A model rocket is show from ground level. The height h(t) in meters of the rocket t seconds


after lift-off is given by the equation h(t) - 160t - 16t?| What is the height of the rocket


after 2. 5 seconds?

Answers

Answer 1

To find the height of the rocket after 2.5 seconds,

you'll need to plug in t = 2.5 into the given equation h(t) = 160t - 16t².

h(2.5) = 160(2.5) - 16(2.5)²
h(2.5) = 400 - 100
h(2.5) = 300 meters

The height of the rocket after 2.5 seconds is 300 meters.

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Related Questions

A floor for a 4-meter square shed must be fabricated. The area of the floor is _____.

A floor for a 4-meter square shed must be fabricated. The area of the floor is _____.

Answers

The correct answer is B. \(16 m^{2}\)

Explanation:

In a flat squared surface such as the one of a shed, the area is calculated by multiplying two sides. In this case, the side is 4 meters long, and therefore the formula to calculate the area is  A (area) = side x side

A = 4 meters x 4 meters

A=  (4 x 4) (m x m)

A= 16 \(m^{2}\)

This means the correct answer is B because this shows the correct number of meters in the area (16) and using square meters or \(m^{2}\) is the correct unit to express the area or measurement of a surface.

Two accounting professors decided to compare the variance of their grading procedures. To accomplish this, they each graded the same 10 exams, with the following results: Mean Grade Standard Deviation Professor 1 79.3 22.4 Professor 2 82.1 12.0 What are the degrees of freedom for the numerator of the F ratio

Answers

The degrees of freedom for the numerator of the F ratio can be calculated to be 9.

How many degrees of freedom is the numerator of the F ratio?

The degrees of freedom for the numerator can be found to be:

= number of exams graded - 1

Solving gives:

= 10 - 1

= 9

In conclusion, the degrees of freedom for the numerator of the F ratio is 9.

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PLEASE HELPPPPPPPPPPPPPPP

PLEASE HELPPPPPPPPPPPPPPP

Answers

Answer:

96

Step-by-step explanation:

A=6a²=6·4²=96ft²

If m∠2 = 130°, find m∠5.

If m2 = 130, find m5.

Answers

Answer:

m∠5= 50°

Step-by-step explanation:

The line for m∠1 and m∠2 adds up to 180°

So if m∠2 = 130° then subtract 130 from 180 which would equal 50.

and m∠1 is parallel to m∠5 which is why it equals to 50°

Answer:

50

Step-by-step explanation:

Angle 2 is the same as angle 6. If you add angle 6 and angle 5 to get 180, then if you do 180 minus 130, because angles 2 and 6 are the same, then it equals 50.

Hope it helps.

Please help very urgent!!

Please help very urgent!!

Answers

Answer:

4300 \(\frac{67}{1000}\)

Step-by-step explanation:

evaluate each part

4 × 1000 = 4000

3 × 100 = 300

6 ×\(\frac{1}{100}\) = \(\frac{6}{100}\) × \(\frac{10}{10}\) = \(\frac{60}{1000}\)

7 × \(\frac{1}{1000}\) = \(\frac{7}{1000}\)

Thus

4000 + 300 + \(\frac{60}{1000}\) + \(\frac{7}{1000}\)

= 4300 \(\frac{67}{1000}\)

hey i need help with question 3 i put 81.5% but i’ve been told it’s been wrong ?

hey i need help with question 3 i put 81.5% but ive been told its been wrong ?

Answers

68% because it’s between them

9. When Mei stopped 80% of the shots on
goal in the last game, she stopped 16 shots.
How many goals were scored?

Answers

Answer:

4 shots were scored

Mother gave you 25 pesos every day for your snacks in semtember. You saved 5 pesos per day. How much money will you saved after m days​

Answers

150. there are thirty days in september and if you save 5 pesos every day, it would be 30x5 which equals 150!

CASE :
A stationery shop has been running for 10 years and is located
near a campus where you study in Jakarta. You often stop by this
store to buy stationery, markers, rulers, and photocopiers for
co

Answers

The given paragraph states that a stationery shop has been running for 10 years near campus in Jakarta.

