find the weight of 5 kg potato​

Answer:

The extrapolated data from these simulations determined that Earth will lose its oxygen-rich atmosphere in approximately 1 billion years. That's the good news. The bad news is that once that happens, the planet will become completely inhospitable for complex aerobic life.

The magnitude of the deceleration of the car will be 3.895 meters per second square.

One dimension denotes mobility in a single direction or in a straight line. Think of a vehicle traveling down a straight road or a person walking on a straight track. Imagine throwing something vertically into the air, then observing it fall.

When the driver suddenly presses the brakes, a car that is now moving at 28.6 m/s begins to slow down steadily. Within 105 meters, the vehicle stops.

v² - u² = 2as

0² - (28.6)² = 2 x a x 105

- 817.96 = 210a

a = - 3.895 meters per second square

The magnitude of the deceleration will be 3.895 meters per second square.

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Answer:

Explanation:

average speed is distance traveled over time

v = (50 + 30(1.5)) / (2 + 1.5) = 27.1428571...

v = 27 km/hr

Answer:

t = 3.924 s

Explanation:

First, we will calculate the amount of work required to get the astronaut back to the capsule:

\(W = Fd\\\)

where,

W = work required = ?

F = Force = Weight = mg = (80 kg)(9.81\ m/s²) = 784.8 N

d = distance = 5 m

Therefore,

\(W = (784.8\ N)(5\ m)\\W = 3924 J\)

Now the time can be calculated as:

\(Power = \frac{W}{t}\\t = \frac{W}{Power}\\\\t = \frac{3924\ J}{1000\ W}\\\\\)

t = 3.924 s

To figure out this issue, we can combine vectors and use trigonometry. Let's analyze the provided information:

The force in rope A (horizontal direction) is 6 kilonewtons.

The angle between rope A and the horizontal is 60 degrees.

The force pushing up on the post is 12 kilonewtons.

First, let's calculate the up and down force in rope A. The force in rope A going up should be the same as the resultant force, which is also going up.

The force pulling upward on rope A is 12 kilonewtons.

We can use trigonometry to find the sideways force in rope A. To find the horizontal part, you can use this formula:

The horizontal part of the force in rope A can be found by multiplying the force in rope A by the cosine of the angle.

The horizontal force in rope A is equal to 6 kilonewtons multiplied by the cosine of 60 degrees.

The force pulling horizontally on rope A is equal to 6 kilonewtons (kN) multiplied by 0. 5

The force pulling on rope A from side to side is 3 kN.

Now, let's figure out the strength in rope B. Since the total force is the combination of the forces in ropes A and B, we can express this using the following equation:

"The resultant force is the sum of the force in rope A and the force in rope B. "

The force in rope B is equal to 12 kN minus 3 kN.

Making the equation simpler, we discover or figure out:

The force in rope B is equal to the total force minus the force in rope A.

The force in rope B is 12 kN minus 3 kN.

The force in rope B is 9 kilonewtons.

Lastly, let's determine the angle between rope B and the horizontal line. We can use trigonometry again.

The tan of an angle is equal to the vertical force in rope B divided by the horizontal force in rope B.

The tangent of an angle equals the force in rope B divided by the force in rope A.

The tangent of an angle is equal to 9 kilonewtons divided by 3 kilonewtons.

The tan of an angle is equal to 3.

To find the inverse tangent (arctan) of both sides,

The angle is equal to the arctan of 3.

The angle is approximately 71. 57 degrees

So, the force in rope B is 9 kilonewtons and the angle 0 is about 71. 57 degrees

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Answer:

A system of two co-axial cylindersof different diameters which rotate together is called wheel and axle example; the door knob , knob of the tap ,screw driver,water tap

Answer:

C. remix

Explanation:

A is wrong because the prefix ir- means not

B is wrong because the prefix un means not

C is correct because re means again

D is wrong because over means too much

Answer:

Explanation: The moon of the Earth is much lighter in mass than the planet itself. In addition to being smaller than Earth, the Moon is also only approximately 60% as dense. A human weighs less on the Moon because there is less gravitational attraction there than there is on Earth.

Moon has lesser mass as conpared to earth, therefore gravitational force exerted by moon on any object is lesser than that of gravitational force exerted by earth on the same object, hence we can say that astronauts weight less on moon, i.e approximately 1/6 th of their weight on earth.

