Answer:
Cans of soup = 10
Frozen dinners = 5
Step-by-step explanation:
To determine the number of cans of soup and frozen dinners Caleb purchased, set up and solve a system of equations based on the given information.
Let x be the number of cans of soup Caleb purchased.
Let y be the number of frozen dinners Caleb purchased.
Each can of soup has 200 mg of sodium and each frozen dinner has 500 mg of sodium. The total amount of sodium in the purchased cans and frozen dinners is 4500 mg. Therefore:
\(200x + 500y = 4500\)
Caleb purchased a total of 15 cans of soup and frozen dinners. Therefore:
\(x + y = 15\)
To solve the system of equations, rearrange the second equation to isolate x:
\(\begin{aligned}x + y &= 15\\x + y -y&= 15-y\\x&=15-y\end{aligned}\)
Substitute this into the first equation to eliminate the term in x, and solve for y:
\(\begin{aligned}200(15-y) + 500y &= 4500\\3000-200y + 500y &= 4500\\3000+300y &= 4500\\3000+300y-3000 &= 4500-3000\\300y&=1500\\300y \div 300&=1500 \div 300\\y&=5\end{aligned}\)
Therefore, Caleb purchased 5 frozen dinners.
Substitute the found value of y into the rearranged second equation and solve for x:
\(\begin{aligned}x&=15-y\\x&=15-5\\x&=10\end{aligned}\)
Therefore, Caleb purchased 10 cans of soup.
Answer:
Caleb purchased 10 cans of soup and 5 frozen dinners.
Step-by-step explanation:
Caleb purchased 10 cans of soup and 5 frozen dinners.
Let no. of can of soup be x and no. of frozen dinner be y.
To solve this, we can set up the following system of equations:
\(\tt x + y = 15\)......[i]
\(\tt 200x + 500y = 4500\)......[2]
Let's find the value by elimination method:
Multiplying equation one by 200.
we get,
\(\tt 200 x+ 200 y = 15*200\)
\(\tt 200x +200 y =3000\)
Subtracting equation 2 with equation 1.
\(\tt (200x+500y)-(200x +200 y) =4500-3000\)
\(\tt \tt 300y = 1500\)
\(\tt y =\dfrac{1500}{300}\)
\(\tt y = 5\)
Substitute the value of y into the first equation to find x.**
\(\tt x + 5 = 15\)
\(\tt x = 15 - 5\)
\(\tt x = 10\)
Therefore, Caleb purchased 10 cans of soup and 5 frozen dinners.
help! offering 15 points
The formula for the centripetal force, as a function of the radius, is given as follows:
F = 896/r.
What is a proportional relationship?The equation that defines a direct proportional relationship is given as follows:
y = kx.
In which k is the constant of proportionality.
For an inverse proportional relationship, the equation is given as follows:
y = k/x.
The centripetal force varies inversely with the radius, hence the equation is given as follows:
F = k/r.
When F = 56, r = 16, hence the constant k is obtained as follows:
56 = k/16
k = 56 x 16
k = 896.
Hence the equation is given as follows:
F = 896/r.
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Hello, I am trying check my answer to see if it’s correct ?
SOLUTION
Write out the expression given;
\(6.9+5.12+0.005\)To simplify this expression, we set put the expression as given in the image below.
Therefore
\(6.9+5.12+0.005=12.025\)Answer; 12. 025
What is the volume of the prism?
Enter your answer, as a mixed number in simplest form, in the box.
