The crate is moving at constant velocity when the forces acting on it are
balanced.
The value of the force F required to pull the crate with constant velocity is; \(\underline{F = \sqrt{2} \cdot \mu \cdot m\cdot g}\)Reasons:
Mass of the crate = m
Cross section of through = Right angled
Orientation (inclination) of the through to horizontal = 45°
Coefficient of kinetic friction = μ
Required:
The value of the required to pull the crate along the through at constant
velocity.
Solution:
When the through is moving at constant velocity, we have;
Friction force acting on crate = Force pulling the crate
Friction force = Normal reaction × Coefficient of kinetic friction
Normal reaction on an inclined plane = \(\mathbf{F_N}\)
Each side of the through gives a normal reaction.
The vertical component of the normal reaction on each side of the through
is therefore;
\(F_N\)·j = \(\mathbf{F_N}\) × sin(θ)The sum of the vertical component = \(F_N\)·j + \(F_N\)·j = 2·\(F_N\)·j = 2·\(F_N\)×sin(θ)
The sum of the vertical component of the normal reactions = The weight of the crate
Therefore;
2·\(F_N\)×sin(θ) = m·g
θ = 45°
Therefore;
2·\(F_N\)×sin(45°) = m·g
\(\displaystyle sin(45^{\circ}) = \mathbf{\frac{\sqrt{2} }{2}}\)
Therefore;
\(\displaystyle 2 \cdot F_N \cdot sin(45^{\circ}) = 2 \cdot F_N \times \frac{\sqrt{2} }{2} = \sqrt{2} \cdot F_N\)
\(\displaystyle F_N = \mathbf{ \frac{m \cdot g}{\sqrt{2} }}\)
Which gives;
\(\displaystyle Force \ required, \ F = Sum \of \ friction \ forces \ = 2 \times F_N \times \mu = \mathbf{ 2 \times \frac{m \cdot g}{\sqrt{2} } \times \mu}\)
\(\displaystyle Force \ required, \ F = 2 \times \frac{m \cdot g}{\sqrt{2} } \times \mu = \mathbf{ \sqrt{2} \cdot \mu \cdot m \cdot g}\)
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A power station that is being started up for the first time generates 6120 MWh of energy over a 10 hour period. (i) If the rated power at full capacity is 660 MW, calculate how long it takes the power station to reach its full power output. (You may assume a constant increase in power from zero to full power) (ii) State what type of power station can be started up fastest and explain why the start-up times for other types of power station are slower. Explain briefly, how this is relevant to optimising the usage of windfarms. c) What is the Bremsstrahlung effect and how can it be avoided in shielding design? d) Sketch the electromagnetic field output from an antenna, describing in detail the two main regions in the output field.
(i)Therefore, it takes approximately 9.27 hours to reach its full power output.(ii)It is necessary to have quick-start power sources, this helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.(c)The Bremsstrahlung effect needs to be considered to ensure proper radiation protection.(d) The near-field region is characterized by strong electric and magnetic fields while the far-field region represents the radiation zone.
(i) To calculate the time it takes for the power station to reach its full power output, we can use the formula:
Energy = Power × Time
Given that the power station generates 6120 MWh of energy over a 10-hour period and the rated power at full capacity is 660 MW, we can rearrange the formula to solve for time:
Time = Energy ÷ Power
Converting the energy to watt-hours (Wh):
Energy = 6120 MWh × 1,000,000 Wh/MWh = 6,120,000,000 Wh
Converting the power to watt-hours (Wh):
Power = 660 MW × 1,000,000 Wh/MW = 660,000,000 Wh
Now we can calculate the time:
Time = 6,120,000,000 Wh ÷ 660,000,000 Wh ≈ 9.27 hours
Therefore, it takes approximately 9.27 hours (or 9 hours and 16 minutes) for the power station to reach its full power output.
(ii) The type of power station that can be started up fastest is a gas-fired power station. Gas-fired power stations can reach full power output relatively quickly because they use natural gas combustion to produce energy.
In contrast, other types of power stations, such as coal-fired or nuclear power stations, have longer start-up times. Coal-fired power stations require time to heat up the boiler and generate steam, while nuclear power stations need to go through a complex series of procedures to ensure safe and controlled nuclear reactions.
