Calcium carbonate is a white mineral. A chemist burns calcium carbonate, CaCO3, to produce carbon dioxide, CO2, and a white powder, CaO. The following chemical equation shows the reaction.

CaCO3 ---------> CO2 + CaO


A. Compare the properties of the products and reactants in this reaction.





B. Use numbers of atoms to describe the amounts of calcium, carbon, and oxygen before and after the reaction.

The half-life of Po-210 is 140 days. If the initial mass of the sample is 5 kg, 3.5g will remain after 280 days.

Chemical kinetics is a subfield of physical chemistry that studies the speeds of chemical processes. The rate of the reaction may be used to classify it as quick, moderate, or sluggish. Reaction mechanism also enables us to study the effects of temperature and catalyst on reaction rate and rate constant. It informs us about reaction processes and enables us to apply particular rate constants to certain mechanistic stages.

The rate law for first order kinetics is

K=(2.303/T)×log(a/a-x)

half life=0.693/K

Where

k - rate constant

t - time passed by the sample

a - initial amount of the reactant

a-x - amount left after the decay process

K=0.693/half life

K=0.693/140

=0.086

0.086=(2.303/ 280)×log( 5 /a-x)

0.086=0.07×log( 136/a-x)

1.22=log( 136/a-x)

136/a-x=16.5

a-x=3.5g

Therefore, 3.5g will be left after 280 days.

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The density (in g/cm³) of a cube of metal that is 2 inches on a side and weighs 444.5 grams is 3.4 g/cm³ (1st option)

First, we shall obtain the volume of the metal. Details below:

Volume = L³

Volume = 5.08³

Volume = 131.1 cm³

Finally, we shall obtain the density of the metal. Details below:

Density = mass / volume

Density of metal = 444.5 / 131.1

Density of metal = 3.4 g/cm³

Thus, we can conclude from the above calculation that the density of the metal is 3.4 g/cm³ (1st option)

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Complete question:

What is the density (in g/cm³) of a cube of metal that is 2 inches on a side and weighs 444.5 grams?

3.4 g/cm³

8.89 g/cm³

55.56 g/cm³

0.180 g/cm³

Answer:

In the given question, the mass of empty slender is given 25 points 489 Grand. The mass of Slender plus unknown liquid is given 57 points 847 g. The volume of a non liquid is given 45 three ml. We have to find the density of a non liquid. Firstly we will find the mass of unknown liquid. As the mass of unknown liquid is equal to the mass of cylinder plus unknown liquid minus the mask of empty cylinders. So the mass of a non liquid is equal to seven points 847 g -25 points 489 g. The mass of a non liquid will be 32 points 358 g. The formula to calculate the density of a non liquid is equal to the mass of a non liquid divided by the volume of a non liquid. So we will put the values as the mass of a non liquid is 32.358 g, Divided by the volume, which is given 45.3 ML. When we solve this Comes out to be 0.71 g, but I am in. So the Final answer is the density of a non liquid is equal to 0.71 g.

Answer: Br-CH₂-CH₂-C≡N (3-bromopropanenitrile)

Explanation:

The question tells us to " Deduce the identity of the following compound from the spectral data given. C3H4BrN: H NMR, δ 2.98 (2H, triplet), 3.53 (2H, triplet) 13C NMR, δ 21.05 (triplet), 23.87 (triplet), 118.08 (singlet) (ppm):JR, 2963, 2254 cm" Express your answer as a chemical formula".

Answer: Another Alternative to this is seen below

The Double Bond Equivalent of C₃H₄BrN = 3+1-4/2-1/2+1/2 = 2

2254 cm-1 Vc ≡N [IR analysis]

2963.4 = sp³Vc-H streek [IR analysis]

where the first CH₂ = b = 2.98 (2H,triplet) and

the second CH₂ = a = 3.53 (2H,triplet)

Note:  where both are 1HNMR.

where C = c = 118.08 (singlet)

CH₂ = b = 21.05 (triplet)

CH₂ = a = 23.87 ( triplet)

Note: where all are 13CNMR

Important:

I have attached a copy of the solution to enhance better understanding in case the typed solution isn't clear enough.

Answer: sh have on other countries?