Net forces in all above cases will be

A) F net = 0

B) F net = 1 N

C) F net = 5 N

D) F net = 5N

E) F net  = 5 N

F) F net = 5 N

G) F net = 9.9 N

H) F net = 9.9 N

A) net force = upward force - downward force

                   = 4 - 4 = 0

B) net force = rightward force - leftward force = 4 - 3 = 1 N  

C) net force  

using Pythagoras theorem

F net =  \(\sqrt{4^{2} + 3^{2} }\) = \(\sqrt{25}\) = 5 N

D) F net = \(\sqrt{-4^{2} + (-3)^{2} }\) = 5 N

E) balancing horizontal forces

   rightward force - leftward force  = 5 - 2 = 3 N

   using  Pythagoras theorem

   F net =  \(\sqrt{4^{2} + 3^{2} }\) = 5 N

F) balancing vertical forces

   -5 + 2 = -3 N

    using  Pythagoras theorem

     \(\sqrt{(-4)^{2} +(-3) ^{2} }\) = 5 N

G) using  Pythagoras theorem

    F net = \(\sqrt{7^{2} + 7^{2} }\) = 9.9 N

H ) balancing horizontal forces

     10 - 3 = 7 N

     \(\sqrt{7^{2} + 7^{2} }\) = 9.9 N

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1. The speed of light in vacuum is 3x108 m/s

2. Polarized filter is helpful to a photographer because, it blocks some light but not all.

3. When a sound wave propagates through air, the air molecules vibrate side to side, perpendicular to the wave’s direction of travel.

Polarization of light is defined as the phenomenon by which the vibrations of light gets restricted to a particular direction that is perpendicular to the direction of wave motion.

Here,

1. The speed of light in the vacuum, c = 3x108 m/s

2. Photographers use the polarized filters for photography to improve the landscape photographs. This is because, using polarized filters in the camera can reduce unwanted reflections and glares from the external light. This could help to improve the contrast in landscape photography.

3. When a sound wave is propagated through air, the air molecules also move along with it. This is because, when the wave passes through the air, it pushes the air molecule, leading to the bouncing of air molecules with the surrounding molecules. Thus exerts a high pressure in air and when the the peak of the wave is passed, the pressure gets lower. This causes the movement of air molecules in a direction perpendicular to the direction of propagation of the wave.

Hence,

1. The speed of light in vacuum is 3x108 m/s

2. Polarized filter is helpful to a photographer because, it blocks some light but not all.

3. When a sound wave propagates through air, the air molecules vibrate side to side, perpendicular to the wave’s direction of travel.

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g i rl co me

Mee: 5324611502

Pass: 1234

Answer:

Explanation:

The Spanish flu pandemic of 1918, the deadliest in history, infected an estimated 500 million people worldwide about one-third of the planet’s population and killed an estimated 20 million to 50 million victims, including some 675,000 Americans. The 1918 flu was first observed in Europe, the United States and parts of Asia before swiftly spreading around the world. At the time, there were no effective drugs or vaccines to treat this killer flu strain. Citizens were ordered to wear masks, schools, theaters and businesses were shuttered and bodies piled up in makeshift morgues.

Does this sound familiar?

Its the same thing but with a different name called the Corona virus pandemic the same thing happened in 1918 and now it is happening again in 2020 , but in in 2020 there are far less people infected by the Corona virus as compared to the Spanish flu the numbers approximate around 70 million infected and deaths are around 2 million.

The rapid spread of Spanish flu in the fall of 1918 was at least partially to blame on public health officials unwilling to impose quarantines during wartime. The public health response to the crisis in the United States was further hampered by a severe nursing shortage as thousands of nurses had been deployed to military camps and the front lines. But one of the chief reasons that the Spanish flu claimed so many lives in 1918 was that science simply didn’t have the tools to develop a vaccine for the virus. Microscopes couldn’t even see something as incredibly small as a virus until the 1930s.

That is why the Spanish Flu claimed so many lives in 1918 and the Corona Virus didn't claim that many.

The Corona Virus patients with respect to Spanish Flu patients exponentially decreased because in 2020 we had the specific tools to fight the virus and since mankind was aware when the world engrossed into the pandemic 100 years before the new the risks that it could impose on the world , People started to Quarantine themselves, more nurses/doctors are available rather than in the era of the 19th century.

Mathematically we would say that the exponential growth would be:

\(y=ab^x\)

This is an exponential function, which means as you increase  x , y  increases exponentially, and where a is the initial value and b is the growth factor.

For example:

There are 100,000 cases of Coronavirus when the virus outbroke. If the number of cases doubles every week then how many cases would be there in 10 weeks?

