Answer:
80/1
Explanation:
to figure out the answer of how many miles/meters per second divide the meters/miles by the second
so 400÷5 would be 80
80 meters per second
hope this helps :))
Which electrical component is used for detecting light levels in digital cameras?
The electrical component that is used for detecting light levels in digital cameras is the light meter.
What are light meters?A light meter is a device used to measure the amount of light. In photography industry, a light meter is used to determine the proper exposure for a photograph.
A digital camera is a camera that captures photographs in digital memory.
Most digital cameras can be grouped into four main types which includes:
digital SLR (or DSLR), point-and-shoot, bridge cameras, and camera phones.Each type of these digital cameras has advantages and disadvantages, and some the types are more expensive than their counterparts.
There are two different kinds of light meters which are:
incident and reflective.-An incident light meter measures all the light falling onto a subject. Incident light meters help a camera focus on a subject regardless of how light or dark the surrounding background is.
- Reflective light meters on the other hand do the opposite by measuring the light reflected by or bouncing off a subject.
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what is the energy equivalent of an object with a mass of 2.5 kg?
Answer:
2,500g is the answer yes
how can you use parallax to get the distance to a star? explain and write down the formula for distance in terms of parallax.
Parallax can be used to get the distance to a star by using the angular measurement concept. The formula d = 1/p is used to find the distance in terms of parallax.
The parallax method can be used to calculate the distance to stars. This method makes use of the concept of angular measurement to find the distance to stars. Angular measurement is used because measuring the distance to stars directly is difficult due to the vastness of the universe.
Parallax occurs when an observer on Earth sees an object in space from two different locations. The shift in the position of the star is known as the parallax angle. The parallax angle is the angle between the two lines of sight to the star.
The formula for distance in terms of parallax is:d = 1/pWhere d is the distance to the star in parsecs, and p is the parallax angle in arcseconds. The parsec is the unit of distance that astronomers use most often. It is the distance at which an object will have a parallax angle of 1 arcsecond when viewed from two different positions on Earth.
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An object at rest has no net force acting on it. 
True or False
Answer:
True
Explanation:
The object is at rest, which means it's not moving, so there is no net force on it, according to Newton's First Law.
1. A 25.0 kΩ resistor is hooked up to a 50.0 V battery in a circuit with a switch.
a.) Draw a circuit diagram for the circuit described. Label all parts and values.
b.) What is the current flowing through the resistor?
c.) What is the power dissipated by the resistor?
2.A 10.0 Ω resistor is hooked up in series with an 8.0 Ω resistor followed by a 27.0 Ω resistor. The circuit is powered by a 12.0 V battery.
a.) Draw a labeled circuit diagram for the circuit described.
b.) Calculate the equivalent resistance.
c.) Calculate the voltage drop across each resistor in the circuit.
3.A 9.0 V battery is hooked up with three resistors (R1, R2, R3) in parallel with resistances of 2.0 Ω, 5.0 Ω, and 10.0 Ω, respectively.
a.) Draw a labeled circuit diagram for the circuit described.
b.) Calculate the equivalent resistance.
c.) Calculate the current passing through each resistor in the circuit.
What does a simple pulley do?
A. It makes you have to pull harder on the rope.
B. It increases the force.
O O O O
C. It redirects the force.
D. It makes the load heavier.
Answer:
C. It redirects the force
the combination of a uniform flow and a source can be used to describe flow around a streamlined body called a half- body. (see video v6.5.) assume that a certain body has the shape of a half-body with a thickness of 0.5 m. if this body is placed in an airstream moving at 15 m/s, what source strength is required to simulate flow around the body?
The combination of a uniform flow and a source can be used to describe flow around a streamlined body called a half- body. (see video v6.5.) assume that a certain body has the shape of a half-body with a thickness of 0.5 m. if this body is placed in an airstream moving at 15 m/s, The source strength is required to simulate flow around the body is (m)= 94.2 kg.
What is force?Force is a physical appearance that happen on a object of some amount of masses and then it changes it form and move a bit that called the force. It is a vector quantity. It can be measured in Newton, Dyne.