A. Exported the depression to Europe

B. Boosted the economies of European countries

C. Had very little effect on other countries

D. Let other countries operate independently

Explanation:

The pressure of oxygen is 1 Ka

Partial pressure is the pressure that a gas would exert if it occupied the same volume as a mixture of gases, but alone. In other words, it is the pressure that a gas contributes to the total pressure of a mixture of gases.

The partial pressure of a gas can be calculated using the following equation:

Partial pressure = Total pressure x mole fraction

where the mole fraction is the fraction of the total number of moles of gas that is made up by the particular gas of interest.

Let total pressure = PA + PB + PC

Then the pressure of the oxygen = 74 - (54 + 19)

= 1 Ka

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Answer:

The element X is sulfur.

Sulfur will gain 2 electrons to become an ion.

The charge of sulfide ion is (2-).

Explanation:

Intermolecular force is the force of attraction that holds the particles in the atom together. The force referred to in the question is the force that binds the various elements together when they come together.

The intermolecular forces presented in the answer options in order of strength to weakness are ion-dipole hydrogen bonds dipole-dipole and van der Waals forces. The dipole-dipole interaction is the strongest intermolecular attraction. These are the weakest intermolecular forces and exist between all types of molecules, whether ionic or covalent, polar or non-polar.

Solids usually have the strongest intermolecular forces compared to liquids and gases. In solids, they are incompressible and dense because the particles are close together. The weakest intermolecular force is the London dispersion force. London Dispersion Force The London dispersion force is also known as the induced dipole induced dipole because it is a temporary attractive force that generates a temporary dipole. London dispersion exists in nonpolar monatomic gases.

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Answer:

nonpolar substance < polar substance < ionic substance

Explanation:

Answer key

Answer:

The answer is C.

Explanation:

Hello there!

In this case, since the ionization of HCl to H+ and Cl- ions decrease the pH of a solution as it gets more acidic due to the H+ ions; it is possible to infer that the presence of Cl- ions in the solution does not modify the pH of the solution because it is not able to react with water to form HCl and then undergo the aforementioned reaction because HCl is a strong acid so the ions are not able to undergo the reverse ionization.

In such a way, the answer will be C.

Regards!

A. The maximum theoretical yield of the gaseous product in grams is 0.037 g

B. The grams of the excess reagent are left over is 0.97 g

C. The pH of the HBr solution is 1.37

D. The OH¯ concentration of the HBr solution is 2.33×10¯¹³ M

E. The volume (in mL) of the gaseous product is 323 mL

F. The new temperature of the gas is 61 °C

We'll begin by calculating the mole of HBr in the solution. This is illustrated below:

Molarity = mole / Volume

Mole = molarity × volume

Mole of HBr = 0.043 × 0.8506

Mole of HBr = 0.0366 mole

Thus, the mass of HBr can be obtained as follow:

Mass = mole × molar mass

Mass of HBr = 0.0366 × 81

Mass of HBr = 2.96 g

Balanced equation

Ca + 2HBr --> CaBr₂ + H₂

Molar mass of Ca = 40 g/mol

Mass of Ca from the balanced equation = 1 × 40 = 40 g

Molar mass of HBr = 81 g/mol

Mass of HBr from the balanced equation = 2 × 81 = 162 g

Molar mass of H₂ = 2 g/mol

Mass of H₂ from the balanced equation = 1 × 2 = 2 g

SUMMARY

From the balanced equation above,

40 g of Ca reacted with 162 g of HBr to produce 2 g of H₂

Next, we shall determine the limiting reactant.

From the balanced equation above,

40 g of Ca reacted with 162 g of HBr.

Therefore,

1.7 g of Ca will react with = (1.7 × 162) / 40 = 6.885 g of HBr.

Since a higher amount of HBr is needed, therefore HBr is the limiting reactant and Ca is the excess reactant

Finally, we shall determine the maximum theoretical yield of the gaseous product. details below

From the balanced equation above,

162 g of HBr reacted to produce 2 g of H₂.

Therefore,

2.96 g of HBr will react to produce = (2.96 × 2) / 162 = 0.037 g of H₂

Thus, The maximum theoretical yield of the gaseous product obtained is 0.037 g

Ca is the excess reactant

From the balanced equation above,

162 g of HBr reacted with 40 g of Ca.

