What is electricity?
Answers
Answer:Electricity is the flow of electrons. All matter is made up of atoms, and an atom has a center, called a nucleus. When electrons are "lost" from an atom, the free movement of these electrons constitutes an electric current. Electricity is a basic part of nature and it is one of our most widely used forms of energy.
Explanation:
Answer:
Electricity is the set of physical phenomena associated with the presence and motion of matter that has a property of electric charge. Various common phenomena are related to electricity, including lightning, static electricity, electric heating, electric discharges and many others.a form of energy resulting from the existence of charged particles (such as electrons or protons), either statically as an accumulation of charge or dynamically as a current.
Explanation:
Related Questions
For motion along a straight line it ______ possible for speed to be constant while acceleration is not zero.
Answers
For motion along a straight line it NOT possible for speed to be constant while acceleration is not zero.
If the acceleration is not zero means that the speed has changed whether to higher (positive acceleration) or lower (negative acceleration) if the object is slowing down.
When the speed is constant, it means that the velocity at the beginning of the motion and the velocity at the ending of the motion are the same.
What is acceleration?It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
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A tugboat is pulling a barge into a harbor. The barge is exerting a force of 3000 N against the tugboat. Which force would most likely allow the tugboat to move the barge into the harbor? –4500 N –2500 N 2500 N 4500 N
Answers
Answer:
the correct one is F’= 4500 N
Explanation:
To solve this problem we must use Newton's second law
where F₁ is the force of the barge F₁ = 3000N and the force of the tugboat is F '
F '- F₁ = m a
we substitute
F '- 3000 = m a
the mass is always a positive quantity, therefore if we want the tug to pull the barge
F ’-3000> 0
when you check it, you respect the correct one is F’= 4500 N
Answer:
The answer is -4500 N
Explanation:
I just got it right on the test
A ball of mass m is attached to a string of length L. It is being swung in a vertical circle with enough speed so that the string remains taut throughout the ball's motion. Assume that the ball travels freely in this vertical circle with negligible loss of total mechanical energy. At the top and bottom of the vertical circle, the ball's speeds are v_t and v_b, and the corresponding tensions in the string are T_t and T_b. T_t and T_b (vectors) have magnitudes T_t and T_b.
Find T_b - T_t, the difference between the magnitude of the tension in the string at the bottom relative to that at the top of the circle.
Express the difference in tension in terms of m and g. The quantities v_t and v_b should not appear in your final answer.
Answers
The difference in tension in terms of m and g is given by T_b - T_t = 2mg
To find the difference in tension T_b - T_t, we will first analyze the forces acting on the ball at the top and bottom of the circle and then compare the magnitudes.
1. At the top of the circle:
- The tension force T_t is acting downward.
- The gravitational force mg is also acting downward.
The net force at the top is the sum of these forces:
F_t = T_t + mg
2. At the bottom of the circle:
- The tension force T_b is acting upward.
- The gravitational force mg is acting downward.
The net force at the bottom is the difference of these forces:
F_b = T_b - mg
Since the total mechanical energy is conserved, we can equate the centripetal forces acting on the ball at the top and bottom of the circle:
\(m(v_t^2) / L = m(v_b^2) / L\)
As we can see, the mass m and length L cancel out:
\(v_t^2 = v_b^2\)
Now we can relate the forces to the centripetal acceleration:
At the top: \(F_t = m(v_t^2) / L\)
At the bottom: \(F_b = m(v_b^2) / L\)Substituting the expressions for F_t and F_b, we get:
\(T_t + mg = m(v_t^2) / L\)
\(T_b - mg = m(v_b^2) / L\)
Since \(v_t^2 = v_b^2\), we can set the centripetal forces equal to each other:
m(v_t^2) / L = m(v_b^2) / L
Now subtract the equation for the forces at the top from the equation for the forces at the bottom:
(T_b - mg) - (T_t + mg) = 0
Simplifying the equation, we get:
T_b - T_t = 2mg
So, the difference between the magnitude of the tension in the string at the bottom relative to that at the top of the circle is 2mg.
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Which wave has a longer wavelength?
Answers
How long will it take a projectile to hit the ground from a 400 m tall cliff when launched at 30 m/s horizontally?
