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Answer:

1.05 x 103s

Explanation:

The answer to the question is 1.05 x 103s

The time elapsed between the first splash and the second splash is approximately 0.69 seconds.

To calculate this, we consider the motion of two rocks thrown simultaneously from a bridge. Heather throws a rock straight down with a speed of 14 m/s, while Jerry throws a rock straight up with the same speed.

We use the equation for displacement in uniformly accelerated motion: s = ut + (1/2)at^2.

For Heather's rock, which is thrown downwards, the initial velocity (u) is positive and the acceleration (a) due to gravity is negative (-9.8 m/s^2). The displacement (s) is the height of the bridge (46 m).

Solving the equation, we find two possible values for the time (t): t ≈ -4.91 s and t ≈ 1.91 s.

Since time cannot be negative in this context, we discard the negative value and consider t ≈ 1.91 s as the time it takes for Heather's rock to hit the water.

For Jerry's rock, thrown upwards, we use the same equation with the same initial velocity and acceleration. The displacement is also the height of the bridge, but negative.

Solving the equation, we find t ≈ -5.68 s and t ≈ 1.22 s. Again, we discard the negative value and consider t ≈ 1.22 s as the time it takes for Jerry's rock to reach its maximum height before falling back down.

To find the time difference between the first and second splash, we subtract t ≈ 1.91 s (Heather's rock) from t ≈ 1.22 s (Jerry's rock). This gives us a time difference of approximately 0.69 seconds.

Therefore, the time elapsed between the first splash and the second splash is approximately 0.69 seconds.

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Given that the initial moment of inertia is

The final moment of inertia is

Let the initial angular velocity be

Let the final angular velocity be

The ratio of final and initial kinetic energy is

The examples of ohmic conductors​ are :

Silver(Ag), copper(Cu), aluminium(Al) etc.

Ohmic conductors means which conductors strictly obey the Ohm's law, are known as Ohmic conductors.  

Resistance= \(\frac{Voltage}{Current}\)

In other words there is a linear relationship between voltage and current for all values. That means all the ohmic conductor materials shows a linear character in the V-I characteristic graph.

So, the examples of ohmic conductors are:

Silver(Ag), copper(Cu), aluminium(Al) etc.

All the conductors we mentions here, they all show a linear line in the V-I characteristic graph.

From the above discussion we can conclude that, Silver(Ag), copper(Cu), aluminium(Al) etc. these are the ohmic conductors.

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how much pressure is created when a force of 55N is applied over an area of 8m²

We have been asked to determine the pressure exerted when given magnitude of force acting on given area.

\(☄\bf \qquad \mathcal{Pressure} = \mathcal{\dfrac{Force}{Area}}\)

Put all given value we obtain

\(\qquad \sf \longrightarrow \:Pressure \: = \dfrac{55}{8} \\ \\ \\ \qquad \sf \longrightarrow \:Pressure \: = \cancel\dfrac{55}{8} \\ \\ \\ \qquad \sf \longrightarrow \:Pressure \: = 6.875 \: Pa.\)

Therefore,

Answer:

Any food made from wheat, rice, oats, cornmeal, barley, or another cereal grain is a grain product. Anything else is not

Explanation:

Answer:

If acceleration points in the same direction as the velocity, the object will be speeding up. And if the acceleration points in the opposite direction of the velocity, the object will be slowing down.

Given that,

The acceleration of gravity is -9.8 m/s²

Initial velocity, u = 39.2 m/s

Time, t = 2 s

To find,

The final velocity of the shot.

Solution,

Let v is the final velocity of sling shot. Using first equation of motion to find it.

v = u +at

Here, a = -g

v = u-gt

v = (39.2)-(9.8)(2)

v = 19.6 m/s

So, its velocity after 2 seconds is 19.6 m/s.

A rope pulls a Tesla out of mud. The guy pulls a force F⊥ of 300N, and theta = 4.2°. The tension force T is 298.44__ Newton.

The problem describes a Tesla that is stuck in the mud and needs to be pulled out using a rope. the guy pulls a force F⊥ of 300N and that the angle between the rope and the horizontal plane is θ = 4.2°. The goal is to find the tension force T exerted by the rope.To solve for T, we'll need to use trigonometry. We can break the force vector into its horizontal and vertical components as follows:

Fx = F⊥ cosθ and Fy = F⊥ sinθ.

Since the rope is pulling the Tesla horizontally, the horizontal component of the force will be the tension force T. So we have:

T = Fx = F⊥ cosθ = (300 N) cos(4.2°) ≈ 298.44 N

Taking the cosine of the angle is necessary since it's the adjacent side that we're interested in, which is the horizontal component of the force. Therefore, the tension force exerted by the rope is approximately 298.44 N.

