Answer:
1 - mono
2 - di
3 - tri
4 - tetra
5 - penta
6 - hexa
7 - hepta
8 - octa
9 - nona
10 - deca
Explanation:
These are prefixes that can go on an element.
For example:
CO2= Carbon Dioxide
Answer:
The same atoms can combine in more than one ratio.
Explanation:
why there is no reaction when aluminium is added into cold dilute hydrochloric acid
Answer:
When aluminum is added to cold dilute hydrochloric acid, there is no reaction because aluminum is a highly reactive metal, but it is protected by a thin oxide layer on its surface. This oxide layer is not easily dissolved by dilute hydrochloric acid, so the aluminum does not react with the acid. In order to react with the acid, a stronger acid such as sulfuric acid or nitric acid is needed to dissolve the oxide layer. Additionally, a higher concentration of hydrochloric acid is also needed to react with aluminum.
Another possible reason is that Aluminium metal react with hydrochloric acid to produce hydrogen gas and aluminum chloride salt, but the reaction is relatively slow and requires heat to speed it up. In cold dilute hydrochloric acid, the reaction rate is too slow to observe any visible change.
Answer:
There is a leyer of aluminium that prevents nothing from happening
Explanation:
Keep in mind that this reaction will not take place as soon as you add the piece of aluminium to the hydrochloric acid solution. That happens because the piece of aluminium is protected by a layer of aluminium oxide, Al2O3 , the same layer that protects aluminium from reacting with water
if you have 19.8g of Na how many grams of O2 are required for reaction
Taking into account the reaction stoichiometry, 6.89 grams of O₂ are required to react with 19.8 grams of Na.
Reaction stoichiometryIn first place, the balanced reaction is:
4 Na + O₂→ 2 Na₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Na: 4 molesO₂: 1 moleNa₂O: 2 molesThe molar mass of the compounds is:
Na: 23 g/moleO₂: 32 g/moleNa₂O: 62 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Na: 4 moles ×23 g/mole= 92 gramsO₂: 1 mole ×32 g/mole= 32 gramosNa₂O: 2 moles ×62 g/mole= 124 gramsMass of O₂ requiredThe following rule of three can be applied: If by reaction stoichiometry 92 grams of Na react with 32 grams of O₂, 19.8 grams of Na react with how much mass of O₂?
mass of O₂= (19.8 grams of Na×32 grams of O₂) ÷92 grams of Na
mass of O₂= 6.89 grams
Finally, 6.89 grams of O₂ are required.
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Calculate the energy of a photon of this light wave in joules. [Show all calculations, including the equation and substitution with units.]
The energy of the photon from the calculation performed is 3.5 * 10^-16 J.
What is a photon?A photon is a packet of light. It was derived from the theory of Albert Einstein. The energy of a photon is obtained from; E = hc/λ
h= Plank's constantc = speed of lightλ = wavelengthNow we have that;
E = 6.6 * 10^-34 * 3 * 10^8/562 * 10^-9
E = 3.5 * 10^-16 J
Missing parts:
Calculate the energy, in joules, of a photon of green light having a wavelength of 562nm?
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8. Which has greater thermal energy: a glass of water
or a lake full of water? Why?
Answer:
Im assuming a glass of water
Explanation:
there is less water that needs to be heated up
Question 14 PM2.5 is defined as ________
- the mass concentration of particles in the air less than or equal to 2.5 micrometers in diameter. - the mass concentration of particles in the air equal to 2.5 micrometers in diameter. - the mass concentration of particles in the air greater than or equal to 2.5 micrometers in diameter. Question 15 Carbon dioxide (CO2) is a criteria air pollutant. - True - False Question 16 Roughly percent of emissions of carbon monoxide in Santa Clara County come from mobile sources (select the choice closest to the correct answer). - 50 - 75 - 25 Question 17
The term "photochemical smog" is most synonymous with which of the following criteria air pollutants? - lead (Pb) - carbon monoxide (CO) - sulfur dioxide ( SO2) - ozone (O3) Question 18 "Attainment" of ambient air quality standards requires that measured concentrations at all monitoring stations within an air district are below ambient air standards. - True - False
: PM2.5 is defined as the mass concentration of particles in the air less than or equal to 2.5 micrometers in diameter.Question 15: False, carbon dioxide (CO2) is not considered a criteria air pollutant.
