Write the equation of the given circle.
center at origin, r=3

Answers

Answer 1

Answer:

The standard form is: (x−h)2+(y−k)2=r2where (h,k) is the center and r is the radius.Your center is at (0,0) and the radius, r=3(x−0)2+(y−0)2=32

Step-by-step explanation:


Related Questions

this is the question I meant to post:

Find the value of x, please put an explanation

this is the question I meant to post:Find the value of x, please put an explanation

Answers

Answer:

x=36

Step-by-step explanation:

you would take 72 divided by 2 to get your answer

Answer:

Step-by-step explanation:

Ok, let's see how much I can do

So I don't know how to label the angles, but let's just say there are 2 angles at point B. One is already given. 72. Since a line is 180. We can find the other angle by subtraction: 180 - 72 = 108

And we can also tell that both angles at point D are equal as they are both represented by 2x.

Now by the looks of it, Line AC and DE are parallel so angle A and both the angles at point D are equal to each other. So triangle ABD is at least an isosceles triangle.  Now because we know it's an isosceles triangle, we can now find the measure of triangle ABD.

72 + 2x + 2x = 180

72 + 4x = 180

4x = 108

x = 27

What is the missing value of 5x-2y=30 (8,)

Answers

Answer:

In this equation, we can start by understanding that "x" has a value of 8, as given in the ordered pair. When multiplied by 5, this leads to "40 - 2y = 30". Next, we can subtract 40 from both sides of the equation. This leads us to a value of "-2y = -10". The next step would be to divide both sides by -2 as a way of isolating "y", which leads us to a final value of "y = 5". The final ordered pair would be (8,5).

-1+x=-5 please help me

Answers

Answer:

x = -4

Step-by-step explanation:

\(-1 + x = -5\\x = -4\)

Harper, inc., acquires 40 percent of the outstanding voting stock of kinman company on january 1, 2020, for $334,900 in cash. the book value of kinman's net assets on that date was $625,000, although one of the company's buildings, with a $70,800 carrying amount, was actually worth $135,550. this building had a 10-year remaining life. kinman owned a royalty agreement with a 20-year remaining life that was undervalued by $147,500. kinman sold inventory with an original cost of $77,700 to harper during 2020 at a price of $111,000. harper still held $18,750 (transfer price) of this amount in inventory as of december 31, 2020. these goods are to be sold to outside parties during 2021. kinman reported a $51,800 net loss and a $26,600 other comprehensive loss for 2020. the company still manages to declare and pay a $15,000 cash dividend during the year. during 2021, kinman reported a $57,200 net income and declared and paid a cash dividend of $17,000. it made additional inventory sales of $120,000 to harper during the period. the original cost of the merchandise was $75,000. all but 30 percent of this inventory had been resold to outside parties by the end of the 2021 fiscal year. prepare all journal entries for harper for 2020 and 2021 in connection with this investment. assume that the equity method is applied. (if no entry is required for a transaction/event, select "no journal entry required" in the first account field. do not round intermediate calculations.)

Answers

In 2020, Harper, Inc. acquired 40% of the outstanding voting stock of Kinman Company for $334,900 in cash.

The book value of Kinman's net assets was $625,000, but there were certain adjustments needed. One of Kinman's buildings was undervalued by $64,750 ($135,550 - $70,800), and there was an undervaluation of $147,500 for the royalty agreement. Harper also purchased inventory from Kinman for $111,000, out of which $18,750 was still held in inventory by the end of the year. Kinman reported a net loss of $51,800 and other comprehensive loss of $26,600 in 2020, but it still paid a $15,000 cash dividend.