How can we calculate the source strength is required to simulate flow around the body?To calculate the source strength is required to simulate flow around the body we are using the formula here is,
v= m/2*π*b
Or, m= 2*π*b*v
Here we are given,
b= The thickness of a certain body has the shape of a half-body = 2*r = 2* 0.5 = 1 m
v = The velocity of the object. = 15 m/s.
We have to calculate the values of the source strength is required to simulate flow around the body = m kg
Now we put the values in above equation we get,
m= 2*π*b*v
Or, m= 2*π*1*15
Or, m= 94.2 kg
so we can say that , The source strength is required to simulate flow around the body is (m)= 94.2 kg
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A spring of k=500 N/m that is initially compressed 2m is used to launch a 100N load of bricks up a 2 m tall 
hill. Find the speed of the bricks at the top of the hill. 
a. Qualitatively complete the energy flow diagram and the energy bar graphs.
c. Determine the speed
e. What would the speed at the top of the hill be with 2m of initial compression if 15% of the energy is 
dissipated through friction?
d. What is the minimum compression of the spring necessary to get to the top of the hill? (v=0 at top, no 
friction)
Speed of the bricks at the top of hill is 6.26 m/s. c.)speed of the bricks at the top of hill is 14.14 m/s. d)minimum compression of spring necessary to get to the top of hill is 6.26 m. e) speed of the bricks at the top of hill with 2 m of initial compression and 15% energy dissipation is 13.04 m/s.
What is energy?The capacity or power to do work, such as the capacity to move an object by application of force is called energy.
Initial potential energy of compressed spring is:
Ep = 1/2 kx^2 = 1/2 * 500 N/m * (2 m)^2 = 1000 J
k is spring constant, x is compression of the spring, and J is unit of energy in joules.
Final potential energy of the bricks is:
Ep = mgh = 100 N * 9.81 m/s^2 * 2 m = 1962 J
Ep = Ep
1/2 kx^2 = mgh
v = sqrt(2gh) = sqrt(2 * 9.81 m/s^2 * 2 m) = 6.26 m/s
Therefore, the speed of the bricks at the top of the hill is 6.26 m/s.
c. Initial potential energy of compressed spring is: 1000 J
Ek = Ep = 1000 J
Kinetic energy of the bricks is given by:
Ek = 1/2 mv^2
1000 J = 1/2 * 100 N * v^2
v = sqrt(200 / 1) = 14.14 m/s
Therefore, the speed of the bricks at the top of the hill is 14.14 m/s.
d. As, Ep = m g h
where m is mass of the bricks, g is acceleration due to gravity, and h is height of the hill.
Ep = 100 N * 9.81 m/s^2 * 2 m = 1962 J
Ep = 1/2 kx^2 = 1962 J
1/2 * 500 N/m * x^2 = 1962 J
x = sqrt(2 * 1962 J / 500 N/m) = 6.26 m
Therefore, the minimum compression of the spring necessary to get to the top of the hill is 6.26 m.
e. If 15% of the energy is dissipated through friction, final kinetic energy of the bricks at the top of the hill will be 85% of initial potential energy of the compressed spring. Therefore,
0.85 * 1000 J = 1/2 mv^2
v = sqrt(170 / 1) = 13.04 m/s
Therefore, the speed of the bricks at the top of the hill with 2 m of initial compression and 15% energy dissipation is 13.04 m/s.
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A hot air balloon pilot wants the balloon to quickly rise several feet higher so it will be above some trees in the distance. Which best explains how the pilot can make the balloon rise?
The pilot can adjust the temperature inside the balloon so it is equal to the temperature of the surrounding air. 
The pilot can adjust the density of the air inside the balloon so it is equal to the density of the surrounding air. 
The pilot can decrease the temperature inside the balloon so it is cooler than the surrounding air. 
The pilot can increase the temperature inside the balloon so it is warmer than the surrounding air.
Answer:
temperature inside the balloon so it is warmer than the surrounding air
Explanation:
For the balloon to get an uplift , it should be lighter than air . That means the density of the gas inside should be less than the density of air outside . only then , weight of the balloon plus the weight of the air inside balloon will become less than the weight of displaced air outside . This can be achieved by warming up the air inside. Its temperature must exceed that of outside air.
The option that best explain how the pilot can make the balloon rise is option D. The pilot can increase the temperature inside the balloon so it is warmer than the surrounding air
An object will float in air when the density of the object is lower than the density of the air.