Answer:
\(115 \dfrac{1}{2}\:cm^3\)
Step-by-step explanation:
The volume of a rectangular prism is the product of each of the sides of the prism
Given the sides have lengths
\(3\dfrac{1}{2}, 6 \;and\; 5 \dfrac{1}{2} cm\)
the volume would be
\(3\dfrac{1}{2} \times 6 \times 5 \dfrac{1}{2}\)
To perform this multiplication, convert mixed fractions to improper fractions first
Use the rule that mixed fraction
\(a\dfrac{b}{c}=\dfrac{a\times \:c+b}{c}\)
\(3\dfrac{1}{2}=\dfrac{3\times 2+1}{2} = \dfrac{7}{2}\)
\(5\dfrac{1}{2}=\dfrac{5\times 2+1}{2}= \dfrac{11}{2}\)
Therefore
\(3\dfrac{1}{2}\times \:6\times \:5\dfrac{1}{2}\\\\= \dfrac{7}{2}\times \:6\times \dfrac{11}{2}\\\\= \dfrac{7}{2}\times \dfrac{6}{1}\times \dfrac{11}{2} \quad(6 = \dfrac{6}{1})\)
\(=\dfrac{7\times \:6\times \:11}{2\times \:1\times \:2}\\\\= \dfrac{462}{4}\\\)
Divide numerator and denominator by 2 to get
\(\dfrac{231}{2}\\\)
Convert improper fraction \(\dfrac{231}{2}\) to mixed fraction using quotient/remainder
\(\dfrac{231}{2} \\\\\rightarrow Quotient: 115\\\\\rightarrow Remainder = 231 - 115 \times 2 = 231 - 230 = 1\)
\(\dfrac{231}{2} = 115 \dfrac{1}{2}\)
Part C: Give an example of a situation in which a percentage is greater than 100%. (2 points)
Answer:
If your weekly allowance is 5, then for Christmas week your allowance was 15, then your allowance went up by: 5 =3 - 1 = 2 x 100 =200%.
Answer:
you cannot not have a percentage greater than 100
Step-by-step explanation:
I do
not know
Almost done please help I’m begging y’all it’s almost time
I believe that it is 2x^2+1x-2
HELP ME PLEASE!!!!!!!!!!!!
1) The three main trigonometric ratios of the given triangle are:
sin B = 5/9.43
cos B = 8/9.43
tan B = 5/8
2) The measure of angle A is: ∠A = 39.6°
3) The length of side x is: x = 39.5 mm
How to find the trigonometric ratios?The six trigonometric ratios of a right angle triangle are:
sin x = opposite/hypotenuse
cos x = adjacent/hypotenuse
tan x = opposite/adjacent
cot x = 1/tan x
sec x = 1/cos x
cosec x = 1/sin x
1) The three main trigonometric ratios of the given triangle are:
sin B = 5/9.43
cos B = 8/9.43
tan B = 5/8
2) The measure of angle A is gotten from:
∠A = cos⁻¹ (47/61)
∠A = 39.6°
3) The length of side x using trigonometric ratios is:
21/x = tan 28
x = 21/tan 28
x = 39.5 mm
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(-37)+(-2) please tell quickly
Answer:-39
Step-by-step explanation:
The first thing is to open the bracket.
By doing that, the question becomes -37-2.
note that plus×minus=minus.
Hence,-39 as the final answer
A rectangle has a height of 4 and a width of x2 + 3x + 2.
Express the area of the entire rectangle.
Expression should be expanded.
Hence, we know that area of rectangle is equals to the product of length and breadth.
Therefore, the area of rectangle is,
\( = 4 \times( {x}^{2} +3x + 2 ) \\ = 4({x}^{2} + 3x + 2) \\ = \green{ \boxed{4 {x}^{2} + 12x + 8}}\)
Therefore, the answer is 4x² + 12x + 8.
PLEASE HELP. HAVING TROUBLE
Step-by-step explanation:
Find equation of the parabola to be - 1/4 ( x-3)^2 -1
expanded this = y= - 1/4 x^2 + 6/4 x- 13/4
derivative of this is - 1/2 x + 6/4
set this equal to the desired slope (1/2)
- 1/2 x + 6/4 = 1/2
- 1/2 x = -1
x = 2
Find the perimeter of the polygon with the given vertices. Round your answer to the nearest hundredth.
Ay
F(-2,4) AO, 4)
N
E-2, 2)
B(2,0)
4 x
-4 -2
D(0, -2)
-C(2,-2)
The perimeter is about how many
units.
Perimeter of the given polygon is 16.94 units.