To record these transactions, Harper would make the following journal entries in 2020:

1. To record the investment in Kinman's stock:
  Investment in Kinman Company Stock     334,900
  Cash                                                334,900

2. To adjust the building's carrying amount and recognize the related depreciation:
  Investment in Kinman Company Stock     64,750
  Depreciation Expense                                 6,475
  Accumulated Depreciation                      6,475

3. To adjust the undervalued royalty agreement:
  Investment in Kinman Company Stock     147,500
  Royalty Agreement                                      147,500

4. To record the purchase of inventory from Kinman:
  Inventory                                                   111,000
  Investment in Kinman Company Stock     111,000

5. To recognize the equity in Kinman's net loss and comprehensive loss:
  Equity in Net Loss                                         20,720
  Equity in Other Comprehensive Loss        10,640
  Investment in Kinman Company Stock     31,360

6. To record the receipt of the cash dividend:
  Cash                                                15,000
  Dividend Income                                        15,000

In 2021, Kinman reported a net income of $57,200 and paid a cash dividend of $17,000. Harper purchased additional inventory worth $120,000 from Kinman, out of which 70% ($84,000) was sold to outside parties by year-end. Harper would make the following journal entries in 2021:

1. To recognize the equity in Kinman's net income:
  Equity in Net Income                                22,880
  Investment in Kinman Company Stock     22,880

2. To record the receipt of the cash dividend:
  Cash                                                17,000
  Dividend Income                                        17,000

3. To record the purchase of additional inventory from Kinman:
  Inventory                                                   120,000
  Investment in Kinman Company Stock     120,000

4. To eliminate the unrealized profit in inventory:
  Investment in Kinman Company Stock     8,400
  Equity in Net Income                                8,400

Overall, these journal entries reflect the investment in Kinman Company, adjustments for undervalued assets, recognition of income or loss, and dividend payments. The equity method is used to account for the investment, where Harper recognizes its share of Kinman's net income or loss and adjusts the investment account accordingly.

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Find an antiderivative F(x) with F′(x)=f(x)=4+15x2+15x4 and F(1)=0.
Remember to include a "+ C" if appropriate.
F(x)=

Answers

The antiderivative of the function is F(x) = 4x + 5x^3 + 3x^5 - 12.

To find the antiderivative F(x) for F′(x) = f(x) = 4 + 15x^2 + 15x^4, and given F(1) = 0, follow these steps,
1. Find the antiderivative of f(x) with respect to x:
F(x) = ∫(4 + 15x^2 + 15x^4) dx

2. Integrate each term separately:
F(x) = ∫4 dx + ∫15x^2 dx + ∫15x^4 dx

3. Calculate the antiderivatives:
F(x) = 4x + (15/3)x^3 + (15/5)x^5 + C

4. Simplify:
F(x) = 4x + 5x^3 + 3x^5 + C

5. Use the given condition F(1) = 0 to find the value of C:
0 = 4(1) + 5(1)^3 + 3(1)^5 + C

6. Solve for C:
C = -12

7. Substitute the value of C back into F(x):
F(x) = 4x + 5x^3 + 3x^5 - 12

The antiderivative is F(x) = 4x + 5x + 3x - 12 as a result.

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Write an equation of a vertical line that contains the point (-2,5)

Answers

Answer:

x=-2

Step-by-step explanation:

The line is vertical and/or undefined and it passes through the point (-2,5).

Solve the differential equations 2xy(dy/dx)=1 y^2. y(2)=3

Answers

The solution to the given differential equation 2xy(dy/dx) = y², with the initial condition y(2) = 3, is y = (27 * e⁽ˣ⁻²⁾\()^{1/4}\).

To solve the given differential equation

2xy(dy/dx) = y²

We will use separation of variables and integrate to find the solution.

Start with the given equation

2xy(dy/dx) = y²

Divide both sides by y²:

(2x/y) dy = dx

Integrate both sides:

∫(2x/y) dy = ∫dx

Integrating the left side requires a substitution. Let u = y², then du = 2y dy:

∫(2x/u) du = ∫dx

2∫(x/u) du = ∫dx

2 ln|u| = x + C

Replacing u with y²:

2 ln|y²| = x + C

Using the properties of logarithms:

ln|y⁴| = x + C

Exponentiating both sides:

|y⁴| = \(e^{x + C}\)

Since the absolute value is taken, we can remove it and incorporate the constant of integration

y⁴ = \(e^{x + C}\)

Simplifying, let A = \(e^C:\)

y^4 = A * eˣ

Taking the fourth root of both sides:

y = (A * eˣ\()^{1/4}\)

Now we can incorporate the initial condition y(2) = 3

3 = (A * e²\()^{1/4}\)

Cubing both sides:

27 = A * e²

Solving for A:

A = 27 / e²

Finally, substituting A back into the solution

y = ((27 / e²) * eˣ\()^{1/4}\)

Simplifying further

y = (27 *  e⁽ˣ⁻²⁾\()^{1/4}\)

Therefore, the solution to the given differential equation with the initial condition y(2) = 3 is

y = (27 * e⁽ˣ⁻²⁾\()^{1/4}\)

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solve sinx = 2x-3 using false position method

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The root of the equation sinx = 2x-3 is 0.8401 (approx).