Increase in temperature of a gas decreases the density of the gas.
For the pilot to make the balloon rise, he must find a way to make the balloon more lighter than air. To do this, he has to increase the temperature of the balloon.
In this question, the pilot can increase the temperature inside the balloon so it is warmer than the surrounding air in order for the balloon to quickly rise several feet higher above some trees in distance.
Therefore, option D best explain how the pilot can make the balloon rise.
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Which new type of bacteria was introduced to Patient 23's gut microbiome?
Answer:
Gut flora
Explanation:
Q2 (a) A radar, with coordinates (0,0), has coverage with length of d. While the second radar, with identical coverage, is situated on the east side of the first one. Using signal intersection, both radars detect an object coming closer to the southern direction in the first quadrant. Note that radars swap the covered area into circles.
i) Identify position of the object in terms of distance and angle. Complete your answer with a sketch.
ii) Analyze and calculate the overlapping area from the radar signals intersection at the first quadrant.
Considering the coordinates of the radars as well as the direction of the object in order to determine the object's position in terms of distance and angle. Sincе thе radars arе situatеd at (0,0) and thе sеcond radar is on thе еast sidе of thе first onе, wе can assumе that thе first radar is locatеd on thе x-pivot and thе sеcond radar is locatеd on thе positivе y-hub.
Lеt's say thе objеct is dеtеctеd at coordinatеs (x, y). The objесt's y-coordinativity will be negative and its x-coordinativity positive as it approaches the southern direction in the first quadrant.
We can use the distancе formula to determine the object's diameter from its origin (0, 0):
Distancée = (x + y) 2 The angle can be calculated with trigonometry. The angle can be summarized as:
= arctan(y/x) ii) We must consider the circles of overlap for each radar in order to calculate the overlap from the radar signal intersection in the first quadrant.
Due to the fact that both radars have distinctive overlap and divide the covered area into circles, the overlapped area will be the intersection of these circles.
Thе ovеrlapping arеa can bе calculatеd by finding thе arеa of thе intеrsеction of two circlеs. The formula for the area of the intersection of two circles can be complex and depends on the specific radii and dimensions that exist between the circles' centers.
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1) The electromagnetic spectrum of light is often arranged in terms of frequency. Which one of the following has the highest frequency (circle one)?
 visible 
 light 
	
	
 microwaves 
 radio 
 waves 
	
	
 X-rays 
	
 infrared 
 light 
	
	
 gamma 
 rays 
	
 ultraviolet 
 light 
	
	
2) The electromagnetic spectrum of light can also be arranged in terms of wavelengths. Which one of the following has the longest wavelength (circle one)? \begin{tabular}{ccccc} visible light & X-rays & ultraviolet & unfrared light & light \\ & gamma & microwaves & \multicolumn{2}{c}{ radio } \\ rays & & waves \end{tabular} 3) Which of the following types of light travels at the fastest speed (circie your answer(s))? Explain your answer:
Answer: The increasing order of frequency of electromagnetic spectrum of light: Gamma Ray> X-Rays> Ultraviolet Rays> Visible Rays> Infrared Rays> Microwave rays> Radio waves.
Explanation:
1) Among the options provided, infrared light has the lower frequency in the electromagnetic spectrum.
Decreasing order of frequency: Gamma Ray> X-Rays> Ultraviolet Rays> Visible Rays> Infrared Rays> Microwave rays> Radio waves.
2) In the electromagnetic spectrum, radio waves have the longest wavelength among the options provided.
3) All types of light travel at the same speed, which is the speed of light (approximately 3 x 10^8 meters per second) in a vacuum. This includes visible light, X-rays, ultraviolet, infrared light, gamma rays, microwaves, and radio waves. The reason they all travel at the same speed is because they are all electromagnetic waves, and their speed is determined by the properties of the medium through which they travel (in this case, a vacuum).
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Now, let's perform the calculation. At the Sun's current luminosity, and with Earth having an average albedo of 0.3, Working It Out 5.4 demonstrates that Earth's blackbody temperature is 255 K. Suppose the Sun had exactly 10 times its current luminosity and Earth had the same albedo. What would Earth's blackbody temperature be in this scenario?
