cadmium is like zinc in that it always carries a 2 charge when in an ionic compound. cadmium acetate undergoes a single replacement reaction with solid aluminum. what is the coefficient of cadmium metal in the balanced equation?

Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass = 12 g

volume = final volume of water - initial volume of water

volume = 18.5 - 14 = 4.5 mL

So we have

\(density = \frac{12}{4.5} \\ = 2.66666666...\)

We have the final answer as

Hope this helps you

Answer:

C) Highly reactive

Explanation:

An atom with one or two valence electrons more than a closed shell is highly reactive, because the extra valence electrons are easily removed to form a positive ion

According to the electronic configuration, an atom that has one or two valence electrons is most likely to be highly reactive  as it can easily loose 1 or 2 electrons.

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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Answer:

The answer is "Ammonium nitrate is the reactant of this chemical reaction".

Explanation:

The Ammonium nitrate (NH4NO3)  is an ammonium and nitrate ionic crystalline solid. In water and hygroscopic as a strong, it's also highly soluble, although it does not form hydrates.

It uses as a nutrient for generating medications as well as leaven fertilizers and explosive materials. Nitrate in ammonium is sodium bicarbonate ammonium chloride. It is incendiary, an oxidizing agent, and a fertilizer.

The concentration of conjugate base in the buffer change after the addition of a small amount of strong base The concentration of conjugate base will increase. HA+BOH ⇒ H2O +AB

Buffer capacity refers to the amount of added acid or base that can be neutralized by a buffer. This is determined by the concentration of the conjugate acid and conjugate base. As these concentrations increase, the buffering capacity increases. A buffer is a solution that can withstand changes in pH due to the addition of acidic or basic components.

Can neutralize small amounts of added acids or bases and keep the pH of the solution relatively stable. When a strong base is added to a buffer the hydroxide ions are consumed by the weak acid, forming water, and consumed by the weak conjugate base of the acid. The number of weak acids decreases and the number of conjugate bases increases.

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The balanced chemical equation between pottasium and chlorine is as follows: 2K + Cl₂ → 2KCl. It is a combination reaction.

A chemical reaction is a process, typically involving the breaking or making of interatomic bonds, in which one or more substances are changed into others.

According to this question, a chemical reaction occurs between potassium metal and chlorine gas to form pottasium chloride as follows:

2K + Cl₂ → 2KCl

The chemical reaction is a combination reaction because it involves the combination of two elements to form a compound.

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If pressure is increased, keeping the volume constant, according to the ideal gas law, temperature increases. Therefore, option (D) is correct.

Gay-Lussac's law can be stated when the volume of the given gas is kept constant and the pressure (P) of a gas is directly proportional to the absolute temperature (T).

The mathematical equation of Gay Lussca's law can be represented as follows:

P/T = k

This law can be expressed as the pressure is directly proportional to the temperature of the gas.

P ∝ T                         (where V volume of gas kept constant)

or P₁/T₁ = P₂/T₂

Where P₁ and T₁ represent the initial pressure and initial temperature of the gas. The P₂ and T₂ represent the final pressure and temperature of the gas.

The ideal gas law permits to the prediction of how the properties of a gas change under given circumstances, given an initial change. Therefore, according to the ideal gas law, if pressure is increased, keeping the volume constant, and temperature increases.

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Student 2 explains why the water only condensed on the top part of the test tube using sound scientific reasoning. The process through which a gas transforms into a liquid is called condensation. Therefore, choice B is right.

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4.5 days will pass if 2. 40 mg of calcium-47 decayed to 1. 2 mg of calcium-47.

The decay of calcium-47 is a first-order process, so we can use the equation for radioactive decay,

N(t) = N0 * e^(-kt)

where N(t) is the amount of calcium-47 at time t, N0 is the initial amount of calcium-47, k is the decay constant, and e is the base of the natural logarithm.

The half-life of calcium-47 is 4.5 days, so we can use the half-life to find the decay constant,

t1/2 = 0.693 / k

k = 0.693 / t1/2

k = 0.693 / 4.5 days

k = 0.154 days^-1

Now we can use the equation for radioactive decay to find the time elapsed between the initial amount (N0 = 2.40 mg) and the final amount (N(t) = 1.2 mg),

N(t) = N0 * e^(-kt)

1.2 mg = 2.40 mg * e^(-0.154 days^-1 * t)

0.5 = e^(-0.154 days^-1 * t)

ln(0.5) = -0.154 days^-1 * t

t = ln(0.5) / (-0.154 days^-1)

t = 4.50 days

Therefore, approximately 4.5 days have passed since 2.40 mg of calcium-47 decayed to 1.2 mg of calcium-47. However, since we are asked to express our answer using two significant figures, we round the answer to 4.5 days.