Question 16: The closest answer is 50%, but the exact percentage is not provided in the question.Question 17: The term "photochemical smog" is most synonymous with ozone (O3), which is a criteria air pollutant.Question 18: True, attainment of ambient air quality standards requires that measured concentrations at all monitoring stations within an air district are below ambient air standards.
Question 14 asks about the definition of PM2.5. PM2.5 refers to particulate matter with a diameter less than or equal to 2.5 micrometers. It represents the mass concentration of particles suspended in the air, which are small enough to be inhaled into the respiratory system and can have adverse health effects.
Question 15 states whether carbon dioxide (CO2) is a criteria air pollutant. Criteria air pollutants are a set of pollutants regulated by environmental agencies due to their detrimental impact on air quality and human health. However, carbon dioxide is not considered a criteria air pollutant because it does not directly cause harm to human health or the environment in the same way as pollutants like ozone or particulate matter.
Question 16 asks about the percentage of carbon monoxide (CO) emissions from mobile sources in Santa Clara County. While the exact percentage is not provided in the question, the closest answer option is 50%. However, it is important to note that the precise percentage may vary depending on specific local conditions and emissions sources.
Question 17 inquires about the criteria air pollutant most synonymous with the term "photochemical smog." Photochemical smog is primarily associated with high levels of ground-level ozone (O3). Ozone is formed when nitrogen oxides (NOx) and volatile organic compounds (VOCs) react in the presence of sunlight, creating a hazy and polluted atmospheric condition.
Question 18 addresses the concept of "attainment" of ambient air quality standards. To achieve attainment, measured concentrations of pollutants at all monitoring stations within an air district must be below the established ambient air quality standards. This ensures that the air quality in the given area meets the required standards for protecting human health and the environment.
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If lead (II) nitrate is decomposed and produces .0788 grams of oxygen gas how much nitrogen dioxide is also produced
Please help me I’m in the middle of a final
To determine the amount of nitrogen dioxide (NO2) produced when lead (II) nitrate (Pb(NO3)2) decomposes and produces 0.0788 grams of oxygen gas (O2), we need to consider the balanced chemical equation for the decomposition reaction.
The balanced chemical equation for the decomposition of lead (II) nitrate is:
2Pb(NO3)2(s) → 2PbO(s) + 4NO2(g) + O2(g)
From the balanced equation, we can see that for every 2 moles of lead (II) nitrate decomposed, we get 4 moles of nitrogen dioxide (NO2) gas produced.
To calculate the amount of nitrogen dioxide (NO2) produced, we need to determine the number of moles of oxygen gas (O2) produced.
First, we need to calculate the molar mass of oxygen gas (O2), which is 32.00 grams/mol (16.00 g/mol for each oxygen atom).
Now, we can calculate the number of moles of oxygen gas (O2) produced:
Moles of O2 = Mass of O2 / Molar mass of O2
Moles of O2 = 0.0788 g / 32.00 g/mol ≈ 0.0024625 mol
Since the balanced equation shows that for every 2 moles of lead (II) nitrate decomposed, we get 4 moles of nitrogen dioxide (NO2) gas, we can use the mole ratio to determine the number of moles of nitrogen dioxide (NO2) produced:
Moles of NO2 = Moles of O2 × (4 moles NO2 / 2 moles O2)
Moles of NO2 = 0.0024625 mol × (4/2) ≈ 0.004925 mol
Therefore, approximately 0.004925 moles of nitrogen dioxide (NO2) are produced when 0.0788 grams of oxygen gas (O2) is generated through the decomposition of lead (II) nitrate.\(\)
The process of generating electricity from dams and nuclear power plants is very different, but some of the energy transformations are the same. Which energy transformations occur in both dams and nuclear power plants? Check all that apply.
