CA-Common Core English Language Arts 9 A

A property parcel's acreage can be determined by multiplying its length by its width and dividing the result by 43,560, the number of square feet in an acre.

The entire acreage can be estimated using the following formula given that the Texas railroad segment is 1908 feet by 1902 feet:

1908 feet by 1902 feet divided by 43,560 feet per acre equals 83.063 acres.

We can just split this acreage by two to get half of it:

Half an acre is equal to 83.063% of an acre, or 41.5315 acres.

Therefore, 41.53 acres would be about half of the Texas railway section. It's important to note that this computation makes the assumption that the parcel is rectangular and has straight edges.

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The size of a property lot can be calculated by multiplying its width and length and then dividing the product by 43,560, which is the equivalent of one acre in square feet.

If the Texas railroad segment measures 1908 feet by 1902 feet, the total area can be computed utilizing this equation.

83063 acres can be calculated by dividing an area of 1908 feet by 1902 feet by the conversion factor of 43,560 feet per acre.

We can easily divide this piece of land into two equal parts, obtaining half of it.

An area of 0. 5 acres can be expressed as 83. 063% of an entire acre or approximately 41. 5315

Hence, the Texas railroad section would comprise roughly twice the area of 41. 53 It should be emphasized that in this calculation, the parcel is assumed to have a rectangular shape and its edges are straight.

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Answer:That only applies to highly polished surfaces, eg mirrors.

If you take a high quality laser (ie with low divergence) and aim it at a wall, you can see the spot where the laser beam reaches the wall from anywhere with a direct line-of-sight to the spot where the laser beam reaches the wall. This due to micro imperfections on the surface of the wall. At a microscopic level, the wall surface is very rough and pointing in all directions.

As to why, a beam of light bounces of a highly polished surface, I can only surmise that it is essentially due to kinematics, ie the only force opposing the light beam is normal to the surface, hence there no forces along the reflective surface. Since there are no forces along the reflective surface, the speed component of light along the reflective surface remains unchanged. However, on the plane perpendicular to the reflective surface the, the light photons bounce off at the same speed at which the hit the reflective surface because the mass of the reflective surface is much much much larger than the mass of the photons, which means that the reflective surface won’t move at all. Since conservation of momentum requires that momentum after the collision be the same as the momentum before the collision then the only way for that to happen is if the velocity of the photon perpendicular to the reflective surface is of exactly the same magnitude but in the opposite direction. Vector resolution of the speed component of the reflected beam means that the angle of reflection must be the same as the angle of incidence.

Explanation:

Therefore, the work done by the pushing force is 400 Joules.

The work done by a force can be calculated using the equation W = Fd cosθ, where W is the work done, F is the force applied, d is the distance covered, and θ is the angle between the force and the direction of motion.
In this case, the force on the crate is parallel to the slope, so the angle θ is 0 degrees. The force applied is the weight of the crate, which is given as 80 N. The distance covered is 5.0 m. Plugging these values into the equation, we get:
W = (80 N)(5.0 m) cos(0°)
Since cos(0°) = 1, the equation simplifies to:
W = (80 N)(5.0 m)(1)
W = 400 J
Therefore, the work done by the pushing force is 400 Joules.

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A sound bridge is a d) overlapping the sound of one scene into the next

Sound bridging is an editing technique used to transition through sound from one scene to another. sound bridges, also known as audio bridges, allow filmmakers to enter and exit scenes by filling the gaps with audio. An audio bridge will connects two scenes, allowing the audio of the subsequent scene to play over the previous scene before showing the next shot. The technique used to accomplish this is known as J-cut.

There are different types of sound bridge namely

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Answer:

You should still workout 90 min.

The proper time is measured by a single clock in a single place.

The proper time on earth is 90 min.

The clock on the rocket is also in a single place in the frame of the rocket so you still need to workout for 90 min.

Answer:

2%

Explanation:

E=l/E x r/R x100%

=5000/50 x 0.1/0.6 x100

=2% or 166.7

Answer:

A Transparent

Explanation:

Hope it helps!!!

To determine the mass in kilograms of an object with a weight of 150 kN, we need to convert the weight to mass by dividing it by the acceleration due to gravity.

The weight of an object is the force exerted on it due to gravity, while mass is a measure of the amount of matter in an object. Weight is calculated by multiplying the mass of an object by the acceleration due to gravity. In this case, we are given the weight of the object as 150 kN.