This is relevant to optimizing the usage of windfarms because wind power is intermittent and dependent on the availability of wind. This helps maintain a stable and reliable electricity supply even when wind speeds fluctuate.
(c) The Bremsstrahlung effect is a phenomenon that occurs when charged particles, such as electrons, are decelerated or deflected by the electric fields of atomic nuclei or other charged particles. As a result, they emit electromagnetic radiation in the form of X-rays or gamma rays.
In shielding design, the Bremsstrahlung effect needs to be considered to ensure proper radiation protection. These materials effectively absorb and attenuate the emitted X-rays and gamma rays, reducing the exposure of individuals to harmful radiation.
(d) The electromagnetic field output from an antenna can be represented by two main regions:
Near-field region: This region is closest to the antenna and is also known as the reactive near-field. It extends from the antenna's surface up to a distance typically equal to one wavelength. In the near-field region, the electromagnetic field is characterized by strong electric and magnetic field components.
Far-field region: Also known as the radiating or the Fraunhofer region, this region extends beyond the near-field region.The electric and magnetic fields are perpendicular to each other and to the direction of propagation. The far-field region is further divided into the "Fresnel region," which is closer to the antenna and has some characteristics of the near field, and the "Fraunhofer region," which is farther away and exhibits the properties of the far-field.
The transition between the near-field and the far-field regions is gradual and depends on the antenna's size and operating frequency. The size of the antenna and the distance from it determine the boundary between these regions.
In summary, the near-field region is characterized by strong electric and magnetic fields, while the far-field region represents the radiation zone where the energy is radiated away as electromagnetic waves.
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As you travel downhill, your vehicle needs less power to reach the bottom and your stopping _________ increases.
Answer: Distance
Explanation:
When driving, it is important for one to always use safety belt and obey traffic rules.
During a collision, it is vital to always adhere to safety belts and also use occupant protection systems in order to help reduce the impact that an be felt during a collision. As you travel downhill, your vehicle needs less power to reach the bottom and your stopping distance increase.
2. A quantity of gas is trapped by a piston in a cylinder with thin metal walls. The piston is free to move
without friction within the cylinder.
a) The air in the freezer is at atmospheric pressure, which is 1.0 × 105Pa. The area of the piston in
contact with the air in the freezer is 2.4 × 10–3m2
.
i. Calculate the force exerted on the piston by the air in the freezer.
ii. When the cylinder is first placed into the freezer, the temperature of the gas in the cylinder decreases
and the air pushes the piston into the cylinder. Calculate the work done on the piston by the air in the
freezer as the air pushes the piston at distance of 0.021m into the cylinder.
b) The initial temperature of the cylinder and the gas is 21°C and, in the freezer, the temperature of the
cylinder decreases to –18°C. The thermal capacity of the cylinder is 89J/ °C. Calculate the change in
the internal energy of the cylinder.
a)
i. The force exerted on the piston by the air in the freezer is 240 N.
ii. The work done on the piston by the air as it pushes the piston 0.021 m into the cylinder is 5.04 J.
b) The change in the internal energy of the cylinder is 3486 J.
a)
i. To calculate the force exerted on the piston by the air in the freezer, we can use the formula:
Force = Pressure * Area
Given:
Pressure (P) = 1.0 × \(10^5\) Pa
Area (A) = 2.4 ×\(10^(^-^3^) m^2\)
Substituting these values into the formula, we have:
Force = (1.0 × 10^5 Pa) * (2.4 ×\(10^(^-^3^) m^2)\)
= 240 N
ii. To calculate the work done on the piston by the air in the freezer as the air pushes the piston, we can use the formula:
Work = Force * Distance
Given:
Force = 240 N
Distance (d) = 0.021 m
Substituting these values into the formula, we have:
Work = (240 N) * (0.021 m)
= 5.04 J
b) To calculate the change in the internal energy of the cylinder, we can use the formula:
ΔU = mcΔT
Given:
Initial temperature (T1) = 21°C = 21 + 273 = 294 K
Final temperature (T2) = -18°C = -18 + 273 = 255 K
Thermal capacity (c) = 89 J/°C
Substituting these values into the formula, we have:
ΔU = (89 J/°C) * (294 K - 255 K)
= 3486 J
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a merry-go-round rotates at the rate of 0.1 rev/s with an 97 kg man standing at a point 1.6 m from the axis of rotation. what is the new angular speed when the man walks to a point 0 m from the center? consider the merry-go-round is a solid 72 kg cylinder of radius of 1.6 m. answer in units of rad/s.