The Earth's blackbody temperature would be approximately 303 K (or 30 degrees Celsius) in this scenario, assuming the Earth's albedo remains the same.
This can be calculated using the Stefan-Boltzmann law, which states that the amount of radiation emitted by a blackbody is proportional to its fourth power temperature. Since the Sun's luminosity is 10 times greater, the Earth would receive 10 times more energy and therefore its temperature would increase. Specifically, the temperature would increase by the fourth root of 10 (since the energy received by the Earth is proportional to the square of the distance from the Sun). This calculation results in a temperature increase of about 1.8 times, or approximately 48 degrees Celsius. Therefore, adding this to the Earth's current blackbody temperature of 255 K gives a new temperature of approximately 303 K.
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The blackbody temperature of the Earth would be 255 K x 1.78 = 453.9 K.
According to the Stefan-Boltzmann law, the temperature of a blackbody is directly proportional to the fourth root of its luminosity. Therefore, if the Sun had exactly 10 times its current luminosity, the Earth's blackbody temperature would increase by the fourth root of 10, which is approximately 1.78. So, the new blackbody temperature of the Earth would be 255 K x 1.78 = 453.9 K.
This is significantly higher than the current blackbody temperature of the Earth, and would likely result in a much warmer planet. It is important to note that this calculation assumes that the Earth's albedo remains the same, even though an increase in temperature could potentially lead to changes in the Earth's albedo.
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Qsn 2 full question please?
 
                                                Answer:
the work done by the worker in pulling the crate is 500 J, and the kinetic energy of the crate at the end of the 10 m distance is 292.13 J.
Explanation:
To solve the problem, we need to first resolve the applied force and the frictional force into their horizontal and vertical components. The horizontal component of the applied force is:
F_h = Fcos(30°) = 50cos(30°) = 43.3 N
The vertical component of the applied force is:
F_v = Fsin(30°) = 50sin(30°) = 25 N
The frictional force is acting in the opposite direction to the applied force, so its horizontal component is:
f_h = -F_f = -20 N
Since the crate is initially at rest, the net force on the crate is equal to the applied force minus the frictional force:
F_net = F_h + f_h = 43.3 - 20 = 23.3 N
The acceleration of the crate is given by Newton's second law:
F_net = ma
where a is the acceleration of the crate. Rearranging this equation, we get:
a = F_net/m = 23.3/30 = 0.78 m/s²
The work done by the worker in pulling the crate a distance of 10 m is given by:
W = Fdcos(θ)
where d is the distance pulled, and θ is the angle between the applied force and the displacement. In this case, θ = 0° since the force is applied horizontally. Therefore, the work done is:
W = Fd = 5010 = 500 J
The kinetic energy of the crate at the end of the 10 m distance is:
K = (1/2)mv²
where v is the final velocity of the crate. We can find v using the equation of motion:
v² = u² + 2as
where u is the initial velocity (zero), s is the displacement (10 m), and a is the acceleration (0.78 m/s²). Therefore:
v² = 0 + 20.7810 = 15.6
v = sqrt(15.6) = 3.95 m/s
Substituting this value of v into the equation for kinetic energy, we get:
K = (1/2)mv² = (1/2)30(3.95)² = 292.13 J
Therefore, the work done by the worker in pulling the crate is 500 J, and the kinetic energy of the crate at the end of the 10 m distance is 292.13 J.
A car with a mass of 1,200 kg travels a distance of 150 m as it moves from
one stoplight to the next. At its fastest, the car travels at 22 m/s. What is its
kinetic energy at this point?
A. 290,400
B. 8,872 J
C. 580,800 J
D. 13,200 J
Answer:
A. 290,400
Explanation:
The kinetic energy of a car is 290,400J.
How to find Kinetic energy?Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2.
ke = 1/2mv^2
By using the formula, we get
= 1/2 * 1200 * 22^2
= 600 * 484
= 290,400 J
Kinetic energy is a form of energy that an object or a particle has by reason of its motion. If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.
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An astronaut floating freely in space decides to use his flash light as a rocket. He shines a 10 watt light beam in a fixed direction so that he acquires momentum in the opposite direction. If his mass is 80 kg, how long must he need to reach a velocity of 1 ms
The astronaut decides to use his flashlight as a rocket. He shines a 10-watt light beam in a fixed direction so that he acquires momentum in the opposite direction.