To measure the distance between two points \((x_1,y_1)\) and \((x_2,y_2)\) is given by the ex[pression,
Distance = \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)
By using this expression,
Distance between A(0, 4) and B(2, 0) = \(\sqrt{(0-2)^2+(4-0)^2}\)
= \(\sqrt{20}\) units
Distance between B(2, 0) and C(2, -2) = \(\sqrt{(2-2)^2+(0+2)^2}\)
= 2 units
Distance between C(2, -2) and D(0, -2) = \(\sqrt{(0-2)^2+(-2+2)^2}\)
= 2 units
Distance between D(0 -2) and E(-2, 2) = \(\sqrt{(0+2)^2+(-2-2)^2}\)
= \(\sqrt{20}\) units
Distance between E(-2, 2) and F(-2, 4) = \(\sqrt{(-2+2)^2+(2-4)^2}\)
= 2 units
Distance between F(-2, 4) and A(0, 4) = \(\sqrt{(-2-0)^2+(4-4)^2}\)
= 2 units
Perimeter of ABCDEF = AB + BC + CD + DE + EF + FA
= \(\sqrt{20}+2+2+\sqrt{20}+2+2\)
= \(8+2\sqrt{20}\)
= 16.94 units
Therefore, perimeter of the given polygon in the graph attached is 16.94 units.
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What is the constant up a proportionally in a equation y=x/g
Answer:
Step-by-step explanation:
\(y=(\frac{1}{g} )x\)
Constant up a proportionally is \(\frac{1}{g}\).
Jack is taller than Pater and Bill is shorter than Jack. what is accurate?
Bill is taller than Peter
N
50°
AOMN~ ARPQ
Find 0.
M
Ө
0 = [?]°
<
P
70°
R
Answer:
60°
Step-by-step explanation:
In similar triangles, the corresponding angles are congruent.
∠O = R
O = 70°
In ΔOMN,
∠O + ∠M + ∠N = 180 {Angle sum property of triangle}
70 + 50 + Ф = 180
120 + Ф = 180
Subtract 120 from both sides,
Ф = 180 - 120
Ф = 60°
What is the approximate length of side GF in triangle EFG?
Answer:
41.93 degrees
Step-by-step explanation:
At the store, 1 candy bar cost $1.29. Write an equation that relates the cost, c, to number of candy bars,n
Answer:
4 candy bars cost $5.16?
Step-by-step explanation:
I just added it 4 four times.
Answer:
C= $1.29n
Step-by-step explanation:
Find the indicated measures, given that EA is a diameter
a) mDEF =
b) mEFG =
c) mAC=
d) Explain how you found each angle measure below. Be sure to show all of your work.
Using the knowledge of the measure of a semicircle, the measures in the circle given are:
a. m(DEF) = 152°
b. m(EFG) = 70°
c. m(CA) = 28°
What is the Measure of a Semicircle?Half of a circle is a semicircle = 180°.
Given the following:
m(CDE) = 152°m(FG) = 31°m(AG) = 110°m(DC) = m(EF) = 180 - 110 - 31 = 39° (semicircle)a. m(DEF) = [m(CDE) - m(DC)] + [m(EF)]
m(DEF) = (152 - 39) + 39
m(DEF) = 152°
b. m(EFG) = m(EF) + m(FG)
m(EFG) = 39 + 31 = 70°
c. m(CA) = 180 - 152 (semicircle)
m(CA) = 28°
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Find the measure of < A to the nearest degree.
Answer:
b-a=60-50
Step-by-step explanation:
what percentage is $ 192.00 of 3200.00
6% is $ 192.00 of 3200.00.
Let x be the percentage.
x = 192 * 100 / 3200
= 19200/3200
= 192/32
x = 6%.
Therefore 6% is $ 192.00 of 3200.00.
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What two numbers multiply to -35 and add to get -18
he two numbers that multiply to -35 and add to get -18 are -5 and 3.
To see why, you can use the factoring method. First, find two numbers that multiply to give you -35. The factors of -35 are -1, 1, -5, and 5. So, the two numbers that multiply to -35 are either -5 and 7 or 5 and -7.
Next, find which pair of numbers adds up to -18. It's clear that 5 and -7 add up to -2, so they don't work. However, if we choose -5 and 3, we get:
-5 + 3 = -2
So, -5 and 3 are the two numbers that multiply to -35 and add to -18.
What are the chances your flight will leave on time? To the right are a histogram and summary statistics for the percentage of flights departing on time each month from 2001 thru 2006. There is no evidence of a trend over time. (The correlation of On Time Departure % with time is r = - 0.006.) Complete parts a) through c) below. Find a 90% confidence interval for the true percentage of flights that depart on time. Interpret this interval for a traveler planning to fly. Choose the correct answer below. There is a 90% chance that the true mean monthly percentage of on-time departures is within the interval. We can be 90% confident that the interval contains the true mean monthly percentage of on-time departures. A randomly selected month has a 90% chance of having an on-time departure percentage within the interval. 90% of all months have on=time departure rates within the interval.