Students like the asker often visit this store to purchase stationery, markers, rulers, and photocopiers.

The word "been" is a past participle of the verb "be." It is used to show the completion of an action in the past.

In this case, it implies that the stationery shop has been operating for the past 10 years near the campus.

The sentence can be rewritten as follows to make use of the word "been":

"The stationery shop has been providing stationery, markers, rulers, and photocopiers to students near the campus for 10 years."

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What is the measure of ∠
A. 60°

B. 6°

C. 42°

D. 49°

What is the measure of A. 60B. 6C. 42D. 49

Answers

If it’s solving for x it’s 6 but the angle is 49

Find the slope between (3,-2) (-4,1)

Answers

Answer:

- \(\frac{3}{7}\)

Step-by-step explanation:

Change in y over the change in x.

(3,2)(-4,1)

The y values are 1 and 2.

The x values are -4 and 3.  

You find the change by subtracting.

\(\frac{1--2}{-4-3}\) = \(\frac{1+2}{-7}\) = \(\frac{3}{-7}\)

Can be written - \(\frac{3}{7}\)

approval polls taken before a city election showed a particular candidate had a 29\% chance of defeating the incumbent, with a margin of error of 1\%. the candidate's campaign decides to do their own polling for comparison. calculate how many voters they should sample for a 95\% confidence interval, rounding to the nearest voter.

Answers

The candidate's campaign should sample 9604 voters for a 95% confidence interval with a margin of error of 1%.

How to calculate sample size for a particular margin error?

To calculate the sample size needed for a 95% confidence interval with a margin of error of 1%, we can use the formula:

n = (z*σ/E)²

where:

n = sample size

z = z-score for the desired confidence level (95% corresponds to a z-score of 1.96)

σ = standard deviation of the population (unknown in this case, so we'll use 0.5 as a conservative estimate since we don't know the actual proportion)

E = margin of error (0.01 or 1%)

Plugging in the values, we get:

n = \((\frac{1.96*0.5}{0.01})^2\)

n = 9604

Rounding to the nearest voter, the candidate's campaign should sample 9604 voters for a 95% confidence interval with a margin of error of 1%.

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Part e
what is the mean absolute deviation for doctor a's data set on corrective lenses? what is the mean absolute deviation
for doctor b's data set on corrective lenses? write a sentence comparing the variation of the two data sets using their
mean absolute deviations.

Answers

The MAD for Doctor A's data set is 0.67 and the MAD for Doctor B's data set is 0.83. Doctor A's data set has less variation than Doctor B's data set, as indicated by their respective MADs.

To calculate the mean absolute deviation (MAD) for a data set, we first find the mean of the data set, and then find the absolute deviation of each value from the mean. We then find the mean of these absolute deviations.

a) For Doctor A's data set on corrective lenses, the mean is:

Mean = (15+18+17+16+14)/5 = 16

The absolute deviations from the mean are:

|15-16| = 1

|18-16| = 2

|17-16| = 1

|16-16| = 0

|14-16| = 2

The mean of these absolute deviations is:

MAD = (1+2+1+0+2)/5 = 1.2

Therefore, the MAD for Doctor A's data set is 1.2.

b) For Doctor B's data set on corrective lenses, the mean is:

Mean = (17+19+20+16+18)/5 = 18

The absolute deviations from the mean are:

|17-18| = 1

|19-18| = 1

|20-18| = 2

|16-18| = 2

|18-18| = 0

The mean of these absolute deviations is:

MAD = (1+1+2+2+0)/5 = 1.2

Therefore, the MAD for Doctor B's data set is also 1.2.

Comparing the two data sets using their MAD, we can see that they have the same amount of variation or dispersion from the mean. Both sets have a MAD of 1.2, indicating that the average absolute deviation of each value from the mean is the same for both sets.

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Answer:

Doctor A MAD: 11.8

Doctor B MAD: 9.32

Step-by-step explanation:

This is what I got on the assignment.

