building a dam to produce hydro-electric power and create water storage is one way to take advantage of a common renewable resource. this produces much less pollution than a coal burning plant. water being let out of the dam also produces a lot of kinetic (movement) energy. however, building dams are not a perfect solution. what is the most likely problem related to dams?

The work done in bringing a 3.5 kg mass from the surface to a point 20 m above the surface is 28 J.

The work done in bringing a 3.5 kg mass from the surface of the planet to a point 20 m above the surface is equal to the change in gravitational potential energy of the mass. The change in gravitational potential energy (PE) is equal to the product of the mass and the change in gravitational potential (ΔV):

PE = m × ΔV

The change in gravitational potential (ΔV) is equal to the difference between the gravitational potential at the surface and the gravitational potential at the point 20 m above the surface:

ΔV = V_surface - V_20m_above

The gravitational potential difference between the surface and the point 50 m above the surface is given as 20 J/kg, so the difference between the surface and the point 20 m above the surface is equal to 20/50 * 20 = 8 J/kg.

Therefore, the work done in bringing the 3.5 kg mass from the surface to the point 20 m above is equal to:

PE = m × ΔV = 3.5 × 8 = 28 J.

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Answer:

2 and 4

Explanation:

right on edge

Answer:

can confirm its 2 and 4

Explanation:

The combination of a uniform flow and a source can be used to describe flow around a streamlined body called a half- body. (see video v6.5.) assume that a certain body has the shape of a half-body with a thickness of 0.5 m. if this body is placed in an airstream moving at 15 m/s, The source strength is required to simulate flow around the body is (m)= 94.2 kg.

Force is a physical appearance that happen on a object of some amount of masses and then it changes it form and move a bit that called the force. It is a vector quantity. It can be measured in Newton, Dyne.

To calculate the source strength is required to simulate flow around the body we are using the formula here is,

v= m/2*π*b

Or, m= 2*π*b*v

Here we are given,

b=  The thickness of a certain body has the shape of a half-body = 2*r = 2* 0.5 = 1 m

v = The velocity of the object. = 15 m/s.

We have to calculate the values of the source strength is required to simulate flow around the body = m kg

Now we put the values in above equation we get,

m= 2*π*b*v

Or, m= 2*π*1*15

Or, m= 94.2 kg

so we can say that , The source strength is required to simulate flow around the body is (m)= 94.2 kg

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Answer:

The value we are given in the question is 1.24 * 10^7. This form of writing number is called scientific notation. The standard notation is the normal, regular way of writing numbers. Scientific notation and standard notations are interchangeable.

1.24 * 10^7 written in standard notation will be = 1.24 * 10000000 = 12400000.

Thus, the mass of the meteoroid was 12400000 kg.

Explanation:

Answer:

There is no force in space.

Explanation:

Weight is the gravitational force acting on the mass as in space there is no gravity so weight appeares as zero

Answer:

It is because of gravity that your weight of a certain mass becomes zero in space.

Explanation:

Answer:

ME= 196.2 J

KE= 136.2

Explanation:

potential energy=mgh 2*9.81*10

Our ME is quivalent to PE as that is the toal amount of energy in the system

Kinetic energy= 1/2 m\(v^{2}\)

to solve for kinetic enrgy we need to use a kinaetmtic equation that help us find velocity

vf= vi+at

but we need to find time first

d=vi+1/2(accelretaion)\(t^{2}\)

7=0+1/2(9.81)\(t^{2}\)

t= 1.19 s

vf= 0+ 9.81*1.19

vf= 11.67 m/s

Now

1/2 m\(v^{2}\)

1/2*2*\(11.67^{2}\)

= 136. 2

or we could just (PE/10)*7

so (196.2/10)*7

Answer:

14.3°C

Explanation:

Find the ratio of 10°C : 700ml then use the same ratio to 1000ml.

Have a great day <3

Answer:

smh.

Explanation:

When a 79.0 kg firefighter climbs a flight of stairs 29.0 m high, the work done by gravity is -22,872 J.