19.55 sec
13.33 sec
9.03 sec
4.54 sec
Fast reply if possible
Answers
Explanation:
A string under a tension of 170 N has a frequency of 300 Hz.What will its frequency become if the tension is increased to 340 N?
Answers
The speed of the wave on a string is given by Taylor's formula:
\(v=\sqrt[]{\frac{F}{\mu}}\)where
F = tension force
μ = linear density = mass per unit length
But also we can say the speed of any wave is given by:
\(v=\lambda\times f\)where:
λ = wave length
f = frequency
Plug the second equation in the first one. We get:
\(\lambda\times f=\sqrt[]{\frac{F}{\mu}}\)Now solve for f:
\(f=\frac{1}{\lambda}\times\sqrt[]{\frac{F}{\mu}}\)Lets say wave length is the same on the second case. Since it's the same string μ will also be the same.
See that 340 N = 2 x 170, so we can write:
\(\begin{gathered} f_{new}=\sqrt[]{2}\times\frac{1}{\lambda}\sqrt[]{\frac{F}{\mu}} \\ f_{new}=\sqrt[]{2}\times f_{old} \\ f_{new}=\sqrt[]{2}\times300 \\ f_{new}\approx424Hz \end{gathered}\)Kendra wonders what would happen if the oceans did not exist on Earth. Based on her understanding of the oceans and the water cycle she predicts that Earth would become warmer, with less rain, more clouds, and that living things would not survive. Which part of her prediction is incorrect?
That living things would not survive
That Earth would get warmer
That there would be less rain
That there would be more clouds
Answers
Kendra's prediction that living things would not survive is not necessarily correct.
While the absence of oceans would certainly have a significant impact on Earth's climate and weather patterns, it does not necessarily mean that all living things would perish.
The presence of oceans has a significant impact on Earth's climate and weather patterns. They absorb and store large amounts of solar energy, which helps to regulate the planet's temperature and maintain a stable climate. They also play a key role in the water cycle, which is essential for providing fresh water to plants and animals.
Without oceans, the Earth would likely experience more extreme temperatures and weather patterns, with hotter and drier conditions in some areas, and cooler and wetter conditions in others. This could lead to significant changes in ecosystems and the distribution of plant and animal species.
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a generator is connected to a resistor and a 0.027-h inductor in series. the rms voltage across the generator is 9.2 v. when the generator frequency is set to 180 hz, the rms voltage across the inductor is 3.2 v. determine the resistance of the resistor in this circuit.
Answers
The resistance of the resistor in this circuit is 82.31 Ohms
How to solve for the resistanceWe would first have to solve for the angular frequency
ω = 2π* f
f = 180 hz
= 2* 3.14 * 180
= 1130.4
Next we would have to solve for the Inductive reactance XL = ω* L
= 1130.4 * 0.027
= 30.52
The current is
3.2 v / 30.52
= 0.1048
Impedance Z = V/ I
9.2 v / 0.1048
= 87.79
To get the resistance we would have to use
Z² = (R² + XL²)
87.79² = R² + 30.52²
R² = 87.79² - 30.52²
= 7707.08 - 931.47
= 6775.6
R = √6775.6
= 82.31 ohms
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Introduction
Understanding the relationship between form and function in organisms can increase our knowledge about natural processes, especially when it comes to investigating how physical laws apply to the adaptive design of organisms. The mode of locomotion plays a major role in the evolution of many body traits. Most terrestrial organisms walk or run upright on horizontal surfaces. Organisms that climb on vertical surfaces or hang from objects most likely evolved, through natural selection, specialized modes of locomotion to optimize ease and rate of movement.
In order to move, animals need to "build up" energy and then use that energy in a controlled way. One way to do that is through the interchange of kinetic and gravitational potential energy. One method to do this is an animal moving forward over a stiffened leg. In the initial part of the cycle, some of the kinetic energy used to propel the animal forward also raises its center of mass, increasing its gravitational potential energy. As the center of mass falls, gravitational potential energy is converted back into kinetic energy which facilitates the next step. This is called the inverted pendulum model (Figure 1).
What specific and measurable hypotheses (at least two) can you develop that are supported by the information presented and that address the basic question of this study?