So the solution would be

\(y=ab^x\\y=100000(2)^{10}\\y=102400000\)

Which means people infected with the virus would be approximate 102.5 million. But since this kind of pandemic already broke out in 1918 called the Spanish flu mankind was wise and controlled its growth factor (b) by Quarantining people , shutting down businesses, schools  and implying them to work from home , closing off cafeteria's restaurants for dine in purposes and just allowing take away to reduce human contact, and since 1918 we have more doctors and nurses to treat the infected in 2020 we reduced the outbreak to 70 million in about 10 months other wise it could have been 100 million in just 2.5 months as we can see.

So guys stay indoors just go out if you REALLY need something, avoid meeting others , wear masks and gloves :)

Answer: B im sorry if its wrong

Explanation:

Answer:

Use proportions to find the scale of the first photo, then use that scale and other given information to fill in the equation

S=f/(H-h)

Where:

S = scale of the photo

f = focal length of the camera (in feet)

H = flying height

h = average elevation

Answer:

F is non-conservative.

If F were conservative no work would be done in moving back to the original point.       F dot S = W     if the net distance is zero the work done is zero for a conservative force

An object acted on by a constant force F moves from point 1 to point 2 and back again. The work done by the force F in this round trip is 60 J. Force, F is non-conservative.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Moving back to the initial point wouldn't need any labor if F were a conservative function. Given that F.S = W, a conservative force does not exert any effort if the net distance is zero.

An object acted on by a constant force F moves from point 1 to point 2 and back again. The work done by the force F in this round trip is 60 J. Force, F is non-conservative.

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The height that will illustrate the distance will be d = 6.36m

Based on the information given, the length of the vine will be:

L = ✓(16² + 27.7)²

L = 32m

The velocity of Jane when she reaches position B will be:

V = ✓2gh

V = ✓(2 × 9.8 × 4.3)

V = 9.18m/s

We will apply the conversation of momentum. This will be:

50 × 9.18 = (50 + 80)V1

V1 = 3.53m/s

Therefore, the height that will illustrate the distance will be:

31.36² + d² = 32²

d² = 32² - 31.36²

d = 6.36m

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The energy lost to friction and air resistance is 186 J.

option B.

The energy lost to friction and air resistance is calculated from the change in the mechanical energy of the pendulum.

The initial potential energy of the pendulum at the initial position is calculated as;

PEi = mghi

where;

P.Ei = 12 kg x 9.8 m/s² x 20 m

P.Ei = 2,352 J

The final kinetic energy of the pendulum is calculated as follows;

K.Ef = 0.5 x 12 kg x (19 m/s)²

K.Ef = 2,166 J

ΔE = 2,166 J - 2,352 J

ΔE = -186 J

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The finished compost can be used to enrich soil for planting and gardening. Mix the compost into the soil or use it as a top dressing around plants.

Substances Used to Fill It:

A mixture of "brown" and "green" organic materials such as leaves, grass clippings, fruit and vegetable scraps, coffee grounds, and shredded paper can be used to fill the bin.

Household Items That Can Go in It:

Most fruit and vegetable scraps, eggshells, tea bags, coffee grounds, yard waste such as grass clippings and leaves, and shredded paper can be added to the compost bin. Meat, dairy, and fatty foods should be avoided.

How Long It Takes Before It Is Ready:

The compost should be ready to use in approximately 6 to 12 months, depending on the environmental conditions and the frequency of turning and mixing the compost.

How You Use the Compost:

The finished compost can be used as a nutrient-rich soil amendment for planting and gardening.

Compost Bin Design:

To add household items to your compost bin, simply add any of the following organic materials to the bin: fruit and vegetable scraps, coffee grounds and filters, tea bags, eggshells, yard waste such as leaves and grass clippings, and shredded paper.

Compost is ready to use in this much time:

The compost should be ready to use in approximately 6 to 12 months, depending on the environmental conditions and the frequency of turning and mixing the compost.

Use your compost this way:

The finished compost can be used to enrich soil for planting and gardening. Mix the compost into the soil or use it as a top dressing around plants.

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Answer:

I’m pretty sure it’s B. It is harmful to the person and beneficial to the bacteria.

Explanation:

I’m taking the test right now. But if you think about it the bacteria is fighting off the medicine to which means the bacteria will just keep growing. So I’m 97% sure it’s B. Good luck you can do it don’t stop believing in yourself!!!!!! Hope I helped. And remember at the end of the day all that matters is love and happiness not grades!!!!!!!