We can be 90% confident that the interval [76.4, 79.3] contains the true mean monthly percentage of on-time departures. This means that we are highly confident that the true mean monthly percentage of on-time departures lies within this interval.
To find the 90% confidence interval, we first need to calculate the margin of error. To calculate this, we need to use the standard error, which is calculated by dividing the standard deviation by the square root of the sample size. The standard deviation for the given data is 2.2 and the sample size is 72 (6 years × 12 months). So, the standard error is calculated as 2.2/√72 = 0.44. The margin of error is then calculated by multiplying the standard error by the critical value for 90% confidence, which is 1.645. The margin of error is therefore 0.44 × 1.645 = 0.72. The confidence interval is then calculated by adding and subtracting the margin of error from the sample mean. The sample mean is 77.8, so the 90% confidence interval is 77.8 ± 0.72, or [76.4, 79.3]. This means that we are highly confident that the true mean monthly percentage of on-time departures lies within this interval.
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Find the median for the data set. 1, 1, 2, 6, 3, 1, 6, 6, 3
Solve the following equations:
(2x + 7)(x - 5) = 0
Answer:
x = -7/2
x = 5
Step-by-step explanation:
Answer:
(2x+7)(x-5)=0
2x+7=x-5
2x-x=5-7
X=-2
Point K is on line segment JL. Given KL = 2x – 2, JL = 4x + 9, and
JK = 5x + 2, determine the numerical length of JL. i
Answer:
JL = 21
Step-by-step explanation:
Given that K is on line segment JL, therefore:
KL + JK = JL (according to segment addition postulate)
KL = 2x - 2
JK = 5x + 2
JL = 4x + 9
Thus:
\( (2x - 2) + (5x + 2) = (4x + 9) \)
Solve for x
\( 2x - 2 + 5x + 2 = 4x + 9 \)
\( 2x +5x - 2 + 2 = 4x + 9 \)
\( 7x = 4x + 9 \)
Subtract 4x from both sides
\( 7x - 4x = 4x + 9 - 4x \)
\( 3x = 9 \)
Divide both sides by 3
\( \frac{3x}{3} = \frac{9}{3} \)
\( x = 3 \)
Find the numerical length of JL
\( JL = 4x + 9 \)
Plug in the value of x
\( JL = 4(3) + 9 = 12 + 9 = 21 \)
What is the measure of Zx?
Angles are not necessarily drawn to scale.
B
156
2
.
А
-C
o
2
PLZ HELP
Answer:
\(\huge\boxed{\sf <x = 24\°}\)
Step-by-step explanation:
∠x and 156° are supplementary i.e. angles on a straight line that add up to 180 degrees.
So,
∠x + 156 = 180
Subtract 156 to both sides
∠x = 180 - 156
∠x = 24°
\(\rule[225]{225}{2}\)
Hope this helped!
~AH1807Answer:
\(\boxed{\sf x=24\°}\)
Step-by-step explanation:
From the given diagram, we can see that ∠BOC and ∠AOB are supplementary angles.
Therefore, \(\sf m=\angle BOC+m\angle AOB=180\°\)
\(\sf m=\angle BOC+m\angle AOB=180\°\)
\(\sf x+156=180\°\)
Subtract 156 from both sides:
\(\sf x+156-156=180-156\)
\(\sf x=24\°\)
__________________________________
The angles of a quadrilateral are in the ratio 2:4:5:6 what is the difference between the largest angle and the smallest angle
Answer:
85
Step-by-step explanation:
From the question given above, the following data were obtained:
Ratios of the angle => 2 : 4 : 5 : 6
Difference between the largest angle and the smallest angle =?
Next, we shall determine the various angles in the quadrilateral. This can be obtained as follow:
Ratios of the angle => 2 : 4 : 5 : 6
Total ratio = 2 + 4 + 5 + 6
Total ratio = 17
Angle in a quadrilateral = 360
For ratio 2:
Angle = 2/17 × 360 ≈ 42
For ratio 4:
Angle = 4/17 × 360 ≈ 85
For ratio 5:
Angle = 5/17 × 360 ≈ 106
For ratio 6:
Angle = 6/17 × 360 ≈ 127
SUMMARY:
The angles are => 42°, 85°, 106° and 127°
Finally, we shall determine the difference between largest angle and the smallest angle. This can be obtained as follow:
Smallest angle = 42°
Largest angle = 127°
Difference between the largest angle and the smallest angle =?
