What will be the velocity of a train if it covers the distance of 30m in 3 s?

the force between the two wires if they are separated by 2.50 cm is 0.525 N.

Given that force F between two parallel wires carrying electric currents is inversely proportional to the distance d between the wires and that a force of 0.750 N exists between wires that are 1.75 cm apart and that we are supposed to find the force between them if they are separated by 2.50 cm.

Let the initial force be F₁ and the initial distance be d₁.

Therefore, we can write the relationship between force and distance as;

F₁d₁ = F₂d₂

Where

;F₁ = 0.750 N (initial force)

d₁ = 1.75 cm (initial distance)

F₂ = ? (force at new distance)

d₂ = 2.50 cm (new distance)

Let us find F₂;F₁d₁ = F₂d₂F₂ = F₁d₁/d₂

Now substitute the values we know;

F₂ = (0.750 N x 1.75 cm) / 2.50 cmF₂ = 0.525 N

Therefore, the force between the two wires if they are separated by 2.50 cm is 0.525 N.

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Answer:

How much resistance a material has depends on several factors: the type of material, its width, its length, and its temperature. All materials have some resistance, but certain materials resist the flow of electric current more or less than other materials do.

The amount of air resistance an object experience depends on its speed, cross-sectional area, shape, and density of the air.

Explanation:

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Answer:

Explanation:

This is a direct application of Newton's 2nd Law:

F = ma, where F is the force applied to an object, m is the mass of the object, and a is the acceleration of the object when this force is applied. Note: this is NOT the same as the acceleration due to gravity which is constant at -9.8 m/s/s or -32 ft/s/s. Filling in:

6.0 = m(12.0) so

m = .5 kg

Answer:

The answer to this question would be the first photo: the mountains.

Explanation:

I took the test on edmentum and got the answer right.

First image is most likely to have been created by uplifting and folding of Earth’s crust during a continental-continental convergence. So, the correct option is (A).

Continent-continent convergence is defined as the formation between two continental plates. When these plates converge, oceanic sediments get buried and ejected between the plates and these squeezed sediments will appear as fold mountains along the plate edges.

There are three types of convergent boundaries which are recognized as

1. Continent-Continent

2. Ocean-Continent

3. Ocean-Ocean

Continent-continent convergence formed by two continents colliding. These were at one time separated by oceanic crust which was progressively subducted by one of the continents.

Thus, first image is most likely to have been created by uplifting and folding of Earth’s crust during a continental-continental convergence. So, the correct option is (A).

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When 6.44 g of sulfur reacts with excess O2 according to the given equation 2 S + 3O2 → 2SO3 ∆H = -791.4 kJ, 252.7 kJ of heat will be released.

To find the amount of heat released in the given reaction, we need to find the number of moles of sulfur and then use the balanced chemical equation to find the amount of heat released.

Moles of sulfur = Mass of sulfur/Molar mass of sulfur

= 6.44 g/32.06 g/mol = 0.201 mol

From the balanced chemical equation, it is clear that 2 moles of sulfur reacts with 3 moles of O2 to produce 2 moles of SO3. In this case, we have enough O2. So, sulfur is the limiting reactant. Number of moles of sulfur = 0.201 mol, Number of moles of SO3 produced = 2 × 0.201 mol/2 = 0.201 mol.

According to the balanced chemical equation, 2 moles of SO3 is produced with the release of 791.4 kJ of heat.So, for 0.201 mol of SO3 produced, the amount of heat released = 791.4 kJ/2 mol × 0.201 mol = 79.14 kJ

Thus, the amount of heat released when 6.44 g of sulfur reacts with excess O2 is 79.14 kJ (approx).

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The amount of heat released when 6.44 g of sulfur reacts with excess O₂ is 79.14 kJ (approx.).

When 6.44 g of sulfur reacts with excess O₂ according to the given equation 2 S + 3O₂ → 2SO₃ ∆H = -791.4 kJ, 252.7 kJ of heat will be released.

To find the amount of heat released in the given reaction, we need to find the number of moles of sulfur and then use the balanced chemical equation to find the amount of heat released.