When the force acts in the direction opposite to the motion, the work done is negative. In this case, the force of gravity is acting opposite to the direction of motion of the firefighter who is climbing the stairs. Hence, work done by gravity is negative.CalculationThe force of gravity acting on the firefighter = Weight of the firefighter

Weight = mg

where m is the mass of the firefighter and g is the acceleration due to gravity.

Weight = 79.0 kg × 9.8 m/s²

Weight = 775.2 N

The work done by gravity can be calculated as follows:

Work done by gravity = Force of gravity × height

Work done by gravity = (775.2 N) × (29.0 m)

Work done by gravity = -22,872 J

Therefore, the work done by gravity is -22,872 J.

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Answer:

Mirror

Explanation:

Given, Number of turns, n = 22Area of each turn, A = 50 cm²

Magnetic field, B = 2 T (initial)Magnetic field, B' = 7 T (final)Time, t = 2.0 s

We need to find the emf induced in the coil. Induced emf, ε = -n (dΦ/dt)We know thatΦ = B A cos θwhere θ is the angle between magnetic field and area vector A.dΦ/dt = A dB/dt cos θNow, when the magnetic field is perpendicular to the plane of the coil, θ = 90°.Hence, cos 90° = 0

Therefore, dΦ/dt = 0Now,\(ε = -n (dΦ/dt) = -n×0 =ε = -n (dΦ/dt) = -n×0 = \)xHence, the induced emf in the coil is 0 V.

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Answer:

· Periodic table, in full periodic table of the elements, in chemistry, the organized array of all the chemical elements in order of increasing atomic number —i.e., the total number of protons in the atomic nucleus. When the chemical elements are thus arranged, there is a recurring pattern called the “periodic law” in their properties, in which elements in the same column (group) have similar properties.

its d btw

Answer:

W = 0.15 J

Explanation:

Given that,

The force acting on the ball, F = 15 N

It makes contact with the ball for a distance of 0.01 m

We need to find the work done on the ball. The work done can be calculated as :

W = Fd

So,

W = (15 × 0.01) J

W = 0.15 J

So, the work done is 0.15 J.

Answer:

a or b

Explanation:

Answer:

The answer is C, condensation or large amounts of water vapor and the second question is correct too.

Explanation:

Answer:

portal of entry link

Explanation:

This what I got hope that helps

Answer:

A

Explanation:

The effects due to light from distant stars

The characteristics of the solar system would have to be known or calculated in order to send a probe to a distant planet, such as Jupiter, due to the effects of the gravity from the other planets. Hence, option C is the correct answer.

When sending a probe to a distant planet, such as Jupiter, one of the critical factors that would have to be known or calculated is the effects due to the gravity from the other planets in the solar system. The gravitational interactions between the planets can significantly influence the trajectory and path of the probe during its journey. Accurate calculations are necessary to ensure that the probe's trajectory is properly planned and adjusted to reach its destination with precision. Hence, option C is the correct answer.

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Answer:

\(V=1.76\times 10^{-4}\ V\)

Explanation:

Given that,

The diameter of a wire, d = 1.628 mm

Radius, r = 0.814  mm = 0.000814m

Current, I = 12.5 mA

The length of the wire, l = 2m

The resistivity of the wire, \(\rho=1.47\times 10^{-8}\ \Omega-m\)

We need to find the potential difference across the wire. We know that the resistance of the wire is given by :

\(R=\rho\dfrac{l}{A}\)

Also, V = IR

\(\dfrac{V}{I}=\rho\dfrac{l}{A}\\\\V=\dfrac{\rho l I}{A}\\\\V=\dfrac{1.47\times 10^{-8}\times 2\times 12.5\times 10^{-3}}{\pi \times (0.000814)^2}\\\\V=1.76\times 10^{-4}\ V\)

So, the potential difference of the wire is \(1.76\times 10^{-4}\ V\).

The approximately 0.0081 joules of energy can be stored in the spring when it is stretched 18 cm from its relaxed state.