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Answer:

EMF = 1.1929 V

Explanation:

In this case we need to use the following expression:

EMF = B *ΔA / t   (1)

Where:

B: Magnetic field

ΔA: Difference of area of the balloon

t: time

To get the area, we have the innitial diameter of the balloon, and the expanded diameter when the balloon is blown up, so, assuming the circunference of the balloon, the area can be determined with:

A = π r²   (2)

So, let's calculate the Area of the balloon before and after the blown. Remember to use the units in meter (I just divided the diameter by 2 to get the ratio, and then divide by 100 to convert the units of cm to m)

A₁ = π * (0.105)² = 0.0346 m²

A₂ = π * (0.155)² = 0.0755 m²

Now that we have both areas, let's calculate ΔA:

ΔA = A₂ - A₁

ΔA = 0.0755 - 0.0346 = 0.0409 m²

Finally, we can determine the value of the EMF, using (1):

EMF = 1.4 * 0.0409 / 0.048

Hope this helps

If you jump on the scale from a height of 1.9 m, the scale will read 7160 N at its peak.

When you jump on the scale, your weight and the force of your impact are both applied to the spring inside the scale. At its peak, the scale will read the sum of these two forces.

To calculate the force of your impact, we can use the principle of conservation of energy. When you jump from a height of 1.9 m, you convert potential energy into kinetic energy, given by:

mgh = (1/2)mv^2

where;

Solving for v, we get:

v = √(2gh)

Substituting the values, we get:

v = √(2 x 9.81 m/s^2 x 1.9 m) = 6.46 m/s

Now, the force of your impact on the scale is given by:

F = ma

where;

Assuming that the duration of the impact is very short, we can use the impulse-momentum theorem, which states that the change in momentum of an object is equal to the impulse applied to it. The impulse is given by:

J = Ft

where;

The change in momentum of your body is:

p = mv - 0

where;

Since the momentum is conserved, we have:

mv = Ft

Solving for F, we get:

F = mv/t

Substituting the values, we get:

F = (m x 6.46 m/s) / (0.001 s) = 6460 N

Therefore, the scale will read:

700 N + 6460 N = 7160 N

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Answer:

10778292789403987593790

Explanation:

I am a Cow'

Mesopotamia, with its key features of specialization, government, cities, religion, trade, and written records, advanced human society by fostering economic growth, establishing governance structures, creating urban centers, facilitating cultural exchange, promoting trade networks, and revolutionizing communication and knowledge preservation through writing.

Mesopotamia, often referred to as the "cradle of civilization," possessed several key features that contributed to its advancement and influenced human society as a whole. These features include specialization, government, cities, religion, trade, and written records. Let's explore each of these key features and their significance.

Specialization: Mesopotamian society developed specialization, where individuals began to focus on specific occupations and trades. This led to the emergence of skilled craftsmen, farmers, priests, scribes, and merchants. Specialization allowed for the production of surplus goods, leading to economic growth and the establishment of a more complex society.

Government: Mesopotamia witnessed the development of early forms of government. Initially, city-states were governed by religious leaders known as priest-kings. Over time, as society grew more complex, secular leaders, such as kings, emerged to rule the city-states. These early forms of governance laid the foundation for later systems of government and administration.

Cities: Mesopotamia was characterized by the rise of urban centers. These cities served as political, economic, and cultural hubs. They were densely populated, with advanced infrastructure, including defensive walls, temples, markets, and residential areas. The cities of Mesopotamia, such as Ur, Uruk, and Babylon, provided the framework for the organization and development of early urban societies.

Religion: Religion played a central role in Mesopotamian society. The people of Mesopotamia believed in a pantheon of gods and goddesses and practiced polytheism. Temples were constructed as sacred spaces to honor and worship deities. Priests held significant influence, serving as intermediaries between the people and the divine. Religious beliefs and rituals provided a sense of identity, social cohesion, and moral guidance to the Mesopotamian community.

Trade: Mesopotamia's strategic location between major rivers, the Tigris and Euphrates, facilitated extensive trade networks. The abundance of resources, such as fertile land for agriculture, allowed for surplus production. This surplus was exchanged with neighboring regions, fostering trade and the establishment of commercial relationships. The exchange of goods and ideas through trade networks promoted cultural diffusion and contributed to the overall prosperity and interconnectedness of Mesopotamia.

Written Records: Mesopotamia is credited with the invention of writing, making it one of the earliest literate civilizations. Scribes used wedge-shaped marks known as cuneiform to record important information on clay tablets. The development of writing enabled the recording of laws, contracts, administrative documents, literature, and historical accounts. Written records not only facilitated communication and administration but also served as a means of preserving knowledge and passing it down through generations.