The new angular speed when the man walks to a point 0m from the center is ω = 0.369 rev/s.
What Is Angular Speed?The definition of angular speed is the rate at which angular displacement changes, and it is expressed as,
ω=θ/t
where t is the period of time, is the angular speed, and ω is the angular displacement.
Angular Speed UnitRadian per second is used to measure angular speed. Both angular velocity and angular speed are represented using the same formula.
Now for the given question,
Since there is no external torque, angular momentum of the system is conserved. Then, the angular momentum when the man is at x = 1.6 m, it is equal to that of x = 0 m.
\(L_1=L_2\\I_1ω_1=I_1ω_2\)
where I is the moment of inertia of the system. Here we consider the merry-go-round which is a solid cylinder and the man which can be regarded as a point object.
Total moment of inertia in first case is
\(I_1=I_{cylinder}+ I_{man}= 1/2 m_{cylinder}R^2_{cylinder}+m_{man}d^2\\ = 1/2 (72)(1.6)^2+(97)(1.6)^2=340.48\)
moment of inertia in second case is
\(I_2=1/2 m_{cylinder}R^2_{cylinder}+ m_{man}(0)\\=1/2(72)(1.6)^2=92.16\)
In the second case, the man shows no contribution to the moment of inertia of the system, since he stands on the center.
Finally,
\(I_1ω_1=I_2ω_2\\(340.48)(0.1)=(92.16)ω_2\\ω_2=0.369 rev/sec.\)
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What is another way to describe the vector below?
"40 feet to the right"
A. 40 feet to the left
B. -40 feet to the left
C. -40 m to the left
D. 40 m to the left
Answer:
-40 feet to the left
Explanation:
opposite of 40 feet from right is -40 to left
Answer:
B. -40 feet to the left
How might a behaviorist explain why some people pretend to be ill to get sympathy?
In an RLC series circuit, the rms potential difference provided by the source is V = 210 V, and the frequency is f = 250 Hz. Given that L = 0.35 H, C = 70 uF, and VR = 45 V, find: , = 3 a) I (rms); I 1.962331945 = A b) R; R = 44.65985162 12 c) VL (rms); Vi 176.3328743 V d) Vc (rms). VCE = 28.78760123 V
Answer:
The rms voltage across the capacitor is approximately 224.926 V.
a) To find the rms current (I) in the RLC series circuit, we can use the formula:
I = V / Z
Where V is the rms potential difference provided by the source, and Z is the impedance of the circuit.
The impedance of an RLC series circuit is given by:
Z = √(R^2 + (Xl - Xc)^2)
Where R is the resistance, Xl is the inductive reactance, and Xc is the capacitive reactance.
V = 210 V
f = 250 Hz
L = 0.35 H
C = 70 uF
VR = 45 V
First, let's calculate the reactances:
Xl = 2πfL
Xc = 1 / (2πfC)
Substituting the values:
Xl = 2π * 250 * 0.35
Xc = 1 / (2π * 250 * 70e-6)
Calculating:
Xl ≈ 549.78 Ω
Xc ≈ 114.591 Ω
Next, we can calculate the impedance:
Z = √(R^2 + (Xl - Xc)^2)
Substituting the given VR value, we have:
VR = I * R
Rearranging the equation to solve for R:
R = VR / I
Substituting the given values:
45 = I * R
Solving for R:
R = 45 / I
Substituting the values of Xl and Xc into the impedance equation:
Z = √(R^2 + (549.78 - 114.591)^2)
Substituting the value of Z into the formula for rms current:
I = V / Z
Calculating:
I ≈ 1.962331945 A
Therefore, the rms current in the RLC series circuit is approximately 1.962 A.