Answer:
Kinetic energy to mechanical energy, and mechanical energy to electrical energy.
Explanation:
From the Law of conservation of Energy, which state that energy can neither be created nor destroyed but can be transformed from one form to another. Energy transformation is essential in science and technology, in the process of generating electricity from dams and nuclear power plants
some of the energy transformations are the same, the energy transformations occur in both dams and nuclear power plants is Kinetic energy to mechanical energy, and mechanical energy to electrical energy. Kinectic energy is the energy in motion which means the dams is a running water and posses a Kinectic energy then it's is been convert to mechanical energy (which is the macroscopic energy) then to electrical energy by producing light.
Answer:
Explanation:
Kinetic energy to mechanical and mechanical to electrical
What is the end result
of diffusion?
Answer:
The End Result Of Diffusion Is An Equal Concentration, Or Equilibrium, Of Mocules On Both Sides Of The Membrane.
Explanation:
☺️ Hope It helps Ty.
Drag each tile to the correct image. Match each hydrocarbon class to its structure. carboxylic acid amine halocarbon alcohol
Answer:
1. Amine.
2. Alcohol.
3. Carboxylic Acid.
4. Halocarbon.
Explanation:
The correct answer according to the tile are Amine, Alcohol, Carboxylic acid, Halocarbon.
How can hydrocarbons be classified based on their structure?
Hydrocarbons can be classified as either aromatic or aliphatic compounds, depending on the presence of a benzene ring.
What is the most common classification of hydrocarbons?
Alkanes are hydrocarbons in which all of the bonds are single bonds. Alkenes are hydrocarbons that contain a carbon-carbon double bond.
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Calculate the number of copper atoms in 2.45 mole of copper
Answer:
1.48×10²⁴ Cu atoms
Explanation:
For this question you need to use Avogadro's number 6.022×10²³atoms.
2.45 moles of Cu ×\(\frac{6.022x10x^{23} atoms }{1 mole}\)= 1.47539×10²⁴ atoms.
The moles cancel out so you are left with atoms.
Since there are 3 significant figures in the question there should be 3 significant figures in your answer, which is 1.48×10²⁴ Cu atoms.
How long is a bench? Select the best estimate.
4 centimeters
4 milllimeters
4 kilometers
4 meters
Answer:
4 meters
Explanation:
4 centimeters and millimeters are too small, while 4 kilometers is too large.
What is NOT an example of evidence of a super continent?
Question 5 options:
Fossil Record
Continuous Chain
Ocean Currents
Climate
A supercontinent is a landmass that consists of an aggregate mass of entire earth lithospheric landmasses. Pangaea was the last supercontinent that split about 200 million years ago.
The German geologist Alfred Wegener gave numerous pieces of evidence to support his theory of continental drift. These theories include fossil records, glacial chains, coal despites. In some places, he has also mentioned the presence of a similar climate type.Hence the option C is correct.
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What is the compound name for Bel?
calculate the molarity of the solution obtained by diluting 69.2 ml of 0.929 m ammonium chloride to 0.384 l.
the molarity of the solution obtained by diluting 69.2 ml of 0.929 m ammonium chloride to 0.384 l, we can use the formula:M1V1 = M2V2 the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume. M2 = 0.167 M. the molarity of the solution obtained by diluting 69.2 ml of 0.929 m ammonium chloride to 0.384 l is 0.167 M.
the molarity of the solution obtained by diluting 69.2 mL of 0.929 M ammonium chloride to 0.384 L. Here are the steps the answer: First, convert the initial volume of the ammonium chloride solution from milliliters to liters:
69.2 mL × (1 L / 1000 mL) = 0.0692 L Next, use the dilution formula, which is:
M1V1 = M2V2the initial molarity (0.929 M), V1 is the initial volume (0.0692 L), M2 is the final molarity, and V2 is the final volume (0.384 L).
Rearrange the formula to solve for M2 (the final molarity): M2 = M1V1 / V2 Plug in the given values and calculate M2: M2 = (0.929 M × 0.0692 L) / 0.384 L Perform the calculation to get the final molarity: M2 = 0.166 M
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Use the solubility curve to match each scenario with its correct saturation level. All scenarios are in 100g of water.