Given equation is sinx = 2x-3

We need to solve this equation using false position method.

False position method is also known as the regula falsi method.

It is an iterative method used to solve nonlinear equations.

The method is based on the intermediate value theorem.

False position method is a modified version of the bisection method.

The following steps are followed to solve the given equation using the false position method:

1. We will take the end points of the interval a and b in such a way that f(a) and f(b) have opposite signs.

Here, f(x) = sinx - 2x + 3.

2. Calculate the value of c using the following formula: c = [(a*f(b)) - (b*f(a))] / (f(b) - f(a))

3. Evaluate the function at point c and find the sign of f(c).

4. If f(c) is positive, then the root lies between a and c. So, we replace b with c. If f(c) is negative, then the root lies between c and b. So, we replace a with c.

5. Repeat the steps 2 to 4 until we obtain the required accuracy.

Let's solve the given equation using the false position method.

We will take a = 0 and b = 1 because f(0) = 3 and f(1) = -0.1585 have opposite signs.

So, the root lies between 0 and 1.

The calculation is shown in the attached image below.

Therefore, the root of the equation sinx = 2x-3 is 0.8401 (approx).

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Write an equation in point slope form for the line through the given point with the given slope.
(-7, 9); m: 4/5

A. y+7=4/5(x-9)
B. y-7=4/5(x+9)
C. y-9=4/5(x-7)
D. y+9=4/5(x-7)

❤︎

Answers

Answer:

Ans C

m=4/5

X1= -7

Y1 = 9

Y-Y1=m(X-X1)

Y-9=4/5(X-(-7))

Y-9=4/5(X+7)

Can you provide the solution for this exercise?

Let u(w) = −(b − w)c. What restrictions on w, b, and c are required to ensure that u(w) is strictly increasing and strictly concave? Show that under those restrictions, u(w) displays increasing absolute risk aversion.

Answers

under the restrictions that c is negative to ensure strict concavity, the utility function u(w) = -(b - w)c displays increasing absolute risk aversion.

To ensure that u(w) is strictly increasing, we need the derivative of u(w) with respect to w to be positive for all values of w. Taking the derivative, we have du(w)/dw = -c. For u(w) to be strictly increasing, -c must be positive, which implies c must be negative.

To ensure that u(w) is strictly concave, we need the second derivative of u(w) with respect to w to be negative for all values of w. Taking the second derivative, we have d²u(w)/dw² = 0. Since the second derivative is constant and negative, u(w) is strictly concave.

Now, let's examine the concept of increasing absolute risk aversion. If a utility function u(w) exhibits increasing absolute risk aversion, it means that as wealth (w) increases, the individual becomes more risk-averse.

In the given utility function u(w) = -(b - w)c, when c is negative (as required for strict concavity), the absolute risk aversion increases as wealth (w) increases. This is because the negative sign implies that the utility function is concave, indicating that the individual becomes more risk-averse as wealth increases.

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Which equation shows the inverse property of multiplication? 4 + (-4) = 0 -8 + (-3) = -3 + (-8) 2 times one-half = 1 Eight-fifths + 0 = Eight-fifths

Answers

Answer:

  2 times one-half = 1

Step-by-step explanation:

In order to show a property of multiplication, the equation must involve multiplication. There is only one choice that does.

  2 times one-half = 1

__

The multiplicative inverse of a number, multiplied by the number, results in 1, the multiplicative identity element.

Equation C,2 times one-half = 1 shows the inverse property of multiplication. Option C is correct.

What is multiplicative inverse?

A multiplicative inverse is a number whose value is equal to 1 when multiplied by the original number.