b) The resistance (R) in the circuit can be found using the equation:
R = VR / I
Substituting the given values:
R = 45 / 1.962331945
Calculating:
R ≈ 22.943 Ω
Therefore, the resistance in the RLC series circuit is approximately 22.943 Ω.
c) The rms voltage across the inductor (VL) can be calculated using the formula:
VL = I * Xl
Substituting the values:
VL = 1.962331945 * 549.78
Calculating:
VL ≈ 1,076.644 V
Therefore, the rms voltage across the inductor is approximately 1,076.644 V.
d) The rms voltage across the capacitor (Vc) can be calculated using the formula:
Vc = I * Xc
Substituting the values:
Vc = 1.962331945 * 114.591
Calculating:
Vc ≈ 224.926 V
Therefore, the rms voltage across the capacitor is approximately 224.926 V.
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A remote controlled plane accelerates to a velocity of 21.0 m/s while covering a distance of 87.4 m in 6.11 s. What was the plane's initial velocity?
Answer:
7.61 m/s
Explanation:
Given:
Δx = 87.4 m
v = 21.0 m/s
t = 6.11 s
Find: v₀
Δx = ½ (v + v₀) t
87.4 m = ½ (21.0 m/s + v₀) (6.11 s)
v₀ = 7.61 m/s
71.6
Δx = 87.4 m
v = 21.0 m/s
t = 6.11 s
Find: v₀
Δx = ½ (v + v₀) t
87.4 m = ½ (21.0 m/s + v₀) (6.11 s)
v₀ = 7.61 m/s
Refraction of a light ray may be defined as
A. bouncing off the boundary
B. passing through the boundary
C. maintaining speed after a boundary
D. changing direction while crossing a boundary
Answer:
Explanation:
Refraction of a light ray may be defined as:
D. changing direction while crossing a boundary
A 3.0-kg meatball is moving with a speed of 6.0 m/s directly toward a 2.0 kg meatball which is at rest. The two meatballs collide and stick together. What is their velocity immediately after the (inelastic) collision?
18 m/s
3.6 m/s
6 m/s
5 m/s
Answer:
Their common velocity after collision is 3.6 m/s
Explanation:
Given;
mass of the first meatball, m₁ = 3.0 kg
initial velocity of the first meatball, u₁ = 6.0 m/s
mass of the second meatball, m₂ = 2.0 kg
initial velocity of the first meatball, u₂ = 0 m/s
let their common velocity after collision = v
Apply the principle of conservation of linear momentum for inelastic collision ;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(3 x 6) + (2 x 0) = v( 3 + 2)
18 = 5v
v = 18 / 5
v = 3.6 m/s
Therefore, their common velocity after collision is 3.6 m/s
A 1167 kg car is driving along a highway with 458,350 J of kinetic energy.
What is its speed?
The speed of the car having kinetic energy 458,350 J is 28.03m/s
What is What is Kinetic Energy ?
Kinetic energy is a type of power that a moving object or particle possesses. An item accumulates kinetic energy when work, which involves the transfer of energy, is done on it by exerting a net force. A moving object or particle has kinetic energy, which depends on both its mass and its rate of motion. The type of motion can be vibration, rotation on an axis, translation (or travel along a path from one place to another), or any combination of these.
K.E = 1/2*m*v2
K.E = kinetic energy
m = mass
v = velocity/speed
458350 = 1/2*1167*v2
v2= 458350*2/1167
v = 28.03 m/s
The speed of the car having kinetic energy 458,350 J is 28.03m/s
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A 300 kg snowmobile is traveling at 30 m/s. How fast would a 200 kg snowmobile need to travel to have
the same momentum?
A 200 kg snowmobile having the same momentum will travel at 45 m/s.
What is momentum?Momentum of an object is the product of mass and speed of an object.
P = mv
where;
m is mass of the objectv is speed of the objectm₁v₁ = m₂v₂
v₂ = m₁v₁/m₂
v₂ = (300 x 30)/200
v₂ = 45 m/s
Thus, a 200 kg snowmobile having the same momentum will travel at 45 m/s.
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What is the measure of the average kinetic energy of the particles in a material known as?
