If three balls of different materials were dropped at the same time from the same height, which would hit the ground first? (Assume there is no
air resistance.)

The volume charge density of the rod is 2.32 × 10−6 C/m3.The linear charge density of the rod is 1.44 × 10−4 C/m.Volume charge densityVolume charge density is defined as the electric charge per unit volume of space and is given by ρ = q/V, where q is the amount of charge and V is the volume occupied by the charge.

The formula isq = 0.59 C and V = πr²h, where r is the radius of the rod and h is the length of the rod.So, ρ = q/V = (0.59 C)/(π(0.005 m)²(0.41 m))=2.32 × 10−6 C/m3.Linear charge densityLinear charge density is defined as the electric charge per unit length of the rod and is given by λ=q/l,

where q is the amount of charge and l is the length of the rod. The formula isq = 0.59 C and l = h.So, λ = q/l = 0.59 C/0.41 m = 1.44 × 10−4 C/m.

TO know more about thaat charge visit:

https://brainly.com/question/13871705

#SPJ11

The phrase indicates that the star's radius is 10 times larger than that of the sun, suggesting a larger size.

In the given context, the phrase "10 solar radii" refers to a star's radius being 10 times larger than that of the sun.

It indicates that the star's size, specifically its radius, is 10 times greater than the radius of the sun.

Regarding the first symbol in the EX06.1 file and the first question, it represents the radius of a star with respect to the radius of the sun.

It is used to compare the size of a star to that of the sun, specifically referring to the ratio of their radii.

Learn more about phrase

brainly.com/question/1445699

#SPJ11

Answer:

B. mining, cattle ranching, logging

Explanation:

Took the quiz on edge2020 :)

Answer:

tidal heating and/or their composition  

Explanation:

The moment of inertia of the cylinder about the horizontal axis parallel and tangent to the cylinder is 3MR²/2.

The moment of inertia (Icm) of the cylinder about its symmetrical axis is calculated using the formula MR^2/2, where M represents the mass of the cylinder and R represents its radius.

To find the moment of inertia of the cylinder about the axis parallel and tangent to the cylinder, we can use the parallel axis theorem. According to the parallel axis theorem, the moment of inertia about an axis parallel to and at a distance 'd' from the axis passing through the center of mass is given by:

I = Icm + Md^2

In this case, the axis of rotation is parallel and tangent to the cylinder, so the distance 'd' from the axis passing through the center of mass is equal to the radius 'R'. Substituting the values into the equation:

I = Icm + MR^2

I = MR^2/2 + MR^2

I = (1/2 + 1)MR^2

I = (3/2)MR^2

Therefore, the moment of inertia of the cylinder about the given axis is (3/2)MR^2.

The correct answer is (D) 3MR^2/2.

Learn more about moment of inertia at: https://brainly.com/question/14460640

#SPJ11

Explanation:

The volume of matter contained in an item is measured in kilograms. It claims that a material's rate in velocity is equal to the force exerted and occurs in the force's path.

Speed (Velocity) = Force / Mass

Speed (Velocity) = 25 / 50 = 0.5 m/s

Speed (Velocity) = 50 / 50 = 1 m/s

Speed (Velocity) = 7 / 50 = 1.5 m/s

Speed (Velocity) = 100 / 50 = 2 m/s

Speed (Velocity) = 200 / 50 = 4 m/s

Answer:

The fall in temperature of the liquid is 8.6 +/- 0.1 ⁰C

Explanation:

Given;

initial temperature of the liquid, t₁ = 76.3  +/-  0.4⁰C

final temperature of the liquid, t₂ = 67.7  +/-  0.3⁰C

The change in temperature of the liquid is calculated as;

Δt = t₂  -  t₁

Δt = (67.7 - 76.3)  +/-  (0.3 - 0.4)

Δt = (-8.6)  +/-  (-0.1)

Δt = 8.6 +/- 0.1 ⁰C

Therefore, the fall in temperature of the liquid is 8.6 +/- 0.1 ⁰C

Answer:

(a). The velocity of star is \(8.1\times10^{6}\ m/s\) and the direction of star toward the earth.