The left-hand side of the equation is;

LHS =  2 times one-half

LHS = 2×(1/2)

LHS = 2

The right-hand side of the equation is;

RHS =1

If both LHS and RHS are equal and the RHS value is equal to 1 the RHS is the multiplicative inverse of LHS.

Equation C,2 times one-half = 1 shows the inverse property of multiplication.

Hence, option C is correct.

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scores on an english test are normally distributed with a mean of 33.3 and a standard deviation of 7.1. find thescore that separates the top 41% from the bottom 59%

Answers

The score that separates the top 41% from the bottom 59% is approximately 35.08. To find the score that separates the top 41% from the bottom 59% of scores on an English test with a mean of 33.3 and a standard deviation of 7.1, we need to use the standard normal distribution.

First, we need to find the z-score that corresponds to the top 41% of scores, which can be found using a standard normal distribution table or a calculator. The z-score corresponding to the top 41% is approximately 0.27. We can then use the formula z = (x - μ) / σ to find the corresponding raw score, x, where μ is the mean and σ is the standard deviation. Rearranging the formula gives us x = zσ + μ, which gives us the score that separates the top 41% from the bottom 59%.

In this case, we have z = 0.27, σ = 7.1, and μ = 33.3. Plugging these values into the formula gives us x = 0.27 * 7.1 + 33.3, which simplifies to x = 35.08. Therefore, the score that separates the top 41% from the bottom 59% is approximately 35.08.

This means that if a student scores above 35.08 on the English test, they would be in the top 41% of scores, while if they score below 35.08, they would be in the bottom 59% of scores.

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How much money does Hector need to buy 3 CDs and 7 cell phones?

Answers

Answer:

i need more info, like how much r the CDs and the phones

Step-by-step explanation:

if u answer this can u help me with the other questions ??

if u answer this can u help me with the other questions ??

Answers

Answer:

B=2, C=3, D=4, E=5

a process filling small bottles with baby formula has a target of 3.1 ouncesplus or minus 0.280 ounce. two hundred bottles from the process were sampled. the results showed the average amount of formula placed in the bottles to be 3.050 ounces. the standard deviation of the amounts was 0.075 ounce. determine the value of upper c subscript pk . roughly what proportion of bottles meet the​ specifications? part 2 the process capability index is enter your response here ​(round your response to three decimal​ places).

Answers

More than 50% of the bottles meet the specifications.

To determine the proportion of bottles that meet the specifications, we need to calculate the process capability index (Cpk).

The formula for Cpk is:

Cpk = min((USL - X) / (3* σ), (X - LSL) / (3 * σ))

Given:

USL = 3 + 0.150 = 3.150 ounces

X = 3.042 ounces

σ = 0.034 ounce

So, Cpk = min((3.150 - 3.042) / (3 * 0.034), (3.042 - 2.850) / (3 * 0.034))

   = min(0.108 / 0.102, 0.192 / 0.102)

   = min(1.059, 1.882)

   = 1.059

To determine the proportion of bottles that meet the specifications, we can use the following table:

Cpk Value       Proportion within Specifications

-----------------------------------------------

< 1.00          Poor

1.00 - 1.33     Fair

1.33 - 1.67     Good

> 1.67          Excellent

Since the Cpk value is 1.059, it falls within the range of 1.00 - 1.33, which corresponds to a "Fair" proportion within specifications.

Therefore, slightly more than 50% of the bottles meet the specifications.

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Part A) How many numbers are in the list -33, -28, -2... 52, 57?
Part B ) How many numbers are in the list 4, 6, 8, ..., 128, 130?

Answers

Part A) There are 23 numbers in the list.

Part B) There are 65 numbers in the list.

3. A picture costs $40 but Brian has a coupon
for 10% off. How much money will Brian have
to pay for the picture?

Answers

Answer: $36

Step-by-step explanation: 10% of 40 is 4 so 40- 4 is 36

-4x < 28
does anyone know the solution and answer?​

Answers

Answer:

x>−7

Explanation:

Let's solve your inequality step-by-step.

−4x<28

Step 1: Divide both sides by -4.

