.
In which polymer does the monomer include a benzene ring?

Answers

Answer 1

The polymer that includes a monomer with a benzene ring is called a phenolic polymer.

What is a polymer ?

A polymer is a large molecule made up of repeating subunits called monomers. These monomers can be identical or different, and they are linked together through chemical bonds to form a long chain. Polymers can be natural, such as proteins, cellulose, and DNA, or they can be synthetic, such as plastics, synthetic rubber, and fibers.

Polymers have a wide range of properties and can be tailored to meet specific requirements for various applications. For example, some polymers are strong and tough, making them suitable for use in structural materials, while others are flexible and elastic, making them useful in materials such as rubber and elastomers.

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Related Questions

Pls halp. i give brainliest to 1st correct answer

Pls halp. i give brainliest to 1st correct answer

Answers

Answer:

C is correct

Explanation: Heat describes the transfer of thermal energy between molecules within a system and is measured in Joules. Heat measures how energy moves or flows. ... Temperature describes the average kinetic energy of molecules within a material or system and is measured in Celsius (°C), Kelvin(K), Fahrenheit (°F), or Rankine (R)

What is the most abundant element on Earth?
A oxygen
B Cobalt
C Carbon
D Iron
5
Any substance represented by a chemical formula
A Homogenous mixture
B Heterogenous Mixture
C elements
D pure substance

Answers

Answer:

oxygen is the most abundant element on the earth.

Please help me with this problem and what is the reaction type?

Please help me with this problem and what is the reaction type?

Answers

Let's first count how many atoms of each element we have on each side of the reaction.

Reagent side

Mg --->1 atom

Fe ---> 2 atoms

O ---->3 atoms

Product side

Mg --->1 atom

Fe ---->1 atom

O ----> 1 atom

We see that we have three oxygens on the reactant side and one on the product side, therefore we place the coefficient 3 in front of the MgO molecule:

\(Mg+Fe_2O_3\rightarrow Fe+3Mg_{}O\)

Now we balance the Mg atoms that changed, we have 3 atoms in the products, so we put the coefficient 3 in front of Mg

\(3Mg+Fe_2O_3\rightarrow Fe+3Mg_{}O\)

And finally we need to balance the iron, we have 2 iron atoms in the reactants, so we put the coefficient 2 in front of the iron molecule:

\(3Mg+Fe_2O_3\rightarrow2Fe+3Mg_{}O\)

Now we have on each side of the reaction:

Mg ---3 atoms

Fe ----2 atoms

O ---3 atoms

Now the reaction is balanced.

We have a substitution reaction because Mg trades place with Fe

According to theory, which term best describes the universe before the big bang?
a planet
a cloud of gas and dust
a star
a small densely packed ball of matter
Plz help

Answers

a small densely packed ball of matter

Describe how valence electrons from these elements behave when forming metallic bonds:

Answers

well depending on the elements, valence electrons that don’t have a complete outer shell are attracted to others to either steal or give away a valence electrons to have a complete shell, or they’ll share and form bonds...but the missing valence electrons depends on the elements

If a snail crawls 55 inches per day, how many centimeters will he crawl in 23 days?

Group of answer choices

5.0X102 cm

1.06 cm

3.2X103 cm

6.1 cm

2.0X10-3 cm

Answers

If a snail crawls 55 inches per day ,the snail will crawl approximately \(3.2 * 10^3 centimeters.\)

To convert inches to centimeters, we need to use the conversion factor: 1 inch = 2.54 centimeters.

First, let's calculate the distance the snail crawls in inches in 23 days. We can multiply the daily distance by the number of days:

Distance in inches = 55 inches/day × 23 days = 1265 inches.

Now, to convert the distance from inches to centimeters, we multiply the distance in inches by the conversion factor:

Distance in centimeters = 1265 inches × 2.54 cm/inch = 3215.1 cm.

Rounding to the appropriate number of significant figures, the snail will crawl approximately 3215 cm or \(3.2 * 10^3 centimeters.\) in 23 days.

