Answer:
41.38
Explanation: You take the 3.14 and multiply it with the
A 33 kg box sits at rest on a tabletop.
Draw and clearly label all the forces acting on the box;
Calculate the normal force.
Answer:
323.4N
Explanation:
Given parameters:
Mass of the box = 33kg
Unknown:
Normal force on the body = ?
Solution:
The normal force of a body is the vertical force the body exerts on another body.
It is expressed as;
Normal force = mass x acceleration due to gravity
Acceleration due to gravity = 9.8m/s²
Normal force = 33 x 9.8 = 323.4N
The gymnast swings from one bar to the other bar several times.
Describe how the gravitational potential energy store and the kinetic energy store of the
gymnast change as she moves between the bars.
Each and every ounce of potential energy begins to transform into kinetic energy. Also, the height at the bottom is zero and is not present. Her ability to sense energy is thus at its optimum, and potential energy equals zero.
In plain terms, what is kinetic energy?Kinetic energy is indeed the power a thing has as a result of motion. Applying a force is necessary in order to accelerate an object. We must exert effort in order to apply a force. Once the job is finished, energy is transferred to the item, which then moves at a new, constant speed.
Why is it known as kinetic energy?An object or particle has kinetic energy because of its motion. When an item undergoes work—the transfer of energy—by being subjected to a net force, it accelerates and acquires kinetic energy.
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How to Estimate your age in seconds ?
No Spamming ~
Answer:
Explanation:
First, remember your age.
Then, multiply it times 365 x 24 x 60 x 60.
Or basically, multiply it times 315.36 x 10⁵
A lump of metal was placed in a liquid whose temperature is held constant at 80oF. The initial temperature of the lead block was 30oF. After 10 minutes, the temperature of the lead block was 60oF. Assuming that the temperature of the lump obeys Newton's Law of Cooling, determine the temperature T of the lump after t minutes.
The temperature T of the lump of metal after t minutes, assuming it obeys Newton's Law of Cooling, can be expressed as T = -30kt + 30. However, the value of the cooling constant k is not provided, so it is not possible to determine the exact temperature without additional information.
Newton's Law of Cooling states that the rate of change of temperature of an object is directly proportional to the temperature difference between the object and its surroundings. Mathematically, this can be expressed as:
dT/dt = -k(T - Ts)
where dT/dt is the rate of change of temperature with respect to time, T is the temperature of the object, Ts is the temperature of the surroundings, and k is the cooling constant.
In this case, we can use the given data to find the value of k. After 10 minutes, the temperature of the lead block was 60oF, and the temperature of the surroundings was held constant at 80oF. Plugging these values into the equation, we have:
dT/dt = -k(60 - 80)
Simplifying the equation, we get:
-30k = dT/dt
Integrating both sides, we have:
∫-30k dt = ∫ dT
-30kt + C1 = T
Since the initial temperature of the lead block was 30oF, we can substitute t = 0 and T = 30 into the equation:
-30k(0) + C1 = 30
C1 = 30
Therefore, the equation for the temperature of the lump after t minutes is:
T = -30kt + 30
To determine the temperature T after a specific time t, we need to know the value of k.
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If you slide a box across the floor, it produces friction. The friction generates thermal energy. Which object/s would be warmer from the heat generated?
The temperature of the box and floor eventually rise as a result of the thermal energy flowing as heat inside these two things.
This is further explained below.
What is thermal energy?Generally, The energy present in a system that determines its temperature is referred to as thermal energy.
Thermal energy flows as heat. Thermodynamics is a whole field of physics that studies how heat is transmitted across various systems and how work is performed in the process (see the first law of thermodynamics).
In conclusion, This thermal energy is transferred in the form of heat throughout the box as well as the floor, which eventually results in an increase in temperature for both of these locations.
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A handball is hit toward a wall with a velocity of 14.3 m/s in the forward direction. It returns with a velocity of 13.5 m/s in the backward direction. If the time interval during which the ball is accelerated is 0.011 s, what is the handball's average acceleration?
Answer:
Let's define t = 0 as the moment when the ball hits the wall.
in this moment, we have a given acceleration, but if we only want to calculate the average acceleration, then let's consider the acceleration constant.
a(t) = A.