Therefore,

2.96 g of HBr will react with = (2.96 × 40) / 162 = 0.73 g

Thus, the mass of the excess reactant leftover can be obtained as illustrated below:

Mass of excess reactant leftover = 1.7 - 0.73

Mass of excess reactant leftover = 0.97 g

pH = –Log H⁺

pH = –Log 0.043

pH = 1.37

[H⁺] × [OH¯] = 10¯¹⁴

0.043 × [OH¯] = 10¯¹⁴

Divide both side by 0.043

[OH¯] = 10¯¹⁴ / 0.043

[OH¯] = 2.33×10¯¹³ M

Using the ideal gas equation, the volume of the gas can be obtained as follow:

PV = nRT

Divide both side by P

V = nRT / P

V = (0.0185 × 0.0821 × 362) / 1.7

V = 0.323 L

Multiply by 1000 to express in mL

V = 0.323 × 1000

V = 323 mL

The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

(1.7 × 0.323) / 362 = (0.329 × 1.54) / T₂

Cross multiply

1.7 × 0.323 × T₂ = 362 × 0.329 × 1.54

Divide both side by 1.7 × 0.323

T₂ = (362 × 0.329 × 1.54) / (1.7 × 0.323 )

T₂ = 334 K

Subtract 273 to obtain answer in °C

T₂ = 334 – 273 K

T₂ = 61 °C

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Answer:

t5gbt 4 tbg3rvb tjj5tb4b4bv

Explanation:fhtb v4bvtvhbvv bh

Answer:

In He2 molecule,

Atomic orbitals available for making Molecular Orbitals are 1s from each Helium. And total number of electrons available are 4.

Molecular Orbitals thus formed are:€1s2€*1s2

It means 2 electrons are in bonding molecular orbitals and 2 are in antibonding molecular orbitals .

Bond Order =Electrons in bonding molecular orbitals - electrons in antibonding molecular orbitals /2

Bond Order =Nb-Na/2

Bond Order =2-2/2=0

Since the bond order is zero so that He2 molecule does not exist.

Explanation:

Answer:

H-C = C-H NaNH2 \(\ \to \0}\) H-C = CNa

H-C = C - CH2 CH2 CH2 CH3

Explanation:

NaNH2 acts as base in this reaction. The organic products released after the reaction of carbon hydrogen atom with sodium amide. These products released after the chemical reaction when carbon and hydrogen atom reacts and NaNH2 acts as base then substitution nucleophilic reaction takes place.

The temperature increase from 20 °C to 46 °C indicates that the reaction between zinc and copper sulfate solution is exothermic, with heat being released into the surroundings.

In the given reaction between zinc and copper sulfate solution, the temperature change can provide insights into the type of heat change occurring during the reaction. Based on the provided information, the initial temperature of the copper sulfate solution was 20 °C, and the final temperature of the mixture after the reaction was 46 °C.

The temperature increase observed in this reaction indicates an exothermic heat change. An exothermic reaction releases heat energy into the surroundings, resulting in a temperature rise. In this case, the reaction between zinc and copper sulfate solution is exothermic because the final temperature is higher than the initial temperature.

During the reaction, zinc displaces copper from copper sulfate to form zinc sulfate and copper metal. This displacement reaction is known as a single displacement or redox reaction. Zinc is more reactive than copper and therefore replaces copper in the compound.

The formation of new chemical bonds during the reaction releases energy in the form of heat. This energy is transferred to the surroundings, leading to an increase in temperature. The heat released is greater than the heat absorbed, resulting in a net increase in temperature.

The exothermic nature of this reaction can be explained by the difference in bond energies between the reactants and products. The breaking of bonds in the reactants requires energy input, while the formation of new bonds in the products releases energy.

In this case, the energy released during the formation of zinc sulfate and copper metal is greater than the energy required to break the bonds in copper sulfate and zinc.

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Answer:

Technology

hope this helps

If during a spectroscopy experiment a student notes a wavelength peak measurement at 280 nm, then the region of the electromagnetic spectrum observed is the UV region.

The electromagnetic spectrum refers to all types of wavelengths that radiation can emit as light, which involves both visible light and also ultraviolet (UV) radiation.

In conclusion, if during a spectroscopy experiment a student notes a wavelength peak measurement at 280 nm, the region of the electromagnetic spectrum observed is the UV region.