Therefore, the answer is  Option 3:\(3.2 * 10^3 centimeters.\)

This means that in 23 days, the snail will crawl approximately\(3.2 * 10^3 centimeters.\)

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At 99.0 °C and 748 torr, a sample of a volatile liquid is vaporizedcompletely in a 250 mL flash. The condensed vapor weighs 1.097 grams. Calculate the molar mass of the gas.

Answers

Answer:

To calculate the molar mass of the gas, we can use the ideal gas law, which relates the pressure, volume, temperature, and number of moles of a gas:

PV = nRT

where P is the pressure in atmospheres, V is the volume in liters, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in kelvin.

First, we need to convert the temperature to kelvin:

T = 99.0 °C + 273.15 = 372.15 K

Next, we can calculate the number of moles of gas using the ideal gas law:

n = PV/RT

where P is the pressure in atmospheres (we convert 748 torr to atmospheres by dividing by 760 torr/atm), V is the volume in liters (we convert 250 mL to 0.25 L), R is the ideal gas constant, and T is the temperature in kelvin:

n = (748/760) × 0.25 L / (0.0821 L·atm/mol·K × 372.15 K) = 0.0105 mol

Finally, we can calculate the molar mass of the gas by dividing the mass of the condensed vapor (1.097 g) by the number of moles:

molar mass = mass/number of moles = 1.097 g / 0.0105 mol = 104.38 g/mol

Therefore, the molar mass of the gas is approximately 104.38 g/mol.

Explanation:

What is the effect of adding more water to the following reaction at equilibrium? CO2 + H2O H.CO.
The equilibrium is shifted in the direction of reactants, CO2 and H2O.
There is no effens.
The Cos concentration increases.
More H.CO) is produced.​

Answers

Answer:If the pressure of a gaseous reaction mixture is changed the equilibrium will shift to minimise that change. If the pressure is increased the equilibrium will shift to favour a decrease in pressure.

Explanation:

Slidin brainliest??

Use the periodic table to write the electron
configuration for barium (Ba) in noble-gas notation.
Ba: 6s²

Answers

Answer:

[Xe]: 6s²

Explanation:

that's the noble gas config for Barium.

Final answer:

The electron configuration of barium (Ba) in noble gas notation is [Xe] 6s². This shorthand notation signifies that barium has chemically stable electron configuration similar to that of the noble gas xenon (Xe), plus two additional electrons in the 6s orbital.

Explanation:

The electron configuration of an element represents the distribution of electrons in an atom's electron shells. Barium (Ba) is a chemical element with atomic number 56 in the periodic table. Its electron configuration can be written out in full, but the noble-gas notation provides a convenient shorthand. To write the electron configuration of barium in noble gas notation, you first locate the nearest noble gas that precedes barium in the periodic table. In this case, the nearest noble gas is xenon (Xe), which has an atomic number of 54. This leaves two more electrons, which go into the 6s orbital. So, the electron configuration of barium in noble gas notation is [Xe] 6s².

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1. The type of bond most likely to
occur between Mg and Br is a(n)
bond.
---

Answers

Answer:

Ionic bond.

Explanation:

Group 7 elements like Bromine (Br) and group 2 elements like Magnesium,(Mg) involved loss and gain of electrons which is typical with Ionic bonding.

Calculate the mass of water that can be vaporized with 1250 calories of energy.

Answers

Answer:

2.31 g

Explanation:

Step 1: Given data

Energy added to vaporize the water (Q): 1250 calStandard enthalpy of vaporization of water (ΔH°vap): 540 cal/gMass of water (m): ?

Step 2: Calculate the mass of water that can be vaporized with 1250 calories of energy

We will use the following expression.

Q = ΔH°vap × m

m = Q/ΔH°vap

m = 1250 cal/(540 cal/g)

m = 2.31 g

For the reaction

2A(g)+2B(g)+C(g)⟶3G(g)+4F(g)

the initial rate data in the table was collected, where [A]0 , [B]0 , and [C]0 are the initial concentrations of A , B , and C , respectively.