The mass of the astronaut is 80 kg.
the time required by the astronaut to reach a velocity of 1 m/s.Given,Mass of the astronaut, m = 80 kgPower of light, P = 10 WVelocity acquired by the astronaut, v = 1 m/s
The momentum acquired by the astronaut is given by:
momentum = Power * time / speed
Therefore, Time is taken, t = momentum * speed/power
first calculate the momentum of the astronaut using the given power. We know that the power is given by P = F * v, where F is the force applied, and v is the velocity of the beam.
P = F * vF = P / v = 10 / (3 * 10^8) = 1 / 3 * 10^8 N
Time taken to reach a velocity of 1 m/s is given by:t = m * v / F = 80 * 1 / (1 / 3 * 10^8)= 2.4 * 10^8 s
Therefore, the astronaut needs 2.4 * 10^8 seconds to reach a velocity of 1 m/s.
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whne was physics created
Answer:
energy and matter
Explanation:
physics is the study of matter and it interaction with energy
in a chemical equation, where do the products appear
Answer:
products would appear after the raw materials
Explanation:
raw material + raw material = product (anything deriving from combining two materials)
14. What is the mass of a 250 N bag of groceries?
Answer:
mass = 25.5kg
Explanation:
The gravitational force equivalent, or, more commonly, g-force, is a measurement of the type of force per unit mass – typically acceleration – that causes a perception of weight, with a g-force of 1 g equal to the value of gravitational acceleration on Earth, g, of about 9.8 m/s².
Mass, m = \(\frac{Force}{acceleration due to gravity}\)
\(mass,m=\frac{F}{g} = \frac{250}{9.8}= 25.5 kg\)
INSTRUCTIONS:
 (1) Avoid using of and/or referring to any online sources!
 (2) Write in your own words and sufficiently explain your reasoning based on your understanding of the astronomy concepts and thoughts presented in the chapter/textbook and related astronomy/astrophysics journals!
 W.Q. 1: If photons of blue light have more energy than photons of red light, how can a beam of red light carry as much energy as a beam of blue light?
 W.Q. 2: Name and explain at least two (2) advantages that reflecting telescopes have over refractors.
 W.Q. 3: What is refraction and what causes it? Explain
 NEXT PAGE!
 W. Q. 4: Consider two optically perfect telescopes having different diameters but the same focal length. Is the image of a star larger or smaller in the focal plane of the larger telescope? Explain your answer!
 W. Q. 5: Explain quantum efficiency and how it contributes to the detection of faint astronomical objects.
1) The number of photons in each beam is what determines the amount of energy each beam carries. A beam of red light contains more photons than a beam of blue light, but each photon in the blue beam carries more energy than each photon in the red beam. Therefore, the two beams can carry the same amount of energy despite having different energies per photon.
2) Reflecting telescopes have two advantages over refractors. They are cheaper to manufacture, and they do not suffer from chromatic aberration.
3) Refraction is the bending of light as it passes from one medium to another. Refraction occurs because light waves travel at different speeds through different materials. The amount of refraction depends on the angle at which the light passes through the medium.
4) The image of a star is larger in the focal plane of the larger telescope. This is because the larger telescope collects more light than the smaller telescope, which means that the image is brighter and has a higher signal-to-noise ratio.
5) Quantum efficiency is a measure of how efficiently a detector converts incoming photons into electrical signals. A higher quantum efficiency means that more of the incoming
photons are detected, which makes it easier to detect faint astronomical objects.
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1) The number of photons in each beam is what determines the amount of energy each beam carries.
2) Reflecting telescopes have two advantages over refractors.
3) Refraction is the bending of light as it passes from one medium to another.
4) The image of a star is larger in the focal plane of the larger telescope.
5) Quantum efficiency is a measure of how efficiently a detector converts incoming photons into electrical signals.
1) The number of photons in each beam is what determines the amount of energy each beam carries. A beam of red light contains more photons than a beam of blue light, but each photon in the blue beam carries more energy than each photon in the red beam. Therefore, the two beams can carry the same amount of energy despite having different energies per photon.