Answers
Answer:
As the locomotion of organisms depends upon the interchange of kinetic and potential energy, animals that walk upright and have a higher centre of mass will be able to propel themselves higher compared to a shorter animal with each step. Physically, Energy can be written as1/2 mtotal ( ucm² + vcm² + wcm²)+1/2mi {u1-ucm)²+(v1-vcm)²+(w1-wcm)²} + mgh. Where ucm, vcm, wcm are the velocities of centre of mass of each portion.u1,w1,v1 are the velocities of different parts of body relative to COM
Hypothesis 2
Similarly, for the animals having lower centre of mass we can say that they will be better at climbing and traversing trees. An animal with low centre of mass will be able to get maximum traction with tree and it will be harder for it to lose its balance. Hence animals like leopard, sloth, gecko, Red panda etc. all showcase this lower centre of mass. These animals gravitational potential energy is minimum when all feet are on the ground and maximum when the body is raised high above
Their motion can be written in the form dr/dl = -r/2l where r can be written as radius of the torso of the animal. L is length of animals body.
Explanation:
I think this is physics?
A student wants to calculate the density of the two objects shown below:
A Metal Cube and a Small Statue.
Describe the methods that the student should use to calculate the densities of the two objects.
ASAP please this piece of work is already late XD
Answers
Answer:
Okay
Explanation:
First we should quickly remind ourselves of the equation for density:density= mass/ volumeTo calculate the density we need a method of measuring the mass of each object and another method for measuring the volume of each object. To measure the mass in both cases we can simply use a measuring balance. To measure the volume we will need to use 2 separate methods. For the cube we can simply measure the length, height and depth with a ruler, multiply our measurements and we obtain the volume. The statue is a little more tricky because it has an irregular shape so we can't use the ruler anymore. Instead we should use graduated tank/trough of water. First of all measure the amount of water in the tank before putting in the statue. Then submerge the statue in the water and take another measurement of the volume of water in the tank. The statue will displace the water in the tank giving a higher value. We finally subtract the initial volume from the final volume and we should obtain the volume of the statue.We now have all the measurements necessary to calculate the density of both objects!
Can someone pls help me answer this I’ll give brainliest to whoever actually answers it
Answers
Answer:
Limestone classifacation: sedimentary rock
Sandstone: sedimentary rock
Identify the unknown particle(s) X in the following equation for fission. (Enter your answer in the form
AX Z.)
23492U → 13351Sb + 9841Nb + X
Answers
The unknown particle(s) X in the given equation for fission ²³⁴U₉₂ → ¹³³Sb₅₁ + ⁹⁸Nb₄₁ + X is 4 He.
What is nuclear fission?Fission is a nuclear reaction that occurs when the nucleus of an atom splits into two or smaller nuclei, resulting in a release of a significant amount of energy. Nuclear fission is caused by the impact of a high-energy neutron on a target nucleus. When the target nucleus captures the neutron, it becomes unstable and splits into two smaller nuclei, releasing energy and additional neutrons that can cause fission to occur in other atoms.
The unknown particle(s) X in the given equation for fission ²³⁴U₉₂ → ¹³³Sb₅₁ + ⁹⁸Nb₄₁ + X is 4 He.
Therefore, the balanced equation is: ²³⁴U₉₂ → ¹³³Sb₅₁ + ⁹⁸Nb₄₁ + X is 4 He
This equation can also be written in the form of a nuclear equation as:
²³⁴U₉₂ → ¹³³Sb₅₁ + ⁹⁸Nb₄₁ + ⁴He₂
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Which of the following have derived units?
A. 56 kg
B. 2.5 m
C. 87 m/s²
D. 60 N
Answers
Answer:
The answer is C!!!!!!!
Becuz meters and seconds are derived into m/s²
Explanation:
Plss follow me and Mark as brainlest
Thanks :-)
Answer:
C. 87 m/s^2
Hope it helps.
A 432 g sample of 60/27Co has a decay constant of 4.14 x 10-9 s-1. How long will it take before only 1/3 of the original sample remains?
Answers
Answer:
432 60 27 4.14 10 9 1=15000
Moby lifted Tim off the ground a distance of 2 meters using a force of 2N. How much work did Moby do?