Experiment [A]0 (mmol⋅L−1) [B]0 (mmol⋅L−1) [C]0 (mmol⋅L−1) Initial rate (mmol⋅L−1⋅s−1)
1 11.0. 200.0 220.0 8.80
2 22.0 200.0 165.0 17.6
3 22.0 400.0 55.0 70.4
4 11.0 200.0 110.0 8.80

Reactant A is first order reactant, Reactant B is second order reactant, and Reactant C is zero order reactant...

1. What is the overall order of the reaction ______ ???
2. Write the rate law for the reaction where is the rate constant. Rate = k___???
3. Calculate the rate constant, , and identify its units. K = ____?????
4. Determine the initial rate of the reaction when [A]0=4.87 mmol⋅L−1 , [B]0=0.184 mmol⋅L−1 , and [C]0=12.0 mmol⋅L−1 . Initial Rate = _______ mmol⋅L−1⋅s−1 ??????

Answers

The overall order of the reaction is 3 and the rate law for the reaction is rate =  [A]^n [B]^m [C]^l

How to find the Order of Reaction?

1) The order of reactant A is first order reactant because a first-order reaction can be defined as a chemical reaction in which the reaction rate is linearly dependent on the concentration of only one reactant.

The order of reactant B is second order reactant because a second order reaction is a type of chemical reaction that depends on the concentrations of one-second order reactant or two first-order reactants.

Thus, the overall order of the reaction is 3.

2) The rate law in this reaction is;

rate =  [A]^n [B]^m [C]^l

But in this question, since the reactant C is zero order, then it will be simplified to; rate = k[A][B]² .

3) When we plug in the initial concentrations of A and B, we will get the rate constant of the problem which is k = 20.

4) The initial rate when [A]0=4.87 mmol⋅L−1 , [B]0=0.184 mmol⋅L−1 , and [C]0=12.0 mmol⋅L−1 is;

Rate = 20 * 4.87 * 0.184²

Rate = 3.3

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A 134.0 g sample of an unknown metal is heated to 91.0⁰C and then placed in 125 g of water at 25.0⁰C. The final temperature of the water is measured at 31.0⁰C. Calculate the specific heat capacity of the unknown metal. Specific Heat of water is 4.18 J/g*C pls answer as quickly as possible

Answers

Answer:

\(Cp_{metal}=39.0\frac{J}{g\°C}\)

Explanation:

Hello,

In this case, since the following equation relates heat, mass, specific heat and temperature:

\(Q=mCp(T_2-T_1)\)

For the two substances, we say that the heat lost by the metal equals the heat gained by the water, thus we have:

\(m_{water}Cp_{water}(T_2-T_{water})=-m_{metal}Cp_{metal}(T_2-T_{metal})\)

Thus, the specific heat of the metal turns out:

\(Cp_{metal}=\frac{m_{water}Cp_{water}(T_2-T_{water})}{m_{metal}(T_2-T_{metal})}\)

Therefore, we obtain:

\(Cp_{metal}=\frac{125g*4.18\frac{J}{g\°C} *(31.0-91.0)\°C}{-134.0g*(31.0-25.0)\°C}\\\\Cp_{metal}=39.0\frac{J}{g\°C}\)

Best regards.

A natural resource found in nature that humans use my be

Answers

A natural resource found in nature that humans use may be coal, which is a non-renewable fossil fuel obtained from the earth's crust.

What is a natural resource?

A natural resource can be defined as any material and or energy obtained from the environment and available to be used to achieve a particular objective.

Natural resource bay be finite such as occurs with fossil fuels (i.e., coal, sedimentary rocks from the earth's crust, natural gases, etc) or also they can be obtained in reversible ways and therefore in an infinite amount (e.g. the energy from the sun or the eolic energy, which are renewable sources of energy)

Therefore, with this data, we can see that a natural resource is any type of piece of matter or also different types of energies that can be renewables and not renewables such as occur with eolic energy and coal, respectively.

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What are the purpose of a chemical equation check all that apply

Answers

It’s not no pictures so we cannot see

Answer: (A,B,D) [1, 2, 4]

Explanation:

44 is what percent of 132?