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Enthalpy change (H) and entropy change (S) are 11.7 103 Jmol-1 and 105 Jmol-1K-1, respectively, for a reaction at 25 °C.

The absolute entropies of a reactants and their products are S°(N2H4) (= half of this period J/(mol•K), S°(N2) = 191.6 J/(mol•K), or S°(H2) = 130.7 J/(mol•K) at 25°C, where the standard enthalpy change (H°) is 50.6 kJ/mol.

E0 is known as 0.268 V at standard potential at 25°C, despite a slight variation in the computed value above. Similar to a silver-silver chloride electrode, the electrode potential is dependent on the chloride ion concentration.

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There are 2.64 × 1022 molecules of sucrose present in this serving of fruit dessert containing 15.0 g of sugar.

To determine the number of molecules of sugar present in the serving, we need to calculate the number of moles of sugar and then convert it to the number of molecules.

Given:

Mass of sugar (sucrose) = 15.0 g

Molar mass of sucrose (C12H22O11) = 342 g/mol

First, calculate the number of moles of sugar using the formula:

Number of moles = Mass of substance / Molar mass

Number of moles of sugar = 15.0 g / 342 g/mol ≈ 0.0439 mol

Next, we use Avogadro's number, which states that there are approximately 6.022 × 10^23 molecules in one mole of a substance. Therefore, to find the number of molecules of sugar:

Number of molecules = Number of moles × Avogadro's number

Number of molecules of sugar = 0.0439 mol × 6.022 × 10^23 molecules/mol ≈ 2.64 × 10^22 molecules

Therefore, there are approximately 2.64 × 10^22 molecules of sugar present in this serving.

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Answer:

optical engineer

Explanation:

Answer:optical engineer

Explanation: HOPE IT HELPS YOU .PLEASE GIVE BRAINLIEST THANKS . .

Answer:

The rms speed of its molecules becomes. (T) has become four times. Therefore, v_(rms) will become two times,...

Answer:

Increases

Explanation:

The gravitational potential energy of an object increases as you bring it higher with respect to the ground.

Gravitational potential energy depends on the mass, height and gravity between two bodies;

   Gravitational potential energy  = mgh

m is the mass

g is the height

h is the height

Step 1: Let's calculate the quantity in moles of anhydrous barium chloride using the resulted mass after the heating divided by its molar mass (molar mass of BaCl2 is 208.23 g/mol)

so:

8.57/208.23 = 0.04 moles of BaCl2

Step 2: Now let's calculate the quantity in moles of water. But first, we need to calculate the mass of H2O. For this, we just subtract the mass before the heating by the mass after the heating. The water evaporated because of the heat.

mass of H2O = 10.05 - 8.57 = 1.48 g

Now we divide the mass by its molar mass to find the quantity in moles (molar mass of water is 18 g/mol)

1.48/18 = 0.082 moles of H2O

Step 3: Now we determine the number ratio:

0.082/0.04 = 2

So the formula is:

Answer: a. BaCl2 x 2H2O

b. barium chloride dihydrate

A) Calculate the lower and upper bounds of the 95% confidence interval:

Lower bound = X - ME

Upper bound = X + ME

B) you would compare the obtained mean concentration (0.101675 N) with the prepared concentration (0.1012 N) and calculate the t-value. The t-value is then compared to the critical t-value at a certain significance level (e.g., a = 0.05) and the degrees of freedom (n-1) to determine if there is a statistically significant difference.

(a) To determine the range within which you can be 95% confident that the true value falls, you can calculate the confidence interval using the obtained results.

First, calculate the mean (X) of the measured concentrations:

X = (0.1017 + 0.1019 + 0.1016 + 0.1015) / 4 = 0.101675 N

Next, calculate the standard deviation (s) of the measured concentrations:

s = sqrt(((0.1017 - X)² + (0.1019 - X)² + (0.1016 - X)² + (0.1015 - X)²) / (4 - 1))

Then, calculate the standard error of the mean (SE) using the formula:

SE = s / sqrt(n)

where n is the number of measurements (in this case, n = 4).

With the standard error, you can calculate the margin of error (ME) for a 95% confidence interval using the t-distribution. The t-value for a 95% confidence interval with 3 degrees of freedom is approximately 3.182.