−4x/−4 < 28/−4

x>−7

Answer: x>−7

Jason runs at a pace of 7 miles per hour and his friend runs at a pace represented by
the equation y = 6x where y is distance in miles and x is time in hours. Who runs
faster?

Answers

Answer:

Jason runs faster then his friend.

Step-by-step explanation:

Jason's speed is represented by the equation y = 7x because he runs 7 miles in an hour. If his friend's speed is represented by y = 6x, then his friend runs a total of 6 miles in an hour.

Two cars are traveling along a straight road. Car A maintains a constant speed of 77.0 km/h. Car B maintains a constant speed of 114 km/h. At t=0, car B is 45.0 km behind car A. How long does it take before car A is overtaken by car B?

Answers

Answer: 72.97 Minutes

Step-by-step explanation: We have two cars, A and B, traveling along a straight road. Car A is moving at a constant speed of 77.0 km/h, while car B is moving at a constant speed of 114 km/h. At the starting point (t=0), car B is 45.0 km behind car A.

To figure out how long it takes for car B to catch up and overtake car A, we need to consider their relative speeds. The relative speed is the difference between the speed of car B and the speed of car A.

Relative speed = Speed of car B - Speed of car A

Relative speed = 114 km/h - 77.0 km/h

Relative speed = 37.0 km/h

So, car B is moving 37.0 km/h faster than car A. Now, we need to determine the time it takes for car B to cover the initial distance between them, which is 45.0 km.

To calculate time, we use the formula: Time = Distance / Speed. In this case, the distance is 45.0 km, and the speed is the relative speed of 37.0 km/h.

Time = 45.0 km / 37.0 km/h ≈ 1.2162 hours

Now, let's convert the time to minutes by multiplying it by 60 (since there are 60 minutes in an hour).

Time = 1.2162 hours * 60 minutes/hour ≈ 72.97 minutes

Therefore, it takes approximately 1.2162 hours or 72.97 minutes for car B to catch up and overtake car A.

Hope this helps!

Cory and Dalia like to buy fruit at the farmers’ market on Sundays. One Sunday, Cory bought 4 apples and 6 oranges and paid $5.10. Dalia bought 2 apples and 5 oranges and paid $3.65.

What is the cost of 2 oranges?

Write the answer as a decimal to 2 places

Answers

The cost of two oranges is 1.1 dollars.

How to find the cost of two oranges?

One Sunday, Cory bought 4 apples and 6 oranges and paid $5.10. Dalia bought 2 apples and 5 oranges and paid $3.65.

Therefore, using equation,

let

x = cost of each apples

y = cost of each oranges

Hence,

4x + 6y = 5.10

2x + 5y = 3.65

Multiply equation(ii) by 2

4x + 6y = 5.10

4x + 10y = 7.3

4y = 2.2

y = 2.2 / 4

y = 0.55 dollars

Therefore,

cost of 2 oranges = 0.55(2) = 1.1 dollars

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During the last basketball season, Alice made 320 out of 360 free-throw attempts. Betty made 300 free-throws out of 320 attempts. Cathy made 90% of her free-throws. Denise had an average of 0.913 for successful free-throws.

Which girl had the highest percentage of free throws?

Answers

Vbgc 457799866 ghjc

Lines AB and CD intersect at E, mLAED = 110,
m_DEB = 3x + 2y, mZBEC = 9x + y, and mZCEA =
= 70.
Find the values of x and y. Check your answer. [Only an
algebraic solution will be accepted.]
А
'D
110°
(3x+2y)
70°
E
(9x + y)
с
B

Answers

Answer:

45,698,09864,58586,96403

Answer:

x = 10, y = 20

Step-by-step explanation:

Form a system of equations:

From the picture at the bottom you can see that vertical angles are equal, so:

\(3x + 2y = 70\)

Then, since the angles all together will add up to 360, you can do

\(3x+2y+9x+y+70+9x+y=360\)

\(21x+4y+70=360\)

subtract 70 from both sides

\(21x + 4y = 290\)

With the equation 3x + 2y = 70, multiply both sides by 2

\(6x+4y=140\)

Subtract the two equations:

\(15x=150\\x=10\)