Answers

Answer:

33.33

Explanations:

Let the required percentage value be "x".

44 is what percent of 132 is expressed as:

\(44=x\%\text{ of 132}\)

Simplify the equation to geet the values of "x"

\(\begin{gathered} 44=\frac{x}{100}\times132 \\ 44=0.01x\times132 \\ 44=1.32x \end{gathered}\)

Divide both sides by 0.32 to have:

\(\begin{gathered} 1.32x=44 \\ \frac{\cancel{1.32}x}{\cancel{1.32}}=\frac{44}{1.32} \\ x=\frac{44}{1.32} \\ x\approx33.33 \end{gathered}\)

How many grams of liquid water can be heated by 8920 joules through a change in temperature of 30K?

Answers

Answer:

One of water's most significant properties is that it takes a lot of energy to heat it. Precisely, water has to absorb 4,184 Joules of heat (1 calorie) for the temperature of one kilogram of water to increase 1°C. For comparison sake, it only takes 385 Joules of heat to raise 1 kilogram of copper 1°C.

Explanation:

4. It is desired to prepare 0.5 L of a 0.1 M solution of NaClfrom a 1 M stock solution. How many milliliters of thestock solution must be taken for the dilution?5. Calculate the osmotic pressure of a 0.5 M sucrosesolution if the temperature is 298 K.0123456789abcdefghij edited question

4. It is desired to prepare 0.5 L of a 0.1 M solution of NaClfrom a 1 M stock solution. How many milliliters
4. It is desired to prepare 0.5 L of a 0.1 M solution of NaClfrom a 1 M stock solution. How many milliliters

Answers

This is a perfect answer

ω

\(\text{y = ax + b}\)

4. It is desired to prepare 0.5 L of a 0.1 M solution of NaClfrom a 1 M stock solution. How many milliliters
4. It is desired to prepare 0.5 L of a 0.1 M solution of NaClfrom a 1 M stock solution. How many milliliters

A covalent bond forms when two atoms share unpaired electrons in their outer shell. Covalent bonds between carbon (C), hydrogen (H), oxygen (O), nitrogen (N), and phosphorus (P) are particularly important and numerous in biological organisms. Rank the following covalent bonds in terms of which molecules would take the least amount of energy to break apart.
Question List (6 items)
(Drag and drop into the appropriate area)
C—H
C—C
C—O
N—H
C—N
O—H
Covalent Bonds
Least Energy to Break
1
2
3
4
5
6
Greatest Energy to Break

Answers

To determine which of the following covalent bonds would require the least energy to break apart in a given molecule: Energy Required to Break: The greatest energy to break is C—H, N—H, O—H, C—N, C—O, and C—C.

The energy needed to break a covalent link between two atoms is known as covalent bond energy. Atoms share electrons in their outer shell to create covalent bonds, which can result in a stable and energetically advantageous arrangement of electrons. The atoms involved, their electronegativities, and the length of the connection all affect how strong a covalent bond is. Covalent bonds often have higher electronegativities and shorter bond lengths. Covalent bonds between the atoms of carbon, hydrogen, oxygen, nitrogen, and phosphorus play a crucial role in the synthesis of complex macromolecules like proteins, nucleic acids, and carbohydrates in living things. Understanding covalent bond energy is crucial for formulating medications that can target specific biological molecules and for predicting the reactivity of compounds.

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how is biochemist related to chemistry? pls answer if I don't get an answer I will fail the school year

Answers

Answer:

biochemist is both life science and a chemical . it explores the chemistry of the living organisms and the molecular basis for the changes occurring in the living organisms. it uses the method of chemistry . BIOCHEMIST has become the foundation for understanding all biological processes

1.
Use the Rydberg equation to calculate the energy (in J) and then find the wavelength
in (nm) for the following transitions.
-18
AE = 2.179x10
a.
3-2.