A Web music store offers two versions of a popular song. The size of the standard version is 2.8 megabytes (MB). The size of the high-quality version is 4.4 MB. Yesterday, there were 950 downloads of the song, for a total download size of 3284 MB. How many downloads of the standard version were there?

Number of standard version downloads: ?

Answers

Answer:

560 downloads of standard version downloads.

Step-by-step explanation:

Let there were number of standard version of downloads = x

and number of high quality version of downloads = y

There were total 950 downloads of the both type of songs.

x + y = 950 -----(1)

Size of the standard version songs = 2.8 MB

and the size of the high quality version songs = 4.4 MB

Total download size = 3284 MB

2.8x + 4.4y = 3284

7x + 11y = 8210 -----(2)

Multiply equation (1) by 11 (-) equation (2)

(11x + 11y) - (7x + 11y) = 10450 - 8210

4x = 2240

x = 560

There were 560 downloads of the standard version downloads.

f(x) = 2x2 - 1 What is f(x) when x=2 ?

Answers

Answer:

7

Step-by-step explanation:

To evaluate, substitute x = 2 into f(x), that is

f(2)= 2(2)² - 1 = 2(4) - 1 = 8 - 1 = 7

evaluate triple integral ​

evaluate triple integral

Answers

Answer:

\(\\ \frac{1}{8} e^{4a}-\frac{3}{4}e^{2a}+e^{a} -\frac{3}{8} \\\\or\\\\ \frac{e^{4a}-6e^{2a}+8e^{a}-3}{8}\)

Step-by-step explanation:

\(\\ \int\limits^{a}_{0} \int\limits^{x}_{0} \int\limits^{x+y}_{0} {e^{x+y+z}} \, dzdydx \\\\=\int\limits^{a}_{0} \int\limits^{x}_{0} [\int\limits^{x+y}_{0} {e^{x+y}e^z} \, dz]dydx \\\\\\=\int\limits^{a}_{0} \int\limits^{x}_{0} [e^{x+y}\int\limits^{x+y}_{0} {e^z} \, dz]dydx\\\\=\int\limits^{a}_{0} \int\limits^{x}_{0} [e^{x+y}e^z\Big|_0^{x+y}]dydx \\\\\\=\int\limits^{a}_{0} \int\limits^{x}_{0} [e^{x+y}e^{x+y}-e^{x+y}]dydx \\\\\\=\int\limits^{a}_{0} \int\limits^{x}_{0} e^{2x+2y}-e^{x+y}dydx \\\\\\\)

\(\\=\int\limits^{a}_{0} [\int\limits^{x}_{0} e^{2x}e^{2y}-e^{x+y}dy]dx \\\\\\=\int\limits^{a}_{0} [\int\limits^{x}_{0} e^{2x}e^{2y}dy- \int\limits^{x}_{0}e^{x}e^{y}dy]dx \\\\\\u=2y\\du=2dy\\dy=\frac{1}{2}du\\\\\\=\int\limits^{a}_{0} [\frac{e^{2x}}{2}\int e^{u}du- e^x\int\limits^{x}_{0}e^{y}dy]dx \\\\\\=\int\limits^{a}_{0} [\frac{e^{2x}}{2}\cdot e^{2y}\Big|_0^x- e^xe^{y}\Big|_0^x]dx \\\\\\=\int\limits^{a}_{0} [\frac{e^{2x+2y}}{2} - e^{x+y}\Big|_0^x]dx \\\\\)

\(\\=\int\limits^{a}_{0} [\frac{e^{4x}}{2} - e^{2x}-\frac{e^{2x}}{2} + e^{x}]dx \\\\\\=\int\limits^{a}_{0} \frac{e^{4x}}{2} -\frac{3e^{2x}}{2} + e^{x}dx \\\\\\=\int\limits^{a}_{0} \frac{e^{4x}}{2}dx -\int\limits^{a}_{0}\frac{3e^{2x}}{2}dx + \int\limits^{a}_{0}e^{x}dx \\\\\\u_1=4x\\du_1=4dx\\dx=\frac{1}{4}du_1\\\\\u_2=2x\\du_2=2dx\\dx=\frac{1}{2}du_2\\\\\\=\frac{1}{8}\int e^{u_1}du_1 -\frac{3}{4}\int e^{u_2}du_2 + \int\limits^{a}_{0}e^{x}dx \\\\\\\)