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--The complete question is, How many days have passed if 2.40 mg of calcium-47 decayed to 1.2 mg of calcium-47? Express your answer using two significant figures.--

To determine the number of grams of sulfur dioxide formed when 10.0 mol of copper(I) sulfide reacts during the process of roasting, we need to use the balanced chemical equation and the molar masses of the compounds involved.

The balanced chemical equation for the reaction of copper(I) sulfide (Cu2S) with oxygen (O2) to form copper(I) oxide (Cu2O) and sulfur dioxide (SO2) is:

2 Cu2S + 3 O2 → 2 Cu2O + 2 SO2

From the balanced equation, we can see that for every 2 moles of Cu2S, 2 moles of SO2 are formed.

Therefore, using the stoichiometry of the reaction:

10.0 mol Cu2S * (2 mol SO2 / 2 mol Cu2S) = 10.0 mol SO2

Next, we can calculate the mass of sulfur dioxide using the molar mass of SO2, which is approximately 64.06 g/mol:

Mass of SO2 = 10.0 mol SO2 * 64.06 g/mol

= 640.6 g

Therefore, when 10.0 mol of copper(I) sulfide reacts during roasting, approximately 640.6 grams of sulfur dioxide are formed.

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Answer:

the trigger . it's the trigger

Answer:

It is the handle

Explanation:

I know because I did this test in school

Answer:

You gave no examples

Explanation:

Basically any amount that equals to 8, so all noble gases

Gravity is a (n) force between objects and depends on an object's size and their distance apart.

Gravitational force is the attractive that exist between all object with mass an object with mass attracts another object with mass the magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the distance between the two objects

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Answer:

I hope that's what u were lookong for :))

Explanation:

Answer: 10

Explanation:

The volume of the stone is:

New Water level - Orginal Water level = Volume

35 - 30=5

The mass of the stone is 50

Density=mass/volume

X= 50/5

The density of the Stone = 10g/cm

The transcription product of the DNA sequence 5ʹ-TGCCA-3ʹ is mRNA with the sequence 5ʹ-ACGGU-3ʹ.

Transcription is the process by which the genetic information present in DNA is copied into RNA. The transcription process takes place in the nucleus of the cell, and DNA acts as a template for mRNA synthesis. mRNA is synthesized using RNA polymerase enzyme, which catalyzes the formation of mRNA strands with complementary base pairs to the template DNA strand.

The DNA sequence 5ʹ-TGCCA-3ʹ has the following complementary sequence 3ʹ-ACGGT-5ʹ, which is used as a template for mRNA synthesis. The mRNA is synthesized with the following complementary sequence to the template DNA strand: 5ʹ-ACGGU-3ʹ. The base Uracil (U) replaces the Thymine (T) base in RNA, and that's why the mRNA sequence is 5ʹ-ACGGU-3ʹ instead of 5ʹ-ACGGT-3ʹ.

The synthesized mRNA strand is processed further before it moves to the cytoplasm for translation. In processing, a cap structure is added at the 5ʹ end, and a poly(A) tail is added at the 3ʹ end. These modifications protect the mRNA from degradation and help in mRNA stability.

Hence, the transcription product is 5ʹ-ACGGU-3ʹ.

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The mass of CuSO₄.5H₂O that is required to prepare 100 mL of a 0.500 mol/L aqueous solution is 84.3045g.

We know that  0.5-mol/L solution of copper(II) sulfate contains 0.5000 moles of copper(II) sulfate, the solute, for every  

1 L= 10³ml of the solution.

This means that the  sample of copper sulfate must contain,

      = (100ml)x0.5 moles of CuSO₄/10³ml

      =   0.05 moles of CuSO₄.

It should be noted that every mole of copper(II) sulfate pentahydrate contains 1 mole of anhydrous copper(II) sulfate, CuSO4, and 5 moles of water of hydration, H₂O.