A. heat transfer B. radiation
C. temperature
D. thermal expansion
Answer:
The answer is temperature
constriction is made in a clinical thermometer why
subject :science (energy)
Answer:
The constriction in the thermometer is to prevent the mercury from dropping back to the bulb when the reading is being taken. It is easier for us to take reading. It prevents the thermometric substance (Mercury or Alcohol) from running back into the bulb.
Explanation:
Hope it is helpful....
Answer:
constriction is made in a clinical thermometer because it prevents the thermometric liquid from running back into the bulb.
When a bulb is connected to a 12V cell a current of 0.05A flows through the bulb.
What is the resistance of the bulb?
Use the equation
resistance (R) = (V) voltage/ (I) current
A 0.6 Ω
B 6 Ω
C 24 Ω
D 240 Ω
Answer:
=0.6
Explanation:
R=v*I
R=12*0.05
R=0.6
sonet’s extraordinary ____ results from its use of a double-ring topology over fiber-optic cable.
SONET, or Synchronous Optical Network, is a high-speed communication technology used for transmitting large volumes of data over fiber-optic cables. SONET's extraordinary performance results from its use of a double-ring topology, which provides a high level of redundancy and fault tolerance.
In a double-ring topology, two separate rings are formed, with data being transmitted in opposite directions on each ring. This redundancy ensures that if one ring is broken or damaged, data can still be transmitted through the other ring, ensuring uninterrupted communication.
Additionally, SONET uses fiber-optic cables, which have a much higher bandwidth than traditional copper cables, enabling faster data transmission rates. The use of fiber-optic cables also ensures that data is transmitted over long distances without any loss of signal strength, making it ideal for long-haul communication.
Overall, SONET's extraordinary results are due to its combination of a double-ring topology and fiber-optic cables, which provide a high level of reliability, fault tolerance, and fast data transmission rates, making it a popular choice for high-speed data communication networks.
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Two wires are identical, except that one is aluminum and one is copper. The aluminum wire has a resistance of 0.263Ω. What is the resistance of the copper wire? Take the resistivity of copper to be 1.72 x 10^-8 Ω·m, and that of aluminum to be 2.82 x 10^-8 Ω·m.
The resistance of the copper wire is 0.161 Ω. The resistance of a material depends on various factors, including its length, cross-sectional area, and temperature.
What is Resistance?
Resistance is a measure of how much a material opposes the flow of electric current. It is defined as the ratio of the voltage applied to a conductor to the current flowing through it, and is measured in ohms (Ω). Materials with high resistance are poor conductors of electricity, while materials with low resistance are good conductors.
We can use the formula for resistance of a wire:
R = (ρ * L) / A
where R is resistance, ρ is resistivity, L is length of the wire, and A is its cross-sectional area.
We know that the wires are identical, so they have the same length and cross-sectional area. Therefore, their resistances are proportional to their resistivities:
R_aluminum / R_copper = ρ_aluminum / ρ_copper
We can rearrange this to solve for the resistance of the copper wire:
R_copper = R_aluminum * ρ_copper / ρ_aluminum
Plugging in the given values, we get:
R_copper = 0.263 Ω * (1.72 x 10^-8 Ω·m) / (2.82 x 10^-8 Ω·m) = 0.161 Ω
Therefore, the resistance of the copper wire is 0.161 Ω.
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Two objects with negative charges of 6.2 nC each are separated by 0.3 m. What is the size and direction of the force between the two charges?
The force between the charges are \(3844*10^{3} N\)
Before we try to calculate Coulomb's law for forces between multiple charges, we need to understand Coulomb's force between two charged particles. Coulomb’s law or Coulomb’s inverse square law was discovered in 1785 by French physicist Charles-Augustin de Coulomb. The experimentally proven law quantifies the force exerted by a static charged particle on another static charged particle.Assume two static charged particles with a charge of ‘q1’ and ‘q2’ respectively. The force exerted by one particle on the other, if they are separated by a distance of ‘r’ between their centers is given by:\(F = kQq/r^{2}\)
Given, Q = q = 6.2 mC = \(6.2 * 10^{-3}\)
r = distance = 0.3m
k = constant = \(9*10^{9}\)
Putting these values in above equation we get F = \(3844*10^{3} N\)
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how many bulldogs to beat 43 dragonss if each bulldog can beat 10 dragons
Answer:
5 bulldogs
Explanation:
you need 4 bulldogs to beat 40 dragons, but since you would still need 3 dragons defeated, you would need another bulldog
a boat travels at 2.0 m s-1 east towards a port, 2.2 km away. when the boat
reaches the port, the passengers travel in a car due north for 15 minutes at 60
km h-1.