To find the velocity equation we should integrate, and the constant of integration will be the initial velocity, in this case, is 14.3m/s.
v(t) = A*t + 14.3m/s
Now we know that at t = 0.011s, the velocity is -13.5m/s (the sign is negative because the ball is moving in the opposite direction as before).
Then we can solve the equation:
v(0.011s) = -13.5m/s = A*0.011s + 14.3m/s
Now we can solve it for A, the average acceleration:
-13.5m/s - 14.3m/s = A*0.011s
(-27.8m/s)/0.011s = A = -1313.5 m/s^2
a copper telephone wire has essentially no sag between poles 35.0 m apart on a winter day when the temperature is 220.08 c. how much longer is the wire on a summer day when the temperature is 35.08 c ?
The stretching of the wire will be more in higher temperatures. The length of the telephone wire at a temperature of 35.08° C is 5.57 m.
What is thermal stretching?Objects under high temperature undergo thermal vibrations and the particles moves apart by gaining thermal energy. This leads to a stretching in the size of the object called the thermal stretching.
The thermal stretching or the change in length is thus, directly proportional to the temperature. Hence, for a length of l1 and temperature T1 and length l2 at a temperature T2 can be written as follows:
l1/T1 = l2/T2
l1 T2 = l2 T1.
Given T1 = 228.08 ° C
l1 = 35.08 m
T2 = 35.08 ° C
then, l2 = (35.0 m × 35.08 ° C) / 228.08 ° C
= 5.57 m
Therefore, the length of the telephone wire at 35.08 ° C will be 5.57 m.
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A projectile is launched from level ground at a launch angle of 26 and an initial speed of 48 m/sec. How far away from the launch point does the projectile hit the ground? Assume the x-axis is horizontal, the positive y-axis is vertical (opposite g), the ground is horizontal, and only the gravitational force acts on the objects. Round to the nearest integer.
The projectile will land approximately 37 meters from the launch point.
The projectile motion is a form of motion in which an object or a particle is projected into the air and travels along a path. It is a type of motion that is heavily influenced by gravitational force.
When a projectile is launched, it will follow a parabolic path.
The following formula can be used to determine how far the projectile travels horizontally:
x=vtcosθ
Where: x = the horizontal displacement (meters, m)v = the initial velocity (m/s)t = the time (s)θ = the launch angle (degrees)
Using the above equation, we can solve the given problem. Given:
v = 48 m/ s
θ = 26°
Let's first convert the angle to radians:
θ = 26° × (π / 180°) = 0.4536 rad
We can now solve for x:
x = vt cosθ = (48 m/s)(cos 0.4536 rad)
x = 36.59 meters
Therefore, the projectile will land approximately 37 meters from the launch point. The final answer will be 37 meters.
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two different r resistors in parallel always have the same ____________; two resistors in series always have the same ______________.
Answer:two different r resistors in parallel always have the same U; two resistors in series always have the same I.
Explanation:
If two different r resistors in parallel always have the same voltage or potential difference across them and if two resistors in series always have the same electric current passing through them .
What is resistance?Resistance is the obstruction of electrons in an electrically conducting material .
The mathematical relation for resistance can be understood with the help of the empirical relation provided by Ohm's law .
V = I × R
The voltage is the same if the resistance is connected in a parallel arrangement .
The current is the same if the resistance is connected in a series arrangement .
Thus , If the voltage or potential difference across two separate resistors connected in parallel is always the same, as well as the electric current flowing through two resistors connected in series .
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Question 2
1
Without gravity, the stars, planets and all celestial objects in the universe would
Answer:
fly apart
Explanation:
gravity holds everything in place by constantly attracting both of the objects
without gravity, the objects would not be attracted anymore. Hence, they fly apart.
1 A grandfather clock uses energy stored in raised weights. The weights transfer energy to the clock mechanism as they fall. One clock has a 4.5 kg weight that supplies energy to the chimes (which play a few notes every 15 minutes), and two 3.5 kg weights that power the clock and the mechanism that strikes the hours.
For all questions on this sheet,
use g = 10 N/kg
a Calculate how much energy is stored when all three of these weights are raised by 70 cm. b How far does the 4.5 kg weight have to be lifted to store 45 J of energy?
2 The water tank in a house can hold 200 litres of water. The mass of 1 litre of water is 1 kg. The tank is 2 m above the bathroom taps and 5 m above the kitchen taps. The kitchen taps are 1 m above the floor.
a
Calculate the gravitational potential energy (GPE stored in the water in the tank when it is full. State any assumptions made in your answer.
b Calculate the speed at which the water would come out of the bathroom taps and kitchen taps. You
may assume that no energy is transferred due to friction in the pipes.