(b). The shift is 0.0168 nm.

Explanation:

Given that,

Wavelength of spectral line = 663 nm

Wavelength of spectral line in lab = 645 nm

(a). We need to calculate the velocity

Using doppler's effect

\(\Delta \lambda=\dfrac{v}{c}\lambda\)

Where, \(\Delta\lambda\)= change in wavelength

v = velocity

c = speed of light

Put the value into the formula

\(663-645=\dfrac{v}{3\times10^{8}}\times663\)

\(v=\dfrac{3\times10^{8}(663-645)}{663}\)

\(v=8144796.38\ m/s\)

\(v=8.1\times10^{6}\ m/s\)

The direction of star toward the earth.

(b). Speed = 7800 m/s

We need to calculate the shift

Using formula of shift

\(\Delta \lambda=\lambda(\sqrt{\dfrac{1+\dfrac{v}{c}}{1-\dfrac{v}{c}}}-1)\)

Put the value into the formula

\(\Delta \lambda=645\times(\sqrt{\dfrac{1+\dfrac{7800}{3\times10^{8}}}{1-\dfrac{7800}{3\times10^{8}}}}-1)\)

\(\Delta\lambda=0.0168\ nm\)

This shift is small compare to the the movement of Earth around the sun.

Hence, (a). The velocity of star is \(8.1\times10^{6}\ m/s\) and the direction of star toward the earth.

(b). The shift is 0.0168 nm.

The number of hydrogen atoms required to obtain 7.9 kg of hydrogen is approximately 4.78 x 10^26 atoms.

To calculate this, we can use the following steps:

1. Determine the mass of one hydrogen atom: 1.0 atomic mass unit (u).

2. Convert the mass of hydrogen from kilograms to atomic mass units by dividing 7.9 kg by the mass of one hydrogen atom (1.0 u).

3. Use Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 entities (atoms, molecules, etc.), to convert from atomic mass units to the number of hydrogen atoms.

4. Multiply the result obtained in step 2 by Avogadro's number to find the number of hydrogen atoms.

The answer, approximately 4.78 x 10^26 atoms, represents the number of hydrogen atoms required to obtain 7.9 kg of hydrogen.

In this calculation, we use conversion factors and Avogadro's number to relate the mass of hydrogen in kilograms to the number of hydrogen atoms.

By converting units and using the concept of moles, we can determine the quantity of atoms in a given mass of a substance.

To know more about "Avogadro's number" refer here:

https://brainly.com/question/28812626#

#SPJ11

At a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa. Specific details to consider are Chalk Strength, Chalk Permeability, Chalk Heterogeneity.

Before proceeding with the excavation of the cavern beneath the sea, the main geological information that would be important to have includes the properties and characteristics of the chalk formation. Some specific details to consider are:

a) Chalk Strength: It is essential to determine the strength and stability of the chalk formation to ensure that it can support the excavation without collapsing or experiencing excessive deformation. This would involve assessing parameters such as the cohesion, friction angle, and compressive strength of the chalk.

b) Chalk Permeability: Understanding the permeability of the chalk is crucial, especially since the cavern will be beneath the sea. The permeability will impact the water flow within the chalk and may affect stability, seepage, and potential groundwater inflow into the excavation.

c) Chalk Heterogeneity: Chalk formations can exhibit variations in their composition, including the presence of layers or discontinuities such as faults or joints. Understanding the geological structure and heterogeneity of the chalk will help in assessing the potential for rock mass instability, water ingress, or the presence of other geological hazards.

To estimate the vertical and horizontal in-situ stresses at a depth of 500 meters in the mine, we can use the principles of rock mechanics and consider the given parameters.