Answer:

Answer is B!

Explanation:

I took the cumulative exam and got 100%

The frequency of f3 is approximately 716 Hz.

The frequency of a repeated event is its number of instances per unit of time. Hertz (Hz), which stands for the number of cycles per second, is a popular unit of measurement.

a. Given two frequencies, f1 and f2, the frequency ratio is as follows:

frequency ratio= \(\frac{f2}{f1}\)

Inputting the values provided yields:

frequency ratio = \(\frac{576}{320Hz}\) =1.8.

As a result, the difference in frequency between f1 = 320 Hz and f2 = 576 Hz is 1.8.

b. Since there are 12 half-steps in an octave and a fourth is a distance of 5 half-steps, going down a fourth requires dividing the frequency by \(2^{(4/12)}\). Hence, once a fourth is subtracted, the frequency ratio between f and f1 is:

frequency ratio= \(\frac{f}{ (f1 /f2 ) }\)=  \(\frac{f}{ (f1 / 1.3348) }\)

By dividing the numerator and denominator by 1.3348, we may make this more straightforward:

frequency ratio= (f × 1.33348)/f1

As a result, (f × 1.3348) / f1 is the frequency ratio between f and f1 after descending a fourth.

c. (c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by: \(2^{(7/12)}\) = 1.49831

Therefore, the frequency of f3 is:

f3 = f1 × (\(2^{(7/12)}\)) × (\(2^{(7/12)}\)) = 320 Hz × 1.49831 ×1.49831 = 716 Hz

Therefore, the frequency of f3 is approximately 716 Hz.

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Answer:

\(F=5(240t^2i+72tj)\ N\)

Explanation:

Given that,

The mass of the object, m = 5 kg

The position vector is, \(r=20t^4i+12t^3j\)

Velocity, \(v=\dfrac{dr}{dt}=80t^3i+36t^2j\)

Acceleration, \(a=\dfrac{dv}{dt}=240t^2i+72tj\)

Newton's second law of motion is given as follows:

F = ma

Put all the values,

\(F=5(240t^2i+72tj)\ N\)

Hence, this is the required solution.

Answer:

1. The de Broglie wavelength of the electron decreases if its momentum increases.

b. The de Broglie wavelength of the electron decreases is the correct answer

2. The de Broglie wavelength of the electron increases as the kinetic energy decreases.

a. The de Broglie wavelength of the electron increases is the correct option

Explanation:

1. The relationship between de Broglie wavelength, λ and momentum ρ is given by

λ = h/ρ

Where λ is the de Broglie wavelength

h is Planck's constant and

ρ is the momentum

From the formula, the de Broglie wavelength, λ varies inversely with the momentum, ρ. Hence, as the de Broglie wavelength increases the momentum decreases; similarly, as the de Broglie wavelength decreases, the momentum increases.

For question 1, The de Broglie wavelength of the electron decreases if its momentum increases.

b. The de Broglie wavelength of the electron decreases is the correct answer

2. From

λ = h/ρ

ρ = mv

∴ λ = \(\frac{h}{mv}\)

Where m is mass

and v i velocity

Recall that Kinetic energy K.E is given by

K.E = \(\frac{1}{2}mv^{2}\)

\(E_{K} = \frac{1}{2}mv^{2}\)

\(E_{K}\) is the kinetic energy

∴ \(v = \sqrt{\frac{2E_{K} }{m} }\)

Now we will evaluate \(mv\)

\(mv = m \sqrt{\frac{2E_{K} }{m} }\\mv = \sqrt{m^{2} }.\sqrt{\frac{2E_{K} }{m} }\\ mv = \sqrt{\frac{2m^{2}E_{K} }{m} } \\mv = \sqrt{{2mE_{K} }\)

∴ λ = \(\frac{h}{mv}\) becomes

λ = \(\frac{h}{\sqrt{2mE_{K} } }\)

This equation shows the relationship between the de Broglie wavelength and kinetic energy, \(E_{K}\)

From the equation, de Broglie wavelength varies inversely with kinetic energy. That is, as the de Broglie wavelength increases the kinetic energy decreases; similarly, as the de Broglie wavelength decreases, the kinetic increases.

For question 2, The de Broglie wavelength of the electron increases as the kinetic energy decreases.

a. The de Broglie wavelength of the electron increases is the correct option

Answer:

Kinetic.

Explanation:

Temperature can be defined as a measure of the degree of coldness or hotness of a physical object. It is measured with a thermometer and its units are Celsius (°C), Kelvin (K) and Fahrenheit (°F).

