Reactions can occur because of a precipitation reaction
Further explanationDouble-Replacement reactions, happens if there is an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product
To predict whether this reaction can occur or not is one of them, the precipitation reaction. A precipitation reaction occurs if two ionic compounds which are dissolved reacted to produce one of the products of the ion compound does not dissolve. Formation of these precipitating compounds that cause reactions can occur
Chloride solution reacts with Sodium carbonate solution
CaCl₂(aq)+Na₂CO₃(aq)⇒CaCO₃(s)+NaCl(aq)
Because Calcium carbonate, CaCO₃ an insoluble solid , it will precipitates so that a reaction can occur
A known reaction has Change in U= 38 kJ/mol. The reaction is done at constant pressure and you measure the amount
of work done to be w=+2 kJ/mol. What is q in kJ/mol?
q = 36kJ/ mol amount of heat is produced according to 1st law of Thermodynamics
What is 1st law of Thermodynamics ?
The first law of thermodynamics states that energy is neither created nor destroyed, only its form can be changed. In any system, energy transfer involves exceeding control limits by mass, external work, or heat transfer beyond limits. These cause changes in the stored energy within the control volume.
The first law of thermodynamics states that heat is a form of energy and therefore thermodynamic processes obey the law of conservation of energy. This means that it cannot generate or destroy thermal energy.
ΔU = q + w
38kJ/ mol = q + 2kJ/mol = 36kJ/mol
q = 36kJ/ mol amount of heat is produced according to 1st law of Thermodynamics
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Draw,label,and describe the four major types of galaxies
The four main types of galaxies are spiral, elliptical, irregular, and lenticular :)
ZSM-5, a catalyst material, has a surface area of 581 m²/g. What is the surface
area of this material in cm²/mg?
ZSM-5 is a catalyst material, which has a surface area of 581 m²/g. This is equivalent to a surface area of 5810 cm²/mg.
What is a catalyst?A catalyst is a substance that increases the rate of a chemical reaction without itself undergoing any permanent chemical change. Catalysts have large surface areas to increase the reaction rate.
Biological catalysts are known as enzymes.
ZSM-5 is a catalyst material, which has a surface area of 581 m²/g. We want to convert this value to cm²/mg.
Step 1: Convert 581 m²/g to cm²/g.We will use the conversion factor 1 m = 100 cm.
581 m²/g × (100 cm/1 m)² = 5.81 × 10⁶ cm²/g
Step 2: Convert 5.81 × 10⁶ cm²/g to cm²/mg.We will use the conversion factor 1 g = 1000 mg.
5.81 × 10⁶ cm²/g × (1 g/1000 mg) = 5810 cm²/mg
ZSM-5 is a catalyst material, which has a surface area of 581 m²/g. This is equivalent to a surface area of 5810 cm²/mg.
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I have the smallest atomic number of all the
elements that have electrons in three different
energy levels. Who am I?
The element with the smallest atomic number is hydrogen
What is atomic number?
A chemical element's atomic number is its position in the periodic system, which places the elements in ascending order of the number of protons in their nuclei. As a result, the atomic number is also determined by the number of protons, which is always equal to the number of electrons in a neutral atom.
The charge number of an atomic nucleus is the chemical element's atomic number, also known as nuclear charge number. This is the number of protons present in the nucleus of each atom of that element, or the proton number, for conventional nuclei. The atomic number of common chemical elements can be used to uniquely identify certain elements.
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If molarity of 100 ml glucose is 1.5 then the no of carbon atoms in the solution are
Answer:
Molarity =[ number of moles* (1000mL/L)] / volume in mL
Explanation:
Given: Molarity =1.5M, volume = 100mL
1.5 =[ (no. of moles) * (1000mL/L) / 100mL
no of moles = (1.5* 100) / 1000
no of moles = 0.15
We know that, 1 mole = 6.023 *10²³ atoms
Since the compound contains 0.15moles, it has
0.15 * 6.023* 110²³
9.0345*10²² atoms of carbon are present in the compound.