3 The Victoria Falls in Africa is one of the world's largest waterfalls. Just over 1000 m° of water pass over the falls every second and fall approximately 100 m. 1 m3 of water has a mass of 1000 kg. a What mass of water goes over the falls every second? Give your answer in standard form.
b
Calculate the GPE of 1 kg of water at the top of the falls.
c If all the GPE stored in 1 kg of water is transferred to kinetic energy, calculate the speed of the water as
it reaches the bottom.
d Suggest why the water will not be falling as fast as your answer to part c suggests. e What is the total energy transferred per second as the GP stored in the water falling in one second is
transferred to other energy stores.
f Suggest the ways in which this energy is finally stored.
4 A post driver is used to drive fence posts into the ground. It is a hollow tube with a closed top, and handles on the side. A person fits the driver over a fence post, then lifts it up and lets it drop.
post driver
50 cm
a A post driver has a mass of 10 kg. Calculate the change in GPE stored when the post driver is lifted by 50 cm above the post, as shown in the diagram.
b
Calculate the speed of the driver when the end hits the post.
C
Explain how much extra energy is stored if the post driver is
fence post
lifted by 1 metre instead of only 50 cm.
d Calculate the speed of the post driver after it falls for 1 m. e A new design of post driver has a mass of 15 kg. Suggest one advantage and one disadvantage of this new design.
Extra challenge
5 F The post driver in question 4a stops in
0.5 seconds when it hits the fence post.
a Calculate the force needed to bring the post driver to a stop. (Hint: use your answer to 4b.)
The momentum of a moving object is the product of its mass and its velocity. The force needed to stop a moving object depends on how fast its momentum changes.
force = change in momentum
=
mv - mu
time
t
b What provides this force?
c Explain how your answer might be different it the post were being sunk into very soft ground,
F = force (N)
u = initial velocity (m/s)
te time (s)
m = mass (kg)
v = final velocity (m/s)
1a) The total energy stored when all three weights are raised by 70 cm is 80.5 J.
1b) The height of the tank is 2 m.
2b) The potential energy is converted into kinetic energy when the water flows out of the taps 6.32 m/s.
3a) The mass of water that goes over the falls every second is 1 x 10⁶ kg.
3b) The gravitational potential energy of 1 kg of water at the top of the falls 1000 J.
3c) The speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy is 44.72 m/s.
3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.
3e) The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.
1a) To calculate the amount of energy stored in the three weights, we use the formula given below:
E = mgh
Where,E = Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
For the 4.5 kg weight:
E = 4.5 x 10 x 0.7 = 31.5 J
For each of the 3.5 kg weight:
E = 3.5 x 10 x 0.7 = 24.5 J
Thus, the total energy stored when all three weights are raised by 70 cm is:
31.5 J + 24.5 J + 24.5 J = 80.5 J
1b) To calculate how far the 4.5 kg weight must be lifted to store 45 J of energy, we use the formula:
E = mghh = E/mg = 45 / (4.5 x 10) = 1 m2a)
To calculate the gravitational potential energy stored in the water in the tank when it is full, we use the formula given below:
E = mgh
Where,E = Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
The mass of 1 litre of water is 1 kg and the tank can hold 200 litres of water. Therefore, the total mass of water in the tank is:
Mass = 200 kg
The height of the tank is 2 m.
Therefore, the gravitational potential energy stored in the water in the tank is:
E = mgh = 200 x 10 x 2 = 4000 J
Assumptions made in the answer:
We have assumed that the tank is full.
2b) To calculate the speed at which the water would come out of the bathroom and kitchen taps, we use the formula given below:
PE = KEPE = mghKE = 1/2mv²
Where,PE = Potential Energy (Joules)
KE = Kinetic Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
v = Velocity (m/s)
Assuming that the potential energy of the water in the tank is converted into kinetic energy when the water flows out of the taps, the potential energy stored in the water in the tank is given by:
PE = mgh = 200 x 10 x 2 = 4000 J
The potential energy is converted into kinetic energy when the water flows out of the taps.
