The bank reconciliation reveals various errors and discrepancies between ABC Company's records and the bank statement, including missing deposits, incorrect check charges, outstanding checks, unrecorded interest proceeds, fees, NSF charges, and recording errors.
Upon analyzing the bank reconciliation for ABC Company, several discrepancies between the company's records and the bank statement are identified:
A deposit of Br. 410.90 made after banking hours does not appear on the bank statement. This indicates that the deposit was not processed by the bank before the statement was generated.
A check drawn for Br. 79 was charged by the bank as Br. 973. This suggests an error by the bank in processing the check, resulting in an incorrect charge to ABC Company.
Outstanding checks are checks issued in July but have not yet been paid by the bank. The checks include check numbers 801, 888, 890, and 891, with respective amounts of Br. 100.00, Br. 10.25, Br. 294.50, and Br. 205.00.
A check written for Br. 210 was charged by the bank as Br. 120, indicating an error in the bank's recording.
The proceeds from the collection of an interest-bearing note receivable from David, with a face amount of Br. 500, are not reflected in the bank statement.
A Br. 24.75 interest earned on the average account balance during July is included in the bank statement.
A check for Br. 10, which was recorded in the check register as Br. 100, was returned with the statement. This discrepancy could be due to an error in recording the check amount.
A Br. 5.00 fee was charged by the bank for handling the collection of a note receivable.
A Br. 50.25 check from customer John, deposited by ABC Company, was charged by the bank as Non-Sufficient Funds (NSF), indicating that the customer's check bounced.
A Br. 12.70 service charge was imposed by the bank for the month of July.
Check number 875 was issued on July 20 for Br. 85 but was erroneously recorded in the cash payment journal as Br. 58 for the payment of telephone expenses.
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Determine whether each of the following provides enough information to prove that △SQP ≅ △SQR. Select Yes or No for each statement.
Q is the midpoint of PR.
∠P ≅ ∠R
∠SQP is a right angle, ∠PSQ ≅ ∠RSQ
∠SQP is a right angle, m∠P = 33°, m∠RSQ = 57°
∠P ≅ ∠R, ∠PSQ ≅ ∠RSQ
For each statement for triangle SQP and SQR, Q is the midpoint of PR: No, ∠P ≅ ∠R: No, ∠PSQ ≅ ∠RSQ: Yes, m∠P = 33°, m∠RSQ = 57°: No, ∠P ≅ ∠R, ∠PSQ ≅ ∠RSQ: Yes.
What is triangle?
A triangle is a geometric shape that consists of three line segments connected end-to-end to form a closed shape. Triangles are one of the basic shapes studied in geometry and are used in a wide range of applications, from construction to computer graphics.
Here are the answers to whether each statement provides enough information to prove that △SQP ≅ △SQR:
Q is the midpoint of PR: No, this information alone is not sufficient to prove the triangles are congruent. We need additional information about the angles or sides.
∠P ≅ ∠R: No, this information alone is not sufficient to prove the triangles are congruent. We need additional information about the sides or other angles.
∠SQP is a right angle, ∠PSQ ≅ ∠RSQ: Yes, this information is sufficient to prove that the triangles are congruent by the angle-angle-side (AAS) congruence criterion.
∠SQP is a right angle, m∠P = 33°, m∠RSQ = 57°: No, this information alone is not sufficient to prove the triangles are congruent. We need additional information about the sides or other angles.
∠P ≅ ∠R, ∠PSQ ≅ ∠RSQ: Yes, this information is sufficient to prove that the triangles are congruent by the angle-angle-angle (AAA) congruence criterion.
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Quadrilateral QRST has vertices Q(−1,0), R(2,2), S(5,0), T(−1,−4). Determine whether QRST is a trapezoid and if so, determine whether it is an isosceles trapezoid.
The quadrilateral QRST is a trapezoid and not an isosceles trapezoid.
What is trapezoid?A trapezoid, also known as a trapezium, is a flat closed shape having 4 straight sides, with one pair of parallel sides.
