Kinetic Energy in Solids, Liquids, and Gases
Particles of solids, liquids, and gases have kinetic energy because the particles
are in constant motion.
The particles of solids have extremely _ kinetic energy
The particles of liquids
have extremely_ kinetic energy
The particles of gases
have_kinetic energy

Answer:

Water serves to suspend the red blood cells to carry oxygen to the cells. It is the solvent for the electrolytes and nutrients needed by the cells, and also the solvent to carry waste material away from the cells. With water as the solvent, osmotic pressure acts to transport the needed water into cells.

Explanation:

Answer:

8g/mL

Explanation:

Density = Mass/Volume

There is 5.6g of Iron added to the water of 23.60mL and it rose by 0.7mL.

Density = 5.6g/0.7mL of Iron.

The percentage decrease in the amount of dissolved oxygen is 10%

Percent yield is the percent ratio of actual yield to the theoretical yield. It is calculated to be the experimental yield divided by theoretical yield multiplied by 100%. If the actual and theoretical yield ​are the same, the percent yield is 100%

In chemistry, yield is a measure of the quantity of moles of a product formed in relation to the reactant consumed, obtained in a chemical reaction, usually expressed as a percentage.

From the graph,

The amount of dissolved oxygen at  15°C is 10 mg/L

The amount of dissolved oxygen at  20°C is 9 mg/L

The decrease in the amount of dissolved oxygen is 1mg/L

The percentage decrease = (1/10) × 100 = 10%

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Answer:

The equation is not correct:

[CH4 + O2 → CO2 + 2H2O]

Explanation:

The chemical formulas for methane, oxygen, and carbon dioxide are correct, but the equation is not balanced, so we really don't know idf the overall reaction is written correctly.

Let's balance the reaction:

CH4 + O2 → CO2

We need to have the same numbers of atoms on both sides.  

Count the numbers of each atom:

Element    Reactants    Products    Difference

 C                         1              1                  0                  Balanced

 H                         4              0                -4                  XXX!!!!

 O                         2              2                 0                  Balanced

The hydrogens aren't showing up in the products.  In fact, there is a product missing entirely from the reaction, H2O, water.  The basic reaction is:

CH4 + O2 → CO2 + H2O

Now balance this reaction:

Element    Reactants    Products    Difference

 C                         1              1                  0                  Balanced

 H                         4              2                -2                  Hmmmm . . .

 O                         2              3                 1                  Uh = oh . . .

This reaction is not possible - there are either too many or too few element atoms (the "Difference").

We can adjust the coefficients for each of the molecules to balanced the equation.  This is a bit tricky, but it consists of trying some coefficients that would make things balance.  Only whole number coefficients are allowed in the final answer, although fractions might be used in the process to help find the whole numbers.

We need 2 H2O molecules to account for the 4 hydrogens on a single methane molecule

Step 1:  CH4 + O2 → CO2 + 2H2O

That leads to:

Element    Reactants    Products    Difference

 C                         1               1                 0                  Balanced

 H                         4              4                0                   Balanced

 O                         2              4                 2                  Darn

We need more oxygen atoms, so:

Step 2:  CH4 + 2O2 → CO2 + 2H2O

This leads to:

Element    Reactants    Products    Difference

 C                         1               1                  0                  Balanced

 H                         4              4                 0                   Balanced

 O                         4              4                 0                   Balanced

This is a balanced reaction, and the correct chemical equation.

The number of moles of oxygen gas needed to react with 4.0 moles of Mg is 2.0 moles.

Equation: 2Mg + O2 → 2MgO

Step 1: Identify the mole ratio between Mg and O2 from the equation. For every 2 moles of Mg, there is 1 mole of O2 needed (2Mg:1O2).

Step 2: You have 4.0 moles of Mg. To find the number of moles of O2 needed, we can set up a proportion based on the mole ratio:

(4.0 moles Mg) / (x moles O2) = (2 moles Mg) / (1 mole O2)

Step 3: Solve for x moles O2 by cross-multiplying:

4.0 moles Mg * 1 mole O2 = 2 moles Mg * x moles O2
4.0 moles O2 = 2x moles O2

Step 4: Divide both sides by 2 to get the number of moles of O2:

x = 4.0 moles O2 / 2
x = 2.0 moles O2

The number of moles of oxygen gas needed to react with 4.0 moles of Mg is 2.0 moles (Option B).