Answers
Answer:
4 J
Explanation:
As I guess,
From the equation,
work done = force × distance travelled
= 2 × 2
= 4 J
There are no conversions since all are given in the standard form.
the head of a nail is 0.39 cm0.39 cm in diameter. you hit it with a hammer with a force of 27 n.27 n. what is the pressure pheadphead on the head of the nail?
Answers
The pressure is 22.59 x 10⁵ Pa.
We need to know about pressure to solve this problem. Pressure is unit that describe how much force applied on a surface area. It can be determined as
P = F / A
where P is pressure, F is force and A is area.
From the question above, we know that
d = 0.39 cm = 0.0039 m
F = 27 N
Calculate the surface area of the nail
A = π . r²
A = π . (1/2 . d)²
A = π . (1/2 . 0.0039)²
A = 1.195 x 10¯⁵ m²
Determine the pressure
P = F / A
P = 27 / (1.195 x 10¯⁵ )
P = 22.59 x 10⁵ Pa
Hence, the pressure is 22.59 x 10⁵ Pa.
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Are three coefficients of expansion alpha bita and gamma universal constant?
Answers
Answer:
As the temperature increases, the volume of the material also increases. This is known as thermal expansion. It can also be explained as the fractional change in the length or volume per unit change in the temperature.
The relation between alpha, beta, and gamma is given in the form of a ratio and the ratio is 1:2:3 and can be expressed as:
alpha=fracbeta2=fracgamma3
Following is the relation between the three:
L = L (1 + α.ΔT)
Where, α is the coefficient of linear expansion
A = A (1 + β.ΔT)
Where, β is the coefficient of aerial expansion
V = V (1 + γ.ΔT)
Where, γ is the coefficient of cubical expansion
V = V + γV.ΔT
V = V (1 + γ.ΔT)
L3 = L3 (1 + α.ΔT)3
L3 = L3 (1 + 3α.ΔT + 3α2.ΔT2 + α3.ΔT3)
L3 = L3 (1 + 3α.ΔT)
Alpha, beta, and gamma are related to one another in the form of a ratio, and that ratio is 1:2:3, and yes they are universal constants.
What is expansion?A substance's volume expands while its mass stays constant. Heating is typically the cause of expansion. When a substance is heated, the molecular bonds separating its particles weaken, the particles move more quickly, and the substance expands as a result.
Determine the relation as shown below,
L = L (1 + α × Δ T)
here, α is the coefficient of linear expansion
A = A (1 + β × Δ T)
here, β is the coefficient of aerial expansion
V = V (1 + γ × Δ T)
here, γ is the coefficient of cubical expansion
V = V + γ × V × Δ T
V = V (1 + γ × ΔT)
L3 = L3 (1 + α × Δ T)3
L3 = L3 (1 + 3α × ΔT + 3α2 × ΔT2 + α3 × ΔT3)
L3 = L3 (1 + 3α × Δ T)
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As the alternating current through a conductor increases, an expanding and collapsing electromagnetic field through the conductor produces a voltage within the conductor. this is known as:_____
Answers
As the alternating current through a conductor increases, an expanding and collapsing electromagnetic field through the conductor produces a voltage within the conductor. this is known as electromagnetic induction.
As the alternating current through a conductor increases, an expanding and collapsing electromagnetic field through the conductor produces a voltage within the conductor. This process is known as electromagnetic induction, which is a fundamental principle in physics and electrical engineering. It describes the generation of an electric current in a conductor when it is exposed to a changing magnetic field. This phenomenon is the basis for various applications, including generators, transformers, and induction coils. Electromagnetic induction plays a crucial role in the functioning of many electrical devices and is a fundamental concept in the study of electromagnetism.
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What would happen to your blood in space without a spacesuit?
Answers
Pls give full explanation!
Answers
1. The part that shows the body is accelerating is the first 2 hours (ABE). The acceleration is 20 Km/h²
2. The part that shows the body is coming to rest the last 2 hours (CDF)
3. The distance travelled in the first 2 hours is 40 Km
1. How to determine the accelerated motionAcceleration is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the timeFrom the diagram (ABE), we can see that the body starts from rest and attain a final velocity (40 Km/h) within the first 2 hours. This clearly indicates that the body is accelerating.