Given that, a quadrilateral QRST has vertices Q(−1,0), R(2,2), S(5,0), T(−1,−4).
We need tof verify that it is a trapezoid or not, we will find slopes of each side,
Slope = y₂-y₁ / x₂-x₁
Slope QR = 2-0 / 2+1 = 2/3
Slope RS = 0-2 / 5-2 = -2/3
Slope ST = -4-0 / -1-5 = 2/3
Slope QT = -4/0 = not defined
QR ║ ST
Since, two slope are equal therefore, the quadrilateral QRST is a trapezoid
Finding the distance between QS and TR
QS = √(5+1)²+(0-0)² = 6 units
TR = √(-1-2)²+(-4-2)² = √9+36 = √45 = 6.70
Since, QS ≠ TR, it is not an isosceles trapezoid.
Hence, the quadrilateral QRST is a trapezoid and not an isosceles trapezoid.
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For what value of A is the function, (x), continuous at x=0?
(i) \(\lim_{x \to \frac{\pi^-}{2}}\) h(x) = 3
(ii) \(\lim_{x \to \frac{\pi^+}{2}}\) h(x) = -1
(iii) h(0) = 1/7
The value of λ must be 7, for h(x) to be continuous at x = 0.
The given function is,
h(x) = 1/7, when x = 0
= 1 - 2 cos 2x, when x < π/2
= 1 + 2 cos 2x, when x > π/2
= x cos x/sin λx, when x < 0
Now,
(i) \(\lim_{x \to \frac{\pi^-}{2}}\) h(x) = \(\lim_{x \to \frac{\pi^-}{2}}\) (1 - 2 cos 2x) = 1 - 2 cos π = 1 + 2 = 3
(ii) \(\lim_{x \to \frac{\pi^+}{2}}\) h(x) = \(\lim_{x \to \frac{\pi^+}{2}}\) (1 + 2 cos 2x) = 1 + 2 cos π = 1 - 2 = -1
(iii) h(0) = 1/7
Since the function is continuous at x = 0, so
\(\lim_{x \to 0}\) h(x) = h(0)
\(\lim_{x \to 0}\) x cos x/sin λx = 1/7
\(\lim_{x \to 0}\) cos x.\(\lim_{x \to 0}\) 1/λ(sinλx/λx) = 1/7
1/λ = 1/7
λ = 7
Hence the value of λ must be 7.
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What is the area of the shaded region in the rectangle?10 in.9 inA 45 in.2B90 in.2C 180 in.2D 360 in 2
Step 1: Let's calculate the area of the rectangle. as follows:
Area = Length * Width
Area = 10 * (2 * 9) We see that the base of the triangles is 9 and we have two triangles, thus the lenght of the rectangle is 2 * 9
Area = 10 * 18 square inches
Area = 180 square inches
Step 2: Let's calculate the area of the two triangles that form the shaded region:
Area = (Base - Height)/2
We can see that the base of the triangle is 9, and the height is also the width of the rectangle, 10.
Area = 9 * 10/2
Area = 90/2
Area = 45 square inches
Like we have two triangles, then the shaded area is:
Area = 45 * 2 (You can calculate this multiplication, Lizzy)
And that is the answer to our problem.
If we want to know the area of the non-shaded region, we proceed this way:
Area = Area of the rectangle - Area of the shaded region
Area = 180 - Area of the shaded region
find the radius of this circle.
Answer:
r = 5 units
Step-by-step explanation:
Given:
Angle subtended at the centre (∅) in radians = 2π/3
Arc length (S) = 10π/3
radius (r) = ?