Difference = Largest – Smallest
Difference = 127 – 42
Difference = 85
Thus, the difference between the largest angle and the smallest angle is 85.
I need help with this question. I would like a detailed explanation please!(what are the measurements)
Answer:
X = 66
Step-by-step explanation:
A straight line is equal to 180 degrees so if you have one side of that line you can figure out the inside angle.
Now that you have two of the angles inside the triangle add them up. All the interior angles of a triangle will add to 180. So add up 38 and 76 to get 114. Now do 180 - 114, you should get 66
so x = 66
A person standing 213 feet from the base of a church observed the angle of elevation to the church's steeple to be 33 ∘ .
Complete Question
A person standing 213 feet from the base of a church observed the angle of elevation to the church's steeple to be 33 ∘. Find the height of the church
Answer:
138.3 ft
Step-by-step explanation:
We solve this question above using using the Trigonometric function of Tangent.
tan θ = Opposite/Adjacent
Where:
Opposite = Height of the church = x
Adjacent = Distance for the base of the church = 213ft
Angle of elevation θ = 33°
Hence:
tan 33 = x /213 ft
Cross Multiply
x = tan 33 × 213 ft
x = 138.32381735 ft
x = Opposite Approximately = 138.3 ft
Therefore, the height of the church = 138.3 ft
the following are the populations for the top twelve largest cities in the u. s. New York city, NY: 8,336,817 Los Angeles ca: 979.576 Chicago, il:2,693,976 Houston, Tx: 2,320,268 phoenix Az: 1,680,992 Philadelphia pa: 1,584,064 San Antonio Tx: 1, 547,253 San Diego ca: 1,423,851 Dallas Tx: 1,343,573 San Jose ca: 1,021,795 Austyn tx:978,908 Jacksonville Fl: 911,507. what is the mean population?, what is the median population?, what is the mode?, what is range?, what is the standard deviation?I need the standard deviation, I already did mode, mean, range, take the value of the population of each city, subtract the mode raised to 2, it does not give me the result
The mean is 2,071,798.33
The Median is 1,485,552
The range is 7,425,310
The standard deviation is given as 1961105.68
The mean population can be computed as:Mean = (Sum of all populations) / (Number of cities)
= (8,336,817 + 979,576 + 2,693,976 + 2,320,268 + 1,680,992 + 1,584,064 + 1,547,253 + 1,423,851 + 1,343,573 + 1,021,795 + 978,908 + 911,507) / 12
= 24,861,580 / 12
= 2,071,798.33
To find the median, we need to arrange the populations in increasing order and find the middle value. If we arrange these values, we get:
911,507, 978,908, 979,576, 1,021,795, 1,343,573, 1,423,851, 1,547,253, 1,584,064, 1,680,992, 2,320,268, 2,693,976, 8,336,817
Since there are 12 cities (an even number), the median would be the average of the 6th and 7th values:
Median = (1,423,851 + 1,547,253) / 2
= 1,485,552
The mode isn't applicable here as no city population repeats.
The range is the highest population minus the lowest population:
Range = 8,336,817 - 911,507
= 7,425,310
Standard deviation = (911507- 2068548.3333333)² + (978908 - 2068548.3333333)² + (979576 - 2068548.3333333)² + ( 1021795 - 2068548.3333333)² + (1343573- 2068548.3333333)² +( 1423851- 2068548.3333333)² + (1547253- 2068548.3333333)² +( 1584064- 2068548.3333333)² + (1680992- 2068548.3333333)² + ( 2320268- 2068548.3333333)² +(2693976- 2068548.3333333)² +( 8336817 - 2068548.3333333)² / 12
= 46151226311869 / 12
= 3845935525989.1
\(standard deviation = \sqrt{ 3845935525989.1}\)
= 1961105.6896529
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the probability of an airline flight arriving on time at a certain airport is 84%, use a normal approximate to find the probability that more than 240 in a random sample of 400 commercial airline flights at the airport will arrive on time
The probability that more than 240 flights in a random sample of 400 commercial airline flights will arrive on time is approximately 1 or 100%.