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Generally, temperature measures the average kinetic energy of particles in a particular substance. Also, when the temperature of a particular substance is greater than absolute zero, it is said to possess kinetic energy.

Additionally, conduction involves the transfer of electric charge or thermal energy due to the movement of particles.

In the process of heat conduction, thermal energy is usually transferred from fast moving particles to slow moving particles during the collision of these particles. Also, thermal energy is typically transferred between objects that has different degrees of temperature and materials (particles) that are directly in contact with each other but differ in their ability to accept or give up electrons.

The term "temperature" refers to a measurement of how cold or hot an actual physical object is. It is measured with a thermometer, which gives readings in Celsius, Kelvin, and Fahrenheit (°C, K, and °F).

Thus, An energy that an object or body possesses as a result of its motion is known as kinetic energy.

The average kinetic energy of the particles in a given substance is often measured by temperature. Additionally, a substance is said to have kinetic energy when its temperature is higher than absolute zero.

Conduction also entails the transmission of heat or electric charge as a result of the motion of particles. Thermal energy is typically transmitted from quickly moving particles to slowly moving particles during a collision in the process of heat conduction.

Thus, The term "temperature" refers to a measurement of how cold or hot an actual physical object is. It is measured with a thermometer, which gives readings in Celsius, Kelvin, and Fahrenheit (°C, K, and °F).

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Answer:

(a) Fw = 101.01 N

(b) W = 282.82 J

(c) Fg = 382.2 N

(d) N = 368.61 N

(e) Net force = 0 N

Explanation:

(a) In order to calculate the magnitude of the worker's force, you take into account that if the ice block slides down with a constant speed, the sum of forces, gravitational force and work's force, must be equal to zero, as follow:

\(F_g-F_w=0\)        (1)

Fg: gravitational force over the object

Fw: worker's force

However, in an incline you have that the gravitational force on the object, due to its weight, is given by:

\(F_g=Wsin\theta=Mg sin\theta\)       (2)

M: mass of the ice block = 39 kg

g: gravitational constant =  9.8m/s^2

θ: angle of the incline

You calculate the angle by using the information about the distance of the incline and its height, as follow:

\(sin\theta=\frac{0.74m}{2.8m}=0.264\\\\\theta=sin^{-1}(0.264)=15.32\°\)

Finally, you solve the equation (1) for Fw and replace the values of all parameters:

\(F_w=F_g=Mgsin\theta\\\\F_w=(39kg)(9.8m/s^2)sin(15.32\°)=101.01N\)

The worker's force is 101.01N

(b) The work done by the worker is given by:

\(W=F_wd=(101.01N)(2.8m)=282.82J\)

(c) The gravitational force on the block is, without taking into account the rotated system for the incline, only the weight of the ice block:

\(F_g=Mg=(39kg)(9.8m/s^2)=382.2N\)

The gravitational force is 382.2N

(d) The normal force is:

\(N=Mgcos\theta=(39kg)(9.8m/s^2)cos(15.32\°)=368.61N\)

(e) The speed of the block when it slides down the incle is constant, then, by the Newton second law you can conclude that the net force is zero.

\({T sin \theta}\)Answer:

 q = 27.16 C

Explanation:

For this exercise we use the equations of equilibrium. Let's set a reference system with the x-axis horizontally.

X axis

            F_e - Tₓ = 0

Axis y

           T_y -W = 0

let's use trigonometry

           cos θ = T_y / T

           sin θ= Tx / T

           T_y = T cos θ

           Tₓ = T sin θ

Axis y

            T cos θ = W

            T = mg / cos θ

X axis

            F_e = T sin θ

            qE = T sin θ

            q =   \(\frac{T sin \theta}{E}\)  

            q = \(\frac{mg}{cos \theta } \frac{sin \thrta }{E}\)

            q = \(\frac{mg}{E} tan \theta\)

in the exercise they indicate that the electric field is the month of birth E = 8 N / C and the angle tea = 30º

let's calculate

              q = 0.2 9.8 8 / tan 30

              q = 27.16 C

Answer:

(a) Ra = 9.25 kN; Rb = 5.75 kN

(b) 26.7 kN

Explanation:

(a) Draw a free-body diagram of the crane.  There are four forces:

Reaction Ra pushing up at A,

Reaction Rb pushing up at B,

Weight force 12.5 kN pulling down at G,

and weight force 2.5 kN pulling down at F.