Moles of sulfur = Mass of sulfur/Molar mass of sulfur

= 6.44 g/32.06 g/mol = 0.201 mol

From the balanced chemical equation, it is clear that 2 moles of sulfur reacts with 3 moles of O₂ to produce 2 moles of SO₃. In this case, we have enough O₂. So, sulfur is the limiting reactant. Number of moles of sulfur = 0.201 mol, Number of moles of SO₃ produced = 2 × 0.201 mol/2 = 0.201 mol.

According to the balanced chemical equation, 2 moles of SO₃ is produced with the release of 791.4 kJ of heat.So, for 0.201 mol of SO₃ produced, the amount of heat released = 791.4 kJ/2 mol × 0.201 mol = 79.14 kJ

Thus, the amount of heat released when 6.44 g of sulfur reacts with excess O₂ is 79.14 kJ (approx).

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The time needed for a wave to make one complete cycle is called the wave's period. The period of a wave is defined as the time it takes for a wave to repeat its pattern or for a single complete cycle to occur. It is typically represented by the symbol T and is measured in units of time, such as seconds.

The period of a wave is inversely related to its frequency. The frequency of a wave, represented by the symbol f, is the number of complete cycles or oscillations that occur in one second. It is measured in units of hertz (Hz), which is equal to one cycle per second. The relationship between period and frequency is given by the equation T = 1/f.

While frequency represents the number of cycles per unit time, the period specifically refers to the time it takes to complete one cycle. Therefore, the correct answer is b. period.

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Answer:

The answer is B The forces pointing up and down are balanced

Explanation:

The speed of the projectile when it strikes the ground below is approximately 620.6 m/s.

We can use the kinematic equations of motion to solve this problem.

First, we can find the time it takes for the projectile to hit the ground using the vertical motion equation:

y = vi*t + (1/2)at²

where y is the vertical displacement (in this case, the initial height of the cliff), vi is the initial vertical velocity (in this case, zero), a is the acceleration due to gravity (-9.8 m/s^2), and t is time.

Plugging in the values, we get:

265 m = 0t + (1/2)(-9.8 m/s²)*t²

Solving for t, we get:

t = √((2*265 m) / (9.8 m/s²)) = 8.25 s

Next, we can find the horizontal displacement of the projectile using the horizontal motion equation:

x = v*t

where x is the horizontal displacement, v is the initial horizontal velocity, and t is time.

Since the initial velocity is at a 45-degree angle, we can break it down into its horizontal and vertical components:

v_initial_x = v_initial*cos(45 degrees) = 350 m/s * cos(45 degrees) = 247.5 m/s

v_initial_y = v_initial*sin(45 degrees) = 350 m/s * sin(45 degrees) = 247.5 m/s

The horizontal displacement can now be calculated as:

x = v_initial_x * t = 247.5 m/s * 8.25 s = 2041.9 m

Finally, we can find the speed of the projectile when it hits the ground using the total velocity equation:

v_final² = v_initial_x² + v_initial_y² + 2ay

where v_final is the final velocity, v_initial_x and v_initial_y are the horizontal and vertical components of the initial velocity, and y is the vertical displacement.

Plugging in the values, we get:

v_final² = (247.5 m/s)² + (350 m/s)² + 2*(-9.8 m/s²)*(265 m)

Solving for v_final, we get:

v_final = √((247.5 m/s)² + (350 m/s)² + 2*(-9.8 m/s²)*(265 m)) = 620.6 m/s

Therefore, the speed of the projectile when it strikes the ground below is approximately 620.6 m/s.

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In general, planets produce warmness in keeping with their size. Radioactive atoms decay withinside the indoors, and conduction and convection delivery this warmness from the indoors to the surface.

Bigger planets have greater gravity, and the stress because of gravity enables to create a molten indoors which can power geological activity. What procedure keeps to warmness the terrestrial planets

Radioactive decay is maximum essential warmness supply today. Convection transports warmness as warm cloth rises and funky cloth falls. Conduction transfers warmness from warm cloth to chill cloth. Radiation sends electricity into space.