Plug this into one of the original equations

\(30+2y=70\\2y = 40\\y=20\)

Lines AB and CD intersect at E, mLAED = 110,m_DEB = 3x + 2y, mZBEC = 9x + y, and mZCEA == 70.Find the

A conventional amplitude modulation (AM) signal is defined as: 
xAM​(t)={1+ka​m(t)}×cos(20πt). 
The message signal m(t) is assumed to be a rectangular pulse given by m(t)={1,0,​ if −0.2s≤t≤0.2 s otherwise ​ 
(i) Sketch the waveforms of the resultant AM signals for ka​=0.5 and 1.5, respectively. (ii) Discuss whether the message signal can be recovered using the envelop detector for both cases of ka​=0.5 and 1.5, respectively. 

Answers

(i) Sketch the waveforms of the resultant AM signals for ka=0.5 and 1.5, respectively. In amplitude modulation (AM), the amplitude of the carrier signal is varied proportional to the instantaneous amplitude of the modulating signal, i.e., the message signal.

The amplitude modulated (AM) waveform is expressed as a product of two functions, i.e., a carrier wave and a message signal. The mathematical representation of an AM signal is as follows:

xAM​(t)={1+ka​m(t)}×cos(20πt).

Here, ka​ is the amplitude sensitivity or modulation index and m(t) is the message signal. For example, when ka​ = 1, it is known as 100% modulation. When ka​ > 1, it is known as over modulation. When ka​ < 1, it is known as under modulation.

The message signal m(t) is assumed to be a rectangular pulse given by m(t)={1,0,​ if −0.2s≤t≤0.2 s otherwise ​The waveform of the resultant AM signal for ka​ = 0.5 is shown below:

Waveform of the AM signal for ka=0.5The waveform of the resultant AM signal for ka​ = 1.5 is shown below:

Waveform of the AM signal for ka=1.5(ii) Discuss whether the message signal can be recovered using the envelop detector for both cases of ka​=0.5 and 1.5, respectively.

The message signal cannot be recovered using the envelope detector in case of overmodulation, i.e., when ka​ > 1. In this case, the carrier is suppressed, and the envelope detector cannot extract the original message signal.The message signal can be recovered using the envelope detector in case of normal modulation, i.e., when ka​ < 1. The envelope detector consists of a diode and a low-pass filter.

The diode rectifies the AM signal, and the low-pass filter smoothens the rectified waveform to obtain the original message signal.

The waveform of the resultant AM signal for ka​ = 0.5 is shown below:The waveform of the resultant AM signal for ka​ = 1.5 is shown below:

The message signal cannot be recovered using the envelope detector in case of overmodulation, i.e., when ka​ > 1. In this case, the carrier is suppressed, and the envelope detector cannot extract the original message signal. The message signal can be recovered using the envelope detector in case of normal modulation, i.e., when ka​ < 1.

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here is my question plz answer it anyone

here is my question plz answer it anyone

Answers

Answer:

14

Step-by-step explanation:

-1+15=14

.................

Santiago is going to invest in an account paying an interest rate of 3.3% compounded annually. How much would Santiago need to invest, to the nearest ten dollars, for the value of the account to reach $81,000 in 16 years?

Answers

Santiago needs to invest  50467.3 dollars for the value of the account to reach $81,000 in 16 years at a rate of 3.3%.

What are simple and compound interests?

Simple interest is often a predetermined percentage of the principle amount borrowed or lent paid or received over a specific time period.

Borrowers are required to pay interest on interest in addition to principal since compound interest accrues and is added to the accrued interest from prior periods.

Given Santiago is going to invest in an account paying an interest rate of 3.3% compounded annually for the value of the account to reach $81,000 in 16 years.

We know the formula of compound interest which is A = P(1 + r/100)ⁿ,

where A = Amount, P = Principle, n = Time in years and r = rate percentage.

∴ 81000 = P( 1 + 3.3/100)¹⁶.

81000 = P( 1 + 0.03)¹⁶.

81000 = P( 1.03)¹⁶.

81000 = P×1.605.

P = 81000/1.605

P = 50467.3 dollars.

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Tamar's house is greater than 472 and less than 500 which number can be on Tamar's house?