2) Reflecting telescopes have two advantages over refractors. They are cheaper to manufacture, and they do not suffer from chromatic aberration.
3) Refraction is the bending of light as it passes from one medium to another. Refraction occurs because light waves travel at different speeds through different materials. The amount of refraction depends on the angle at which the light passes through the medium.
4) The image of a star is larger in the focal plane of the larger telescope. This is because the larger telescope collects more light than the smaller telescope, which means that the image is brighter and has a higher signal-to-noise ratio.
5) Quantum efficiency is a measure of how efficiently a detector converts incoming photons into electrical signals. A higher quantum efficiency means that more of the incoming
photons are detected, which makes it easier to detect faint astronomical objects.
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a beam of light in water (n = 1.33) enters a glass slab (n = 1.50) at an angle of incidence of 60.0°. what is the angle of refraction? a. 90.0° b. 60.0° c. 39.8° d. 50.2° e. 27.5°
The angle of refraction is approximately 39.8°, which is answer choice C at an angle of incidence of 60.0°
To find the angle of refraction, we can use Snell's Law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the inverse ratio of the indices of refraction:
n1 * sin(angle1) = n2 * sin(angle2)
In this case, n1 = 1.33 (water), n2 = 1.50 (glass), and angle1 = 60.0°. We want to find angle2.
1.33 * sin(60.0°) = 1.50 * sin(angle2)
Now, we need to solve for angle2:
sin(angle2) = (1.33 * sin(60.0°)) / 1.50
angle2 = arcsin((1.33 * sin(60.0°)) / 1.50)
angle2 ≈ 39.8°
So the angle of refraction is approximately 39.8°, which is answer choice C.
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A body has weight 20N. How much force is required to move it vertically upward with an acceleration of 2ms-2
A body has weight 20N.
The force required to move the body vertically upward with an acceleration of 2 m/\(s^{2}\) can be found using Newton's second law, which states that force is equal to mass times acceleration.
The mass of the body can be found using the formula
Weight = mass × gravitational acceleration
Where gravitational acceleration is approximately 9.81 m/\(s^{2}\).
Therefore,
Mass = Weight / gravitational acceleration
Mass = 20 N / 9.81 m/\(s^{2}\) = 2.039 kg
Now, we can use Newton's second law to find the force required
Force = mass × acceleration
Force = 2.039 kg × 2 m/\(s^{2}\)= 4.078 N
Therefore, a force of 4.078 N is required to move the body vertically upward with an acceleration of 2 m/\(s^{2}\).
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a sight glass that is full of vapor or liquid may look the same.
The given statement is true. A sight glass is a transparent or translucent window installed in a pipeline or vessel to visually inspect the presence, level, and characteristics of a fluid.
Explanation: When a sight glass is full of vapor, it may appear similar to when it is filled with liquid. This is because both vapor and certain liquids can be transparent or have similar optical properties. In such cases, it can be challenging to distinguish between a sight glass filled with vapor and one filled with liquid by visual observation alone.
To accurately determine whether a sight glass is filled with vapor or liquid, additional information or techniques may be required.
For example, measuring the temperature or pressure of the system, observing any condensation or evaporation occurring in the sight glass, or employing other complementary instruments or indicators can help differentiate between vapor and liquid contents.
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(8th grade HELP)
1. Inertia causes a stationary object to...
a.stay still
b.move
c.have an increased velocity
d.change it’s speed or direction
2. Once an applied force causes an object to start moving, the object keeps moving because....
a.none of the above
b.the force continues to be applied to it
c.no other force is acting on it
d.it has inertia
Which of the following best describes the velocity of an object?
A B0 m/s
B 30 m east
C 30 m/s east
D 30 m/s2
Explain how you got the answer
Answer:
27
Explanation:
a force of 315 n is exerted on the pedal cylinder of an automatic hydraulic system. The pedal cylinder has a diameter of 0,450 cm. How much pressure is transmitted in the hydraulic system? Express your answer in atmospheres.
The pressure transmitted in the hydraulic system is approximately 195.33 atm. The pressure transmitted in the hydraulic system can be calculated by dividing the force applied by the area of the pedal cylinder.