Therefore, KE = 1/2mv²v² = 2KE/mv² = 2(4000)/200 = 40 m²/s²v = √(40) = 6.32 m/s (speed of the water coming out of the taps)
3a) To calculate the mass of water that goes over the falls every second, we use the formula given below:
Mass = Volume x Density
Where,Volume = 1000 m³/s, Density = 1000 kg/m³, Mass = 1000 x 1000 = 1000000 kg = 1 x 10⁶ kg
3b) To calculate the gravitational potential energy of 1 kg of water at the top of the falls, we use the formula:
E = mgh
Where,m = 1 kg, g = 10 N/kg, h = 100 m, E = 1 x 10 x 100 = 1000 J
3c) To calculate the speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy, we use the formula given below:
PE = KEP
E = mgh
KE = 1/2mv²
Where,PE = Potential Energy (Joules)
KE = Kinetic Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
v = Velocity (m/s)
Assuming that all the potential energy is converted into kinetic energy when the water reaches the bottom,
PE = KEKE = mghv² = 2mghv² = 2(1)(10)(100)v² = 2000v = √(2000) = 44.72 m/s
3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.
3e) To calculate the total energy transferred per second as the GPE stored in the water falling in one second is transferred to other energy stores, we use the formula given below:
Power = Energy / Time
Where,Power = 1 x 10⁶ x 10 x 100 = 1 x 10⁹ W = 1 GW (assuming that 1 m³ of water falls every second)3f)
The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.
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Two steel cylindrical rods a and b (same material) with the same length l, and the diameter da =2 db. assume that these two rods are under the same normal stress, then:__________
If the two steel cylindrical rods, A and B, have the same length (l) and the diameter of rod A (da) is twice the diameter of rod B (db), and they are subjected to the same normal stress, then the stress acting on rod A will be twice the stress acting on rod B.
The stress experienced by a cylindrical rod is given by the formula stress = force/area. In this case, since both rods have the same length (l) and are made of the same material, the force applied to each rod will be the same.
However, the area of rod A (π(da/2)^2) is four times the area of rod B (π(db/2)^2) because the diameter of rod A is twice the diameter of rod B. Therefore, when the same force is applied, the stress acting on rod A will be four times the stress acting on rod B.
In conclusion, if the two steel cylindrical rods have the same length and the diameter of rod A is twice the diameter of rod B, and they are subjected to the same normal stress, the stress on rod A will be twice the stress on rod B.
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a 1150-kg car is held in place by a light cable on a very smooth (frictionless) ramp. what is the tension the cable?
The tension in the cable is also 11,269.5 N.
Since the ramp is frictionless, the only force acting on the car is its weight which is given by:
W = m×g
where m is the mass of the car and g is the acceleration due to gravity (approximately 9.81 m/s²). Substituting the values, we get:
W = 1150 kg×9.81 m/s² = 11,269.5 N
Since the cable is holding the car in place, it must be exerting an equal and opposite force (tension - it is also a force) to counteract the weight of the car.
Therefore, the tension in the cable is also 11,269.5 N.
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Find the deceleration of
a cyclist who comes to
rest from 10m/s in 2
seconds.
Answer:
-5 m/s^2
Explanation:
10/2=5 and is is a stop so it is negitive
qa cprojectile lands at the same height from which it was alunched. which initial velocoti will result in the greates horrizontal displacement of the projectile. neglect firction
The initial velocity will result in the greates horrizontal displacement of the projectile. neglect firction is Option C.
The horizontal velocity of the projectile is constant. There is a vertical acceleration due to gravity with a value of 9.8 m/s/s down. The projectile's vertical velocity changes at 9.8 m/s per second. The horizontal movement of the projectile is independent of vertical movement.
At its highest point, the vertical velocity is zero. As the object falls toward the Earth its vertical velocity increases again but points in the opposite direction to its initial vertical velocity. The initial horizontal velocity can also be determined by measuring the diameter d of the sphere and dividing it by the time t it takes for the sphere to move across the photogate.
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If a car is going 60 MPH in 2.2 seconds, What is the acceleration of that car?
Answer 0-60=2.2sec
Explanation:
A 100 kg steel beam is being lifted by a crane to the top of 15 meter building. How much Potential Energy is in the steel be a m when it reaches the top of the building.
You are gardening in the peak of summer, it hasn't rained in a week, and your plants are looking rough. You decide to water the plants for an hour. The next day you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. With what you know from class, please try and explain what is happening to your plants.