Tamar's house is greater than 472 and less than 500 which number can be on Tamar's house?

Answers

490… I don’t know how to explain this without sounding condescending

490

472 <490<500

it fits the criteria

If k is a positive integer, find the radius of convergence of the series: Sum from n=0 to infinity of [(n!)^(k)/(kn)!]*[x^(n)].

Answers

The radius of convergence of the given series is infinity.

To find the radius of convergence, we use the ratio test, which involves computing the limit of the ratio of successive terms. Applying the ratio test to the given series, we get:

limit as n approaches infinity of [((n+1)!)^k/(k(n+1))!][k!/(n!)^k][x^(n+1)][(kn)!/k!][n!/(kn)!]*[x^n]

Simplifying the expression, we get:

limit as n approaches infinity of [(n+1)/(kx)]*|x|

Since the limit is infinity, the radius of convergence is infinity. This means that the series converges for all values of x.

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If f(x) - 2x2 +5./(x-2), complete the following statement:
The domain for f(x) is all real numbers
than__or equal to 2.

Answers

Answer: Greater than or equal to 2.

Step-by-step explanation:

Given

Function is  \(f(x)=2x^2+5\sqrt{x-2}\)

The entity inside a square root is always positive i.e. greater than equal to zero

\(\therefore \ x-2\geq 0\\\Rightarrow x\geq2\)

So, the domain of the function is all real numbers greater than or equal to 2.

IKEA service desk operates returns, replacements, product defects, and requests for parts. Waiting line observation shows that processing time by customer is 6 minutes, with a 8 minute standard deviation. Customers arrive on average every 2 minutes, with a 1.5 minute standard deviation. There are 5 service desks. Customers take a ticket upon arrival and go to the first available service desk. a. What is the average total time customer will experience in the service area?
b. If IKEA reduce to 4 service desks, what would be the average waiting time?
c. Can IKEA reduce to 3 service desks ? YES/NO, comment.

Answers

The average total time a customer experiences in the service area is 9 minutes. If IKEA reduces to 4 service desks, the average waiting time will become 4 minutes. Yes, IKEA can reduce to 3 service desks.

a. To calculate the average total time a customer will experience in the service area, we need to consider both the waiting time and the processing time.

The average waiting time can be calculated using the M/M/1 queuing model, which assumes that arrivals follow a Poisson distribution and service times follow an exponential distribution. Since we have multiple service desks, we need to use the M/M/c queuing model.

Using the M/M/c model with λ = 0.5 arrivals per minute, μ = 1/6 customers per minute, and c = 5 service desks, we can calculate the average waiting time as:

W = (λ / (c * μ - λ)) * (c / (c - 1)) * (1 / μ)

W = (0.5 / (5 * (1/6) - 0.5)) * (5 / 4) * 6

W = 3 minutes

The average processing time is given as 6 minutes. Therefore, the average total time a customer will experience in the service area is:

Total time = Waiting time + Processing time

Total time = 3 + 6 = 9 minutes

b. If IKEA reduces to 4 service desks, the average waiting time will increase. Using the M/M/c model with λ = 0.5 arrivals per minute, μ = 1/6 customers per minute, and c = 4 service desks, we can calculate the new average waiting time as:

W = (λ / (c * μ - λ)) * (c / (c - 1)) * (1 / μ)

W = (0.5 / (4 * (1/6) - 0.5)) * (4 / 3) * 6

W = 4 minutes

Therefore, the average waiting time would increase from 3 minutes to 4 minutes if IKEA reduces to 4 service desks.

c. It is possible for IKEA to reduce to 3 service desks, but it would result in an increase in the average waiting time. Using the M/M/c model with λ = 0.5 arrivals per minute, μ = 1/6 customers per minute, and c = 3 service desks, we can calculate the new average waiting time as:

W = (λ / (c * μ - λ)) * (c / (c - 1)) * (1 / μ)

W = (0.5 / (3 * (1/6) - 0.5)) * (3 / 2) * 6

W = 6 minutes

Therefore, if IKEA reduces to 3 service desks, the average waiting time would increase from 3 minutes to 6 minutes.

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