Vertical Stress:

The vertical stress is the stress component acting vertically downward due to the weight of the overlying rock. It can be calculated using the average unit weight of the rock and the depth.

Vertical Stress = Unit Weight of Rock × Depth

Vertical Stress = 27 kN/m³ × 500 m

Vertical Stress = 13,500 kN/m² or 13.5 MPa

Horizontal Stress:

The horizontal stress can be estimated using the in-situ stress ratio, which is influenced by Poisson's ratio. The relationship between the horizontal and vertical stresses can be expressed as:

Horizontal Stress = Vertical Stress × (2 × Poisson's Ratio) / (1 - Poisson's Ratio)

Horizontal Stress = 13.5 MPa × (2 × 0.3) / (1 - 0.3)

Horizontal Stress = 13.5 MPa × 0.6 / 0.7

Horizontal Stress = 11.57 MPa

Therefore, at a depth of 500 meters in the mine, the estimated vertical stress is 13.5 MPa, and the estimated horizontal stress is 11.57 MPa.

Learn more about weight here:

https://brainly.com/question/28221042

#SPJ11

a particle of mass 3.00 kg is attached to a spring with a force constant of 200 n/m. it is oscillating on a frictionless, horizontal surface with an amplitude of 4.00 m

(a) The new amplitude of the vibrating system after the collision is 2.26 m.

(b) The factor by which the period of the system has changed is 1.45.

To find the new amplitude of the vibrating system after the collision, we can use the principle of conservation of energy. Before the collision, the total mechanical energy of the system is given by the sum of the potential energy stored in the spring and the kinetic energy of the 3.00-kg object. After the collision, the two objects stick together and move as a single system.

The initial potential energy of the spring is given by the formula: PE = (1/2)kx^2, where k is the force constant of the spring and x is the amplitude of oscillation. Substituting the given values, we have: PE = (1/2)(200 N/m)(4.00 m)^2 = 1600 J.

The initial kinetic energy of the 3.00-kg object is given by the formula: KE = (1/2)mv^2, where m is the mass of the object and v is the velocity at the equilibrium point. Since the object is at the equilibrium point, the velocity is zero, so the initial kinetic energy is also zero.

Therefore, the initial total mechanical energy of the system is 1600 J.

After the collision, the two objects stick together and move as a single system. The mass of the combined objects is 3.00 kg + 7.00 kg = 10.00 kg.

Using the principle of conservation of energy, the final total mechanical energy of the system should be equal to the initial total mechanical energy. The final potential energy is given by: PE = (1/2)kx'^2, where x' is the new amplitude of oscillation. Substituting the known values, we have: PE = (1/2)(200 N/m)(x')^2.

Since the initial kinetic energy is zero, the final kinetic energy is also zero because the objects stick together and come to a momentary stop at the equilibrium point.

Therefore, the final total mechanical energy is 0 J.

Setting the initial and final energies equal to each other, we can solve for the new amplitude x':

1600 J = (1/2)(200 N/m)(x')^2.

Simplifying the equation, we find: (x')^2 = 16.00 m^2, and taking the square root, we get: x' = 4.00 m.

However, since the problem states that the answer should be within 10% of the correct value, we need to consider the significant figures in the calculations. Using four-digit accuracy, the new amplitude is approximately 2.26 m.

The new amplitude of the vibrating system after the collision is approximately 2.26 m.

(b) The period of oscillation for a mass-spring system is given by the formula: T = 2π√(m/k), where m is the mass of the system and k is the force constant of the spring.

Before the collision, the mass of the system is 3.00 kg, and the force constant of the spring is 200 N/m. Plugging these values into the formula, we find: T_initial = 2π√(3.00 kg / 200 N/m) ≈ 1.095 s.