To find the mass, we divide the weight by the acceleration due to gravity, which is approximately 9.8 m/s². Converting 150 kN to Newtons (N) by multiplying by 1000, we have:

Weight = 150 kN = 150,000 N

Now, dividing the weight by the acceleration due to gravity:

Mass = Weight / Acceleration due to gravity

Mass = 150,000 N / 9.8 m/s²

Calculating this value gives us the mass of the object in kilograms.

Understanding the difference between weight and mass is fundamental in physics. Weight depends on the gravitational force acting on an object, while mass represents the amount of matter an object contains. Converting between weight and mass requires dividing or multiplying by the acceleration due to gravity, which can vary slightly depending on the location on Earth or the celestial body in question.

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Answer:

5,600

Explanation:

You split x10^15 into x10^12 and x10^3. Our new equation is 5.6x10^3x10^12

We do 5.6x10^3 and we get 5,600. Our new equation is 5,600x10^12. I hope this answered your question.

The final volume of water in the container after increasing the temperature is 203.8 m³.

From the given,

The initial volume of water (Vο) = 200 cm³

Initial temperature = 4°C = 4+273 = 277K

Final temperature = 95°C = 273+95 = 368 K

Volume expansion co-efficient = 210×10⁻⁶(°C)⁻¹

Final volume =?

β = 1/Vο (ΔV/ΔT),  β represents the volume expansion coefficient, ΔV change in volume, ΔT is the change in temperature, and Vο is the initial volume.

ΔV = β×Vο×ΔT

     = 210×10⁻⁶×200×(368-277)

    =  210×10⁻⁶×200×91

ΔV = 3.83 m³

ΔV = final volume - initial volume

final volume = ΔV + 200

                    = 3.82 +200

                    = 203.82 m³

Final volume = 203.82 m³.

Thus, the final volume of the water is 203.82 m³.

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Answer:

The answer is A. Cementing...

Explanation:

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Answer:

plate tectonics

Explanation:

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Answer:

F t = m Δv         impulse delivered = change in momentum

Δv = 100 * .1 / .5 = 20 m/s     original speed of puck

KE = 1/2 m v^2 = .5 * 20^2 / 2 = 100 J     initial KE of puck

E = μ m g d        energy lost by puck

Ff = μ m g = m a      deceleration of puck due to friction

a = μ  g = 9.8 * .2 = 1.96 m/s^2

v2 = a t + v1 = -1.96 * 4 + 20 = 12.2 m/s     speed of puck on striking box

m v2 = M V       conservation of momentum when puck strikes box

V = m v2 / M = 12.2 * .5 / .8 = 7.63 m/s     speed of box after collision

KE = 1/2 M V^2 = .8 * 7.63^2 / 2 = 23.3 J     KE of box after collision

KE = μ M g d     energy lost by box in sliding distance d

d = 23.3 / (.3 * .8 * 9.8) = 9.91 m     distance box slides

Scalar quantities have magnitude only, while vector quantities have magnitude and direction. Scalars can be added algebraically, while vectors follow specific rules. Scalars have a single value, while vectors require representation with magnitude and direction.

Scalar quantities and vector quantities are two fundamental types of physical quantities used in physics. Here are five key differences between scalar and vector quantities:

1. Definition: Scalar quantities are defined by magnitude only, meaning they have a numerical value but no specific direction. Examples of scalars include time, temperature, mass, and speed. In contrast, vector quantities have both magnitude and direction. Examples of vectors include displacement, velocity, force, and acceleration.

2. Representation: Scalar quantities are represented by a single numerical value or variable, often accompanied by appropriate units. For instance, temperature can be represented by a value like 25 degrees Celsius. Vector quantities, on the other hand, require a representation that includes both magnitude and direction. This can be achieved using vectors or by using a combination of numerical values and angles.

3. Addition and Subtraction: Scalar quantities can be added or subtracted algebraically by simply considering their numerical values. For example, adding two temperatures of 10 degrees Celsius and 15 degrees Celsius gives a result of 25 degrees Celsius. In contrast, vector quantities follow different rules for addition and subtraction. Vector addition involves considering both the magnitude and direction of the vectors, using methods such as the parallelogram law or the triangle law.

4. Algebraic Operations: Scalar quantities can undergo all basic algebraic operations, such as multiplication, division, addition, and subtraction. These operations apply only to the numerical values of the scalars. Vector quantities, however, have additional operations specific to vectors, including dot product and cross product, which involve both the magnitude and direction of the vectors.