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Answer:

M=3

B=25

Equation= 3x+25

Explanation:

M is your slope and if you follow the slope- intercept formula (y=m+b) you just need to plug in the numbers.

Thus your answer:

M=3

B=25

Equation= 3x+25

A base, according to the Arrhenius definition, is any species that increases the concentration of OH- in the solution. Some examples of bases are, NaOH, KOH, LiOH, all these substances will increase the concentration of OH when dissolved. Letter C

minerals are disbursed through the water

Explanation:

say you have a bottle of water and you leave it in a car when you go in to a store you come back and you see some particles in the water well that's mixture water is made of minerals so when it says the particles so when the mix the minerals get disbursed through out the water and they become invisible. that's why minerals water is a mixture

The volume of 0.175 M \(Na_3PO_4\) solution required to completely react with 126 mL, 0.150 M  \(CuCl_2\) is 0.72 L 0r 720 mL.

From the balanced equation of the reaction, the mole ratio of  \(Na_3PO_4\) and   \(CuCl_2\) is 2:3.

Recall that: mole = molarity x volume

126 mL = 126/1000 = 0.126 L

Mole of 126 mL, 0.150 M   \(CuCl_2\) = 0.150 x 0.126

                = 0.0189 moles

Equivalent mole of  \(Na_3PO_4\) from the mole ratio = 2/3 x 0.0189

                   = 0.0126 moles

Volume = mole/molarity

Volume of 0.0126 moles, 0.175 M  \(Na_3PO_4\) = 0.126/0.175

               = 0.72 L

0.72 L = 0.72 x 1000

             = 720 mL

In other words, 0.72 L 0r 720 mL of 0.175 M \(Na_3PO_4\) is required to completely react with 126 mL of 0.150 M  \(CuCl_2\).

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In the titration of 50.0 ml of 0.400 m hcooh with 0.150 m lioh, the equivalence point is the point at which the moles of acid and base are equal.  133 mL of 0.150 M lioh are required to reach the equivalence point in the titration of 50.0 mL of 0.400 M hcooh.

To find the volume of lioh required to reach the equivalence point, we can use the equation:

n(hcooh) = n(lioh)

Where n is the number of moles of each compound. The number of moles of hcooh is:

n(hcooh) = C(hcooh) x V(hcooh)
n(hcooh) = 0.400 mol/L x 0.0500 L
n(hcooh) = 0.0200 mol

At the equivalence point, the number of moles of lioh added is equal to the number of moles of hcooh. So:

n(lioh) = 0.0200 mol

We can use the equation above to find the volume of lioh required:

n(lioh) = C(lioh) x V(lioh)
V(lioh) = n(lioh) / C(lioh)
V(lioh) = 0.0200 mol / 0.150 mol/L
V(lioh) = 0.133 L or 133 mL

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Answer:

urinary tract infections. B

Explanation:

12.0 grams od n2 & 15.0 gram of ar are present in a gas mixture with a pressure head of 1.32 atm. 0.704 atm is the pressure drop of n2.

Another of the fundamental observable characteristics of the this phase of matter, pressure (P) is understood to be the force of all gas particulate interactions divided by the size of the wall.

Pressure has a major impact on every aspect of our life, from of the weather to flying. It is particularly crucial during chemical reactions. Chemists can compel chemical reactions to happen and hasten the transitions among solids, fluids, or gases by adjusting pressure.

N=12.0, Ar=15.0

Total pressure=1.32

Partial pressure= n2

WN₂=12.0

WAr =15.0

nN₂=12/28 =0.42

nAr=15/40 =0.37

Xn₂=0.42/0.42+0.37 =0.53

Pn=Xn2×Ptotal

=0.53×1.32=0.69atm that ie nearly equal to 0.7atm.

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When a patient is admitted to the emergency department with symptoms of headache, weakness, and slight confusion, the physician diagnoses carbon monoxide poisoning. In this case, the nurse should first administer oxygen therapy to the client.

Carbon monoxide poisoning is a medical emergency that occurs when carbon monoxide (CO) gas is breathed in.

It may cause serious harm or death, making it important to identify and manage the condition as soon as possible.

CO is a colorless, odorless, tasteless gas that is produced by burning fuels like coal, wood, charcoal, oil, kerosene, natural gas, and propane.

Carbon monoxide poisoning is a medical emergency that can lead to death if not treated quickly.