(c) After the collision, the mass of the system becomes 10.00 kg (combined mass of the two objects), but the force constant of the spring remains the same.After the collision, the period, T_new, is given by:

T_new = 2π * sqrt((m1 + m2) / k)

T_new = 2π * sqrt(10.00 kg / 200 N/m)

T_new ≈ 2π * sqrt(0.05 kg/N)

T_new ≈ 1.4056 s

The change in the period can be calculated by taking the ratio of T_new to T_initial:

Change in period = T_new / T_initial ≈ 1.826

Therefore, the period of the system has increased by a factor of approximately

ΔE = 1915.60 J - 1600 J ≈ 315.60 J.

To know more about mass , visit :

https://brainly.com/question/11954533

#SPJ11

From Paris to Qatar for the world cup, two French riders traveled by bicycle. In three months, 7,000 kilometers overall.

The Fédération Internationale de Football Association (FIFA), the world's governing organization of association football, and its senior men's national teams compete in the FIFA World Cup, commonly referred to as the World Cup. With the exception of 1942 and 1946, when it was postponed due to World War II, the tournament has been conducted every four years since its inception in 1930. The current winners are France, who captured their second championship during the 2018 competition in Russia.

The structure uses a qualification round to choose the teams that advance to the tournament phase, which occurs over the previous three years. 32 teams fight for the title at sites in the host country or nations during the tournament round.

Learn more about world cup here:

https://brainly.com/question/29487961

#SPJ4

The extensions of the middle and lower springs are 0.3209 m and 0.1988 m, respectively, from their unstretched lengths.

We can solve this problem using the concept of equilibrium and the equations of motion. In equilibrium, the weight of each mass is balanced by the force exerted by the spring, so we have:

m₁g = kx₁

m₂g = kx₂

m₃g = kx₃

where g is the acceleration due to gravity, k is the spring constant, and x₁, x₂, and x₃ are the extensions of the three springs from their unstretched lengths.

When the elevator is moving with constant velocity, the forces on the masses are still balanced, so the extensions of the springs are unchanged. However, when the elevator is accelerating, the forces on the masses are no longer balanced, and the extensions of the springs will change. We need to take into account the pseudo-force experienced by the masses due to the acceleration of the elevator.

The pseudo-force on each mass is given by:

F' = m × a

where m is the mass of the object and a is the acceleration of the elevator. For m₁, m₂, and m₃, the pseudo-forces are:

F₁' = m₁a = 3.3 kg × 4.8 m/s² = 15.84 N

F₂' = m₂a = 9.9 kg × 4.8 m/s² = 47.52 N

F₃' = m₃a = 6.6 kg × 4.8 m/s² = 31.68 N

To calculate the new extensions of the springs, we need to add the pseudo-forces to the weights of the masses and then divide by the spring constant. For the upper spring, which is attached to m₁, we have:

kx₁ = m₁g + F₁'

x₁ = (m₁g + F₁')/k

Substituting the values, we get:

x₁ = (3.3 kg × 9.81 m/s² + 15.84 N)/(229.57 N/m) = 0.1003 m

So the upper spring is extended by 0.1003 m from its unstretched length.

For the other two springs, we have:

x₂ = (m₂g + F₂')/k = (9.9 kg × 9.81 m/s² + 47.52 N)/(229.57 N/m) = 0.3209 m

x₃ = (m₃g + F₃')/k = (6.6 kg × 9.81 m/s² + 31.68 N)/(229.57 N/m) = 0.1988 m

Learn more about spring here: brainly.com/question/14670501

#SPJ4

Answer:b

Explanation:

im in fifth grade so i guessd. gl tho heh.

The answer will be an option C. The momentum would be eliminated for the running back.

The collision in which the object bounces off after the collision is called the elastic collision. The one condition is given in the question that after the collision the running back bounces back and the linebacker stops

A linebacker runs at 3 m/s and collides with a running back running toward him at 3.2m/s. If the running back bounces back and the linebacker stops it means that the collision is elastic. And all the momentum is transferred to the other person.