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What is the pressure, in atmospheres, exerted by a 0.100 mol sample of oxygen in a 2.00 L container at 273 °C? A) 4.48 x 10¹¹ atm B) 2.24 x 10⁰ atm C) 1.12 x 10³ atm D) 2.24 x 10³ atm
The pressure, in atmospheres, exerted by a 0.100 mol sample of oxygen in a 2.00 L container at 273 °C is 2.24 × 10⁰ atm.
How to calculate pressure?The pressure of a substance can be calculated using the following formula;
PV = nRT
P = pressureV = volumen = no of molesR = gas law constantT = temperatureAccording to this question, the pressure, in atmospheres, exerted by a 0.100 mol sample of oxygen in a 2.00 L container at 273 °C can be calculated as follows:
P × 2 = 0.1 × 0.0821 × 546
2P = 4.48266
P = 2.24 × 10⁰ atm
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Totsw6) 33 grams of Beryllium hydride, BeH2, are dissolved
in 6.0 Liters of solution.
M001 loi 0.
no
Answer?
The molarity of the solution obtained by dissolving 33 g of Beryllium hydride, BeH₂, in 6.0 Liters of solution is 0.5 M
What is molarity?Molarity is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
How to determine the mole of BeH₂Mass of BeH₂ = 33 gMolar mass of BeH₂ = 9 + (1×2) = 11 g/mol Mole of BeH₂ =?Mole = mass / molar mass
Mole of BeH₂ = 33 / 11
Mole of BeH₂ = 3 moles
How to determine the molarity Mole of BeH₂ = 3 moles Volume = 6 L Molarity =?Molarity = mole / Volume
Molarity = 3 / 6
Molarity = 0.5 M
Thus, the molarity of the solution is 0.5 M
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Calculate the energy of combustion for one mole of butane if burning a 0.367 g sample of butane (C4H10) has increased the temperature of a bomb calorimeter by 7.73 °C. The heat capacity of the bomb calorimeter is 2.36 kJ/ °C.
The energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.
To calculate the energy of combustion for one mole of butane (C4H10), we need to use the information provided and apply the principle of calorimetry.
First, we need to convert the mass of the butane sample from grams to moles. The molar mass of butane (C4H10) can be calculated as follows:
C: 12.01 g/mol
H: 1.01 g/mol
Molar mass of C4H10 = (12.01 * 4) + (1.01 * 10) = 58.12 g/mol
Next, we calculate the moles of butane in the sample:
moles of butane = mass of butane sample / molar mass of butane
moles of butane = 0.367 g / 58.12 g/mol ≈ 0.00631 mol
Now, we can calculate the heat released by the combustion of the butane sample using the equation:
q = C * ΔT
where q is the heat released, C is the heat capacity of the calorimeter, and ΔT is the change in temperature.
Given that the heat capacity of the bomb calorimeter is 2.36 kJ/°C and the change in temperature is 7.73 °C, we can substitute these values into the equation:
q = (2.36 kJ/°C) * 7.73 °C = 18.2078 kJ
Since the heat released by the combustion of the butane sample is equal to the heat absorbed by the calorimeter, we can equate this value to the energy of combustion for one mole of butane.
Energy of combustion for one mole of butane = q / moles of butane
Energy of combustion for one mole of butane = 18.2078 kJ / 0.00631 mol ≈ 2888.81 kJ/mol
Therefore, the energy of combustion for one mole of butane is approximately 2888.81 kJ/mol.
In conclusion, by applying the principles of calorimetry and using the given data, we have calculated the energy of combustion for one mole of butane to be approximately 2888.81 kJ/mol.
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4. Which formula represents the binary molecular compound dinitrogen tetroxide?
O N₂0
ON₂04
O NO4
O N₂02
N₂0₄ is the formula represents the binary molecular compound dinitrogen tetroxide. Therefore, option B is correct.