calculate:
a. the total distance travelled
b. the total displacement
c. the total time taken
d. the average speed in m s-1
e. the magnitude of the average velocity
a. The total distance travelled is 17.2 km.
b. The total displacement is 15.16 km.
c. The total time taken is 901.1 s.
d. The average speed in m/s is 19.07 m/s.
e. The magnitude of the average velocity is 16.8 m/s.
To calculate the quantities, we need to convert units to ensure consistency.
a. To find the total distance travelled, we sum the distances travelled by boat and car. The boat travels 2.2 km, and the car travels (60 km/h) × (15 min) × (1/60 h/min) = 15 km.
Therefore, the total distance travelled is 2.2 km + 15 km = 17.2 km.
b. The total displacement is the straight-line distance between the starting point and the final destination, taking direction into account. The boat moves east, and the car moves north.
Thus, the displacement is given by the Pythagorean theorem as √((2.2 km)² + (15 km)²) = √(4.84 km² + 225 km²) = √(229.84 km²) ≈ 15.16 km.
c. The total time taken is the sum of the time taken by the boat and the car. The boat takes (2.2 km) / (2.0 m/s) = 1.1 s. The car takes (15 min) × (60 s/min) = 900 s. Thus, the total time taken is 1.1 s + 900 s = 901.1 s.
d. The average speed is given by the total distance travelled divided by the total time taken. Converting km to meters, we have (17.2 km) × (1000 m/km) = 17200 m.
Therefore, the average speed is 17200 m / 901.1 s ≈ 19.07 m/s.
e. The magnitude of the average velocity is the absolute value of the displacement divided by the total time taken.
Thus, the magnitude of the average velocity is 15.16 km / 901.1 s ≈ 0.0168 km/s ≈ 16.8 m/s.
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Identify the following physical quantities as scalars or vectors.speeddistancevelocitypositiondisplacementaverage velocityacceleration
Speed, distance, and position are scalar quantities, while velocity, displacement, average velocity, and acceleration are vector quantities.
Speed refers to how fast an object is moving and is a scalar quantity, with only magnitude, without direction. Distance is a scalar quantity that refers to the amount of space between two points, also having only magnitude.
Position is a scalar quantity that refers to the location of an object in space and also has only magnitude.
Velocity, on the other hand, is a vector quantity, as it has both magnitude and direction. It is the rate of change of an object's position over time.
Displacement is another vector quantity, and it refers to the change in position of an object from its starting point.
Average velocity is a vector quantity that is the average of all velocity changes during a certain time interval.
Acceleration is also a vector quantity and refers to the rate of change of velocity. It measures how quickly the velocity of an object changes, and like velocity, it has both magnitude and direction.
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On average how fast does the radiation spread from an atom-bomb?
Answer:
around 30 grays
Explanation:
Hope this helps :)
Rock layer that must be rich in organic matter that was subjected to heat and pressure overtime during the formation of oil and natural gas
The lowest rock layer is a layer that must be rich in organic matter that was subjected to heat and pressure over time during the formation of oil and gas.
The lowest rock layer can be explained as;
The lowest rock layer refers to the lowermost part of the Earth's mantle, which is a thin rock layer (approximately 250 km).
In the Earth, the layers of rocks are progressively deposited, thereby pressing them to the bottom to generate sedimentary rocks.
The lowest rock layers on the bottom must be rich in organic matter to form fossil fuels.
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True/false: dark nebulae are opaque to all wavelengths of electromagnetic radiation.
The answer is False, dark nebulae are not opaque to all wavelengths of electromagnetic radiation. Dark nebulae are interstellar clouds of dust and gas that obscure the light from stars and other celestial objects behind them, primarily in the visible light spectrum.