The acceleration can be obtained as followed:
Initial velocity (u) = 0 Km/hFinal velocity (v) = 40 Km/hTime (t) = 2 hoursAcceleration (a) = ?a = (v – u) / t
a = (40 – 0) / 2
a = 20 Km/h²
2. How to determine the part showing the body is coming to restFrom the diagram (CDF), we can see that the object velocity changes from 40 to 0 within the last 2 hours. This clearly indicates that the object caming to rest.
3. How to determine the distance travelled in the first 2 hours Initial velocity (u) = 0 Km/hFinal velocity (v) = 40 Km/hTime (t) = 2 hoursAcceleration (a) = 20 Km/h²Distance (s) = ?v² = u² + 2as
v² = 2as
s = v² / 2a
s = 40² / (2 × 20)
s = 40 Km
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A cheerleader launches a t-shirt from an air gun.The shirt leaves the gun at with a speed of 29m/s.
A. Ignoring air resistance, how long would it take the shirt to reach the top of it arc?
B. Ignoring air resistance, if the cheerleader launches with an intial height of 1.75m, what is the maximum height reached by the shirt?
Answers
With the use of vertical motion formula, the shirt will take 3 s to reach the top of its arc. And the maximum height reached is 44.7 m
Motion Under GravityThe motion of an object under is the vertical motion of the object under the influence of acceleration due to gravity.
Given that a cheerleader launches a t-shirt from an air gun. The shirt leaves the gun with a speed of 29 m/s.
A. Ignoring air resistance, the time it will take the shirt to reach the top of its arc can be found by using the equation
v = u - gt
Where
final velocity v = 0 at maximum heightinitial velocity u = 29 m/sacceleration due to gravity g = 9.8 m/s²time t = ?Substitute all the parameters into the equation
0 = 29 - 9.8t
9.8t = 29
t = 29/9.8
t = 2.96 s
t = 3 s approximately
B. Ignoring air resistance, if the cheerleader launches with an initial height of 1.75m, let us first calculate the maximum height reached by the shirt by using the formula
v² = u² - 2gH
At maximum height, v = 0
0 = 29² - 2 × 9.8 × H
0 = 841 - 19.6H
19.6H = 841
H = 841/19.6
H = 841/19.6
H = 42.9 m
The maximum height reached = 42.9 + 1.75 = 44.7 m
Therefore, the time taken for the shirt to reach the top of its arc is 3 s and the maximum height reached is 44.7 m
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find the lateral area and surface area of a right rectangular prism with height of 7 inches, length 3 inches, and width 4 inches.
Answers
The lateral area of the prism is 98 square inches and the surface area is 122 square inches.
What is the lateral area and surface area?To find the lateral area and surface area of a right rectangular prism with height 7 inches, length 3 inches, and width 4 inches, we can use the following formulas:
Lateral area = 2h(l + w)
Surface area = 2lw + 2lh + 2wh
Plugging in the given values, we get:
Lateral area = 2(7)(3 + 4) = 2(7)(7) = 98 square inches
Surface area = 2(3)(4) + 2(3)(7) + 2(4)(7) = 24 + 42 + 56 = 122 square inches
Therefore, the lateral area of the prism is 98 square inches and the surface area is 122 square inches.
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Using F=mXa
1.
Maria's bicycle has a mass of 18.0 kg. What is the net force needed to attain the
acceleration of 1.62 m/s2?
Answers
Answer:
29.16 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 18 × 1.62
We have the final answer as
29.16 NHope this helps you
Explain how the Sun's gravitational force affects Earth even though the Sun is 93 million miles away.
Answers
Answer:
Perfect distance away makes it suitable for life
Explanation:
The Sun's gravitational pull helps to control tides on earth and also to keep the earth in a curvilinear motion.
What is gravity?Gravity, or gravitation, is a natural phenomenon in which all entities with mass or energy are drawn to one another, including planets, stars, galaxies, and even light.
The gravitational pull of the sun continuously pulls the earth towards it, although because of the fast movement of the earth we never reach towards the sun instead we revolve around it.
Despite the fact that the sun's gravitational pull is neutralised by the movement of the earth in a curve, there is still some gravitational pull that exists which helps to control the tides on earth.