What is the binary molecular compound ?Binary molecular compounds are made up of exactly two nonmetal elements. HF, NO2, and P2O5 are a few examples. It is extremely simple to name binary molecular compounds. The first element is given its element name, followed by ide; the second element is given its root (hydr, bor, carb, ox, fluor, etc.).
In N₂0₄ molecule there are two nitrogen atoms at the suffix so, it is binary and in oxygen atom its suffix is 4 so, it is tetroxide. Therefore, N₂0₄ is the formula represents the binary molecular compound dinitrogen tetroxide.
Thus, option B is correct.
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Draw the structure of phosphatidylserine and discuss its components
Phosphatidylserine is a type of phospholipid that is mainly found in cell membranes. Its structure is made up of two fatty acid chains, a phosphate group, a serine molecule, and a glycerol molecule.
The fatty acid chains are hydrophobic, meaning they repel water, while the phosphate group and serine molecule are hydrophilic, meaning they attract water.
The glycerol molecule acts as a bridge that connects the two fatty acid chains to the phosphate group and serine molecule.
The structure of phosphatidylserine is important for its function in the cell membrane.
Because of the hydrophobic and hydrophilic components of its structure, phosphatidylserine is able to form a lipid bilayer, which is a barrier that separates the inside of the cell from the outside environment.
The hydrophilic heads of the phosphatidylserine molecules face outward and interact with water, while the hydrophobic tails face inward and repel water.
Phosphatidylserine also plays a role in cell signaling and apoptosis, which is programmed cell death.
It acts as a signaling molecule by binding to proteins that are involved in cellular pathways.
In addition, phosphatidylserine is translocated to the outer leaflet of the cell membrane during apoptosis, which signals to immune cells that the cell is ready to be removed.
In conclusion, the structure of phosphatidylserine is made up of two fatty acid chains, a phosphate group, a serine molecule, and a glycerol molecule. Its hydrophobic and hydrophilic components allow it to form a lipid bilayer in cell membranes, and it also plays a role in cell signaling and apoptosis.
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would the [H+] for the 1.0M HNO3 be greater than , less than, or equal to 1.0M
Answer:
Equal
Explanation:
Nitric Acid is a strong acid and therefore completely disassociates.
9. Nitric acid, HNO3, is extensively used in the manufacture of fertilizer. A bottle containing 75.0 ml of nitric acid solution is labeled 6.0 M HNO3.
a. How many moles of HNO3 are in the bottle?
b. A reaction needs 5.00g of HNO3. How many ml of solution are required?
(Molar mass of HNO3 = 63.01 g /mol)
a)There are 0.45 moles of HNO₃ in the bottle.
b)Approximately 13 ml of the solution are required for the reaction.
a. To find the number of moles of HNO₃ in the bottle, we can use the formula:
moles = concentration (M) x volume (L)
Given that the concentration of the nitric acid solution is 6.0 M and the volume is 75.0 ml, we need to convert the volume to liters:
75.0 ml = 75.0 ml x (1 L/1000 ml) = 0.075 L
Now, we can calculate the number of moles:
moles = 6.0 M x 0.075 L = 0.45 moles
So, there are 0.45 moles of HNO₃ in the bottle.
b. To determine the volume of solution required for 5.00 g of HNO3, we need to use the molar mass of HNO3 to convert grams to moles:
moles = mass (g) / molar mass (g/mol)
Given that the molar mass of HNO₃ is 63.01 g/mol and the mass required is 5.00 g, we can calculate the number of moles:
moles = 5.00 g / 63.01 g/mol ≈ 0.079 moles
Now, we can use the concentration to find the volume:
volume (L) = moles / concentration (M)
volume (L) = 0.079 moles / 6.0 M ≈ 0.013 L
Finally, we need to convert the volume to milliliters:
volume (ml) = 0.013 L x (1000 ml/1 L) ≈ 13 ml
So, approximately 13 ml of the solution are required for the reaction.