ME = t * SE

Finally, calculate the lower and upper bounds of the 95% confidence interval:

Lower bound = X - ME

Upper bound = X + ME

(b) To determine if there is a statistical difference between the obtained mean concentration (0.101675 N) and the prepared concentration (0.1012 N), you can perform a t-test. The t-test compares the means of two sets of data to determine if they are significantly different from each other.

Using the formula for a two-sample t-test, you would compare the obtained mean concentration (0.101675 N) with the prepared concentration (0.1012 N) and calculate the t-value. The t-value is then compared to the critical t-value at a certain significance level (e.g., α = 0.05) and the degrees of freedom (n-1) to determine if there is a statistically significant difference.

If the calculated t-value is greater than the critical t-value, it suggests a statistically significant difference between the obtained mean concentration and the prepared concentration.

Please note that the actual calculations and interpretation may vary depending on the statistical software or method used, and it's always recommended to consult a statistician or refer to appropriate statistical references for accurate analysis.

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Answer:

down below

Explanation:

The police's influence can happen based on a response to a problem. An example is when the police are called because of a thief child. If the police handles the situation correctly-using reasonable force, if necessary, and reading them their rights- the public will perceive the police in a good light or way. If the police use gross misconduct and do not go by the book, then they will be perceived as an enemy or in a bad light or way.

Answer:

distillation

Explanation:

dont have one

Answer: distillation

Please. Mark as brainliest

Answer:

1.104 J/g°C

Explanation:

Using Q = m × c × ∆T

Where;

m = mass of substance (g)

c = specific hear capacity (J/g°C)

∆T = change in temperature (°C)

For a colorimeter,

Q(water) = - Q(metal)

m. c. ∆T (water) = - m. c. ∆T (metal)

According to the information provided;

For water:

m = 28.0g

c = 4.184 J/g°C

∆T = (21.23 - 19.73°C)

For the metal:

m = 2.05g

c = ?

∆T = (21.23 - 98.88°C)

m. c. ∆T (water) = - m. c. ∆T (metal)

[28 × 4.184 × (21.23 - 19.73°C)] = -[2.05 × c × (21.23 - 98.88°C)]

[117.152 × 1.5] = -[2.05 × c × (-77.65)]

175.728 = -[-159.1825c]

175.728 = 159.1825c

c = 175.728 ÷ 159.1825

c = 1.104

c = 1.104 J/g°C

A 70 piece of metal at 120 C is dropped into a kilometer with 150 g of 30C water the final temperature of the water and little changes 35c,  0.385 J/g°c is the specific heat of the metal​.

The amount of heat needed to raise a substance's temperature by one degree Celsius in one gramme, also known as specific heat. Typically, calories and joules per gramme per degree Celsius are used as a measure of specific heat.

In the 18th century, the Scottish researcher Joseph Black found that equivalent masses of various substances required varying quantities of heat to bring them across the same temperature range. Based on this finding.

cm = (0.15 kg x 4.18 J/gCx (35C - 30C)) / (70 pieces x 0.1 kg/piece x (120C - 35C))

cm = 0.385 J/g°c

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a. The Mass of water driven off = 0.15 g

b. Moles of anhydrate = 0.00257 moles

c. Moles of water driven off is 0.00833 moles

d. There are 3 moles of water within the crystalline structure of one molecule of the hydrated salt.

e. The molecular formula of the hydrated salt will be X.3H₂O

a. The mass of water driven off from the hydrated salt is:

Mass of water driven off = 0.5 g - 0.35 g

Mass of water driven off = 0.15 g

b. Molecular mass of salt = 136 g/mol

moles of anhydrate = 0.35/136

Moles of anhydrate = 0.00257 moles

c. Moles of water driven off = mass/molar mass

molar mass of water = 18 g/mol

Moles of water driven off = 0.15/18

Moles of water driven off = 0.00833 moles

d. Moles of water within the crystalline structure of one molecule of the hydrated salt is determined by converting to whole number mole ratio by dividing with the smallest ratio,

Salt to water ratio = 0.00257 /0.00257  :  0.00833/0.00257

Salt to water ratio = 1 : 3

Therefore, there are 3 moles of water within the crystalline structure of one molecule of the hydrated salt.

e. Assuming the anhydrous salt is X, the molecular formula of the hydrated salt will be X.3H₂O

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Answer:

90.08784 grams

Explanation:

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