Required:
Radius (r)
Solution:
Formula for arc length given the central angle in radians is:
S = r∅
Make e the subject of the formula by dividing both sides by ∅
S/∅ = r∅/∅
r = S/∅
Plug in the values
r = (10π/3) / (2π/3)
Change the operation sign to multiplication and turn the fraction by your right upside down
r = 10π/3 × 3/2π
r = (10π × 3)/(3 × 2π)
Cross out terms that can divided each other
r = 5
need a lil help please
Answer:
B(2, 4)Step-by-step explanation:
Given points:
A(-1, -9) and M(0.5, -2.5)Let the coordinates of B are (x, y)
Use midpoint formula to determine the point B:
0.5 = (- 1 + x)/2 ⇒ 1 = -1 + x ⇒ x = 1 + 1 = 2-2.5 = (-9 + y)/2 ⇒ -5 = -9 + y ⇒ y = -5 + 9 = 4pecan theatre inc. owns and operates movie theaters throughout florida and georgia. pecan theatre has declared the following annual dividends over a six-year period: year 1, $80,000; year 2, $90,000; year 3, $150,000; year 4, $150,000; year 5, $160,000; and year 6, $180,000. during the entire period ended december 31 of each year, the outstanding stock of the company was composed of 250,000 shares of cumulative, preferred 2% stock, $20 par, and 500,000 shares of common stock, $15 par
Preferred shares = 0.40/25.00 = 1.60%
Common shares = 0.07/17.50 = 0.40%
What is stock market?
The phrase "stock market" describes a number of marketplaces where shares of publicly traded firms can be purchased and sold. Such financial transactions take place on official exchanges and in over-the-counter (OTC) markets that adhere to a predetermined set of rules.
Year Total Preference Common Dividend per
dividend dividend dividend common share
1 80000 80000 0 0.32 0.00
2 90000 90000 0 0.36 0.00
3 150000 130000 20000 0.52 0.04
4 150000 100000 50000 0.40 0.10
5 160000 100000 60000 0.40 0.12
6 180000 100000 80000 0.40 0.16
Note: 2.40 0.42
Preference dividend per year = 250000*$20*2%= 100000
Preference dividend for the 3rd year includes arrear dividend of $20000 for the 1st year
and $10000 for the second year, in addition to the $100000 dividend of that year.
Average annual dividend per share:
Preferred shares = 2.40/6 = $0.40
Common shares = 0.42/6 = $0.07
Average annual percentage return:
Preferred shares = 0.40/25.00 = 1.60%
Common shares = 0.07/17.50 = 0.40%
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There are 5 ten-pound bags and 8 twenty-pound bags of rice on a shelf.How many pounds of rice are on the shelf?
Answer:
210
Step-by-step explanation:
You simply just do some math:
5(10) + 8(20) = ?
50 + 160 = 210 lbs.
Hope it helps :>
XLiV represents 64 true ya false
Answer:
False
Step-by-step explanation:
Given
\(XLIV = 64\)
Required
True or False
The above numeral can be split as follows:
\(XLIV = XL + IV\)
X means 10 and L means 50.
But because X (10) which is smaller comes before L (50), XL is executed as:
\(XL = -10 + 50\)
\(XL = 40\)
In Roman numerals;
\(IV = 4\)
Substitute 40 for XL and 4 for IV.
\(XLIV = 40 + 4\)
\(XLIV = 44\)
Hence;
\(XLIV = 64\) is false
Choose the inequality that represents the following graph.
A x<-5
B x≤-5
C x>-5
D x≥-5
Answer:
x > -5, so the correct answer is C.
To find the quotient of 8➗1/3, multiply 8 by
o 1/8
o 1/3
o 3
o 8
A ball is thrown into the air. The function h(x) = -16x2 + 64x + 8 models the height, in feet above ground, of the ball after x seconds.
What was the height of the ball at the time it was thrown?
How many seconds after being thrown did the ball reach its maximum height?
Answer:
At the time the ball was thrown, it was 8 feet above the ground.
h'(x) = -32x + 64 = 0, so x = 2
The ball reaches its maximum height after 2 seconds.
A truck's position relative to a Carr's position is 60 feet. The car and the truck move in the same direction, but the car moves 5 feet per second faster for 8 seconds. What operation could be used to find the truck's relative position after 8 seconds?
In linear equation ,The truck's relative position with respect to the car is 100 feet
What is linear equation ?