The curve represents saturation. Below the curve, the water is unsaturated. Above the curve, water is supersaturated. This means that more solute is present than the water can contain.
The line of the solubility curve indicates that the solution is saturated. A saturated solution is defined as a solution in which 100 g of solute is dissolved in 100 g of water. Simulations below this line indicate unsaturated solutions.
The difference between unsaturated and saturated solutes can be determined by adding very small amounts of solute to the solution. In unsaturated solutes, solutes will dissolve, and solutes in saturated solutes will not dissolve. In saturated solutes, crystals will form very quickly around the added solute.
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which answer choice shows the correct ratio of moles ni:po43- for the reaction of aqueous nicl2 with na3po4?
The correct ratio of moles of Ni²⁺ : PO₄³⁻ is 3 : 2.
The reaction of Na₃PO₄ and NiCl₂ is given as :
Na₃PO₄ + NiCl₂ ----> Ni₃(PO)₂ + NaCl
The balanced chemical equation between the Na₃PO₄ and NiCl₂ is given as :
2Na₃PO₄ + 3NiCl₂ ----> Ni₃(PO)₂ + 6NaCl
The complete ionic equation between the Na₃PO₄ and NiCl₂ is given as :
6Na⁺ + 2PO₄³⁻ + 3Ni²⁺ + 6Cl⁻ --> Ni(PO₄)₂ + 6Na⁺ + 6Cl⁻
from the above equation it is clear that ratio of moles of Ni²⁺ : PO₄³⁻ is
3 : 2.
Thus , The correct ratio of moles of Ni²⁺ : PO₄³⁻ is 3 : 2.
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2. The atomic number of an atom comes from *
The number of electrons.
The number of neutrons.
The number of protons.
Its atomic mass.
Carbon dioxide molecules (select all that apply)
Group of answer choices
Protect the Earth from all of the harmful Ultraviolet (UV) radiation
Absorb most of the shortwave radiation emitted from the Sun
Are one of the most abundant constituents of Earth's atmosphere
Can move in many ways, thus absorbing and emitting infrared radiation
Carbon dioxide molecules can absorb and emit infrared radiation, and they are one of the most abundant constituents of Earth's atmosphere.
Thus, the correct options are:d) Are one of the most abundant constituents of Earth's atmospheree) Can move in many ways, thus absorbing and emitting infrared radiation
Carbon dioxide is a trace gas present in the Earth's atmosphere. It's a vital component of Earth's carbon cycle, which helps to regulate Earth's temperature and support life as we know it. Carbon dioxide molecules are one of the most common gases in the atmosphere, accounting for around 0.04% of the Earth's atmosphere.
The greenhouse effect is caused by carbon dioxide, methane, and other greenhouse gases. When the Sun's energy reaches the Earth's surface, it is absorbed and then radiated back into space as infrared radiation. Greenhouse gases absorb this radiation and trap it in the atmosphere, which causes the Earth's temperature to rise and the climate to change.
Carbon dioxide molecules are capable of absorbing and emitting infrared radiation due to their molecular structure, which consists of one carbon atom and two oxygen atoms. This property of carbon dioxide is the main reason it's classified as a greenhouse gas.
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It takes a water wave 5.2 seconds to travel between two docks there are 19 m apart. An observer notices that 20 crests pass the first dock in 17 seconds.
find the wavelength of the water waves.
Answer:
152.12
Explanation:
hope it helps
Kong Mali po sorry
calculate the thermal conductivity of argon (cv,m σ = 0.36 nm2 ) at 298 k.
The thermal conductivity of argon at 298K is 0.017 W/mK.
The thermal conductivity of argon (k) at 298K can be calculated using the following formula:
\(k = (1/3) * Cv,m * v * lambda\)
At 298K, Cv,m of argon is 12.5 J/mol*K and the average velocity of argon molecules is 322 m/s. The mean free path of argon molecules can be calculated using the formula:
\(lambda = (1/(2*(\sqrt{(2)}*sigma^2)*N/V)) * (1/100)\)
where sigma is diameter of the argon molecule, N is the number of molecules per unit volume, and V is the molar volume of argon.