In the peak of summer, it hasn't rained in a week, and the plants are looking rough, so watering the plants for an hour is a good idea.
However, the next day, you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. Plants absorb water through their roots. The root system of a plant is responsible for drawing water and nutrients from the soil. A plant's root system must be able to absorb water quickly in order for the plant to grow and thrive. When the soil around the root system is dry, the roots will stop growing and will not be able to absorb water.
It may even start to die. Watering plants during the peak of summer is important because it will help keep the soil moist and prevent the roots from drying out. However, watering a plant too much can be harmful. If a plant is overwatered, the water may not be able to penetrate the soil and reach the roots. Instead, it may just sit on top of the soil, causing the roots to rot and die. This can cause the plant to wilt and die.To summarize, if the soil around the plant is too dry, the roots may not be able to absorb the water you gave them, causing the plant to look worse than before. Conversely, overwatering can also be harmful because the water may not be able to penetrate the soil and reach the roots, causing the roots to rot and die.
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what element is chemically similar to Krypton?
Answer:
Nobel gases
Explanation:
Well since Krypton is in a group called the “Noble Gases”, then Krypton is similar to the others; Xenon, Helium, Neon, Argon, and Radon.
An element that is unable to create a ion and therefore always has a charge of 0 is most likely a member of a family called
Explanation:
'noble gases' which are also known as group VIII
the average earth–sun distance is 1.00 astronomical unit (au). at how many aus from the sun is the intensity of sunlight 1/4 the intensity at the earth? au
The intensity of sunlight is 1/4 at a distance of approximately 2 astronomical units (au) from the Sun compared to Earth.
The intensity of sunlight follows the inverse square law, which states that the intensity decreases as the square of the distance increases. If we consider Earth as the reference point with an intensity of 1, we can calculate the distance at which the intensity drops to 1/4.
Let's assume that x is the distance in astronomical units (au) from the Sun where the intensity is 1/4. According to the inverse square law, we can set up the following equation:
\(\( \left(\frac{1}{4}\right) = \left(\frac{1}{x}\right)^2 \)\)
Simplifying the equation, we have:
\(\( \frac{1}{4} = \frac{1}{x^2} \)\)
Cross-multiplying, we get:
\(\( x^2 = 4 \)\)
Taking the square root of both sides, we find:
\(\( x = 2 \)\)
Therefore, at a distance of approximately 2 astronomical units (au) from the Sun, the intensity of sunlight is 1/4 the intensity at Earth.
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100 POINTS PLEASE HELP I NEED A GOOD GRADE DESPERATELY TO PASS!!!
Answer:
set A is showing the same position in both graphs
Answer:
B
Explanation:
The answer is B.
I'm positive it's B
What is the definition of period in physics
In your own words
Answer:
Period refers to the time that it takes to do something. ... The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.
Which phase of cell division is shown?
Exploring meiosis.
A. metaphase
B. prophase
C. anaphase
D. telophase
Answer:
Anaphase
Explanation:
This is because the spindle fibres have shortened and is pulling the chromatids towards the poles of the cell. The chromatids have also separated.
The cell division which is shown in the picture is anaphase. The correct option is C.
What are the phases of meiosis?Meiosis is divided into two main phases, each with its own set of subphases:
1 Meiosis I:
a. Prophase I: This is the longest and most complex phase of meiosis. During this phase, homologous chromosomes pair up and form bivalents, and crossing over occurs between the homologous chromosomes. The nuclear envelope breaks down, and spindle fibers form from the centrioles at opposite poles of the cell.
b. Metaphase I: During this phase, the homologous chromosomes line up along the metaphase plate, with one chromosome from each homologous pair facing each pole of the cell.
c. Anaphase I: During this phase, the spindle fibers contract and pull the homologous chromosomes towards opposite poles of the cell.
d. Telophase I: During this phase, the chromosomes reach the poles of the cell and the nuclear envelope reforms around each set of chromosomes. The cell then undergoes cytokinesis, resulting in two daughter cells.
2. Meiosis II:
a. Prophase II: During this phase, the nuclear envelope breaks down, and spindle fibers form from the centrioles at opposite poles of the cell.
b. Metaphase II: During this phase, the chromosomes line up along the metaphase plate, with sister chromatids facing opposite poles of the cell.
c. Anaphase II: During this phase, the spindle fibers contract and pull the sister chromatids towards opposite poles of the cell.
d. Telophase II: During this phase, the chromosomes reach the poles of the cell and the nuclear envelope reforms around each set of chromosomes. The cell then undergoes cytokinesis, resulting in four haploid daughter cells.