The  maximum essential procedures in heating the interiors of the terrestrial worlds are: (1) Heat deposited with the aid of using the procedure of formation; (2) warmness launched with the aid of using radioactive decay.

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Answer:

A the charge has only one path through which it can flow.

Answer:

Hope the picture will help

an infant born with a genetic defect that causes little or no brown fat to be formed will have (b) difficulty regulating his body temperature.

Brown fat is a specialized type of fat that generates heat to help regulate body temperature in newborns and infants. If an infant is born with a genetic defect that causes little or no brown fat to be formed, they will have difficulty regulating their body temperature. This can result in hypothermia or hyperthermia, depending on the environment. The other options listed in the question (difficulty absorbing nutrients from the intestine, very stretchy tendons, reduced bone mass, and difficulty breathing) are not directly related to the function of brown fat.

Brown fat, also known as brown adipose tissue, plays a crucial role in generating heat and maintaining body temperature, especially in infants. Without sufficient brown fat, the infant will struggle to regulate their body temperature, leading to the mentioned issue.

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Answer:

^ correct

Explanation:

Option A on edge 2020

the curve must be banked at an angle of approximately 19.1 degrees, angle between the string and the vertical is approximately 25.7 degrees, Therefore, the work done by the force is 391 J.

tan(θ) = v² / (r * g)

1. where θ is the angle of banking, v is the speed of the car, r is the radius of the curve, and g is the acceleration due to gravity.

Plugging in the given values, we get:

tan(θ) = (11.18 m/s)²  / (188.0 m * 9.81 m/s² )

tan(θ) = 0.346

Taking the inverse tangent of both sides, we get:

θ = tan^-1(0.346)

θ = 19.1 degrees

Therefore, the curve must be banked at an angle of approximately 19.1 degrees.

2.The force of gravity on the mass provides the centripetal force needed to keep it moving in a circle. The angle between the string and the vertical can be found using the equation:

tan(θ) = v² / (g * r)

where θ is the angle between the string and the vertical, v is the tangential speed of the mass, g is the acceleration due to gravity, and r is the length of the string.

Plugging in the given values, we get:

tan(θ) = (2.890 m/s)²  / (9.81 m/s²  * 1.390 m)

tan(θ) = 0.474

Taking the inverse tangent of both sides, we get:

θ = tan⁻¹(0.474)

θ = 25.7 degrees

Therefore, the angle between the string and the vertical is approximately 25.7 degrees.

3.The work done by the force can be found using the equation:

W = F * d * cos(θ)

where W is the work done, F is the force applied, d is the distance over which the force is applied, and θ is the angle between the force and the direction of motion.

Plugging in the given values, we get:

W = (48.7 N) * (3.33 m) * cos(25.7 degrees)

W = 391 J

Therefore, the work done by the force is 391 J.

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To find the equation of a circle using matrices, we need at least 3 data points.

The general equation for a circle is given by:

x² + y² + Cx + Dy + E = 0

There are 3 constants in the above equation, C, D, and E. Hence, we need 3 independent equations in order to get unique solution for C, D, and E.

To get 3 equations, we need minimum 3 data points.

Let the data points be: (x₁, y₁) , (x₂, y₂), and (x₃, y₃)

Substitute each data point into the general equation:

x₁² + y₁² + Cx₁ + Dy₁ + E = 0

x₂² + y₂² + Cx₂ + Dy₂ + E = 0

x₃² + y₃² + Cx₃ + Dy₃ + E = 0

The matrix form can be written as:

| x₁   y₁  1 |  | C |         | x₁² + y₁²  |

| x₁   y₁  1 |  | D | =  -   | x₂² + y₂² |

| x₁   y₁  1 |  | E |          | x₃² + y₃² |

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Metals - Conductivity and weight can be tailored, Ceramics - Good electrical and thermal insulators, Composites - The level of conductivity or resistivity can be controlled, Polymers - Poor electrical and thermal conductivity, Semiconductors - low compressive strength.