This means that in order to deliver 0.05000 moles of anhydrous copper(II) sulfate to the solution, we must deliver 0.05000 moles of copper(II) sulfate pentahydrate.

In addition to the 0.05000 moles of anhydrous copper(II) sulfate, this sample will contain,

= 0.5 moles of CuSO₄.5H₂Ox 5 moles of H2O/1mole of CuSO₄.5H₂O.

= 0.25 moles of H₂O.

Therefore, the total mass of the copper(II) sulfate pentahydrate will be equal to the mass of  

0.5 moles of anhydrous copper(II) sulfate and a mass of  0.25moles of water of hydration.

Then, the total mass of the copper(II) sulfate pentahydrate will be equal to the mass of  

0.5000 moles of anhydrous copper(II) sulfate and the mass of  0.25 moles of water of hydration which is given by,

Mass of CuSO₄ = 0.5x159.609=79.8045g

Mass of 5 moles of H₂O =0.25x18.015 = 4.5 g.

Therefore, the total mass of the copper(II) sulfate pentahydrate that will deliver  

0.5 moles of anhydrous copper(II) sulfate to your solution will be,

79.8045+4.5 = 84.3045g

Therefore, the mass of copper(II) sulfate pentahydrate required to make 100 mL of a 0.500 mol/L aqueous solution is 84.3045g

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Answer:

its 25

Explanation:

Answer:

your answer should be c i had this qs before

Explanation:

Answer: ending results

Explanation:

You spent approximately 7.9 entire days of your life playing games on your phone in a year.

To calculate the number of entire days spent playing games, we need to convert the total number of minutes into days.

First, we multiply 31 minutes by 365 days to get the total number of minutes spent playing games in a year:

31 minutes/day × 365 days = 11,315 minutes

Next, we divide the total number of minutes by the number of minutes in a day:

11,315 minutes ÷ 60 minutes/hour ÷ 24 hours/day = 7.85 days

Rounded to the nearest tenth, you spent approximately 7.9 entire days of your life playing games on your phone in a year.

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Answer:

The nucleus contains protons, which have a positive charge

Explanation:

Answer:

- Water from beaker will move to the tube

Explanation:

Total percentage of water in the beaker;

\( = { \tt{100\% - 5\%}} \\ = { \tt{95\%}}\)

Total percentage of water in dialysis tube;

\({ \tt{ = 100\% - 15\%}} \\ = { \tt{85\%}}\)

So, there is much water concentration in the beaker than the dialysis tubing, this causes a determined percentage of water to diffuse to the tubing, and determined percentage of salt to move from tubing to the beaker.

Percentage of water moving to tubing;

\({ \tt{ = 95\% - 85\%}} \\ = { \tt{10\%}}\)

Percentage of salt moving from tubing to beaker

\({ \tt{ = 15\% - 5\%}} \\ { \tt{ = 10\%}}\)

The amount of electrical work (per mole) obtained from burning liquid methanol is 666.0 kJ/mol.

What is electrical work?

Electric charges flow across a potential difference or voltage during electrical work, labor carried out by or on an electrical system.

a) The balanced chemical equation for the reaction is:

2CH₃OH(l) + 3O₂(g) → 2CO₂(g) + 4H₂O(l)

b) The maximum amount of electrical work that may be produced by burning one mole of liquid methanol can be estimated as the reaction's negative Gibbs free energy change, which is given by:

ΔG = ΔH - TΔS

ΔH = enthalpy change of the reaction,

ΔS =entropy change of the reaction,

T = temperature in Kelvin.

The standard formation enthalpies of the reactants and products can be used to calculate the reaction's enthalpy change:ΔH°f(CH3OH,l) = -239.1 kJ/mol

ΔH°f(\(CO_{2}\),g) = -393.5 kJ/mol

ΔH°f(\(H_{2}O\),l) = -285.8 kJ/mol

The enthalpy change of the reaction is, therefore:

ΔH = [ΔH°f(\(CO_{2}\),g) + 2ΔH°f(\(H_{2} O\),l)] - [ΔH°f(\(CH_{3}OH\),l) + 1.5ΔH°f(\(O_{2}\),g)]

ΔH = [-393.5 kJ/mol + 2(-285.8 kJ/mol)] - [-239.1 kJ/mol + 1.5(0 kJ/mol)]

ΔH = -726.3 kJ/mol

The standard entropies of the reactants and products can be used to determine the reaction's entropy change:

ΔS°f(\(CH_{3}OH\),l) = 126.8 J/mol·K

ΔS°f(\(CO_{2}\),g) = 213.6 J/mol·K

ΔS°f(\(H_{2}O\),l) = 69.9 J/mol·K

ΔS°f(\(O_{2}\),g) = 205.0 J/mol·K

The entropy change of the reaction is, therefore:

ΔS = [ΔS°f(\(CO_{2}\),g) + 2ΔS°f(\(H_{2}O\),l)] - [ΔS°f(\(CH_{3}OH\),l) + 1.5ΔS°f(\(O_{2\\\),g)]

ΔS = [213.6 J/mol·K + 2(69.9 J/mol·K)] - [126.8 J/mol·K + 1.5(205.0 J/mol·K)]

ΔS = -201.7 J/mol·K

Assuming T1 = 298 K, the maximum amount of electrical work that can be obtained from burning one mole of liquid methanol is:

ΔG = ΔH - T1ΔS

ΔG = -726.3 kJ/mol - 298 K(-201.7 J/mol·K)

ΔG = -726.3 kJ/mol + 60.3 kJ/mol

ΔG = -666.0 kJ/mol

Therefore, at 298 K and 1 bar, one mole of liquid methanol can burn for a maximum of 666.0 kJ/mol of electrical work.

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The balanced chemical equation for the reaction of liquid methanol and gaseous oxygen is \(2 \mathrm{CH_3OH} (\ell) + 3 \mathrm{O_2} (\mathrm{g}) \rightarrow 2 \mathrm{CO_2} (\mathrm{g}) + 4 \mathrm{H_2O} (\ell)\). The reaction releases a large amount of energy, but cannot occur spontaneously and requires an input of energy.

a) The balanced chemical equation for the reaction of liquid methanol and gaseous oxygen is:

\(2 \mathrm{CH_3OH} (\ell) + 3 \mathrm{O_2} (\mathrm{g}) \rightarrow 2 \mathrm{CO_2} (\mathrm{g}) + 4 \mathrm{H_2O} (\ell)\)

b) To calculate the amount of electrical work that can be obtained from burning liquid methanol, we need to determine the change in Gibbs free energy (ΔG) of the reaction. This can be calculated using the standard Gibbs free energy change (ΔG°) and the reaction quotient (Q):

ΔG = ΔG° + RTln(Q)

where R is the gas constant, T is the temperature in Kelvin, and ln(Q) is the natural logarithm of the reaction quotient.

Assuming standard conditions (298 K and 1 bar), we can use tabulated values of standard Gibbs free energy of formation (ΔG°f) to calculate ΔG° for the reaction:

\($\Delta G^\circ = \sum n \Delta G^\circ_\mathrm{f}(products) - \sum m \Delta G^\circ_\mathrm{f}(reactants)$\)

\($\Delta G^\circ = [2\Delta G^\circ_\mathrm{f}(CO_2) + 4\Delta G^\circ_\mathrm{f}(H_2O)] - [2\Delta G^\circ_\mathrm{f}(CH_3OH) + 3\Delta G^\circ_\mathrm{f}(O_2)]$\)

\($\Delta G^\circ = [-394.4\ \mathrm{kJ/mol} + 4(-285.8\ \mathrm{kJ/mol})] - [-238.8\ \mathrm{kJ/mol} + 3(0\ \mathrm{kJ/mol})]$\)

\($\Delta G^\circ = -726.4\ \mathrm{kJ/mol}$\)

The reaction quotient Q can be calculated from the initial and final concentrations of the reactants and products. Since we are assuming complete combustion, the initial concentration of methanol is equal to the amount of methanol we are burning, which is 1 mole. The final concentrations of the products can be calculated using the stoichiometry of the balanced equation. At equilibrium, Q = Kc, where Kc is the equilibrium constant for the reaction. For complete combustion, the value of Kc is very large, as the reaction goes essentially to completion. Thus, we can consider that Q ≈ ∞and the natural logarithm of Q is then infinity:

ln(Q) ≈ ln(∞) = ∞

Substituting the values into the equation for ΔG, we get:

ΔG = ΔG° + RTln(Q)

ΔG = -726.4 kJ/mol + (8.314 J/mol*K) * (298 K) * ln(∞)

ΔG ≈ -∞

The negative value of ΔG indicates that the reaction is exergonic, meaning it releases energy. However, the value of ΔG is so large that the reaction cannot occur spontaneously. In other words, the reaction requires an input of energy to occur, which means that it cannot be used to obtain electrical work. The balanced chemical equation for the reaction of liquid methanol and gaseous oxygen is \(2 \mathrm{CH_3OH} (\ell) + 3 \mathrm{O_2} (\mathrm{g}) \rightarrow 2 \mathrm{CO_2} (\mathrm{g}) + 4 \mathrm{H_2O} (\ell)\).