To calculate the potential energy stored in a spring, you can use Hooke's Law and the formula for spring potential energy. Hooke's Law states that the force needed to stretch or compress a spring is proportional to the displacement (x) from its equilibrium position: F = kx, where k is the spring constant.

In this case, the spring constant (k) is 0.5 N/m and the displacement (x) is 18 cm (0.18 m). The formula for the potential energy (PE) stored in a spring is PE = 0.5 * k * x^2.

Plugging in the values, we get:

PE = 0.5 * (0.5 N/m) * (0.18 m)^2
PE ≈ 0.0081 J

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Answer:

The magnitude of the force is 12 N Upwards

Explanation:

The force on a positive charge will be in the same direction as the field, but the force on a negative charge will be in the opposite direction to the field. Thus the direction of the force is upward.

Given;

magnitude of charge, q = 0.06 C

magnitude of electric field, E = 200 N/C

The magnitude of the force is given by;

F = qE

F = 0.06 x 200 N/C

F = 12 N Upwards

Therefore, the magnitude of the force is 12 N Upwards

Answer:

A. 12N up

Explanation:

According to the dude above me

The correct statements from the list are:

Low-density hot gases produce emission spectra.

Emission spectra have dark lines.

The size of an electron's orbit depends on its energy.

Electrons will move to higher orbits when an atom absorbs enough energy.

Hot solids emit continuous spectra.

An absorption spectrum is a pattern of dark lines or gaps in a continuous spectrum that is produced when light passes through a cooler gas or a cloud of gas. This pattern is caused by the gas absorbing certain wavelengths of light from the continuous spectrum.

Each element or molecule has a unique absorption spectrum, as they absorb different wavelengths of light based on the energy levels of their electrons. The absorption spectrum can be used to identify the presence of certain elements or molecules in a sample, as well as to study the physical and chemical properties of the gas.

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Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.

\(\Delta p = mv - mu \\\\\implies \Delta p = m(v-u) \\\\F = \dfrac{\Delta p}{\Delta t} = \dfrac{m(v-u)}{\Delta t} = ma\)

F = ma is the formula of Newton’s Second Law of Motion.

To prove Newton's second law of motion,

Given Force F = Δp/Δt

Proof for F=ma

     Let us consider an object of mass m, moving along a straight line with an initial velocity u, final velocity v and it has some particular time t and thus Momentum can be related as,

For initial velocity u, p1 = m × u

The final velocity v, p2 = m × v

The change in momentum can be expressed as

p2 – p1 = (m × v) – (m × u)

p2 – p1 = m (v – u)

Here, we know that the rate of change of momentum with respect to time is proportional to the applied force.

The applied force F,

F ∝ [m (v – u)]/t

F ∝ m × a

As acceleration (a) is the rate of change of velocity with respect to time.

F = k × m × a

F = ma

where k can be the constant.

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Answer:

D

Explanation:

Trees are obviously effected from deforestation.

Pollution effects the things trees need to grow (water, air).

Reduction removes parts of the tree, some parts being needed.

Answer: D

Explanation:Trees are obviously effected from deforestation.

Pollution effects the things trees need to grow (water, air).

Reduction removes parts of the tree, some parts being needed.

Answer:

Four

Explanation:

Answer:4

Explanation:

Answer:

C. amount of charge on the source charge.

Explanation:

Electric field lines can be defined as a graphical representation of the vector field or electric field.

Basically, it was first introduced by Michael Faraday and it is typically a curve drawn to the tangent of a point is in the direction of the net field acting on each point.

The number, or density, of field lines on a source charge indicate the amount of charge on the source charge. Therefore, the density of field lines on a source charge is directly proportional to quantity of charge on the source.

Answer:

Sphere is a geometrical object in dimensional space  that surface of a circle and ball.

Explanation:

Sphere is that the circular objects in the two dimensional space (1) circle

(2) disk. Two dimensional space is a set of points and the distance of that point,The two points of Sphere that length and center.