Using given value of sigma and the ideal gas law, we can calculate N/V and V as \(2.6910^25\ m^-3\) and\(22.410^{-3} m^3\)/mol, respectively.
Plugging in the values, we get k = 0.017 W/mK.
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It is given that the probability of requiring ICU care for patients hospitalized for COVID-19 is 5%. What is the probability of observing at least one ICU admissions, among the next six patients hospitalized for COVID-19?| Answer: a. 0.26491 b. 0.73509 c. 0.03125 d. 0.98437 e. 0.23213
The probability of observing at least one ICU admission, among the next six patients hospitalized for COVID-19 is 0.26491. Option A is correct.
The probability of not observing any ICU admission among the next six patients hospitalized for COVID-19:
Probability of not observing ICU admission = 1 - Probability of observing ICU admission
= 1 - 0.05
= 0.95
Probability of no ICU admission among the next six patients hospitalized for COVID-19:
Probability of no ICU admission in one trial = 0.95
Probability of no ICU admission in six trials (patients)
= 0.95 × 0.95 × 0.95 × 0.95 × 0.95 × 0.95
= 0.73509
Now, we can calculate the probability of observing at least one ICU admission among the next six patients hospitalized for COVID-19:
Probability of at least one ICU admission= 1 - Probability of no ICU admission
= 1 - 0.73509
= 0.26491
Therefore, the answer is A.
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SOMEONE PLEASE HELP
Classify each of the following as either a pure substance or a mixture.
(a) Pop is composed of water, sugar, and carbon dioxide.
(b) Carbon dioxide is composed of carbon and oxygen chemically
combined.
(c) Sand is composed of white grains and black grains.
(d) The graphite at the centre of a pencil is composed of carbon.
Answer:
(a) Mixture
(b) Pure substance
(c) Mixture
(d) Pure substance
How do you prepare 300 ml buffer of 100 mm tris ph 7. 8 and 250 mm nacl?
A buffer of 300 ml of 100 mM Tris pH 7.8 and 250 mM NaCl can be prepared by dissolving 3.64 g of Tris and 4.27 g of NaCl in 300 ml of water, and adjusting the pH to 7.8 using 10 ml of 1 M HCl. The % v/v refers to the volume of the solute while % w/v refers to the weight of the solute.
To prepare a 300 ml buffer of 100 mM Tris pH 7.8 and 250 mM NaCl, you need to follow the following steps:1. Calculate the amount of Tris required to prepare 100 mM solution of Tris, which is equal to 100 mM x 0.3 L = 0.03 moles. The molecular weight of Tris is 121.14 g/mol. Thus, the amount of Tris required is 3.64 g.2. To make the buffer of pH 7.8, use HCl or NaOH to adjust the pH. For this, use 1 M HCl or 1 M NaOH to avoid diluting the buffer. Add 10 ml of 1 M HCl to the solution.3. Measure 4.27 g of NaCl and add it to the solution. 4. Add water to the solution to make up the final volume of 300 ml. 5. Mix the solution thoroughly until everything is dissolved. Your buffer of 100 mM Tris pH 7.8 and 250 mM NaCl is now ready. % v/v refers to the percentage volume of a solute in a solvent while % w/v refers to the percentage weight of a solute in a solvent. The percent v/v is calculated by the volume of the solute divided by the volume of the solution while the percent w/v is calculated by the mass of the solute divided by the volume of the solution in which it is dissolved.For more questions on buffer
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The correct question would be as
How do you prepare 300 ml buffer of 100 mM Tris pH 7.8 and 250 mM NaCl? % v/v,% w/v Questions.
Provide a structure for the given compound. c6h12o2; ir: 1743 cm−1; h1 nmr spectrum?
The compound with the formula C6H12O2 can have multiple structural isomers. Without further information, it is difficult to determine the specific structure of the compound.