Metals: Metals are known for their good electrical and thermal conductivity. They are excellent conductors of electricity and heat, allowing for efficient transfer of these forms of energy.
Ceramics: Ceramics, on the other hand, are good electrical and thermal insulators. They possess high resistivity to the flow of electricity and heat, making them suitable for applications where insulation is required.
Composites: Composites are materials that consist of two or more different constituents, typically combining the properties of both. The conductivity and weight of composites can be tailored based on the specific composition.
Polymers: Polymers are characterized by their low conductivity, both electrical and thermal. They are poor electrical and thermal conductors.
Semiconductors: Semiconductors possess unique properties where their electrical conductivity can be controlled. They have an intermediate level of conductivity between conductors (metals) and insulators (ceramics).

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The dioptric power of the lens is 5 diopters.

To calculate the focal length of the lens, we can use the formula:

Focal length (f) = 1 / magnifying power (M)

Given that the magnifying power of the lens is 5x, we can substitute this value into the formula:

f = 1 / 5 = 0.2 units (assuming units are meters)

Therefore, the focal length of the lens is 0.2 units (meters).

To calculate the angular magnification (Mₐ) for a person whose near point is 30 cm, we can use the formula:

Mₐ = 1 + (D / F)

Where D is the least distance of distinct vision (typically taken as 25 cm) and F is the focal length of the lens.

Given that the near point is 30 cm, we substitute the values into the formula:

Mₐ = 1 + (0.3 / 0.2) = 1 + 1.5 = 2.5

Therefore, the angular magnification of the lens for a person with a near point of 30 cm is 2.5.

The dioptric power of the lens is given by the formula:

Power (P) = 1 / focal length (f)

Using the previously calculated focal length of 0.2 units, we can calculate the dioptric power:

P = 1 / 0.2 = 5 diopters

Therefore, the dioptric power of the lens is 5 diopters.

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Answer:

A

Explanation:

only is true when the objects mass is constant

Answer:

A.

Explanation:

When the mass is constant. Newton's second law will work perfectly.

Fun fact you probably won't need to know this, but the original formula that Newton derived was F=change in momentum divided by change in time. Momentum will account for a change in mass. The schooling system lies to you all the time especially in physics.

Answer:

A

Explanation:

This is to do with convection currents :)

Hope this helps!

During time interval t2, the voltage is decreasing from the maximum value to 0, as the magnetic flux linkage with the coil is reduced.

When an isolated magnetic North pole is discovered and dropped through the set-up (magnet through a coil experiment), there is a change in magnetic flux linkage within the coil. Therefore, the induced electromotive force (EMF) will cause a voltage pattern to form.The Faraday's Law of Electromagnetic Induction states that when there is a change in magnetic flux linkage within a coil, an EMF is induced in the coil.

In this scenario, the magnetic flux linkage increases as the magnetic North pole enters the coil and decreases when it exits the coil, which will result in a change in the direction of the induced EMF within the coil.The voltage pattern obtained from the experiment depends on the rate at which the magnetic North pole is dropped through the set-up and the number of turns of the coil.

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Answer:

Explanation:

Overgrazing and woodcutting are responsible for most of the desertification of rangelands, cultivation practices inducing accelerated water and wind erosion are most responsible in the rain-fed croplands, and improper water management leading to salinization is the cause of the deterioration of irrigated lands.

Explanation:

As they are in same direction, you can add them directly. And result is 12 + 8 m = 20 m North. If you use vector addition: Vectors = 12m & 8 m & angle b/w them is 0°(as both are in same direction).

As a submarine commander, if you want to avoid the effect of 300 ft (91 meters) wavelength storm waves, you would need to dive to a depth of at least 152 meters (500 feet). This is because waves lose energy as they travel through the water, and the longer the wavelength, the deeper they penetrate.

Therefore, a 300 ft wavelength storm wave would lose most of its energy at a depth of around 152 meters (500 feet).