Sphere can constructed as the named of surface form circle about  any diameter. circle is the special type of the revolution replacing the circle,

sphere is the distance r is the radius of the ball and circle  is the center of mathematical ball,as the center and the radius of the sphere is to respectively.

The ball and sphere has not be maintained mathematical references  as a solid references. A sphere of any radius is centered at the number of zero.

By discussing many topics in the same module and asking you to score your level of confidence, it facilitates learning the content using interleaving.

Numerous applications in geoscience, navigation, and testing of fundamental physics are the focus of cold-atom inertial sensors. For these applications, obtaining high sample rates and high inertial sensitivities over extended interrogation durations is difficult. We describe a cold-atom gyroscope that operates in an interleaved manner, interrogating three atomic clouds at once in an atom interferometer with a sampling rate of 3.75 Hz and an interrogation duration of 801 ms. By effectively averaging vibration noise, interleaving increases inertial sensitivity and enables us to undertake dynamic rotation measurements in a hitherto unknown range. We show a 3 1010 rad s1 stability, which is comparable to the greatest stability values attained with fiber-optic gyroscopes.

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Answer:

Approximately \(1.1 \times 10^{4}\; {\rm Pa}\) and \(8.0 \times 10^{3}\; {\rm Pa}\), respectively (assuming that \(g = 9.81\; {\rm N \cdot kg^{-1}}\).)

The \(55.5\; {\rm kg}\) box exerts more pressure than the \(65.5\; {\rm kg}\) box.

Explanation:

Let \(m\) denote the mass of the \(55.5\; {\rm kg}\) box.

The weight of that box would be: \(W = m\, g\).

The normal force \(N\) that this box exerts on the ground would be the same as its weight: \(N = W = m\, g\).

If the contact area between the box and the ground is \(A\), the pressure \(P\) that this box exerts on the ground would be \(N / A\). That is:

\(\displaystyle P = \frac{N}{A}= \frac{m\, g}{A}\).

The contact area between the ground and this \(55.5\; {\rm kg}\) box is \(A = 0.25\; {\rm m} \times 0.20\; {\rm m}\). Substitute in these values and evaluate to find the pressure:

\(\begin{aligned} P &= \frac{N}{A} \\ &= \frac{m\, g}{A} \\ &= \frac{55.5\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}}}{0.25\; {\rm m} \times 0.20\; {\rm m}} \\ & \approx 1.1 \times 10^{4}\; {\rm Pa}\end{aligned}\).

Similarly, for the \(65.5\; {\rm kg}\) box:

\(\begin{aligned} P &= \frac{N}{A} \\ &= \frac{m\, g}{A} \\ &= \frac{65.5\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}}}{0.20\; {\rm m} \times 0.40\; {\rm m}} \\ & \approx 8.0 \times 10^{3}\; {\rm Pa}\end{aligned}\).

Thus, the \(55.5\; {\rm kg}\) box exerts greater pressure on the ground than the \(65.5\; {\rm kg}\) box.

If the thickness of an absorber is 1.5 cm and 36.45% of a beam is attenuated by the absorber, The half-value layer is 0.51 cm.

The half-value layer (HVL) is a measure of the thickness of an absorber required to reduce the intensity of a beam to half its initial value. In this case, we are given that the absorber attenuates 36.45% of the beam.

To find the HVL, we can use the relationship between the percent attenuation and the thickness of the absorber. The HVL is the thickness at which the beam is attenuated to 50% or 0.5 of its initial intensity.

Since 36.45% of the beam is attenuated by the absorber, the remaining intensity is 100% - 36.45% = 63.55% or 0.6355 of the initial intensity.

We can set up the following equation:

0.5 = 0.6355^x

Solving for x, we find x ≈ 0.51.

Therefore, the half-value layer is approximately 0.51 cm, indicating that a thickness of 0.51 cm of the absorber is required to reduce the beam intensity to half its initial value.

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Answer:

I’d say stuffy. It has the most negative connotation of all the options .

Mark Brainlest please!