The given force is 315 N and the diameter of the pedal cylinder is 0.450 cm. To calculate the area, we need to convert the diameter to meters by dividing it by 100. Thus, the radius of the pedal cylinder is 0.450 cm / 2 / 100 = 0.00225 m.The area of the pedal cylinder is then calculated using the formula for the area of a circle: A = π * r^2. Substituting the values, we have A = π * (0.00225)^2 ≈ 0.0000159 m^2.Now, we can calculate the pressure by dividing the force (315 N) by the area (0.0000159 m^2). The pressure transmitted in the hydraulic system is approximately 19,811,320.75 Pa.To express the pressure in atmospheres, we can convert Pa to atm by dividing by the standard atmospheric pressure, which is approximately 101,325 Pa. Therefore, the pressure transmitted in the hydraulic system is approximately 195.33 atm.
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The isotope of plutonium 238 Pu is used to make thermoelectric power sources for spacecraft. Suppose that a space probe was launched in 2012 with 2.0 kg of 238 Pu.
The space probe launched in 2012 with 2.0 kg of plutonium-238 (238Pu) is utilized for thermoelectric power sources in spacecraft.
Plutonium-238 (238Pu) is an isotope of plutonium that undergoes radioactive decay, emitting heat in the process.
This unique property makes it an ideal choice for generating power in space missions where sunlight is limited, such as deep space probes or missions to distant planets. The heat produced by the radioactive decay of 238Pu is converted into electricity using thermoelectric materials.
In the context of the space probe launched in 2012, the 2.0 kg of 238Pu serves as the fuel for the thermoelectric power source.
The heat generated by the decay of the plutonium is harnessed to produce electricity through the Seebeck effect.
Thermocouples, made from two dissimilar materials, are used to create a temperature gradient. As the heat flows across the junction of the thermocouple, it creates a voltage difference that can be utilized to power the spacecraft's instruments, systems, and communication devices.
The use of 238Pu as a power source offers several advantages for space missions.
Unlike solar panels, which are dependent on sunlight, thermoelectric generators powered by plutonium-238 can operate in deep space or in regions where solar energy is insufficient.
This is particularly crucial for missions that venture beyond the orbit of Mars or explore dark, shadowed areas where sunlight is scarce.
Additionally, the longevity of 238Pu's decay heat allows for prolonged power generation, ensuring continuous operation and data transmission over long-duration missions.
Plutonium-238 (238Pu) is a scarce and highly valuable resource due to its applications in space exploration. It is primarily produced through the irradiation of neptunium-237 in nuclear reactors.
The production and handling of 238Pu require strict safety measures due to its high radioactivity. Furthermore, the dwindling global supply of 238Pu has posed challenges for future space missions relying on this isotope.
The development of alternative power sources and the search for innovative ways to produce and utilize plutonium-238 remain areas of active research in the field of space exploration.
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It refers to the condition of the atmosphere in a place over a long period of time.
Answer:
Climate
Explanation:
conditions of the atmosphere at a particular location over a long period of time; it is the long-term summation of the atmospheric elements
Which two statements about earth's oceanic and continental crust are true? A. Oceanic crust is thicker than continental crust. B. Oceanic crust is denser that continental crust. C. Continental crust is darker in color than oceanic crust. D. Continental crust is older than oceanic crust. PLEASE HELPPPPPP I GIVE LOT OF POINTS I NEED THIS
The oceanic crust is not thicker than the continental crust. The thickness of the continental crust is typically 30 km, compared to the oceanic crust's average thickness of 7 km.
Is the continental crust thicker than the oceanic crust on Earth?There are two different types of crust that cover the Earth: continental and oceanic. The continental crust is typically up to 25 miles thick, whereas the thinner oceanic crust is typically a little over four miles thick.
Is it accurate to say that the crust on land is thicker than that on the ocean?The thickness of the continental crust is normally 40 km (25 miles), whereas the thickness of the oceanic crust is only 6 km (4 miles). Different densities of lithospheric rock's impact can be seen in
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A student makes a voltage divider from a 45-V battery, a 475-k
resistor, and a 235-k resistor. The output is measured across the
smaller resistor. What is the voltage?
Answer:
14.9 v
Explanation:
V = IR
The voltages across the resistors will be proprtional to the values of the resistors
45 * 235 / (235 + 475) =