The given IR (infrared) spectrum peak at 1743 cm−1 suggests the presence of a carbonyl group (C=O) in the compound. This peak typically corresponds to a ketone or an ester functional group. In the absence of additional information, it is challenging to distinguish between these possibilities.
The H1 NMR spectrum (proton nuclear magnetic resonance) can provide further insights into the compound's structure. It would show the number of distinct proton environments and their chemical shifts. However, the H1 NMR spectrum is not provided in the question, so we cannot determine the exact structure or the number of peaks.
In summary, without the H1 NMR spectrum and additional information, it is not possible to provide a specific structure for the compound C6H12O2. The IR spectrum indicates the presence of a carbonyl group, while the H1 NMR spectrum would provide more information about the compound's structure.
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Calculate the reaction rate given the following:
After 2 minutes (120 seconds), the concentration of a product was measured to
increase from 0.0012 M to 1.48 M.
1.48 M/s
0.0123 M/s
0.0012 M/s
-0.0123 M/s
Answer:
0.0123 M/s
Explanation:
The reaction rate is the rate at which the reaction takes place and results in an increased concentration of the products. The rate of the reaction is 0.0123 M/s.
What is the reaction rate?
The reaction rate is the increase of the concentration of the product with respect to time in seconds. The rate of reaction is given by,
\(\rm rate = \rm \dfrac {\Delta C}{\Delta t}\)
Given,
Change in product concentration = 1.478
Time period = 120 seconds
Substituting values in the above equation:
\(\begin{aligned} \rm rate &= \rm \dfrac {\Delta C}{\Delta t}\\\\& = \dfrac{1.478}{120}\\\\&= 0.0123 \end{aligned}\)
Therefore, option B. 0.0123 M/s is the reaction rate.
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What are the steps to determine the number of valence electrons of phosphorus
Answer:
Phosphorus is in group VA so it has 5 valence electrons and Oxygen is in group VIA so each oxygen has 6 valence electrons. Total valence electrons = 5 + 4(6) = 29
Explanation:
How many moles of KCl are produce when 61.5 g of KClO3 are decomposed?
Answer:
0.502mol
Explanation:
The balanced chemical equation of the reaction described in this question is as follows:
2KClO3 → 2KCl+ 3O2
According to the equation above, 2 moles of KClO3 will produce 2 moles of KCl.
Using mole = mass/molar mass to convert mass of KClO3 to moles
Molar mass of KClO3 = 39 + 35.5 + 16(3)
= 39 + 35.5 + 48
= 122.5g/mol
mole = 61.5 g ÷ 122.5g/mol
mole = 0.502mol
Since 2 moles of KClO3 will decompose to produce 2 moles of KCl.
0.502 mol of KClO3 will decompose to produce 0.502 × 2/2
= 0.502mol of KCl.
a compound that contains only c and h and has a molecular ion with an m/z value of 86
The molecular formula of a compound which has c and h with molecular ion with an m/z is C6H14.
For molecular formula use the 13 rule.
firstly divide 86 by 133+//1333= 13.
86/13= 6 + 8/13
Use the formula Cn+Hn+r
where n = 6 and r = 8
substituting the values of n and r in the formula
C6+H(6+8)
C6H14 is the molecular formula
Hexane, an organic substance with the chemical formula C6H14, is a straight-chain alkane having six carbon atoms. When pure, it is a colorless liquid with no odor, and its boiling point is about 69 °C (156 °F).
The chemical formula for a molecular compound's molecular formula lists the variety of atoms that make up the molecule.
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A mixture of hydrogen and oxygen gases has a total pressure of 5.50 atm. What is the partial pressure of the hydrogen if the P(O2) = 1250 mm Hg?
Answer:
P O 2 = 5.21 atm P C O 2 = 4.79 atm
Explanation:
Hope it helps!
PLZ HELP I DON'T WANT TO BE YELLED AT
A mechanical device, or arrangement of fixed and moving parts that people use to do work.
Answer:
This is literally just the definition of a machine