Symptoms of carbon monoxide poisoning include:

Headache

Dizziness

Nausea and vomiting

Weakness

Fatigue

Chest pain

Shortness of breath

Confusion

Loss of consciousness

The treatment for carbon monoxide poisoning involves removing the person from the source of CO gas and providing oxygen therapy.

Administering 100% oxygen through a mask is the preferred method of treatment, as it helps to reduce the amount of carbon monoxide in the blood and tissues.

This helps to restore oxygen to the body's tissues and organs, and it also helps to prevent the formation of carbon monoxide in the bloodstream.

The nurse should first administer oxygen therapy to the client because it is the first and most important step in treating carbon monoxide poisoning.

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Answer:

Atomic number

Explanation:

Atomic number is the number of protons, and therefore also the total positive charge, in the atomic nucleus. The Rutherford–Bohr model of the hydrogen atom (Z = 1) or a hydrogen-like ion (Z > 1).

Answer:

The answer is chlorine

Explanation:

Answer:

23.5 %

Explanation:

La fórmula del ácido sulfúrico es H₂SO₄, mientras que su masa molar es de 98 g/mol.

Siendo la densidad 1.4 g/mL, quiere decir que en 1 mL de solución tenemos 1.4 g de solución. Como la concentración es de 330 g/L entendemos que la solución contiene 330 gramos de soluto en 1L de solución.

Entonces en 1000 mL de solución (lo que equivale a 1 litro), tendremos:

1.4 g/mL = masa de solución / 1000 mL

masa de solución = 1.4 g/mL . 1000 mL =  1400 g

Como % en masa es la concentración que define la masa de soluto en 100 gramos  de solución, para esta solución de H₂SO₄ es:

(330 g / 1400 g) . 100 = 23.5 %

Water is always involved in hydrolysis reactions in the given options.

The term "hydrolysis" refers to the breakage of chemical bonds by the addition of water and represents the reaction of an organic chemical with water to produce two or more new chemicals. Some occurrences of hydrolysis include the formation of hydronium and bisulfate compounds when sulphuric dissolves in water or a salt of a weak acid or base is mixed with water.

Inversion is the mechanism of hydrolyzing sucrose to produce glucose and fructose. Invert sugar is the consequence of the hydrolysis of sucrose, which causes the sign of rotation to alter from dextro (+) to laevo (-).

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Answer:

C. He feels excited and happy

Explanation:

a) [HOC₆H₅] ≈ 0.57 M ; b)  pH of the solution is approximately 3.41.c) concentration of [HBr] = (3.9012 × 10⁻⁴)²/Ka ≈ 2

Propanoic acid is a carboxylic acid with chemical formula as C₃H₆O₂ and is also known as propionic acid.

a.) HOC₆H₅(aq) + H₂O(l) ⇌ H₃O⁺(aq) + OC₆H₅⁻(aq)

[H₃O⁺] = [OC₆H₅⁻] = 0.0684/100 × 0.57 M = 3.9012 × 10⁻⁴ M

Initial concentration of HOC₆H₅ is 0.57 M, and since only small fraction of it has dissociated, we can assume that its concentration at equilibrium is approximately equal to initial concentration. Therefore:

[HOC₆H₅] ≈ 0.57 M

b.) pH = - ㏒ [H₃O⁺]

pH = - ㏒ (3.9012 × 10⁻⁴) ≈ 3.41

Therefore, pH of the solution is approximately 3.41.

c.) pH = pKa +  ㏒([OC₆H₅⁻]/[HOC₆H₅])

The pKa of propanoic acid is 4.87, so:

3.41 = 4.87 + ㏒([OC₆H₅⁻]/[HOC₆H₅])

㏒([OC₆H₅⁻]/[HOC₆H₅]) = -1.46

[OC₆H₅⁻]/[HOC₆H₅] = 3.47 × 10⁻²

[OC₆H₅⁻] = (3.47 × 10⁻²) × 0.57 M ≈ 1.97 × 10⁻² M

HBr(aq) + H₂O(l) ⇌ H₃O⁺(aq) + Br⁻(aq)

Ka = [H₃O⁺][Br⁻]/[HBr]

Ka = (3.9012 × 10⁻⁴)²/1.97 × 10⁻² ≈ 7.69 × 10⁻⁹

Ka = [H₃O⁺][Br⁻]/[HBr] = [H₃O⁺]²/[HBr]

[H₃O⁺] = √(Ka[HBr])

3.9012 × 10⁻⁴ = √(Ka[HBr])

[HBr] = (3.9012 × 10⁻⁴)²/Ka ≈ 2

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Answer:

(I). Evaporation

(ii). Sublimation

Answer:

A and D

Explanation:

unsaturated hydrocarbons have double or triple bonds

O2- Option B is correct

Explanations:

Calcium atom is a group 2 elements that gives out two electrons in order to form a stable configuration and a Ca2+ ion. These two electrons are transferred to an atom that required two electrons to complete its outer shell.