Collectively, these key features of Mesopotamia played a pivotal role in advancing human society as a whole. Specialization allowed for the efficient allocation of resources and the growth of economies. The establishment of early forms of government provided organization and stability to communities. Urbanization transformed social structures and fostered cultural and intellectual exchange. Religion served as a unifying force and provided a moral framework. Trade networks expanded horizons and facilitated the exchange of goods and ideas. Finally, the invention of writing revolutionized communication, education, and the preservation of knowledge.

Therefore, Mesopotamia's legacy as a cradle of civilization lies in its ability to establish foundations for complex societies, laying the groundwork for subsequent advancements in various aspects of human life.

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The final total energy of the system is 45J + 2J = 47J. So, the correct option is (c) 47J.

The total energy at the beginning equals the total energy at the conclusion, according to the rule of conservation of energy. The energy present in a system that determines its temperature is referred to as thermal energy.

Thermal energy flows as heat. Mechanical energy, also known as kinetic energy or potential energy, is the energy that an object possesses when it is in motion or the energy that an object stores due to its location.

Therefore, the final total energy of the system is 45J + 2J = 47J.

So, the correct option is (c) 47J.

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Answer:

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

PE = 10 × 9.8 × 20

We have the final answer as

Hope this helps you

The tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

To calculate the total displacement of the tank division, we need to find the vector sum of the two legs of their journey.

We can see that the tank division travelled 30 miles to the west (W30) and then 70 miles to the north (N70), so their total displacement is the vector sum of these two legs.

To add vectors, we need to break them down into their horizontal and vertical components.

For the first leg, the tank division travelled 30 miles to the west, so its horizontal component is -30 (since it's to the left of the base) and its vertical component is 0 (since it didn't travel up or down).

For the second leg, the tank division travelled 70 miles to the north, so its horizontal component is 0 (since it didn't travel left or right) and its vertical component is 70 (since it travelled directly north).

Now we can add these components to get the total displacement:

Horizontal component = -30 + 0 = -30

Vertical component = 0 + 70 = 70

So the total displacement is a vector with a horizontal component of -30 and a vertical component of 70.

We can use the Pythagorean theorem to find the magnitude of this vector:

|displacement| = √((-30)² + 70²) ≈ 75.9 miles

And we can use trigonometry to find the direction of this vector:

\(\theta = tan^{-1}\dfrac{70} { -30}\)

θ ≈ -67.4°

So the tank division's total displacement from the base is approximately 75.9 miles at a bearing of W67.4S.

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Answer:i

Explanation:∩

Plate Boundaries on Earth assignment involves identifying and illustrating different types of plate movements at the Earth's contact points.

Here are the steps to be followed:

Step 1: Understanding the Assignment Requirements

Read through the assignment instructions carefully to ensure a clear understanding of the tasks and expectations.

Step 2: Research

Start by conducting research on plate boundaries, their types, movements, and associated geological processes. Use reliable and valid resources such as scientific journals, textbooks, and reputable websites. Take notes on the different plate movements, their characteristics, and examples of each.

Step 3: Worksheet Setup

Create a table or chart with six rows corresponding to the six categories specified in the assignment instructions: Plate Boundary (Movement), Diagram, Lithosphere (Created or Destroyed), Geologic Process, Real World Example, and References.

Step 4: Fill in Row 1 - Plate Boundary (Movement)

In the first row, list the three types of plate boundaries: convergent, divergent, and transform. Next to each type, write the correct description in parentheses: sliding, separating, or colliding.

Step 5: Fill in Row 2 - Diagram

In the second row, draw a diagram or illustration for each type of plate movement. Use arrows to indicate the direction of movement and whether the plates are colliding, separating, or sliding past each other.

Step 6: Fill in Row 3 - Lithosphere (Created or Destroyed)

In the third row, identify whether the Earth's crust is created or destroyed at each type of plate boundary. Note the corresponding effects of plate movement on the lithosphere.

Step 7: Fill in Row 4 - Geologic Process

In the fourth row, provide at least one example of a geologic process or event that occurs as a result of plate movement at each type of boundary. This could include processes like subduction, seafloor spreading, or earthquakes.

Step 8: Fill in Row 5 - Real World Example

In the fifth row, give at least one real-world example of a location where each type of plate movement is demonstrated along a plate boundary. Include the name of the location and its corresponding plate boundary type.

Step 9: Fill in Row 6 - References

In the final row, provide the references for your research in APA format. Include the sources you used to gather information on plate boundaries, plate movements, and related geological processes.

Step 10: Review and Proofread

Review the completed assignment, ensuring that all information is accurate and properly cited. Proofread for any grammatical or spelling errors.