However, they do allow certain wavelengths of electromagnetic radiation to pass through, particularly longer wavelengths such as infrared and radio waves. Observations in these wavelengths enable astronomers to study the structures and properties of dark nebulae, as well as the star formation processes occurring within them. In summary, dark nebulae are not completely opaque to all forms of electromagnetic radiation, but rather selectively absorb and scatter specific wavelengths, particularly visible light.
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-A 180 kg hippo is riding a bicycle at a speed of 6.0
m/s. Out of nowhere, a chimpanzee runs out in the
hippo's path and he must slam on his brakes. If the
bicycle's brakes exert a force of 1600 N, how
long will it take to stop the bicycle? _s
Answer:
0.0675 seconds
Explanation:
From the question,
We apply newton's second law of motion
F = m(v-u)/t.................... Equation 1
Where F = force exert by the brake, v = final speed, u = initial speed m = mass of the bicycle, t = time.
make t the subject of the equation
t = m(v-u)/F................... Equation 2
Given: m = 180 kg, u = 6.0 m/s, v = 0 m/s (comes to stop), F = -1600 N ( agianst the dirction of motion)
Substitute these value into equation 2
t = 180(0-6.0)/-1600
t = -1080/-1600
t = 0.0675 seconds.
A family drives north for 30km then turns east for 20km. The family then decided to turn west for 5km before finally stopping to take a break. Which of the following is true?
A) the distance driven is more than the displacement.
B) the displacement is more than the distance driven.
C) the distance driven and the displacement are the same.
Answer:
A
Explanation:
They drove 30km north. The displacement adds up to 25km therefore making the distance greater
Hope this helps!
What small lifestyle change can you make to have a positive impact on your physical exercise?
Use technology to make simple chores even easier.
Choose a tech activity that gets your body moving.
Drive to a neighbor's house instead of walking there.
Choose a tech activity that helps you be more stationary.
Along with your family, plan nutritious meals, or establish a weekly healthy potluck at work. I don't enjoy exercising. Discard the outdated idea that exercising involves weightlifting at a gym.
What lifestyle modifications are beneficial?The six fundamental lifestyle habits for a long, good health include sleeping enough, eating a good food, exercising, keeping a healthy weight, quitting smoking, and drinking in moderation.
What are five healthy lifestyle activities?Walking, cycling, skating, sports, active recreation, and play are all common methods to be active that anyone may do for fun and at any ability level. It has been demonstrated that regular exercise helps control and prevent noncommunicable diseases like diabetes, heart disease, stroke, and a number of malignancies.
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what types of electromagnetic radiation does the sun emit?
Answer:
https://gml.noaa.gov/education/info_activities/pdfs/LA_radiation.pdf
Explanation:
when you plug your cell phone into an electrical outlet to recharge it, you are using energy for a industry. b commercial use. c residential use. d transportation.
When you plug your cell phone into an electrical outlet to recharge it, you are using energy for c) residential use.
This is because the electricity is being consumed in a household setting for personal use. Commercial use would be if the energy was being used in a business or commercial setting, and transportation would involve using energy for moving vehicles. So, the long answer is that plugging your cell phone into an electrical outlet for charging purposes falls under the category of residential use of energy.
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Which planetary body has the fastest orbit, and which has the slowest orbit? Do you notice a general pattern here? Briefly explain a relationship between orbital velocity and orbital radius.
The planetary body with the fastest orbit is Mercury, and the one with the slowest orbit is Neptune.
There is a general pattern between orbital velocity and orbital radius known as Kepler's second law of planetary motion. According to this law, a planet sweeps out equal areas in equal times as it orbits the Sun. This implies that planets closer to the Sun have smaller orbital radii and must travel faster to cover the same area in the same amount of time.
The relationship between orbital velocity and orbital radius can be expressed as v ∝ 1/r, where v represents the orbital velocity and r denotes the orbital radius. This relationship shows that as the orbital radius increases, the orbital velocity decreases. In other words, planets farther from the Sun have slower orbital velocities compared to those closer to the Sun.
This pattern is consistent with observations in our solar system. The inner planets, such as Mercury, have smaller orbital radii and faster orbital velocities, while the outer planets, like Neptune, have larger orbital radii and slower orbital velocities.
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