1.Use the Rydberg equation to calculate the energy (in J) and then find the wavelengthin (nm) for the

Answers

Answer:

Approximately \(3.03\times 10^{-19}\; \rm J\), which corresponds to a wavelength of approximately \(6.56 \times 10^{2}\; \rm nm\) in vacuum.

Explanation:

When the electron of a hydrogen atom transits from energy level \(n_1\) to \(n_2\), the energy change would be:

\(\displaystyle \Delta E \approx 2.179 \times 10^{-18}\; {\rm J} \, \left(\frac{1}{{(n_1)}^{2}} - \frac{1}{{(n_2)}^{2}}\right)\).

For the transition from \(n_1 =3\) to \(n_2 = 2\):

\(\begin{aligned}\Delta E &\approx 2.179 \times 10^{-18}\; {\rm J} \, \left(\frac{1}{{(n_1)}^{2}} - \frac{1}{{(n_2)}^{2}}\right)\\ &= 2.179 \times 10^{-18}\; {\rm J} \, \left(\frac{1}{{3}^{2}} - \frac{1}{{2}^{2}}\right) \\ &\approx -3.02639 \times 10^{-19} \; \rm J \\ &\approx -3.03\times 10^{-19}\; \rm J\end{aligned}\).

The value of \(\Delta E\) is negative because energy is released during this transition.

Look up Planck's Constant (for finding frequency from energy) and the speed of light in vacuum (for finding wavelength from frequency.)

Planck's Constant: \(h \approx 6.62607 \times 10^{-34} \; \rm J \cdot s^{-1}\).Speed of light in vacuum: \(c \approx 2.99792 \times 10^{8}\; \rm m \cdot s^{-1}\).

Calculate the frequency \(f\) of photons from this transition using the Planck-Einstein relation:

\(E = h \cdot f\).

Therefore:

\(\begin{aligned}f &= \frac{E}{h}\end{aligned}\).

Calculate the wavelength \(\lambda\) of these photos in vacuum:

\(\begin{aligned}\lambda &= \frac{c}{f} \\ &= \frac{c}{ E/ h} \\ &= \frac{h \cdot c}{E} \\ &\approx \frac{6.62607 \times 10^{-34}\; \rm J \cdot s \times 2.99792 \times 10^{8}\; \rm m \cdot s^{-1}}{3.02639 \times 10^{-19}\; \rm J} \\ &\approx 6.65 \times 10^{-7}\; \rm m \\ &= 6.65 \times 10^{-7}\; \rm m \times \frac{10^{9}\;\rm nm}{1\; \rm m} \\ &= 6.65 \times 10^{2}\; \rm nm\end{aligned}\).

If 2.50 ml of vinegar requires 34.50 ml of 0.0960 M NaOH to reach the equivalence point in a titration, how many grams of acetic acid are in 500.0 ml of this vinegar? Density of vinegar=1.01 g ml

Answers

Grams of acetic acid in 500 ml vinegar=39.744 g

Further explanation

Titration (equivalence point⇒mol acid(CH₃COOH)=mol base(NaOH))

M₁V₁n₁=M₂V₂n₂(n=valence acid/base, for CH₃COOH and NaOH=1)

\(\tt M_1\times 2.5\times 1=0.0960\times 34.5\times 1\\\\M_1(acetic~acid)=1.3248~mol/L\)

For MW CH₃COOH = 60 g/mol, mass of acetic acid in 1 L :

\(\tt 1.3428~mol/L\times 60~g/mol=79.488~g/L\)

for 500 ml :

\(\tt 79.488\times 0.5~L=39.744~g\)

The mass of vinegar present in 500mL of solution is 39.6 g.

Concentration of acid (CA) = ?

Volume of acid(VA) = 2.50 ml

Concentration of base (CB) =0.0960 M

Volume of base (VB) =  34.50 ml

Number of moles of acid = 1

Number of moles of base = 1

Equation of the reaction;

CH3COOH (aq) + NaOH(aq) ------> CH3COONa(aq) + H2O(l)

From CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CA = CBVBNA/VANB

CA = 0.0960 × 34.50 × 1/2.50 × 1

CA = 1.32 M

Number of moles = concentration  × volume

Number of moles = 1.32 M × 500/1000

Number of moles = 0.66 moles

Number of moles = mass/molar mass

Mass = Number of moles  × molar mass

Molar mass of acetic acid = 60 g/mol

Mass =  0.66 moles  ×  60 g/mol

Mass = 39.6 g

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How many moles of NaHCO3
are in 27.5 g NaHCO3
?