Since oxygen required 2 electron to attain its octet configuration, hence they can easily accepts the two electrons from calcium atoms to form CaO which is composed of Ca2+ and O2- ions in the ratio of one Ca2+ ion to one O2− ions.

Answer:

The three-point test

Explanation:

The three-point test refers to a ground test utilizing an auxiliary current electrode and an auxiliary potential electrode.

A single replacement reaction is a type of chemical reaction that takes place when one element in a compound is replaced by another element. In other words, in this reaction, one element is replaced by another element. There are a few ways to predict whether or not a single replacement reaction will occur.

These ways are explained below: Paying Attention to ReactantsThe first way to predict if a single replacement reaction will occur is by paying attention to the reactants. In a single replacement reaction, a more reactive element will replace a less reactive element. For example, if a metal element is mixed with an aqueous solution that contains ions of another metal, a single replacement reaction will occur if the metal in the solid state is more reactive than the metal in the solution state. For instance, if you put zinc in copper sulfate, a reaction will occur because zinc is more reactive than copper. Therefore, it will replace copper, producing zinc sulfate and copper.Using the Activity SeriesAnother way to predict if a single replacement reaction will occur is by using the activity series. The activity series is a list of metals and their ability to replace other metals from their compounds. This list is arranged in order of decreasing activity. Therefore, if a metal is more active than another metal on the activity series, it will replace that metal from its compound. For example, if you put magnesium in silver nitrate, a reaction will occur because magnesium is more reactive than silver. Therefore, magnesium will replace the silver, producing magnesium nitrate and silver. If the metal is less active than another metal on the activity series, no reaction will occur.Using Electrochemical SeriesThe electrochemical series is another way to predict if a single replacement reaction will occur. The electrochemical series lists the elements in order of their standard reduction potentials. A metal with a higher reduction potential will replace a metal with a lower reduction potential from its compound. For instance, if you put copper in magnesium sulfate, no reaction will occur because copper has a lower reduction potential than magnesium. Therefore, magnesium will not replace copper from its compound.

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Pyruvate undergoes fermentation, which transforms it into lactic acid inside the absence of oxygen.

The breakdown of the drug occurs throughout this process. similar to how pyruvate is converted into lactic acid.

An organic acid contains lactic acid. Its chemical formula is CH 3CH(OH)COOH.

It serves as a synthesis precursor inside a number of biochemical as well as molecular synthesis industries.

The final result of the glycolysis pathway, pyruvate, is transformed into lactic acid inside the lack of oxygen.

Glycolysis

The process through which glucose gets broken down to provide energy is known as glycolysis.

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Answer: 2 Na (s) + Cl(g) -> 2 NaCl (s)

Explanation:

Mixture: A combination of two or more substances that are physically intermingled. Can be separated by physical methods.

Compound: A substance composed of two or more elements chemically bonded together. Can only be separated by chemical means.

Classification:

(i) Limestone - Mixture

(ix) Clay - Mixture

(ii) Diamond - Element

(x) Urea - Compound

(iii) Sand - Mixture

(xi) Antimony - Element

(iv) Soil - Mixture

(xii) Soap - Compound

(v) Urine - Mixture

(xiii) Milk - Mixture

(vi) Bronze - Mixture

(xiv) Air - Mixture

(vii) Sugar - Compound

(xv) Neon - Element

(viii) Gold - Element

(xvi) Iron - Element

Differences between mixtures and compounds:

Composition: Mixtures have variable compositions, meaning the ratio of substances can vary. Compounds have a fixed composition with a specific ratio of elements.

Separation: Mixtures can be separated into their components using physical methods. Compounds can only be separated into elements through chemical reactions.

Properties: Mixtures exhibit the properties of their individual components and can have varying physical properties throughout. Compounds have unique properties different from the elements they are composed of.