An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation with one variable has the conventional form Ax + B = 0. In this case, the variables x and A are variables, while B is a constant.If the truck is moving at a seed "V" then its position after 8 seconds is going to be:
XT = V* t = V * 8 = 8 V
The car, which is initially 60 feet ahead of the truck and starts moving at 5 m/s faster than the truck, would have a speed given by: V + 5
And its position (relative to the truck's) would be:
XC = 60 + (V + 5) * t = 60 + (V + 5) * 8 = 60 + 40 + 8 V = 100ft + 8 V
then the position of the truck relative to that of the car would be given by the difference:
XT - XC = 8 V - (100 +8 V) = 8 V - 8 V - 100ft = -100 feet
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Solve the system of equation
Answer:
x = 0
y = 1
z = -4
Step-by-step explanation:
6x + 4y + 1z = 0 => z = -6x -4y
If 12x - 4y - 5z = 16, then
12x - 4y - 5(-6x - 4y) = 16
12x - 4y + 30x + 20y = 16
42x + 16y = 16 => 21x + 8y = 8
then y = (8 - 21x)/8
if -24x - 4y + 5z = -24
-24x - 4y + 5(-6x -4y) = -24
-24x - 4y - 30x - 20y = -24
-54x - 24y = -24 => -9x - 4y = -4
substitute y = (8 - 21x)/8
then -9x - 4(8 -21x)/8 = -4
-9x - 1/2(8 -21x) = -4
times 2 in both side
-18x - (8 - 21x) = -8
-18x - 8 + 21x = -8
3x = -8 + 8
3x = 0
x = 0
then y = (8 - 21x)/8 = (8 - 21(0))/8 = (8 - 0)/8 = 8/8 = 1
then z = -6x -4y = -6(0) - 4(1) = 0 - 4 = -4
Hope this helps
A triangle is 4 cm wider than it is tall. The area is 16 cm2. Find the height and the base.
Step-by-step explanation:
base = 4cmarea = 16cm²height = ?
area = 1÷2 × base × height
16cm² = 1/2 × 4cm × height
height = (2 × 16)÷4
height = 8cm_______________FOLLOW MEBlake needs a wooden dowel that is 2 1/6 feet
long. How much should he cut off the dowel
shown below?
-5 1/4 ft
Blake needs a wooden dowel that is 2 1/6 feet long. Blake needs to cut off 7.4167 feet from the dowel.
What are arithmatic operations?
Arithmetic operations is a branch of mathematics, that involves the study of numbers, the operation of numbers that are useful in all the other branches of mathematics. It basically comprises operations such as Addition, Subtraction, Multiplication, and Division.
To find out how much Blake should cut off the dowel, we need to subtract the length of the dowel from the required length.
The length of the dowel is -5 1/4 feet, which can be written as -5.25 feet.
The required length is 2 1/6 feet, which can be written as 2.1667 feet (rounded to four decimal places).
To find out how much needs to be cut off, we can subtract the length of the dowel from the required length:
2.1667 ft - (-5.25 ft) = 7.4167 ft
Therefore, Blake needs to cut off 7.4167 feet from the dowel.
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3,998-(-7)= can you please help me with this problem
Answer:
4005
Step-by-step explanation:
3,998 - (-7) = ?
Two negative signs will make a positive sign.
3,998 - (-7) = 3998 + 7 = 4005
So, the answer is 4005
james determined that these two expressions were equivalent expressions using the values of x=4 and x=6 which statements are true? Check all that apply.