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map below represents a bridge over the meander of a stream From the bridge, a student measures the stream velocity at locations ABand C Which table represents the most probable stream velocity recordings at each location ?
The correct option is 2.
A 88
B 94
C 100
To solve this problem, we need to use our knowledge of how streams flow and how velocity changes in different parts of the stream.
Typically, streams flow fastest in the center of the channel and slowest along the edges, due to friction with the banks and bottom of the stream.
Given that it lies in the middle of the stream's two extreme velocities, option 2, which equals 94, is probably the right response. The velocity near the channel's middle is probably closer to 100 because the stream runs there the quickest.
On the other hand, it is likely that the velocity near the edges is closer to 88 since the stream runs more slowly along the edges due to friction with the banks and streambed. Consequently, a velocity of 94 is the most logical choice because it is within the range that is predicted by the velocity distribution of a stream.
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write a brief short note on translation and transcription?
Answer:
Transcription is when you make a copy of the RNA from DNA. This is how the mRNA can leave the nucleus which exists to the cytoplasm and into ribosomes where protein synthesis occurs. Translation is what happens after transcription and this is where protein synthesis occusrs in the ribosomes/endoplasmic reticulum.
Explanation:
What information does an energy diagram give?
A. It shows the transfer of potential energy to kinetic energy.
B. It shows how concentrations of reactants affect the energy.
C. It shows the rate of the reaction as a function of time.
D. It shows the energy requirements needed in order for a reaction to
occur.
The information from diagram shows the energy requirements needed in order for a reaction to
occur.
What is Collision theory?The collision theory states that each and every chemical reaction can occur between particles when the molecules collide each other.
The collision between particles is necessary but it is not sufficient for a reaction to take place. The collisions must be effective.
It is necessary to know the exact nature of an effective collision since this indicates whether particles react with each other and form new products.
According to collision theory, the reaction occur when molecules collide and molecules have sufficient activation energy to cross energy barrier.
Greater the energy, greater will be number of collision. Lesser energy, lesser will be number of collision.
Thus, the given energy diagram shows about the energy required for a reaction to take place.
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Answer: D) it shows the energy requirements needed in order for a reaction to occur.
If the pOH of a solution is 13, what is the PH of the solution?
Answer: pH= 1
Explanation: pOH + pH =14
4. Write an equilibrium equation for the following:
A. H₂ +F₂ <-----> 2HF
B. MnO₂ + 4HCI <-----> MnCl₂ + Cl₂ + H₂O
The equilibrium expressions are written for the reactions as;
a) K =[HF]^2/[H₂] [F₂]
b) [MnCl₂] [Cl₂] [H₂O]/[MnO₂] [HCI]^4
What is the equilibrium expression?Let us note that many times it is important to see the extent to which the reactant are converted into products. The value that shows us how much the reactants are converted into products is what we call the equilibrium expression.
Given this, the equilibrium has to do with the ratio of the products to that of the reactants. In this case, we can see that the equilibrium position can be written as the ratio of the amounts of the reactants to the products raised to the power of the stoichiometric coefficients of the species involved.
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If I dilute 334.75 mL of 1.28 M lithium acetate solution to a volume of 822.18 ml, what
will the concentration of this solution be?
Answer:
C₂ = 0.52 M
Explanation:
Given data:
Initial volume = 334.75 mL
Initial concentration = 1.28 M
Final volume = 822.18 mL
Final concentration = ?
Solution:
C₁V ₁ = C₂V₂
By putting values,
1.28 M×334.75 mL = C₂×822.18 mL
C₂ = 1.28 M×334.75 mL / 822.18 mL
C₂ = 428.48 M.mL / 822.18 mL
C₂ = 0.52 M
c) Discuss precision and Accuracy as they relate to types of errors.
what is the answer
Precision relates to the consistency and reproducibility of measurements, while accuracy reflects how close measurements are to the true value.