Thus, the Sun's gravitational pull helps to control tides on earth and also to keep the earth in a curvilinear motion.
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PLS HELP
What is the gravitational force acting on a 53 kg object standing on the surface of the Earth?
a) 5.3 N
b) 63N
c)48N
d) 530N
Answers
Answer:
D.
Explanation:
DId the test
The gravitational force acting on the body of mass 53 Kg on earth will be 530 Newtons.
What is Weight ?
Weight is the force exerted by earth on a body on the surface of earth. Mathematically -
W = mg
Given is a 53 kg object standing on the surface of the Earth.
The gravitational force acting on the body will be same as it weight and will be directed towards the center of earth. Using the formula for weight -
W = mg = 53 x 10 = 530 N [taken g = 10 m/s²]
Therefore, the gravitational force acting on the body of mass 53 Kg on earth will be 530 Newtons.
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The shadow produced by an object held close to a piece of paper in sunlight will be
fuzzy
sharp
Answers
False, the shadow produced by an object held close to a piece of paper in sunlight will be sharp.
Is it true or false that the shadow produced by an object held close to a piece of paper in sunlight will be fuzzy?The shadow produced by an object held close to a piece of paper in sunlight will be sharp. This is because the closer the object is to the paper, the sharper the shadow will appear. If the object is far away from the paper, the shadow will be fuzzy.
This is due to the fact that the edges of the shadow are less defined the further away the object is from the paper.
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Cell phones use digital signals to send and receive information. These digital signals travel as what kind of wave?
ОООО
Gamma rays
X-rays
Microwaves
Radio waves
Answers
the answer would be microwaves!
Answer:
Microwaves
Explanation:
Explanation:
a rotor rotating about a fixed axis through its mass center, the rotor has a mass of 60 kg, radius of gyration of 70 mm, and angular acceleration of 9 rad/s2. determine the moment the fixed axis.
Answers
Given
60 kg of mass, 70 mm or 0.07 meters of gyroscopic radius, and 9 rad/sec2 of angular acceleration
Utilized conceptInertia, It is an object's resistance to any change in motion. The amount of inertia is directly related to an object's mass; in fact, as we frequently observe, the heavier an object is, the harder it is to change its direction of motion.
The moment of inertia must be identified. EM = I > I > MK2
I stands for inertia mass moment.
I = 60 kg/m2 M = I = 0.216 kg/m2 = 11 kg/m2 M = 2.376 nm
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Answer:
Explanation:
Given:
m = 60 kg
R = 70 mm = 0.070 m
ε = 9 rad/s²
__________________
M - ?
The moment:
M = J·ε = m·R²·ε
M = 60·0.070²·9 ≈ 2.65 N·m
a balloon, rising vertically with a velocity of 16 feet per second, releases a sandbag at the instant it is 64 feet above the ground. assume the acceleration of the object is -32 feet per second per second. (a) how many seconds after its release will the bag strike the ground? (b) at what velocity will the bag hit the ground?
Answers
The sandbag will hit the ground with a velocity of -48 feet per second (negative sign indicates the downward direction).
(a) To determine the time it takes for the sandbag to strike the ground, we can use the equation:
h(t) = h₀ + v₀t + 0.5at²
where h(t) is the height at time t, h₀ is the initial height (64 feet), v₀ is the initial velocity (16 ft/s), a is the acceleration (-32 ft/s²), and t is the time in seconds. We want to find the time t when h(t) = 0 (when the bag hits the ground).
0 = 64 + 16t - 16t²
0 = 64 - 16t²
Now, we solve for t:
t² = 4
t = 2 seconds
The sandbag will strike the ground 2 seconds after its release.
(b) To find the velocity at which the bag hits the ground, we use the equation:
v(t) = v₀ + at
where v(t) is the velocity at time t, v₀ is the initial velocity (16 ft/s), a is the acceleration (-32 ft/s²), and t is the time in seconds.
v(2) = 16 - 32(2)
v(2) = 16 - 64
v(2) = -48 ft/s
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overall force acting on an object.
Answers
Answer:
Gravity
Explanation:
Gravity is a force that acts upon every single object on Earth.