Classification of substances:

(i) Limestone: Mixture (contains minerals and impurities)

(ii) Diamond: Element (composed of carbon atoms)

(iii) Sand: Mixture (combination of mineral particles)

(iv) Soil: Mixture (combination of organic matter, minerals, water, and air)

(v) Urine: Mixture (contains various dissolved substances)

(vi) Bronze: Mixture (alloy of copper and tin)

(vii) Sugar: Compound (composed of carbon, hydrogen, and oxygen)

(viii) Gold: Element

(ix) Clay: Mixture (combination of minerals and organic matter)

(x) Urea: Compound (composed of carbon, hydrogen, nitrogen, and oxygen)

(xi) Antimony: Element

(xii) Soap: Compound (formed by the reaction of fatty acids with an alkali)

(xiii) Milk: Mixture (contains water, proteins, fats, sugars, and minerals)

(xiv) Air: Mixture (combination of gases like nitrogen, oxygen, carbon dioxide, etc.)

(xv) Neon: Element

(xvi) Iron: Element

It's important to note that some substances listed may have impurities or variations in composition, which can affect their classification.

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A respirator containing 50.0 g of diiodine pentaoxide can remove approximately 20.95 g of carbon monoxide from the air, leaving approximately 190.08 g of diiodine (\(I_2\)) remaining.

We use stoichiometry and the given balanced equation:

\(I_2O_5(s) + 5CO(g)\)→\(I_2(s) + 5CO_2(g)\)

(a) The mass of carbon monoxide (CO) that can be removed, we need to determine the stoichiometric ratio between diiodine pentaoxide\((I_2O_5)\) and CO. From the balanced equation, we can see that 1 mole of \((I_2O_5)\) reacts with 5 moles of CO.

We calculate the number of moles of \((I_2O_5)\):

Number of moles = mass / molar mass

Molar mass of \((I_2O_5)\) = 2(I) + 5(O) = 2(126.9 g/mol) + 5(16.0 g/mol) = 333.8 g/mol

Number of moles of \((I_2O_5)\) = 50.0 g / 333.8 g/mol ≈ 0.15 mol

Since the stoichiometric ratio is 1:5 between \((I_2O_5)\) and CO, the number of moles of CO that can be removed is:

Number of moles of CO = 0.15 mol × 5 = 0.75 mol

The mass of CO, we multiply the number of moles by its molar mass:

Mass of CO = number of moles × molar mass

Molar mass of CO = 12.0 g/mol + 16.0 g/mol = 28.0 g/mol

Mass of CO = 0.75 mol × 28.0 g/mol ≈ 21.0 g

Therefore, approximately 21.0 grams of carbon monoxide could be removed from the air by a respirator containing 50.0 grams of diiodine pentaoxide.

(b) To find the mass of \(I_2\) remaining in the respirator, we use the stoichiometric ratio of 1 mole of \((I_2O_5)\) to 1 mole of\(I_2\)

Number of moles of \(I_2\) remaining = 0.15 mol

To calculate the mass of \(I_2\), we multiply the number of moles by its molar mass:

Mass of \(I_2\) = number of moles × molar mass

Molar mass of \(I_2\) = 2(I) = 2(126.9 g/mol) = 253.8 g/mol

Mass of \(I_2\) = 0.15 mol × 253.8 g/mol ≈ 38.1 g

Therefore, approximately 38.1 grams of \(I_2\) would remain in the respirator.

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The quantity in moles of chlorine gas at 120.0 °C and 33.3 atm that would occupy a vessel of 12.0 L is 0.754 moles.


We can use the Ideal Gas Law to solve for the quantity of moles of chlorine gas. The formula for the Ideal Gas Law is PV = nRT, where P is pressure, V is volume, n is the quantity in moles, R is the gas constant, and T is temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin: 120.0°C + 273.15 = 393.15 K.

Next, we can rearrange the Ideal Gas Law to solve for n:
n = PV/RT

We plug in the values given in the problem:
P = 33.3 atm
V = 12.0 L
R = 0.0821 L•atm/mol•K (gas constant)
T = 393.15 K

n = (33.3 atm x 12.0 L) / (0.0821 L•atm/mol•K x 393.15 K)
n = 0.754 moles

Therefore, the quantity in moles of chlorine gas at 120.0°C and 33.3 atm that would occupy a vessel of 12.0 L is 0.754 moles.

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