Precision and accuracy are two important concepts in the context of errors in measurements. While they both pertain to the quality of data, they refer to different aspects.
Precision refers to the degree of consistency or reproducibility in a series of measurements. It reflects the scatter or spread of data points around the average value. If the measurements have low scatter and are tightly clustered, they are considered precise. On the other hand, if the measurements have a high scatter and are widely dispersed, they are considered imprecise.
Accuracy, on the other hand, refers to the closeness of measurements to the true or target value. It represents how well the measured values align with the actual value. Accuracy is achieved when measurements have a small systematic or constant error, which is the difference between the average measured value and the true value.
Errors in measurements can be classified into two types: random errors and systematic errors.
Random errors are associated with the inherent limitations of measurement instruments or fluctuations in the measurement process. They lead to imprecise data and affect the precision of measurements. Random errors can be reduced by repeating measurements and calculating the average to minimize the effect of individual errors.
Systematic errors, on the other hand, are caused by consistent biases or inaccuracies in the measurement process. They affect the accuracy of measurements and lead to a deviation from the true value. Systematic errors can arise from factors such as instrumental calibration issues, environmental conditions, or experimental techniques. These errors need to be identified and minimized to improve the accuracy of measurements.
In summary, precision refers to the degree of consistency or reproducibility of measurements, while accuracy refers to the closeness of measurements to the true value. Random errors affect precision, while systematic errors affect accuracy. To ensure high-quality measurements, both precision and accuracy need to be considered and appropriate techniques should be employed to minimize errors.
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Which of the following is NOT a property of gases?
Your answer:
A.They are easy to compress.
B.They expand to fill their containers.
C.They have a definite shape and a definite volume.
D.They occupy far more space than the liquids or solids from which they form.
Answer: C
Explanation:
A. As they do not have a given shape and expand to fill the container, modifying the size of the container modifies the space the gas occupies
B. They are nearly free molecules, which means no bound between them, moving fast and freely around the container
C. NOT A PROPERTY. As said before, as there are no bindings between molecules and move freely, they cannot have a fixed size cause they're always on the move.
D. Because they expand to fill the container, it's easy to them to occupy more space than in any other state, as the container is the only thing that defines how much volume they occupy
burning 12g of urea raise temp of water by 30C what is the enthalpy of combustion for 1kg urea
The enthalpy of combustion for 1kg of urea is -1223525.84 J/mol.
Urea is a compound that is used in fertilizers and in some plastics.The enthalpy of combustion for urea is the amount of energy that is released when urea is burned. In order to calculate the enthalpy of combustion for 1kg of urea, we need to use the information that is provided to us in the question. Let us start by writing down the balanced equation for the combustion of urea: CO(NH2)2 + 3/2 O2 → CO2 + 2H2O + N2
The balanced equation shows that 1 mole of urea reacts with 1.5 moles of oxygen gas to produce 1 mole of carbon dioxide, 2 moles of water, and 1 mole of nitrogen gas. The enthalpy change for this reaction is equal to the amount of energy that is released when 1 mole of urea is burned.
The heat of combustion (ΔHc) of urea is -632.6 kJ/mol. This means that 632.6 kJ of energy is released when 1 mole of urea is burned. We know that 12g of urea raised the temperature of water by 30°C. We can use this information to calculate the amount of energy that was released when 12g of urea was burned.
The specific heat capacity of water is 4.18 J/g°C. This means that it takes 4.18 J of energy to raise the temperature of 1 gram of water by 1°C. Therefore, it takes 4.18 x 1000 = 4180 J of energy to raise the temperature of 1 kg of water by 1°C.