5. Physical Interpretation: Scalar quantities represent quantities that can be fully described by a single value, such as the magnitude of a quantity. For example, the speed of an object is a scalar that represents the magnitude of its velocity. Vector quantities, on the other hand, have physical interpretations that involve both magnitude and direction. For instance, displacement represents both the distance and the direction from the starting point to the endpoint.

In summary, scalar quantities have magnitude only, while vector quantities have both magnitude and direction. Scalars are represented by single numerical values, while vectors require representation with both magnitude and direction. Scalar quantities can be algebraically added or subtracted, whereas vector quantities follow specific rules for vector addition and subtraction. Scalars can undergo all basic algebraic operations, while vectors have additional vector-specific operations. Scalar quantities represent fully describable quantities, while vector quantities require consideration of both magnitude and direction for a complete description.

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Answer:

Inside the film the wavelength will be λ/n

For constructive interference to occur the film must be λf/4 thick where λf is the wavelength of the light in the film - there will be a 180 degree phase shift at the water/film interface since the index of refraction of the film is greater than that of water - and the light has to travel λ/2 inside the film for constructive interference to occur

280 nm / 1.6 * 4 = 700 nm is the greatest wavelength allowed

Note that 700 nm is also the upper wavelength of the visible spectrum

The characteristics of image formed is a real, inverted, highly magnified image and at infinity.

The following are the general properties of image formed by a convex lens when the object is placed at focal point of the lens;

Thus, when an object is placed at the focal point of a convex lens, the image formed is a real, inverted, highly magnified image and at infinity.

These properties can be seen in the ray diagram attached to this solution.

To construct the ray diagram, draw a line from the top of the image through the focal point and principal axis.

If you look at the lens diagram carefully, you will notice that;

So the object is placed at the focus of the lens.

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When a negatively charged object is introduced close to the ball of the electroscope, if the metal leaves of the instrument separate even more, the charge close to the ball is likewise negatively charged.

Yes, it is possible to determine the sign of the charge close to the ball of an electroscope if the electroscope itself has a negative charge.

An electroscope consists of a metal ball at the end of a metal rod, with metal leaves hanging from the ball. The ball and the leaves are all made of conductive materials. When a charged object is brought close to the ball, it induces a separation of charges in the leaves, causing them to repel each other and move apart.

If the electroscope is negatively charged, it means that the metal leaves of the electroscope have an excess of electrons. When a positively charged object is brought close to the ball, it will attract electrons from the ball, which will flow down the metal rod and into the leaves. This will neutralize the negative charge on the leaves and cause them to collapse.

On the other hand, if a negatively charged object is brought close to the ball, it will repel the electrons in the ball and cause them to move towards the top of the metal rod, inducing a greater negative charge on the leaves. This will cause them to move even further apart, indicating the presence of a negative charge close to the ball.

Therefore, if the metal leaves of the electroscope move apart further when a negatively charged object is brought close to the ball, it indicates that the charge close to the ball is also negative.

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The approximate distance to the galaxy is 78.7 million light-years.

The shift in the absorption line wavelength can be attributed to the Doppler effect, specifically the redshift caused by the expansion of the universe. We can use Hubble's law to estimate the distance to the galaxy. Hubble's law states that the recessional velocity of a galaxy is proportional to its distance from us. The equation is v = H0 * d, where v is the recessional velocity, H0 is the Hubble constant, and d is the distance. Rearranging the equation, we have d = v / H0. The redshift of the absorption line corresponds to the recessional velocity of the galaxy. By knowing the redshift and the Hubble constant, we can calculate the approximate distance. Considering the redshift from the given wavelength shift and using a Hubble constant of 70 km/s/Mpc, we find that the approximate distance to the galaxy is 78.7 million light-years.

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The ratio of the load arm to effort arm is 0.25 to 1, or 1 to 4.

The load arm is the distance between the fulcrum and the point where the load or weight is applied to the lever. The effort arm, on the other hand, is the distance between the fulcrum and the point where the effort or force is applied to the lever.

The mechanical advantage (MA) of a lever is defined as the ratio of the load arm to the effort arm. Mathematically, this can be expressed as:

MA = Load arm / Effort arm

If the mechanical advantage is given as 0.25, we can set up the equation as follows:

0.25 = Load arm / Effort arm

To solve for the ratio of load arm to effort arm, we can rearrange the equation as:

Load arm / Effort arm = 0.25

Therefore, the ratio of load arm to effort arm is 0.25 to 1, or 1 to 4. This means that the load arm is four times longer than the effort arm in this lever system.

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A car would be easier to push than a bus. The primary reason for this is the difference in mass and weight between the two vehicles. A bus would be harder to stop compared to a car. This is due to the same reason of mass and weight. The greater the mass and weight of an object, the more force is required to change its state of motion (e.g., push or stop it).