Note: The specific format and layout of the worksheet may vary based on your preference or instructor's instructions. Make sure to follow any specific formatting guidelines provided by your instructor.

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Answer: Magnitude of the electric field at a point which is 2.0 mm from the symmetry axis is 18.08 N/C.

Explanation:

Given: Density = 80 \(nC/m^{3}\) (1 n = \(10^{-9}\) m) = \(80 \times 10^{-9} C/m^{2}\)

\(r_{1}\) = 1.0 mm (1 mm = 0.001 m) = 0.001 m

\(r_{2}\) = 3.0 mm = 0.003 m

r = 2.0 mm = 0.002 m (from the symmetry axis)

The charge per unit length of the cylinder is calculated as follows.

\(\lambda = \rho \pi (r^{2}_{2} - r^{2}_{1})\)

Substitute the values into above formula as follows.

\(\lambda = \rho \pi (r^{2}_{2} - r^{2}_{1})\\= 80 \times 10^{-9} \times 3.14 \times [(0.003)^{2} - (0.001)^{2}]\\= 2.01 \times 10^{-12} C/m\)

Therefore, electric field at r = 0.002 m from the symmetry axis is calculated as follows.

\(E = \frac{\lambda}{2 \pi r \epsilon_{o}}\)

Substitute the values into above formula as follows.

\(E = \frac{\lambda}{2 \pi r \epsilon_{o}}\\= \frac{2.01 \times 10^{-12} C/m}{2 \times 3.14 \times 0.002 m \times 8.85 \times 10^{-12}}\\= 18.08 N/C\)

Thus, we can conclude that magnitude of the electric field at a point which is 2.0 mm from the symmetry axis is 18.08 N/C.

Answer: 4

Explanation: because 0s aren’t significant and after the decimal point, there was to be a value greater than 0 than the rest are sig figs.

Answer:

v = 0.5 [m/s]

Explanation:

In order to determine the speed in such a time interval, we must calculate the slope between the last two positions.

The slope of a line is determined by the following mathematical expression.

P₂ = point 2 = (12,12) = (x₂,y₂)

P₁ = Point 1 = (6,9) = (x₁,y₁)

In this specific case, we must see that in the x-axis we have time, and on the y-axis, we have the space axis.

Now using the slope:

\(m =\frac{y_{2} -y_{1} }{x_{2} -x_{1} } \\m = \frac{12-9}{12-6}\\m = 0.5\)

This slope is equal to the speed (velocity)

v = 0.5 [m/s]

Answer: In a pulley, the ideal mechanical advantage is equal to the number of rope segments pulling up on the object. The more rope segments that are supporting to do the lifting work, the less pressure that is needed for the job.

Explanation:

Answer:

In 1820, Hans Christian Oersted(the founder) developed the oersted experiment to display a relationship between magnetism and electricity.

Explanation:

Answer:

A

Explanation:

Answer:

D. Conduction

Explanation:

Convection heat transfer occurs in fluids, while conduction heat transfer occurs in solids.

1) The temperature at the beginning  is 288 K

b)After we doubled the pressure we have, the temperature at 576 K

The ideal gas equation is the key that is going to help with the temperature of the gas as we can see the parameters in the question clearly shown as follows;

Pressure = 200 kPa or 1.97 atm

Volume =  3000 cm3  or 3 L

Temperature = ?

Moles of the gas = mass/molar mass = 7 g/28 g/mol = 0.25 moles

Thus;

PV = nRT

T = PV/nR

T =  1.97 * 3/0.25 * 0.082

T = 5.91/0.0205

T = 288 K

After the pressure is doubled;

P1/T1 = P2/T2

P1T2 = P2T1

T2 = 2(1.97) * 288/1.97

T2 = 576 K

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No. The potential of a non-uniform charged sphere cannot be the same as that of a point charge.

The potential at any point in space is determined by the distribution of charge within the system, and a non-uniform charged sphere has a different charge distribution than a point charge.

A point charge has all of its charges concentrated at a single point, while a non-uniform charged sphere has charge distributed throughout its volume.

As a result, the electric field and potential will be different for these two systems, even if they have the same total charge. Therefore, the potential of a non-uniform charged sphere cannot be the same as that of a point charge.

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Answer:

Fault

Explanation:

it only carries a current if there is a fault.

The change in the displacement is 70 m

Recall that the displacement is obtained as the product of the velocity and time. We have the velocity at two intervals.

At v1, the displacement can be obtained from;

x1 = 0.5 * 20 = 10 m

At v2, the displacement can be obtained as;

x2 = 2 * 40 = 80 m

Now

Δx = 80 m - 10 m = 70m

Thus the change in the displacement is 70 m

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