Answers

I am pretty sure it is 4

why did my dad hasn't come back with the milk for 10 years

Answers

Answer:

Milk's heavy

Explanation:

I
II
III
none of the above

IIIIIInone of the above

Answers

2 is most likely to rearrange

Answer:

i think it will be the first one

Explanation:

chemical reaction
on carbon reduction process?


Answers

Answer:

In a blast furnace, the carbon fuel will be oxidized before the metal in the oxide is reduced. The metal in the oxide is then reduced by carbon monoxide and the product of the reaction will be metal and carbon dioxide.

Explanation:

Use the band of stability to determine if europium-154 is a stable or unstable nucleus. Hint: You
must first find the atomic number to determine the number of protons and then use the equation,
neutrons = mass number - protons, to find the neutrons.

On/Z=0.69, unstable
On/Z=0.69, stable
On/Z=1.44, unstable
On/Z=1.44, stable

Answers

Answer:

1.44 STABLE

Explanation:

If an atomic number of an element is 24, the number of protons the Atom has is

A. 24
B. 12
C. 189
D.51.996

Answers

Explanation:

i think the answer is A ........ hope this helps

Given: H2 + O 2 → H2O1
the reaction occurs at ST.P a) Balance the chemical equation. (1 pts) b) Calculate the number of moles of the reactants needed to obtain 45 liner of H2O (2 pt) 4) Deduce the volume of the reactants (2 pts)​

Answers

a) The balanced chemical equation for the reaction is: 2H₂ + O₂ → 2H₂O

b) the number of moles of O₂ required is approximately 1.004 moles.

c)  approximately 45 liters of H₂ and 22.5 liters of O₂ are needed to obtain 45 liters of H₂O.

a) Balancing the chemical equation:

The balanced chemical equation for the reaction is: 2H₂ + O₂ → 2H₂O

b) Calculating the number of moles of the reactants needed to obtain 45 liters of H₂O:

From the balanced equation, we can see that for every 2 moles of H₂O produced, we need 2 moles of H₂ and 1 mole of O₂. Since the stoichiometry is based on moles, we need to convert the given volume of H2O into moles.

To convert volume to moles, we need to use the ideal gas law, PV = nRT. At standard temperature and pressure (STP), the molar volume of an ideal gas is 22.4 liters.

Given that we have 45 liters of H2O, we can calculate the number of moles as follows:

moles of H₂O = (volume of H₂O) / (molar volume at STP)

            = 45 liters / 22.4 liters/mol

            ≈ 2.008 moles of H₂O

Since the stoichiometry of the reaction is 2 moles of H₂O for every 2 moles of H₂, we need an equal number of moles of H₂. Therefore, the number of moles of H₂ required is also approximately 2.008 moles.

For O₂, since the stoichiometry is 1 mole of O₂ for every 2 moles of H₂O, we need half the number of moles of H₂O. Thus, the number of moles of O₂required is approximately 1.004 moles.

c)  the volume of the reactants:

Since the stoichiometry of the balanced equation is 2 moles of H₂for every 1 mole of O₂ and 2 moles of H₂O, we can deduce the volume of the reactants based on their molar volumes at STP.

For 2.008 moles of H₂, the volume can be calculated as follows:

volume of H₂= (moles of H₂) * (molar volume at STP)

            = 2.008 moles * 22.4 liters/mol

            ≈ 45 liters of H₂

For 1.004 moles of O₂, the volume can be calculated similarly:

volume of O₂= (moles of O₂) * (molar volume at STP)

            = 1.004 moles * 22.4 liters/mol

            ≈ 22.5 liters of O₂

Therefore, approximately 45 liters of H₂and 22.5 liters of O₂ are needed to obtain 45 liters of H₂O

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Which of these represents a wave with the highest energy?