To obtain electrical work from the combustion of liquid methanol, we need to use a fuel cell or a combustion engine, which can harness the energy released by the reaction to generate electricity. The amount of electrical work that can be obtained will depend on the efficiency of the device used and may be less than the total amount of energy released by the reaction.

The balanced chemical equation for the reaction of liquid methanol and gaseous oxygen is \(2 \mathrm{CH_3OH} (\ell) + 3 \mathrm{O_2} (\mathrm{g}) \rightarrow 2 \mathrm{CO_2} (\mathrm{g}) + 4 \mathrm{H_2O} (\ell)\). The reaction releases a large amount of energy, but cannot occur spontaneously and requires an input of energy.

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Answer:

The elements are arranged in seven horizontal rows, called periods or series, and 18 vertical columns, called groups.

Explanation:

In chemistry, a group (also known as a family) is a column of elements in the periodic table of the chemical elements. ... Groups may also be identified using their topmost element, or have a specific name. For example, group 16 is also described as the "oxygen group" and as the "chalcogens".

(hope this helps ^^)

Answer:

The dog ate the bone hiding under the shady tree.

Explanation:

The best observation is that the dog ate the bone hiding under the shady tree. This is because it provides the most graphic details about the position and activities of the dog.

Answer:

The dog ate the bone hiding under the shady tree.

Explanation:

It has the most detail :)

The resolution between Peak A and Peak B is approximately 55.71.

First, we need to calculate the peak width at half height (W1/2) for Peak A. The formula to do this is:
W1/2 = 2.35482 * sigma
Before we use the formula, we need to convert sigma from seconds to minutes by dividing it by 60:
sigma (in minutes) = 1.50 sec / 60 = 0.025 min
Now we can calculate W1/2 for Peak A:
W1/2 = 2.35482 * 0.025 min ≈ 0.0587 min
Next, we'll calculate the resolution between Peak A and Peak B. The formula for resolution is:
Resolution = (trB - trA) / ((W1/2A + W1/2B) / 2)
We have all the values needed:
trA = 2.75 min
trB = 3.15 min
W1/2A = 0.0587 min
W1/2B = 0.0988 min
Now we can calculate the resolution:
Resolution = (3.15 - 2.75) / ((0.0587 + 0.0988) / 2) ≈ 4.385 / 0.07875 ≈ 55.71

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Explanation:

In chemistry, thermodynamics, and many other related fields, phase transitions (or phase changes) are the physical processes of transition between the basic states of matter: solid, liquid, and gas, as well as plasma in rare cases.

Answer:

In chemistry, thermodynamics, and many other related fields, phase transitions are the physical processes of transition between the basic states of matter: solid, liquid, and gas, as well as plasma in rare cases. A phase of a thermodynamic system and the states of matter have uniform physical properties.

Explanation:

When omitting the sodium thiosulfate solution from the kinetic trials, the resultant solution from mixing solutions A and B will appear differently than a correctly completed experiment.

Without the sodium thiosulfate, a reaction between the two solutions would not occur, so the resultant solution would be that of an unmixed combination of A and B, rather than a reaction product.

This can be confirmed by running the experiment correctly and including the sodium thiosulfate solution in the kinetic trials.

Omitting the sodium thiosulfate solution can significantly affect the appearance of the resulting solution from a kinetic experiment by not neutralizing the excess iodine and leaving unreacted iodine present in the solution.

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Answer:

B

Explanation:

Due to the fact that by us knowing that H2O is water, it doesn't tell us that we can drink it.

does that make sense to you, if not, I can give you another example.

Answer:

I catalyst promoter is the answer

Answer:

The answer is " salt".

Explanation:

Hey there!

When any acids and base react with eachother, they forms water and respective salts.

For example:

HCl + NAOH = NACl + H2O.

Hope it helps!