Meiosis involves two rounds of chromosome segregation, resulting in four haploid daughter cells that are genetically distinct from the parent cell.
Therefore, The correct option is C i.e anaphase.
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Question 7 of 20 A permanent magnet is placed in a coil of wire. If there is no electric current in the wire, which statement must be true? A. The magnet is moving relative to the wire. B. The magnet is not moving relative to the wire. C. The magnet is longer than the coil of wire. D. The magnet is shorter than the coil of wire.
Answer:
the magnet is not moving relative to the wire so B
Explanation:
The magnet is not moving relative to the wire if, A permanent magnet is placed in a coil of wire, If there is no electric current in the wire so, option B is correct.
What is current?Electric current is a term used to describe how much electricity flows across a circuit and how it flows in an electronic circuit. Amperes are used to measure it (A). The more electricity flowing across the circuit, the higher the ampere value.
When current flows through a coil of wire, it transforms into an electromagnet. The coil spins as a result of the electromagnet's interaction with a permanent magnet.
An electromagnet is created when current passes through a coil of wire. Because of the electromagnet's interaction with a permanent magnet, the coil spins.
Thus, The magnet is not moving relative to the wire.
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PLEASE HELP Due Soon!
What are two examples of chemical energy being transformed?
Answer:
Hope I can help you.
Explanation:
Here u go here are some that you can choose from! :)
1) Air bags are activated by a chemical reaction inside the bag. A sensor turns on an electrical circuit, and then sodium azide is ignited. The reaction that occurs generates nitrogen gas, which fills the bag at an extremely rapid rate.
2) Baking soda and vinegar produce carbon dioxide gas when mixed. As this gas grows in volume, it puts pressure on whatever container it is in, and will erupt out of an opening in the container, creating a volcano effect. This chemical reaction is safe, making it a great science activity for kids.
3) Batteries have two terminals: the anode and the cathode. They're separated by an electrolyte, a chemical that allows the anode and cathode to transmit a charge. When something's connected to a battery, chemical reactions take place along the electrodes to produce electricity. Of course, you can't see the energy in the battery when the battery is just sitting around; it is when the electricity is produced that the energy is seen.
4) Explosives: when an explosive goes off, chemical energy that was stored in it is changed and transferred into sound energy, kinetic energy, and thermal energy. Just because chemical energy is being released, it doesn't mean an explosion will occur. But, when a solid material quickly changes into a hot, expanding gas, you may be looking at an explosion. Take TNT, for example. Two units of solid TNT can instantly change into 15 units of hot gas, creating a dark and sooty explosion.
5) Food: chemical energy in food is released when the food is digested and the molecules of food are broken down into smaller pieces. Our bodies digest food by mixing it with acids and enzymes in the stomach. This process turns carbohydrates into glucose. The stomach (and small intestine) then release that glucose into the bloodstream, serving as energy for our bodies.
6) Heating packs (used to warm up cold hands or soothe sore muscles) have chemicals inside them. A lot of them function by "cracking" (or bending) them. This is because they're filled with iron. Once you crack the heating pack, the iron is exposed to the air. As the iron reacts to the oxygen, it transforms into iron oxide, a chemical that can produce heat.
7) Wood, when dry, stores chemical energy. This chemical energy is released as the wood burns, and it is converted into heat, or thermal energy. This also produces light energy. As a result of burning, the wood turns into an entirely new substance - ashes.
a liquid of density 1457 kg/m3 flows through two horizontal sections of tubing joined end to end. in the first section the cross-sectional area is 4.36 cm2 , the flow speed is 3.4 m/s, and the pressure is 167 kpa . in the second section the cross-sectional area is 2.89 cm2.