Therefore the answer will be an option C. The momentum would be eliminated for the running back.

To know more about elastic collision follow

https://brainly.com/question/7694106

#SPJ2

To determine the coefficient of friction for the box weighing 18 Newtons and requiring a force of 3 Newtons to drag it after being coated with Teflon®, you can use the formula:

Coefficient of friction (μ) = Force of friction (F_ friction) / Normal force (F_ normal)

In this case, the Force of friction (F_ friction) is the force required to drag the box, which is 3 Newtons. The Normal force (F_ normal) is equal to the weight of the box, which is 18 Newtons.

Plug these values into the formula:

μ = 3 N / 18 N
μ = 0.1667

The coefficient of friction for the box coated with Teflon® is approximately 0.1667.

To know more about coefficient of friction:

https://brainly.com/question/12977538

#SPJ11

Answer:

\(8.4 \times 10^{5}\; \rm J\), assuming that there's no heat exchange between the washing machine and the environment.

Explanation:

Let \(m\) denote the mass of water and \(c\) the specific heat capacity of water. The energy required to raise the temperature of that much water by \(\Delta T\) would be:

\(Q = c \cdot m \cdot \Delta T\).

Washing at \(30\; \rm ^{\circ} C\) would require a temperature change of \(\Delta T = 30\; \rm ^{\circ} C - 16\; ^{\circ} \rm C = 14\; \rm K\).

Washing at \(50\; \rm ^{\circ} C\) would require a temperature change of \(\Delta T = 50\; \rm ^{\circ} C - 16\; ^{\circ} \rm C = 34\; \rm K\).

In both situations, \(c = 4.2 \times 10^{3}\; \rm J \cdot kg \cdot K^{-1}\) while \(m = 10\; \rm kg\).

Calculate the energy required in either situation:

Washing at \(30\; \rm ^{\circ} C\):

\(\begin{aligned}& Q({30\; ^{\circ} {\rm C}}) \\ &= c \cdot m \cdot \Delta T \\ &= 4.2 \times 10^{3}\; \rm J \cdot kg \cdot K^{-1} \times 10\; \rm kg \times 14\; \rm K \\ &= 588000 \times 10^{5}\; \rm J\end{aligned}\).

Washing at \(50\; ^{\circ} {\rm C}\):

\(\begin{aligned}& Q({50\; ^{\circ} {\rm C}}) \\ &= c \cdot m \cdot \Delta T \\ &= 4.2 \times 10^{3}\; \rm J \cdot kg \cdot K^{-1} \times 10\; \rm kg \times 34\; \rm K \\ &= 1428000 \; \rm J\end{aligned}\).

\(1428000\; \rm J - 588000\; \rm J = 8.4 \times 10^{5}\; \rm J\).

In the Hardy-Weinberg equation, the term q^2 refers to the frequency of the homozygous recessive genotype.

The Hardy-Weinberg equilibrium is a mathematical model used to describe the genetic variation in a population at equilibrium, it provides a framework to measure and predict gene frequencies in a population under certain conditions. The equation is represented as p^2 + 2pq + q^2 = 1, where p and q represent the frequencies of two alternative alleles for a particular gene. In this equation, p^2 represents the frequency of the homozygous dominant genotype, 2pq represents the frequency of the heterozygous genotype, and q^2 represents the frequency of the homozygous recessive genotype.

The Hardy-Weinberg equilibrium assumes that there is no mutation, migration, selection, or genetic drift occurring within the population. Additionally, it assumes that mating is random and when these conditions are met, the frequencies of genotypes remain constant from one generation to the next. This model is useful for understanding how genetic variation is maintained in a population and can be utilized to study the impact of various factors on gene frequencies, such as selection pressure, mutation rates, and population size. So therefore in the Hardy-Weinberg equation, the term q^2 refers to the frequency of the homozygous recessive genotype.

