0 to 5z.

The limits of integration for y are from −1 to 1.

The limits of integration for z are from 0 to 1 − y²

The density function is given by ρ(x, y, z) = 7.

Thus, the mass of E is given by:

M = ∭E ρ(x, y, z) dV

= ∭E 7 dV

= ∫₀⁵z ∫₁⁻¹ ∫₀¹−y² 7 dz dy dx

= 28/3

The x-coordinate of the center of mass is given by:

x-bar = (1/M) ∭E xρ(x, y, z) dV

= (1/M) ∭E x(7) dV

= (1/M) ∫₀⁵z ∫₋₁¹ ∫₀¹−y² x(7) dz dy dx

= 35/36

Similarly, the y-coordinate of the center of mass is given by:

y-bar = (1/M) ∭E yρ(x, y, z) dV

= (1/M) ∭E y(7) dV

= (1/M) ∫₀⁵z ∫₋₁¹ ∫₀¹−y² y(7) dz dy dx

= 0

And, the z-coordinate of the center of mass is given by:

z-bar = (1/M) ∭E zρ(x, y, z) dV

= (1/M) ∭E z(7) dV

= (1/M) ∫0^5z ∫−1^1 ∫0^1−y^2 z(7) dz dy dx

= 7/4

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