Answer: I got 1, 4, and 7
brainlist plz:)
Step-by-step explanation:
use elimination to solve each system below:
system 1 system 2
4x+3y=4 3x+2y=7
-2x-3y=-8 2x-y=7
enter the value of x and y in the solution for each in the following table
value of x value of y
system 1
system 2
Answer:
SYSTEM 1
\(4x + 3y = 4 - - - eqn(i) \\ - 2x - 3y = - 8 - - - eqn(ii) \\ eqn(i) + eqn(ii) \\ = > 4x - 2x = 4 - 8 \\ 2x = - 4 \\ x = \frac{ - 4}{2} \\ x = - 2 \\ in \: eqn(i) \: \: 4x + 3y = 4 \\ but \: x = - 2 \\ = > 4( - 2) + 3y = 4 \\ = > - 8 + 3y = 4 \\ 3y = 12 \\ y = \frac{12}{3} \\ y = 4\)
SYSTEM 2
\(3x + 2y = 7 - - - eqn(i) \\ 2x - y = 7 - - - eqn(ii) \\ multiply \: eqn(ii) \: by \: 2 \\ = > 4x - 2y = 14 - - - eqn(iii) \\ eqn(i) + eqn(iii) \\ = > 7x = 21 \\ x = \frac{21}{7} \\ x = 3 \\ in \: eqn(ii) \: 2x - y = 7 \\ but \: x = 3 \\ hence \: \: 2(3) - y = 7 \\ y = 6 - 7 \\ y = - 1\)
find the values of x and y
The value of x is 1.75 and y is 5. The solution is obtained using properties of congruent triangles.
What is a congruent triangle?
Two triangles that are congruent will have precisely the same three sides and three angles.
The dimensions of the triangles' sides and angles determine whether two or more triangles are congruent. A triangle's size is determined by its three sides, and its shape by its three angles. Pairs of corresponding sides and corresponding angles in two triangles are said to be equal if they are congruent. They share a similar size and shape. In triangles, there are numerous congruence conditions.
The triangles are congruent by SAS congruency because
AC = CD (Given)
∠ACB = ∠DCE ( Vertically opposite angles)
BC = CE (Given)
Thus, Triangle ABC ≅ Triangle DEC
Since, the triangles are congruent, therefore
⇒AC = CD
⇒4y-6 = 2x+6 ...(1)
Also, BC = CE
⇒3y+1 = 4x
⇒(3y+1)/4 = x ...(2)
Now, substituting the value of x in (1), we get,
⇒4y-6 = 2(3y+1)/4+(6)
⇒4y-6 = (6y+2 +24)/4
⇒16y-24 = 6y+2 +24
⇒10y = 50
⇒y = 5
Now putting the value of y in (2), we get
⇒(3(2)+1)/4 = x
⇒7/4 = x
⇒ x = 1.75
Hence, the value of x is 1.75 and y is 5.
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Help me with this please
The proposed skyscraper is 172.8 m tall
Scale drawingFrom the question, we are to determine the how tall the proposed skyscraper is in meters
From the given information,
The scale of the model is
1 in : 7.2 m
and
The model is 2 ft tall
First, convert 2 ft to inches
NOTE: 1 foot = 12 inches
∴ 2 feet = 2 × 12 inches
= 24 inches
Now,
If 1 inch represents 7.2 m
Then,
24 inches will represent 24 × 7.2 m
24 × 7.2 m = 172.8 m
Hence, the proposed skyscraper is 172.8 m tall
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m23 is (3x + 4)º and mz5 is (2x + 11)
Angles 3 and 5 are
p
12
4
can be
w/
The equation
used to solve for x.
O
56
78
m25 =
V
9514 1404 393
Answer:
same-side interior(3x +4) +(2x +11) = 18077°Step-by-step explanation:
Angles 3 and 5 are on the same side of the transversal, between the parallel lines, so can be called "same-side interior angles". These are also called "consecutive interior angles". As such, they have a sum of 180°, so are also "supplementary angles." We don't know what your pull-down menu options are, but perhaps one of these descriptions is on there.
__
Because the angles are supplementary, their sum is 180°. So, the equation ...
(3x +4)° +(2x +11)° = 180°
can be used to solve for x. Likewise, any of the possible simplifications of this can be use:
(3x +4) +(2x +11) = 180 . . . . . divide by degrees
5x +15 = 180 . . . . . . . . . . . collect terms
5x = 165 . . . . . . . . . . . . . subtract 15
x = 33 . . . . . . . . . . . . . . divide by 5
__
Once we know that x=33, then the measure of angle 5 is found from its expression:
m∠5 = (2x +11)° = (2·33 +11)°
m∠5 = 77°
This table shows the ratio of the number of red beans to the total number of beans.