A. Assume incompressible flow
Since volumtric flow rate will be same in both section
Q1 = Q2
A1*V1 = A2*V2
V2 = A1*V1/A2
V2 = 6.9*10^-4*288*10^-2/(3.3*10^-4)
V2 = 6.02 m/sec
B. using bernoulli's equation:
P1/rho + v1^2/2 + g*h1 = P2/rho + v2^2/2 + g*h2
Since pipes are horizontal
h1 = h2
P1/rho + v1^2/2 = P2/rho + v2^2/2
P2 = P1 + (v1^2 - v2^2)*rho/2
P2 = 1.5*10^5 + (2.88^2 - 6.02^2)*1100/2
P2 = 1.35*10^5 Pa
The rate of change in position of an object in any course. Speed is measured because the ratio of distance to the time wherein the distance became included. Speed is a scalar amount because it has handiest route and no significance.
Velocity can be notion of as the rate at which an object covers distance. A quick-moving object has a high speed and covers a notably big distance in a given amount of time, whilst a sluggish-shifting item covers a relatively small amount of distance in the same amount of time.
The primary unit or the S.I. unit of velocity is m/s or ms?¹.
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if the mass of object is 135 kg then its weight on earth will be?
Answer:
1323
Explanation:
we know ,
weight = m*g
= 135 * 9.8 ( acceleration due to gravity in earth is 9.8 m/S2)
= 1323 N
PLEASE HELP 50 AND BEST ANSWER
Begin by printing out a copy of the periodic table. Use the file attached to the assignment page or download the file from the Course Resources folder.
1. Label the rows as the electron energy levels.
2. Label the number of valence electrons in Columns 1,2, and 13-18.
3. Label the metals, semi-metals, and non-metals using different colors. Make sure you don't obscure any of the information about different elements by coloring.
4. Label the ion charges for elements in the first 3 rows. Remember all the elements in Columns 1,2,16,17,18 will always have the same charge. Elements in Columns 13,14, or 15 can have different charges within the same row it's especially useful to write these charges on your periodic table. --
5. Label the trends for atomic size, ionization energy, and electron affinity.
Label the rows as the electron energy levels:
The rows of the periodic table are also known as periods. There are seven periods, and each period corresponds to a particular energy level. You can label them from 1 to 7, starting from the top row.
What are the responses to other questions?Label the number of valence electrons in Columns 1, 2, and 13-18:
Columns 1 and 2 are the s-block elements, and they have 1 and 2 valence electrons, respectively. Columns 13-18 are the p-block elements, and they have 3 to 8 valence electrons, respectively. You can label the number of valence electrons in each column.
Label the metals, semi-metals, and non-metals using different colors:
Metals are on the left side of the periodic table, semi-metals are in the middle, and non-metals are on the right side. You can use different colors to label them without obscuring any of the information about different elements.
Label the ion charges for elements in the first 3 rows:
Elements in the first 3 rows of the periodic table have predictable ion charges. The alkali metals (Group 1) have a charge of +1, the alkaline earth metals (Group 2) have a charge of +2, and the elements in Group 13 have a charge of +3. For Groups 15, 16, and 17, the charges are -3, -2, and -1, respectively. The noble gases (Group 18) are unreactive and do not form ions. You can write these charges for each element in their respective positions.
Label the trends for atomic size, ionization energy, and electron affinity:
Atomic size generally decreases from left to right across a period and increases from top to bottom within a group. Ionization energy generally increases from left to right across a period and increases from bottom to top within a group. Electron affinity generally increases from left to right across a period and becomes less negative from top to bottom within a group. You can label these trends on your periodic table as well.
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A 76g ball is attached to a string that is 1.5m long. It is spun so that it completes two full rotations every second. What is the centripetal acceleration felt by the ball? m/s2
What is the Force tension on the string? N
The centripetal acceleration = 236.63 m/s²
The force = 17.98 N
Further explanationGiven
mass = 76 g = 0.076 kg
r = 1.5 m
f = 2 rps = 2 rotation per second
Required
The centripetal acceleration
The Force tension
Solution
Centripetal force is a force acting on objects that move in a circle in the direction toward the center of the circle
\(\large {\boxed {\bold {F = \frac {mv ^ 2} {R}}}\)
F = centripetal force, N
m = mass, Kg
v = linear velocity, m / s
r = radius, m
The speed that is in the direction of the circle is called linear velocity
Can be formulated:
\(\tt \displaysyle v = 2 \pi.r.f\)
r = circle radius
f = rotation per second (RPS)
The linear velocity : 2 x 3.14 x 1.5 x 2 =18.84 m/s
The centripetal acceleration : ac = v²/R = 236.63 m/s²
The force : F = m x ac = 0.076 x 236.63 = 17.98 N