We know that 12g of urea raised the temperature of water by 30°C. Therefore, the amount of energy that was released when 12g of urea was burned is:
Energy = mass x specific heat capacity x temperature change
Energy = 0.012 kg x 4180 J/kg°C x 30°C
Energy = 1497.6 J
We can now use this information to calculate the enthalpy of combustion for 1kg of urea:
Enthalpy of combustion = energy released / moles of urea burned
Enthalpy of combustion = 1497.6 J / (0.012 kg / 60.06 g/mol)
Enthalpy of combustion = - 1223525.84 J/mol
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pOH of the 0.001M NaOH solution is
The pOH of the 0.001 M NaOH solution is approximately 3.
To determine the pOH of a solution, we need to know the concentration of hydroxide ions (OH-) in the solution.
In the case of a 0.001 M NaOH solution, we can assume that all of the NaOH dissociates completely in water to form Na+ and OH- ions. Therefore, the concentration of hydroxide ions in the solution is also 0.001 M.
The pOH is calculated using the equation:
pOH = -log[OH-]
Substituting the concentration of hydroxide ions, we have:
pOH = -log(0.001)
Using a calculator, we can evaluate the logarithm:
pOH ≈ 3
Therefore, the pOH of the 0.001 M NaOH solution is approximately 3.
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Problem PageQuestion Nitric acid and nitrogen monoxide react to form nitrogen dioxide and water, like this: (aq)(g)(g)(l) At a certain temperature, a chemist finds that a reaction vessel containing a mixture of nitric acid, nitrogen monoxide, nitrogen dioxide, and water at equilibrium has the following composition: compound amount Calculate the value of the equilibrium constant for this reaction. Round your answer to significant digits. Clears your work. Undoes your last action. Provides information about entering answers.
Answer:
3.4
Explanation:
Nitric acid and nitrogen monoxide react to form nitrogen dioxide and water, like this: 2 HNO₃(aq) + NO(g) ⇄ 3 NO₂(g) + H₂O(l)
At a certain temperature, a chemist finds that a 9.5L reaction vessel containing a mixture of nitric acid, nitrogen monoxide, nitrogen dioxide, and water at equilibrium has the following composition:
compound amount
HNO₃ 15.5g
NO 16.6g
NO₂ 22.5g
H₂O 189.0g
Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.
Step 1: Write the balanced equation.
2 HNO₃(aq) + NO(g) ⇄ 3 NO₂(g) + H₂O(l)
Step 2: Calculate the molar concentration of the species at equilibrium
We will use the following expression.
M = mass of solute / molar mass of solute × liters of solution
[HNO₃] = 15.5g / 63.01 g/mol × 9.5 L = 0.026 M
[NO] = 16.6g / 30.01 g/mol × 9.5 L = 0.058 M
[NO₂] = 22.5g / 46.01 g/mol × 9.5 L = 0.051 M
We do not calculate the molarity of water because it is a pure liquid and will not be included in the equilibrium constant.
Step 3: Calculate the equilibrium constant (Kc)
Kc = [NO₂]³/[HNO₃]²×[NO]
Kc = 0.051³/0.026²×0.058
Kc = 3.4
What mass of CaCl2 (in g ) should the chemist use?
The mass of the solute required is 250.25 g.
What is the mass of the solute?We know that the number of moles of the solute can be used to obtain the mass of the solute that is required. We can now try to find the mass of the solute that is required.
Concentration of the solution = 0.350M
Volume of the solution = 6.5 L
Number of moles of the solute = 0.350M * 6.5 L
= 2.275 moles
We now have the mass of the solute as;
2.275 moles * 110 g/mol
= 250.25 g
Th measured mass of the solute that we would have to use is 250.25 g.
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Missing parts;
A chemist wants to make 6.5 L of a .350M CaCl2 solution. What mass of CaCl2(in g) should the chemist use?
Look at the attachment below.
Sally is wrong because copper is less electropositive than hydrogen, thus, can not displace hydrogen from dilute acids.