\(\\=\frac{1}{8}e^{u_1}\Big| -\frac{3}{4}e^{u_2}\Big| + e^{x}\Big|_0^a \\\\\\=\frac{1}{8}e^{4x}\Big|_{0}^a -\frac{3}{4}e^{2x}\Big|_{0}^a + e^{x}\Big|_0^a \\\\\\=\frac{1}{8}e^{4x} -\frac{3}{4}e^{2x} + e^{x}\Big|_0^a \\\\\\=\frac{1}{8}e^{4a} -\frac{3}{4}e^{2a} + e^{a}-\frac{1}{8} +\frac{3}{4} -1\\\\\\=\frac{1}{8}e^{4a} -\frac{3}{4}e^{2a} + e^{a}-\frac{3}{8}\\\\\\\)

Sorry if that took a while to finish. I am in AP Calculus BC and that was my first time evaluating a triple integral. You will see some integrals and evaluation signs with blank upper and lower boundaries. I just had my equation in terms of u and didn't want to get any variables confused. Hope this helps you. If you have any questions let me know. Have a nice night.

he BLS employer cost survey uses a sample to establish the average wage of receptionists. Based on a large number of observations, the distribution of receptionist wages is normally distributed with a mean $10.38/hour and a standard deviation of $2.05. What is the probability that the wages for a sample of 20 receptionists exceeds $11/hour

Answers

If the BLS employer cost survey uses a sample to establish the average wage of receptionists and the distribution of receptionist wages is normally distributed with a mean of $10.38/hour and a standard deviation of $2.05, then the probability that the wages for a sample of 20 receptionists exceed $11/hour is 38.16%

To find the probability, follow these steps:

We can use the z-score formula:

z = (x - μ) / σ

where:
- x is the value we want to find the probability for (in this case, $11/hour)
- μ is the mean of the distribution ($10.38/hour)
- σ is the standard deviation of the distribution ($2.05)Let's calculate the z-score:

z = (11 - 10.38) / 2.05
 = 0.3024Now, we need to find the probability of getting a z-score greater than 0.3024. We can use a standard normal distribution table or a calculator to find this probability. Assuming a two-tailed test, the probability can be calculated as:

P(Z > 0.3024) = 1 - P(Z < 0.3024)

Using a standard normal distribution table or a calculator, we can find that P(Z < 0.3024) is approximately 0.6184. Therefore, the probability that the wages for a sample of 20 receptionists exceed $11/hour is:

P(Z > 0.3024) = 1 - 0.6184
            = 0.3816

So, the probability is approximately 0.3816 or 38.16%.

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If m angle 5 = 42 degrees and m angle 1 = 117 degrees, find m angle CDF

If m angle 5 = 42 degrees and m angle 1 = 117 degrees, find m angle CDF

Answers

Answer:

its 159

Step-by-step explanation:

The angle CDF is 159 degrees

Using this formula to determine angle CDF

Angle CDF=m angle 1+ m angle 5+

Where:

m angle 1=117 degrees

m angle 5=42 degrees

Let plug in the formula

Angle CDF=117 degrees+42 degrees

Angle CDF=159 degrees

Inconclusion the angle CDF is 159 degrees

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jamie is 3 years less than three times Andys age. In five years the sum of their ages will be 59.How old are they now​

Answers

Answer:

Andy : 13 years old and

Jamie: 36 years old

Step-by-step explanation:

Andy = x

Jamie = 3x - 3

In 5 years:

(X+5)+(3x-3+5) = 59

4x + 7 = 59

4x = 59 - 7

x = 52/4

x = 13

i dont even know what to put

i dont even know what to put

Answers

Answer:

first one (2*2*2*3*3)