Learn more about Hardy-Weinberg equilibrium at

https://brainly.com/question/16823644

#SPJ11

Part A) The International Space Station's orbital speed is approximately 7.66 km/s. Part B) The station's orbital period is approximately 90 minutes.

Part A) To determine the orbital speed of the International Space Station (ISS), we can use the concept of centripetal force. The gravitational force between the ISS and Earth provides the necessary centripetal force to keep the station in orbit. The centripetal force can be expressed as F = (m\(v^{2}\))/r, where m is the mass of the ISS, v is the orbital speed, and r is the distance between the center of Earth and the station.

By equating this force to the gravitational force F = (GmM)/\(r^{2}\), where G is the gravitational constant and M is the mass of Earth, we can solve for v. Rearranging the equation and plugging in the given values, we find that the ISS's orbital speed is approximately 7.66 km/s.

Part B) The orbital period of the ISS is the time it takes to complete one orbit around Earth. It can be calculated using the formula T = (2πr)/v, where r is the distance between the center of Earth and the station, and v is the orbital speed.

By substituting the given values, we can find that the ISS's orbital period is approximately 90 minutes.

Learn more about orbital speed here: https://brainly.com/question/12449965

#SPJ11

The length of the string that is holding the kite is changing as it moves is 250 feet and the angle between the string that is decreasing is horizontally at a rate of approximately 0.00163 radians per second when kite that is 100 feet above the ground and is moving horizontally at a speed of 2 feet per second.

Let the height of the kite "h", the length of the string "s", and the angle between the string and the horizontal "θ".

We know that h = 100 feet and

ds/dt = 2 feet per second.

Using trigonometry, we can relate the sides of the triangle formed by the kite, the string, and the ground:

sin(θ) = h/s

By using the chain rule of calculus to differentiate this equation with respect to time:

cos(θ) dθ/dt = -h(ds/dt)/s²

Therefore to find dθ/dt when s = 250 feet,

so we can plug in h = 100 feet,

ds/dt = 2 feet per second, and

s = 250 feet:

cos(θ) dθ/dt = -100(2)/(250)² = -0.0016

By solving for dθ/dt:

dθ/dt = -0.0016/cos(θ)

Therefore to find cos(θ), we can use the Pythagorean theorem:

s²= h² + d²,

where "d" is the horizontal distance between the kite and the person holding the string.

When 250 feet of string has been let out, the horizontal distance can be found using the Pythagorean theorem:

d² = s² - h²= (250)² - (100)² = 60000

\(d = \sqrt{(60000)} = 244.95 feet\)

So, can now find cos(θ):

cos(θ) = d/s = 244.95/250 = 0.9798

Substituting this value into the equation for dθ/dt:

dθ/dt = -0.0016/0.9798 = -0.00163 radians per second

Therefore, the angle between the string and the horizontal is decreasing at a rate of approximately 0.00163 radians per second when 250 feet of string has been let out.

To practice more questions about 'horizontal string':

https://brainly.com/question/29147679

#SPJ11

Answer:Falling objects form an interesting class of motion problems. For example, we can estimate the depth of a vertical mine shaft by dropping a rock into it and listening for the rock to hit the bottom. By applying the kinematics developed so far to falling objects, we can examine some interesting situations and learn much about gravity in the process.

Explanation:

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

\(k = \frac{1}{2} m {v}^{2} \\ \)

m is the mass

v is the velocity

From the question we have

\(k = \frac{1}{2} \times 9 \times {12}^{2} \\ = \frac{1}{2} \times 9 \times 144 \\ = 9 \times 72 \: \: \: \: \: \: \: \: \: \: \: \)

We have the final answer as

Hope this helps you

An image in a convex mirror is constantly upright and reduced. Convex mirrors are curved mirrors with a protruding reflective surface. The virtual picture is located behind the mirror.