Generally speaking, a car would be easier to push than a bus. The primary reason for this is the difference in mass and weight between the two vehicles. Buses are considerably larger and heavier than cars, meaning they have greater inertia and resistance to motion. Inertia is a property of matter that describes an object's tendency to resist changes in its state of motion. The greater the mass of an object, the greater its inertia. On the other hand, a bus would be harder to stop compared to a car. This is due to the same reason of mass and weight. Buses have more momentum due to their larger mass, and stopping a vehicle with more momentum requires greater force and distance. Additionally, buses typically have larger and more powerful braking systems to handle their increased weight and inertia. Based on this example, we can formulate a general principle: The greater the mass and weight of an object, the more force is required to change its state of motion (e.g., push or stop it). This principle highlights the importance of considering mass and weight when analyzing the motion and dynamics of objects.

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Jane's rate along the summit was 25 mph.

Let's assume that Jane's rate along the summit is represented by the variable "x" in miles per hour. We know that she rode 72 miles uphill at a rate that was 5 mph slower than her rate along the summit. Therefore, her rate uphill would be (x - 5) mph.

To find her average rate for the entire journey, we can calculate the total time taken for each segment and divide it by the total distance covered.

Time taken to ride uphill = Distance / Rate

Time taken to ride uphill = 72 miles / (x - 5) mph

Time taken to ride along the summit = Distance / Rate

Time taken to ride along the summit = 21 miles / x mph

Since the total time taken for the entire journey is 3 hours, we can write the equation:

Time taken to ride uphill + Time taken to ride along the summit = Total time

72 / (x - 5) + 21 / x = 3

By solving this equation, we find that x = 25 mph. Therefore, Jane's rate along the summit was 25 mph.

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Answer:

Aircraft never crash because of one single issue. It's almost always a combination of factors that lead to an accident. Whilst flying is extremely safe, typical reasons why planes crash include pilot error, technical failures, bad weather, terrorism, and pilot fatigue.

Answer The force of the air pushing up on the plane is

equal to the force of gravity pulling down on the

plane.

Answer:

The answer is "perpendicular and distance".

Explanation:

The Perpendicularity would be the connection of two lines that meet in such a right angle perpendicularity (90 degrees). It extends to all geometric objects involved.

The Distance was its cumulative motion of a body regardless of the direction that's why the value "d" is perpendicular to the distance from the transformer.

Answer:

His third law states that for every action or force in nature there is an equal and opposite reaction.

Explanation:

The heavier the books get, the harder it is for Molly to exert enough force to move the cart.

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The intensity level of the sound from the leaf blower is approximately 113 decibels.

To find the intensity level in decibels, we need to use the formula:

IL = 10 * log(I/Iref)

where:

IL is the intensity level in decibels

I is the measured intensity of the sound

Iref is the reference intensity, which is equal to 1 × 10⁻¹² W/m²

In this case:

the measured intensity (I) is 22x10⁻² w/m²

the reference intensity (Iref) is typically 10⁻¹² w/m²

Plugging in these values, we get:
IL = 10 * log((22x10⁻²)/(10⁻¹²))

Now, simply calculate the log and multiply by 10 to find the intensity level in decibels:
IL ≈ 10 * log(220000000000) ≈ 113.42 dB

So, the intensity level of the sound from the leaf blower is approximately 100 decibels.

The complete question could be as follows:

The intensity of the sound from a certain leaf blower is measured at 22x10⁻² w/m² . Find the intensity level in decibels.

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Answer:

the car slowed at a rate of 2.93 mph

A star leaves the horizontal branch in the HR diagram (Hertzsprung-Russell) when it exhausts its helium supply in the core.

In case of HR diagram: The luminosity (brightness) and temperature of stars are graphically represented by the Hertzsprung-Russell (HR) diagram. It demonstrates a relationship between a star's colour (temperature) and absolute magnitude (luminosity), assisting in the division of stars into main-sequence objects, giants, supergiants, and white dwarfs.

1. A star is located on the horizontal branch after it has evolved from the red giant phase.
2. During the horizontal branch phase, the star's core is primarily fusing helium into carbon and oxygen.
3. As the helium supply in the core is depleted, the fusion process slows down.
4. Once the helium is exhausted, the star leaves the horizontal branch and moves to the next stage of its evolution, which may involve becoming an asymptotic giant branch (AGB) star or directly transitioning to the planetary nebula phase, depending on its mass.

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