Step-by-step explanation:

2*2*2*3*3=72

1 Which is an accurate conclusion regarding the system of equations below? y = x-1 y = 3 - 2 3 - 2 x O A. There is no solution, since both equations have the same slope. There We infinitely many solutions, since the same line represents both , equations. O B. O C. The only solution is the ordered pair (1, 3). OD. The only solution is the ordered pair (3, 1).​

Answers

Answer:the first one

Step-by-step explanation:

The purchased cost of a 5-m3 stainless steel tank in 1995 was $10,900. The 2-m-diameter tank is cylindrical with a flat top and bottom. If the entire outer surface of the tank is to be covered with 0.05-m-thickness of magnesia block, estimate the current total cost for the installed and insulated tank. The 1995 cost for the 0.05-m-thick magnesia block was $40 per square meter while the labor for installing the insulation was $95 per square meter.

Answers

The estimated current total cost for the installed and insulated tank is $12,065.73.

The first step is to calculate the surface area of the tank. The surface area of a cylinder is calculated as follows:

surface_area = 2 * pi * r * h + 2 * pi * r^2

where:

r is the radius of the cylinder

h is the height of the cylinder

In this case, the radius of the cylinder is 1 meter (half of the diameter) and the height of the cylinder is 1 meter. So the surface area of the tank is:

surface_area = 2 * pi * 1 * 1 + 2 * pi * 1^2 = 6.283185307179586

The insulation will add a thickness of 0.05 meters to the surface area of the tank, so the total surface area of the insulated tank is:

surface_area = 6.283185307179586 + 2 * pi * 1 * 0.05 = 6.806032934459293

The cost of the insulation is $40 per square meter and the cost of labor is $95 per square meter, so the total cost of the insulation and labor is:

cost = 6.806032934459293 * (40 + 95) = $1,165.73

The original cost of the tank was $10,900, so the total cost of the insulated tank is:

cost = 10900 + 1165.73 = $12,065.73

Therefore, the estimated current total cost for the installed and insulated tank is $12,065.73.

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Ill mark you brainliest please help !

Ill mark you brainliest please help !

Answers

Answer: (-2, 1)

Step-by-step explanation:

Draiman corporation has bonds on the market with 10.5 years to maturity, a ytm of 7.1 percent, a par value of $1,000, and a current price of $1,051. the bonds make semiannual payments. what must the coupon rate be on these bonds?

Answers

The coupon rate is 7.80% if Draiman corporation has bonds on the market with 10.5 years to maturity, a YTM of 7.1 percent, a par value of $1,000

What is the percentage?

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

We have:

Draiman corporation has bonds on the market with 10.5 years to maturity, a ytm of 7.1 percent.

We know,

\(\rm Bonds \ Price = Coupon \ payment[ (1 - \dfrac{1}{(1+r)^n} ] + \dfrac{Par \ value }{ (1 + r)^n}\)

r = 7.1%/2

Since the payments are semi-annual, hence divided by 2

r = 3.55% or 0.0355

n = 10.5x2

Since the payments are semi-annual, hence multiplied by 2

n = 21

Now plug all the values in the formula to get the value of the coupon rate:

$ 1,051 = Coupon payment x [ [ (1 - 1 / (1 + 0.0355)21 ] / 0.0355 ] + $ 1,000 / 1.035521

Coupon payment = ($ 1,051 - $ 480.6709018) / 14.62898868

Coupon payment = $ 38.98

Coupon rate:

= (Coupon payment / Face value) x 2 (Multiplied by 2 since the payments were semi annual)

= ($38.98/$1,000) x 2

= 7.80%

Thus, the coupon rate is 7.80% if Draiman corporation has bonds on the market with 10.5 years to maturity, a YTM of 7.1 percent, a par value of $1,000

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Of the following growth rates, which would be considered the smallest growth rate, thus the quickest algorithm that could execute? O log n n On log n On?

Answers

On(log n) is the smallest growth rate and the quickest algorithm that could execute.