Sum of moments about B in the counterclockwise direction:

∑τ = Iα

-Ra (0.66 m + 0.42 m + 2.52 m) + 12.5 kN (2.52 m + 0.42 m) − 2.5 kN ((3.6 m + 0.9 m) cos 30° − 2.52 m) = 0

-Ra (3.6 m) + 12.5 kN (2.94 m) − 2.5 kN (1.38 m) = 0

Ra = 9.25 kN

Sum of moments about A in the counterclockwise direction:

∑τ = Iα

Rb (0.66 m + 0.42 m + 2.52 m) − 12.5 kN (0.66 m) − 2.5 kN ((3.6 m + 0.9 m) cos 30° + 0.66 m + 0.42 m) = 0

Rb (3.6 m) − 12.5 kN (0.66 m) − 2.5 kN (4.98 m) = 0

Rb = 5.75 kN

Alternatively, you can use sum of the forces in the y direction as your second equation.

∑F = ma

Ra + Rb − 12.5 kN − 2.5 kN = 0

Ra + Rb = 15 kN

9.25 kN + Rb = 15 kN

Rb = 5.75 kN

However, you must be careful.  If you make a mistake in the first equation, it will carry over to this equation.

(b) At the maximum weight, Ra = 0.

Sum of the moments about B in the counterclockwise direction:

∑τ = Iα

12.5 kN (2.52 m + 0.42 m) − F ((3.6 m + 0.9 m) cos 30° − 2.52 m) = 0

12.5 kN (2.94 m) − F (1.38 m) = 0

F = 26.7 kN

Answer:

it is A  or 20x80 cm

Explanation: DID IT ON APEX

WOO

The bullet is in the barrel for 4.5610^-5 s, experiences a force of 16713 N, an impulse of 0.763 Ns, and has a momentum of mv = 34.5 kg*m/s as it leaves the barrel.

What are the time, force, impulse, and momentum of a bullet fired from a gun with given mass, barrel length, and muzzle velocity

(a) The time the bullet spends in the barrel can be found using the equation for distance traveled by an object with constant acceleration, where the initial velocity is zero and the distance is the barrel length:

d = 1/2 at^2

Solving for time t, we get:

t = √(2d/a)

where a is the acceleration of the bullet as it is propelled out of the barrel. To find the acceleration, we can use the equation for force:

F = ma

where F is the force exerted on the bullet, m is the mass of the bullet, and a is its acceleration. Since the bullet is in the barrel, the force is the force of the expanding gases from the gunpowder. We can find this force using the ideal gas law:

PV = nRT

where P is the pressure of the gases, V is the volume of the barrel, n is the number of moles of gas produced by the gunpowder, R is the ideal gas constant, and T is the temperature of the gases. Solving for P, we get:

P = nRT/V

We can assume that the volume of the barrel remains constant during the firing of the bullet, so we can write:

P = k nT

where k is a constant that depends on the volume of the barrel and the gas constant R. Since the bullet is fired in a fraction of a second, we can assume that the temperature of the gases remains constant, so we have:

P = k n

The force exerted on the bullet is then:

F = PA = k nA

where A is the cross-sectional area of the barrel.

a = F/m = k nA/m = k P A/m = (kRT/V)(πr^2)/m

where r is the radius of the barrel. we get:

a = (k)(8.31 J/molK)(293 K)/(0.00066 m^3)(π(0.0033 m)^2)/(0.075 kg) = 2.4110^7 m/s^2

Plugging this into the equation for time, we get:

t = √(2d/a) = √(20.66 m/2.4110^7 m/s^2) = 4.56*10^-5 s

So the bullet is in the barrel for 4.56*10^-5 s.

(b) The force on the bullet while it is in the barrel is the force exerted by the expanding gases from the gunpowder, which we found to be:

F = k nA

Substituting in the given values, we get:

F = (k)(8.31 J/mol*K)(293 K)/(0.00066 m^3)(π(0.0033 m)^2) = 16713 N

So the force on the bullet while it is in the barrel is 16713 N.

(c) The impulse exerted on the bullet while it is in the barrel is the product of the force and the time:

J = FΔt = (16713 N)(4.5610^-5 s) = 0.763 Ns

So the impulse exerted on the bullet while it is in the barrel is 0.763 N*s.

(d) The momentum of the bullet as it leaves the barrel can be found using the equation:

p = mv

where p is the momentum, m is the mass of the bullet, and v is its velocity. We can find the velocity using conservation of energy, since the gun and bullet

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