The reactions to prepare copper (ii) chloride are:
the chlorination of copper sulfide at a high temperature
reaction of copper (ii) oxide with dilute hydrochloric acid
The equations of the given reactions are as follows:CuS + Cl₂ ---> CuCl₂ + SCuO + 2HCl ----> CuCl₂ + H₂O
What are reactive metals?Reactive metals are metals that readily give up their electrons to form positive ions.
Reactive metals displace hydrogen from dilute acids. They are found in group 1A and 2A of the periodic table. Copper is not a reactive metal and will not displace hydrogen from acids.
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Sally is wrong because copper chloride is not made from the reaction of copper and dilute hydrochloric acid.
2. Copper (ii) chloride can be prepared as follows:
reacting copper (ii) oxide with dilute hydrochloric acidsingle replacement reaction of copper sulfide and chlorine gas at a high temperature3. the equations of the reaction are:
CuO + 2HCl ----> CuCl₂ + H₂OCuS + Cl₂ ---> CuCl₂ + SWhat are single replacement reactions?Single replacement reactions are reactions in which a more reactive atom replaces another atom in a compound.
An example of a single replacement reaction is the reaction of chlorine gas with copper sulfide at high temperatures to form copper chloride.
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What would question four will be?
Please explain
Energy, according to scientists, is the capacity for work. Because of the development of energy conversion technology, modern civilisation is feasible.
What are the two most commonly used units of energy?Calorie (cal) (cal). In more recent times, the calorie has been defined in terms of the joule; historically, this relationship has been referred to as the mechanical equivalent of heat. Joules is the energy unit used in the SI (J). The formula for joules is 1 kg*m2*s-2. The unit of energy known as a kilojoule (kJ) is 1000 joules.
The term "calorie" (Cal) refers to the amount of energy that is either contained in food or used by the body. A joule is equivalent to (roughly): the quantity of electricity needed to power a 1 W device for one second. the power necessary to move a 1 kg mass 1 m/s2 at a distance of 1 m. Nonrenewable and renewable energy sources can be divided into two categories.
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The element X has three naturally occurring isotopes. The isotopic masses (amu) and % abundances of the isotopes are given in the table below. Calculate the average atomic mass of the element in amu. PLEASE HELP ASAP THANK YOU SO MUCH
Answer:
162.35 amu
Explanation:
Let A represent isotope X-159
Let B represent isotope X-163
Let C represent isotope X-164
The following data were obtained from the question:
Isotope >>> Abundance >>> Mass no
A >>>>>>>> 30.60 >>>>>>>> 159.37
B >>>>>>>> 15.79 >>>>>>>>> 162.79
C >>>>>>>> 53.61 >>>>>>>>> 163.92
Average Atomic mass =.?
The average atomic mass of element X can be obtained as follow:
Average atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100] + [(mass of C × C%)/100]
= [(159.37 × 30.60)/100] + [(162.79 × 15.79)/100] + [(163.92 × 53.61)/100]
= 48.77 + 25.70 + 87.88
= 162.35 amu
Therefore, the average atomic mass of element X is 162.35 amu
Matter is anything that has mass and takes up space (volume). How does volume change as matter changes state?
A. The density of matter remains the same, only energy of the atoms changes.
B. matter becomes more dense as it moves from solid to gas
C. Matter becomes less dense as it moves from gas to solid state
D. Matter becomes more dense as it moves from gas to solid state
Answer: D) Matter becomes more dense as it moves from gas to solid state
A gas expands to fill up the container of whatever shape or size. As it cools to a solid, the molecules get closer together and don't move as much (the molecules still will vibrate and move somewhat even in solid form). So effectively the volume of the object shrinks while the amount of mass stays the same. This is why the density increases when going from gas to solid.
Why is the shadow not at its shortest midday in the uk ?
Hint: Find out about Daylight saving time...
Please answer this one!,
Answer:
Your reasoning that the shadow is the shortest at mid-day is spot-on! The wording of the question is the key to the answer. It says that the measurements were made in Summer. So this means that British Summer Time (BST) is being applied.
Convert 355 kJ to Cal