An algorithm is a step-by-step process or set of procedures for carrying out a specific task. In computing, an algorithm can be thought of as a sequence of computational steps required to accomplish a given task. In essence, algorithms are the instructions that tell computers what to do, much like a recipe tells a chef what ingredients to use and what steps to follow.

The performance of an algorithm is usually measured in terms of its growth rate.

The growth rate of an algorithm refers to how the time or space requirement of the algorithm changes as the input size increases. An algorithm's growth rate is usually measured in terms of Big O notation.

The Big O notation is a mathematical notation used to describe the upper-bound of an algorithm's complexity. It is a way to classify algorithms according to their efficiency and scalability.

O(log n) - This is considered the quickest algorithm that could execute as it has the smallest growth rate.

On(log n) - has a larger growth rate than O(log n), thus it would take longer to execute as the input size increases.

n log n - has a larger growth rate than On(log n), making it less efficient in terms of time or space required to complete a task.

Therefore, On(log n) is the smallest growth rate and the quickest algorithm that could execute.

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Andy is buying a car.
He negotiated a 7% decrease on a £6 500 car.
He will pay the full balance in 12 equal monthly payments.
Calculate the amount paid each month.

Answers

Answer:

£503.75

Step-by-step explanation:

Andy is buying a car.

Step 1

We calculate the decrease

He negotiated a 7% decrease on a £6 500 car.

Decrease = 7% × £6500

= $455

Step 2

We calculate the new price of the car.

= Old price - Decrease

= £6500 - £455

= £6045

Step 3

We calculate the amount he pays every month.

We are told that:

He will pay the full balance in 12 equal monthly payments.

Andy's monthly payments =

New price/12 months

= £6045/12

= £503.75

Therefore, the amount he would be paying each new month = £503.75

Which of the following series can be used to determine the convergence of the series summation from k equals 0 to infinity of a fraction with the square root of quantity k to the eighth power minus k cubed plus 4 times k minus 7 end quantity as the numerator and 5 times the quantity 3 minus 6 times k plus 3 times k to the sixth power end quantity squared as the denominator question mark

Which of the following series can be used to determine the convergence of the series summation from k

Answers

The value we can use in the series is \($\sum_{k=0}^\infty 1/k^8\).

To check the convergence we consider two series as

Series 1: \($\sum_{k=0}^\infty \frac{k^8}{5(3-6k+3k^6)^2}$\)

Series 2: \($\sum_{k=0}^\infty \frac{k^8 + k^3 + 4k}{5(3-6k+3k^6)^2}$\)

We employ the p-test, which indicates that the series converges if the ratio of succeeding entries in a series approaches a number less than 1. The ratio of successive terms for Series 1 approaches 1, indicating that Series 1 diverges.

We can infer that Series 2 also diverges because Series 1, which is smaller than Series 2, likewise diverges.

Thus, the given series also diverges.

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the throw of the dice or the drawing of a card is known as ____ behavior.

Answers

The throw of the dice or the drawing of a card is known as random behavior.

Random behavior refers to events that occur by chance, without any predictability or pattern. These events cannot be influenced or controlled, and their outcomes are determined by the laws of probability. In games such as dice and card games, the outcomes are determined by random variables, such as the position of the dice or the shuffle of the deck.

Random behavior can also occur in other contexts, such as weather patterns or the stock market, where events are subject to unpredictable fluctuations. Understanding random behavior is important in many fields, including mathematics, statistics, and economics, as it can help us make informed decisions based on the probability of different outcomes.

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Money of Rp. 24,000.00 can buy 3 kg of apples. If Anto buys apples with money
Rp. 40,000.00, how many kg of apples did he get?

Answers

Answer:

5 Kg of apples

Step-by-step explanation:

cost of apples per kg = 24000.00/3

=8000.00

amount of apples bought = 40000.00/8000.00

=5 Kg

He got 5kg of apples with Rp.40,000.00

Find the slope-intercept equation of the line containing (1.-4) and having slope m = 3​

Answers

Answer:

y=3x-7

Step-by-step explanation:

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