A 2-column table has 2 rows. Column 1 is labeled Total with entries 30, and 15. Column 2 is labeled Red with entries 20, and 10.
Which ratios are equivalent to 30:20? Check all that apply.
40:30
10:0
3:2
the answer is C and D
The ratio which is equivalent to 30:20 is option C, 3:2.
How to obtain real measurements from the ratio of two measurements?Suppose the real measurements were "a" and "b"
Then their ratio will be formed as
\(\dfrac{a}{b} = \dfrac{p \times x}{q \times x} = \dfrac{p}{q}\)
where is a common factor (not 1)? This shows that to get the real measurements from the given ratio, we need to assume to have some factor possibly canceled from both the numerator and the denominator.
Thus, a = px, b = qx
We have given that a 2-column table has 2 rows. Column 1 is labeled
The Total with entries 30, and 15. Column 2 is labeled Red with entries 20, and 10.
Given ratio is 30:20
Or
3:2
Therefore, we can conclude that the ratio which is equivalent to 30:20 is option C, 3:2.
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Need help fast what is 8 ones and 9 hundredths in decimal or standard form plz.
Anyone available to help me with this?
Answer:
Step-by-step explanation:
The angles shown are alternate exterior angles, so they are congruent. Therefore, to find x, you can simply set up an equation like so:
\(6(x+7)=24(x-8)\\6x+42=24x-192\\-18x=-234\\x=13\)
Now, we plug in x=13 to the remaining equations:
\(6(13+7)\\=6(20)\\=120\)
(top)
\(24(13-8)\\=24(5)\\=120\)
(bottom)
log2(1/128)=x, then x =
The value of x will be -7. The expression is solved using the identity.
What is the definition of a logarithm?Exponents can also be written as logarithms. The other number is equal to a logarithm with a number base. It's the exact inverse of the exponent function.
Given expression;
\(\rm log_2(\frac{1}{128}) = x\)
The expression is solved using the identity as;
\(\rm log_e1 = x\\\ e^x=1\)
Apply the identity;
\(\rm log_2(\frac{1}{128}) = x \\\\ 2^x = \frac{1}{128}\\\\ 2^x = \frac{1}{2^7} \\\\ 2^x = 2^{-7} \\\\ x = -7\)
Hence the value of x will bed -7.
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How many solutions does the system have?
You can use the interactive graph below to find the answer.
y=3x+3
y=-2x+3
(Choice A)
A
Exactly one solution
(Choice B,)
B
No solutions
(Choice C)
C
Infinitely many solutions
Answer:
its A exactly one soulution
Step-by-step explanation:
what is the length of the conjugate axis? (y-2)^2/16 -(x+1)^2/144=1
Answer: 24
A hyperbola is the locus of a point in a plane which moves in the plane in such a way that the ratio of its distance from a fixed point in the same plane to its distance from a fixed line is always constant, which is always greater than unity.
the fixed point is called the focus and the fixed line is directrix and the ratio is the eccentricity.
The general equation for the vertical hyperbola is
[ (y-k)^2 / a^2 ] – [ (x-h)^2 / b^2 ] = 1
The conjugate axis of the vertical hyperbola is y = k
Length of the conjugate axis = 2b
According to the question k = 2, h = -1, a = 4, b = 12
Length of the conjugate axis = 2b = 2 * 12 = 24
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Rewrite u = kx + y, for x
If the image is rotated about the x-axis, which of the following images best represents the result?
A. Y
B. Z
C. X
D. W
The images best represents the result is image W.
We have, the image is rotated about the x-axis.
Now, rotating around x axis can give the other half of the image.
Also, rotating about x axis gives the mirror image of the figure.
So, the rotation leads to a circle.
and, In three dimensional we can say that Sphere.
Thus, the required image is W.
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