Diving to this depth would require careful consideration of several factors, including the safety of the submarine and its crew, the ability to navigate in deep waters, and the impact on mission objectives. It is also important to note that while diving to this depth may provide some protection against storm waves, it does not completely eliminate the risk of encountering dangerous conditions at sea. As such, it is critical for submarine commanders to remain vigilant and adaptable in responding to changing weather and ocean conditions.

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∴ p = 13.2 kgms⁻¹. As a result, the ball has a momentum of 13.2 kgms1.

Given conditions ⇒

Mass of the ball = 6 kg.

Velocity = 2.2 m/s.

Using the Formula,

Momentum = mass × velocity

∴ p = mv

⇒ p = 6 × 2.2

∴ p = 13.2 kgms⁻¹.

Hence, the momentum of the ball is 13.2 kgms⁻¹.

∴ p = 13.2 kgms⁻¹. As a result, the ball has a momentum of 13.2 kgms1.

Velocity (v) is a vector quantity that measures displacement (or change in position, Δs) over the change in time (Δt), represented by the equation v = Δs/Δt.

momentum = 5x2 = 10 kg m/s.

Any object's velocity is a measurement of how swiftly it moves. Therefore, it can be described as the change in an object's position divided by time.

Both a magnitude (a value) and a direction are associated with velocity. Meters per second (meter/second) is the unit used to measure velocity.

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The Fad,x, the x-component of the force exerted by the infinite wire on segment AD of the loop is 2.39 X 10⁻⁸ N. The Fbc,x, the x-component of the force exerted by the infinite wire on segment BC of the loop is 9.56 X 10⁻⁹ N. The Fnet,y, the y-component of the net force exerted by the infinite wire on the loop is zero.

1. The Fad,x, the x-component of the force exerted by the infinite wire on segment AD of the loop =

= Fad,x = u₀i₁i₂H / (2πL)

= Fad, x = [ (4π X 10⁻⁷)(0.672)(0.256) X (0.25) ] /2π X 0.36

= Fad,x= 2.39 X 10⁻⁸ N

2. The Fbc,x, the x-component of the force exerted by the infinite wire on segment BC of the loop =

= Fbc,x = u₀i₁i₂H / (2π) X (L+W)

= Fbc,x = (4π X 10⁻⁷)(0.672)(0.256)((0.25)/2π X (0.36+0.54)

= Fbc,x = 9.56 X 10⁻⁹ N

3. The Fnet,y, the y-component of the net force exerted by the infinite wire on the loop =

= Fnet,y = 0, since force acting on perpendicular wire is zero.

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The pattern due to like and unlike charges are attached accordingly.

Charges that are similar repel each other whereas charges that are dissimilar attract. As a result, two negative charges repel each other, but a positive charge attracts a negative charge.

The attraction or repulsion is directed along the line formed by the two charges. The magnitude of the force is proportional to the square of the distance between the two charges.

Positive-positive/negative-negative charges are referred to as like charges, whereas positive-negative/negative-positive charges are referred to as unlike charges.

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When a beam of 11 keV X-rays illuminates a sample, the angles that will produce diffraction maxima of the first, second, and third order can be calculated using Bragg's law, which states that nλ = 2d sin(θ), where n is the order of diffraction, λ is the wavelength of the X-rays, d is the spacing between crystal lattice planes, and θ is the angle of incidence.

Bragg's law can be used to calculate the angles for diffraction maxima. For the first-order maximum (n = 1), we have λ = 2d sin(θ₁). Rearranging the equation, we get sin(θ₁) = λ / (2d). Substituting the values, with λ representing the wavelength of 11 keV X-rays (which can be converted to the corresponding wavelength), and the known spacing between lattice planes, we can solve for θ₁.

For the second-order maximum (n = 2), the equation becomes λ = 2d sin(θ₂). Solving for sin(θ₂) and substituting the values, we can find θ₂.

Similarly, for the third-order maximum (n = 3), we use λ = 2d sin(θ₃) to determine sin(θ₃) and find θ₃ by substituting the values.

By calculating these angles using Bragg's law, we can determine the angles that will produce diffraction maxima of the first, second, and third order for the given beam of 11 keV X-rays illuminating the sample.

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