To solve this problem using a normal approximation, we need to calculate the mean (μ) and standard deviation (σ) of the binomial distribution and then use the normal distribution to approximate the probability.
Given:
Probability of an airline flight arriving on time (success): p = 0.84
Number of trials (flights): n = 400
Number of flights arriving on time (successes): x > 240
First, we calculate the mean and standard deviation of the binomial distribution using the following formulas:
Mean (μ) = n * p
Standard Deviation (σ) = √(n * p * (1 - p))
μ = 400 * 0.84 = 336
σ = √(400 * 0.84 * 0.16) = √(53.76) ≈ 7.33
Now, we can use the normal distribution to find the probability that more than 240 flights will arrive on time. Since we're interested in the probability of x > 240, we will calculate the probability of x ≥ 241 and then subtract it from 1.
To use the normal distribution, we need to standardize the value of 240:
z = (x - μ) / σ
z = (240 - 336) / 7.33
z ≈ -13.13
Now, we can find the probability using the standard normal distribution table or a calculator. Since the value of z is extremely low, we can approximate it as:
P(x > 240) ≈ P(z > -13.13)
From the standard normal distribution table or calculator, we find that P(z > -13.13) is essentially 1 (close to 100%).
Therefore, the probability that more than 240 flights in a random sample of 400 commercial airline flights will arrive on time is approximately 1 or 100%.
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3.52 A coin is tossed twice. Let Z denote the number of heads on the first toss and W the total number of heads on the 2 tosses. If the coin is unbalanced and a head has a 40% chance of occurring, find (a) the joint probability distribution of W and Z; (b) the marginal distribution of W; (c) the marginal distribution of Z
Answer:
a) The joint probability distribution
P(0,0) = 0.36, P(1,0) = 0.24, P(2,0) = 0, P(0,1) = 0, P(1,1) = 0.24, P(2,1)= 0.16
b) P( W = 0 ) = 0.36, P(W = 1 ) = 0.48, P(W = 2 ) = 0.16
c) P ( z = 0 ) = 0.6
P ( z = 1 ) = 0.4
Step-by-step explanation:
Number of head on first toss = Z
Total Number of heads on 2 tosses = W
% of head occurring = 40%
% of tail occurring = 60%
P ( head ) = 2/5 , P( tail ) = 3/5
a) Determine the joint probability distribution of W and Z
P( W =0 |Z = 0 ) = 0.6 P( W = 0 | Z = 1 ) = 0
P( W = 1 | Z = 0 ) = 0.4 P( W = 1 | Z = 1 ) = 0.6
P( W = 1 | Z = 0 ) = 0 P( W = 2 | Z = 1 ) = 0.4
The joint probability distribution
P(0,0) = 0.36, P(1,0) = 0.24, P(2,0) = 0, P(0,1) = 0, P(1,1) = 0.24, P(2,1)= 0.16
B) Marginal distribution of W
P( W = 0 ) = 0.36, P(W = 1 ) = 0.48, P(W = 2 ) = 0.16
C) Marginal distribution of Z ( pmf of Z )
P ( z = 0 ) = 0.6
P ( z = 1 ) = 0.4
Part(a): The required joint probability of W and Z is ,
\(P(0,0)=0.36,P(1,0)=0.24,P(2,0)=0,P(0,1)=0,P(1,1)=0.24,\\\\P(2,1)=0.16\)
Part(b): The pmf (marginal distribution) of W is,
\(P(w=0)=0.36,P(w=1)=0.48,P(w=2)=0.16\)
Part(c): The pmf (marginal distribution) of Z is,
\(P(z=0)=0.6,P(z=1)=0.4\)
Part(a):
The joint distribution is,
\(P(w=0\z=0)=0.6,P(w=1|z=0)=0.4,P(w=2|z=0)=0\)
Also,
\(P(w=0\z=1)=0,P(w=1|z=1)=0.6,P(w=2|z=1)=0.4\)
Therefore,
\(P(0,0)=0.36,P(1,0)=0.24,P(2,0)=0,P(0,1)=0,P(1,1)=0.24,\\\\P(2,1)=0.16\)
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