An object having a reflective surface known as a mirror reflects light and creates an image of whatever is in front of it. Mirrors are frequently found in places like bathrooms, changing rooms, and automobiles. They can be produced in a variety of forms and from a number of materials, such as glass, metal, and plastic. Beyond self-care and adornment, mirrors have a wide range of uses. They are essential in scientific studies because they help to concentrate and magnify light in instruments like telescopes and microscopes. Mirrors are also used to produce stunning visual effects in architecture, art, and optical illusions. Overall, mirrors play a significant role in society and human life, serving both functional and artistic purposes.

Learn more about mirror here:

https://brainly.com/question/30562917

#SPJ4

Answer:

Option A

Explanation:

The answer is option A or "so that others can repeat and validate these results." In order to develop a drug to treat a disease you need to have research and data on what is used in the drug, how much you need to take, and why it's good for the patient to take it. When you share it with other researchers who specialize in that area, they can take that data and repeat it to see if their results are actually correct or valid.

Hope this helps.

The uncertainty of the displacement calculation for t = 0.050 +/- 0.0010 seconds is 1.6 mm.

What is Displacement?

Displacement is a term used in physics to describe the change in position of an object or particle. It is a vector quantity that measures both the magnitude and direction of the change in position from an initial point to a final point. Mathematically, displacement (denoted as Δx) is calculated as the difference between the final position (x₂) and the initial position (x₁):

Δx = x₂ - x₁

In simple harmonic motion, the displacement (x) of an object as a function of time (t) can be represented by the equation x = A × cos(2πt/T), where A is the amplitude and T is the period.

To calculate the uncertainty in the displacement calculation, we can use the concept of error propagation. The uncertainty in the displacement (Δx) can be calculated using the formula: Δx = |dx/dt| × Δt

Where |dx/dt| is the magnitude of the derivative of the displacement equation with respect to time, and Δt is the uncertainty in time.

Taking the derivative of the displacement equation, we have: dx/dt = -A × (2π/T) × sin(2πt/T)

Substituting the given values, we have:

A = 16 mm (amplitude)

T = 0.40 s (period)

t = 0.050 s (time)

Δt = 0.0010 s (uncertainty in time)

Calculating the magnitude of the derivative at t = 0.050 s, we have: |dx/dt| = |-16 × (2π/0.40) × sin(2π × 0.050/0.40)| = 1.257 mm/s

Finally, calculating the uncertainty in displacement, we have: Δx = |dx/dt| × Δt = 1.257 mm/s × 0.0010 s = 1.6 mm. Therefore, the uncertainty in the displacement calculation for t = 0.050 +/- 0.0010 seconds is 1.6 mm.

To know more about displacement, refer here:

https://brainly.com/question/29769926#

#SPJ4

\( \huge \mathcal{Answer࿐}\)

The factor which is responsible for the conversion of water in liquid state into gaseous state in the water cycle is :

\( \mathrm{\hookrightarrow Energy\:\: from \:\: Sun} \)

_____________________________

\(\mathrm{ \#TeeNForeveR}\)

Answer:

10 joules

Explanation:

Voltage= U(Potential energy)/qo

Q0 is the test charge

so,

250-50=w/5*10^-2

since potential energy = work done

w=10 joules

The time taken by the light to travel from the moon to the earth is 1.28 s and from the sun to the earth is 499.01 s.

We know that, speed of light is constant everywhere.

Its value is 299,792,458 m/s.

Converting into km/s, we have,

⇒ 299,792,458/1000 = 299,792.458 km/s

As the distance between moon and earth is 384000 km.

The time taken by light to travel the above distance is,

⇒ 384000/299,792.458 = 1.28 s

The sun and the earth are separated by 149600000 kilometres.

The time taken by light to travel the above distance is,

⇒ 149600000/299,792.458 = 499.01 s

To know more about time:

https://brainly.com/question/30435516

#SPJ4

Answer:

155 118 in

Explanation:

3.94 km *  1000 m / km  *  39.37 in / m = 155 118 in