Answers

Answer:Gamma rays have the highest energy and shortest wavelength. Then come X-rays, ultraviolet light, visible light, infrared radiation and microwave radiation.

Explanation:

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Which phrase could be the best represented by the algebraic expression w/4-4 what is a fee that broadcasters must pay to musicians for using their songs in public? royalty, copyright,collaboration, or fair use? A gas at a constant pressure occupies 2.24 L at 52 C. If the sample is cooled United it takes up 1.66 L what is the new temperature?A. 0.01 KB. 0.01 CC. 32 CD. 241 KPLS SHOW WORK When designing a website, Claire creates a color palette for the web pages. How can the color palette help Claire design effective web pages? Applying the color palette to the web pages can help Claire create ________ She can best use the color palette to ____________.First blank:A. Smooth and even surfacesB. Depth in the design C. 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(Round answers to 0 decimal places, e.g. $38,487.)(c) The preferred stock is cumulative and participating. (Round the rate of participation to 4 decimal places, e.g.1.4278%. Round answers to 0 decimal places, e.g. $38,487.) You're the leader of the security committee at ACME. After a move to a new facility, you're installing a new security monitoring system throughout. Which of the following best describes a motion detector mounted in the corner of a hallway? A. Perimeter security B. Partitioning C. Security zone D. IDS system this problem requires you to develop a dynamic 12-month cash flow budgeting/forecasting tool. the months should be displayed as columns in the spreadsheet with the following inputs: initial sales of $10,000,000 with forecasted monthly growth 3.5% 35% of sales are collected in month of sale. 20% of sales are collected the following month. 25% collected 2 months later 18% collected 3 months later 2% never collected initial cash balance of $250,000 Evaluate the following expressions how can teachers use effective verbal, nonverbal, and media communication techniques to foster students active inquiry, collaboration * how sport tourism can be beneficial in tourism industry in a country and what are the current issues face ?Ex - visiting overseas for cricket match ( what can go wrong and why important)* what are the areas we need to focus on sport industry 70 POINTS!!!!!Describe how the following can be solved with greater unity.-Bullying-Stereotyping-Safety-Lack of involvement with a community -Environmental problems Braden has $700 in an account that earns 10% interest compounded annually. To the nearest cent, how much will he have in 3 years? In a transaction involving the transfer of corporate and partnership interests in which the special valuation rules under IRC Chapter 14 apply, which one of the following statements is correct? The interest given to the transferee must be valued at zero if the transferee is not given a qualified interest. The interest given to the transferee must be valued at zero if the transferee is given a qualified interest. The interest retained by the transferor must be valued at zero if this retained interest is a qualified interest. The interest retained by the transferor must be valued at zero if this retained interest is not a qualified interest Which statement contains an ironic use of understatement? What is the Temperature Variation with Altitude of the Troposphere, Stratosphere, Mesosphere, and Thermosphere? please - do - not - touch - steve's - pet - alligator this is a mnemonic to help remember a model. please type the three letters of what this helps you remember. Can anyone tell me why I got this wrong? -3(x+2)>15 or x-3 -1my answer was ( -7, 2 )The options areA. ( - infinity, 2)B. (-7, -2)C. [ - 7, infinity)D. ( -7, 2) The Viet Cong and NVA suffered huge military losses, but won a psychological victory during theGroup of answer choicesEaster RisingTet OffensiveFall of SaigonBattle of Dien Bien Phu The food web illustrated here exists in YellowstoneNational Park.SecondaryconsumersERRaven (detritivore)Gray wolfPrimaryconsumersSnowshoehareMooseBeaverRed squirrelPrimaryproducersPineMaple Balsam Fir Cottonwood Aquatic plantsIf red foxes were to go extinct, what would be the two mostlikely effects on the ecosystem?A. Decreased biodiversityB. Increased gray wolf populationC. Increased biodiversityD. Increased aquatic plant populationRed fox